Your awnser is 8, 11 is half of 22 and 8 is half of 16
Hope that helps :)
At the local coffee shop, a small coffee costs $2.50 and a large coffee costs $3.75. Belinda picked up a total
of ten coffees for her team, and paid $33.75 total.
(a) Let x represent small coffees and let y represent large coffees. Write a system to model this situation
and solve it using graphing technology. Yea
Answer:
2.50x + 3.75y = 33.75
Step-by-step explanation:
Solve the equation for x 6x-18-3x<27-2x
Answer:
x<9
Step-by-step explanation:
h(x) = 4x +3. What is
the coordinate pair for h (1)?
9514 1404 393
Answer:
(1, 7)
Step-by-step explanation:
Fill in x=1 and do the arithmetic.
h(1) = 4(1) +3 = 7
The coordinate pair is ...
(x, h(x)) = (1, h(1)) = (1, 7)
help plz..............
Answer:
-20
Step-by-step explanation:say hes on 0 when he moves back 4 hes on -4 when he moves back 4 ore hes on -8 move back 4 more -12 move back 4 more -16 then move back 4 more -20
A production line is equipped with two quality control check points that tests all items on the line. At check point =1, 10% of all items failed the test. At check point =2, 12% of all items failed the test. We also know that 3% of all items failed both tests. A. If an item failed at check point #1, what is the probability that it also failed at check point #22 B. If an item failed at check point #2, what is the probability that it also failed at check point =12 C. What is the probability that an item failed at check point #1 or at check point #2? D. What is the probability that an item failed at neither of the check points ?
The probabilities as follows:
A. P(F2|F1) = 0.3 (30%)
B. P(F1|F2) = 0.25 (25%)
C. P(F1 or F2) = 0.19 (19%)
D. P(not F1 and not F2) = 0.81 (81%)
To solve this problem, we can use the concept of conditional probability and the principle of inclusion-exclusion.
Given:
P(F1) = 0.10 (Probability of failing at Check Point 1)
P(F2) = 0.12 (Probability of failing at Check Point 2)
P(F1 and F2) = 0.03 (Probability of failing at both Check Point 1 and Check Point 2)
A. To find the probability that an item failed at Check Point 1 and also failed at Check Point 2 (F2|F1), we use the formula for conditional probability:
P(F2|F1) = P(F1 and F2) / P(F1)
Substituting the given values:
P(F2|F1) = 0.03 / 0.10
P(F2|F1) = 0.3
Therefore, the probability that an item failed at Check Point 1 and also failed at Check Point 2 is 0.3 or 30%.
B. To find the probability that an item failed at Check Point 2 given that it failed at Check Point 1 (F1|F2), we use the same formula:
P(F1|F2) = P(F1 and F2) / P(F2)
Substituting the given values:
P(F1|F2) = 0.03 / 0.12
P(F1|F2) = 0.25
Therefore, the probability that an item failed at Check Point 2 and also failed at Check Point 1 is 0.25 or 25%.
C. To find the probability that an item failed at either Check Point 1 or Check Point 2 (F1 or F2), we can use the principle of inclusion-exclusion:
P(F1 or F2) = P(F1) + P(F2) - P(F1 and F2)
Substituting the given values:
P(F1 or F2) =\(0.10 + 0.12 - 0.03\)
P(F1 or F2) = 0.19
Therefore, the probability that an item failed at either Check Point 1 or Check Point 2 is 0.19 or 19%.
D. To find the probability that an item failed at neither of the check points (not F1 and not F2), we can subtract the probability of failing from 1:
P(not F1 and not F2) = 1 - P(F1 or F2)
Substituting the previously calculated value:
P(not F1 and not F2) = 1 - 0.19
P(not F1 and not F2) = 0.81
Therefore, the probability that an item failed at neither Check Point 1 nor Check Point 2 is 0.81 or 81%.
