NEED HELP IM BEGGING YOU PLEASE !!!!!!

Answer:

Step-by-step explanation:

so Jada for 1 day, gets charged $30 flat

now, she drove 2 days, so...she's charged 2 * 30 or 60 bucks

plus the mileage

is 0.5 per mile.... so... 1 mile is 0.5

2  miles 2 * 0.5

3 miles 3 * 0.5

4 miles 4 * 0.5

5 miles 5 * 0.5

x miles x * 0.5

she drove "x" miles, whatever that is

we also know, her total cost in the end, was 360

so... those 360 include the 2 days charge, 30 * 2

plus the mileage,  x * 0.5 or 0.5x

so... one can say that

360 = (30 * 2) + 0.5x    <---- solve for "x"

Answer:

150, I believe.

Step-by-step explanation:

If it takes about 30 dollars a day, that would be $60 for 2 days.

The mile expenses should be $300, right? If this is true, we should be able to do: $0.50 * 300.

The answer is 150.

The appropriate choice about the display technique in case of two continuous variables is the scatter plot.

A scatter plot is a graph used to plot two variables, usually as the horizontal and vertical axis, to check for a correlation or connection between them.What is a variable?A variable is a statistical concept that is used to measure the characteristics of a population or a sample.

A variable is an attribute or a feature of an object, event, or person that can be quantified or described numerically. The pie chart is appropriate when you want to display a distribution of a continuous variable. But this technique is not appropriate in this case because you cannot see the distribution of a single continuous variable using a pie chart. A pie chart is best suited for showing percentages of a whole.C.E. A scatter plot is a graphical representation of the relationship between two variables. This technique is appropriate when you want to display two continuous variables. A treemap is best suited for showing the distribution of one categorical variable. F. A pie chart is appropriate when you want to display the distribution of a single continuous variable. A contingency table is appropriate when you want to display the frequency distribution of one categorical and one continuous variable.

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hope it helps

Answer:

a on edge 2021

Step-by-step explanation:

i took the test and got 100, hope this helps:)

Answer:

I think it is D

Step-by-step explanation:

Edge

Answer:

Yes

Step-by-step explanation:

From the origin means from the centre or middle but about a vertex is from a named point.

The formula for the area of the triangle which is directly proportional to the base length a and b and the height of the triangle, indicates that the ratio of the altitudes is b/a

The area of a triangle = (1/2) × Base × Height

Where the base is the length of one side of the triangle, and the height is the perpendicular distance from the base to the opposite vertex.

To prove that if the lengths of two sides of a triangle are a and b respectively, then the lengths of the corresponding altitudes to those sides are in the ratio b/a, we can use the formula for the area of a triangle as follows;

Area of a triangle = (1/2) × Base length × Height of the triangle

Let's assume that the two sides of the triangle are a and b, and the corresponding altitudes are h₁ and h₂ respectively. Then we can write;

Area of the triangle = (1/2) × a × h₁ =  (1/2) × b × h₂

(1/2) × a × h₁/((1/2) × b × h₂) = 1

Simplifying the above equation, we get;

h₁/h₂  b/a

Therefore, the lengths of the corresponding altitudes to those sides are in the ration b/a

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Answer:

After comparing we get \(\mathbf{0.3\: <\: 0.7}\)

Step-by-step explanation:

We need to compare the comparison below.

\(\frac{3}{10}\:?\:0.7\)

For comparison both terms should be in decimal.

So, converting 3/10 into decimal we get 0.3

Now, \(0.3\:?\:0.7\)

We know that 0.3 is less than 0.7

So, \(0.3\: \mathbf{<}\: 0.7\)

So, after comparing we get \(\mathbf{0.3\: <\: 0.7}\)

To solve the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0, we can use algebraic methods and the unit circle to determine the values of x that satisfy the equation.

1. Start by rearranging the equation to a quadratic form: \(6sin^2(x)\) + 6sin(x) + 1 = 0.

2. Notice that the equation resembles a quadratic equation in terms of sin(x). Let's substitute sin(x) with a variable, such as u: \(6u^2\) + 6u + 1 = 0.

