mammoth skeleton has a carbon-14 decay rate of 0.48 disintegrations per minute per gram of carbon (0.48 dis/min⋅gC ).When did the mammoth live? (Assume that living organisms have a carbon-14 decay rate of 15.3 dis/min⋅gC and that carbon-14 has a half-life of 5730 yr.)

Answer: so basically, Newtons Law states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Explanation: newtons law simplified in my opinion is a physical law that describes the attraction between two objects with mass.

hope this helps.

Answer:

Explanation:

she rieat

Answer:8.1g

Explanation:

Explanation:

you can find by using. volume = mass/ density of aluminium.

Answer: Ptolemy or Kepler or Tycho Brache

Answer:

D Electromagnetic and gravitational

The object and image distances are 0.75 m.

Solution:

Focal length = 3/2 = 1.5 m                 ...(i)

R = 2F

We know, in a mirror,

-v/u = magnification

-v/u = 1.5

-v = 1.5u

v = -1.5u                            ...(ii)

Using the mirror formula,

1/v + 1/u = 1/f

-1/1.5u + 1/u = 1/1.5        ∴From (i) & (ii)

(-1 + 1.5)/1.5u = 1/1.5

1.5u = 1.5(-1 + 1.5)

1.5u = -1.5 + 2.25

1.5u = 0.75

u = 0.75/1.5

u = 0.5 m

u = -0.5 m (as it is in the front of the mirror)

Now, putting the value of u = 0.5 m in eq     (ii):-

v = 1.5u

v = 1.5*0.5

v = 0.75 m

Hence, the object distance is 0.5 m and the image distance is 0.75 m.

The distance from the image to the mirror is always equal to the distance from the object to the mirror. So if a person stands 3 meters in front of the mirror, the image is 3 meters behind her in the mirror. The radius of curvature is twice the focal length of the spherical mirror.

Place the object 20 cm in front of a plane mirror and create an image 20 cm behind the mirror. When the mirror is moved 2 cm toward the object. So the total distance between the original image position and the final image position is 4 cm. The relationship between the focal length of a mirror the distance to an object and the distance to an image is called the mirror formula.

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Answer:

How many questions should be answered??

so, 444 eggs would have been released in 37yrs

If a woman releases one egg every month for 37 years, then she releases 444 eggs.

A year is a unit of time that is commonly used to measure the period of time it takes for the Earth to make one revolution around the Sun.

The time it takes for the Earth to complete one orbit around the Sun is approximately 365.24 days, which is why a year is usually defined as 365 days, with an extra day added every four years (in what's called a leap year) to account for the fractional part of the year. This is known as the Gregorian calendar, which is the most widely used calendar system in the world.

A year is also commonly used to refer to the period of time it takes for an event or cycle to repeat, such as the school year, fiscal year, or a company's financial year.

There are 12 months in a year, and they are:

January

February

March

April

May

June

July

August

September

October

November

December

Each month has either 30 or 31 days, except for February which has 28 days (or 29 days in a leap year). The number of days in a month determines the number of days in a year, which is why a year typically has either 365 or 366 days, depending on whether or not it is a leap year.

Here in the question,

37 years is equivalent to 37 x 12 = 444 months (since there are 12 months in a year).

To calculate this, we simply multiply the number of eggs released each month (which is one) by the total number of months:

Number of eggs released = 1 egg/month x 444 months

Number of eggs released = 444 eggs

Therefore, over 37 years, a woman releases 444 eggs.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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Answer:

solution given:

frequency[f]=215.0Hz

velocity[V]=x

wave length=2.4m

we have

wave length=\( \frac{V}{f} \)

2.4m=\( \frac{x}{215} \)

2.4×215=\( \frac{x}{} \)

x=516 m/s

velocity=speed =516m/s

Answer:

516 m/s

Explanation:

Velocity = Frequency * Wavelength

If wavelength = 2.4m, and Frequency =   215 hz

Then Velocity = 2.4 * 215 which is equal to 516

Hence, velocity = 516 m/s

The diameter of the discs is 2 × 0.003 m = 0.006 m.

The electric field between two parallel charged discs can be calculated as E = V/d, where V is the potential difference between the discs and d is the separation distance between them. The charge Q on one of the discs can be calculated as Q = ne, where n is the number of electrons transferred from one disk to the other and e is the charge of an electron.

