Mitzy has a temperature of 109 degrees celsius. How much more is this from her normal body temperature? ​

Answer: Clicking sounds and clicking tools + hearing devices to help hear the clicks in loud situations

Explanation:

Some blind people have developed the ability to make clicking noises, either with their mouth or a clicker, and they can listen for the sound of it bouncing off objects around them. Based on the tone, volume, and depth of the click, these people can tell the distance, size, and sometimes material of an object. A clicking device would be a tool that is helpful, as well as any hearing aid that could allow the wearer to hear the clicks better or clearer in a loud environment. (Note: the sound could be anything. It does not have to be a click. Whistles, beeps, chirps, and other sounds also can work for people.)

The smallest number of hydrogen atoms that can be found in a noncyclic ether is two. Noncyclic ethers are characterized by the presence of an oxygen atom bonded to two carbon atoms. The remaining valences of the carbon atoms are filled by either other carbon atoms or hydrogen atoms.

In the case of a noncyclic ether, the two carbon atoms are each bonded to one hydrogen atom, resulting in a total of two hydrogen atoms in the molecule.

Noncyclic ethers are organic compounds that contain an oxygen atom bonded to two carbon atoms. The oxygen atom forms two sigma bonds with the carbon atoms, leaving two remaining valences on each carbon atom. These remaining valences can be filled by either other carbon atoms or hydrogen atoms.

In the case of a noncyclic ether, the two carbon atoms are typically bonded to each other or to other carbon atoms in the molecule. Since each carbon atom can form a single bond with a hydrogen atom, the smallest number of hydrogen atoms that can be found in a noncyclic ether is two.

These two hydrogen atoms are attached to the carbon atoms that are directly bonded to the oxygen atom. The presence of these hydrogen atoms does not form any additional bonds with the oxygen or carbon atoms in the molecule.

It's important to note that in larger noncyclic ethers, there may be additional carbon atoms and hydrogen atoms present in the molecule. However, for the smallest noncyclic ethers, consisting of only two carbon atoms, there are two hydrogen atoms bonded to the carbon atoms.

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The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

Displacement (denoted by Δx)

Initial Velocity v0

Final Velocity denoted by v

Time interval (denoted by t)

Constant acceleration (denoted by a)

These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.

v = u + at

0 = 9.5 + a (2)

a = - 9.5 /2  m/\(s^{2}\)

\(v^{2}\) = \(u^{2}\) + 2as

0 =  \((9.5)^{2}\) + 2* (- 9.5 /2) * s

-  \((9.5)^{2}\)  = - 9.5 s

s = 9.5 m

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Answer:

Explanation:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

λ

:

λ

=

v

f

Let's plug in our given values and see what we get!

λ

=

340

m

s

440

s

−

1

λ

=

0.773

m

Coefficient of friction is calculated to be 0.4. Therefore, a) will be the correct answer .

Frictional force is that force which is generated by two surfaces that contact and slide against each other. Factors affecting the frictional force are the surface texture and the amount of force impelling them together.

The frictional force is said to be a contact force as frictional force occur when two surfaces come in contact with each other.

Given applied force = 60 N

weight of object = 50N;  friction force = 20N

As we know that, Coefficient of friction =  force of friction/normal force

= 20/50

Coefficient of friction = 0.4

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A wire located at the equator points vertically upward from the surface of the Earth. The wire carries a current straight up in a region where the magnetic field vector points due north. The direction of the resulting force on this current is West.

The magnetic field lines are closed curves leaving the North Pole and following the outside of the magnet to the South Pole. A compass, that's itself a small magnet, aligns parallel to the magnetic lines of pressure it is placed on. The magnetic field lines are the trails that the free North Pole tries to tour. The course of the magnetic field at a factor is determined by using setting a small compass needle at that point.

The north pole of the compass shows the direction of the magnetic area at that factor. outdoor the bar magnet, the magnetic discipline traces move from the north pole to the south pole, forming a closed loop so interior they move from the south pole to the north pole. The magnetic discipline lines seem to move from the south pole to the north pole within the magnet. Magnetic subject strains are directed from the South Pole to the North Pole growing a closed continuous curve.

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Answer:

Explanation:

We can solve for the initial velocity using the first equation of motion

\(v= u +at\)

where

v= final velocity

u= initial velocity

a= acceleration

t= time in seconds

Given data

final velocity= 2.41 m/s

initial velocity v =?

time t= 2.5 seconds

acceleration a= \(0.130m/s^2\)

substituting we have

v= 2.41+0.13(2.5)

v= 2.41+0.325

v= 2.735m/s

v= 2.74m/s

the final velocity is  2.74 m/s

When diving off the platform with an upward velocity of 2 meters per second, you will hit the water with a velocity of approximately 14.14 meters per second.

