Name four planets which never get above freezing at the equators

The angle of the seal's path below the horizontal at 22.6 degree, cover 991 m distance at the speed 17.53 m/s.

A. We can use the tangent function to find the angle of the seal's path below the horizontal:

tan(angle) = opposite side / adjacent side = 360 m / 920 m = 0.3913

angle = tan^-1(0.3913) = 22.6 degrees below the horizontal

B. To find the total distance covered by the seal, we can use the Pythagorean theorem:

distance = sqrt(360^2 + 920^2) = sqrt(130320 + 846400) = sqrt(976620) = 991 m

C. To find the seal's speed, we divide the total distance covered by the time taken:

speed = distance / time = 991 m / 4.0 min * (1 min / 60 s) = 17.53 m/s.

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Answer:

Jumping battle slams - just move the rope up and down

Alternating jump wave - jump and move the rope side to side

Alternating wide circles - move the rope in a circle position

Jumping jacks

Squat to sholder

Explanation:

The guy above me is correct give him Brainliest

Answer:

c = 3.00E8 m/s      speed of light

c = f * λ        frequency ^ wavelength

f = c / λ  = 3.00E8 m/s / .01 m = 3.00E10 / sec

f = 30,000,000,000 /sec

Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.

To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,

mgh = (1/2)mv², plugging in the values given in the problem, we get,

m(9.81 m/s²)(3.5 m) = (1/2)mv²

Simplifying and solving for v, we get,

v = √(2gh)

v = √(2(9.81 m/s²)(3.5 m))

v = 8.29 m/s

Now we can use the kinematic equation,

d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),

0 = 8.29 m/s - μg*t

t = 8.29 m/s / μg

Substituting this value of t back into the kinematic equation, we get,

d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²

d = 6.97 m

Therefore, Josh's sled ends up 6.97 meters from the base of the hill.

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Answer:

200 kilocalories

Explanation:

Answer:

A

Explanation:

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

0.175 second

Explanation:

i hope it helps

The torque applied on the rotating rod is 30 N-m.

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction.

Applied force = 60 N

distance = 1.0 m

the force on the lever is exerted at an angle of 30°

sin 30° = 0.5

Hence, the torque applied on the rod = force × distance × sin30°

= 60 N × 1.0 m × 0.50

= 30 N-m.

Hence,  the torque applied on the rotating rod is 30 N-m.

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Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.

Using the equation, we can solve for the acceleration:

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s

Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.

(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.

(c) To find the initial velocity of the ball, we can use the equation:

v = u + at

At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s upward

Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.

(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:

s = ut + (1/2)at^2

At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.

0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2

0 = 47.864 + (-5.5294)

5.5294 = 47.864

Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.

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The projectile left the ground at an angle of 67.4 degrees above the horizontal, if there was no air resistance.

First, let's find the time of flight. We can use the kinematic equation:

y = yo + voy*t + 0.5*a*t^2

where y is the maximum height (0.57 km), yo is the initial height (0 m), voy is the initial vertical velocity (unknown), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time to reach the maximum height (unknown).

Plugging in the values and solving for t, we get:

0.57 km = 0 + voy*t + 0.5*(-9.81 m/s^2)*t^2

t = 12.19 seconds

Since the total time of flight is twice the time to reach the maximum height, we have:

total time of flight = 2*t = 24.38 seconds

Now we can use the range equation to find the initial velocity vector of the projectile:

x = vox*t

1500 m = vox*24.38 seconds

vox = 61.51 m/s

where x is the range and vox is the initial horizontal velocity.

Finally, we can use trigonometry to find the initial angle of projection, theta:

voy/vox = tan(theta)

voy = vox*tan(theta)

61.51 m/s*tan(theta) = (150 m/s)

theta = 67.4 degrees

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Option E, which states that stars emit light in all directions, Identify the differences between planets and stars.

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Answer: Carbon is the chemical backbone of life on Earth. Carbon compounds regulate the Earth’s temperature, make up the food that sustains us, and provide energy that fuels our global economy.

