Moving water can be used to produce electricity because.
Answers
Moving water can be used to produce electricity because it possesses a significant amount of kinetic energy. This energy can be harnessed using a turbine to turn it into electrical energy that can be used to power homes and businesses.
When water flows through a dam, it exerts pressure on the blades of the turbine, causing them to turn. The mechanical energy produced by the turning turbine is then transformed into electrical energy by a generator that converts the rotational energy into electrical energy that can be used to power homes, businesses, and other facilities. Hydropower is a renewable source of energy that can be used to generate electricity without producing harmful emissions that pollute the environment. It is a clean and sustainable source of energy that can be used to power homes, businesses, and industries. The use of hydropower to generate electricity has a significant environmental benefit, as it reduces the emission of greenhouse gases into the atmosphere, which contributes to climate change. Moving water is a powerful force that can be harnessed to produce electricity and provide power to communities around the world.
In conclusion, moving water can be used to produce electricity because it has a significant amount of kinetic energy that can be harnessed to generate electrical energy. The use of hydropower to generate electricity is a clean, renewable, and sustainable source of energy that can be used to power homes, businesses, and industries without polluting the environment.
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Related Questions
How much work input is required to lower (not drop) a 120-pound weight from the top of a 3-foot table to the floor?
A. 40 foot-pounds.
B. 360 foot-pounds.
C. 120 pounds of force.
Answers
The work input required to lower a 120-pound weight from the top of a 3-foot table to the floor is 360 foot-pounds. The correct answer is option B.
The work done to lower an object is calculated by multiplying the force exerted on the object by the distance over which the force is applied. In this case, the force exerted is the weight of the object, which is 120 pounds.
The distance over which the force is applied is the vertical distance from the table's top to the floor, which is 3 feet.
To calculate the work input, we use the formula W = F × d, where W is the work, F is the force, and d is the distance.
Substituting the given values, we have W = 120 pounds × 3 feet = 360 foot-pounds.
Therefore, the work input required to lower the 120-pound weight from the top of the 3-foot table to the floor is 360 foot-pounds.
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A 5 kg object is moving downward at a velocity of 12 m/s and is
currently 2.6 meters above the ground.
calculate its kinetic energy
calculate its potential energy
calculate its mechanical energy
Answers
Answer:
the first one i think
Explanation:
Astronauts aboard the ISS appear as if they are floating
Answers
Which best describes the relationship between hardware and software? Software instructs hardware how to perform. Software allows users to interact with hardware. Hardware directs the performance of software. Hardware enables software to perform correctly.
Answers
Answer:
A
Explanation:
Answer:
aAAAAAA
Explanation:
What variables have the most effect on the strength of the gravitational attraction between two massive objects?
Help
Answers
Answer:
The distance between the 2 centers of the object.
Explanation:
If it's harder to win a super bowl for the rams than the gravity means the chiefs will win it.
A hammer drives a nail into a piece of wood. Identify an action-reaction pair.Group of answer choicesThe hammer exerts a force on the nail; the wood exerts a force on the nail.The hammer exerts a force on the nail; the hammer exerts a force on the wood.The nail exerts a force on the hammer; the hammer exerts a force on the wood.The hammer exerts a force on the nail; the nail exerts a force on the hammer.
Answers
Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Let:
A = Hammer
B = Nail
so:
\(F_{AB}=-F_{BA}\)Therefore:
The hammer exerts a force on the nail; the nail exerts a force on the hammer.
find the mass and center of mass of the solid e with the given density function . e is bounded by the parabolic cylinder z = 1 − y2 and the planes x 5z = 5, x = 0, and z = 0; (x, y, z) = 7.
Answers
The mass of E is 28/3, and the center of mass is located at (35/36, 0, 7/4).
We can use the triple integral to find the mass and center of mass of the solid E:
The limits of integration for x are from 0 to 5z.
The limits of integration for y are from −1 to 1.
The limits of integration for z are from 0 to 1 − y²
The density function is given by ρ(x, y, z) = 7.