Explanation:

I'd be happy to help with your diving question.

a. To determine the velocity with which you'll hit the water stepping off from a 10-meter dive platform, we need to use the equation for free fall:

v = √(2 * g * h)

where v is the velocity, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height of the platform (10 meters).

v = √(2 * 9.8 * 10)
v ≈ 14 m/s

So, you will hit the water with a velocity of approximately 14 meters per second when stepping off the platform.

b. To calculate the velocity with which you'll hit the water diving off the platform with an upward velocity of 2 m/s, we need to use the following equation:

v² = u² + 2 * g * h

where v is the final velocity, u is the initial velocity (2 m/s), g is the acceleration due to gravity (9.8 m/s²), and h is the height (10 meters).

v² = (2)² + 2 * 9.8 * 10
v² = 4 + 196
v² = 200
v ≈ √200
v ≈ 14.14 m/s

When diving off the platform with an upward velocity of 2 meters per second, you will hit the water with a velocity of approximately 14.14 meters per second.

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Answer:

The force exerted by one source object on another target object always creates another force at the target object that pushes back on the source object with the same ... or His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

Answer:

Red Volcano Rock and the Lava Rock Covered in Sulphur

Explanation:

Igneous Rocks are formed by volcanoes, lava, and magna. Sandstone is sedimentary and Slate is metamorphic. The other two are literally formed by volcanoes.

Answer:

Red Volcano Rock and the Lava Rock Covered in Sulphur

Explanation:

Answer: 48

Explanation:

Given the expression (5x + 4y)/2

Where x represents the valence of Argon and y represents the summation or valencies of sulphur and Neon

A neutral Argon, Sulphur and Neon will have :

The valence of Argon = 8

The valence of sulphur = 6

The valence of Neon = 8

Therefore, X = 8 and Y = 6 + 8 = 14

Substitute x and y into the expression.

(5x + 4y)/2 = (5×8 + 4×14)/2

(40 + 56)/2 = 96/2 = 48

Evaluating: (5x + 4y)/2 = 48

Answer:

2 m/s

Explanation:

Just divide the distance and time. 4/2= 2 m/s

Answer:

a

Explanation:

the river over time will eroded the rock

To calculate the amount of potential energy initially stored in the spring, we need to consider the conservation of mechanical energy.

The mechanical energy of the block-spring system is conserved when no external forces other than gravity and friction are acting on it. At point A, the mechanical energy is stored entirely as potential energy in the compressed spring. The potential energy stored in the spring can be calculated using the formula: Potential Energy (PE) = (1/2)kx^2

where k is the spring constant and x is the displacement of the spring from its equilibrium position.

To find the spring constant, we need to know the force constant of the spring (k) or the spring's compression distance (x). Unfortunately, this information is not provided in the given question. If you have any additional information about the spring constant or the compression distance, please provide it so that I can assist you further.

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Answer for the first one is 2. The answer for the 3rd one is 8

The correct expression for the force applied by the small dog is determined as Fs = ma + Fb.

The net force on the bone will determine the direction of the bone's acceleration. The net force on the bone is determined by applying Newton's second law of motion.

If the acceleration of the bone is towards the right (rightward), the direction of the net force will be towards the right. This implies that the force applied by the dog on the right (S) is greater than the force applied by the dog on the left (B).

F(net) = Fs - Fb

The acceleration of the bone is calculated from the net force by applying Newton's second law of motion.

a = F(net) / m

a = (Fs - Fb)/m

make Fs the subject of the formula;

Fs - Fb = ma

Fs = ma + Fb

Thus, the correct expression for the force applied by the small dog is determined as Fs = ma + Fb.

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One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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The formula for calculating density is expressed as

Density = mass/volume

From the information given,

mass of empty pycnometer = 10.2

mass of the same pycnometer with an unknown liquid is 21.8.

Mass of unkown liquid = 21.8 - 10.2 = 11.6

volume of unknown liquid = 7

Thus,

Density = 11.6/7

Density = 1.7 g/ml

Answer:

The icicle will be moving at 333.54 m/s

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is \(g = 9.81 m/s^2\).

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The icicle falls from rest for 34 seconds. We need to find the speed after that time:

vf = 9.81*34

vf = 333.54 m/s

The icicle will be moving at 333.54 m/s

(a) For +7 to +8 diopters the distance of the object from the lens should be 2.33 cm to 2.4 cm and for +20 diopters the distance of the object from the lens should be 2.2 cm. (b) The corrective lens should have a negative power to compensate for the positive power of the eye lens and should be placed in front of the eye.

(a) To determine the distance from the lens to the object that will be focused on the retina, we can use the thin lens formula:

1/f = 1/o + 1/i

where f is the focal length of the lens, o is the distance from the lens to the object, and i is the distance from the lens to the image.

