Answer:
Most covalently bonded substances consist of individual separate molecules. each individual molecule is held together by means of strong convalent bonds between the atoms. in addition, there are weak forces of attraction between the individual molecules, intermolecular called forces.
what is the concentration of the iron (iii) ions in solution when 22.0 ml of 0.34 m sodium sulfide reacts with 53.0 ml of 0.22 m iron (iii) nitrate?
The concentration of iron (III) ions in the solution is 0.0705 M.
Finding the Concentration of a SolutionTo determine the concentration of iron (III) ions in the solution, we need to use the stoichiometry of the reaction between sodium sulfide (Na2S) and iron (III) nitrate (Fe(NO3)3) and the volumes and concentrations of the reactants.
The balanced equation for the reaction is:
2 Na2S + 3 Fe(NO3)3 → 6 NaNO3 + Fe2S3
From the equation:
2 moles of sodium sulfide react with 3 moles of iron (III) nitrate to form 1 mole of iron (III) sulfide.
2 moles Na2S + 3 moles Fe(NO3)3 = 1 mole Fe2S3
First, let's calculate the number of moles of sodium sulfide and iron (III) nitrate used in the reaction:
Moles of sodium sulfide = volume (in L) × concentration
= 0.022 L × 0.34 mol/L
= 0.00748 mol
Moles of iron (III) nitrate = volume (in L) × concentration
= 0.053 L × 0.22 mol/L
= 0.01166 mol
From the stoichiometry of the reaction, we can see that the mole ratio of sodium sulfide to iron (III) nitrate is 2:3. Therefore, the limiting reagent is sodium sulfide because there are fewer moles of sodium sulfide compared to iron (III) nitrate.
Since 2 moles of sodium sulfide react with 1 mole of iron (III) sulfide, we can calculate the moles of iron (III) sulfide formed:
Moles of iron (III) sulfide = (0.00748 mol Na2S) × (1 mol Fe2S3 / 2 mol Na2S)
= 0.00374 mol
Finally, we can determine the concentration of iron (III) ions (Fe3+) in the solution. Since 1 mole of iron (III) sulfide corresponds to 3 moles of Fe3+ ions, the concentration is:
Concentration of Fe3+ = moles of Fe3+ / volume (in L)
= (0.00374 mol) / (0.053 L)
= 0.0705 M
Therefore, the concentration of iron (III) ions in the solution is 0.0705 M.
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Single Replacement Reactions
Calcium + Lead (II) nitrate →
Answer:
Ca(NO3) + Pb
Explanation:
that,s the proper equation
Length of a year. 31,560,000.0 seconds = 3.156 X 10^7 seconds
How do I convert into scientific notation
Answer: 3.156 * 10^7
Explanation: I do not really understand your question. You answered it yourself!
Scientific notation shortens large numbers. The number right after the decimal point can only be between 1 and 9, which you did correctly. When converting to scientific notation, the exponent of ten is based on how many places you moved the decimal and the direction you moved it (left, positive; right, negative). In this case, the exponent of ten is a positive seven.
You did everything correctly :) Good job!
What is the total number of protons, neutrons, and
electrons in a cadmium, Cd, atom that has a mass
number of 112?
Answer:
read below ( sorry if this doesn't help :/ )
Explanation:
Cadmium is a chemical element with atomic number 48 which means there are 48 protons and 48 electrons in the atomic structure. The chemical symbol for Cadmium is Cd.
Answer:
No. of proton: 48
No. of neutron:64
No. of electrons: 48
Someone who studies the stars and planets would be working in which
branch of science?
A. Earth science
B. Marine science
C. Life science
D. Physical science
Answer:
Earth Science?
Explanation:
its not marine science or life so its physical or earth
If the change in His negative and the change in Sis positive, the process isA) spontaneous at low temperatures but not at high temperatures.B) never spontaneous.C) always spontaneous.D) spontaneous at high temperatures but not at low temperatures.
If ∆H is negative and the ∆S is positive, then the process is: C. Always spontaneous.
What is ∆H and ∆S, and their correlation to reactions’ spontaneity?∆H (entalphy change) is the amount of heat absorbed or evolved during a reaction at a constant pressure. Whereas ∆S (entropy change) is the disorder or the change in randomness in the system. Both affect the Gibbs free energy (∆G) which correlates to the spontaneity of a reaction.
The Gibbs free energy is based on this equation:
∆G = ∆H - T∆S
There are three meanings of ∆G values, which:
∆G < 0 means a reaction is spontaneous.∆G > 0 means a reaction is nonspontaneous.∆G = 0 means a reaction is at equilibrium.However, there are 4 conditions for spontaneity regarding the value of ∆H and ∆S. This could be seen in the table given below.
