Mieko has 4 times as many pencils as Holden. Holden has 8 pencils.

How many pencils, p, does Mieko have?

Use the drop-down menu to complete the comparison sentence.

p is 4
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8 is ir less than more than or times as many as

The function is assigning to each element of one set exactly one element from the other set.

First table represent a function.

Second table not represent a function (for -1 are four different numbers).

Third table represent a function.

Fourth table not represent a function (for -6 are two differen numbers 5 and 9)

Answer:

Step-by-step explanation:

This is the answer

Answer:

x = 5

Step-by-step explanation:

Report if wrong

-Stylez-

The simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

The expression is given as:

(-11/2x+30)-2(-11/4x-5/2)

Expand the bracket

-11/2x + 30 + 11/2x + 5

Collect the like terms

11/2x -11/2x + 30 + 5

Evaluate the like terms

35

Hence, the simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

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Answer: x=12

Step-by-step explanation:

5x-15=2x+21(AIA)

3x-15=21

3x=36

x=12

(3a) The 95% confidence interval of σ\(_{1}^{2}\)/σ\(_{2}^{2}\) is: [0.1932 , 1.2032].

Variance is the anticipated squared deviation of a random variable from its population mean or sample mean in probability theory and statistics.

F test for variances, using F distribution (\(df_{num}\)=19,\(df_{denom}\)=20) (two-tailed) (validation).

Hypotheses

\(H_{0}:sigma_{1} = sigma_{2}\\\\H_{1}:sigma_{1}\neq sigma_{2}\)

1. H0 hypothesis

Since p-value > α, H0 is accepted.

The sample standard deviation (S) of LaJolla.res' population is considered to be equal to the sample standard deviation (S) of Pt.Loma.ke's population.

In other words, the difference between the sample standard deviation (S) of the LaJolla.res and Pt.Loma.ke populations is not big enough to be statistically significant.

2. P-value

The p-value equals 0.1152, ( p(x≤F) = 0.05759 ). It means that the chance of type I error, rejecting a correct \(H_{0}\), is too high: 0.1152 (11.52%).

The larger the p-value the more it supports \(H_{0}\).

3. The statistics

The test statistic F equals 0.4796, which is in the 95% region of acceptance: [0.3986 : 2.4821].

S1/S2=0.69, is in the 95% region of acceptance: [0.6313 : 1.5755].

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1)13/4: Rational (a fraction)

2)√17: Irrational (square root of a non-perfect square)

3)3π: Irrational (product of a rational number and an irrational number)

4)0.1 (1 bar): Rational (repeating decimal)

5)-√2: Irrational (negative square root of a non-perfect square)

6)√24: Irrational (square root of a non-perfect square)

7) -√49: Rational (negative square root of a perfect square)

1)13/4: Rational - This number is a fraction, and any number that can be expressed as a fraction is considered rational. In this case, 13/4 can be simplified to 3.25, which is a rational number.

2)√17: Irrational - The square root of 17 cannot be expressed as a simple fraction or terminating decimal. It is an irrational number, meaning it cannot be expressed as a ratio of two integers.

3)3π: Irrational - π (pi) is an irrational number, and when multiplied by a rational number like 3, the result is still an irrational number. Therefore, 3π is an irrational number.

4)0.1 (1 bar): Rational - This number is a repeating decimal, indicated by the bar over the 1. Although it does not have a finite representation, it can be expressed as the fraction 1/9, which makes it rational.

5)-√2: Irrational - Similar to √17, the square root of 2 is also an irrational number. Multiplying it by -1 does not change its nature, so -√2 remains an irrational number.

6)√24: Irrational - The square root of 24 is an irrational number because it cannot be expressed as a simple fraction or terminating decimal. It can be simplified to √(4 × 6), which further simplifies to 2√6, where √6 is an irrational number.

7)-√49: Rational - The square root of 49 is 7, which is a rational number. Multiplying it by -1 does not change its nature, so -√49 remains a rational number.

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The complete question is :

Select whether the following numbers are rational or irrational.

