Make a suggestion on how you will deal with the problem..

Answer:

Mercury is a chemical element with symbol Hg and atomic number 80. Classified as a transition metal, Mercury is a liquid at room temperature.

...

Explanation:

Answer:

Mercurous nitrate!

Answer: 2) Chloroform & Caustic potash

Explanation:

The carbylamine reaction is a kind of chemical test which is done to detect primary amines in an unknown solution. It cannot detect secondary and tertiary amines.

The reaction involves the heating with up of the unknown solution with alcoholic potassium hydroxide or caustic potash and the chloroform.

In the presence of primary amine, the production of isocyanide results.

If the sample is not heated long enough water of hydration remain in the sample which adds on to the molar mass of the sample thereby introducing errors in calculations.

Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

The molecular mass and formula mass are used as synonym for the molar mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.

Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.

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In the given reaction of Sulfur dioxide and calcium carbonate, for complete reaction, 1.90 tons of sulfur dioxide would require 2.9 tons of Calcium carbonate.

Balancing a chemical equation follows the law of mass conservation. The quantity of an element in the product and in reactants should be the same. Balanced equation of the reaction:

2CaCO3 + 2SO2 + O2 → 2CaSO4 + 2CO2

Two moles of calcium carbonate react with two moles of sulfur dioxide and give two moles each of calcium sulfate and carbon dioxide.

One ton is equal to a thousand kilograms and one kilogram is equal to a thousand grams. Which means one ton is equal to 10^6 grams.

The moles of a compound are obtained using the following formula:

Moles = given mass in grams/ molar mass

Tons of SO2  = 1.90 tons

Molecular mass of SO2  = 64

Moles of SO2  = (1.90 x 10^6) /64 = 0.029 x 10^6  

Now, 0.029 x 10^6  moles of SO2 would completely react with 0.029 x 10^6 moles of CaCO3.

The molar mass of CaCO3 = 40+12+16+16+16 =100

Grams in 2.9 x 10^6  moles of CaCO3 = moles x molecular mass

Grams in 2.9 x 10^6  moles of CaCO3= 100 x  0.029 x 10^6

Grams in 2.9 x 10^6  moles of CaCO3 = 2.9 x 10^6

In conclusion, 1.90 tons of sulfur dioxide would require 2.9 tons of Calcium carbonate to react completely.

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Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Answer:

The glucose concentration is measured in mM, the abbreviation for "milliMolar". The molar (M) concentration of a solution is a measure of how much solute (the component of a solution present in lesser amount, often a solid) there is in a given volume of solution. After swirling the flask to dissolve the solid, water is added carefully until the bottom of the meniscus coincides with the calibration mark on the neck of the flash.

If the pH of a solution is one and it is diluted by 1*10^3 times, the pH of the resulting solution will be 4.

The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm of the concentration of hydrogen ions in the solution.

When a solution is diluted by a factor of 10, its pH increases or decreases by 1 depending on whether it is an acidic or basic solution, respectively. In this case, the solution has been diluted by a factor of 1*10^3, which means that its pH will increase by 3 units. Therefore, the pH of the resulting solution will be 4 (pH of the original solution + 3).

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Distillation is a useful technique in the synthesis and reactions of alkenes as it can help increase the yield by shifting the equilibrium towards the product side.

The synthesis of alkenes involves the elimination of a leaving group from a substrate. This can be achieved through various reactions such as dehydration of alcohols, dehydrohalogenation of alkyl halides, and dehalogenation of vicinal dihalides. Once the reaction is complete, the product mixture may contain a combination of desired and undesired products, and may also be in equilibrium with the reactants. Distillation can be used to separate the desired product from the reaction mixture, which helps to shift the equilibrium towards the product side, ultimately increasing the yield.

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When we have a chemical reaction, the speed of the reaction will depend on different factors such as concentration, temperature, or pressure.

If we assume that the temperature and pressure remain constant, it will be the concentration that will determine the rate of reaction for a non-zero order reaction.

If the concentration of the reactants decreases, the reaction rate also decreases, therefore, if the reactants are depleted, the reaction rate decreases.

