The slit separation is 55.1 μm, which is approximately equal to 220 μm (since 1 μm = 10⁻⁶ m).
The distance between the central maximum and the first bright fringe on either side in a double-slit interference pattern can be calculated using the formula:
y = (λL) / d
where y is the distance between the central maximum and the first bright fringe, λ is the wavelength of the light, L is the distance between the slits and the screen, and d is the slit separation.
In this problem, the distance between the central maximum and the first bright fringe on either side is given as 28.0 mm = 0.0280 m. The wavelength of the light is given as λ = 570 nm = 5.70 × 10⁻⁷ m. The distance between the slits and the screen is given as L = 2.70 m.
Solving for the slit separation d, we get:
d = (λL) / y = (5.70 × 10⁻⁷ m)(2.70 m) / 0.0280 m
d = 5.51 × 10⁻⁵ m = 55.1 μm
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8. Volcanoes that are mostly made up of pyroclastic material are called?
a.
Cinder Cone
b. Composite
c. Shield
d.
None of these
Answer:
I think it is Cinder Cone volcano.
Drag each label to the correct location on the chart. Each label can be used more than once.
Classify the waves as longitudinal or transverse.
In the given options diagram 1 and 3 are representing longitudinal waves while diagrams 2 and 4 are representing transverse waves.
What is a transverse and longitudinal wave?Transverse waves are described as waves that oscillate along routes that are perpendicular to the propagation direction of the wave. Examples of transverse waves involve water surface ripples and seismic S waves.
A longitudinal wave can be described as the displacement of the particle parallel to the direction of the propagation. Sound waves in air, primary waves of an earthquake, and the vibration of a spring are longitudinal waves.
A transverse wave has every particle of the medium traveling around its mean location in a direction that is the opposite from the propagating direction of the wave.
Transverse waves can be generated by only the surface of liquids and solids. Transverse waves cannot be created in liquids or gases.
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non-example of Newton's third law of motion
Answer:
Unbalanced forces
Explanation:
Explain how the embryological development of different species reveals similarities of organisms that are not evident in the fully formed anatomy.
Answer:Comparison of the embryological development of different species also reveals similarities that show relationships not evident in the fully-formed anatomy.
Explanation:
Comparison of the embryological development of different species also reveals similarities that show relationships not evident in the fully-formed anatomy.
(Have a great day :D)
The oscillation of an object of on a frictionless surface is characterised by
The oscillation of an object on a frictionless surface is characterized by a constant amplitude, regular frequency, and a lack of energy loss due to the absence of friction.
In such a scenario, the object's motion continues indefinitely, maintaining its oscillatory pattern without any decay in amplitude. Friction is a force between two surfaces that are sliding, or trying to slide, across each other. For example, when you try to push a book along the floor, friction makes this difficult. Friction always works in the direction opposite to the direction in which the object is moving, or trying to move. Friction always slows a moving object down. The amount of friction depends on the materials from which the two surfaces are made.
So, The oscillation of an object on a frictionless surface is characterised by a constant amplitude, regular frequency, and a lack of energy loss due to the absence of friction.
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A ball is tossed at an angle. It moves in a parabolic path, reaches its highest point, and then falls back to the ground. During the ball’s flight, which of the following is TRUE about the direction of the acceleration?
It is pointing downward.
It points opposite its velocity.
It is pointing upward.
It points in the same direction as its velocity.
The ball is following a parabolic path. For the ball's flight, it points in the same direction as its velocity. So, option D is correct.
What is the Projectile motion?A projectile is an object that is launched into the air and then moves only in response to the acceleration of gravity. The trajectory of the object is referred to as the projectile's path. Basics for One-Dimensional Kinematics describes the projectile motion of falling objects as a straightforward one-dimensional kind in which there is no horizontal movement. This section examines the velocity of two-dimensional projectiles, such as a football or other object with minimal air resistance.