For +7 or +8 diopters, the focal length of the lens is:

f = 1/7 or f = 1/8

Using the formula with a distance of 2 cm for the retina:

1/f = 1/o + 1/i

1/7 = 1/2 + 1/i

i = 2.33 cm

or

1/8 = 1/2 + 1/i

i = 2.4 cm

So for +7 or +8 diopters, the lens must be 2.33 cm or 2.4 cm away from the object to focus on the retina at 2 cm.

For +20 diopters, the focal length of the lens is:

f = 1/20

Using the formula with a distance of 2 cm for the retina:

1/f = 1/o + 1/i

1/20 = 1/2 + 1/i

i = 2.2 cm

So for +20 diopters, the lens must be 2.2 cm away from the object to focus on the retina at 2 cm.

(b) If the distance to the retina is larger than 2 cm, an additional lens can be used to correctly focus on the retina. This additional lens is called a corrective lens and can be placed in front of the eye or in eyeglasses.

If the object is at a distance that requires +7 or +8 diopters, the corrective lens should have a negative power to compensate for the positive power of the eye lens. The distance between the corrective lens and the eye lens will depend on the specific prescription, but it should be close to the eye lens.

If the object is at a distance that requires +20 diopters, the corrective lens should have a positive power to further increase the power of the eye lens. Again, the distance between the corrective lens and the eye lens will depend on the specific prescription.

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6 meters

Change in displacement = v times change in t .

Explanation:

Observing the graph, we see that the object moves at a constant velocity of 3 m/s during the span of 6 to 8 seconds. We can thereby find displacement in the in this intreval by finding the area under the curve during 6 to 8 seconds (forming a rectangle).

Displacement (area of rectangle with length = 3 and breadth = 2) = 3 * 2 = 6 m

The probability that the sale price for a randomly selected car is greater than $25,000 is p(x>25) = 0.0228

B. To find the probability that the sale price for a randomly selected car is greater than $25,000, we need to use the cumulative distribution function (CDF) of the normal distribution.

The CDF of the normal distribution is given by P(X≤x)=F(x)=1/2*[1+erf((x-μ)/(σ*√(2)))]

Where x is the sale price, μ is the mean of the distribution, σ is the standard deviation of the distribution and erf is the error function.

Since we are looking for the probability that x>25, we need to subtract the probability that x≤25 from 1.

By plugging in the given values we can find out the probability, p(x>25) = 1 - P(X≤25) = 1 - F(25) = 0.0228 (approx)

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Binocular disparity refers to the discrepancy between the images viewed by each eye. For items that are closer, the difference is greater, and for those that are farther away, the difference is smaller.

The discrepancy between how an object appears to the left and right eye is known as binocular disparity. The difference is brought about by the horizontal distance between the eyes, which offers each eye a marginally different perspective of the outside world. The brain generates a 3D perception of the surroundings using the discrepancies between the images from the two eyes. The object appears to be closer the higher the binocular dispersion. The images perceived by each eye differ more from one another because the eyes must condense more in order to focus on close objects. On the other hand, since the eyes are almost parallel, objects in the distance have less discrepancy.

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At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

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According to the given statement 11.38 T is the magnitude of the magnetic field inside the solenoid.

By using the symbol |v|, the strength of a vector theorem can be utilized to determine the length for such a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point. The range calculation, which we will go over in this section, is used to determine the vector's magnitude.

Length of solenoid, L = 2.5 cm = 0.025 m

Radius of solenoid, r = 0.55 cm = 0.0055 m

Number of turns, N = 45 turns

Current, I = 1.15 A

Magnetic field, B, is given as:

B = (N*r*I) /L

B = (45 * 0.0055 * 1.15)/0.025

B = 11.38 T

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The complete question is-

A solenoid of length 2.50 cm and radius 0.550 cm has 45 turns. If the wire of the solenoid has 1.15 amps of current, what is the magnitude of the magnetic field inside the solenoid?

Answer:

The power expended by the car during the acceleration is 116.38KW

Explanation:

Power is a term that defines the rate at which energy is expended whenever work is done.

Power can be given as Force X velocity.

Force can be found using the formula:

F = mass X acceleration.

In this case,

F = 1100kg X 4.6m/s2

F = 5060 N

The final velocity, v of the car can be obtained from this formula:

v = u+ at

U = initial velocity = 0 (since the car started from rest)

a = acceleration = 4.6m/s2

t = time = 5 seconds

v = 0 + 4.6 X 5 = 23 m/s

Therefore, the power expended is 5060N X 23m/s=116,380W

The power expended by the car during the acceleration is 116.38KW

Answer:

Speed is a "scalar" quantity

(C) is the correct answer

An object could travel at 10 m/s to some point and then return to the origin at 10 m/s for an average speed of 10 m/s, however it's displacement over that time would be zero for a net velocity of zero.