3. Solve this quadratic equation for u. You can use the quadratic formula or factorization methods to find the values of u. The solutions are u = (-3 ± √3) / 6.

4. Since sin(x) = u, substitute back the values of u into sin(x) to obtain the values for sin(x): sin(x) = (-3 ± √3) / 6.

5. To find the values of x, we can use the inverse sine function. Take the inverse sine of both sides: x = arcsin[(-3 ± √3) / 6].

6. The arcsin function has a range of [-π/2, π/2], so the values of x lie within that range. Use a calculator to find the approximate values of x based on the values obtained in step 5.

7. Plot the obtained x-values on the graph to show the solutions of the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0. The graph will illustrate the points where the curve intersects the x-axis.

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The equations of the perpendicular lines are: y = 1/2x + 6, y = 15, y = -x - 2, y = 6x + 3 and y = 1/3x - 4

When a linear equation is represented as:

Ax + By = C

The slope (m) is:

m = -A/B

When the linear equation is represented as:

y = mx + c

The slope is m

A line perpendicular to a linear equation that has a slope of m would have a slope of -1/m

Using the above highlights, the equations of the lines are:

6. y = -2x + 5; (2, 7)

The slope is:

m = -2

The perpendicular slope is:

n = 1/2

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 1/2(x - 2) + 7

Evaluate

y = 1/2x - 1 + 7

This gives

y = 1/2x + 6

7. y = -5; (11, 15)

The slope is:

m = 0

The perpendicular slope is:

n = 1/0 = undefined

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 15

8. Graph ; (-12, 10)

The slope is:

m = (y2 - y1)/(x2 - x1)

Using the points on the graph, we have:

m = (2 - 3)/(3 - 4)

m = 1

The perpendicular slope is:

n = -1

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = -1(x + 12) + 10

y = -x - 12 + 10

Evaluate

y = -x - 2

9. y = -1/6x + 1; (-2, -9)

The slope is:

m = -1/6

The perpendicular slope is:

n = 6

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 6(x + 2) - 9

Evaluate

y = 6x + 12 - 9

This gives

y = 6x + 3

10. 6x + 2y = 14; (12, 0)

The slope is:

m = -6/2

m = -3

The perpendicular slope is:

n = 1/3

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 1/3(x - 12) + 0

Evaluate

y = 1/3x - 4

Hence, the equations of the perpendicular lines are: y = 1/2x + 6, y = 15, y = -x - 2, y = 6x + 3 and y = 1/3x - 4

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Answer:

y = 8.7 - 1.3x

The distance between the foot of the ladder and the foot of the building is 2.6 ft

Part 1) The general form of a circle is given as x²+y² +4x - 12y + 4 = 0.

(a)What are the coordinates of the center of the circle?

(b)What is the length of the radius of the circle?

x²+y² +4x - 12y + 4 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²+4x)+(y²- 12y)=-4

Complete the square twice. Remember to balance the equation by adding the same constants to each side

(x²+4x+4)+(y²- 12y+36)=-4+4+36

Rewrite as perfect squares

(x+2)²+(y-6)²=36--------> (x+2)²+(y-6)²=6²

center (-2,6)

radius 6

the answer Part a) is

the center is the point (-2,6)

the answer Part b) is

the radius is 6

Part 2)

see the picture attached N 1 to better understand the problem

we know that

sin ∅=opposite side angle ∅/hypotenuse

opposite side angle ∅=9.2 ft

hypotenuse=10 ft

so

sin ∅=9.2/10-----> 0.92

∅=arc sin (0.92)------> ∅=66.93°-----> ∅=67°

the answer Part a) is

67°

Part b)

see the picture attached N 2 to better understand the problem

cos 75=adjacent side angle 75/hypotenuse

adjacent side angle 75=AC

hypotenuse=10 ft

so

cos 75=AC/10---------> AC=10*cos 75----> AC=2.59 ft----> AC=2.6 ft

the answer Part B) is

The distance between the foot of the ladder and the foot of the building is 2.6 ft

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Answer:

-x^3-5x^2+10x-4

Step-by-step explanation:

(−x + 1) (x ^ 2 + 6x − 4) = (-x)(x ^ 2 + 6x − 4) + 1(x ^ 2 + 6x − 4)

= -x^3-6x^2+4x+x^2+6x-4 = -x^3-5x^2+10x-4

Answer:

(-5+8,3-8) = (3,-5)

Step-by-step explanation:

The second pit stop was 0.327 seconds faster than the first pit stop which is the difference between both time

Subtraction is a mathematical operation that deducts the right-hand operand from the left-hand operand.

for example 4 -2 = 2

We have been given that during a race the first pit stop took 8.352 seconds and the second pit stop took 8.025 seconds.

To determine how much faster the second pit stop.

We need to calculate the difference between the first pit stop and the second pit stop of time.

the difference = Time of first pit stop - Time of second pit stop

the difference = 8.352 - 8.025

the difference = 0.327 second

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Answer:

length times witdth times height

Answer:

\(\sf slope: \dfrac{5}{4}\)

\(\sf y-intercept: 0\)

explanation:

comparing with the formula: y = mx + b  

Here the input equation: y = 5/4 x + 0

\(\hookrightarrow\) m = 5/4 and b = 0

Answer:

Answer:

\(f(x) = 2x + 1 \\ g(x) = {x}^{2} - 7 \\ (f + g)(x) = f(x) + g(x) \\ (f + g)(x) = (2x + 1) + ( {x}^{2} - 7) \\ (f + g)(x) = 2x + 1 + {x}^{2} - 7 \\ \boxed{ (f + g)(x) = {x}^{2} + 2x - 6}\)

Answer:

Step-by-step explanation:

Dont know need help

The amount of money he will be able to withdraw after 10 years after his last deposit is $926,400.

= $96,000

A = P(1 + r/n)^nt

= $96,000( 1 + 0.24/2)^(2×10)

= 96,000 (1 + 0.12)^20

= 96,000(1.12)^20

= 96,000(9.65)

= $926,400

Therefore, the amount of money he will be able to withdraw after 10 years after his last deposit is $926,400

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Answer:

The y-interept is 3 and the slope is -2.

Step-by-step explanation:

The y-intercept is always the "b" in y=mx+b

Answer:

Slope:  − 2

y-intercept:  ( 0 , 3 )

Step-by-step explanation:

The distance and time are not proportional and it is not uniform speed or velocity

When an object travels an equal amount of distance in an equal amount of time then it is moving with a uniform speed. It is a scalar quantity. Its unit is m s - 1 . For example, a truck moving on a highway covers equal distances in equal time intervals regardless of the direction of motion of the truck.

In the table above,

The interval of time between 6 and 8 is 2 and the

interval of time between 8and 12 is 4. Though the interval in time are equal but the distances are not equal. This means that the speed between 8 and 12 is higher to the speed it uses between 6 and 8

speed = distance/time

= 2/5 = 0.4km/min

speed = distance/time

= 4/5 = 0.8km/min

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Answer:

72yd2

Step-by-step explanation:

making figure into 2

1st figure

= 6×5

= 30yd^2

2nd figure

= 14×3

= 42yd^2

Area of the full figure

= (30+42)yd^2

= 72yd^2

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A product that is less than 1 3/5 is 1.4 and one that is greater than 1 3/5 is 1.8 or 2.

Let's simplify the fraction given to better understand it, for this, let's use division:

1 + 3/5

1 + 0.6 = 1.6

This means that the fraction given is equivalent to 1.6.

Now, based on this information, here are some examples of values that are less and more than 1 and 3/5.

More than the fraction: 1.8, 2, 2.5

Less than the fraction: 1.4, 1.5, 1.2

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After the conversion of $500 in japanese yen Ben will have 61,650 yen.

According to the question.

The amount of money in US dollars Ben wishes to convert in Japanese yen is $500.

Also, it is given that

$1 = 123.3yen

Therefore,

The number of yen Ben have after the conversion of dollars in yen

= 500 × 123.3

= 61,650

Hence, after the conversion of $500 in japanese yen Ben will have 61,650 yen.

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