Answer: D. The rate of the reaction slows down.

Answer:A molecule is composed of two elements. In general, the elements that combine to form binary molecular compounds are both nonmetals.

This contrasts with ionic compounds, which usually involve bonds between metal ions and nonmetal ions.

Explanation:

Answer: look down hope I helped

Explanation:

1) First convert to pOH as OH is the dissociating species in a base equilibrium.pH + pOH = 14 (at 25 C)pH=13, hence pOH = 1,Hence [OH] = 10^-1 Mdiluting by factor of 10 with pure water gives [OH] = 10^-2 MThe new pOH = 2, hence the new pH is 12In general, dilution (with pure water) by a factor of 10 moves the pH 1 unit in the direction of the pH of water (pH 7). i.e. it moves up for acids, down for bases.(At infinite dilution of either acids or bases, you’d have pure water - obvious when you think of it like that)

4.44 g of carbon dioxide is produced Sodium bicarbonate reacts with hydrochloric acid in a gas-forming reaction.

The question provides us with a balanced chemical reaction and the masses of our reactants  \(NaHCO_{3}\) (8.28 g) and HCl (5.22 g). As we do not know which is the limiting reactant, we will start by converting the masses of both reactants to moles:

n = \(\frac{m}{M}\)

Where, n = moles; m = mass; M = molar mass

The molar masses of \(NaHCO_{3}\) and HCl are obtained by adding the atomic masses of each atom. The atomic masses are obtained from the periodic table:

\(M_{ NaHCO_{3} }\) = (22.99g/mol)+(1.01g/mo)+(12.01g/mol)+(3×16.00g/mol)          

              =84.01g/mol

\(M_{HCL}\) = (1.01g/mol)+(45.45g/mol)

         =46.46g/mol

Now we can substitute the values in and solve:

\(n_{NaHCO_{3} }\) = \(\frac{m}{M}\) = \(\frac{8.28g}{ 84.01g/mol }\)

               = 0.958 mol

\(n_{HCL}\) = \(\frac{m}{M}\) = \(\frac{5.22g}{46.46g/mol}\)

          =0.112 mol

Next we will calculate the theoretical yield (in moles) of carbon dioxide from each reactant. In the process we will also determine the limiting reactant.

0.1 mol \(NaHCO_{3}\) × \(\frac{1molCO2}{1molNaHCO3}\) = 0.985 mol \(CO_{2}\)

0.112 mol HCl× \(\frac{1molCO2}{1molHCL}\) =0.112 mol \(CO_{2}\)

From the results we can see the limiting reactant is

 \(NaHCO_{3}\) as it produces less \(CO_{2}\). As the limiting reactant determines the theoretical yield, this means 0.1 mol of \(CO_{2}\) will be produced. To determine the mass of \(CO_{2}\)

we will rearrange the formula we used earlier with the molar mass of \(CO_{2}\).

\(M_{CO_{2} }\) = 12.01g/mol + (2×16.00g/mol) = 44.01g/mol

m = \(\frac{n}{M}\) = (0.958 mol)(44.01g/mol)=4.44 g

Therefore 4.44 g of carbon dioxide is produced

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Answer:

Explanation:

A. Ethanoic acid-acetic acid being weak acid dissocated weekly and turns solution to weakly acidic, ph will be between 4-7,

B. Hydrochloric acid - the solution would be acidic- with lots of H+ ions, Ph will be between 1-4,

C. Sodium chloride - solution prodcued netural Na+ and Cl- hence wont affect ph of solution will be equalt to 7.

D. Sodium hydrogen carbonate-NaHCO3 is weak base and the PH will be above 7,

After one day, approximately 8.67mg of the sample will be remaininga) The function that models the sample of Technetium-99 is given by

f(t) = P₀e^(-kt)

Where,P₀ = initial quantity = 100mgk = decay constantt = timef(t) = remaining quantity after t time.