Using the equations for electric field and charge, we can find the separation distance d between the discs as follows:

\(E = \frac{V}{d} = \frac{Q}{A\epsilon_0}\)

d = Q/(AEε 0 ) = ne/(Aε 0 E)

\(d= 9.4 * 10^{9} * 1.60 * 10^{-19} / (\pi (d/2)^{2} * 8.85 * 10^{-12} * 1.0 * 10^{5})\)

Rearranging and solving for d, we find:

\(d = \sqrt{9.4 * 10^9 * 1.60 * 10^-19 / (\pi * 8.85 * 10^{-12} * 1.0 * 10^5)} \\\\ = \sqrt{1.0 * 10^{-7}}m = 0.003 m\)

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Answer:

W = F * s    

Work done equals applied force * distance traveled

Apparent weight = M g (1 - sin θ)     since some of applied force will lighten sled

μ = coefficient of kinetic friction

F cos θ = force applied to motion of sled

s = distance traveled

[μ M g (1 - sin θ)] cos θ * s = work done in moving sled

Note that F = μ M g    if applied force is in the horizontal direction

(a) When l = 2, the possible magnetic quantum numbers (mₑ) are -2, -1, 0, 1, and 2.(b) When l = 4, the possible magnetic quantum numbers (mₑ) are -4, -3, -2, -1, 0, 1, 2, 3, and 4.

(a) The magnetic quantum number (mₑ) represents the projection of the orbital angular momentum along a chosen axis. It takes on integer values ranging from -l to +l, including zero. When l = 2, the possible values for mₑ are -2, -1, 0, 1, and 2. These values represent the five different orientations of the orbital angular momentum corresponding to the d orbital.

(b) Similarly, when l = 4, the possible values for mₑ are -4, -3, -2, -1, 0, 1, 2, 3, and 4. These values represent the nine different orientations of the orbital angular momentum corresponding to the f orbital. The range of values for mₑ is determined by the value of l and follows the pattern of -l to +l, including zero.Therefore, when l = 2, the possible magnetic quantum numbers (mₑ) are -2, -1, 0, 1, and 2. And when l = 4, the possible magnetic quantum numbers (mₑ) are -4, -3, -2, -1, 0, 1, 2, 3, and 4.

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Answer:

\(Q=-38.15kJ\)

Explanation:

From the question we are told that

Piston-cylinder initial Volume of air \(v_1=0.1 m^3\)

Piston-cylinder initial temperature \(T_1=400k\)

Piston-cylinder initial pressure \(P_1= 100kpa\)

Supply line temperature\(T_s=400k\)

Supply line pressure \(P_s= 500kpa\)

Valve  final pressure \(P_v=500kpa\)

Piston movement pressure \(P_m=200kpa\)

Piston-cylinder final Volume of air\(v_2=0.2 m^3\)

Piston-cylinder final temperature \(T_2=440k\)

Piston-cylinder final pressure \(P_2= 500kpa\)

Generally the  equation for conservation of mass is mathematically given by

\(Q=m_2 \mu_2-m_1 \mu_1 +W-(m_2-m_1)h\)

where

Initial moment

\(m_1=\frac{p_1 V_1}{RT_1}\)

\(m_1=\frac{100*0.1}{0.287*400}\)

\(m_1=8.7*10^-^2kg\)

Final moment

\(m_2=\frac{p_2 V_2}{RT_2}\)

\(m_1=\frac{500*0.3}{0.287*440}\)

\(m_1=79*10^{-2}kg\)

Work done by Piston movement pressure

\(W=Pd\)

\(W=P(v_2-v_1)\)

\(W=200(0.2-0.1))\)

\(W=20000J\)

Heat function

\(h=cT_1\)

\(h=1.005(400)\)

\(h=402\)

Therefore

\(Q=(0.792*0.718(440)-0.0871*0.718(400)+20-(0.792-0.087)*402))\)

\(Q=-38.15kJ\)

It is given mathematically that the system lost  or dissipated Heat of

\(Q=-38.15kJ\)

The cross product is a useful tool in geometry and physics for calculating areas, volumes, and determining perpendicular vectors.

The cross product of two vectors is defined as the product of their magnitudes and the sine of the angle between them.

This results in a vector that is perpendicular to both of the original vectors.

That is, if u and v are two vectors in space, their cross product is a vector denoted by u x v that is perpendicular to both u and v.