1. 13/4

2. \sqrt{17}

3. 3 π

4. 0.1 (1 bar)

5. - \sqrt{2}

6. \sqrt{24}

7. - \sqrt{49

Based on the information provided, the appropriate population for generalizing conclusions from the study would be C. The conclusions should apply to people at that particular college.

Since the study was conducted using a random sample of 200 people from one college, the conclusions drawn from the study are most likely applicable to the population of people at that specific college. It would be incorrect to assume that the conclusions can be generalized to all people in the same country (Option A), all people within the same city as the college (Option B), people at any college (Option D), or that the conclusions apply only to the sample (Option E).

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The standard deviation of the sampling distribution of the sample mean would be approximately 2.8284

To determine the standard deviation of the sampling distribution of the sample mean, we will use the formula;

σ_mean = σ / √n

where σ is the standard deviation of the population that is 20 and n is the sample size (n = 50).

So,

σ_mean = 20 / √50 = 20 / 7.07

σ_mean  = 2.8284

The standard deviation of the sampling distribution of the sample mean is approximately 2.8284 it refers to that the sample mean would typically deviate from the population mean by about 2.8284, assuming that the sample is selected randomly from the population.

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The complete question is;

Another application of the sampling distribution of the sample mean Suppose that, out of a total of 559 full-service restaurants in Delaware, the number of seats per restaurant is normally distributed with mean mu = 99.2 and standard deviation sigma = 20. The Delaware tourism board selects a simple random sample of 50 full-service restaurants located within the state and determines the mean number of seats per restaurant for the sample. The standard deviation of the sampling distribution of the sample mean is Use the tool below to answer the question that follows. There is a.25 probability that the sample mean is less than

The correct answer is B

The rank of A is equal to the number of non-pivot columns in A. Since there are more rows than columns in an 8 times 6 matrix, the rank of an 8 times 6 matrix must be equal to the number of pivot positions, which is 6. Since there are 6 rows in a 6 times 8 matrix, there are a maximum of 6 pivot positions in A. Thus, there are 2 non-pivot columns. Therefore, the largest possible rank of a 6 times 8 matrix is 2.

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Answer:

-3/2, -1, 2/3, .75

Step-by-step explanation:

A book store is hosting a special night in which families can enjoy a story and craft time. The ticket have been sold so far would be 75.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

We have given that 45 children's tickets have been sold, being 60% of the total tickets having been sold.

So, we have to solve for x:

60% × x = 45

60/100 × x = 45

Multiplying both sides by 100 and dividing both sides by 60,

x = 45 × 100/60

x = 75

Thus, the ticket have been sold so far would be 75.

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Answer:

y =-5-4x

Step-by-step explanation:

Answer: 38.5 minutes, aka 38 minutes and 30 seconds, round up, unless ur teacher wants the exact time.

Answer:

38.5 minutes or if rounded up it would be 39 minutes.

Step-by-step explanation:

22 divided by 4 bags would get you 5.5. This means it would take you 5.5 minutes to rake 1 bag. Since, they already raked 4 bags that would be 22 minutes, plus the other 3 bags it would be, 5.5 x 3 = 16.5 minutes. Add it together and you get 22 minutes + 16.5 minutes = 38.5 minutes to rake 7 bags. Hope this helped!

Answer:

24496

Step-by-step explanation:

40912 * (1-5%) ^10 = 24495.5

becuase they are humans, so round up to 24496

I belive it is assets

the probability that the diameter of a elected bearing is greater than 85 millimeter P(diameter > 85) = P(z > (85-81)/4) = P(z > 1) = 0.1587

The diameter of ball bearings is normally distributed, with a mean of 81 millimeters and a variance of 16.

To calculate the probability that a selected bearing has a diameter greater than 85 millimeters, we first calculate the z-score for 85 millimeters.

We subtract 81 from 85 to get 4, and divide by 4 to get 1 for the z-score.

We the look up the probability for a value of 1 in the z-table, which is 0.1587.

