Name the following compounds: a. ClF3 b. As2O5 c. B4H10

Answer:

anion

Explanation:

anion undergoes reduction.

cation undergoes oxidation.

The ions are categorized according to the process of oxidation and reduction. The ion usually undergoes reduction is an anion.

A process involving the partial or complete gain of electrons and loss of oxygen. The ions acquire a net negative charge on them.

Thus, anions usually undergo a reduction.

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Answer:

The valency of an element refers to the number of electrons an atom can gain, lose or share to attain a stable configuration.

Aluminum (Al) is a metal with an atomic number of 13, which means it has 13 electrons in its neutral state. In its outermost shell, aluminum has three valence electrons.

To attain a stable electronic configuration, aluminum can lose these three valence electrons to become a cation with a 3+ charge (Al3+). By losing these electrons, the outermost shell of the aluminum atom becomes completely filled with eight electrons, which is a stable configuration.

Therefore, the valency of aluminum is 3 because it can lose three electrons to form a stable cation with a 3+ charge.

Explanation:

Answer:

The valency of an element refers to the number of electrons an atom can gain, lose or share to attain a stable configuration.

Aluminum (Al) is a metal with an atomic number of 13, which means it has 13 electrons in its neutral state. In its outermost shell, aluminum has three valence electrons.

To attain a stable electronic configuration, aluminum can lose these three valence electrons to become a cation with a 3+ charge (Al3+). By losing these electrons, the outermost shell of the aluminum atom becomes completely filled with eight electrons, which is a stable configuration.

Therefore, the valency of aluminum is 3 because it can lose three electrons to form a stable cation with a 3+ charge.

Explanation:

Answer:

your awnser is Atomic mass

Explanation:

you are welcome

Saturn does not have a true surface and lacks features like volcanoes, extreme temperature and pressure, and craters.

Saturn is a gas giant and does not possess a solid surface like terrestrial planets such as Earth or Mars. Instead, it is composed mostly of hydrogen and helium gases. Due to its gaseous nature, Saturn does not have volcanoes or craters typically found on rocky bodies.

Additionally, extreme temperature and pressure are present in the planet's deep interior, but they are not considered surface features.

Instead, Saturn's atmosphere exhibits fascinating phenomena such as its iconic ring system, storms, and swirling cloud patterns. These distinct characteristics make Saturn a unique and mesmerizing planet in our solar system.

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Answer:

Explanation:

We know that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.

So, hydrogen is the limiting reactant, and if 10 moles of hydrogen are used, then the reaction will occur 3.33 times.

Hence, this means there is enough nitrogen left for the reaction to occur another 0.67 times, and hence 0.67 moles of nitrogen will be left over.

Answer:

8-)

Explanation:

Baking powder is a dry chemical leavening agent, a mixture of a carbonate or bicarbonate and a weak acid. The base and acid are prevented from reacting prematurely by the inclusion of a buffer such as cornstarch. Baking powder is used to increase the volume and lighten the texture of baked goods

The number and intensity of CO stretching modes in the IR spectra can be used to distinguish between cis-M(CO)2X2 and trans-M(CO)2X2.

The IR spectra of molecules can offer precious records about their systems. Especially, the CO stretching location of the IR spectra is informative for distinguishing between cis-M(CO)2X2 and trans-M(CO)2X2.

Every CO ligand inside the molecule contributes one stretching mode to the IR spectrum. For cis-M(CO)2X2, there are two feasible preparations of the CO ligands: cis-association, where the CO ligands are on the equal aspect of the molecule, and trans-arrangement, where the CO ligands are on opposite sides of the molecule.

The cis-arrangement will result in a symmetric CO stretching mode and an uneven CO stretching mode. Then again, the trans-arrangement will result in degenerate symmetric CO stretching modes and degenerate uneven CO stretching modes.

Therefore, with the aid of reading the wide variety and intensity of the CO stretching modes inside the IR spectra, one could distinguish between cis-M(CO)2X2 and trans-M(CO)2X2.

Particularly, cis-M(CO)2X2 will show off  CO stretching modes with exclusive frequencies and intensities, at the same time as trans-M(CO)2X2 will show 4 CO stretching modes with the same frequency and intensity.

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(a) Predict the product and provide a step-by-step mechanism for the following reaction. Show complete arrow pushing to indicate electron flow in each of these steps and specify what intermediates and products clearly.

The given reaction is shown below:

Step 1: The benzene ring is an electron-rich molecule and it acts as a nucleophile to attack the carbonyl carbon.

Step 2: The lone pair of electrons on the oxygen atom of water is used to attack the protonated carbonyl carbon.

Step 3: The lone pair of electrons on the oxygen atom is used to attack the protonated carbonyl carbon.

