Melvina has a mass of 70 kg and is about to jump from the window ledge of a burning building.
The ledge is 80 m above the ground. What is Melvina's potential energy?

Answers

Answer 1

Melvina's potential energy is 54,880 Joules.

To calculate Melvina's potential energy, we need to use the formula for gravitational potential energy:

Potential energy = mass × gravitational acceleration × height

Potential energy is a measure of the energy an object possesses due to its position relative to other objects. In this case, Melvina's potential energy is a result of her height above the ground. As she stands on the ledge of the burning building, her potential energy is stored and can be converted into other forms of energy if she were to jump or fall. The potential energy will decrease as she descends, and it will be converted into kinetic energy (energy of motion).

Given that Melvina has a mass of 70 kg and the ledge is 80 m above the ground, we can substitute the values into the formula:

Potential energy = 70 kg × 9.8 m/s² × 80 m

Calculating this, we find:

Potential energy = 54,880 Joules

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Related Questions

A commuter backs her car out of her garage with a constant acceleration of 1.20 m/s2. (a) How long in seconds does it take her to reach a speed of 1.90 m/s

Answers

The time in seconds it will take her to reach a speed of 1.9 m/s is 1.58s.

What is time?:

Time can be defined as the measurable period or duration, during which an action, process, or condition exists or continue.

The time taken for the commuter to reach a speed of 1.9 m/s, can be calculated using the formula below.

Formula:

a = (v-u)/t................. Equation 1

Where:

a = acceleration of the commuterv = final velocity of the commuteru = initial velocity of the commutert = time taken for the commuter to reach the speed.

make t the subject of equation 1

t = (v-u)/a................. Equation 2

From the question,

Given:

v = 1.90 m/sa = 1.2 m/s²u = 0 m/s

Substitute these values into equation 1.

t = (1.9-0)/1.2t = 1.58 s.

Hence, The time in seconds it will take her to reach a speed of 1.9 m/s is 1.58s

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PS Final Exam
What type of friction exists between a moving car's tires and the road?
O rolling friction
O static friction
O sliding friction

Answers

Answer:

rolling friction

Explanation:

A participant reported migraine headache and missed work for a day

Answers

Explanation:

do you understand it now

A participant reported migraine headache and missed work for a day

The effective spring constant describing the potential energy of the HBr molecule is 410 N/m and that for the NO molecule is 1530 N/m.A) Calculate the minimum amplitude of vibration for the NO molecule.
B) Calculate the minimum amplitude of vibration for the HCl molecule.

Answers

Answer:

a. the minimum amplitude of vibration for the NO molecule A \(\simeq\) 4.9378 pm

b. the minimum amplitude of vibration for the HCl molecule A \(\simeq\) 10.9336 pm

Explanation:

Given that:

The effective spring constant describing the potential energy of the HBr molecule is 410 N/m

The effective spring constant describing the potential energy of the NO molecule is 1530 N/m

To calculate the minimum amplitude of vibration for the NO molecule, we use the formula:

\(\dfrac{1}{2}kA^2= \dfrac{1}{2}hf\)

\(kA^2= hf\)

\(A^2= \dfrac{hf}{k}\)

\(A = \sqrt{\dfrac{hf}{k}}\)

\(A = \sqrt{\dfrac{(6.626 \times 10^{-34} \ J. s ) ( 5.63 \times 10^{13} \ s^{-1})}{1530 \ N/m}}\)

\(A = \sqrt{\dfrac{3.730438 \times 10^{-20} \ m}{1530 }\)

\(A = \sqrt{2.43819477 \times 10^{-23}\ m\)

\(A =4.93780799 \times 10^{-12} \ m\)

A \(\simeq\) 4.9378 pm

The effective spring constant describing the potential energy of the HCl molecule is 480 N/m

To calculate the minimum amplitude using the  same formula above, we have:

\(A = \sqrt{\dfrac{hf}{k}}\)

\(A = \sqrt{\dfrac{(6.626 \times 10^{-34} \ J. s ) ( 8.66 \times 10^{13} \ s^{-1})}{480 \ N/m}}\)

\(A = \sqrt{\dfrac{5.738116\times 10^{-20} \ m}{480 }\)

\(A = \sqrt{1.19544083\times 10^{-22}\ m\)

\(A = 1.09336217 \times 10^{-11} \ m\)

