NEED HELP ASAP!!!! please !!!!

Measure of angle:

∠A  = 36.86°

∠B = 90°

∠C = 53.13 °

Measure of side ,

AB =  28

BC = 21

CA = 35

Given triangle ABC.

Right angled at B.

Now, using trigonometric ratios to find angle A , B , C .

Right angled at B : ∠B = 90°

Angle A,

SinA = 21/35

∠A = 36.86

Angle C,

SinC = 28/35

∠C = 53.13

Now measures of side.

To find the length of side use sine rule .

Sine rule:

a/sinA = b/sinB = c /sinC

a = opposite side of angle A .

b = opposite site of angle B .

c = opposite side of angle C.

AB = 28

BC = 21

CA = 35

Hence the sides and angles of the triangles are measured .

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Answer:

Step-by-step explanation:The solutions to the equation x^2=6x-15 are x=3+sqrt(6)i,x=3-sqrt(6)i

Answer:

\(\displaystyle x=-\frac{3}{2}\pm \frac{\sqrt{21}}{2}i\)

Step-by-step explanation:

\(\displaystyle -2x^2-6x=15\\0=2x^2+6x+15\\\\x=\frac{-6\pm\sqrt{6^2-4(2)(15)}}{2(2)}=\frac{-6\pm\sqrt{36-120}}{4}=\frac{-6\pm\sqrt{-84}}{4}=\frac{-6\pm2i\sqrt{21}}{4}\\\\=-\frac{3}{2}\pm \frac{\sqrt{21}}{2}i\)

respuesta: $32,5

Step-by-step explanation:

Divide los $ 130,00 entre 4 y obtendrás cuanto cobra el fontanero como mano de obra

The descriptive statistics of the variables tota The mean of total_cases represents the average number of reported COVID-19 cases, while the mean of total_deaths represents the average number of reported COVID-19 deaths.

The measures of dispersion, such as standard deviation, indicate the spread or variability of the data points around the mean.

The mean of total_cases reveals the average magnitude of the spread of COVID-19 cases. A higher mean suggests a larger overall impact of the virus. The standard deviation quantifies the degree of variation in the total_cases data. A higher standard deviation indicates a wider range of reported cases, implying greater heterogeneity or inconsistency in the number of cases across different regions or time periods.

Skewness measures the asymmetry of the distribution. Positive skewness indicates a longer right tail, suggesting that there may be a few regions or time periods with exceptionally high case numbers. Kurtosis measures the shape of the distribution. Positive kurtosis indicates a distribution with heavier tails and a sharper peak, which implies the presence of outliers or extreme values in the data.

Similarly, the mean of total_deaths provides an average estimate of the severity of the COVID-19 outbreak. A higher mean indicates a greater number of deaths attributed to the virus. The standard deviation of total_deaths indicates the variability or dispersion of the death toll across different regions or time periods. Skewness and kurtosis for total_deaths provide insights into the shape and potential outliers in the distribution of death counts.

The means of total_cases and total_deaths offer average estimates of the impact and severity of COVID-19. The standard deviations indicate the variability or spread of the data, while skewness and kurtosis provide information about the shape and potential outliers in the distributions of the variables. These descriptive statistics help us understand the overall patterns and characteristics of COVID-19 cases and deaths.

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Profitability index is 1.387. Thus, the correct option is (c) 1.387.

The formula for calculating the profitability index is:

P.I = PV of Future Cash Flows / Initial Investment

Where,

P.I is the profitability index

PV is the present value of future cash flows

The initial investment in the project is $30 million. The cash flow at the end of the first year is $2.85 million.

The present value of cash flows can be calculated using the formula:

PV = CF / (1 + r)ⁿ

Where,

PV is the present value of cash flows

CF is the cash flow in the given period

r is the discount rate

n is the number of periods

For the first-year cash flow, n = 1, CF = $2.85 million, and r = 11%.

Substituting the values, we get:

PV = 2.85 / (1 + 0.11)¹ = $2.56 million

To calculate the present value of all future cash flows, we can use the formula:

PV = CF / (r - g)

Where,

PV is the present value of cash flows

CF is the cash flow in the given period

r is the discount rate

g is the constant growth rate

For the subsequent years, CF = $2.85 million, r = 11%, and g = 3.85%.

Substituting the values, we get:

PV = 2.85 / (0.11 - 0.0385) = $39.90 million

The total present value of cash flows is the sum of the present value of the first-year cash flow and the present value of all future cash flows.