A half-life of 6 hours is given. The decay constant can be found using the half-life formula:

T½ = (ln 2)/k6

= (ln 2)/kk

= (ln 2)/6f(t)

= P₀e^(-kt)f(t)

= 100e^(-0.1155t)mg

b) After one day, 24 hours = 4 half-lives Remaining amount,

f(t) = P₀e^(-kt)f(24)

= 100e^(-0.1155 × 24)

= 100e^(-2.772)

≈ 8.67mg

After one day, approximately 8.67mg of the sample will be remaining. The function that models the sample is

f(t) = 100e^(-0.1155t), where t is time in hours and f(t) is the remaining quantity in milligrams.

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After one day, approximately 8.67mg of the sample will be remaininga) The function that models the sample of Technetium-99 is given by

f(t) = P₀e^(-kt)

Where,P₀ = initial quantity = 100mgk = decay constantt = timef(t) = remaining quantity after t time.

A half-life of 6 hours is given. The decay constant can be found using the half-life formula:

T½ = (ln 2)/k6

= (ln 2)/kk

= (ln 2)/6f(t)

= P₀e^(-kt)f(t)

= 100e^(-0.1155t)mg

b) After one day, 24 hours = 4 half-lives Remaining amount,

f(t) = P₀e^(-kt)f(24)

= 100e^(-0.1155 × 24)

= 100e^(-2.772)

≈ 8.67mg

After one day, approximately 8.67mg of the sample will be remaining. The function that models the sample is

f(t) = 100e^(-0.1155t), where t is time in hours and f(t) is the remaining quantity in milligrams.

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Answer:

I hope this will help you and Please mark me as Brilliant

Explanation:

Consider this balanced chemical equation:

2 H2 + O2 → 2 H2O

We interpret this as “two molecules of hydrogen react with one molecule of oxygen to make two molecules of water.” The chemical equation is balanced as long as the coefficients are in the ratio 2:1:2. For instance, this chemical equation is also balanced:

100 H2 + 50 O2 → 100 H2O

This equation is not conventional—because convention says that we use the lowest ratio of coefficients—but it is balanced. So is this chemical equation:

5,000 H2 + 2,500 O2 → 5,000 H2O

Again, this is not conventional, but it is still balanced. Suppose we use a much larger number:

12.044 × 1023 H2 + 6.022 × 1023 O2 → 12.044 × 1023 H2O

These coefficients are also in the ratio of 2:1:2. But these numbers are related to the number of things in a mole: the first and last numbers are two times Avogadro’s number, while the second number is Avogadro’s number. That means that the first and last numbers represent 2 mol, while the middle number is just 1 mol. Well, why not just use the number of moles in balancing the chemical equation?

2 H2 + O2 → 2 H2O

is the same balanced chemical equation we started with! What this means is that chemical equations are not just balanced in terms of molecules; they are also balanced in terms of moles. We can just as easily read this chemical equation as “two moles of hydrogen react with one mole of oxygen to make two moles of water.” All balanced chemical reactions are balanced in terms of moles.

Example 8

Interpret this balanced chemical equation in terms of moles.

P4 + 5 O2 → P4O10

Solution

The coefficients represent the number of moles that react, not just molecules. We would speak of this equation as “one mole of molecular phosphorus reacts with five moles of elemental oxygen to make one mole of tetraphosphorus decoxide.”

Test Yourself

Interpret this balanced chemical equation in terms of moles.

N2 + 3 H2 → 2 NH3

Answer

One mole of elemental nitrogen reacts with three moles of elemental hydrogen to produce two moles of ammonia.

Answer:

hcl is a covalent compound

Explanation:

Correct option is c. 0

Let's discuss it further below.

In the Lewis structure for formaldehyde (H2CO), where C is the central atom, the formal charge on C is:

Step 1: Determine the number of valence electrons for C. Carbon has 4 valence electrons.
Step 2: Calculate the number of electrons assigned to C in the Lewis structure. In formaldehyde, C is bonded to 2 H atoms (each with 1 bond) and 1 O atom (with a double bond). This gives C a total of 4 bonds, so it has 4 assigned electrons.
Step 3: Calculate the formal charge on C using the formula: Formal Charge = (Valence Electrons) - (Assigned Electrons). Thus, Formal Charge on C = (4) - (4) = 0.

So, the formal charge on C in the Lewis structure for formaldehyde is 0 (option c).

