Answer: He should’ve multiplied 70x5 but instead he added 70+5.
Step-by-step explanation:
Hope I helped! May I have brainliest!
1. Let the distribution of X be the normal distribution N (μ, σ2) and let Y = aX + b. Prove that Y is distributed as N (aμ + b, a2σ2).
2. Let X and Y be two independent random variables with E|X| < [infinity], E|Y| < [infinity] and E|XY| < [infinity]. Prove that E[XY] = E[X]E[Y].
1 Y is distributed as N(aμ + b, a^2σ^2), as desired.
2 We have shown that under these conditions, E[XY] = E[X]E[Y].
To prove that Y is distributed as N(aμ + b, a^2σ^2), we need to show that the mean and variance of Y match those of a normal distribution with parameters aμ + b and a^2σ^2, respectively.
First, let's find the mean of Y:
E(Y) = E(aX + b) = aE(X) + b = aμ + b
Next, let's find the variance of Y:
Var(Y) = Var(aX + b) = a^2Var(X) = a^2σ^2
Therefore, Y is distributed as N(aμ + b, a^2σ^2), as desired.
We can use the definition of covariance to prove that E[XY] = E[X]E[Y]. By the properties of expected value, we know that:
E[XY] = ∫∫ xy f(x,y) dxdy
where f(x,y) is the joint probability density function of X and Y.
Then, we can use the fact that X and Y are independent to simplify the expression:
E[XY] = ∫∫ xy f(x) f(y) dxdy
= ∫ x f(x) dx ∫ y f(y) dy
= E[X]E[Y]
where f(x) and f(y) are the marginal probability density functions of X and Y, respectively.
Therefore, we have shown that under these conditions, E[XY] = E[X]E[Y].
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any help would be appreciated.
Answer:
10.4
Step-by-step explanation:
cosine rule=\(a^{2}=b^{2} +c^{2} -2bc*cosa\)
\((2\sqrt{3}) ^{2}=(x+2)^{2} +x^{2} -2(x+2)x*cos60\\12=x^{2} +4x+4+x^{2} -2x^{2} -4x*\frac{1}{2}\\2x-8=0\\x=4\\Area=\frac{1}{2}absinc\\ = \frac{1}{2}*6*4*sin60\\\\ =6\sqrt{3}\\=10.4(3 sig.fig)\)
The value of x is:
120⁰
40⁰
50⁰
60⁰
Answer: 60
Step-by-step explanation:
Line=180 degrees
180-120=60
which statement would be true if you evaluate the expression (980+205)÷5
a. the solution is 5 times as small as 980-205
b. the solution is 5 times as small as 980+205
c. the solution is 5 times as large as 980+205
d. the solution is 5 times as large as 980-205
gasoline brand and weight are both quantitative variables. gasoline brand is a quantitative variable and weight is a categorical variable. gasoline brand and weight are both categorical variables. gasoline brand is a categorical variable and weight is a quantitative variable.
In "gas-mileage" experiment : (a) "gasoline-brand" is "categorical-variable" and weight is "quantitative-variable".
In this experiment, the brand of gasoline is a categorical variable because it represents different distinct categories or labels, namely Amoco, Marathon, and Speedway. Gasoline brands cannot be measured on a numerical scale, but rather they represent different brands.
The weight of the car is a quantitative variable because it can be measured on a numerical scale. The weight is given in pounds and represents a continuous range of values, such as 3,000, 3,500, or 4,000 pounds. It can be measured and compared using mathematical operations, such as addition or subtraction.
Therefore, the correct option is (a).
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The given question is incomplete, the complete question is
You are planning an experiment to determine the effect of the brand of gasoline and the weight of a car on gas mileage measured in miles per gallon. You will use a single test car, adding weights so that its total weight is 3,000, 3,500, or 4,000 pounds. The car will drive on a test track at each weight using each of Amoco, Marathon, and Speedway gasoline.
In the gas mileage experiment,
(a) gasoline brand is a categorical variable and weight is a quantitative variable.
(b) gasoline brand and weight are both categorical variables.
(c) gasoline brand and weight are both quantitative variables.
(d) gasoline brand is a quantitative variable and weight is a categorical variable.
A local frame shop charges $5 per foot for the wood to make a frame. You want to have an 8 inch by 10 inch picture frame. How much will it cost?
Answer:15$
Step-by-step explanation:
given a normally distributed variable of mean 24 and standard deviation 5, what is the distance between the 85th and the 95th percentile?
The distance between 85th and 95th percentile is 0.345.
What is a normal distribution?