Thus, the mass of E is given by:
M = ∭E ρ(x, y, z) dV
= ∭E 7 dV
= ∫₀⁵z ∫₁⁻¹ ∫₀¹−y² 7 dz dy dx
= 28/3
The x-coordinate of the center of mass is given by:
x-bar = (1/M) ∭E xρ(x, y, z) dV
= (1/M) ∭E x(7) dV
= (1/M) ∫₀⁵z ∫₋₁¹ ∫₀¹−y² x(7) dz dy dx
= 35/36
Similarly, the y-coordinate of the center of mass is given by:
y-bar = (1/M) ∭E yρ(x, y, z) dV
= (1/M) ∭E y(7) dV
= (1/M) ∫₀⁵z ∫₋₁¹ ∫₀¹−y² y(7) dz dy dx
= 0
And, the z-coordinate of the center of mass is given by:
z-bar = (1/M) ∭E zρ(x, y, z) dV
= (1/M) ∭E z(7) dV
= (1/M) ∫0^5z ∫−1^1 ∫0^1−y^2 z(7) dz dy dx
= 7/4
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An object moving with a speed of 108km/h stops in 15s due to auniform acceleration.Find the value of the acceleratiin.
Answers
Vf (final velocity) = 0 m/s (because it stops)
Δt(time)=15 s
a (acceleration) = ?
The rule for acceleration is
a= (Vf - Vi)/Δt
Substitute
a= (0-30)/15 = -30/15 = -2 m/s^2
Hope this helps
108 km/h = 30 m/s (approx)
The formula for acceleration is:
a = (v_f - v_i) / t
where a is the acceleration, v_f is the final velocity, v_i is the initial velocity, and t is the time taken. We know the initial velocity is 30 m/s (since the object is moving with a constant velocity before it starts to decelerate), the final velocity is 0 m/s (since the object comes to a stop), and the time taken is 15 s. Substituting these values into the formula, we get:
a = (0 - 30) / 15 = -2 m/s^2
The negative sign indicates that the acceleration is in the opposite direction to the initial velocity, which is deceleration. Therefore, the value of the acceleration is 2 m/s^2.
Can a solution be separated by filtration?
Answers
Answer:
Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )
Explanation:
Listo!
If you are in motion can you have the same speed as someone else in motion but different velocities? Give an example
Answers
Answer:
Yes
Explanation:
Velocity is a vector quantity, meaning it has size and direction, as opposed to speed, a scalar quantity which only has size.
An example is speed may be 30km/h, and an example of velocity is 30km/h East.
Therefore two people can have the same speed and different velocities because they can be traveling in different directions.
For example, you and your friend could be doing shuttles together but you started at one wall and they started at the other, so even though you are running at the same speed, you always have different velocities because they are running in the opposite direction as you.
Hope this helped!
Can ya pls answer dis rq!
Answers
Answer: Proteins are large molecules composed of one or more chains of amino acids.
Answer: We need protein to help the body repair cells and make new ones.
Answer: We should choose which proteins to eat by shifting the balance of carbs and proteins.
Answer: Low protein foods are not proteins such as,dried fruits, peas,beans,and corn.
A student standing on a stationary skateboard tosses a textbook with a mass of my = 1.55 kg to a friend standing in front of him. The student and the skateboard have a combined mass of m. = 99 kg and the book leaves his hand at a velocity of r = 2.25 m/s at an angle of 27° with respect to the horizontalwhat is the velocity of the center of mass of the student-book system (in the lab frame) before the student throws the book?
Answers
The velocity of the center of mass of the student-book system before the student throws the book is -0.0352 m/s.
The velocity of the center of mass of the student-book system before the student throws the book can be found using the conservation of momentum. The total momentum of the system before the book is thrown is equal to the total momentum of the system after the book is thrown.
Before the book is thrown, the student and the skateboard are stationary, so the total momentum of the system is zero. After the book is thrown, the momentum of the system is the sum of the momentum of the student and skateboard and the momentum of the book.