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Answer:  Raw data, perhaps.

Explanation:  I'm not certain what the question is seeking for an answer, but I would suggest "raw data" would be a reasonable choice.  It reflects the data was recorded, but not yet processed to provide a conclusion or observation.

If one were a bit snarky, other possiblities include

Based in the nature of a DNA molecule, to construct a DNA molecule:

A molecule of DNA molecule is composed of two double-stranded nucleotide sequences which are antiparallel to each other.

In the nucleotide sequence of a DNA molecule, guanylate, G pairs with cytidylate, C and adenylate, A pairs with thymidylate, T.

Therefore, to construct a DNA molecule:

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Answer:

Negative 5

Explanation:

I am not 100% sure btw

A chemical catalyst increases the rate of a reaction by decreasing the energy of activation.

In a chemical reaction, the presence of a catalyst increases the reaction rate in both forward and backward  reactions by providing an alternative pathway by lowering the activation energy.

Catalysts increase the rate of a reaction without being used up. With the presence of a catalyst in a certain reaction, more number of collisions take place,  so the rate of reaction increases.

When the activation energy is lowered, more reactants can cross the reaction barrier easily and so, the rate of reaction increases.

Therefore, we can say that the role of a catalyst is to lower the activation energy in order to increase the reaction rate.

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Explanation:

This is because the hydrogen bonding in water H2O is stronger than that is hydrogen sulfide H2S.

Molality is used in colligative property investigations instead of molarity because colligative properties depend on the number of solute particles present in a given mass of solvent, not on the total volume of the solution.

Molality is defined as the number of moles of solute per kilogram of solvent, while molarity is defined as the number of moles of solute per liter of solution. Since colligative properties are affected by the concentration of solute particles in the solvent, molality is the more appropriate measure of concentration to use.

Additionally, molality is a more accurate measure of the concentration of a solution when the temperature changes, as its value remains constant with temperature.

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Answer: d) 164.9 g

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)     \(\text{Moles of octane}=\frac{47g}{114g/mol}=0.412moles\)

The balanced chemical reaction is:

\(2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)\)  

According to stoichiometry :

2 moles of \(C_8H_{18}\) require = 25  moles of \(O_2\)

Thus 0.412 moles of \(C_8H_{18}\) will require=\(\frac{25}{2}\times 0.412=5.15moles\)  of \(O_2\)

Mass of \(O_2=moles\times {\text {Molar mass}}=5.15moles\times 32g/mol=164.9g\)

Thus 164.9 g of oxygen is consumed.

1. The pH change when 0.094 mol NaOH is added to 1.00 L of the buffer is -0.61.

2. The pH change when 0.062 mol KOH is added to 1.00 L of the buffer is 0.26.

1. The pH change can be determined by using the Henderson-Hasselbalch equation.

The initial pH of the buffer can be found using the equation:
pH = pKa + log([A⁻]/[HA])
where pKa = -log(Ka)
and [A⁻]/[HA] = K₂SO₃/KHSO₃

The Ka value of HSO₃⁻ is 1.02 × 10⁻². Therefore, the pKa value is 1.99.

Substituting the values into the Henderson-Hasselbalch equation:
pH = 1.99 + log(0.249/0.372) = 1.99 - 0.107 = 1.88

Before addition, the pH of the buffer is 1.88.

Now, the NaOH reacts with the HSO₃⁻ ion in the buffer to form SO₃²⁻ ion and water.

NaOH + HSO₃⁻ → SO₃²⁻ + H₂O

0.094 mol NaOH will react completely with 0.094 mol HSO₃⁻ to form 0.094 mol SO₃²⁻.

Now, the new concentrations of KHSO₃, K₂SO₃, HSO₃⁻, and SO₃²⁻ are:
KHSO₃ = 0.372 - 0.094 = 0.278 M
K₂SO₃ = 0.249 M
HSO₃⁻ = 0.278 M
SO₃²⁻ = 0.094 M

The new pH of the buffer can be calculated using the same equation:
pH = pKa + log([A⁻]/[HA])

where pKa = -log(Ka)

and [A⁻]/[HA] = SO₃²⁻/HSO₃⁻

The Ka value of HSO₃⁻  is 1.02 × 10⁻². Therefore, the pKa value is 1.99.

