Marcy tests a solution with a strip of blue litmus paper. The paper turns red. The solution is _____.
acidic
basic
neutral

Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

Answer:

0.00121 atm

Explanation:

Step 1: Given data

Step 2: Calculate the pressure exerted by the column of water in SI units

The pressure exerted by the column of liquid depends on the height of the column, the density of the liquid and the gravitational constant. We can calculate it using the following expression.

P = ρ × g × h

P = 1.00g/cm³ × 9.80665 m/s² × 12.5 m

P = 123 Pa

Step 3: Convert "P" to atm

We will use the conversion factor 101325 Pa = 1 atm.

123 Pa × (1 atm/101325 Pa) = 0.00121 atm

Answer:

Explanation:

Kelvin is preferred for solving problems related to Charles' Law because , it is the Absolute temperature scale.

To convert Celsius to  Kelvin scale, you add 273 to the temperature in the centigrade/Celsius scale.

The compound C4H6O4 can be classified as a dicarboxylic acid. In this case, the presence of four carbon atoms (C4) indicates that it is a relatively larger molecule.

The molecular formula also contains six hydrogen atoms (H6) and four oxygen atoms (O4). The presence of oxygen and carbon atoms suggests the possibility of carboxyl groups (-COOH) in the compound. Carboxyl groups are functional groups consisting of a carbonyl group (C=O) and a hydroxyl group (-OH) attached to the same carbon atom.

Since the compound contains four oxygen atoms, it is possible that it contains two carboxyl groups. A compound with two carboxyl groups is classified as a dicarboxylic acid. Dicarboxylic acids are organic compounds that have two carboxyl functional groups.

They are characterized by their ability to donate two protons (H+) and act as acids. Therefore, based on the molecular formula C4H6O4, the compound is classified as a dicarboxylic acid.

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Answer:

c

Explanation:

use %composition given to calculate emperical 4mular

The empirical formula of the compound having 57.5% Na, 40.0% O, and 2.5% H is NaOH (Option C)

Divide by their molar mass

Na = 57.5 / 23 = 2.5

O = 40 / 16 = 2.5

H = 2.5 / 1 = 2.6

Divide by the smallest

Na = 2.5 / 2.5 = 1

O = 2.5 / 2.5 = 1

H = 2.5 / 2.5 = 1

Thus, the empirical formula of the compound is NaOH

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The heat capacity corresponds to the energy needed to raise one degree of temperature for one gram of substance. That is, the greater the heat capacity, for the same mass, the greater the energy required to raise the temperature of the material.

Therefore, between the two metals with the same mass, the same initial temperature, and the same heat added, we can say that the one with the higher heat capacity will present a lower final temperature.

Answer:

Constructive interference is when two waves interact causing larger waves because the crest will meet a crest or a trough will meet a trough which adds the waves together changing the size of the amplitude.

Destructive interference is when two waves interact causing smaller waves because the crest will meet a trough or a trough will meet a crest which subtracts the waves together changing the size of the amplitude.

Answer:

1. The substance is an ether.

2. The substance was formed from an alcohol and an alkyl halide.

3. The IUPAC name of the parent aldehyde or ketone is propanone.

Explanation:

The given structural diagram represents an ether with the formula CH3C(OCH2CH3)2.

This substance is an ether because it contains an oxygen atom bonded to two alkyl groups. It can be formed from an alcohol and an alkyl halide through a reaction called the Williamson ether synthesis.

The alcohol would be ethanol (CH3CH2OH) and the alkyl halide would be 1-chloropropane (CH3CH2CH2Cl).

The reaction would be as follows:CH3CH2OH + CH3CH2CH2Cl → CH3C(OCH2CH3)2 + HCl

The parent aldehyde or ketone in this case is propanone (CH3COCH3), also known as acetone. This is because the ether is derived from the substitution of the two hydrogen atoms on the carbonyl group of propanone with two ethoxy groups (OCH2CH3). The IUPAC name of the ether would be 2,2-diethoxypropane.

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The pressure of the nitrogen gas produced is determined as 44.77 atm.

The pressure of the nitrogen gas is determined from ideal gas equation, as shown below;

PV = nRT

P = nRT/V

where;

P = (2 x 0.08205 x 341)/(1.25)

P = 44.77 atm.

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Answer:

The second picture

Explanation:

The first picture shows a solid because the particles of a solid are organized and compact. They can only vibrate in place

The third picture represents a gas because of how spaced out each particle is. They can move fast and erratically.

The second picture is the liquid because the particles aren't extremely packed, so they have space to move.

