List the three ways substances can dissolve in water.
________?
________?
________?

Explanation:

The frequency of a wave is the number of times per second that the wave cycles. Frequency is measured in Hertz or cycles per second. The frequency is often represented by the lower case "f." The period of the wave is the time between wave crest

The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Answer:  1.53 M

Explanation:

1) solve for moles

345 g CaCO3 x ( 1mol/100.09 g) =3.446897792 moles

2) plug in formula M=mole/liters

3.446897792 / 2.25 = 1.53 M

Answer:

See explanation

Explanation:

PO4{3-} is phosphate
Sulfite's formula is SO3{2-}
Sulfate is SO4{2-}
OH- is hydroxide
Note: {x±} signifies the charge of the entire molecule

The polyatomic ions in question are phosphite ion, sulfite ion, and sulfate ion.

The formula PO3−4 represents the polyatomic ion called phosphite ion. It is composed of one phosphorus atom bonded to three oxygen atoms. The name of the sulfite ion is SO3−2, and it consists of one sulfur atom bonded to three oxygen atoms. Lastly, the sulfate ion has the formula SO4−2, and it is composed of one sulfur atom bonded to four oxygen atoms.

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Approximately 631.5 liters of dry air at 25°C and 750 torr would need to be processed to produce 150 liters of liquid \(O_2\) -183°C.

To solve this problem, we need to consider the ideal gas law and the molar volume of gases.

First, we can calculate the number of moles of oxygen in 150 L of liquid \(O_2\) at -183°C. To do this, we divide the mass of liquid oxygen by its molar mass:

Mass of liquid oxygen = volume of liquid oxygen * density of liquid oxygen = 150 L * 1.14 g/mL = 171 g

Molar mass of oxygen (O2) = 32 g/mol

Number of moles of oxygen = mass of oxygen / molar mass of oxygen = 171 g / 32 g/mol ≈ 5.34 mol

Since the mole fraction of oxygen in dry air is given as 0.21, we can calculate the total moles of dry air needed to produce 5.34 mol of oxygen:

Moles of dry air = moles of oxygen / mole fraction of oxygen = 5.34 mol / 0.21 ≈ 25.43 mol

Now, we can use the ideal gas law to calculate the volume of dry air at 25°C and 750 torr (convert to atm) that corresponds to 25.43 mol:

PV = nRT

P = 750 torr * (1 atm / 760 torr) ≈ 0.987 atm

V = volume of dry air (unknown)

n = 25.43 mol

R = 0.0821 L·atm/(mol·K)

T = 25°C + 273.15 = 298.15 K

Solving for V:

V = nRT / P = (25.43 mol)(0.0821 L·atm/(mol·K))(298.15 K) / 0.987 atm ≈ 631.5 L

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The gases in the Earth's atmosphere that block a high amount of infrared light are called greenhouse gases.

These include carbon dioxide (CO₂), methane (CH₄), nitrous oxide (N₂O), and fluorinated gases, among others.

Greenhouse gases trap heat within the Earth's atmosphere and play a significant role in regulating the Earth's temperature.

However, when their concentration increases beyond natural levels, they can cause the Earth's temperature to rise, leading to global warming and climate change.

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Answer:

An element is an ATOM or aggregate of atoms all of which have the same number of protons. In pure form, they will also have the same number of electrons. Each element has its own unique number of protons. For example, hydrogen always has one proton, helium always has two and lithium always has three.

Explanation:

To calculate the moles of each element in methane:

We will use the avogadros number.

For C:

1 mole = 6.022x10^23 atoms

in CH4 there is only 1 carbon.

Which is 1 x 6.022x10^23 atoms = 1 mole

There is 1 moles of carbon.

For H:

For hydrogen its 4 x 6.022x10^23 atoms = 4 moles

therefore there are 4 moles of hydrogen.

1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Answer:

Conduction

Explanation:

I took the course

Answer:

B. conduction

The statement "Superficial zone chondrocytes can get compacted under physiological loading: a multiscale finite element analysis" is true.

Superficial zone chondrocytes are the most exposed to mechanical loading and are therefore at risk of being compacted under physiological loading. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

This means that chondrocytes in the superficial zone of cartilage are at risk of being compacted under the physiological loading that it experiences in everyday life. A multiscale finite element analysis can be used to model and predict the mechanical behavior of cartilage under physiological loading, allowing for a better understanding of the factors that affect its mechanical properties.