It is also known as Gaussian distribution. . It shows the data near the more. This appears as bell curve in graphical form. It is a bell shaped frequency distribution curve of a continuous random variable.
A normally distributed random variable x with mean μ=24 and standard deviation=σ=5
X≈N(μ,σ²)
X≈N(24,25)
Let, 85th percentile=x₁ and 95th percentile=x₂
p(X ≤ x₁)=0.85 and p(X ≤ x₂)=0.95
p((X-μ/σ)≤ ((x₁-24)/5)=0.85 and p((X-μ/σ)≤ ((x₂-24)/5)=0.95
p(z≤ (x₁-24)/5)=0.85 and p(z≤ (x₂-24)/5)=0.95
\(\bar\)\(\bar{\phi}\)((x₁-24)/5)=0.85 and \(\bar\)\(\bar{\phi}\)((x₂-24)/5)=0.95
(x₁-24)/5)= \(\bar\)\(\bar{\phi}\)⁻¹(0.85) and (x₂-24)/5)= \(\bar\)\(\bar{\phi}\)⁻¹(0.95)
x₁=24+5×1.036 and x₂=24+5×1.645
x₁=29.18 and x₂=32.225
The distance between 85th and 95th percentile
Δx=|x₁-x₂|=|29.18-32.225|
Δx=0.345
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help please!!!!!!!!!!!!!!!!!!!!!!!!11111
Which pair or pairs of polygons are congruent?
A. 3 and 4
B. 1 and 3
C. 1, 3, and 4
D. 2, 3, and 4
E. 1, 2, 3, and 4
Answer:
b
Step-by-step explanation:
100 POINTS! Mr. Moore's physics class built different-shaped parachutes to see which shapes were more effective. The students tested the parachutes by dropping them from a height of 30 feet and timing the fall. They calculated the summary below:
Answer:
Im not really sure but i think is D
Step-by-step explanation:
Plz let me know if its wrong
i hope it helped <3
what is the slope of the line whose equation is -3x 8y = -10.
Given a line with the equation -3x+8y=-10, its slope can be calculated using the slope intercept form of the line that is 3/8.
What is slope?A line's steepness can be determined by looking at its slope. Slope is calculated mathematically as "rise over run" (change in y divided by change in x). A line's slope is how steeply it slopes from LEFT to RIGHT. The slope of a line is determined by dividing its rise, or vertical change, by its run, or horizontal change. No matter which two locations on the line you choose, the slope of a line is always constant (it never varies). The slope of a line in mathematics indicates how steep a line is. It is also referred to as the gradient. The "change in y" over the "change in x" of a line is referred to as the slope.
Here,
-3x+8y=-10
y=mx+c
where m=slope of line
8y=3x-10
y=3x/8-10/8
slope=3/8
The slope of given line whose equation is -3x+8y=-10 is 3/8 using slope intercept form of line.
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PLEASEEE HELP ME!!!!
Answer:
girl I have the same question
Help with these 10th grade geometry angle problems? I'm desperate and my teacher won't help me. Please also explain how you got your answer. Thank you.
Answer: 60
Step-by-step explanation:
See
m<COB and m<EOD are opposite anglesHence they are equal in measure.Hence
m<COB=60°
Find the dimensions of the following vector spaces.
(a) The vector space of all diagonal 3 x 3 matrices
(b) The vector space R 6
(c) The vector space of all upper triangular 2 x 2 matrices
(d) The vector space P₁[x] of polynomials with degree less than 4
7x5 (e) The vector space R7
(f) The vector space of 3 x 3 matrices with trace (
The dimensions of the vector spaces are:
(a) 3
(b) 6
(c) 1
(d) 4
(e) 7
(f) 2
To find the dimensions of the given vector spaces, we need to determine the number of linearly independent vectors that form a basis for each space.
(a) The vector space of all diagonal 3x3 matrices:
A diagonal matrix has non-zero entries only along the main diagonal, and the remaining entries are zero. In a 3x3 matrix, there are three positions on the main diagonal. Each of these positions can have a different non-zero entry, giving us three linearly independent vectors. Therefore, the dimension of this vector space is 3.
(b) The vector space R^6:
The vector space R^6 consists of all 6-dimensional real-valued vectors. Each vector in this space has six components. Therefore, the dimension of this vector space is 6.
(c) The vector space of all upper triangular 2x2 matrices:
An upper triangular matrix has zero entries below the main diagonal. In a 2x2 matrix, there is one position below the main diagonal. Therefore, there is only one linearly independent vector that can be formed. The dimension of this vector space is 1.