Answer:

The second one is correct

Given:98.1 mL of 5 M potassium hydroxide is mixed with 39.9 mL of 4.5 M Iron (III) acetate resulting in a precipitate of Iron (III) hydroxide.To calculate the theoretical yield in grams of Iron (III) hydroxide, the first step is to balance the chemical equation for the reaction that takes place between potassium hydroxide and iron (III) acetate. 3KOH + Fe(C2H3O2)3 → Fe(OH)3 + 3KC2H3O2The balanced chemical equation for the reaction that takes place between potassium hydroxide and iron (III) acetate can be represented as follows;3KOH + Fe(C2H3O2)3 → Fe(OH)3 + 3KC2H3O2The molar mass of Fe(OH)3 is calculated as follows;Molar mass of Fe(OH)3 = Atomic mass of Fe + (3 x Atomic mass of O) + (3 x Atomic mass of H) = (55.85 g/mol) + (3 x 16 g/mol) + (3 x 1 g/mol) = 106.85 g/molThus the molar mass of Fe(OH)3 is 106.85 g/mol.To determine the theoretical yield of Iron (III) hydroxide we must first determine the limiting reactant (the reactant that is fully consumed in the reaction) among potassium hydroxide and iron (III) acetate.Limiting ReactantIn order to find out the limiting reactant among potassium hydroxide and iron (III) acetate, we will first find out the number of moles of each using the formula;Moles = Concentration x Volume in Liters (L)Moles of KOH = Concentration of KOH × Volume of KOH = 5 M × (98.1 mL/1000 mL) = 0.4905 moles Moles of Fe(C2H3O2)3 = Concentration of Fe(C2H3O2)3 × Volume of Fe(C2H3O2)3 = 4.5 M × (39.9 mL/1000 mL) = 0.17955 molesBased on the balanced chemical equation, the mole ratio of KOH to Fe(C2H3O2)3 is 3:1. Hence, the limiting reactant is Fe(C2H3O2)3 since it is lesser in moles compared to KOH. This means that all of the 0.17955 moles of Fe(C2H3O2)3 will be consumed in the reaction while 0.4905 - (0.17955 x 3) = 0.05145 moles of KOH will be left over after the reaction is complete.The theoretical yield is then calculated using the limiting reactant. We can calculate the number of moles of Fe(OH)3 produced from 0.17955 moles of Fe(C2H3O2)3 using the balanced chemical equation. The mole ratio of Fe(C2H3O2)3 to Fe(OH)3 is 1:1. Hence;Moles of Fe(OH)3 = Moles of Fe(C2H3O2)3 = 0.17955 moles. The mass of Fe(OH)3 is then calculated using the formula;Mass = Number of moles × Molar massMass of Fe(OH)3 = Number of moles of Fe(OH)3 × Molar mass of Fe(OH)3 = 0.17955 moles × 106.85 g/mol = 19.179 gTherefore, the theoretical yield of Fe(OH)3 is 19.179 g.

The theoretical yield of iron (III) hydroxide is 19.19 grams.

The balanced chemical equation for the reaction between potassium hydroxide and iron (III) acetate is:

3 KOH + Fe(C₂H₃O₂)₃ → Fe(OH)₃ + 3 KC₂H₃O₂

To calculate the theoretical yield of iron (iii) hydroxide, first, we determine the limiting reagent.

The number of moles of each reactant:

Number of moles (n) = Molarity (M) × Volume (V)

For potassium hydroxide (KOH):

n(KOH) = 5 M × 0.0981 L

number of moles = 0.4905 moles

For iron (III) acetate (Fe(C₂H₃O₂)₃):

number of moles = 4.5 M × 0.0399 L

number of moles = 0.17955 moles

Since the stoichiometric ratio is 1:1, the number of moles of Fe(OH)₃ = 0.17955 moles.

The molar mass of Fe(OH)₃ = 106.88 g/mol

Theoretical yield = Number of moles × Molar mass

Theoretical yield = 0.17955 moles × 106.88 g/mol

Theoretical yield= 19.19 grams

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55.03 moles of KCI are produced when 6743 grams of \(KClO_{3}\) decomposes

To determine the number of moles of KCl produced when 6743 grams of \(KClO_{3}\) decomposes, we need to use the concept of molar mass and the balanced chemical equation.

First, let's calculate the molar mass of \(KClO_{3}\)

The molar mass of potassium (K) is approximately 39.10 g/mol.

The molar mass of chlorine (Cl) is approximately 35.45 g/mol.

The molar mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of \(KClO_{3}\) is:

(39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol.

Now, we need to calculate the number of moles of \(KClO_{3}\):

Number of moles = Mass / Molar mass

Number of moles = 6743 g / 122.55 g/mol = 55.03 mol.

According to the balanced chemical equation:

2\(KClO_{3}\) -> 2 KCl + 3 O2,

we can see that for every 2 moles of \(KClO_{3}\), we obtain 2 moles of KCl.

Therefore, the number of moles of KCl produced will be equal to the number of moles of \(KClO_{3}\) since the ratio is 1:1. Thus, 55.03 moles of KCl will be produced.

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Answer: 51.86

Explanation:

Total, 46.86 grams of antique brass can be made from 18.0 grams of zinc and 32.8 grams of copper.

To find out how much antique brass can be made from the given amounts of zinc and copper, we need to determine the limiting reactant in the reaction between zinc and copper.