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How can we avoid hot spots while heating flasks with burners?
Hot spots are areas of concentrated heat that can occur when heating a flask with a burner. These spots can cause uneven heating of the flask, which can lead to a variety of problems, including cracked or shattered glassware, chemical spills, or even explosions.
To avoid hot spots when heating flasks with burners, it is important to use a good quality burner that is appropriate for the size of the flask being burner. A high-quality burner will distribute the heat evenly across the bottom of the flask, reducing the risk of hot spots.
Another important factor is to ensure that the flask is positioned correctly on the burner. The flask should be placed directly over the flame, with the bottom of the flask in contact with the burner. This will ensure that the heat is distributed evenly across the entire bottom of the flask.
It is also important to stir the contents of the flask frequently while heating to ensure that they are evenly heated. This can be done using a magnetic stirrer or by manually stirring the contents with a glass rod.
Finally, it is important to monitor the temperature of the flask carefully while heating. This can be done using a thermometer or by using a temperature controller. If the temperature of the flask starts to rise too quickly or if hot spots are detected, the heat should be reduced immediately to avoid any potential hazards.
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he student first rinsed the volumetric flask with distilled water, leaving some droplets of distilled water on the inside of the flask. as a result of this step, will the concentration of kocl(aq) be greater than, less than, or equal to 2.00 m?
The presence of some droplets of distilled water inside the volumetric flask after rinsing would not have any significant effect on the concentration of KOCl(aq). This is because the number of water droplets left behind would be very small compared to the volume of the solution that would be added to the flask.
The concentration of KOCl(aq) would remain the same as the initial concentration of 2.00 M, assuming no other factors affected the solution. The purpose of rinsing the volumetric flask with distilled water was to remove any impurities that could affect the accuracy of the concentration measurement.
In conclusion, the presence of a few droplets of distilled water in the volumetric flask would not alter the concentration of KOCl(aq). It is important to ensure that the flask is properly rinsed with distilled water to remove any impurities before measuring the concentration of a solution.
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Elements on the right side of the Periodic Table are mostly in what state of matter?
\(\huge\mathfrak\red {Answer:}\)
Elements on the right side of the periodic table are mostly Non - metals.
And Nonmetals exist in all three states of matter. The majority are gases, such as nitrogen and oxygen. Bromine is a liquid. A few are solids, such as carbon and sulfur.
\(\mathfrak\purple {Hope\: this\: helps\: you...}\)
Identify the group number and generic outer electron configuration for a neutral main‑group element with the following two Lewis dot symbols.
X with 1 dot on the top, bottom and right
X with 1 dot on all sides
Answer: Answer to #1 is 3A and ns2np1
Answer to #2 is 4A and ns2np2
Explanation:Group number is the number of valance electrons and generic outer electron configuration has to add up to equal the number of valance electrons
The element in the first diagram is in group 13 while the element in the second diagram is in group 14.
The Lewis structure of an atom of an element is a representation of the number of valence electrons on the outermost shell of the atom of that element. Every group of elements have a generic electron configuration which represents the number of valence electrons contained by atoms of elements in that group.
In the first diagram, the element X belongs to group 3A(13) and has a generic outer electron configuration, ns2np1. In the second diagram, the element X is in group 4A(14) and has outer electron configuration ns2np2.
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What does the atomic number of an element represent?
A. number of isotopes
B. number of protons
C. number of bonds
D. number of atoms
Answer:
protons
Explanation:
btw you protons and electrons are always the same
prcAnswer:
e c. proton
Explanation:
i pueslist
What amino acid is most famous for its role in the stimulation of human growth hormone, creatine synthesis, and nitric oxide production?
Answer:
L-Arginine
Explanation:
L-arginine is an essential amino acid that have the effects on growth hormone secretion and nitric oxide production.
It is estimated that the total amount of oxygen (O₂) contained in BIFs is equivalent to 6.6% of the oxygen present in the modern atmosphere. This is quite impressive given that the atmosphere during Archaean and early Proterozoic times was largely devoid of oxygen! Therefore, this reflects the photosynthetic efficiency of the early biosphere, coupled with its operation over long periods of time. Knowing that the mass of the modern atmosphere is 5.01×10¹⁸ kg, of which 21% is oxygen, what is the mass (in kilograms) of oxygen contained within BIFs?
_____ ×10¹⁶ kg of O₂ contained in BIF deposits
Knowing that the molecular mass of O₂ is 32 g/ mole (0.032 kg/ mole ), how many moles of O₂ are contained within BIFs?