The most crucial thing to keep in mind in this situation is that motions along perpendicular axes are independent and may therefore be studied separately. Breaking two-dimensional projectile motion into motions along the horizontal and vertical axes is the key to understanding it.
Hence, it points in the same direction as its velocity.
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A plane is cruising at 10,000 feet, moving to the right at 575 mph. Its engine are exerting a force of 5000N to the right, and there is 5000N of air resistance on it.
The magnitude of the net force on the plane is 0 N.
What is the net force on the plane?
The net force on the plane is the sum of all the forces acting on the plane.
The magnitude of the net force on the plane is obtained summing all the forces acting on the plane and considering the direction of the forces as well.
Mathematically, the formula for the net force on the plane is calculated as follows;
F(net) = F1 + F2
Let the rightward force = positive
Let the leftward force = negative
The net force on the plane is calculated as follows;
F(net) = 5000 N - 5000 N
F(net) = 0 N
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The complete question is below:
A plane is cruising at 10,000 feet, moving to the right at 575 mph. Its engine are exerting a force of 5000N to the right, and there is 5000N of air resistance on it. What is the net force on the plane?
state the sources of alternating current
Answer:
hudroelectricity
..........
Answer:
generator, crystal oscillator, alternator are sources of AC current.
a river flows due south with a speed of 1.90 m/sm/s . a man steers a motorboat across the river; his velocity relative to the water is 4.00 m/sm/s . the river is 700 mm wide.
The time it takes the motorboat to cross the river is approximately 73.40 seconds.
The velocity of the motorboat with respect to the river is v_b = 4.00 m/s at an angle of 30° north of east with the north direction. The river flows south with velocity v_r = 1.90 m/s. The width of the river is d = 700 m. We need to find the time t it takes the motorboat to cross the river.
Step 1: Find the velocity of the motorboat with respect to the ground - The velocity of the motorboat with respect to the ground can be found using the velocity addition formula:
v_bg = v_b + v_r
where v_bg is the velocity of the motorboat with respect to the ground.
v_bg = (4.00 m/s)² + (1.90 m/s)² + 2(4.00 m/s)(1.90 m/s cos 30°)
v_bg = sqrt(22.76) m/s
v_bg ≈ 4.78 m/s
Step 2: Find the time to cross the river - The time to cross the river is given by the distance across the river divided by the component of the velocity of the motorboat with respect to the ground perpendicular to the river, which is v_bg sin 30°.
t = d / (v_bg sin 30°)
t = 700 m / (4.78 m/s)(0.5)
t ≈ 73.40 s
Therefore, the time it takes the motorboat to cross the river is approximately 73.40 seconds.
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The magnitude of the electric field 1 m away from the positive charge is _________ the magnitude of the electric field 2 m away equal to one-quarter four times two times one-half Submit
For the given charge the magnitude of electric field at 1 m is 4 times the electric field at 2 m.
Electric charge can create magnetic field as well electric fields.
According to the given question a charge is given and we need to find electric field at 2 different positions that is at 1 m and 2 m.
Electric field at 1 m is E1 E1 = Kq/r₁²
E1 = Kq / 1²
E1 = Kq -------- 1
Electric field at 2 m is E2 , E2 = Kq/ r₂²
E2 = Kq / 2²
E2 = Kq / 4 ---------- 2
After comparing E1 and E2 from the above equation 1 and 2
E1 = 4 E2
Thus electric field at 1 m is 4 times the electric field at 2 m.
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The above question is incomplete. Check complete question below:
The magnitude of the electric field 1 m away from the positive charge is _________ the magnitude of the electric field 2 m away .
1. equal to
2. one-quarter
3. four times
4. two times
5. one-half
Integrated Science- 8th grade science
Please Help ASAP!
Its almost the end of semester And I need to fix my grade for science so PLEASE help!
its almost report cards time!
Answer:
I do believe it is A.
