Firslty, we need to find the empirical formula. Assuming the eprcentages are in mass, we first need to to divide each by the atomic weight of the corresponding atom to find the number of moles correspondent of the percentages.
We can use either the percentage or the decimal form, so let's use the decimal:
\(\begin{gathered} P\colon27.87\%=0.2787 \\ S\colon72.13\%=0.7213 \end{gathered}\)The atomic masses are:
\(\begin{gathered} M_P=30.973762g/mol \\ M_S=32.065g/mol \end{gathered}\)So, making the division, we have:
\(\begin{gathered} P\colon\frac{0.2787}{30.973762}=0.008997938\ldots \\ S\colon\frac{0.7213}{32.065}=0.022494932\ldots. \end{gathered}\)Now, we divide one by the other. Since has a bigger number, we can divide it by the P to get the ratio S to P:
\(\begin{gathered} S\colon P \\ \frac{0.022494932\ldots}{0.008997938\ldots}=2.500009599\ldots\approx2.5=\frac{5}{2} \end{gathered}\)This means that for each 5 S we have 2 P, so the empirical formula is:
\(P_2S_5\)Now, the molar mass of this empirical formula is:
\(M_{P_2S_5}=(2\cdot30.973762+5\cdot32.065)g/mol=222.272524g/mol\)To see how many of the empirical formula there are in each of the compound, we divide the molar mass of the compound by the molar mass of its empirical formula:
\(\frac{444.56g/mol}{222.272524g/mol}=2.000067\ldots\approx2\)So, the actual compound has twice the amount of atoms compared to the empirical formula, so its molecular formula is:
\(\begin{gathered} (P_2S_5)_2 \\ P_4S_{10} \end{gathered}\)Help me in this question!!!
Answer:
d. End product is that product with a ketone and carboxylic acid.
Explanation:
\({ \sf{NaBH_{4} : }}\)
Sodium borohydride is a reducing agent, it reduces the ketone to a primary alcohol.
\({ \sf{H _{2} O \: and \: H {}^{ + } }}\)
Then acidified water is an oxidising mixture which reverses the reduction reaction.
Explanation:
Option D is your answer
Hope it helps
starting with toluene which sequence of reactions below works best to prepare the folowing cyclohexadiene compound
The toluene which is sequence of reactions below the works best to prepare the following cyclohexadiene compound is given as follows :
NBS , heat NaOCH₃ Na, NH₃
Toluene ------------------> -----------------> ------------>
CCl₄ CH₃OH CH₃OH
The toluene is the substituted aromatic hydrocarbon. the cyclohexadiene is used as the starting material for the synthesis of the natural complex products. the cyclohexadiene can be formed by the toluene . the synthesis which is the best to prepare the cyclohexadiene from the compound that is toluene is given as follows :
NBS , heat NaOCH₃ Na, NH₃
Toluene ------------------> -----------------> ------------>
CCl₄ CH₃OH CH₃OH
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pls answer asap this is due in 15 mins!!
Answer:
gelatin and cornstarch
Explanation:
when looking at the data show you can infer the correct answer. hope this helps!
Answer:
Corn Starch and Gelatin
Explanation:
They both give the same as unknown
The volume of a constant amount of gas at a constant temperature is increased from 3.4L to 4.0L. What is its pressure if its original was 3.0atm?
PLS HELP!! thank u
The final pressure of the gas, when its volume is increased from 3.4 L to 4.0 L at a constant temperature, is approximately 2.55 atm.
To determine the final pressure of a gas when its volume is changed while its amount and temperature remain constant, we can use Boyle's law. Boyle's law states that the pressure of a gas is inversely proportional to its volume at constant temperature.
Mathematically, Boyle's law can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure
V2 = Final volume
In this case, we are given:
P1 = 3.0 atm
V1 = 3.4 L
V2 = 4.0 L
We need to find P2, the final pressure.
Rearranging the formula, we have:
P2 = (P1 * V1) / V2
Substituting the values we have:
P2 = (3.0 atm * 3.4 L) / 4.0 L
P2 = 10.2 atm / 4.0 L
Calculating P2:
P2 = 2.55 atm
Therefore, the final pressure of the gas, when its volume is increased from 3.4 L to 4.0 L at a constant temperature, is approximately 2.55 atm.
Boyle's law demonstrates the inverse relationship between pressure and volume for a gas at a constant temperature. As the volume increases, the pressure decreases, and vice versa, as long as the amount and temperature of the gas remain constant.