A diagram of the carbon cycle with arrows showing the movement of carbon through a landscape with plants and animals, mountains and a volcano, a river leading to the ocean, and an industrial area. Carbon moves in and out of our atmosphere, ocean, waterways, and soil through burning fossil fuels, precipitation, fires, vegetation, volcanoes, and organic processes.

The carbon cycle. (Image credit: NOAA)

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Most of Earth’s carbon is stored in rocks and sediments. The rest is located in the ocean, atmosphere, and in living organisms. These are the reservoirs through which carbon cycles.

This graph shows the monthly mean carbon dioxide measured at Mauna Loa Observatory, Hawaii, the longest record of direct measurements of CO2 in the atmosphere.

Climate change: Atmospheric carbon dioxide

Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.

Carbon storage and exchange

Carbon moves from one storage reservoir to another through a variety of mechanisms. For example, in the food chain, plants move carbon from the atmosphere into the biosphere through photosynthesis. They use energy from the sun to chemically combine carbon dioxide with hydrogen and oxygen from water to create sugar molecules. Animals that eat plants digest the sugar molecules to get energy for their bodies. Respiration, excretion, and decomposition release the carbon back into the atmosphere or soil, continuing the cycle.

The ocean plays a critical role in carbon storage, as it holds about 50 times more carbon than the atmosphere. Two-way carbon exchange can occur quickly between the ocean’s surface waters and the atmosphere, but carbon may be stored for centuries at the deepest ocean depths.

Rocks like limestone and fossil fuels like coal and oil are storage reservoirs that contain carbon from plants and animals that lived millions of years ago. When these organisms died, slow geologic processes trapped their carbon and transformed it into these natural resources. Processes such as erosion release this carbon back into the atmosphere very slowly, while volcanic activity can release it very quickly. Burning fossil fuels in cars or power plants is another way this carbon can be released into the atmospheric reservoir quickly.

A research vessel ploughs through the waves, braving the strong westerly winds of the Roaring Forties in the Southern Ocean, in order to measure levels of dissolved carbon dioxide in the surface of the ocean.

Southern Ocean confirmed as strong carbon dioxide sink

New research utilizes airborne measurements of carbon dioxide to estimate ocean uptake.

Changes to the carbon cycle

Human activities have a tremendous impact on the carbon cycle. Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere. As a result, the amount of carbon dioxide in the atmosphere is rapidly rising; it is already greater than at any time in the last 3.6 million years. The ocean absorbs much of the carbon dioxide that is released from burning fossil fuels. This extra carbon dioxide is lowering the ocean’s pH, through a process called ocean acidification. Ocean acidification interferes with the ability of marine organisms (including corals, Dungeness crabs, and snails) to build their shells and skeletons.

An aerial view of Century City section of Los Angeles, California.

Atmospheric carbon dioxide rebounds as global pollution rates approach pre-Covid levels

Global carbon emissions are projected to bounce back to after an unprecedented drop caused by the response to the coronavirus pandemic, according to an annual report by the Global Carbon Project.

EDUCATION CONNECTION

Take a bite of dinner, breathe in air, or a drive in a car — you are part of the carbon cycle. The resources in this collection provide real world examples of the changes occurring in the cycle. There is much to learn about this essential topic, and some of the resources highlight exciting career opportunities in this field of study.

Explanation: learn from a middle schooler like me smart

Carbon was formed in stars through nuclear fusion and scattered into space when the star died. Carbon was incorporated into organic molecules through photosynthesis and eventually became part of animals' bodies. The carbon cycle involves the uptake of carbon dioxide by plants, transfer to animals, and release back into the atmosphere through respiration and decomposition, and human activities have disrupted this cycle.

Carbon was formed in the universe through nuclear fusion reactions that took place in the cores of stars. These reactions fused lighter elements into heavier ones, including carbon. When the star eventually died in a supernova explosion, the carbon and other elements were scattered into space.

The carbon, along with other elements, eventually formed clouds of gas and dust that coalesced to form new stars and planets. On our planet, carbon was incorporated into organic molecules through photosynthesis by plants and other photosynthetic organisms. These organic molecules were then consumed by animals, which allowed the carbon to become part of their bodies.