\(A = 10.9336217 \times 10^{-12} \ m\)

A \(\simeq\) 10.9336 pm

what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm​

Answers

Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

Fill in the magnitude of net force for each case. Including the solution plss

Fill in the magnitude of net force for each case. Including the solution plss

Answers

Net forces in all above cases will be

A) F net = 0

B) F net = 1 N

C) F net = 5 N

D) F net = 5N

E) F net  = 5 N

F) F net = 5 N

G) F net = 9.9 N

H) F net = 9.9 N

A) net force = upward force - downward force

                   = 4 - 4 = 0

B) net force = rightward force - leftward force = 4 - 3 = 1 N  

C) net force  

using Pythagoras theorem

F net =  \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N

D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N

E) balancing horizontal forces

   rightward force - leftward force  = 5 - 2 = 3 N

   using  Pythagoras theorem

   F net =  \(\sqrt{4^{2} + 3^{2} }\) = 5 N

F) balancing vertical forces

   -5 + 2 = -3 N

    using  Pythagoras theorem

     \(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N

G) using  Pythagoras theorem

    F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N

H ) balancing horizontal forces

     10 - 3 = 7 N

     \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N

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The brake in most cars makes use of a hydraulic system. This system consists of a fluid filled tube connected at each end to a piston. Assume that the piston attached to the brake pedal has a cross sectional area of 3 cm2 and the piston attached to the brake pad has a 2 cross section area of 15 cm . When you apply a force of 50 Newton to the piston attached to the brake pedal, how much will be the force at the brake pad

Answers

Answer:

The force at the brake pad = 250 N

Explanation:

The hydraulic brake system works on the Pascal's Principle for pressure transmission in fluids; the pressure applied to a fluid is transmitted undiminished in all directions.

For hydraulic systems, the pressure applied to the brake pedal is transmitted undiminished through the fluid filled tube, connected at each end to a piston, to the brake pad.

Hence, mathematically,

P(brake pedal) = P(break pad)

Pressure is given as the force applied divided by the cross sectional Area perpendicular to the direction of applied force.

P(brake pedal) = (Force applied on the brake pedal) ÷ (Cross Sectional Area of the brake pedal)

Force applied on the brake pedal = 50 N

Cross Sectional Area of the brake pedal = 3 cm²

P(brake pedal) = (50/3) = 16.67 N/cm²

P(brake pad) = P(brake pedal) = 16.67 N/cm²

P(brake pad) = (Force applied on the brake pad) ÷ (Cross Sectional Area of the brake pad)

Force applied on the brake pad = F = ?

Cross Sectional Area of the brake pad = 15 cm²

16.67 = (F/15)

F = 16.67 × 15 = 250 N

Hence, the force at the brake pad = 250 N

Hope this Helps!!!

ayuden ha resolver este ejercicio porfa​

ayuden ha resolver este ejercicio porfa

Answers

Answer:

un café y a seguir pensando porque no se la respuesta xd

The course an object travels along is called DIRECTION.

A
TRUE

B
FALSE

Answers

Yes! It is A: True. Direction is...“a course set along which someone or *something* moves.”

Which of the following scenarios describes an object being acted on by a conservative force?
A. A woman hikes up a mountain to a point 20 feet above ground.
B. A dishwasher was pulled up to a window by a rope, using a pulley system.
C. A feather falls from one end of a tube to the other inside a vacuum.
D. A puck glides across and slowly comes to a stop on an ice rink.

Answers

A puck glides across and slowly comes to a stop on an ice rink describes an object being acted on by a conservative force

What is conservative force?

This is the type of force that is known to do work on an object. This force is known to conserve mechanical energy. The KE and the PE would have to remain fixed or constant here. Gravity and elastic forces are good examples.