The momentum of the student and skateboard is equal to their combined mass (m) times their velocity (v), and the momentum of the book is equal to its mass (m_y) times its velocity (r).
Using the conservation of momentum equation, we can solve for the velocity of the student and skateboard (v):
0 = mv + m_yr
v = -m_yr/m
Plugging in the given values for the mass of the book (m_y = 1.55 kg), the mass of the student and skateboard (m = 99 kg), and the velocity of the book (r = 2.25 m/s), we get:
v = -(1.55 kg)(2.25 m/s)/(99 kg) = -0.0352 m/s
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Will give correct answer brainliest please help
Two cars are involved in a head-on collision in an alley. The driver of a car with mass,
ma = 1,200 kg claims to have been traveling west at via = 7 m/s. The driver of the
other car with mass, mb = 1,000 kg claims to have been traveling east at vib - 10
m/s. The investigating officer found that both cars were stuck together and traveled
with a common final velocity of 3 m/s, eastward, after the collision.
Assuming that at least one driver is correct, what does an application of the law of
conservation of momentum allow the officer to conclude about the accident?
The driver of the westbound car was moving significantly faster than reported.
Both drivers correctly reported their velocities at the time of the collision.
Either the driver of the westbound car overestimated his velocity or the driver of
the eastbound car underestimated his velocity,
KID Either the driver of the westbound car underestimated his velocity, or the driver
of the eastbound car overestimated his velocity.
Answers
Answer:
it is the 3rd answer choice
The correct assumption of the given situation is required.
The correct option is
Either the driver of the westbound car overestimated his velocity or the driver of the eastbound car underestimated his velocity,
\(m_a\) = Mass of west moving car = 1200 kg
\(m_b\) = Mass of east moving car = 1000 kg
\(v_{ia}\) = Velocity of west moving car = -7 m/s
\(v_{ib}\) = Velocity of east moving car = 10 m/s
v = Combined velocity of the cars = 3 m/s
From the conservation of momentum we get
\(m_av_{ia}+m_bv_{ib}=(m_a+m_b)v\\\Rightarrow 1200\times -7+1000\times10=(1000+1200)\times 3\\\Rightarrow 1600\neq 6600\)
So, either westward ( \(1000\times10\) ) moving car needs to have more velocity or eastward (\(1200\times -7\)) moving car needs to have less velocity.
Since, mass is constant only the velocity can be different.
The correct option is
Either the driver of the westbound car overestimated his velocity or the driver of the eastbound car underestimated his velocity.
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The beat frequency produced when a 240 hertz tuning fork and a 246 hertz tuning fork are sounded together is
Answers
The beat frequency produced when a 240 Hz tuning fork and a 246 Hz tuning fork are sounded together is 6 Hz. This corresponds to option d) 6 hertz.
When two tuning forks with slightly different frequencies are sounded together, they produce a beat frequency. The beat frequency is the result of the interference between the two waves produced by the tuning forks.
In this case, we have a 240 Hz tuning fork and a 246 Hz tuning fork. To find the beat frequency, we need to calculate the difference between the frequencies of these two tuning forks:
Beat frequency = |Frequency1 - Frequency2|
Beat frequency = |240 Hz - 246 Hz|
Beat frequency = |-6 Hz|
Since frequency cannot be negative, we take the absolute value of the result:
Beat frequency = 6 Hz
So, the beat frequency produced when a 240 Hz tuning fork and a 246 Hz tuning fork are sounded together is 6 Hz. This corresponds to option d) 6 hertz.
In summary, the beat frequency is the difference between the frequencies of two tuning forks sounded together. In this case, with a 240 Hz and a 246 Hz tuning fork, the beat frequency is 6 Hz.
The complete question is:
The beat frequency produced when a 240 hertz tuning fork and a 246 hertz tuning fork are sounded together is
a) 245 hertz
b) 240 hertz
c) 12 hertz
d) 6 hertz
e) none of the above
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What is the most abundant gas in the atmosphere?