The carbon cycle is the process by which carbon moves through the Earth's atmosphere, oceans, and biosphere. This cycle involves the uptake of carbon dioxide by plants through photosynthesis, the transfer of carbon from plants to animals through the food chain, and the release of carbon back into the atmosphere through respiration and decomposition. Human activities, such as the burning of fossil fuels, have disrupted this cycle, leading to increased levels of carbon dioxide in the atmosphere and contributing to climate change.

Therefore, Nuclear fusion in stars produces carbon, which is then released into space when the star dies. By photosynthesis, carbon was added to organic molecules, eventually becoming a component of animal bodies. Human activities have interrupted the carbon cycle, which involves the intake of carbon dioxide by plants, its transport to animals, and its release back into the atmosphere through respiration and decomposition.

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Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

The amount indicated by is not fixed and changes over time. In situations where the linear acceleration is not zero, the velocity is always changing.

The first case is true

Since it depends on time, is not constant?

The amount indicated by is not fixed and changes over time. In situations where the linear acceleration is not zero, the velocity is always changing.

The dimension of the quantity albo will be ufa au av u t when calculating a particle's velocity as a function of time t using the formula v = a(1 - eb), where a and b are constants. (1 - e-b) Greutate, urb'a 221 Aich, a zat a2b3c faut Eleft.

The amount indicated by is not fixed and changes over time. When linear acceleration is absent  .

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The quantity represented by v is a function of time (i.e., is not constant).

True or false

A  particle moves with constant acceleration a. The expression VI +80 represents the particles velocity at what instant in time.

A. At a time T=zero

B. At the initial time

A particle starts from the origin at time t = 0 and moves along the positive x - axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s?

Note: The values given in the answer are rounded off to the nearest hundredth.

Answer:

e

Explanation:

From the given information:

Suppose Q = total charge of the sphere.

here, the electric field outside the sphere at distance R/2 can be expressed as:

\(E_1 = \dfrac{1}{4 \pi \varepsilon _o}* \dfrac{Q}{(R + \dfrac{R}{2})^2}\)

where:

\(k = \dfrac{1}{4 \pi \varepsilon _o}\)

\(E_1 = \dfrac{kQ}{(\dfrac{3R}{2})^2}\)

\(E_1 = \dfrac{4kQ}{9R^2}\)

For the electric field inside the sphere, we have:

\(E_2 = \dfrac{kQr}{R^3}\)

here:

r = distance of the point from the center = R/2

R = radius of the sphere

∴

\(E_2 = \dfrac{kQ * \dfrac{R}{2}}{R^3}\)

\(E_2 = \dfrac{kQ }{2R^2}\)

As such, the ratio of the electric field outside the sphere to the one inside is:

\(\dfrac{E_1}{E_2} = \dfrac{ \dfrac{4kQ}{9R^2}}{ \dfrac{kQ }{2R^2}}\)

\(\dfrac{E_1}{E_2} = \dfrac{4kQ}{9R^2} \times \dfrac{ 2R^2 }{kQ}\)

\(\mathbf{\dfrac{E_1}{E_2} = \dfrac{8}{9}}\)

For a solid uniformly charged sphere of radius R, the electric field at a distance R/2 outside the sphere, divided by the electric field at a distance R/2 inside the sphere is -  e) 8/9

field  \(E2= \frac{k(Q)}{(3R/2)^2}\)

=  \(\frac{4}{9} \frac{k(Q)}{R^2}\)

=

Thus, E2/E1

= (4/9)/(1/2)

= 8/9

Thus, the electric field at a distance R/2 outside the sphere, divided by the electric field at a distance R/2 inside the sphere is -  8/9

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Answer:9.6m

Explanation:

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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Answer:

    vₐ = v_c  \(( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )\)

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

          Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

         Em_f = U = - G Mm / R₂

energy is conserved

           Em₀ = Em_f

           ½ m v_c² - G Mm / R = - G Mm / R₂

           v_c² = 2 G M (1 /R -  1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

           v_c = \(\sqrt{\frac{2GM}{R} }\)

now indicates that the mass and radius of the planet changes slightly

            M ’= M + ΔM = M ( \(1+ \frac{\Delta M}{M}\) )