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Determine whether the following five molecules are polar or nonpolar and explain your answer:
a) Beryllium chloride b) Hydrogen sulphide c) Sulphur trioxide d) Water e) Trichloromethane
The following are categorized into polar or nonpolar molecules:
a) Beryllium chloride - nonpolar b) Hydrogen sulphide - polar c) Sulphur trioxide - nonpolar d) Water - polar e) Trichloromethane - polar How to determine polar or nonpolar?a) Beryllium chloride (BeCl₂) is a nonpolar molecule. The Be-Cl bond is polar due to the electronegativity difference between beryllium and chlorine, but the molecule is linear with the two polar bonds pointing in opposite directions, resulting in a net dipole moment of zero.
b) Hydrogen sulphide (H₂S) is a polar molecule. The H-S bond is polar due to the electronegativity difference between hydrogen and sulfur, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.
c) Sulphur trioxide (SO₃) is a nonpolar molecule. The S-O bonds are polar due to the electronegativity difference between sulfur and oxygen, but the molecule is trigonal planar with the three polar bonds pointing in different directions, resulting in a net dipole moment of zero.
d) Water (H₂O) is a polar molecule. The H-O bond is polar due to the electronegativity difference between hydrogen and oxygen, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.
e) Trichloromethane (CHCl₃) is a polar molecule. The C-Cl bonds are polar due to the electronegativity difference between carbon and chlorine, and the molecule has a tetrahedral shape, resulting in a net dipole moment that is not zero.
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A 25 ml solution of 0.5 M NaOH is titrated until neutralized into a 50 ml sample of HCl?
The concentration of the acid is \(0.25 M\).
Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a standardized solution of known concentration.
The titration formula can be given by,
(Volume of the Base) \(\times\) (Normality of the Base) = (Volume of the Acid) \(\times\) (Normality of the Acid)
\(\Rightarrow V_1N_1=V_2N_2\)
Given, the volume of the base (\(NaOH\)), \(V_1 =25 ml\).
The concentration of the base (\(NaOH\)), \(M_1=0.5 M\).
The equivalence of the base (\(NaOH\)) is \(1\).
Hence, the normality of the base (\(NaOH\)), \(N_1=\frac{0.5}{1}N=0.5N\).
Given, the volume of the acid (\(HCl\)), \(V_2 =50 ml\).
Let us assume that the normality of the acid (\(HCl\)) \(N_2\).
Substitute the values in the given formula of titration.
\((25\times0.5)=(50 \times N_2)\\\Rightarrow 12.5=50N_2\\\Rightarrow N_2=\frac{12.5}{50} N\\\Rightarrow N_2=0.25 N\)
Hence, the normality of the acid (\(HCl\)), \(N_2=0.25 N\).
The equivalence of the acid (\(HCl\)) is \(1\).
Therefore, the concentration of the acid, \(M_1=\frac{0.25}{1}=0.25 M\).
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What is the coefficient for sodium chloride when this equation is balanced?
Answer:
To resolve this, we need to place the coefficient “2” in front of the sodium in the reactant, to give the equation shown below. 2 Na (s) + Cl 2 (g) → 2 NaCl (s) In this equation, there are two sodiums in the reactants, two sodiums in the products, two chlorines in the reactants and two chlorines in the products; the equation is now balanced.
Explanation:
following this list of common polyatomic ions what would be the charge for aluminum nitrate?
Nitrate NO3
Phosphate PO43,
Sulfate SO4 -2
acetate C2H3O2-1
Ammonium NH4.
Chromate CrO4-2
Carbonate C03-2
Dichromate CrO7-2
Permanganate MnO4-1
What would be the correct answer for Aluminum nitrate
Answer:
Nitrate NO3
here's your answer, hope it helps you
which of the following spheres is likely to represent a metal atom? WHich
Answer:
Metals lose electrons when reacting with nonmetals, so the red sphere represents a metal.
What Are the Answers.
Answer:
Yes
Explanation:
it is
in a land ecosytem , some organisms only live in the soil under rocks logs or plants . What would be a resonable prediction about how theses organisms would be affected if humans removed the coverings .
Answer:
The number of these organisms in the soil would decrease.
Explanation:
volume reading
final: 33.5 mL
start: 12.3 mL
Total Volume: 21.2 mL
What is the Molarity of vinegar?
Based off the information provided
To calculate the molarity of vinegar, we need to know the moles of acetic acid (the main component of vinegar) and the volume of vinegar used.