Group of answer choices
Oxygen
Nitrogen
Carbon Dioxide
Water Vapor
Answers
Answer: Nitrogen
Explanation: Nitrogen makes up 78% of the atmosphere, Oxygen makes up 21%, and Argon 0.9%.
Water vaper makes up between 1-4%, depending on the region.
Carbon Dioxide makes up only about 0.04%.
Answer: The answer is: Nitrogen
Explanation: I have my ways ;>
A stone dropped from the top of a building strikes the ground in 4.2 s. How tall is the building? Someone explain please!
Answers
Answer:
well i'm not sure if which unit of measure you need but i think its 86.49 meters tall.
0.18 kg of helium is constrained within one portion of an insulated container,such that it fills a volume of only 2.1 . a barrier divides the helium from the rest of the container, which is completely evacuated. for some unknown reason, the barrier ruptures. as a result, the helium expands to fill the entire container. the temperature of the helium remains a constant 340 k before, during, and after the expansion. if the specific volume of the helium increases by a factor of 3.5 during the expansion, what is the final pressure of the helium in kpa?
Answers
The final pressure of the helium in kPa would be 28.986 P1 kPa.
Ideal gas problemTo solve this problem, we can use the ideal gas law, which states that:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
Given:
Initial volume of helium (V1) = 2.1 L
Final volume of helium (V2) = 2.1 L * 3.5 = 7.35 L
Amount of helium (n) = mass / molar mass = 0.18 kg / 4 g/mol = 0.045 mol
Temperature (T) = 340 K
Gas constant (R) = 8.314 J/(mol·K)
Using the ideal gas law, we can write the equation as:
P1 * V1 = n * R * T
P2 * V2 = n * R * T
Since the temperature remains constant, we can simplify the equation as:
P1 * V1 = P2 * V2
Substituting:
P1 * 2.1 L = P2 * 7.35 L
P2 = (P1 * 2.1 L) / 7.35 L
P2 = P1 * 0.286
Now, we need to convert the pressure from atm to kPa:
1 atm = 101.325 kPa
P2 (kPa) = P2 (atm) * 101.325 kPa
P2 (kPa) = P1 * 0.286 * 101.325 kPa
= 28.986 P1 kPa.
Therefore, the final pressure of the helium in kPa is approximately 28.986 P1 kPa.
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Part A
What is the mean free time between collisions for electrons in an aluminum wire?
= _____________ s
Wrong answers: 6.97*10^-9 and 1.26*10^-9
Part B
What is the mean free time between collisions for electrons in an iron wire?
=______________ s
Wrong answers: 1.40*10^-9 and 3.67*10^-10
Answers
The mean free time between collisions for aluminum wire is
1.62 * 10^-20 s and the mean free time between collisions for Iron is
1.68 * 10^-20 s.
What are electrons?Electrons are subatomic particles that carry a negative electrical charge. They are found outside the nucleus of an atom and are responsible for chemical reactions, electrical conductivity, and magnetism.
The mean free time between collisions for electrons in a metal wire can be calculated using the mean free path (λ) and the electron density (n) of the metal. The mean free time between collisions is given by the equation:
τ = λ / v
Where τ is the mean free time, λ is the mean free path, and v is the velocity of the electrons.
Using the formula, we can calculate mean free path:
λ = 1 / (n * σ)
Where σ is the collision cross-section, which is a measure of how likely it is for an electron to collide with an atom in the metal.
For aluminum, the mean free path is approximately:
λ = 1 / (n * σ) = 1 / (8.49 * 10^28 * 2.82 * 10^-15) = 3.51 * 10^-14 m
For aluminum, the mean free time between collisions is:
τ = λ / v = 3.51 * 10^-14 m / (2.18 * 10^6 m/s) = 1.62 * 10^-20 s
For Iron, the mean free path is approximately:
λ = 1 / (n * σ) = 1 / (8.05 * 10^28 * 2.82 * 10^-15) = 3.65 * 10^-14 m
For Iron, the mean free time between collisions is:
τ = λ / v = 3.65 * 10^-14 m / (2.18 * 10^6 m/s) = 1.68 * 10^-20 s
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A train travelling at 22m/s accelerates uniformly at 0.85 m/s^2 for 25s. Calculate the distance travelled by the train at this time.