This is the probability that a selected bearing has a diameter greater than 85 millimeters, rounded to four decimal places.

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Angle ABC is equal to 1/2 x, proved as required.

To prove that ABC = 1/2 x, we will use the following reasoning:

∴ ∠ OAB = ∠OBA = (180 - x)/2 (the sum of angles in a triangle is 180 degrees and ∠ AOB is twice the size of ∠ OAB)

∠ABC  = ∠OBC - ∠OBA.  (the sum of angles in a triangle is 180 degrees).

∠OBC is a right angle, since it is the angle between a radius and a tangent to the circle at B.

∴, ∠OBC = 90 ⁰

Substituting in the values we have found, we get:

ABC = OBC - OBA

ABC = 90 - (180 - x)/2 = x/2.

Therefore, ABC = 1/2 x, as required.

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Answer:

133.78684807256

Step-by-step explanation:

step 1: We need the assumption that 44.1 is 100% since it is our output value

step 2: We need to represent the value we seek in x

step 3: From step 1, it follows that 100% = 44.1

step 4: In the same vein x% = 59

step 5: This give us a pair of simple equations:

100% = 44.1 (1)

x% = 59 (2)

step 6: by simplify dividing equation 1 by equation 2 and taking note of the fact that both the LHS (left hand side) of both equations have the same unit (%); we have

\( \frac{100}{x} = \frac{44.1}{59} \)

step 7: Taking the inverse (or reciprocal) of both sides yields

\( \frac{x}{100 } = \frac{59}{44.1} \)

= x = 133.78684807256

Therefore, 59 is 133.78684807256% of 44.1

Answer:

The correct answer is "the term number, n."

Step-by-step explanation:

Answer:

Step-by-step explanation:

on edge!! dear student... you got this.. don't procrastinate and more importantly don't doubt yourself. You CAN and WILL make it to 100%

Answer:

\(6\)

Step-by-step explanation:

\(7+8=15\)

\(15+3=18\)

\(18+4=22\)

\(22+8=30\)

\(30\) ÷ \(5\) \(=6\)

\(\huge\text{Hey there!}\)

\(\mathsf{Formula \rightarrow \mathtt{\dfrac{sum\ of\ all\ your\ terms}{total \ number \ you \ have\ in\ your\ data} = mean} }\)

\(\textsf{Your equation should look like}\rightarrow\mathtt{\dfrac{7 + 8 + 3 + 4 + 8}{5} = mean}\)

\(\textsf{Now let us solve for it}\)

\(\mathtt{\dfrac{7 + 8 + 3 + 4 + 8}{5} = mean}\)

\(\mathtt{\dfrac{15 + 3 + 4 + 8}{5} = mean}}\)

\(\mathtt{\dfrac{22 + 8}{5} = mean}}\)

\(\mathtt{\dfrac{30}{5} = mean}}\)

\(\mathtt{6 = mean}\)

\(\huge\text{Therefore your answer should be:}\)

\(\huge\boxed{\mathtt{6}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

Given that a continuous random variable x has a normal distribution with a mean of 12.25 and the probability that x is less than 13 is 0.82, we can use the symmetry of the density function to find the probability that x is greater than 11.50.

Since the normal distribution is symmetric, the probability of x being less than 13 is equivalent to the probability of x being greater than the mean minus 13. Therefore, P(x < 13) = P(x > 12.25 - 13).

To find the probability that x is greater than 11.50, we can use the same reasoning. We know that the probability of x being less than 11.50 is equivalent to the probability of x being greater than the mean minus 11.50. Therefore, P(x < 11.50) = P(x > 12.25 - 11.50).

To illustrate the computation, we can sketch the density curve of the normal distribution with the relevant regions shaded. The mean, 12.25, is the center of the distribution. We shade the region to the left of 13, representing P(x < 13), and shade the region to the right of 11.50, representing P(x > 11.50). By using the symmetry of the density function, we can see that the shaded region to the right of 11.50 is equal to the shaded region to the left of 13.