In conclusion, we have calculated the probabilities as follows:
A. P(F2|F1) = 0.3 (30%)
B. P(F1|F2) = 0.25 (25%)
C. P(F1 or F2) = 0.19 (19%)
D. P(not F1 and not F2) = 0.81 (81%)
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which of the following shapes are squares? please answer correctly I'll mark brainliest
All are technically squares, but if you are referring to just squares, then C and D are squares.
a knowledge of statistics helps us make decisions based on ______ evidence.
Empirical, A knowledge of statistics is essential for anyone who wants to make informed decisions based on empirical evidence.
A knowledge of statistics helps us make decisions based on empirical evidence. Empirical evidence is data that has been collected through observation and experimentation, and statistics is a method for analyzing and interpreting this data. By using statistical tools and techniques, we can draw conclusions from empirical evidence and make informed decisions based on this information.
Statistics plays a crucial role in modern society, from medicine and public policy to business and finance. A knowledge of statistics enables individuals to understand and analyze data, to make informed decisions based on empirical evidence, and to communicate findings to others. Statistics helps us to quantify uncertainty and variability, to identify patterns and trends, and to make predictions based on past data. By using statistical methods, we can determine the probability of certain outcomes, assess risks and benefits, and evaluate the effectiveness of interventions or policies. For example, in medical research, statistics is used to test the effectiveness of new treatments or therapies, to determine the safety of drugs, and to identify risk factors for diseases. In public policy, statistics is used to analyze demographic trends, to assess the impact of social programs, and to inform decision-making around issues such as climate change or public health.
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How many inches are equal to 12 cm ?
Answer:
12/2.54 ≈ 4.72 inches
Harry Potter has a potion that can change voracious vampires into harmless hobbits. But the chemical evaporates over time and when the concentration in the potion is too weak, it turns the vampires into destructive Demogorgons. Oh no! The half-life of the potion means the amount of time it takes for the potion to lose half of its existing power, measured in magical units. This potion has a half-life of 2 months. Which statement about the potion's strength is correct? * a. Of the original 160 magical units, 5 magical units are left after 10 months of mixing the potion. b. Of the original 160 magical units, 16 magical units are left after 10 months of mixing the potion. c. Of the original 160 magical units, less than 1 magical unit is left after 10 months of mixing the potion. d. Of the original 160 magical units, 20 magical units are left after 10 months of mixing the potion e. Of the original 160 magical units, 80 magical units are left after 10 months of mixing the potion.
Answer:
im going to say c
Step-by-step explanation:
if its has 160 units and goes to half-life after 2 months im assuming it loses 1/2 of the units so in order for it to lose that many it will have to lose 40 units a month so i say its c after 10 months there will be less than 1 unit in the potion
hope this helps im sorry if im wrong have a blessed day :)
Solve for A.
-11 + a/15= -13
Please show work.
Answer:
A/15 = -13+11
A/5=-2
A= -2*5
A = -10
Answer:
-30
Step-by-step explanation:
-11+a/15=-13
a/15=-13-(-11)
a/15=-13+11
a/15=-2
a=-2*15
a=-30
Find the first quartile (Q1) of the data set below.
{99, 88, 88, 91, 92, 100}
89.5
0 95.5
O 88
0.99
Determine number of solutions
How many signals are produced by each of the following compounds in its a. 'H NME spectram? b. "C NMR spectrum? 1. 2. 48. Draw a spluting diagram for the H b proton and give its multiplicity if a. f k,
=f h
. b. J k
=2J h
-
Part a. H NMR and C NMR spectra signals of compounds A signal is characterized by its position (chemical shift), intensity (peak area), and multiplicity (splitting pattern).