Explanation:
I hope this helps :)
Answer:I believe it is A
Explanation: B just doesn't seem like something an 8th grader would be learning about, and I'm not sure about the other ones.
now calculate the acceleration between points B and E as follows
time between dots calculation
It should be noted that to calculate the acceleration between points B and E, we need to have information about the initial and final velocities, as well as the time it takes to go from point B to point E.
How to explain the accelerationAssuming we have this information, we can use the following formula to calculate the acceleration:
acceleration = (final velocity - initial velocity) / time
Here's a step-by-step process to calculate the acceleration between points B and E:
Determine the initial velocity at point B. This could be given to you or you may need to calculate it based on other information.
Determine the final velocity at point E. Again, this could be given to you or you may need to calculate it based on other information.
Determine the time it takes to go from point B to point E. This could be given to you or you may need to calculate it based on other information.
Plug the values from steps 1, 2, and 3 into the acceleration formula:
acceleration = (final velocity - initial velocity) / time
Calculate the acceleration using the formula and express the answer in the appropriate units (such as meters per second squared or feet per second squared).
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Alisa, a skateboarder, is riding down a hill. If Alisa and the skateboard are considered a single object, what forces are acting on her? Check all that apply.
Answer: gravity
normal force
friction
Explanation:
A force is refered to as the interaction which when unopposed, will lead to a change in an objects motion. The velocity of an object will be changed when force is applied.
Since Alisa s riding down a hill and she and the skateboard are considered to be a single object, then the forces that are acting on her include gravity, normal force and friction.
.
A .63 kg ball is moving at 4.3m/s. What is the momentum of the ball?
Answer:
Given Mas (m) =63kg
velocity (v) =4.3m/s
momentum (p) =?
p=mv
63kgx4.3m/s
270.9kg.m/s
the momentum =270.9kg.m /s
If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.
Momentum = mass of the object × velocity of the object
As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of 4.3 meters/seconds,
The momentum of the ball = 0.63× 4.3
=2.709 kilogram meters/second
Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.
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Help me to answer this pls
here is the answers, hope this helps you.
How much will an object weigh on the moon if it weighs 60 lbs on the earth?
Answer:
10lbs on the moon
Explanation:
At 40 degrees is 25g of NaNO3 saturated or unsaturated?
I think unsaturated
because -
At 55°C, a saturated solution would contain 120 g of solute, NaNO3. (Notice, this point is exactly on the solute's curve). If, for example we mixed in 140 g of NaNO3 instead of 110 g of solute at 55°C, we would create a SUPER saturated solution, because we would be at a point ABOVE the solute's solubility curve.
a spectrometer uses a grating with 12300 lines/cm. find the angle at which red light, 634.3 nm, has the first-order bright band.
The angle at which the red light has the first-order bright band is 0.053 degrees.
The diffraction angle for red light with a wavelength of 634.3 nm can be found using the formula:
\(\theta = sin^-1 (n\lambda/L)\),
where n is the order of diffraction (1 for first-order), λ is the wavelength, and L is the number of lines per centimeter.
Therefore,
n = 1
λ = 634.3 nm = 634.3 * 10^(-9) m
L = 12300 lines/cm = 12300 * 10^(-2) lines/m
Plugging in the values, we get:
\(\theta = sin^-1 (1 * 634.3 * 10^{-9} / (12300 * 10^{-2} ))\)
Converting the result from radians to degrees gives us approximately 0.053 degrees.
This is the angle at which the first-order bright band for red light will occur in the spectrometer using a grating with 12300 lines/cm.
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a mass is hanging from spring and vibrating. it is replaced by a mass which is twice as large and its amplitude is increased by a factor of two. what happens to the period of the pendulum?
The period of the pendulum will increase by a factor of √2 when the mass is replaced by a mass that is twice as large, but the amplitude is increased by a factor of 2.
The period of a simple harmonic oscillator, such as a mass hanging from a spring, is given by:
T = 2π√(m/k)
where T is the period, m is the mass, and k is the spring constant.
If we replace the original mass with a new mass that is twice as large, the period will change as follows:
T' = 2π√(2m/k)
where T' is the new period.