____ ×10¹⁸ moles of O₂ contained in BIF deposits
Now, let us think about iron (Fe). The total mass of BIF's globally is estimated at 5.0×10¹⁷ kg, wherein iron accounts for approximately 35% by mass. The atomic mass of iron is 55.8 g/mole(0.0558 kg/mole). What is the total mass of iron in BIFs in kilograms and moles?
_____ ×10¹⁷ kg of Fe contained in BIF deposits
_____ ×10¹⁸ moles of Fe contained in BIF deposits
Finally, take the values you have computed in units of moles, and express them as the molar ratio of iron (Fe) to oxygen (O₂) of BIFs. You can do this by dividing both sides of the ratio by the larger number (Fe in this case).
FeO₂=1 _____
Your calculated ratio above should fall between the Fe: O₂ molar ratios of both Hematite (1:0.75) and Magnetite (1:0.67). Which molar ratio is your calculated value closest to (meaning which iron component, Hematite or Magnetite, is the more dominate in BIFs)?
The calculated molar ratio of iron to oxygen in BIFs is 1.452.
Comparing this ratio to the molar ratios of Hematite (1:0.75) and Magnetite (1:0.67), we can see that the calculated value of 1.452 is closest to the Hematite molar ratio of 1:0.75. Therefore, Hematite is the more dominant iron component in BIFs.
To calculate the mass of oxygen contained within BIFs, we'll use the given information:
Total mass of the modern atmosphere = 5.01×10¹⁸ kg
Percentage of oxygen in the modern atmosphere = 21%
Mass of oxygen contained within the modern atmosphere = (5.01×10¹⁸ kg) × (0.21) = 1.051×10¹⁸ kg
Percentage of oxygen contained in BIFs = 6.6% (given)
Mass of oxygen contained within BIFs = (6.6% of 1.051×10¹⁸ kg) = 6.6/100 × 1.051×10¹⁸ kg = 6.9166×10¹⁶ kg
Therefore, the mass of oxygen contained within BIFs is 6.9166 × 10¹⁶ kg.
To calculate the number of moles of oxygen contained within BIFs, we'll use the molecular mass of O₂:
Molecular mass of O₂ = 0.032 kg/mole
Number of moles of oxygen contained within BIFs = (Mass of oxygen in BIFs) / (Molecular mass of O₂)
= (6.9166×10¹⁶ kg) / (0.032 kg/mole) = 2.1614375 × 10¹⁸ moles
Therefore, the number of moles of oxygen contained within BIFs is 2.1614375 × 10¹⁸ moles.
Next, let's calculate the mass of iron in BIFs:
Total mass of BIFs = 5.0×10¹⁷ kg
Percentage of iron in BIFs = 35%
Mass of iron contained within BIFs = (35% of 5.0×10¹⁷ kg) = 35/100 × 5.0×10¹⁷ kg = 1.75×10¹⁷ kg
To calculate the number of moles of iron contained within BIFs, we'll use the atomic mass of iron:
Atomic mass of iron = 0.0558 kg/mole
Number of moles of iron contained within BIFs = (Mass of iron in BIFs) / (Atomic mass of iron)
= (1.75×10¹⁷ kg) / (0.0558 kg/mole) = 3.1367419 × 10¹⁸ moles
Therefore, the number of moles of iron contained within BIFs is 3.1367419 × 10¹⁸ moles.
Finally, let's calculate the molar ratio of iron to oxygen in BIFs:
Molar ratio of iron to oxygen = (Number of moles of iron) / (Number of moles of oxygen)
= (3.1367419 × 10¹⁸ moles) / (2.1614375 × 10¹⁸ moles)
≈ 1.452
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Which of the following is not a magnetic material A cobalt B iron C nickel D plastic E steel
Answer:
D. plastic\(\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}\)
An ionic compound formed by a neutralization reaction
a.
acid
c.
solvent
b.
base
d.
salt
Answer: salt
Explanation:
..................
arrange the following elements in order of decreasing atomic size: f, ne, na.
The atomic size generally decreases from left to right across a period in the periodic table and increases from top to bottom within a group.
Fluorine (F) is located on the right side of the periodic table and has a small atomic radius due to the strong attraction between the valence electrons and the nucleus. Neon (Ne) is located to the left of fluorine, in the noble gases group, and has a larger atomic radius than fluorine due to its additional electron shell. Sodium (Na) is located to the left of neon, in the alkali metals group, and has a much larger atomic radius due to its much larger atomic size.