(d) The vector space P₁[x] of polynomials with degree less than 4:
The vector space P₁[x] consists of all polynomials with degrees less than 4. A polynomial of degree less than 4 can have coefficients for x^0, x^1, x^2, and x^3. Therefore, there are four linearly independent vectors. The dimension of this vector space is 4.
(e) The vector space R^7:
The vector space R^7 consists of all 7-dimensional real-valued vectors. Each vector in this space has seven components. Therefore, the dimension of this vector space is 7.
(f) The vector space of 3x3 matrices with trace 0:
The trace of a matrix is the sum of its diagonal elements. For a 3x3 matrix with trace 0, there is one constraint: the sum of the diagonal elements must be zero. We can choose two diagonal elements freely, but the third element is determined by the sum of the other two. Therefore, we have two degrees of freedom, and the dimension of this vector space is 2.
In summary, the dimensions of the vector spaces are:
(a) 3
(b) 6
(c) 1
(d) 4
(e) 7
(f) 2
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The dimensions of various vector spaces: 3 for diagonal 3x3 matrices, 6 for R6, 3 for upper triangular 2x2 matrices, 4 for polynomials with degree less than 4, 7 for R7, and 8 for 3x3 matrices with trace 0.
Explanation:(a) The vector space of all diagonal 3 x 3 matrices has a fixed dimension of 3, because every diagonal matrix has only 3 diagonal elements.
(b) The vector space R6 has a dimension of 6, because it consists of all 6-dimensional vectors.
(c) The vector space of all upper triangular 2 x 2 matrices has a dimension of 3, because there are 3 independent entries in the upper triangle.
(d) The vector space P₁[x] of polynomials with degree less than 4 has a dimension of 4, because it can be represented by the coefficients of a polynomial of degree 3.
(e) The vector space R7 has a dimension of 7, because it consists of all 7-dimensional vectors.
(f) The vector space of 3 x 3 matrices with trace 0 has a dimension of 8, because there are 8 independent entries in a 3 x 3 matrix with trace 0.
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please explain this in steps please friends
Answer:
See below
Step-by-step explanation:
The LHS and RHS are exactly the same, so the equality is true.
The associate property of addition says that
\(\boxed{a+(b+c)=(a+b)+c}\)
In order to make the addition of fractions, the denominators should be same. So we can write three fractions as one.
\(\dfrac{1}{2} +\left(\dfrac{2}{3}+\dfrac{3}{4} \right )\)
\(\dfrac{1}{2} +\dfrac{2}{3}+\dfrac{3}{4}\)
\(\dfrac{1\cdot 6 }{2\cdot 6} +\dfrac{2 \cdot 4}{3 \cdot 4}+\dfrac{3 \cdot 3 }{4 \cdot 3}\)
\(\dfrac{ 6 }{12} +\dfrac{8}{12}+\dfrac{9 }{12}\)
\(\dfrac{ 23 }{12}\)
Answer:
You gotta give me (us) more to work with homie.
Step-by-step explanation:
If I have more of a picture with it I could possibly help but all there is a barely readable and legible nonsense equation. Sorry :(
What is the slope of the line represented by the equation 2y = 5x + 4? A. 2. 5 B. 2 5 C. 2 D. 5
Answer:
A i think
Step-by-step explanation:
What is the integrated rate law for a 1st order reaction?
How do i solve this paper?
I feel like my answers are gone and i need help.
Answer:
you have it correct sir
Step-by-step explanation:
let e be an algebraic extension of a field f. if r is a ring and f ⊆ r ⊆ e show that r must be a field.
If e is an algebraic extension of a field f and r is a ring with \(f\subseteq r\subseteq e$,\) then r must be a field.
we have \(a^{-1} = -\frac{1}{c_0}(a^{n-1} + c_{n-1}a^{n-2} + \cdots + c_1)$,\) and all of the terms on the right-hand side of this equation belong to $r$.
Therefore, \($a^{-1}\in r$\), and we have shown that r is a field.
Since e is an algebraic extension of f, every element \($x\in e$\) satisfies some non-zero polynomial with coefficients in \($f$\), say \($f(x)=0$\) for some non-zero polynomial\($f(t) \in f[t]$.\)
Now, suppose \($r$\) is a subring of \($e$\) containing f.
To show that r is a field, it suffices to show that every non-zero element of r has a multiplicative inverse in r.
Let \($a\in r$\) be a non-zero element.