If we also increase the amplitude of the motion by a factor of 2, this will not affect the period of the pendulum. The period depends only on the mass and the spring constant, and is independent of the amplitude of the motion.
Therefore, the new period of the pendulum will be:
T' = 2π√(2m/k)
which is equal to the original period multiplied by the square root of 2.
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trouble shoot a john deere d110 19hp briggs and stratton. when i try to start enging with ignition switch it blows a fuse. if i jump the starter selonoid the engine starts.
Here are a few troubleshooting steps you can take Check the fuse, Inspect the wiring, Test the ignition switch, Check the starter solenoid, Seek professional assistance.
If you are experiencing a blown fuse when trying to start the engine of your John Deere D110 with the ignition switch, but the engine starts when you jump the starter solenoid, it indicates a possible issue with the ignition switch or the wiring associated with it. Here are a few troubleshooting steps you can take:
Check the fuse: Inspect the blown fuse and replace it with a new one of the correct rating. If the new fuse blows immediately upon starting, there may be a short circuit or excessive current draw in the ignition circuit.
Inspect the wiring: Examine the wiring connected to the ignition switch, starter solenoid, and other components involved in starting the engine. Look for any loose or damaged wires, frayed insulation, or signs of overheating. Repair or replace any faulty wiring.
Test the ignition switch: Use a multimeter to check the continuity and functionality of the ignition switch. Ensure it is providing a complete circuit when in the "start" position. If the switch is faulty, replace it with a new one
Check the starter solenoid: Although the engine starts when you jump the starter solenoid, it's worth inspecting the solenoid for any issues. Ensure it is properly connected and functioning correctly. If necessary, replace the starter solenoid.
Seek professional assistance: If the above steps do not resolve the issue, it is recommended to consult a qualified technician or contact the John Deere service center for further diagnosis and repair.
Remember to take appropriate safety precautions, such as disconnecting the battery, when working with electrical components of the equipment.
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Q2. Which of these is what we call drag in a specific
liquid?
Water resistance
Tension
Gravity
O Lift
2/8
Next Question
Answer:
Water resistance
Hope this helps
Answer:
water resistance is the correct answer
A sheet of paper 3.0 cm by 4.0 cm is lying on the desk. If the atmospheric pressure is 1.013105 Pa, what is the total force exerted on the top side of the paper by the atmosphere?
Answer:
132.56N
Explanation:
Pressure is defined as force per unit area.
Expressed mathematically as;
P = F/A
Where P-pressure
F-force
A-area
From the above formula,
F= P×A
= 1.1013 × 10^5 × (3×4/10000)
= 11.013×12 =132.56N
Note: the unit of measure in cm is converted to m and since 100cm makes 1m for each sides 3cm and 4cm we convert to 'm' by dividing by 100 twice giving division by 10000)
The unit of measure Pa means Pascal and is the same as N/m2
Capacitor 2 has half the capacitance and twice the potential difference as capacitor 1.
What is the ratio Uc1/Uc2.
Where would I start with this problem and what equation would I use?
You can start the problem by using the formula for capacitance, C = Q/V, where C is the capacitance, Q is the charge stored on the capacitor, and V is the potential difference across the capacitor.
What are capacitors?A capacitor is a passive electrical component that stores electrical energy in an electric field. It consists of two conductive plates, separated by an insulating material called the dielectric. When a voltage is applied across the conductive plates, an electric field is created, which stores energy in the dielectric. The ability of a capacitor to store electrical energy is measured in farads (F).
Given that Capacitor 2 has half the capacitance and twice the potential difference as Capacitor 1, you can express the capacitance and potential difference of Capacitor 2 in terms of those of Capacitor 1.
C₂ = 1/2 × C₁ V₂ = 2 × V₁
You can use these equations to find the ratio of the stored energy in the two capacitors. The stored energy in a capacitor is given by the formula U = 1/2CV², where U is the stored energy, C is the capacitance, and V is the potential difference.