In the option D, the puck goes up the rink. Then it slows down because of friction. The frictional force is not conservative in nature

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A standard 1 kilogram weight is a cylinder 47.0 mm in height and 49.0 mm in diameter. What is the density of the material

Answers

Answer:

11,627.91 kg/m^3

Explanation:

The computation of the density of the material is shown below

Given that

Mass , m = 1 kg

Height, H - 47 mm = 0.047 m

Diameter, d = 49 mm = 0.049 m

Now radius, r = D ÷ 2

= 0.049 ÷ 2

= 0.0245

Volume = πr^2h

= 3.14 × (0.0245)^2 × 0.047

= 0.000086m^3

Now the density of the material is

= mass ÷ volume

=  1÷  0.000086m^3

= 11,627.91 kg/m^3

Answer: 11,282.8 kg/m^3

Explanation:

We know:

Density = mass/volume

1 kg = mass

(π)(r^2)(h) = volume

Density = m/(πr^2h)

Plug in your values:

Density = 1kg/(π)(24.5 mm)^2(47 mm)

^we have to cut 49 (the diameter) in half because the equation calls for radius

Remember to multiply the density by 10^9 mm/ 1 m because the answer asks for kg/m^3

A 80 kg
bicyclist is coasting down a long hill that has a 5.0 ∘
slope. His cross-section area is 0.35 m2
, his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is 0.02, and the air temperature is 20∘C
.

Answers

the Speed reached by the bicyclist is given by, v = 26 m/s

What are the types of friction?

There are mainly four types of friction: static friction, sliding friction, rolling friction, and fluid friction. Friction and normal force are directly proportional to the contacting surfaces, and it doesn't depend on the hardness of the contacting surface.

Given that,

Gravitational acceleration = 9.81 m/s²

Mass of bicyclist = 80 kg

Slope(θ) = 5°

Cross-sectional area of bicyclist = 0.35 m²

μ = coefficient of rolling friction = 0.02

t = air temperature = 20 °C

Let ρ be the density of air at 20oC = 1.2041 kg/m3

ρ = 1.2041 kg/m3

We have the balancing equation:

F₁ = F₂ + F₃

where,

F₁ = component of the weight of the bicyclist down the plane,

F₂ = frictional force up the plane, and

F₃ = air drag force up the plane.

Thus, F₃ = F₁ - F₂

sinθ = sin(5°) = 0.087

cosθ = cos(5°) = 0.996

Now we will calculate the forces,

F₁ = m g sinθ = 80 kg x 9.81 m/s2 x 0.087 = 68.227 N

F₁ = 68.227 N

F₂ = μ m g cosθ = 0.02 x 80 kg x 9.81 m/s2 x 0.996 = 15.63 N

F₂ = 15.63 N

Put the values of F1 and F2 in eqn (1) and we get:

F₃ = F1 - F2

F₃ = 68.227 - 15.63

F₃ = 52.597 N

Let v be the speed reached by a bicyclist,

From the general formula of velocity:

V = ((2 xF₃ / (ρ x CD x A))1/2

v = ((2 x F₃ / (ρ x CD x A))1/2

v = ((2 x 120.78 N / (1.2041 kg/m3 x 0.85 x 0.35))1/2 = 25.97 m/s

v = 26 m/s

Therefore, the Speed reached by the bicyclist is given by, v = 26 m/s

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A8 kg ball is held at postam A before being rolled down the ramp below. Asume no energy is lost due to
Position
A
A-5m)
Position
B
(x-2m)
Position
C
As
h-5m
Kinetic Energy
B
h-2.5 m
Gravitational Potential Energy
C
h-0m
Total Energy

A8 kg ball is held at postam A before being rolled down the ramp below. Asume no energy is lost due toPositionAA-5m)PositionB(x-2m)PositionCAsh-5mKinetic

Answers

At position A, the ball has only potential energy due to its position above the ground.

The potential energy of the ball at position A is:

PE = mgh

where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the ball above the ground.

PE(A) = 8 kg * 9.8 m/s^2 * 5 m

PE(A) = 392 J

At position B, the ball has both kinetic and potential energy.

The potential energy of the ball at position B is:

PE = mgh

where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the ball above the ground.

PE(B) = 8 kg * 9.8 m/s^2 * 2.5 m

PE(B) = 196 J

The kinetic energy of the ball at position B is:

KE = (1/2)mv^2

where m is the mass of the ball and v is the velocity of the ball.

Since the ball is rolling down the ramp, we can use the conservation of energy principle to find the velocity of the ball at position B.