PV of future cash flows = $39.90 million + $2.56 million = $42.46 million

Profitability index (P.I) = PV of future cash flows / Initial investment

= 42.46 / 30

= 1.387

Therefore, the correct option is (c) 1.387.

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Answer:

I believe the correct answer would be 16.

Step-by-step explanation:

There are 2 cases of golf balls that hold 12 boxes of 12 balls.

    12(12) + 12(12) = 288

You need to find how many cases Joan can buy to equal the amount of 288 balls.

    18(x) = 288

I simply divided 288 by 18 to get the answer of 16.

    x = 16

The number of packages should need to buy is 16.

There are 2 cases of golf balls that hold 12 boxes of 12 balls.

12(12) + 12(12) = 288

Now

18(x) = 288

x = 16

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The expected difference is 0.17

A supermarket is a self-service store with various food, drink, and household goods options divided into categories. While this type of store is bigger and has a wider variety of products than older grocery stores, it is smaller and offers a smaller selection of goods than a hypermarket or big-box market. Fresh meat, produce, dairy, deli foods, baked goods, etc. may usually be found in the store.

Additionally, shelf space is set aside for canned and packaged goods as well as a variety of non-food items like pet supplies, cleaning supplies, cookware, and household cleansers.

The table is: 0 1 2 3

x1 0 0.08 0.06 0.04 0.00

1 0.05 0.18 0.05 0.03

2 0.05 0.04 0.10 0.06

3 0.00 0.03 0.04 0.07

4 0.00 0.01 0.05 0.06

Expected difference =

+(0.08*(0-0)) +(0.06*(0-1)) +(0.04*(0-2)) +(0.00*(0-3)) +(0.05*(1-0)) +(0.18*(1-1)) +(0.05*(1-2)) +(0.03*(1-3)) +(0.05*(2-0)) +(0.04*(2-1)) +(0.10*(2-2)) +(0.06*(2-3)) +(0.00*(3-0)) +(0.03*(3-1)) +(0.04*(3-2)) +(0.07*(3-3)) +(0.00*(4-0)) +(0.01*(4-1)) +(0.05*(4-2)) +(0.06*(4-3))

= 0.17

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Therefore, the set of values of c in the equation for which the curve and the line intersect at two distinct points is given by:

c > -4

To show that two amounts or values are equivalent, an equation is employed, such as 6 x 4 = 12 x 2. Number able noun A situation where two or more factors must be considered in order to see or comprehend the overall situation is referred to as an equation.

To find the points of intersection between the curve and the line, we need to solve the system of equations:

y = x² + 2cx + 4

y + 4x = -c

Substituting the expression for y from the first equation into the second equation:

x² + 2cx + 4 + 4x = -c

x² + (2c + 4)x + (c + 4) = 0

For the curve and the line to intersect at two distinct points, the quadratic equation above must have two distinct real solutions for x. This means that the discriminant of the quadratic equation must be positive:

(2c + 4)² - 4(c + 4)(c) > 0

4c² + 8c + 16 - 4c² - 16c > 0

4c > -16

c > -4

Therefore, the set of values of c for which the curve and the line intersect at two distinct points is given by:

c > -4

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The line integral of $2x^2 \mathrm{~d}y$ along the curve $C$ is equal to 486 according to the given information.

To calculate the line integral $\int_C 2x^2 \mathrm{~d}y$, we need to parameterize the curve $C$ and express $x$ and $y$ in terms of the parameter $t$. The given curve is defined as $\mathbf{r}(t) = \langle 3t-3, 3t \rangle$, where $0 \leq t \leq 4$.

Differentiating $\mathbf{r}(t)$ with respect to $t$, we have $\mathbf{r}'(t) = \langle 3, 3 \rangle$. Integrating $2x^2$ with respect to $y$ along the curve $C$ gives us:

$\int_C 2x^2 \mathrm{~d}y = \int_0^4 2(3t-3)^2 (3 \mathrm{~d}t) = 2 \int_0^4 (27t^2 - 54t + 27) \mathrm{~d}t$.

Evaluating the integral, we get $\int_C 2x^2 \mathrm{~d}y = [9t^3 - 27t^2 + 27t]_0^4 = 486$.

Therefore, the line integral $\int_C 2x^2 \mathrm{~d}y$ along the curve $C$ is equal to 486.

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They should use 6 cup of Noah's measuring cup

They are the set of numbers and symbols that are related by the different mathematical operation signs such as addition, subtraction, multiplication, division among others.