Uc1 = 1/2C₁V₁² Uc2 = 1/2C₂V₂²
By substituting the values of C₂ and V₂ in terms of C₁ and V₁, you can find the ratio of the stored energy in the two capacitors:
Uc1/Uc2 = (1/2C₁V₁²) / (1/2×(1/2C₁) (2V₁) ²) Uc1/Uc2 = 1/8
The ratio of stored energy in the two capacitors is 1/8.
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A driver takes her car to the market 40m in one direction then after shopping, she drives the car back to her house 40m in the opposite direction. What is the total displacement?
Motion of car from market 40 m in one direction then after shopping, she drives the car back to her house 40 m in the opposite direction. he total displacement is 0 meter.
What is motion?The phenomenon of an item changing its position with respect to time is known as motion in physics. In mathematics, displacement, distance, velocity, and acceleration are used to explain motion.
Displacement is change in distance between two points.
Motion of car from market 40 m in one direction then after shopping, she drives the car back to her house 40 m in the opposite direction. he total displacement is 0 meter.
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1. Match each vocabulary with it definition
4 points
According to
Newton's third When An object
law of motion experiences a A force acting
forces always force for a for a given
come in pairs, specific amount amount of time
where for every of time that that will change
action there is results in a an object's
an equal and changing its momentum
opposite momentum
reaction.
mass in motion
Momentum
O
O
O
Impulse
O
O
Collision
o
O
o
action-reaction
force pairs
According to Newton's third law, when two bodies come into contact, they exert forces on one another that are equal in size and directed in the opposite direction.
Here are the vocabulary terms matched with their definitions:
1. Newton's third law of motion - action-reaction force pairs: Forces always come in pairs, where for every action there is an equal and opposite reaction.
2. Momentum - mass in motion: The product of an object's mass and its velocity, representing the object's motion.
3. Impulse - A force acting for a given amount of time that will change an object's momentum: The product of force and time, responsible for changing an object's momentum.
4. Collision - When an object experiences a force for a specific amount of time that results in changing its momentum: An interaction between objects in which their momentum changes due to applied forces.
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1. Match each vocabulary with it definition
According to Newton's third When An object law of motion experiences a A force acting forces always force for a for a given come in pairs, specific amount amount of time where for every of time that that will change action there is results in a an object's an equal and changing its momentum opposite momentum reaction. mass in motion
Momentum-Impulse
Collision - action-reaction force pairs
Paco was driving his scooter west with an initial velocity of 4 m/s. He accelerates at 0. 5 m/s2 for 30 seconds. What is his final velocity? 2 m/s 8 m/s 19 m/s 60 m/s.
Answer:
Final velocity = 19 m/s
Explanation:
Initial velocity (u) = 4 m/s
Acceleration (a) = 0.5 m/s²
Time (t) = 30 s
Final velocity (v) = ?
In this question, you must use the formula:
v = u + at
Substitute the values into the formula.
v = 4 + (0.5 × 30)
v = 4 + 15
v = 19 m/s
A geologist studies two bands of rock on the western side of a mid-ocean ridge. Band A is located approximately 5 km from the ridge, and band B is located approximately 50 km from the ridge. Which of the following statements is most likely true?
Answer: A
Explanation:
HELP I WILL MARK Brainliest To the correct answer
Please help ACTUALLY ANSWER i dont understand CER writing?
this is an example:
Claim: cookies are good because they are good
evidence : ¨cookies have 1 billion protien¨- the new york times
reasoning: (what would i put here???)
PLEASE HELP AND ACTUALLUY ANSWER
An object moving at 6.7 m/s undergoes an acceleration of 2.7 m/s2 for 16 seconds, how far will it travel? if you can like show the work thanks.
Answer:
452.8mExplanation:
Δx=Xo+vo(t)+(1/2)(a)(t)^2Δx=0+(6.7)(16)+(1/2)(2.7)(16)^2=452.8m