The total energy of the ball at position A is:

E(A) = PE(A)

E(A) = 392 J

The total energy of the ball at position B is:

E(B) = PE(B) + KE(B)

E(B) = 196 J + (1/2)(8 kg)v^2

E(B) = 196 J + 4v^2

Since energy is conserved, we have:

E(A) = E(B)

392 J = 196 J + 4v^2

196 J = 4v^2

v^2 = 49 m^2/s^2

v = 7 m/s

The kinetic energy of the ball at position B is:

KE(B) = (1/2)mv^2

KE(B) = (1/2)(8 kg)(7 m/s)^2

KE(B) = 196 J

At position C, the ball has only kinetic energy.

The potential energy of the ball at position C is zero since the ball is at ground level.

The kinetic energy of the ball at position C is:

KE(C) = (1/2)mv^2

KE(C

Which light behavior does this reperesent

Which light behavior does this reperesent

Answers

Answer:

Refraction

Explanation:

because the pencil looks magnified or distorted in water

Answer:

(B) Refraction

Explanation:

the fact or phenomenon of light being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.

In physics, refraction is the redirection of a wave as it passes from one medium to another. The redirection can be caused by the wave's change in speed or by a change in the medium.

Hope this helps!! :) (Also there is an example attached :D)

Which light behavior does this reperesent

The anomalous expansion characteristics of liquid water are crucial to many biological systems. Rather than an approximately constant value for the coefficient of volume expansion, the value for water changes drastically, as illustrated in the figure.

Below what temperature T
does water shrink when heated?

If the temperature of water at 30 ∘C
is raised by 1 ∘C
, the water will expand. At approximately what initial temperature T
will water expand by twice as much when raised by 1 ∘C
?

Answers

(A) The water will shrink when is heated above 4°C. (B).water at an initial temperature of 33.3°C will be expand by twice as much when it is raised by 1°C compared to water at 30°C.

The anomalous expansion of water refers to the fact that its volume increases upon cooling from 4°C to 0°C, and then contracts upon further cooling to 0°C, and continues to contract upon further cooling. Similarly, when water is heated, its volume first contracts until it reaches 4°C, and then expands upon further heating.

To determine at what temperature water shrinks when heated, we need to find the point at which the coefficient of volume expansion, β, becomes negative. The coefficient of volume expansion is defined as the fractional change in volume per degree Celsius change in temperature, i.e.,

β = (1/V)  (dV/dT)

where V is the volume of the water and dV/dT is the rate of change of volume with respect to temperature.

At temperatures below 4°C, the coefficient of volume expansion is positive, indicating that water expands upon heating. However, at temperatures above 4°C, the coefficient of volume expansion becomes negative, indicating that water contracts upon heating.

Therefore, water will shrink when heated above 4°C.

To determine the initial temperature at which water will expand by twice as much when raised by 1°C, we can use the formula for the coefficient of volume expansion:

β = (1/V)  (dV/dT)

We want to find the initial temperature T such that

(dV/dT)T = 2 (dV/dT)30

where (dV/dT)T is the rate of change of volume with respect to temperature at temperature T, and (dV/dT)30 is the rate of change of volume with respect to temperature at 30°C.

Using the coefficient of volume expansion for water, we have

β = 3α

where α is the coefficient of linear expansion, which is approximately constant for small temperature changes. Therefore, we can write

(dV/dT) = V × 3α

Substituting this into the equation above and simplifying, we get

T = 30 + 10/3 = 33.3°C

Therefore, water at an initial temperature of 33.3°C will expand by twice as much when raised by 1°C compared to water at 30°C.

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The anomalous expansion characteristics of liquid water are crucial to many biological systems. Rather

Write a hypothesis about the pH level of common household solutions based on what you know about their physical and chemical properties. Use the format of "if . . . then . . . because . . .” and be sure to answer the lesson question "How is pH used to determine if a solution is acidic or basic?

Answers

The terms "IF" and "THEN" are frequently used when writing the hypothesis. For instance, "I will not pass the test if I don't study." Your variables are reflected in the "if" and "then" lines. A solution is said to be acidic or basic depending on its pH value, which ranges from 7 to 14.

How are acids and bases classified using pH?

All compounds fall into one of three categories: basic (pH higher than 7), acid (pH or less 7), or neutral (pH about 7). The pH also indicates how powerful or weak the substance is. For instance, an item with a pH of 8 acts as a weak base, whereas an item with a pH of 3 is a powerful acid.

What is the theory behind the experiment in problem solving?