To solve this problem we must perform the following algebraic operations with the given information

Information about the problem:

Calculating the number of cup the should use:

Number of cup = Recipe call / Noah's cup

Number of cup = (3/4) / (1/8)

Number of cup = 3*8 / 4*1

Number of cup = 24/4

Number of cup = 6

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Correctly written question:

Melanie and Noah are baking a birthday cake for Francesca. The recipe call for 3/4 measuring cup and Noah has a 1/8 measuring cup. Which cup should they use?

K'(-2, 1) is the coordinate of the image of point K, found by multiplying the original x-coordinate of the point K (2) by -1. To reflect the triangle over the y-axis, the x-coordinate of each point is multiplied by -1.

Triangle is a three-sided geometric shape which has three angles and three sides. The three sides of a triangle are typically referred to as the base, the height, and the hypotenuse. A triangle can be classified as either right, obtuse, or acute depending on the measure of its angles. Right triangles have one right angle, obtuse triangles have one obtuse angle, and acute triangles have three acute angles.

The coordinate of the image of point K is K’(-2, 1). This means that the x-coordinate of the point is -2 and the y-coordinate of the point is 1. This can be found by multiplying the original x-coordinate of the point K (2) by -1. The y-coordinate of point K remains the same, so the y-coordinate of the image of point K is 1.

Therefore, the coordinate of the image of point K is K’(-2, 1).

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Given that, The 99% confidence interval of a population mean is (1,7). We need to find the 95% confidence interval.As the confidence interval becomes wider as the confidence level increases. Hence, the 95% confidence interval will have a greater range than the 99% confidence interval.Confidence interval can be calculated by the formula:Confidence Interval = $\overline{X}$ ± Zα/2 (σ/√n)Where, $\overline{X}$ is the sample mean.Zα/2 is the critical valueσ is the population standard deviationn is the sample sizeNow, Zα/2 for 99% confidence interval is 2.576 as per the normal distribution table.In the same way, Zα/2 for 95% confidence interval is 1.96.Converting the above formula for 95% confidence interval:1.96 = (1,7 - $\overline{X}$)/(σ/√n)On solving the above equation, we get: σ/√n = 0.2039σ = 0.2039 √n.....(1)Also, (1,7 - $\overline{X}$)/σ = 1.96....(2)Substituting equation (1) in equation (2), we get:(1,7 - $\overline{X}$)/ (0.2039√n) = 1.96On solving this equation, we get:$\overline{X}$ = 1.47 √n + 1.7...........(3)Now, for option (a), (b), (c) and (d), we need to verify which option satisfies the equation (3).Let's check for option (a):(2+6)/2 = 4............taking the average1.47 √n + 1.7 = 4n = 19.22 squaring both sidesn = 363.6Hence, option (a) is the correct answer.Write the answer in main part:The 95% confidence interval is (2,6).Explanation:On solving the equation, we get that the option (a) is correct. Therefore, the 95% confidence interval is (2,6).Conclusion:Therefore, option (a) (2,6) is the correct 95% confidence interval.

The 95% confidence interval for the population mean is given as follows:

c) (2,6).

The 99% confidence interval for the population mean is given as follows:

(1,7).

Hence the sample mean is given as follows:

(1 + 7)/2 = 4.

Meaning that the mean of the two bounds in the interval must be of 4.

The 95% confidence interval is narrower than the 99% confidence interval, hence, considering the mean of the bounds of 4, option c is the correct option for this problem.

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Given:

The system of the equation is,

Draw the lines on the graph, the point at which the lines intersects. That point will be the solution of the system.

The points on the line 2x+5y=0 are,

And the points on the line x+6y=14

The graph of the lines is,

As the point of intersection is ( -10,4).

The solution of the given system of equation is x = -10, y = 4.

Answer:

\(y=\frac{3}{13}x-\frac{174}{13}\)

Step-by-step explanation:

slope:

\(m=\frac{-15-(-9)}{-7-19} =\frac{-15+9}{-26} =\frac{-6}{-26} =\frac{3}{13}\)

Equation, with the point (19, -9):

\(y-(-9)=\frac{3}{13} (x-19)\)

\(y+9=\frac{3}{13} x-\frac{57}{13}\)

\(y=\frac{3}{13} x-\frac{57}{13} -9\)

                                      \(-9=-9(\frac{13}{13} )=-\frac{117}{13}\)

\(y=\frac{3}{13}x-\frac{174}{13}\)

Hope this helps

Answer:

y=4x+13

Step-by-step explanation:

Answer:

y=4 x+ 13

Step-by-step explanation:

I have had that same question before gussed and got it right.