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All terms beyond n=7 are zero, we can truncate the series at n=7: i ≈ (0.3/4) + (1/8) + 0 + 0 + 0 + 0 + 0 + 0 = 0.0875. This approximation is accurate to six decimal places.

To approximate the definite integral using a power series, we need to first determine the power series representation of the integrand and then integrate it within the given limits. The integrand in your question seems to have a typo. However, I will provide a general method for solving this type of problem.

For a given function f(x), its power series representation can be written as:

f(x) = Σ (a_n * x^n) from n=0 to infinity

First, find the power series representation of the function you're interested in. Then, integrate the power series term-by-term:

∫(f(x) dx) = ∫(Σ (a_n * x^n) dx) from n=0 to infinity

= Σ (a_n * ∫(x^n dx)) from n=0 to infinity

= Σ (a_n * (x^(n+1))/(n+1)) from n=0 to infinity

Now, find the definite integral by evaluating this power series at the given limits (in your case, from 0 to 0.3) and subtracting:

i ≈ Σ (a_n * ((0.3^(n+1))/(n+1))) from n=0 to infinity

To achieve an approximation up to six decimal places, you can truncate the power series after a sufficient number of terms, which ensures the error is less than 10^(-6). Then, sum the truncated series to find the value of the definite integral, i.

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Answer:

3 is a positive number which makes -2 less then 3

Answer:

The x intercepts are x = 4, x = -1, and x = 3.

Step-by-step explanation:

\(g(x)=(2x-8)(x+1)(9-3x)^{2}\\(2x-8)(x+1)(9-3x)^{2}=0\\2x-8-0\\2x=9\\x=4\\x+1=0\\x=-1\\9-3x=0\\3x=9\\x=3\\\)

Answer:

20

Step-by-step explanation:

I'm pretty sure its 20 but I could be wrong but 20 is my best guess.

Answer:

16 of the 33 plays none.

Step-by-step explanation:

From the list, we get that 18 students play football, 1 basketball, and 7 both.

What we need to do here is add up 18 and 1

then we subtract 19 by 7 to cancel out the people who play both

and then subtract the total number of 33 by 17,

which gives you 16.

Answer:

0.029

Step-by-step explanation:

The answer

The composite function N(T(t)) = 20082.The time when the bacteria count reaches 20082 is approximately 30.28 hours.

To find the composite function N(T(t)), we need to substitute the expression for T(t) into the function N(T).

Given:

N(T) = 307² - 112T + 75

T(t) = 3t + 1.7

Substituting T(t) into N(T), we get:

N(T(t)) = 307² - 112(3t + 1.7) + 75

Simplifying:

N(T(t)) = 307² - 336t - 190.4 + 75

N(T(t)) = 307² - 336t - 115.4

Now let's find the time when the bacteria count reaches 20082.

N(T(t)) = 20082

307² - 336t - 115.4 = 20082

Taking 115.4 to the other side:

\(307^2\) - 336t = 20082 + 115.4

307² - 336t = 20197.4

336t = 307² - 20197.4

Dividing by 336:

t = (307² - 20197.4) / 336

Calculating the value of t:

t ≈ 30.28

Therefore, the time when the bacteria count reaches 20082 is approximately 30.28 hours.

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A cylindrical object is 3.13 cm in diameter and 8.94 cm long and weighs 60.0 g. The density of the cylindrical object is 0.849 g/cm^3.

To calculate the density, we first need to find the volume of the cylindrical object. The volume of a cylinder can be calculated using the formula V = πr^2h, where r is the radius (half of the diameter) and h is the height (length) of the cylinder.

Given that the diameter is 3.13 cm, the radius is half of that, which is 3.13/2 = 1.565 cm. The length of the cylinder is 8.94 cm.

Using the values obtained, we can calculate the volume: V = π * (1.565 cm)^2 * 8.94 cm = 70.672 cm^3.

The density is calculated by dividing the weight (mass) of the object by its volume. In this case, the weight is given as 60.0 g. Therefore, the density is: Density = 60.0 g / 70.672 cm^3 = 0.849 g/cm^3.

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