Additionally, the magnitude of the cross product is given by the area of the parallelogram formed by the two vectors u and v multiplied by the sine of the angle between them.

The geometric interpretation of the cross product is that it provides us with a vector that is perpendicular to both of the original vectors.

This is because the sine of the angle between two vectors is zero when the vectors are parallel, and is maximized at 1 when the vectors are perpendicular.

Therefore, the cross product gives us a way to find a vector that is orthogonal to both u and v.

Furthermore, the cross product can be used to find the area of a parallelogram or the volume of a parallelepiped.

Specifically, the magnitude of the cross product is equal to the area of the parallelogram formed by the two vectors u and v, and the dot product of the cross product with a third vector gives us the volume of the parallelepiped formed by the three vectors.

Thus, the cross product is a useful tool in geometry and physics for calculating areas, volumes, and determining perpendicular vectors.

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Answer:

a=1m/s²

Explanation:

note that the moving body is accelerating from 10m/s to 15m/s, so in this case the initial velocity is 10mls, and the final velocity is 15m/s, and the body makes this increase in just 5seconds. so looking at what we've been given in the question, we can now calculate acceleration.

so our Data is;

V= 15m/s

U= 10m/s

t= 5m/s

a=?

we can find acceleration by using these two formulas;

1) V= U + at

15= 10+ a(5)

15=10+5a

make 5a the subject of the formula, and to make it the subject of the formula, we need to transpose 10m/s, and when we transpose it, it will

become a negative number because of crossing the equal sign

15-10=5a

5=5a

divide throughout by 5 to remain with a

5/5=5a/5

1=a

:. a=1m/s²

then the second formula is;

a= (V-U)/t

a=(15-10)/5

a=5/5

a=1m/s²

Answer:

The trees are blocking the sunlight.

Explanation:

B is obviously not the answer because fertilizer wouldn't have that effect. For C, shade doesn't change the temperature that much that it would inhibit plant growth. For D, even if the tree blocks the water, the surrounding ground will still be wet and therefore the grass should still have a sufficient amount of water to grow.  Sunlight can't be gotten from somewhere else, unlike water, so this would inhibit plant growth.

Answer: chemical properties include those properties that are determined only by changing the molecular structure or chemical composition of any substance.

These include reactivity, flammability, corrosiveness, toxicity, acidity.

Reactivity is the tendency of matter to react with another substance.

"Deflection resistance is indeed related to the moment of inertia of a structural member." The higher the moment of inertia, the stiffer the member and the less it will deflect under a given load.

To determine which of the given sections will deflect the least with respect to the strong axis, we need to compare their moment of inertia values. The moment of inertia varies depending on the specific shape and dimensions of the section.

Here is the approximate moment of inertia values for the given sections:

a. W18x40: Moment of Inertia (I) ≈ 924 in⁴

b. W16x50: Moment of Inertia (I) ≈ 1,120 in⁴

c. W12x53: Moment of Inertia (I) ≈ 1,330 in⁴

d. W10x77: Moment of Inertia (I) ≈ 1,580 in⁴

Based on the moment of inertia values, we can see that the section with the least deflection resistance with respect to the strong axis is option (a) W18x40, with an approximate moment of inertia of 924 in⁴. Therefore, option (a) should deflect the least compared to the other options provided.

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Answer:

The orbital period of Titan ... Hyperion, another moon of Saturn, orbits at a mean radius of 1.48 x109 m. ... mass of the Sun is 1.99x1030 kg. ... calculate Pluto's orbital period in Earth days.

Answer:

50.4÷1.18= 42.7m/s as speed is equal to the distance over the time taken

Answer:

it's answer is B

A planet is round because of gravity. A planet's gravity pulls equally from all sides. Gravity pulls from the centre to the edges like the spokes of a bicycle wheel. This makes the overall shape of a planet a sphere, which is a three -dimensional circle

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The magnitude of the electric field between the plates when there is a layer of dust is higher than when there is no layer of dust. The resistances are in seriesThe gas in the precipitator behaves in a highly non-Ohmic manner. The current is proportional to the third power of the electric field.

The effective resistance of the gas depends strongly on the applied field. After a layer of dust has accumulated on the ground plate, the effective resistance of the gas is increasing. Once a layer of dust has accumulated, the effective resistance rises to a high level. This increase in resistance is due to the layer of dust between the plates.The magnitude of the electric field between the plates when there is a layer of dustThe magnitude of the electric field between the plates when there is a layer of dust is higher than when there is no layer of dust.