Answer:

44 words

Step-by-step explanation:

Step one:

given data

The dimension is

7cm long and = 0.07mm

5mm in diameter

radius= 2.5mm

The volume = πr^2h

Volume= 3.142*2.5^2*0.07

Volume= 3.142*6.25*0.07

volume= 1.4 mm^3

If 1.4 mm^3 will write 310 words on an average

1/5(0.2mm^3) liter will write x

cross multiply we have

x= 0.2*310/1.4

x=62/1.4

x=44 words

Answer:

13

Step-by-step explanation:

y=5+2(4)

Answer:

c y would equal 13 your answer is C

1. In the context of spacetime, the locus of points equidistant from the origin of a spacetime plane is a hyperbola.

In Euclidean space, the distance between two points is given by the Pythagorean theorem, which only considers spatial dimensions. However, in spacetime, the concept of distance is extended to include both spatial and temporal components. The spacetime distance, also known as the interval, is given by the Minkowski metric:

ds^2 = -c^2*dt^2 + dx^2 + dy^2 + dz^2,

where c is the speed of light, dt represents the temporal component, and dx, dy, dz represent the spatial components.

To determine the locus of points equidistant from the origin, we need to find the set of points where the spacetime interval from the origin is constant. Setting ds^2 equal to a constant value, say k^2, we have:

-c^2*dt^2 + dx^2 + dy^2 + dz^2 = k^2.

If we focus on a spacetime plane where dy = dz = 0, the equation simplifies to:

-c^2*dt^2 + dx^2 = k^2.

This equation represents a hyperbola in the spacetime plane. It differs from a circle in Euclidean space due to the presence of the negative sign in front of the temporal component, which introduces a difference in the geometry.

Therefore, the locus of points equidistant from the origin in a spacetime plane is a hyperbola.

(Note: The explanation provided assumes a flat spacetime geometry described by the Minkowski metric. In the case of a curved spacetime, such as that described by general relativity, the shape of the locus of equidistant points would be more complex and depend on the specific curvature of spacetime.)

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Answer:

about 8.5, -8.5

Step-by-step explanation:

the answer will be thirty three cm.

Answer:

The answer you're looking for is 1470.

Step-by-step explanation:

The method I used was PEMDAS

Since there was no parenthesis, I simplified the exponents.

2.130 x 10³ - 6.6 x 10² = ?
2.130 x 1000 - 6.6 x 100 = ?

After that, I multiplied all terms next to each other.

2.130 x 1000 - 6.6 x 100 = ?
2130 - 660 = ?

The final step I did was to subtract the two final terms and ended up with 1470 as my final answer.

1470 = ?

I hope this was helpful!

Macy has 148 apples.

\(198 - 75 = 123\)

\(123 + 75 = 198\)

\(198 - 70 = 128\)

\(128 + 20 = 148\)

Therefore, your correct answer would be 148.

The rule of parallel lines: they never intersect each other.

We know that two lines are parallel to each other if they lie in the same plane and never intersect each other.

Parallel lines are always equidistant from each other.

Also, the parallel lines are coplanar.

Mathematically, the parallel lines are represented by the symbol, ‘||‘.

If two lines l₁ and l₂ are parallel to each other then they are represented as l₁ || l₂.

Two lines parallel to a third line are parallel

As we know, the slopes of parallel lines are equal.

Let us assume that m₁ be the slope of line l₁ and m₂ be the slope of line l₂.

If line l₁ and l₂ are parallel to each other then m₁ = m₂

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Answer:  

Step-by-step explanation:

4564.  2 75444214///4222.-112

The fully simplified form of the expression is \(\frac{3}{2x+12}-\frac{-3}{x-8} +\frac{4}{x+6}\)

A quadratic equation is a type of polynomial equation that has the general form ax^2 + bx + c = 0, where a, b, and c are coefficients and x is an unknown variable. The equation has two solutions, which can be found using the quadratic formula x = (-b ± √(b^2 - 4ac)) / 2a, where the ± symbol indicates that there are two possible solutions.

