Need help ASAP! Tysmm

Answer:

X=4

Step-by-step explanation:

(4x+34) + (x+36) = 90

4x + 34 + x + 36 = 90

5x + 70 = 90

5x = 20

x = 4

The Mean Absolute Deviation of Set 1 exists 13 more than the mean absolute deviation of Set 2.

Set 1: 12, 8, 10, 50

Set 2: 13, 9,8

To determine the mean for each set

Mean = totality of elements/number of elements

Mean of Set 1:

\($=\frac{12+8+10+50}{4}\)

\($=\frac{80}{4}=20$\)

Mean of Set 2:

\($=\frac{13+9+8}{3}\)

\($=\frac{30}{3}=10$\)

To determine the mean absolute deviation (MAD) of the data in each set.

M.A.D of Set 1:

\($=\frac{|12-20|+|8-20|+|10-20|+|50-20|}{4}\)

\($=\frac{8+12+10+30}{4}=\frac{60}{4}=15$$\)

M.A.D of Set 2:

\($=\frac{|13-10|+|9-10|+|8-10|}{3}\)

\($=\frac{3+1+2}{3}=\frac{6}{3}=2$\)

The Mean Absolute Deviation of Set 1 exists 13 more than the mean absolute deviation of Set 2.

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a) The mean and the standard deviation of the amateur golfer’s scores for both the years 2014 and 2015 are given below:2014 Season Mean of scores = (72+76+77+75+73+71+73+75) / 8

= 592 / 8 = 74

Standard Deviation (SD) of scores = 2.29 (rounded to 2 decimal places) 2015

Season Mean of scores

= (69+68+73+75+83+78+69+77) / 8

= 592 / 8

= 74

Standard Deviation (SD) of scores = 5.05 (rounded to 2 decimal places)b)

The primary difference in performance between 2014 and 2015 is that the standard deviation of the scores in 2015 is greater than that in 2014.

This indicates that the scores in 2015 were more spread out or varied than in 2014.

Improvement can be seen in the 2015 scores as the mean of scores in 2015 is less than the mean of scores in 2014. The lower mean score indicates an improvement in the performance of the amateur golfer.

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The way that the correlation will be affected if the units are changed from minutes to seconds is that the correlation will still be the same.

Correlation simply means a statistical measure which expresses the extent to which two variables are linearly related.

From the information, it was stated that twenty-five trials are completed and the correlation coefficient between typing speed and time is determined to be -0.622.

In this case, even when the units for time are changed from minutes to seconds, the correlation won't change. This is because the change in units has no effect on the correlation.

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Answer:

The correlation would stay the same because the change in units for time would have no effect on it.

Step-by-step explanation:

Answer:

try ( -4,1)

Step-by-step explanation:

if not then i'm sorry

Answer:

Step-by-step explanation:

The slope is the ratio of rise to run.

Rise is the difference of y-coordinates, run is the difference of x-coordinates.

Now, the slope is said undefined if the difference of x-coordinates is zero.

It means you have to divide by zero but it is impossible.

We have a point (- 4, - 8) and the slope is undefined.

It means our line has repeat x = -4 coordinates, it is a vertical line.

Its equation will be:

Let's write the equation

\(\\ \sf\longmapsto y=mx+b\)

\(\\ \sf\longmapsto x+4=\dfrac{-8}{\infty}\)

\(\\ \sf\longmapsto x+4=0\)

\(\\ \sf\longmapsto x=-4\)

Answer:

ok what is it

Step-by-step explanation:

Answer:

a = -20/9.

Step-by-step explanation:

We can write it as

f(x) = a(x - 7)(x + 1)

When x = -2 and y = -20   (at the point(-2, -20):

-20 = a(-2 -7)(-2 + 1)

-20 = -9*-1 a

9a = -20

a = -20/9.

Area of shaded region is 0.3554.

What is an area in math?

The area is the region bounded by the shape of an object. The space covered by the figure or any two-dimensional geometric shape, in a plane, is the area of the shape.

