Model the tungsten filament of a lightbulb as a black body at temperature 2900 K. (a) Determine the wavelength of light it emits most strongly.

Answer:

59F

Explanation:

Given parameters:

Temperature in °C  = 15°C

Unknown:

Temperature in Fahrenheit scale  = ?

Solution:

To solve this, we use the conversion equation below;

       F  = (C x 1.8)  + 32

C is the temperature in celcius;

    F = (15 x 1.8) + 32  = 59F

Answer:

If the potential difference between the ends of the wire are the same then wire Y will experience a smaller drift speed. This is necessary to explain the difference in resistivity.

Answer:

1 Watt

Explanation:

P=W/t

P=10/10

P=1 Watt

Covalent

Explanation:

Covalent Bond

Answer:

diphosphorus trioxide

Explanation:

A total differential is an equation in which all the differentials can be integrated independently of each other. To verify that the given expressions are total differentials, we must check if they meet the conditions of being an exact differential function.The given expression is not an exact differential function.

According to the exact differential function, an expression dQ should be equal to the sum of two partial derivatives of the same function. i.e, dQ= dP+ dRA primitive function of an expression is obtained by integrating the given expression partially. Let's solve the given expressions, one by one:

1. Expression : (x² + 2xy-y²)dx + (x²-2xy - y²)dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = x² + 2xy - y²  ∂Q/∂y = x² - 2xy - y².

On verifying, we get:∂P/∂x = ∂Q/∂y.

Hence, the given expression is an exact differential function.

To find the primitive function, we need to integrate any one of the partial derivatives with respect to x and other with respect to y.

∴ P(x,y) = ∫(x² + 2xy - y²)dx = x³/3 + x²y - xy² + C1 and ∴ Q(x,y) = ∫(x² - 2xy - y²)dy = x²y - y³/3 + C2.

Therefore, the primitive function of the expression is: P(x,y) = Q(x,y) = x³/3 + x²y - xy² - y³/3 + C2.

Expression : (2xcosy - y² sinx) dx + (2ycosx - x² siny) dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = 2cosy  ∂Q/∂y = 2ycosx.

On verifying, we get:∂P/∂x ≠ ∂Q/∂y .

Hence, the given expression is not an exact differential function.

Therefore, there does not exist a primitive function for the given expression.

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Answer:

she is going to be mad dude

True, heat transfer into a system from the surroundings is considered a positive transfer of energy. This is because the system is gaining energy from its surroundings, causing its internal energy to increase. This can be represented by a positive value for heat transfer (Q) in the equation for the change in internal energy of a system: ΔU = Q - W, where W is the work done by the system. If heat is transferred out of the system and into the surroundings, it would be considered a negative transfer of energy and represented by a negative value for Q.

The answer is yes because of conservation of momentum. That is, the momentum before collision is equal to the momentum after collision.

Momentum is the product of mass and velocity. It is a vector quantity. And it is measured in Kgm/s

If two vehicles have a head-on collision, the vehicles essentially stick together and travel a certain distance for 20 seconds before coming to a complete stop. The final velocity for both vehicles immediately after the crash can be obtain by using the formula

v = u - at

Where

If you are able to obtain the mass of both vehicles, the initial velocity for Vehicle A, and the final velocity for both vehicles immediately after the crash, then you can determine the momentum of both vehicles before the collision by calculating the momentum of both after the collision because momentum is always conserved.

Or by first calculating the initial velocity for vehicle B by using the formula below

\(M_{1}U_{1} - M_{2}U_{2} = (M_{1} + M_{2} )V\)

where

After we obtain initial velocity for vehicle B, we can calculate the momentum of both vehicles before the collision

Therefore, the momentum of both vehicles before the collision can be determined.

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The final temperature of the water is 21.2658°C.

Explanation:-

To find out the final temperature of the water after a 90 kg person jumps from a 30 m tower into a tub of water with a volume of 5 m³ initially at 20°C,

assuming that all of the work done by the person is converted into heat to the water,

let's follow the steps given below:

First, let's find out the work done by the person.

The work done by the person will be equal to the potential energy of the person just before the jump minus the potential energy of the person just after the jump.