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Answer: 1 M \(BeCl_2\) > 1 M KCl = 2 M \(CH_3CH_2CH_2OH\) > 1 M \(C_12H_{22}O_{11}\)

Explanation:

\(\pi =iCRT\)

\(\pi\) = osmotic pressure = ?

i = vant hoff factor

C= concentration in Molarity  

R= solution constant

T= temperature

a) 1 M \(BeCl_2\)

i = 3

\(BeCl_2\rightarrow Be^{2+}+2Cl^-\)

Thus Concentration of ions = \(3\times 1M=3M\)

b) 1 M KCl

i = 2

\(KCl\rightarrow K^{+}+Cl^-\)

Thus Concentration of ions = \(2\times 1M=2M\)

c) 2 M \(CH_3CH_2CH_2OH\)

i = 1 ( as it doesnot dissociate)

Thus Concentration of ions = \(1\times 2M=2M\)

d) 1 M \(C_12H_{22}O_{11}\)

i = 1  ( as it doesnot dissociate)

Thus Concentration of ions = \(1\times 1M=1M\)

Thus order from highest to lowest osmotic pressure is:

1 M \(BeCl_2\) > 1 M KCl = 2 M \(CH_3CH_2CH_2OH\) > 1 M \(C_12H_{22}O_{11}\)

The best way to measure the pH of a natural solution while out in a forest is to use a portable pH meter or pH test strips specifically designed for field use. These instruments provide accurate and reliable pH measurements and are convenient for outdoor applications.

1. Prepare the necessary equipment: Before heading out to the forest, gather the required tools. You will need a portable pH meter or pH test strips, as well as the necessary reagents or calibration solutions if using a pH meter.

2. Collect the sample: Locate the natural solution you want to measure the pH of, such as a stream, pond, or soil. Use a clean container to collect a representative sample of the solution.

3. Calibrate the pH meter (if applicable): If you are using a portable pH meter, it is essential to calibrate it before taking measurements. Follow the manufacturer's instructions to calibrate the meter using the provided calibration solutions.

4. Conduct the measurement: For pH meters, immerse the electrode into the collected sample. Allow some time for the reading to stabilize, and then record the pH value indicated on the meter's display.

5. Using pH test strips: If you are using pH test strips, dip the strip into the collected sample for the recommended amount of time. Remove the strip and compare the color change with the provided color chart. Determine the corresponding pH value from the chart.

6. Repeat for accuracy: To ensure reliability, repeat the measurement process at least once and compare the results. This step helps confirm the accuracy of your measurements.

7. Record and analyze the data: Note down the pH values obtained and any relevant observations. Analyze the data as needed for your research or monitoring purposes.

By following these steps and using the appropriate equipment, you can effectively measure the pH of a natural solution while in a forest setting.

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Answer:

electron-electron repulsion

Explanation:

When electrons add into valence shell of neutral elements, the element assumes a negative oxidation state. With this, the number of electrons having (-) charges will be larger than the number of protons having positive (+) charges. As a result, the extra electrons repel one another (i.e., like charges repel) and a larger radius is the result.  

In contrast, when cations are formed, electrons are removed from the valence level (oxidation) producing an element having a greater number of protons than electrons. The larger number of protons will function to attract the electron cloud with a greater force that results in a contraction of atomic radius and a smaller spherical volume than the neutral unionized element.    

To visualize, see attached chart that shows atomic and ionic radii before and after ionization of the elements.  

Answer:

the structure of an atom, theoretically consisting of a positively charged nucleus surrounded and neutralized by negatively charged electrons revolving in orbits at varying distances from the nucleus, the constitution of the nucleus and the arrangement of the electrons differing with various chemical elements.

Explanation:

Answer:

the answer is a          shh /..\  yall smell that

Explanation:

The chemical formulas for the ions and compounds you listed:

Copper (II) ion: Cu²⁺

Bromide ion: Br⁻

Magnesium ion: Mg²⁺

Phosphide ion: P³⁻

Copper (I) Bromide: CuBr

Sulfur Dichloride: SCl₂

Barium Fluoride: BaF₂

Magnesium Phosphate: Mg₃(PO₄)₂

Lithium Permanganate: LiMnO₄

Strontium Sulfite: SrSO₃

Nitrogen Monoxide: NO

Diselenium Tetraoxide: Se₂O₄

Aluminum Sulfide: Al₂S₃

Tin (IV) Iodide: SnI₄

Beryllium Oxide: BeO

Potassium Hydroxide: KOH

Copper (II) ion: Cu²⁺

Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.

Bromide ion: Br⁻

The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.

Magnesium ion: Mg²⁺

The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.

Phosphide ion: P³⁻

The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.