Calculate the number of moles for each element.

Given:

Mass of zinc (Zn) = 18.0 grams

Mass of copper (Cu) = 32.8 grams

Molar mass of zinc (Zn) = 65.38 g/mol

Molar mass of copper (Cu) = 63.55 g/mol

Number of moles of zinc (Zn) = Mass of zinc / Molar mass of zinc

Number of moles of zinc (Zn) = 18.0 g / 65.38 g/mol

≈ 0.2755 moles

Number of moles of copper (Cu) = Mass of copper / Molar mass of copper

Number of moles of copper (Cu) = 32.8 g / 63.55 g/mol

≈ 0.5161 moles

Determine the limiting reactant.

The mole ratio between zinc and copper in antique brass is 30.0% zinc and 70.0% copper, which is approximately a 3:7 ratio.

Zn : Cu = 0.2755 moles : 0.5161 moles

≈ 1 : 1.87

Since the mole ratio between zinc and copper is approximately 1:1.87, the copper is the limiting reactant as it is closer to the 70% required for antique brass.

Calculate the mass of antique brass.

To calculate the mass of antique brass, we will use the mass of copper (the limiting reactant) since it determines the maximum amount of product that can be formed.

Mass of antique brass = Mass of copper / Percentage of copper in antique brass

Mass of antique brass = 32.8 g / 0.70

≈ 46.86 grams

Therefore, approximately 46.86 grams of antique brass can be made from 18.0 grams of zinc and 32.8 grams of copper.

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Answer:

Explanation:

If a zero is found between significant digits, it is significant

Answer:

C) one magnesium and one oxygen

The reaction of 2-Bromo-2-Ethyl-3-Methylbutane with methanol is an example of a nucleophilic substitution reaction.

In this reaction, the methanol molecule acts as a nucleophile and attacks the carbon atom of the bromoalkane, resulting in the displacement of the leaving group (bromine) and the formation of a new carbon-oxygen (C-O) bond.

The reaction mechanism can be described as follows:

Protonation: In the first step, the methanol molecule acts as a base and abstracts a proton from the sulfuric acid catalyst to form the methoxide ion (CH3O-).

Nucleophilic attack: The methoxide ion then attacks the carbon atom of the bromoalkane, which is electrophilic due to the electron-withdrawing effect of the bromine atom. The attack results in the formation of a transition state in which the carbon-bromine bond is weakened and the carbon-oxygen bond is forming.

Elimination: The transition state then collapses to form the product, methylethylmethylcarbinol, with the simultaneous loss of the bromide ion. This step is known as the elimination step and occurs as the newly formed C-O bond is more stable than the weakened C-Br bond.

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Answer:

it is a weak acid

acid

Explanation:

formaldehyde is a weak acid (pK greater than 13),

The change in internal energy = 2.701 x 10² kJ

Given

Heat absorbed by system = 1.69 x 10² kJ

Work done on system = 1.011 x 10² kJ

Required

The change in Internal energy

Solution

We can use the first law of Thermodynamics :

\(\tt \Delta U=Q+W\)

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

Heat absorbed/receive heat from surrounding = Q+

Work done on the system = W+

and input the given values

\(\tt \Delta U= 1.69\times 10^2+1.011\times 10^2\\\\\Delta U=\boxed{\bold{2.701\times 10^2~kJ}}\)

Since HCl is a polar molecule, there will be attraction between the the positive end of the dipole in one molecule and the negative end of the dipole in another molecule.

Polar molecules are those molecules in which there is a high difference in electronegativity between the bonding atoms. This results in the appearance of partial charges in the molecule. One end of the molecule has a partial negative charge and the other end of the molecule has a partial positive charge.

Since HCl is a polar molecule, there will be attraction between the positive end of one molecule and the negative end of another molecule.

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Barium chloride turned from sparkly white into dull white during the heating process.

An inorganic substance with the formula BaCl2 is barium chloride. It is among the most popular barium salts that dissolve in water. Like the majority of some of the other water-soluble barium salts, is also white, extremely hazardous, and gives flames a yellow-green tint.

Among the most common barium salts is barium chloride. Bacl2 is hygroscopic and soluble in water. Deep hypokalemia, generalized muscle weakness, and eventually paralysis of the limbs and breathing muscles can occur within 1 to 4 hours of consumption.

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Answer: It’s correct because it’s showing an exothermic reaction. x is the reactants and y is the products.

Explanation: -ΔH means the reaction is exothermic and releasing heat. This lowers the potential energy.

Answer:

answer above is correct

Explanation:

la tierra nuestro planeta es el único del sistema solar que sabe que mantiene vida: vida que es increíblemente diversa,

Answer:

The final pressure is 90.1 atm.

Explanation:

Assuming constant temperature, we can solve this problem by using Boyle's Law, which states:

Where in this case:

We input the given data:

And solve for P₂:

The final pressure is 90.1 atm.

Answer:

Yes, they work in space. I forgot an example, will edit the post when I found it

Hope this helps!