Step 4: The lone pair of electrons on the oxygen atom of water is used to attack the protonated carbonyl carbon.

Step 5: The lone pair of electrons on the oxygen atom of water is used to attack the protonated carbonyl carbon. The final product is 2,4-pentane dione.

(b) Predict the product and provide a step-by-step mechanism for the following reaction. Show complete arrow pushing to indicate electron flow in each of these steps and specify what intermediates and products clearly. The given reaction is shown below:

Step 1: The nitrogen atom of hydrazine acts as a nucleophile and attacks the carbonyl carbon.

Step 2: The lone pair of electrons on the oxygen atom of acetic acid is used to attack the nitrogen atom of hydrazine.

Step 3: The nitrogen atom of hydrazine is again used as a nucleophile to attack the carbonyl carbon. The final product is N-acetyl hydrazine.

(c) Predict the product and provide a step-by-step mechanism for the following reaction. Show complete arrow pushing to indicate electron flow in each of these steps and specify what intermediates and products clearly. The given reaction is shown below:

Step 1: The lone pair of electrons on the nitrogen atom of amide is used to attack the carbonyl carbon of acetic anhydride.

Step 2: The oxygen atom of the second molecule of acetic anhydride is used to attack the nitrogen atom of the amide. The final product is N, N-dimethylacetamide.

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Answer:

it does not matter

Explanation:

g

Answer:

It doesn't matter

Explanation:

In almost all cases, chemical bonds are formed by interactions of valence electrons in atoms. To facilitate our understanding of how valence electrons interact, a simple way of representing those valence electrons would be useful. Again, it does not matter on which sides of the symbol the electron dots are positioned.

Answer:

10250.8

Explanation:

Formula

multiply the energy value by 4184

Glycogen synthase forms an B)α-1,4-glycosidic bond upon release of UDP.

Glycogen synthase is an enzyme that catalyzes the formation of glycogen, a branched polysaccharide that serves as a storage form of glucose in animals. The enzyme adds glucose residues to the growing glycogen chain by forming α-1,4-glycosidic bonds between adjacent glucose molecules.

When the chain reaches a certain length, branching occurs through the formation of α-1,6-glycosidic bonds, catalyzed by the enzyme branching enzyme.

The release of UDP from glycogen synthase occurs after the addition of each glucose residue, and it is required for the enzyme to continue adding glucose residues to the growing glycogen chain. Therefore, glycogen synthase forms B) α-1,4-glycosidic bonds upon release of UDP.

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Answer:

Rainfall can affect influent flow rate and compositions of wastewater, and thus further affect wastewater treatment performance and the effluent quality.

Explanation:

Answer:

is pleiotropic an answer if it is that is the answer.

explanation: pleiotropic, where one gene is responsible for multiple traits

Answer:

alll I really know is that it includes smaller pools of water

Answer:

Option D. 4

Explanation:

Ag(s) + NO3–(aq) + H+(aq) → Ag+(aq) + NO(g) + H2O(l)

To know the coefficient of H+, let us balance the equation. This is can be done as shown below:

Ag(s) + NO3–(aq) + 2H+(aq) → Ag+(aq) + NO(g) + H2O(l)

There are 3 atoms of O on the left side and a total of 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

Ag(s) + NO3–(aq) + H+(aq) → Ag+(aq) + NO(g) + 2H2O(l)

There are 4 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 4 in front of H+ as shown below:

Ag(s) + NO3–(aq) + 4H+(aq) → Ag+(aq) + NO(g) + 2H2O(l)

Total charge on the left side:

– 1 + 4 = +3

Total charge on the right side:

+1

To balance the charge, we simply put 3 in front of Ag and Ag+ as shown below:

3Ag(s) + NO3–(aq) + 4H+(aq) → 3Ag+(aq) + NO(g) + 2H2O(l)

Now the equation is balanced.

The coefficient of H+ is 4.

Answer:

1. Amine.

2. Alcohol.

3. Carboxylic Acid.

4. Halocarbon.

Explanation:

The correct answer according to the tile are Amine, Alcohol, Carboxylic acid, Halocarbon.

How can hydrocarbons be classified based on their structure?

Hydrocarbons can be classified as either aromatic or aliphatic compounds, depending on the presence of a benzene ring.

What is the most common classification of hydrocarbons?

Alkanes are hydrocarbons in which all of the bonds are single bonds. Alkenes are hydrocarbons that contain a carbon-carbon double bond.

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The pair of elements that are nonmetals and gases at room temperature and normal atmospheric pressure are:

Oxygen (O₂) - Oxygen is a nonmetal that exists as a diatomic gas at room temperature and normal atmospheric pressure. It is colorless, odorless, and tasteless.