Copper (I) Bromide: CuBr

Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.

Sulfur Dichloride: SCl₂

Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.

Barium Fluoride: BaF₂

Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.

Magnesium Phosphate: Mg₃(PO₄)₂

Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.

Lithium Permanganate: LiMnO₄

Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.

Strontium Sulfite: SrSO₃

Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Nitrogen Monoxide: NO

Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.

Diselenium Tetraoxide: Se₂O₄

Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.

Aluminum Sulfide: Al₂S₃

Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "

2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.

Tin (IV) Iodide: SnI₄

Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.

Beryllium Oxide: BeO

Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Potassium Hydroxide: KOH

Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.

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Answer:

wind and solar are continuously renewable and fossil fuels take millions of years to form

Explanation:

so basically maybe you should

Answer:

half lives passed=5

given sample=90g

sample left=2.8125g

Explanation:

no. of half lives=total time/half life

no.=19days/3.8days

no.=5 days

after 5 half lives sample left=2.8125g

Answer:

1.58 g Pt

Explanation:

one mole of platinum weighs 195.09 grams (195.09 g/mol).

to convert moles of platinum to grams, we simply multiply the given moles of platinum by 195.09 to convert it to grams.

0.00808 x 195.09 = 1.576 g

The reaction mechanism explains the separate phases of a reaction and identifies any intermediates that are produced during one step and used in a different step later in the reaction.

One or maybe more chemicals, commonly referred to as reaction mixture, are converted within one or more chemical molecules, referred to as products, during a chemical reaction. Chemical elements and compounds are both substances.

Rearranging the atoms or molecules of two or more substances when they come into touch with one another, producing the production of one or more new substances. The interaction of two different substances' electrons is what drives chemical reactions.

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Answer:

0.167M

Explanation:

Molarity, M, is an unit of concentration in chemistry defined as the ratio between moles of solute (NaOH in this case) and volume of the solution in liters.

To find molarity of 5.00 g Sodium Hydroxide in 750.0 mL of solution we need to convert mass of NaOH to moles (Using its molar mass: 40g/mol) and the mililiters of solution to liters (1L = 1000mL), thus:

Moles NaOH = 5.00g × (1mol/ 40g) = 0.125 moles NaOH = Moles solute

Liters solution = 750.0mL × (1L / 1000mL) = 0.7500L solution

And molariy is:

0.125 moles NaOH  / 0.7500L solution =

0.167M

Answer: The empirical formula for C6H12O6 is CH2O. Every carbohydrate, be it simple or complex, has an empirical formula CH2O

Explanation:

Answer:

232.4 grams of KI solution

Explanation:

Well, we first start off by using like units. The concentration (M) of KI can be rewritten as Moles/ Liter, which makes the solution rewritten as 2.80 Moles/ 1 L.

We also know that 1000 Milliliters are equal to 1 Liter, therefore we can rewrite the 500 Milliliters as 0.500 Liters from doing a conversion (500 mL x  (1 L/1000 mL)= 0.500 L).

From here we multiply the concentration by the number of liters to leave us with moles ((2.80 Moles/ 1 L)  x  0.500 L= 1.4 Moles).

Now, we must find the molar mass of the KI solution, this can be done either by googleing it or adding the molar mass of each element in the compound via the periodic table. In this case, the molar mass for the Potassium in the compound is 39 g/mol while the Iodine is 127 g/mol. Those add to 166 g/mol, and now we can convert to grams from moles.

Now, we multiply the moles by the molar mass to cancel out the moles and leave us with grams. (1.4 mol x (166 g/mol)= 232.4 grams).

I hoped this helps and good luck with your semester in Chemistry!

Answer:

the atom structure in model A has more atoms and they are all the same type of atom while model B has less atoms and they are different types of atoms.

Explanation:

Answer:

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.  ( B )

During the initial cell operation, the oxidation of iodine is  thermodynamically favorable but the oxidation of mercury is not. ( C )

Explanation:

The major Differences between The Zinc mercury cell and Lithium-iodine cell are :

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.   and

During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.

Given the relationship below,

Δ G = -nFE

E = emf of cell ,  G = free energy.

This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy  also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable

Answer:

The atomic mass of methane (CH4)is 12 amu for the carbon plus 4 x 1 amu for the four hydrogens, for a total of 16 amu. Therefore, the molar mass of methane is 16g.

Answer:

Enery transformation is when a forn of energy changes into another.

Explanation:

An example of this would be a lamp. The lamp gets its energy through electricity. This electricity is later turned into light energy. Electrical energy to light evegy.