Question:1)

z  ~ N(0,1)

The shaded standard normal is

P(-3.02 < Z < 4.52)

= P(Z < 4.52) - P(Z < -3.02)

= 0.9999 - 0.0013

= 0.9986

Area of shaded region is 0.9986

Question:2)

P(-1.46 < Z < 0.84)

= P(Z < 0.84) - P(Z < -1.46)

= 0.7995 - 0.0721

= 0.7274

Area of shaded region is 0.7274

Question:3)

P(Z < 0.3707) = 1 - P(Z < 0.3707)

 = 1 - 0.6446

 = 0.3554

Area of shaded region is 0.3554

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Answer:

can u type it so i can answer, i cant see it

Step-by-step explanation:

Answer: 4 (none of the given options are correct)

Step-by-step explanation:

\(f(x)=2x=8\\\\x=\boxed{4}\)

For the function f(x)=2x, the value of x is 8 when f(x) = 8

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The graph shown the function  f(x) = 2x.

A relation is a function if it has only One y-value for each x-value.

We have to find the value of x when f(x) is 8

Let us equate the two functions

2x=8

Divide both sides by 2

x=4

Hence, for the function f(x)=2x, the value of x is 8 when f(x) = 8

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Answer:

If P=Q: (x=R)

If P≠Q: x=(p+q)/2   p≠0, q≠0

Step-by-step explanation:

IF P=Q: then the statement is true for all real numbers (x=R) (I can’t make the symbol for all real numbers here)

IF P≠Q:

(2x+p)/q=(2x+q)/p

cross multiply

2xp+p²=2xq+q² p≠0, q≠0

2xp-2xq=q²-p²  p≠0, q≠0

2x(p-q)=q²-p²  p≠0, q≠0

DIvide both sides by 2(p-q) and you get

x=(p+q)/2   p≠0, q≠0

The set of vectors that form an

orthonormal basis

for R² is B. {[1,0]ᵀ,[0,1]ᵀ}.

To determine which of the sets of vectors form an orthonormal basis for R², we need to check if the vectors are orthogonal and have a length of 1. For set A, we can calculate the dot product of the two vectors and see that it is not equal to zero, so they are not orthogonal. For set C, the dot product of the two vectors is also not equal to zero, so they are not orthogonal. For set D, we can calculate the length of the vectors and see that they are not equal to 1, so they do not have a length of 1. Therefore, the only set of vectors that form an orthonormal basis for R² is set B, which consists of the standard basis

vectors

{[1,0]ᵀ,[0,1]ᵀ}.

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Answer:

576

Step-by-step explanation:

64×9 = 576

72×8= 576

The LCM of both numbers is 576

Answer:

Step-by-step explanation:

It will be the least common multiple of 64 and 72 days

64 = 2 * 2 * 2 * 2 * 2 * 2 = 2⁶

72 = 2*2*2*3*3 = 2³ * 3²

LCM = 2⁶ * 3² = 64 * 9 =  576

Both will meet each other again 576 days

Answer:

∠ DEB = 101.97°

Step-by-step explanation:

BCDE is a cyclic quadrilateral, whose opposite angles are supplementary, so

∠ BCD + ∠ DEB = 180°, that is

78.03° + ∠ DEB = 180° ( subtract 78.03° from both sides )

∠ DEB = 101.97°

For your question:

"A ship travels 60 miles in the direction S 45° E, then travels 150 miles in the direction S 20° W. What is the distance,

x, from the starting location?"

Please see above for answer.

Let me know if you have any further questions.

The distance, x, from the starting location will be 183.6 miles.

Distance is a numerical representation of the distance between two objects or locations.

Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

Let the ship start at point O and proceed for 60 miles in the 34 °S direction to point P. Then, after 150 kilometers Q.

From the obtained value, the angle P can be obtained;

∠P=180°-(45°+20°)

∠P=115°

From triangle,

OP=60 cm

PQ=150

∠P=115°

OQ=x

OQ²=OP²+PQ₂-2OP.PQ.COS∠P

x²=60²+150²-2(60)(150)COS(115°)

x²=3600+22500+7606.8

x²=33,706.8

x=√(33,706.8)

x=183.59

x=183.6 miles

Hence,the distance, x, from the starting location will be 183.6 miles.

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Answer:

0.23 millimeters

Step-by-step explanation:

We can get how much extra gap there is by subtracting the actual gap by the ideal gap, so:

1.12 - 0.89 = 0.23 millimeters

Hope this helped somewhat!