W = PE₁ - PE₂

where W is the work done by the person

PE₁ is the potential energy of the person just before the jump

PE₂ is the potential energy of the person just after the jump

The potential energy of the person just before the jump is given by mgh,

where m is the mass of the person,

g is the acceleration due to gravity,

and h is the height of the tower.

PE₁ = mgh = 90 × 9.8 × 30 = 26,460 J

The potential energy of the person just after the jump is zero.

PE₂ = 0JTherefore, the work done by the person is

W = PE₁ - PE₂ = 26,460 - 0 = 26,460 J

Now, let's find out the heat energy produced in the water.

The heat energy produced in the water is equal to the work done by the person.

Q = W

where Q is the heat energy produced in the water

W is the work done by the person

Q = 26,460 J

Now, let's find out the change in temperature of the water.

The specific heat capacity of water is 4.18 J/g°C.

Therefore, the amount of heat required to raise the temperature of 1 g of water by 1°C is 4.18 J/g.

Also, we know that the density of water is 1000 kg/m³.

Therefore, the mass of water in the tub is given by the product of the density of water and the volume of the tub.

m = ρV = 1000 × 5 = 5000 g

Therefore, the amount of heat required to raise the temperature of the water by ΔT°C is given by

Q = mcΔT

where c is the specific heat capacity of water

Q = mcΔT = 5000 × 4.18 × ΔT = 20,900

ΔTThe heat energy produced in the water is equal to the amount of heat required to raise the temperature of the water by ΔT°C.

Therefore, we can equate the two equations.

Q = 20,900 ΔT26,460 = 20,900 ΔT

ΔT = 1.2658°C

Final temperature of the water = Initial temperature of the water + Change in temperature of the water

= 20°C + 1.2658°C= 21.2658°C

Therefore, the final temperature of the water is 21.2658°C.

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The correct option is D, The net displacement of the particle between 0 seconds and 80 seconds is 20 meters.

Displacement refers to the distance and direction between an initial point and a final point of an object or particle. It is a vector quantity, meaning that it has both magnitude and direction. Displacement can be calculated by subtracting the initial position vector from the final position vector. For example, if an object moves from point A to point B, the displacement vector is the vector that goes from point A to point B.

Displacement is different from distance traveled, which is the total length of the path taken by an object between two points. Displacement takes into account the direction of motion and the final position of the object, while distance traveled does not. Displacement is often used in physics to describe the motion of objects, and is commonly measured in meters or feet.

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Answer:

Harmful bacteria are called pathogenic

Explanation:

Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.

The difference in the pressure between the inside and outside will be 369.36 N/m²

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

The given data in the problem is;

dP is the change in the presure=?

Using Bernoulli's Theorem;

\(\rm \rho\frac{V^2_{12}}{2} +P_1= \rho \frac{V^2_{22}}{2} +P_2 \\\\\ P_2-P_1=\rho \frac{v_2^2-v_1^2}{2} \\\\ P_2-P_1= 1.21 \times \frac{17.4^2-0}{2} \\\\ \triangle p=369.36 \ N/m^2\)

Hence, the difference in the pressure between the inside and outside will be 369.36 N/m²

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Answer: 195.2802 → 195 for Acellus

Explanation: 0.5*1.29*17.4^2

Answer:

B

Explanation:

If you really read and dissect every other question they do not make sense

Answer:  37.5 N-M

Explanation:

The time at which the wheel C reach a rotational speed of 127.0 rev/min is 2.6 seconds.

The time taken for the wheel C to reach the rotational speed is determined by applying principle of angular momentum as shown below.

LA = LC

the angular momentum of wheel A = angular momentum of wheel C

ωf = ωi + αt

where;

The given parameters;

13.3 = 0 + 5.1t

13.3 = 5.1t

t = 13.3/5.1

t = 2.6 seconds

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The required speed of the the can when the spring is stretches is calculated to be 2.39 m/s.

The magnitude of acceleration of the block is calculated to be 4.12 m/s².

The force constant of the spring is given as k = 76 N/m.

Mass of the beans is given as 5 kg.

The constant horizontal force applied is given as 51 N.

The stretching in the spring is given as 0.4 m.

The expression to calculate speed of the block for the stretch in the spring is,

F x - 1/2 k x² = 1/2 m v²

v = √2 (F x - 1/2 k x²)/m

Putting all the values, we have,

v = √2 (51× 0.4 - 1/2× 76 × (0.4)²)/5 = √2 (20.4 - 6.08)/5 = 2.39 m/s.