Therefore, the correct order of the given elements in decreasing atomic size is:
Na > Ne > F
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How many grams are in 0.44 moles of C2H6?
Answer: Im pretty sure it is 13.23037759999987 because I just used a calculator.
Explanation:
Answer:
13.23 grams C2H6
Explanation:
Convert 0.44 moles to grams
13.23 g C2H6
Hope this helps!
Label the equivalence point on the graph of pH versus volume of the titration of a strong acid and strong base shown below
no bots please!
a. What volume of base was needed to neutralize the acid?
b. What is the pH at the equivalence point?
c. How does the number of moles of hydronium ions and hydroxide ions compare at the
equivalence point?
What kind of reaction is KI(aq) +AgNO3(aq) --> AgI(s) + KNO3 (aq)
Answer:
A double-replacement reaction
Explanation:
you're welcome
I need help asap!!! At least with the first part
Answer:
The correct answer -
a. Cd and Pb(NO3)2
b. Redox reactions
c. Pb and Cd(NO3)2
Explanation:
This is the reaction known as the redox or reduction-oxidation reaction of metals. In this particular reaction, there are two reactants Cadmium (III) in solid-state and lead (II) nitrate in the aqueous state. At the end of this reaction, the products that we get are lead (II) in solid-state and Cadmium (III) nitrate in the aqueous state.
cadmium (s)+ lead nitrate (aq) = lead (s) + cadmium nitrate (aq)
Cd (s) + Pb2+(aq) → Pb(s) + Cd2+(aq)
Here, Oxidizing agent is Pb2+ and the reducing agent is Cd.
Based on your knowledge of the periodic table, identify the element Y.
Answer: argon
Explanation:
using the last clue “avg atomic mass of 3.33x greater than carbon-12” we can deduce the atomic mass of the element is 12x3.33=40(2sf) hence its argon. we can further confirm from third clue that it is a noble gas hence unreactive
15. Which of the following statements is correct?
a) Wear rate decreases by increasing the material hardness
b) Wear rate increases by increasing the material hardness
c) Wear rate is not dependant on the material hardness
d) None of the above
16. What type of load causes a fatigue crack initiation?
a) Impact load
b) Static permanent load
c) Dynamic cyclic load
d) Sudden compressive load
Fatigue crack initiation typically occurs under dynamic cyclic loading conditions.
The correct option is:
a) Wear rate decreases by increasing the material hardness
Increasing the hardness of a material generally improves its resistance to wear.
Harder materials have better wear resistance because they can withstand greater forces and are less prone to surface deformation, abrasion, and material removal during sliding or rubbing contact.
The correct option is:
c) Dynamic cyclic load
Fatigue crack initiation typically occurs under dynamic cyclic loading conditions.
When a material is subjected to repeated loading and unloading cycles, especially with high-stress amplitudes, it can lead to the initiation and propagation of fatigue cracks over time.
The cyclic nature of the load induces progressive damage and eventual failure due to the accumulation of microstructural changes and crack growth.
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When the equation
Cu + AgNO3 → Cu(NO3)2 + Ag
is balanced, the coefficient of copper (II) nitrate is
A. 0.
B. 3.
C. 1
An equation which follow the law of conservation of mass is called the balanced equation. The coefficient of copper (II) nitrate is 1 .The correct option is C.
What is a balanced equation?A chemical equation in which the number of atoms of reactants and products on both sides of the equation are equal is defined as the balanced chemical equation.
The coefficients are the numbers which are used to balance the chemical equation. They are added in front of the formulas. According to law of conservation of matter, mass can neither be formed nor be destroyed.
The balanced equation for the given reaction is:
Cu (s) + 2AgNO₃ (aq) → Cu (NO₃)₂ (aq) + 2Ag (s)
Here the coefficient of Cu (NO₃)₂ is 1. The number of 'Cu', 'Ag', 'N' and 'O' atoms are equal. So the given equation is balanced. The coefficient of AgNO₃ is 2, and 'Ag' is 2.
Thus the correct option is C.
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Molarity of Kool Aid solutions can be calculated by comparing the concentrations of Kool Aid powder and sugar added to a given volume of water. The molar mass of Kool Aid will be the same as that of sugar for our purpose. The molecular formula for sugar is C12H22O11- Your objective for this lab will be to calculate the molarity of Kool Aid desired based on package directions. You will then be provided two concentrated Kool Aid solutions. You will use dilution calculations to determine the amount of water and concentrated solution you will need in order to prepare 65 mL of the desired molarity.
Calculate the molarity of Kool Aid desired based on the following information from the package directions.