One signal appears at a higher frequency (δ = 160 ppm) and the other at a lower frequency (δ = 20 ppm).Part b. Splitting diagram for the H b proton and its multiplicityThe splitting diagram is created based on the number of neighboring protons, n, to the H b proton. Then, its multiplicity is determined by applying n+1 rule: $$\text{Multiplicity}
=n+1.$$For f k
= f h, H b proton is split into a septet with seven peaks since it has six neighboring protons (n
= 6).For J k
= 2J h, H b proton is split into a quartet with four peaks since it has three neighboring protons (n
= 3).Here is the splitting diagram for the H b proton: Splitting diagram for the H b proton
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how to do this and the answers.
Answer:
I'm gonna estimate about 240 miles one way
Explanation:
You have a guide on the bottom right-hand corner of the map that tells you how many miles per that amount of distance. As you can see it is split off into tiles incremented by 30. What you do is take a ruler and measure that guide. For example, let's say the map is 9.5cm and the guide is 2cm per 60 miles. The next thing I would do is to measure the distance in centimeters of the physical map between point a and point b which is 8cm. Finally, I convert the centimeters into miles which is (8/2)*60 = 240.
Share 720cm in the ratio 3:4:2:9
Answer:
120 cm, 160 cm, 80 cm, 360 cm
Step-by-step explanation:
The ratio 3:4:2:9 is the same as the ratio 3x:4x:2x:9x
We add all the terms of the second ratio:
3x + 4x + 2x + 9x = 18x
18x = 720
x = 40
3x = 3(40) = 120
4x = 4(40) = 160
2x = 2(40) = 80
9x = 9(40) = 360
Answer: 120 cm, 160 cm, 80 cm, 360 cm
a rectangle is drawn with its adjacent sides chosen from independent and identically distributed uniform distributions over the interval (0,1) . What is the probability that the area of the rectangle is more than 0.5
Let X and Y be random variables representing the side lengths of the rectangle. Then the area of the rectangle is given by the random variable XY.
We have
\(\displaystyle P(XY > 0.5) = \int_{0.5}^1 \int_{0.5/y}^1 dx \, dy \\\\ = \int_{0.5}^1 \left(1-\frac1{2y}\right) \, dy \\\\ = \left(1 - \frac12 \ln(1)\right) - \left(\frac12 - \frac12 \ln\left(\frac12\right)\right) \\\\ = \boxed{\frac{1-\ln(2)}2}\)
or approximately 0.1534.
We want to find the probability that the area of the rectangle is more than 0.5, we will see that the probability is P ≈ 0.1534
We know that the area of a rectangle of length L and width W is given by:
A = L*W
In this case, if we know that:
L can be any value between (0, 1)W can be any value between (0, 1)And we know that the probabilities are equally distributed.
So we impose:
L*W > 0.5
Then we define a lower limit for W as a function of L as:
W = 0.5/L
Then we just compute the lower bound (which is an approximation) of the probability by integrating:
\(P = \int\limits^1_{0.5} \int\limits^1_{0.5/L} dLdW\)
We can rewrite this as:
\(P = \int\limits^1_{0.5} ({1 - \frac{1}{2L} } )\, dL\)
\(P = (1 - 0.5) - (1/2)*(Ln(1) - Ln(0.5))\\\\P = 0.5 - (1/2)*(Ln(1/0.5))\\\\P = 0.5 - (1/2)*Ln(2) = 0.5*(1 - ln(2)) = 0.1534\)
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find the sum of the first 6 terms of the following sequence. round to the nearest hundredth if necessary. 100 , 122 , 148.84 , . . . 100,122,148.84,...
To find the sum of the first 6 terms of the given sequence, we need to identify the pattern and use it to calculate the terms.