Thus, the speed of the can for stretch in the spring is 2.39 m/s.

The relation to calculate the magnitude of acceleration of the block is,

a = (F - k x)/m = (51 - 76× 0.4)/5 = 4.12 m/s²

Thus, the magnitude of acceleration is calculated to be 4.12 m/s².

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In order to determine the energy delivered in the given time, first calculate the electric power of the starter, by using the following formula:

where,

I: current = 210 A

V: voltage = 12 V

Replace the previous values of the parameters into the formula for P:

where W means watts.

Now, consider that power is the energy delivered per second. Then, for

10.0 s the energy delivered is:

Hence, the energy delivered by the starter is approximately 2.5*10^4 J

We are asked to determine the magnitude of the force that acts parallel to the nail. To do that we will add the torque that acts on the point of contact. First, we draw a free-body diagram of the situation:

We have decomposed the force of the nail into its horizontal and vertical components. The horizontal component does no torque since there is no distance parallel to the force to the point of contact.

Now, we add the torques. We consider counterclockwise as positive:

Since we consider the moment before there is no angular acceleration the sum of torques adds up to zero:

Now, we determine the value of Ry as a function of "R" using the trigonometric function cosine:

Now, we multiply both sides by "R":

Now, we substitute in the sum of torques:

Now, we solve for "R". First, we add "30F" to both sides:

Now, we divide both sides by 5cm:

Now, we divide both sides by cosine:

Now, we substitute the values:

Solving the operations:

Therefore, the force on the nail is 1042.8 Newtons.

One key difference between living on earth and in space is the effect of gravity on the human body. On earth, gravity provides a constant force that keeps our bones and muscles strong. In space, however, gravity is much weaker and astronauts experience weightlessness. This can lead to various health problems, such as bone loss, muscle atrophy, and fluid shifts. Therefore, astronauts need to exercise regularly and follow a balanced diet to maintain their physical and mental well-being.

Gravity is a natural phenomenon whereby everything that has mass or energy in the universe—including planets, stars, galaxies, and even light—attracts one another.

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At the lowest point of her swing, she can withstand a maximum speed of 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body,

F = mv²/r = (61.7× v²)/11.5 = 5.37 v²

Gravitational force acting on her is

F = m × g = 61.7 × 9.81 = 605.28 N

By summing up gravitational and centripetal forces to get the total available force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Hence, the maximum speed at the low point of her swing is 10.78 m/s.

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Answer:

An open system.

Explanation:

An isolated system allows the exchange of neither energy nor matter with the surroundings. A closed system allows the exchange of energy, but not matter. An open system allows the exchange of both energy and matter.

Notice that in this question, light (electromagnetic wave) is a form of energy. The entry and exit of light allows this system to exchange energy with its surroundings- just as how the earth receives energy from the sun. Additionally, this system could exchange energy with its surroundings through the exchange of matter (in particular, air) with its surroundings.

Thus, the system in this question is an open system.

Answer:

its called a fault

Explanation:

Its when u mess up

The correct answer is option 4 Schrödinger.

The distribution of electrons within Thomson's model's positively charged region of space quickly earned it the informal moniker "plum pudding," since it reminded many scientists of the raisins—then known as "plums"—found in the traditional English delicacy plum pudding.

Erwin Schrodinger's Electron Cloud Model. With the help of this concept, electrons were no longer pictured as being in a fixed orbit around a central nucleus.

In a series of publications published in 1926, Schrödinger addressed the problem of wave functions and electrons. He utilised mathematical calculations to quantify the probability of finding an electron in a particular position in addition to describing what would later be known as the Schrodinger equation, a partial differential equation that explains how the quantum state of a quantum system varies with time.

This served as the foundation for the Schrodinger equation and the Electron Cloud (quantum mechanical) Model, respectively. The Electron Cloud Model, based on quantum theory, which holds that all matter has qualities related to a wave function, is different from the Bohr Model in that it does not specify the precise route of an electron.