The hypothesis is essentially a prediction of what you believe will occur if you adopt a specific course of action to address an issue. The hypothesis often specifies what will change, what might result from the action, and why you believe the change is necessary.

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Steve is planning his annual Spring Break road trip. He pulls out his map and draws out his route to visit the five locations that he has planned for this year. They go in a counterclockwise loop and he ends up at home, where he started, just in time to start classes again. Whenever he is on the road he travels a constant 60 miles/hour. When Steve adds up the total distance traveled, as measured by his odometer, and divides it by the time that his trip took, he has measured what quantity?

a. His average velocity.
b. His average speed.
c. His instantaneous velocity.
d. His instantaneous speed.

Answers

Answer:

His average speed.

Explanation:

Average speed = Total distance travelled / total time .

In the given case odometer measures total distance travelled . Dividing it by time will give average speed .

Average velocity can not be the answer as it is measured by dividing displacement by time . Displacement here is zero because initial and final point are same . Instantaneous velocity is given by the speedometer . It keeps on changing all the time . It is actually speed at a particular point of time . It can not be average velocity or speed .

1 point What is the weight of a 40 kg child on Earth (g = 10 N/kg)? * O 400 N 400 KG a 4N​

Answers

Mass=40kgAcceleration=10N/kg

\(\\ \sf\longmapsto Force=Mass\times Acceleration\)

\(\\ \sf\longmapsto Force=40(10)\)

\(\\ \sf\longmapsto Force=400N\)

What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?

Answers

The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².

What is the moment of inertia?

This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².

From the question:

Mass,M =4.2kg

Radius, R=32Cm

The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:

moment of inertia, I =1/2MR²

I =\(\frac{1}{2}\) * 4.2 * 32²

  =2,150.4 kgm²

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The key insight that Bohr introduced to his model of the atom was that the angular momentum of the electron orbiting the nucleus was quantized. He introduced the postulate that the angular momentum could only come in quantities of nh/(2π), where h is Planck's constant and n is a nonnegative integer (0,1,2,3,…). Given this postulate, what are the allowable values for the velocity v of the electron in the Bohr atom? Recall that, in circular motion, angular momentum is given by the formula L= mvr.

Answers

Answer:

  v = \(n \frac{\hbar }{m r}\)

the sppedof the electron is also quantized

Explanation:

The angular momentum of a rotating body is

         L = m v r

in Bohr's atomic model the quantization postulate is that the angular momentum is equal to

         L = n \(\hbar\)

we substitute

        n \(\hbar\) = m v r

        v = \(n \frac{\hbar }{m r}\)

where n is an integer.

Therefore, the sppedof the electron is also quantized, that is, sol has some discrete values.

3. How much power does an electric light installation draw at 120 V if it creates a current of 0.8 amps?
O A. 32 watts
O B. 120 watts
Q C. 48 watts
D. 96 watts

Answers

Answer:D

Explanation:

R =  

V

I

=  

120 volt

0.8 ampere

=  150 ohm (Ω)

P =  V × I

=  120 volt × 0.8 ampere

=  96 watt (W)

An electric light installation  can draw Power of 96 Watt  at 120 V if it creates a current of 0.8 amps

What is electric power ?

Electric power  is the rate of electric energy transfer by an electric circuit per unit time . It is denoted by P and measured using the SI unit of power that is Watt (W)

since, Electric Power   = voltage * current

Power    = 120 V * 0.8 A

Power    = 96 Watts

An electric light installation  can draw Power of 96 Watt  at 120 V if it creates a current of 0.8 amps

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Use the work-energy theorem to find the force required to accelerate an electron (m
9.11 x 10-31 kg) moving along the x axis from 3.50 x 106 m/s to 1.55 x 107 m/s in a
distance of 0.0135m.

Answers

2.16x10^-14N is ur answer

7. A car stops at a red light. The light turns green
and the car accelerates up to a constant speed. After
several minutes, the car slows down and stops at the
next red light. Which graph shows the car's motion?

7. A car stops at a red light. The light turns greenand the car accelerates up to a constant speed. Afterseveral

Answers

Answer:

Graph C

Explanation:

This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.

determine the resultant force that water exerts on the overhang sea wall along abc. the wall is 2 m wide.

Answers

The resultant force that water exerts on the overhang sea wall along abc is 179 kN.

What is force?

Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.

Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.

(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.

Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,

Aabefa=1.5m(2.5m)=3.75m2and

2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,

Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N

Therefore,

Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN

FR²   =(Fbc)²H2+[Fab+(Fbc)v]²

==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]

=178.6(10³)N = 179 kN.

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give pressure loss Darcy weisbach equation​

Answers

Answer:

Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product by the square of velocity. Divide the answer by 2.

Explanation:

Multiply the friction factor by pipe length and divide by pipe diameter. Multiply this product with the square of velocity. Divide the answer by 2.

Hope this answer helps you

give pressure loss Darcy weisbach equation

Mass is a physical property that describes the amount of matter in a substance. Mass is commonly measured in grams or kilograms using a triple-beam balance or an electronic balance. Weight is a physical property of matter that
A. is measured in the metric system as pounds.
B. is always equivalent to an object's mass.
C. considers the gravitational force acting on an object.
D. can be measured using a graduated cylinder. Reset Submit​

Answers

Answer:

C

Explanation:

it's the measure of the force of gravity pulling the object towards the centre of the Earth and this value differs at various locations away from the equator and highest at the poles

6. In the diagram below, A is a vector of magnitude 35 cm; B is a vector of magnitude 13 cm. If tan a = 4/3 and tan ß = 5/12, a. write A and B in terms of î and ĵ b. Show that A + B makes an angle of 45° to the x-axis.

Answers

Answer:

A = 21 î + 28 ĵ

B = 12 î + 5 ĵ

Explanation:

a.

To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation

According to the diagram, we have:

tan a = 4/3 tan ß = 5/12

Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.

For A, we have:

x component = 35 cos a y component = 35 sin a

Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:

cos a = 3/5 sin a = 4/5

Therefore, the x and y components of A are:

x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28

Using the vector notation, we can write A as:

A = 21 î + 28 ĵ

Similarly, for B, we have:

x component = 13 cos ß y component = 13 sin ß

Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:

cos ß = 12/13 sin ß = 5/13

Therefore, the x and y components of B are:

x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5

Using the vector notation, we can write B as:

B = 12 î + 5 ĵ

b.

To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.

To find R, we can use the vector addition rule :

R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ

To find θ, we can use the inverse tangent function :

tan θ = y component / x component tan θ = 33 / 33 tan θ = 1

θ = tan^-1(1) θ = 45°

Therefore, A + B makes an angle of 45° to the x-axis.

d) Suppose the person uses a different skateboard with a mass of 50 kg. Using the acceleration you
calculated for Road C, what would the new net force be?

d) Suppose the person uses a different skateboard with a mass of 50 kg. Using the acceleration youcalculated

Answers

250 Newton is net force .

mass= 50 kg

a= 5m/s²

force=ma

force=50×5

force=250 N

In mechanics, a force is any action that seeks to preserve, modify, or deform a body's motion. Isaac Newton's three principles of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the idea of force (1687).

Newton's first law states that unless a force is applied to a body, it will stay in either its resting or uniformly moving condition along a straight path. According to the second law, when an external force applies on a body, the body accelerates (changes velocity) in the force's direction.

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To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeoff velocity, depends on several factors, including the weight of the aircraft and the wind velocity. Part A A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the time tTO needed to take off

Answers

Answer:

t = 26.8 s

Explanation:

Here, we can use the second equation of motion to calculate the required time:

\(s = v_it + \frac{1}{2}at^2\)

where,

s = distance = 1800 m

vi = initial speed = 0 m/s

t = time needed = ?

a = acceleration = 5 m/s²

Therefore,

\(1800\ m = (0\ m/s)t+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(1800\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{720\ s^2}\)

t = 26.8 s

for a moving object distance covered by it is always greater than or equal to the displacement of the object in a given time. explain.​

Answers

Answer

Distance is equal to the Total Distance covered by a body, from the initial till the final point\(.\)

Displacement is equal to the shortest distance between two points.

So we known that Distance can only be equal to or greater than the displacement and can never be shorter than the displacement.

This is just common sense how can anything be shorter than the shortest path itself. But it can be equal to the shortest path━━━━━━━━━━━━━━

Know More

☯ Distance is a scalar quantity and has only magnitude but no direction.

☯ Displacement is a vector quantity and has both magnitude and direction.

☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.

for a moving object distance covered by it is always greater than or equal to the displacement of the
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