Looking at the sequence, we can observe that each term is obtained by adding the square root of the previous term to the previous term. Let's calculate the terms of the sequence:
First term: 100
Second term: 100 + √100 = 100 + 10 = 110
Third term: 110 + √110 ≈ 110 + 10.49 ≈ 120.49
Fourth term: 120.49 + √120.49 ≈ 120.49 + 10.97 ≈ 131.46
Fifth term: 131.46 + √131.46 ≈ 131.46 + 11.46 ≈ 142.92
Sixth term: 142.92 + √142.92 ≈ 142.92 + 11.95 ≈ 154.87
Now, let's calculate the sum of the first 6 terms:
Sum = 100 + 110 + 120.49 + 131.46 + 142.92 + 154.87 ≈ 759.74
Rounding to the nearest hundredth, the sum of the first 6 terms of the sequence is approximately 759.74.
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7. A vehicle smoke emission testing facility claims that 85% of three-year-old sedans pass the smoke emission testing. If the assertion is correct, out of eight three-year-old sedans, a. find the probability that fewer than half pass the smoke emission testing. b. find the probability that all pass the smoke emission testing. c. Illustrate the PMF plot. 8. A civil engineering experiment was conducted to optimize the procedure of manufacturing bricks using clay deposits excavated from a quarry site. In the investigation, the factorial design was made by varying the percentage of illite (high and low), the percentage of smectite (high and low), and the bricks compacting pressure (high and low). Enumerate all the possible treatments.
a. The probability that fewer than half of the eight three-year-old sedans pass the smoke emission testing is approximately 0.034.
b. The probability that all eight three-year-old sedans pass the smoke emission testing is approximately 0.082.
c. The PMF plot illustrates the probabilities of different outcomes for the number of sedans that pass the smoke emission testing.
a. To find the probability that fewer than half of the eight sedans pass the smoke emission testing, we need to calculate the cumulative probability for 0, 1, 2, 3, or 4 sedans passing. We can use the binomial distribution formula to calculate the individual probabilities and sum them up. Using this approach, the probability is approximately 0.034.
b. To find the probability that all eight sedans pass the smoke emission testing, we can use the binomial distribution formula directly. Since the probability of each sedan passing is 0.85, the probability that all eight sedans pass is approximately 0.082.
c. The PMF (Probability Mass Function) plot shows the probabilities of different outcomes for the number of sedans that pass the smoke emission testing. The x-axis represents the number of sedans passing (ranging from 0 to 8), and the y-axis represents the corresponding probabilities. The PMF plot will show a decreasing trend as the number of sedans passing increases, with the highest probability occurring at the expected value (in this case, 85% of eight sedans, which is approximately 6.8). The plot will exhibit a symmetric distribution due to the equal probability of passing or failing the smoke emission testing.
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Question 2 50 pts A custodian plans to repaint some classroom bookcases. She has 5 1 4 gallons of paint. All of the bookcases are the same size and each requires 3 4 gallon of paint. How many bookcases will the custodian be able to repaint with that amount of paint?
Answer:
sorry I wish I could help but I'm stupid
4. Two TV shows each asked 100 viewers for their ages. For one show, the
mean age of the viewers was 35 years and the MAD was 20 years. For the
other show, the mean age of the viewers was 30 years and the MAD was
5 years.
A sixth-grade student says he watches one of the shows. Which show do
you think he watches? Explain your reasoning. (Lesson 8-12)
Drawing conclusions, predicting the future, or developing an explanation are all examples of reasoning.
Does reasoning mean thinking?Using particular examples to support a sound inference is the process of reasoning. This strategy relies on specific examples 1, 2, and 3 to draw a broad generalisation about the entire case. For instance, my Sony stereo, car radio, television, and video system are all in good working order.
A conclusion, a prediction, or an explanation can be reached by utilising knowledge already at hand in the reasoning process. Deductive, inductive, and abductive techniques of reasoning are three different types.
Deductive, inductive, abductive, and analogous reasoning will be the four types of reasoning we will be concentrating on in this article. A logical, deliberate technique of thinking is reasoning.
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does the
The fraction 1/12
is equivalent to a decimal that terminates or does not terminate
Answer:
does not terminate
Step-by-step explanation
1/12 = 0.0833333333333333333333333333333333333333333
it continues. Hence it is does not terminate.