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Correct question is;

Talia is on a road trip with some friends. in the first 2 hours, they travel 100 miles. then they hit traffic and go only 30 miles in the next hour. the last hour of their trip, they drive 75 miles. calculate the average speed of talia’s car during the trip. give your answer to the nearest whole number.

Answer:

Average speed ≈ 51 mi/hr

Explanation:

Total distance travelled by Talia = 100 + 30 + 75 = 205 miles

Total time taken by Talia = 2 + 1 + 1 = 4 hours.

Now, formula for average speed is;

Average speed = Total distance/total time

Thus;

Average speed of talia = 205/4

Average speed of talia ≈ 51 mi/hr

The magnitude of the acceleration of each block, if two blocks are connected vertically by a string over a massless, frictionless pulley, and one block, has a mass of 13.6 kg and the other has a mass of 4.5 kg is 3.2 m/s².

The acceleration of both blocks is the same magnitude (as they are connected together by the string).

How to find the magnitude of acceleration? To find the magnitude of the acceleration of the blocks, we can use the following steps:

Step 1: Find the gravitational force acting on both blocks.

We know that the gravitational force acting on an object is given by

F = m*g

where m is the mass of the object and g is the acceleration due to gravity.

Step 2: Identify the direction of acceleration for each block.

Step 3: Use Newton's second law of motion to determine the acceleration of each block.

Step 4: Calculate the magnitude of acceleration.

Step 1: Find the gravitational force acting on both blocks.

The gravitational force acting on the larger block (13.6 kg) is

F₁ = m₁*g

= 13.6 kg * 9.81 m/s²

= 133.416 N

The gravitational force acting on the smaller block (4.5 kg) is

F₂ = m₂*g

= 4.5 kg * 9.81 m/s²

= 44.145 N

Step 2: Identify the direction of acceleration for each block.

The direction of acceleration for the larger block is downwards because the gravitational force is greater than the tension in the string.

The direction of acceleration for the smaller block is upwards because the tension in the string is greater than the gravitational force.

Step 3: Use Newton's second law of motion to determine the acceleration of each block.

The net force acting on each block is given by

F = m*a

Where F is the net force, m is the mass, and a is the acceleration.

FOR THE LARGER BLOCK: The net force acting on the larger block is given by:

F - T = m₁*a

where T is the tension in the string.

Substituting the values, we get:

133.416 N - T = 13.6 kg * a------(1)

FOR THE SMALLER BLOCK: The net force acting on the smaller block is given by:

T - F = m₂*a

Substituting the values, we get:

T - 44.145 N = 4.5 kg * a----- (2)

Step 4: Calculate the magnitude of acceleration.

To find the magnitude of acceleration, we need to solve the above two equations simultaneously.

133.416 N - T = 13.6 kg * aT - 44.145 N

= 4.5 kg * a

Adding the two equations, we get:

89.271 N = 18.1 kg * a

So, the magnitude of the acceleration of both blocks is:

a = 89.271 N / 18.1 kg

= 4.93 m/s²

Now, we know the acceleration of both blocks is the same magnitude (as they are connected together by the string).

Therefore, the magnitude of the acceleration of each block is 3.2 m/s² (approx).

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Answer:

\(680\; \rm s\).

Explanation:

Start by finding the total amount of energy required for melting that much ice.

\(\begin{aligned}&\text{Energy required for melting ice sample} \\ &= \text{Mass of Ice} \times \text{Specific Latent Heat of Ice} \\ &= 120\; \rm g \times 340\; \rm J \cdot g^{-1} = 4.08 \times 10^{4}\; \rm J \end{aligned}\).

Hence, the heater would need to supply (at least) \(4.08 \times 10^{4}\; \rm J\) of energy.

The power of the heater is \(60\; \rm W\), which is equivalent to \(60\; \rm J \cdot s^{-1}\), In other words, the heater is rated to supply \(60\; \rm J\) of energy every second.

Amount of time it takes for the heater to supply \(4.08 \times 10^{4}\; \rm J\) at \(60\; \rm J \cdot s^{-1}\):

\(\begin{aligned}\frac{4.08 \times 10^{4}\; \rm J}{60\; \rm J \cdot s^{-1}} = 680\; \rm s\end{aligned}\).

Hence, it would take \(680\; \rm s\) for the heater to melt the ice if the heater is insulated, and all the energy from the heater went to the ice.