            R ’= R + ΔR = R ( \(1 + \frac{\Delta R}{R}\) )

we substitute

           vₐ = \(\sqrt{\frac{2GM}{R} } \ \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }\)

let's use a serial expansion

           √(1 ±x) = 1 ± ½ x +…

we substitute

         vₐ = v_ c ( \((1 + \frac{1}{2} \frac{\Delta M}{M} ) \ ( 1 - \frac{1}{2} \frac{\Delta R}{R} )\))

we make the product and keep the terms linear

        vₐ = v_c  \(( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )\)

The minimum escape speed, vc , for an object launched from the surface of the planet will be    \(v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})\)

The escape velocity is defined as the velocity required to send the object out of the gravitational influence of the earth.

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

    \(E_{mo} = K + U = \dfrac{1}{2} m v_c^2 - \dfrac{G Mm} { R}\)

final point. At a very distant point

      \(E_{mf} = U = \dfrac{- G Mm }{ R_2}\)

energy is conserved

         \(E{mo} = E{mf}\)

          \(\dfrac{1}{2}m v_c^2 - \dfrac{G Mm} {R} = \dfrac{- G Mm }{ R_2}\)

\(v_c^2 = 2 G M (\dfrac{1} {R} - \dfrac{ 1 }{R_2})\)

if we consider the speed so that it reaches an infinite position R₂ = ∞

\(v_c = \sqrt{\dfrac{2GM}{R}\)

now indicates that the mass and radius of the planet changes slightly

\(M ’= M + \Delta M = M(1+\dfrac{\Delta M}{M})\)  

\(R ’= R + \Delta R = R (1+\dfrac{\Delta R}{R} )\)

we substitute

   \(vₐ = \sqrt{\dfrac{2GM}{R} }\dfrac{\sqrt{1+\dfrac{\Delta M}{M}}} {\sqrt{1+\dfrac{\Delta R}{R}}}\)

let's use a serial expansion

√(1 ±x) = 1 ± ½ x +…

we substitute

      \(v_a=v_c(1+\dfrac{1}{2}\dfrac{\Delta M}{M})(1-\dfrac{1}{2}\dfrac\Delta R}{R})\)

Hence the minimum escape speed, vc , for an object launched from the surface of the planet will be    \(v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})\)

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Answer:

0.56 km/s

Explanation:

We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.

\(560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s]\)

Therefore the speed of 0.56 [km/s] is the greatest of all

Answer:

There no image

Explanation:

In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.

A procedure the students could use to determine the charge-to-mass ratio of the particles includes the following steps:

1.Obtain a sample of the particles of interest.

2.Set up a parallel plate electrostatic apparatus with a known voltage difference across the plates.

3.Measure the distance between the plates and the electric field strength between the plates.

4.Introduce the sample of particles between the plates, and use a detector to measure the current that flows between the plates.

5.Vary the voltage difference across the plates and record the corresponding current for each voltage.

6.Plot a graph of current versus voltage. The slope of this graph represents the charge-to-mass ratio of the particles.

7.To reduce experimental uncertainty, the students should use a high-precision voltmeter to measure the voltage and a high-precision ammeter to measure the current. They should also take multiple measurements at each voltage and take the average. They should also use a large number of particles to get a more accurate result.

8.Also, the students should ensure that the electrodes are clean, and the electric field is uniform across the gap, as any non-uniformity would affect the results.

9.They should also try to minimize the environmental effects such as temperature and humidity, which could affect the results.

10.Finally, repeat the experiment multiple times and take the average of the results to get the most accurate value of charge-to-mass ratio of the particles.

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Answer:

0.09kg of air

Explanation:

The dimensions of the room are given

change the height to meters by dividing it by thousand.

For the volume multiplying the length,width and height (all should be in the same unit most suitable being meters).

Volume refers to the amount of space inside a box or a object.

The amount of air is equal to the volume.

Answer:

90 m^3

Explanation:

Volume of the room:

    6 m * 5 m * 3 m         =  90 m^3   <=====( I changed 3mm to 3 m)

if  3mm is not a typo mistake

 volume becomes     ( 3 mm = .003 m)

      6 m * 5 m * .003 m   = .09 m^3   ( though unlikely )

The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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