Find mZSGH if mZFGH = 108°
Answer:
22
Step-by-step explanation:
FGH - FGS = SGH
108 - 86 = 22
Answer:
∠ SGH = 22°
Step-by-step explanation:
∠ FGS + ∠ SGH = ∠ FGH , that is
86° + ∠ SGH = 108° ( subtract 86° from both sides )
∠ SGH = 22°
a small community consists of 20 women, each of whom has 5 children. if one woman and one of her children are to be chosen as mother and child of the year, how many different choices are possible?
By probability, 5 different choices are possible .
Describe probability using an example?
A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.
The likelihood of an event occurring increases as its probability increases. The flip of a fair (impartial) coin serves as a straightforward illustration.
According to the situation, The probabilities for each one is given below
As there are 20 families
So the probabilities for each one is
For four families have one child is
= 1/20
For eight families have two children is
= 2/20 = 1/10
For five families have three children is
= 3/20
For two families have four children is
= 4/20 = 1/5
For one family have five children is
= 5/20 = 1/4
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what is one fifth of the difference of a number and 1
Answer:
1/5(1-x)
Step-by-step explanation:
Distributed
1/5-1/5x
Answer:1/5 (n-1)
Step-by-step explanation: Because say 1/5 and difference means subtract and number means variable and 1 means subtract it with the variable.
9
Kim is 5 years older than Scott.
Kim's mum is 3 times Kim's age.
Scott's dad is 3 times Scott's age.
How much older is Kim's mum than Scott's dad?
Answer: 15 years
Step-by-step explanation:
Given : Kim is 5 years older than Scott.
Kim's mum is 3 times Kim's age.
Scott's dad is 3 times Scott's age.
Let age of Scott = y years
Then Kim's age = (y+5) years
Kim's mum age = \(3\times (y+5)=3y+15\) years
Scott's Dad age = \(3\times y=3y\) years
Difference between Kim's mum age and Scott's Dad age = Kim's mum age - Scott's Dad age = (3y+15) - (3y) = 15
Thus Kim's mum is 15 years older than Scott's dad.
Answer:
15
Step-by-step explanation:
Kim . Scott
+5 (y+5) -5 . (y)
let's give them a random age
Kim . Scott
16 . 11
Mum Dad x3
48 . 33
48-33=15
So Kim's mum is 15 years older than Scott's dad
In each of the following situations, a significance test for a population mean µ is called for. State the null hypothesis H0 and the alternative hypothesis Ha in each case. Then, assume p=0.02. State the decision that should be made based upon this p-value. Be sure to justify your decision.
a) Experiments on learning in animals sometimes measure how long it takes a mouse to find its way through a maze. The mean time is 18 seconds for one particular maze. A researcher thinks that a loud noise will cause the mice to complete the maze faster. She measures how long each of 10 mice takes with a noise as stimulus.
b) The examinations in a large accounting class are scaled after grading so that the mean score is 50. A self-confident teaching assistant thinks that his students have a higher mean score than the class as a whole. His students this semester can be considered a sample from the population of all students he might teach, so he compares their mean score with 50.
c) A university awards credit in French language courses to students who pass a placement test. The language department wants to know if students who get credit in this way differ in their understanding of spoken French from students who actually take the French courses. Some faculty think the students who test out of the courses are better, but others argue that they are weaker in oral comprehension. Experience has shown that the mean score of students in the courses on a standard listening test is 24. The language department gives the same listening test to a sample of 40 students who passed the credit examination to see if their performance is different
(expert answer asks for more information, but this is all that was given. There was no more significance testing information given)
The null hypothesis (H0) and alternative hypothesis (Ha) for each situation are a) H0: µ = 18 Ha: µ < 18 b) H0: µ = 50 Ha: µ > 50 c) H0: µ = 24 Ha: µ ≠ 24. Based on the given p-value of 0.02, the decision for each situation are a) Since p < 0.05, we reject the null hypothesis b) Since p < 0.05, we reject the null hypothesis c) Since p < 0.05, we reject the null hypothesis.