Quadratic equations are used to model a variety of real-world phenomena, such as the motion of objects under the influence of gravity, the path of a projectile, and the growth of a population over time. They are also used to describe the parabolic shape of curves and to solve optimization problems, such as finding the maximum or minimum value of a function

We can simplify the expression as follows:

\(\frac{3}{2x+12} =\frac{x-15}{x^{2} -2x-48}\)

First, we'll simplify the denominators. To do this, we can factor the quadratic expression x² - 2x - 48:

x² - 2x - 48 = (x - 8)(x + 6)

Now we can rewrite the denominators:

\(\frac{3}{2x+12}-\frac{x-15}{(x-8)(x+6)}\)

Next, we'll simplify the fraction in the second term using partial fraction decomposition:

\(\frac{x-15}{(x-8)(x+6)} =\frac{A}{x-8}+\frac{B}{x+6}\)

where A and B are constants that we can find by multiplying both sides by (x - 8)(x + 6) and equating the numerators:

x - 15 = A(x + 6) + B(x - 8)

Expanding both sides:

x - 15 = Ax + 6A + Bx - 8B

Comparing coefficients:

-15 = Ax + 6A + Bx - 8B

1 = A + B

8B = Ax + 6A + 15

-6A = -15 - Ax - 8B

-6A = -15 - (A + B)x - 8B

-6A = -15 - x + 7x

-6A = -15 - x + 7x

-6A = -15 + 6x

Solving for A and B, we have:

A = -3

B = 4

So, the second term can be written as:

\(\frac{x-15}{(x-8)(x+6)} =\frac{-3}{x-8}+\frac{4}{x+6}\)

Putting everything together, we have:

\(\frac{3}{2x+12} -\frac{x-15}{(x-8)(x+6)} =\frac{3}{2x+12}-\frac{-3}{x-8} +\frac{4}{x+6}\)

which is the fully simplified form of the expression.

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Answer: Let's use a Venn diagram to solve this problem.

First, we know that 612 students like football, 540 students like volleyball, and all students like at least one game. This means that there is some overlap between the two groups in the Venn diagram.

Let x be the number of students who like both games. Then, the number of students who like only football is 612 - x, and the number of students who like only volleyball is 540 - x.

Since all 900 students like at least one game, we can add up the number of students in each of these three groups and set the sum equal to 900:

(612 - x) + x + (540 - x) = 900

Simplifying the left side of the equation gives:

1152 - 2x = 900

Subtracting 1152 from both sides gives:

-2x = -252

Dividing both sides by -2 gives:

x = 126

Therefore, 126 students like both football and volleyball.

To find the number of students who like only football, we can substitute x = 126 into the expression 612 - x:

612 - 126 = 486

Therefore, 486 students like only football.

Step-by-step explanation:

Answer:

5x+4

Step-by-step explanation:

Answer:14

Step-by-step explanation: so if you add 21 and 264 and 20 u would get 14 hehehehhehehe im da best your not :)

The coordinates of G after dilation is ( -2/3, 4/3).

Dilation:

Dilation is a transformation, which is used to resize the object. Dilation is used to make objects larger or smaller. This transformation produces an image that is the same as the original shape.

Here the three vertices of the triangle are given:

G = ( -2, 4)

H = ( 3, 6)

J = ( 3, -2)

The scale factor is given as, k = 1/3

So the image of G is calculated as:

G' = kG

= 1/3( -2, 4)

= ( -2/3, 4/3)

So the coordinate of G' after dilation is (-2/3, 4/3).

Therefore the coordinate after dilation is (-2/3, 4/3)

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Answer:

4

Step-by-step explanation:

D (-1, -3) and F( 2, 3)

G (-4, -4)

Which point on the y-axis lies on the line that passes through point G and is parallel to line DF?

If the line is parallel to DF then they have the same slope.

slope of line DF is m= difference in y/ difference in x = (-3-3)/( -1-2) = -6/-3 = 2

so slope of line that passes trough G and is ║ with DF is also m= 2

From point G (-4, -4) we go with a slope of 2 until we get to the y-axis

So we go up 2 and 1 left, 2up and 1 left, ... until we get to the point (0, 4), because the slope = rise/run = rise 2/run 1

I) f is continuous at x=2

II) f is differentiable at x=2

These both f (function ) are true

The given limit can be recognized as the definition of the derivative of f at x=2. Specifically, it states that the derivative of f at x=2 is equal to 5.

Using this information, we can make the following conclusions:

I) We cannot say for sure whether f is continuous at x=2 based on the given limit alone. While a function being differentiable at a point implies that it is also continuous at that point, the converse is not necessarily true. Therefore, we would need additional information to determine whether f is continuous at x=2.

II) The given limit implies that f is differentiable at x=2, since the limit exists and is finite. Specifically, we can say that the derivative of f at x=2 exists and is equal to 5.

III) The given limit also implies that the derivative of f is continuous at x=2. This is because the limit defines a continuous function at x=2, and it is well-known that if a function is differentiable at a point, then it is also continuous at that point.

Therefore, the correct answers are II and III.

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