1 package Kool Aid powder = 4. 25 grams 1 cup sugar = 192. 00 grams
2. 00 quarts of water (1. 06 quarts = 1 liter)
The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.
To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:
Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)
= 144.12 + 22.22 + 176.00
= 342.34 g/mol
Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:
Number of moles of Kool Aid powder = Mass / Molar mass
= 4.25 g / 342.34 g/mol
≈ 0.0124 mol
Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:
Number of moles of sugar = Mass / Molar mass
= 192.00 g / 342.34 g/mol
≈ 0.5612 mol
Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:
Volume of water = 2.00 quarts * (1.06 liters / 1 quart)
= 2.12 liters
To find the molarity, we use the formula:
Molarity (M) = Number of moles / Volume (in liters)
Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L
≈ 0.286 M
To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.
Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:
(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:
(C M)(V mL) = (0.286 M)(65 mL)
V mL = (0.286 M)(65 mL) / C M
So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.
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the saturated shown above is left uncovered on a lab bench at a constant temperature. as the solution evaporates, samples of the solution are removed every three days and the in the samples is measured. it is observed that the in the solution did not change over time. which of the following best helps to explain the observation? (a) as the solution evaporates, and leave the beaker along with the water molecules. (b) as the solution evaporates, the dissolution of in the beaker decreases. (c) the evaporation of water is endothermic, so more dissolves exothermically in the solution, which increases the . (d) as water evaporates, more precipitates out of the solution in the beaker.
Answer: option D
Explanation:
Which of the following is an example of chemical weathering?
O A. Water freezes in cracks in a rock, breaking the rock apart.
O B. Weak acid breaks down minerals by reacting with them.
O C. Plant roots grow and split rock into pieces.
O D. An animal kicks a rock down a hill where it hits another rock and shatters.
Answer:O B. Weak acid breaks down minerals by reacting with them.
Explanation:
Chemical weathering is the process whereby rain water which sometimes can be acidic ( As rain falls down it reacts with CO2 in the atmosphere and form acid rain), This reacts with the minerals contained in rocks, dissolves and degrades them further to form entire new minerals.
An example of a rock that is greatly affected by overexposure of acid rain is limestone containing calcite which easily degrades by acid rain.
Other processes whereby Chemical weathering can occur are through reaction with water and oxygen.
In calculating the mass of an atom the mass of the electrons is essentially
Answer:
Sex
Explanation:
a 2.85 g lead weight, initially at 10.3 °c, is submerged in 7.55 g of water at 52.3 °c in an insulated container. what is the final temperature of both substances at thermal equilibrium?
The final temperature of both substances at thermal equilibrium is 51.96°C.
Solution:
31.91 T =10374.27
T= 325.11 K or T= 51.96 °c
Final equilibrium Temperature (T) = 51.96°C.
Two systems are said to be in thermal equilibrium when they are in contact with each other and there is no energy flow between them. Simply put, thermal equilibrium means that two systems are at the same temperature. The zero law of thermodynamics states that if two systems are in thermodynamic equilibrium with his third system, then the original He said that the two systems are in thermal equilibrium with each other.
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When 25.0 mL of a fluid is placed in a beaker with a mass of 30.36 g, the resulting mass of both beaker and fluid is 61.89 g. Determine the density of the fluid.
The formula for density is given by:p= m/v Where p is the density,m is the mass and,v is the volume.We are given that the mass of the beaker and the fluid is 61.89 g. Subtracting the mass of the empty beaker (30.36 g) from the combined mass gives the mass of the fluid to be:61.89 g - 30.36 g = 31.53 g.
Converting the volume of the fluid to liters:25.0 mL = 0.025 L. The density of the fluid can now be calculated as follows:
p = 31.53 g / 0.025 L = 1261.2 g/L.
The first step when calculating density is to identify the mass and volume of the substance. In this problem, we are given the volume of the fluid in milliliters and the mass of the beaker and fluid in grams. To calculate the mass of the fluid, we simply subtract the mass of the empty beaker from the combined mass of the beaker and fluid. We then convert the volume to liters since density is expressed in units of mass/volume.To calculate the density of the fluid, we use the formula:p = m/vwhere p is the density, m is the mass, and v is the volume. Plugging in the values we have, we get:p = 31.53 g / 0.025 L = 1261.2 g/L
Therefore, the density of the fluid is 1261.2 g/L.
Given the mass of the beaker and fluid, and the volume of the fluid, we were able to calculate the density of the fluid using the formula: p = m/v. We found that the density of the fluid is 1261.2 g/L.
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Explain the function of the valence ring?
Answer:
It provides the electrons that "make" electricity and it contains the electrons that are involved in molecular bond formation.