Answers
The distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
What is Second equation of motion?
The second equation of motion is used to calculate the distance traversed by the body moving with uniform velocity. Mathematically -
S = ut + 1/2 at²
Given in the question is a train travelling at 22 m/s accelerates uniformly at 0.85 m/s² for 25s. From this, we can write -
Initial velocity [u] = 22 m/s
acceleration [a] = 0.85 m/s²
time taken [t] = 25 s
In order to find the distance travelled by the train, we will use the second equation off motion -
S = ut + 1/2 at²
S = 22 x 25 + 1/2 x 0.85 x 25 x 25
S = 815.62 meters
Therefore, the distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
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an accident victim with a broken leg is being placed in traction. the patient wears a special boot with a pulley attached to the sole. the foot and boot together have a mass of 4.0 kg, and the doctor has decided to hang a m = 7.0kg mass from the rope. the boot is held suspended by the ropes and does not touch the bed. (figure 1)no title providedA) Determine the amount of tension in the rope by using Newton?s laws to analyze the hanging mass. Assume that ? = 11? ^ circ . Hint: If the pulleys are frictionless, which we will assume, the tension in the rope is constant from one end to the other.B) The net traction force needs to pull straight out on the leg. What is the proper angle ? for the upper rope?C) What is the net traction force pulling on the leg?
Answers
The amount of tension in the rope by using Newton's laws if The mass suspended on ropes is 7 kg, is 68.6 Newtons.
What is mass?A fundamental characteristic of an object, its inertia is quantified by its mass, which is a basic indicator of the volume of substance inside the thing. Because mass is such a fundamental quantity and is difficult to define in terms of another, definitions of it frequently appear circular.
It is possible to define every mechanical quantity in terms of mass, length, and time. The SI unit for mass, denoted by the letter m, is the kilogram.
Given:
The mass of the foot and boot, M = 4 kg,
The mass suspended by ropes, m = 7 kg,
Calculate the tension on the rope as shown below,
Tension on the ropes = m × a
Tension on the ropes = 7 × 9.8
Tension on the ropes = 68.6 N
Thus, the tension on the boot and foot is 68.6 N.
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Help
A. 12,240
B. 6,120
Answers
Answer:
A. 12,240.
Explanation:
1,530 times 8.0 = 12,240.
hope this helped :)
i need help with this question really urgent
Answers
Answer:
Cost Per Hour:
132.0000
Cost Per Day:
39600.0000
Cost Per Month:
1204632.00
Cost Per Year:
14455584.00
kWh Per Day:
3600.00
Which of the following determines the identity of an atom?
A. atomic mass
B. mass number
C. atomic number
D. charge
Answers
how did clair patterson determine the age of earth
Answers
Answer:
Patterson isolated lead from fragments of a meteorite that had struck Earth thousands of years ago, and determined the age of the fragments by analyzing proportions of the lead isotopes. The meteorite is assumed to have been formed at the same time as the rest of the solar system, including Earth
Explanation:
Objects 1 and 2
attract each other with
a electrostatic force
of 72.0 units. If the charge of Object
is one-third the
original value AND the charge of object 2 is doubled AND
the distance separating Objects 1 and 2 is doubled, then the
new electrostatic force will be
units.
Answers
Answer:
12 units
Explanation:
Original F = C q1q2/r^2 now change the parameters
New F = C 1/3 q1 2 q2 / (2r)^2
= 2/12 C q1q2/r^2 <=======the new force is 1/6 of original
1/6 * 72 = 12 units
12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answers
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
P = (400 + k * 15²) * 15
P = (400 + 11250) * 15
P = 11650 Watts
Therefore, the power necessary to maintain the speed of 15ms^-1 is approximately 11650 Watts.
b. The total resistive force at a speed of 30ms^-1 can be found by substituting 30 for v in the force equation:
F = 400 + k * 30^2
F = 12000 N
Therefore, the total resistive force at a speed of 30ms^-1 is approximately 12000 N.
c. The power required to maintain the speed of 30ms^-1 can be found using the same equation as in part a:
P = (400 + k * 30^2) * 30
P = (1500 + 600000) * 30
P = 625000000 Watts
Therefore, the power required to maintain the speed of 30ms^-1 is approximately 625000000 Watts. This is a very large amount of power and would require a significant amount of energy to maintain.