The reason for this is that the resistance of the gas in the precipitator is higher when there is a layer of dust. This means that the potential difference between the plates must be increased to maintain the same current. The electric field between the plates is proportional to the potential difference between the plates divided by the distance between the plates. In series, the resistances add together. Therefore, the effective resistance of the gas in the precipitator is the sum of the resistance of the gas and the resistance of the layer of dust.

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Answer: the atmospheric pressure is generally expressed in terms of the height of the mercury column.at normal temperature and pressure, the barometric height is 760mm at sea level which is taken as one atmosphere. thus atmospheric pressure is also expressed in a unit atmosphere where 1 atm= 0.76m of hg. 9

The speed of the planet at aphelion cannot be directly calculated given the perihelion distance, aphelion distance, and speed at perihelion of a planet.

The perihelion distance is the closest distance between the planet and the star (sun), while the aphelion distance is the farthest distance. The speed at perihelion is the maximum speed of the planet during its orbit. With this information, we can determine various aspects of the planet's orbit.A.

The mass of the star: The masses of the star and the planet are unrelated to the given parameters, so the mass of the star cannot be calculated with this information.B. The mass of the planet: Similarly, the mass of the planet is not related to the given parameters, so it cannot be directly calculated.

C. The speed of the planet at aphelion: The speed of the planet at aphelion depends on the gravitational force exerted by the star, which is related to both the mass of the star and the distance between the planet and the star at aphelion. Since the mass of the star is not provided, the speed at aphelion cannot be determined.D.

The period of the orbit: The period of the orbit depends on the semi major axis of the orbit and the mass of the star. Since the semi major axis is not directly provided, the period of the orbit cannot be calculated.E. The semi major axis of the orbit: The semi major axis can be determined using the perihelion and aphelion distances, so it can be calculated with the given information.

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Answer:

HI!!!

Explanation:

Answer:

what is your questions

The total heat needed to raise 4 moles of ethanol from 72°C to 90°C is equal to 257.2 KJ.

The specific heat of a substance can be defined as the amount of heat needed to raise the temperature in 1 unit of substance by one-degree Celcius.

Q = mCΔT

The heat needed to raise the ethanol from 72°C to a boiling point of 78°C will be:

Q₁ = 4 × 0.110 × (78°C - 72°C)

Q₁ = 33.6 KJ

To calculate the heat needed to evaporate the ethanol is:

Q₂ = 4 × 43.3

Q₂ = 173.2 kJ/mol

The heat needed to raise the ethanol vapor from 78°C to 90°C. is equal to:

Q₃ = 4 × 0.78 × (90°C - 78°C)

Q₃ = 50.4 KJ

Therefore, the total heat needed to raise 4 moles of ethanol from 72°C to 90°C will be:

Q = 33.6 kJ + 173.2 kJ + 50.4 kJ

Q = 257.2 kJ

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The reason you have to keep running your engine when your car is moving at a constant velocity on the highway is to overcome frictional forces.

So, the correct answer is C.

When your car is moving along the highway at a constant velocity, the net force acting on it is zero. However, you still need to keep running your engine to overcome the frictional forces acting on your car.

Frictional forces such as air resistance, rolling resistance, and the resistance caused by the engine and transmission of your car all act against the motion of your car.

Therefore, your engine needs to continue to produce power to counteract these forces and maintain your car's speed.

Additionally, keeping your engine running is important to power essential features of your car, such as your radio and air conditioning, and to prepare for sudden acceleration needs, such as when merging onto a highway or passing another vehicle.

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Answer: 2.43 s

Explanation:

Initial velocity is \(u=15.2\ m/s\)

Final velocity \(v=23\ m/s\)

Average acceleration is \(a_{avg}=3.2\ m/s\)

Average acceleration is change in velocity in the given amount of time

\(\therefore a_{avg}=\dfrac{v-u}{t}\\\\\Rightarrow 3.2=\dfrac{23-15.2}{t}\\\\\Rightarrow t=\dfrac{7.8}{3.2}\\\\\Rightarrow t=2.43\ s\)

Thus, 2.43 s is required to acquire that average acceleration with 23 m/s velocity .