Since \($a\in e$\) , there exists a non-zero polynomial \($f(t)\in f[t]$\) such that \(f(a)=0$.\)
Let n be the degree of f(t), so that \(f(t) = t^n + c_{n-1}t^{n-1} + \cdots + c_1 t + c_0$ for some $c_i\in f$, $0\leq i\leq n-1$.\)
Then, we have \(a^{-1} = -\frac{1}{c_0}(a^{n-1} + c_{n-1}a^{n-2} + \cdots + c_1)$,\) and all of the terms on the right-hand side of this equation belong to r.
Therefore, \($a^{-1}\in r$\), and we have shown that r is a field.
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Serenity filled up her car with gas before embarking on a road trip across the country. Let � G represent the number of gallons of gas remaining in her gas tank after driving for � t hours. A graph of � G is shown below. Write an equation for � G then state the � y-intercept of the graph and determine its interpretation in the context of the problem.
The equation is: G = -⁵/₄t + 15
The slope of the function represents that ⁵/₄ gallons of gas is consumed to drive the car for one hour.
How to find the linear equation of the graph?The formula for the equation of a line in slope intercept form is:
y = mx + c
where:
m is slope
c is y-intercept
From the graph, we see that:
y-intercept = 15 gallons
Now, the slope is gotten from the formula:
Slope = (y₂ - y₁)/(x₂ - x₁)
Slope = (10 - 5)/(4 - 8)
Slope = -⁵/₄
Thus, equation is:
G = -⁵/₄t + 15
The slope of the function represents that ⁵/₄ gallons of gas is consumed to drive the car for one hour.
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for a standard normal distribution, find: p(-1.62 < z < 2.01)
The probability of the interval -1.62 < z < 2.01 in a standard normal distribution is approximately 0.9262 or 92.62%.
In a standard normal distribution, the mean is 0 and the standard deviation is 1. The z-score represents the number of standard deviations a data point is from the mean. To find the probability of a specific interval, we calculate the area under the curve between the corresponding z-values.
Given the interval -1.62 < z < 2.01, we need to find the area under the standard normal curve between these two z-values. This can be done using a standard normal distribution table or by using a statistical software or calculator.
By looking up the z-values in the table or using software, we find the corresponding probabilities: P(z < -1.62) = 0.0526 and P(z < 2.01) = 0.9788.
To find the probability of the interval -1.62 < z < 2.01, we subtract the probability of the lower bound from the probability of the upper bound: P(-1.62 < z < 2.01) = P(z < 2.01) - P(z < -1.62 = 0.9788 - 0.0526 = 0.9262.
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How to factor x^2-2x
Answer:
x(x-2)
Step-by-step explanation:
An expression is shown.
2 3/4 x 2/3
What is the value of the expression?
Answer:
The answer is 1 5/6
Step-by-step explanation:
Watch help video
The dot plot below represents the number of goals scored by the girls' soccer team in
every game so far this season.
GOALS SCORED
times
2
Goals
How many times did the team score 1 goal? I dont like this app
the girl will be scoring a total of 30 goals.
What is number line?
A number line is an image of numbers plotted on a straight line, either horizontally or vertically. We can compare numbers and execute simple arithmetic operations on them easily by writing the numbers down on a number line. The starting point of a number line is often regarded as zero (0). These numbers to the left of zero are all negative while the numbers just on right of zero are all positive. As a result, we can argue that on a number line, the value of numbers grows as we approach the right. The numbers on the right are therefore larger than the ones on the left, according to this statement.
Given, the goal scored
3 times 2
4 times 1
and 5 times 4.
So the total goal scored will be 3*2=6
4*1=4
and 5*4=20
Score = 6+4+20=30
Hence the girl will be scoring a total of 30 goals.
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does anybody knows this if u do please tell me the 3 facts this is due tomorrow!!:[
Thom's restaurant bill is $45 and he leaves a 20 percent tip. What is the total cost for Thom's meal? O $20 $54 O $65 0 $90
Answer:
$54
Step-by-step explanation:
Answer:
B.)$54
Step-by-step explanation:
20%->0.20
45(0.20)=9
45+9=54
The function f(x)=x2−1x+2 is an example of a rational function (the fraction of two polynomials). For what values of x is f(x) continuous Explain.
Continuous on. f(x)=x21x+2 is an illustration of a rational function (the fraction of two polynomials).
A rational function is any function that can be formally stated as an algebraic fraction in which both the numerator and the denominator are polynomials. The coefficients of the polynomials may appear in any field K and need not be rational values. A function that measures two polynomials in comparison. As a ratio, it is "rational" because one is divided by the other. Write the number in decimal form before determining whether it is rational or irrational if you are required to do so. The number is rational if it comes to an end. You should search for a recurring pattern of digits if it goes on forever. The number is irrational if there is no pattern that repeats itself.