What happens to the density of an object if the mass increases, but the volume remains the same?
Answers
A measure of mass per unit of volume. It is how much material a certain volume contains. ... If the volume of the object stays the same but the mass of the object increases then its density becomes greater.
Car AMass: 1,500 kgVelocity: 10 m/sCar BMass: 1,500 kgVelocity: 25 m/sCar CMass: 1,000 kgVelocity: 10 m/sWhich order shows decreasing momentum?A, B, CB, A, CC, B, A
Answers
Answer:
B, A, C
Explanation:
The momentum is equal to the mass times the velocity, so for each car the momentum is equal to
Car A
Momentum = Mass x Velocity
Momentum = 1,500 kg x 10 m/s
Momentum = 15,000 kg m/s
Car B
Momentum = Mass x Velocity
Momentum = 1,500 kg x 25 m/s
Momentum = 37,500 kg m/s
Car C
Momentum = Mass x Velocity
Momentum = 1,000 kg x 10 m/s
Momentum = 10,000 kg m/s
Then, the decreasing momentum is B, A, C because
37,500 is greater than 15,000 and 15,000 is greater than 10,000
So, the answer:
B, A, C
Suppose you measured periods of several pendulums of different lengths. Upon analyzing the data and fitting to a power law, y = aLb, you get values of a = 1.98 and b = 0.485 . What value of the acceleration due to gravity (g, in m/s2) can you infer?
Answers
The period of a pendulum is affected by its length, mass, and the acceleration due to gravity (g). From this problem, we have measured the periods of several pendulums of different lengths.
We have to analyze the data by fitting to a power law, y = a L b. Let us begin by recalling the equation for the period of a pendulum:
\(T = 2π (L/g)^1/2\) Here, T is the period of the pendulum L is the length of the pendulum g is the acceleration due to gravity (which is to be determined).
Substituting the power law, y = a L b in the equation above, we get:
\(2π (L/(a/y^b))1/2 = T2π (y^b/a)^1/2 L^1/2 = Tg = 4π² L/aT²y^b\) Hence, the value of the acceleration due to gravity (g) can be inferred from the equation above as:
\(g = 4π² L/aT²y^b\)
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1. describe what happened when you increased the applied force from 0 to 300n?
Answers
When you increase the applied force from 0 to 300N, the net force also increases as a result. In physics, force is defined as the push or pull applied on an object to cause a change in its motion. When the force is applied, it can either accelerate or decelerate an object in motion, or start moving an object that is at rest.
In the scenario of increasing the applied force from 0 to 300N, a change in the motion of an object was achieved. When an object is in motion, there are different types of forces that act upon it. The different forces are gravitational force, magnetic force, frictional force, and tension force. In this scenario, we are dealing with an applied force. An applied force is the force exerted on an object by a person or another object. This force is used to move or stop an object. As the applied force increases from 0 to 300N, the net force also increases. The net force is the sum of all the forces acting on an object. The increase in the applied force means there is an increase in the net force. The net force and acceleration of an object are directly proportional.
As the net force increases, so does the acceleration. The acceleration of an object is defined as the rate at which the velocity of an object changes over time. The formula for acceleration is given as a = (v₂ - v₁) / t, where v₂ is the final velocity, v₁ is the initial velocity, and t is the time. Acceleration is measured in m/s². The increase in the net force will cause an increase in the acceleration of the object. When an object is at rest, there are no forces acting on it, and its velocity is zero. The moment an applied force is exerted, it begins to move, and its velocity increases. The increase in the velocity of the object means that its acceleration is also increasing. The force required to move an object depends on its mass.
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