Nitrogen (N₂) - Nitrogen is another nonmetal that exists as a diatomic gas at room temperature and normal atmospheric pressure. It is also colorless, odorless, and tasteless.

Both oxygen and nitrogen are essential components of the Earth's atmosphere, with nitrogen making up about 78% of the air we breathe and oxygen making up about 21%.

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Answer:

The gasoline undergoes a change as it burns.

Explanation:

Just took the Unit Test review ((:

Answer:

b

Explanation:

because i said so brudda

After a while at room temperature, a piece of dry ice, or solid CO2, vanishes without leaving a puddle of liquid behind.

Dry ice, which is a solid form of carbon dioxide, is available. When used for short-term refrigeration, CO2 is usually used because it frequently sublimates from the solid form to the gas state due to the fact that it does not have a liquid state at normal atmospheric pressure. Carbon dioxide that is solid is known as "dry ice." Due to its ice-like appearance and the fact that it truly sublimes rather than melting, dry ice appears to be made of ice. Because the solid does not first become a liquid when heated, it is known as dry ice.

Dry ice, also known as solid carbon dioxide, is very cold (109 °F / 78 °C), and it is frequently used to cool vaccines, chill and freeze food, preserve blood and tissue samples, heat-treat metals, and even produce special effects like fog for events or stage plays. Because solid CO2 does not melt into a liquid when heated but instead transforms instantly into gas, it is referred to as dry ice. Sublimation is the name of this procedure.

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Answer:

He was having a tough time as his mother abandoned him at the age of three or we can say his mother passed which led to his insecurity.

(a). The rate law for the reaction between NO (g) + NO₂ (g) + O₂ (g) → N₂O₅ (g) from the given experimental data is Rate = k [NO]²[NO₂]

(b). 1. The rate constant for the reaction 0.10 M 0.10 M 0.10 M 2.1 x 10⁻² Ms⁻¹ is 2.1 x 10² L/mol.s.

2. The rate constant for the reaction 0.20 M 0.10 M 0.10 M 4.2 x 10⁻² Ms⁻¹ is 1.05 x 10² L/mol.s.

3. The rate constant for the reaction 0.20 M 0.30 M 0.20 M 1.26 x 10⁻¹ Ms⁻¹ is 1.4 x 10² L/mol.s.

4. The rate constant for the reaction 0.10 M 0.10 M 0.20 M 2.1 x 10⁻² Ms⁻¹ is 2.1 x 10² L/mol.s.

We can now substitute these values into the rate law equation and solve for the rate constant k:

For the first experiment:

Rate = k [NO]²[NO₂]

⇒ k = Rate / [NO]²[NO₂] = 2.1 x 10⁻² Ms⁻¹ / (0.10 M)²(0.10 M) = 2.1 x 10² L/mol.s

Thus, the rate constant for the initial rate reaction 2.1 x 10⁻² Ms⁻¹ is 2.1 x 10² L/mol.s

For the second experiment:

Rate = k [NO]²[NO₂] 

⇒ k = Rate / [NO]²[NO₂] = 4.2 x 10⁻² Ms⁻¹ / (0.20 M)²(0.10 M) = 1.05 x 10² L/mol.s

Thus, the rate constant for the initial rate reaction 4.2 x 10⁻² Ms⁻¹ is 1.05 x 10² L/mol.s.

For the third experiment:

Rate = k [NO]²[NO₂] 

⇒ k = Rate / [NO]²[NO₂] = 1.26 x 10⁻¹ Ms⁻¹ / (0.20 M)²(0.30 M) = 1.4 x 10² L/mol.s

Thus, the rate constant for the initial rate reaction 1.26 x 10⁻¹ Ms⁻¹ is 1.4 x 10² L/mol.s.

For the fourth experiment:

Rate = k [NO]²[NO₂] 

⇒ k = Rate / [NO]²[NO₂] = 2.1 x 10⁻² Ms⁻¹ / (0.10 M)²(0.10 M) = 2.1 x 10² L/mol.s

Thus, the rate constant for the initial rate reaction 2.1 x 10⁻² Ms⁻¹ is 2.1 x 10² L/mol.s.

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Answer:

bile salts emulsify fats and break them down into smaller particles which gives the enzyme lipase a greater surface area to act on during digestion of fats.

Explanation:

Answer:

NH3 is the molecular formula of ammonia

Explanation:

i hope this will help you :)

A longitudinal wave is one in which the particles of a medium are moved in an orientation parallel to the path of energy transmission.

A longitudinal wave may be formed in a slinky by stretching it horizontally and vibrating the end coil back and forth in a motion that is horizontal.

There is a centre line where what the medium would lie if there was no wave, which is commonly referred to as the undisturbed state. The movement of the medium above this disturbed location is referred to as a crest, whereas the displacement below this undisturbed position is referred to as a trough.

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