Determine the continuous of the function.
Continuous on.
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The function f(x) = (x^2 - 1)/(x + 2) is a rational function that is continuous for all values of x except x = -2. This is because division by zero is undefined, and the denominator of the function becomes zero at x = -2.
The given function f(x) = (x^2 - 1)/(x + 2) is a rational function, which is a fraction of two polynomials. To check the continuity of the function, we need to find any values of x that make the denominator equal to zero since division by zero is undefined. In this case, the denominator becomes zero at x = -2, so the function is discontinuous at x = -2. Therefore, f(x) is continuous for all values of x except x = -2. This means that the function is defined and has a well-defined output value for every input value, except when x is equal to -2.
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Please help I need this done asap 10th grade highschool math
Answer:
9.63
Step-by-step explanation:
Since the ratio of the length of the horizontal leg to the length of the vertical length is 12:1, then the horizontal leg must be 12 × 0.8 m = 9.6 m.
We have a right triangle with legs of lengths 0.8 m and 9.6 m.
We can find the length of the hypotenuse by using the Pythagoras theorem.
a² + b² = c²
(0.8 m)² + (9.6 m)² = c²
c² = 92.8 m²
c = 9.63 m
Answer: 9.63
I set z=t=0(x,y,z,t)
and I got a partial solution (0,1,0,0).
I solved two homogeneous matrices once for z=1
and t=0
, then for z=0
and t=1
and I got two solutions (1,1,1,0)
and (1,1,0,1).
Then, I got (0,1,0,0)+a∗(1,1,1,0)+b∗(1,1,0,1
)
Therefore, all possible results are (0,1,0,0),(1,0,1,0),(1,0,0,1),(0,1,1,1)
Would this be correct?
The correct set of possible results would be (0, 1, 0, 0), (1, 2, 1, 0) and (1, 2, 0, 1).
Your approach seems to be correct, but there seems to be a minor mistake in your final list of possible solutions. Let's go through the steps to clarify.
Given the initial conditions z=t=0, you obtained a partial solution (0,1,0,0).
Next, you solved the homogeneous equations for z=1 and t=0, which resulted in a solution (1,1,1,0).
Similarly, solving the homogeneous equations for z=0 and t=1 gives another solution (1,1,0,1).
To find the general solution, you combine the partial solution with the solutions obtained in the previous step, using parameters a and b.
(0,1,0,0) + a(1,1,1,0) + b(1,1,0,1)
Expanding this expression, you get:
(0+a+b, 1+a+b, 0+a, 0+b)
Simplifying, you obtain the following set of solutions:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Therefore, the correct set of possible results would be:
(0, 1, 0, 0)
(1, 2, 1, 0)
(1, 2, 0, 1)
Note that (0, 1, 1, 1) is not a valid solution in this case, as it does not satisfy the initial condition z = 0.
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Find the factors of 4x2-16x-9.
Answer:
Step-by-step explanation:
\(4x^2-16x-9.\\Writ -16x - as -a -difference\\ 4x^2 +2x-18x -9 \\Factor -out- common- terms\\2x(2x+1)-9(2x+1)\\ Factor -out (2x+1)\\(2x+1)(2x-9)\)
I Hope It Helps :)
Answer:
\( \boxed{\sf (2x - 9)(2x + 1)} \)
Step-by-step explanation:
\( \sf Factor \: the \: following: \\ \sf \implies 4 {x}^{2} - 16x - 9 \\ \\ \sf Factor \: the \: quadratic \: 4 {x}^{2} - 16 x - 9. \\ \sf The \: coefficient \: of \: {x}^{2} \: is \: 4 \: and \: the \: constant \\ \sf term \: is \: - 9. \: The \: product \: of \: 4 \: and \: - 9 \: is \\ \sf - 36. \: The \: factors \: of \: - 36 \: which \: sum \: to \\ \sf - 16 \: are \: 2 \: and \: - 18. \\ \sf So, \\ \sf \implies 4 {x}^{2} - (18 - 2)x - 9 \\ \\ \sf \implies 4 {x}^{2} - 18x + 2x - 9 \\ \\ \sf \implies 2x(2x - 9) + 1(2x - 9) \\ \\ \sf Factor \: 2x - 9 \: from \: 2x(2x - 9) + 1(2x - 9) : \\ \sf \implies (2x - 9)(2x + 1)\)