The null hypothesis (H0) and alternative hypothesis (Ha) for each situation are as follows:
a) H0: µ = 18 (the mean time for mice to complete the maze is equal to 18 seconds)
Ha: µ < 18 (the mean time for mice to complete the maze is less than 18 seconds)
b) H0: µ = 50 (the mean score for the teaching assistant's students is equal to 50)
Ha: µ > 50 (the mean score for the teaching assistant's students is greater than 50)
c) H0: µ = 24 (the mean score for students who passed the credit examination is equal to 24)
Ha: µ ≠ 24 (the mean score for students who passed the credit examination is not equal to 24)
Based on the given p-value of 0.02, the decision for each situation is as follows:
a) Since p < 0.05, we reject the null hypothesis and conclude that the loud noise does cause the mice to complete the maze faster.
b) Since p < 0.05, we reject the null hypothesis and conclude that the teaching assistant's students do have a higher mean score than the class as a whole.
c) Since p < 0.05, we reject the null hypothesis and conclude that the students who passed the credit examination do differ in their understanding of spoken French from students who actually take the French courses.
These decisions are justified because a p-value less than 0.05 indicates that there is a statistically significant difference between the sample mean and the population mean, and therefore we can reject the null hypothesis and accept the alternative hypothesis.
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what is the value of the equation g(^x-1) -2 =25
Find the area of a semicircle with a radius of 6
Answer: => 56.52 cm²
Step-by-step explanation:
Solve the differential equations 2xy(dy/dx)=1 y^2. y(2)=3
The solution to the given differential equation 2xy(dy/dx) = y², with the initial condition y(2) = 3, is y = (27 * e⁽ˣ⁻²⁾\()^{1/4}\).
To solve the given differential equation
2xy(dy/dx) = y²
We will use separation of variables and integrate to find the solution.
Start with the given equation
2xy(dy/dx) = y²
Divide both sides by y²:
(2x/y) dy = dx
Integrate both sides:
∫(2x/y) dy = ∫dx
Integrating the left side requires a substitution. Let u = y², then du = 2y dy:
∫(2x/u) du = ∫dx
2∫(x/u) du = ∫dx
2 ln|u| = x + C
Replacing u with y²:
2 ln|y²| = x + C
Using the properties of logarithms:
ln|y⁴| = x + C
Exponentiating both sides:
|y⁴| = \(e^{x + C}\)
Since the absolute value is taken, we can remove it and incorporate the constant of integration
y⁴ = \(e^{x + C}\)
Simplifying, let A = \(e^C:\)
y^4 = A * eˣ
Taking the fourth root of both sides:
y = (A * eˣ\()^{1/4}\)
Now we can incorporate the initial condition y(2) = 3
3 = (A * e²\()^{1/4}\)
Cubing both sides:
27 = A * e²
Solving for A:
A = 27 / e²
Finally, substituting A back into the solution
y = ((27 / e²) * eˣ\()^{1/4}\)
Simplifying further
y = (27 * e⁽ˣ⁻²⁾\()^{1/4}\)
Therefore, the solution to the given differential equation with the initial condition y(2) = 3 is
y = (27 * e⁽ˣ⁻²⁾\()^{1/4}\)
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What is an estimate for the square root of 150? (Do not find the exact value) Show work
Answer:
Somewhere between 12 and 13, perhaps 12.25
Step-by-step explanation:
This is a (rather) simple explanation:
Look for 2 square numbers that are either side of 150
In this case, it is 144 and 169
The square root of 144 is 12 and the square root of 169 is 13
Therefore we can estimate that the square root of 150 is somewhere between 12 and 13.
As 150 is a lot closer to 144 to 169, I would estimate around 12.25 but you do not need an exact value :)