Substituting the values into the Henderson-Hasselbalch equation:
pH = 1.99 + log(0.094/0.278) = 1.99 - 0.723 = 1.27

The new pH of the buffer is 1.27.

The pH change is calculated as the difference between the new pH and the initial pH:
pH change = 1.27 - 1.88 = -0.61

Therefore, the pH change when 0.094 mol NaOH is added to 1.00 L of the buffer is -0.61.

2. The pH change can be determined by using the Henderson-Hasselbalch equation.

The initial pH of the buffer can be found using the equation:
pH = pKa + log([A⁻]/[HA])
where pKa = -log(Ka)
and [A⁻]/[HA] = NH₃/NH₄⁺

The Ka value of NH₄⁺ is 5.6 × 10⁻¹⁰. Therefore, the pKa value is 9.25.

Substituting the values into the Henderson-Hasselbalch equation:

pH = 9.25 + log(0.287/0.311) = 9.25 - 0.084 = 9.17

Before addition, the pH of the buffer is 9.17.

Now, the KOH reacts with the NH₄⁺ ion in the buffer to form NH₃ and water.

KOH + NH₄⁺ → NH₃ + H₂O

0.062 mol KOH will react completely with 0.062 mol NH₄⁺ to form 0.062 mol NH₃.

Now, the new concentrations of NH₄Br, NH₃, NH₄⁺, and OH⁻ are:
NH₄Br = 0.311 M
NH₃ = 0.287 + 0.062 = 0.349 M
NH₄⁺ = 0.311 - 0.062 = 0.249 M
OH⁻ = 0.062 M

The new pH of the buffer can be calculated using the same equation:
pH = pKa + log([A⁻]/[HA])
where pKa = -log(Ka)
and [A⁻]/[HA] = NH₃/NH₄⁺

The Ka value of NH₄⁺ is 5.6 × 10⁻¹⁰. Therefore, the pKa value is 9.25.

Substituting the values into the Henderson-Hasselbalch equation:
pH = 9.25 + log(0.349/0.249) = 9.25 + 0.177 = 9.43

The new pH of the buffer is 9.43.

The pH change is calculated as the difference between the new pH and the initial pH:
pH change = 9.43 - 9.17 = 0.26

Therefore, the pH change when 0.062 mol KOH is added to 1.00 L of the buffer is 0.26.

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Answer:

In a process called diffusion, .

Explanation:

oxygen moves from the alveoli to the blood through the capillaries (tiny blood vessels) lining the alveolar walls. ... From the heart, this blood is pumped to the lungs, where carbon dioxide passes into the alveoli to be exhaled

1. The kinetic energy and potential energy of both objects will be the same.

2. True. The acceleration due to gravity is different depending on the planet.

The kinetic energy of an object is energy due to the motion of the object.

K.E = ¹/₂ mv²

where;

The speed of the object at different heights is given as;

v = √2gh

for 5 m high;

v = √ (2 x 9.8x 5)

v = 9.9 m/s

for 10 m high;

v = √ (2 x 10 x 9.8)

v = 14 m/s

K.E for 5 m high;

K.E = ¹/₂ x 10 x 9.9²

K.E = 490 J

for 10 m high;

K.E = ¹/₂ x 5 x 14²

K.E = 490 J

2. The acceleration due to gravity is different depending on the planet.

This statement is true because, the value of acceleration due to gravity on Earth is 9.8 m/s² while that of Mars is 3.72 m/s², and so on.

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The complete question;

1. What has more kinetic energy, a 5 kg ball lifted 10 m high, or a 10 kg ball lifted 5 m high?

2. At the beginning of this assessment, you are told that all of the problems take place on earth.

The acceleration due to gravity is different depending on the planet, true or false?

Answer:

Most nuclear fuels contain heavy fissile actinide elements that are capable of undergoing and sustaining nuclear fission. The three most relevant fissile isotopes are uranium-233, uranium-235 and plutonium-239

Explanation:

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