A sampling frequency of 10 pixels per millimeter would produce a spatial resolution of 5 line pairs per millimeter (B).

A sampling frequency of 10 pixels per millimeter would produce a spatial resolution of B. 5 line pairs per millimeter.
Here's a step-by-step explanation:

1. The sampling frequency is given as 10 pixels per millimeter.
2. According to the Nyquist-Shannon sampling theorem, the maximum spatial frequency (in line pairs per millimeter) that can be accurately represented is half of the sampling frequency.
3. Divide the sampling frequency (10 pixels per millimeter) by 2: 10/2 = 5 line pairs per millimeter.

So, the answer is B. 5 line pairs per millimeter.

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The chi-square test of independence is typically used to analyze the relationship between two variables when both variables are nominal, the two variables have been measured on different individuals and the observations on each variable are within-subjects in nature. The answer is  D. all of the above

The chi-square test of independence is a statistical test that is used to determine if there is a significant association between two categorical variables. It is commonly used when both variables are nominal, meaning they consist of categories or groups rather than numerical values.

When conducting the chi-square test of independence, the data is typically collected by measuring the two variables on different individuals or units.

For example, researchers may collect data on the gender (nominal variable) and political affiliation (nominal variable) of different individuals and analyze whether there is a relationship between the two variables.

The test examines the observed frequencies of the different categories in a contingency table and compares them to the expected frequencies under the assumption of independence. If the observed and expected frequencies significantly differ, it suggests that there is an association between the two variables.

Therefore, the chi-square test of independence is applicable when both variables are nominal and the data is collected on different individuals. This allows researchers to investigate the relationship between the variables and determine if they are associated or independent.

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Answer:

it depends on how many females are there

Step-by-step explanation:

I need to know how many females are there

Answer: If there are x total members, then the number of males is 5/8x

Answer:

Sorry if im wrong but for c put (x+8) x (x+y)

for d put (x+3y-1) x (x+y)

Step-by-step explanation:

Answer:

Step-by-step explanation:

BaBaKeKeOriginal

Answer:

Answer: 10x^2 -13x-3

Foil method

Step-by-step explanation:

I beleive its right.

Answer:

$204.98

Step-by-step explanation:

Step 1: Add both item cost

\(99.90 + 89.90 = 189.80\)

Step 2: Find the sales tax of the result

\(\frac{8}{100}\times 189.8 = 15.184\)

Step 3: Add the result from the total cost of both items

\(189.80 + 15.184 = 204.98\)

The total cost of the hats and boots including sales tax is 204.98 dollars

Answer:

49.8 calories were left!!!

Step-by-step explanation: Just subtract 91-41.2!

A) The probability that the sample mean is within $500 of the population mean for a sample of size 60 is 0.6611

B) The probability that the sample mean is within $500 of the population mean for a sample of size 120 is 0.7362

The EAI (Error of the Estimate) sampling problem is a specific case of the Central Limit Theorem, which states that the distribution of sample means from a population with a finite variance will be approximately normally distributed as the sample size increases.

The formula for calculating the standard error of the mean is

SE = σ/√n

where SE is the standard error, σ is the population standard deviation, and n is the sample size.

For n = 30, SE = 4,000/√30 = 729.16

A. For a sample size of n = 60, SE = 4,000/√60 = 516.40

To find the probability that the sample mean is within $500 of the population mean, we need to calculate the z-score for a range of +/- $500

z = (x - μ) / SE

where x is the sample mean, μ is the population mean, and SE is the standard error.

For a range of +/- $500, the z-scores are

z = ($51,300 - $51,800) / 516.40 = -0.969

z = ($52,300 - $51,800) / 516.40 = 0.969

Using a standard normal distribution table, the area between z = -0.969 and z = 0.969 is 0.6611.

B. For a sample size of n = 120, SE = 4,000/√120 = 368.93

Following the same steps as above, the z-scores for a range of +/- $500 are

z = ($51,300 - $51,800) / 368.93 = -1.364

z = ($52,300 - $51,800) / 368.93 = 1.364

Using the standard normal distribution table, the area between z = -1.364 and z = 1.364 is 0.7362.

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