The change in volume during the titration is:
Change in volume = Final volume - Initial volume
= 33.5 mL - 12.3 mL
= 21.2 mL
Assuming that the density of vinegar is approximately 1 g/mL, we can convert the change in volume to grams:
Change in volume (mL) × Density (g/mL) = Mass (g)
21.2 mL × 1 g/mL = 21.2 g
Next, we need to convert the mass of acetic acid to moles. The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol:
Moles = Mass (g) / Molar mass (g/mol)
= 21.2 g / 60.05 g/mol
≈ 0.353 mol
Finally, we calculate the molarity of vinegar using the moles and total volume:
Molarity = Moles / Total volume (L)
= 0.353 mol / 0.0212 L
≈ 16.65 M
Therefore, based on the information provided, the molarity of vinegar is approximately 16.65 M.
The ratio molecular mass of gas A and B is 1.25 calculate the ratio of rate of diffusion of the gases
Answer:
i will tell your teacher that u uding online cheats to answer yout homeworks hhaahaha
Explanation:
good luck brooo hahahha
1. A gas with a volume of 4.0 L at a pressure of 2 08 atm is allowed to expand to a volume of 12.0 L. What is the pressure in atm in the container if the temperature remains constant. Please show work (including the equation you used). --------- 2. The volume of a gas is 200 mL at 350.0 kPa pressure. What will the volume be when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant. Please show all work for full credit. Please show work (including the equation you used).
Explanation
To solve this, we consider Boyle's Law:
It relates gas pressure to volume while keeping other parameters such as temperature and amount of substance constant.
Equation we use here is p1 x V1 = p2 x V2 (1)
(p for pressure and V for volume)
p1 = 2.08 atm
V1 = 4.0 L
If the gas expands, the pressure will be lower than 2.08 atm.
p2 = unknown
V2 = 12.0 L
From (1) we clear p2:
=> p1 x V1/V2 = p2
=> 2.08 atm x 4.0 L/12.0 L = p2
=>0.69 atm = p2
Answer: p2 = 0.69 atm
the metal thorium becomes superconducting at temperatures below 1.62 K. Calculate the temperature at which thorium becomes superconducting in degrees Celsius. Be sure your answer has the correct number of sig fig
The metal thorium becomes superconducting below the temperature of 1.62 K. Then , the temperature on which the metal become super conducting is - 271.38 °C.
What is superconducting ?Superconducting is the property of a certain materials that they conduct electricity when cooled below a critical temperature. The metal thorium is a type-1 super conductor.
Given the critical temperature of thorium = 1.62 K.
We know that the temperature in degree Celsius is converted as follows:
T°C + 273 = T K.
Hence, the critical temperature in kelvin scale is:
1.62 K -273 = - 271.38 °C.
Therefore, the temperature at which thorium is superconducting is - 271.38 °C.
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Thermal Energy and Kinetic Molecular Theory Quick Check
The Kinetic Molecular Theory is a scientific model that states atoms in a compound are found in a constant state of motion (movement).
What is the Kinetic Molecular Theory?The Kinetic Molecular Theory is a scientific model that states atoms in a compound are found in a constant state of motion (movement).
Thermal energy refers to the movement of particles and therefore both concepts are interrelated.
In conclusion, the Kinetic Molecular Theory is a scientific model that states atoms in a compound are found in a constant state of motion (movement).
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SOS TESTING:
Which change of state is exothermic?
Group of answer choices
melting
sublimation
condensation
vaporization
Answer:
Condensation
Explanation:
An exothermic process is one in which heat is lost. Condensation is a change of state from gas to liquid. Thus is loses heat.
HOPE THIS HELPED
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la tierra nuestro planeta es el único del sistema solar que sabe que mantiene vida: vida que es increíblemente diversa,
The calcium and magnesium in a urine sample were precipitated as oxalates. A mixed precipitate of calcium oxalate (CaC2O4) and magnesium oxalate (MgC2O4) resulted and was analysed by gravimetry. The formed precipitate mixture was heated to form calcium carbonate (CaCO3) and magnesium oxide (MgO) with a total mass of 0.0433 g. The solid precipitate mixture was ignited to form CaO and MgO, the resulting solid after ignition weighed 0.0285 g. What was the mass of calcium in the original sample? All answers should be reported with the correct significant figures
The mass of calcium in the original urine sample would be 0.0140 g.
Stoichiometric problemFirst, we need to find the masses of calcium and magnesium oxalates in the original sample. Let x be the mass of calcium oxalate and y be the mass of magnesium oxalate. Then we have:
x + y = mass of the mixed oxalate precipitate
Next, we need to use the information given to find the mass of calcium in the original sample. The mass of calcium oxide formed after ignition is equal to the mass of calcium oxalate in the original sample. We can calculate the mass of calcium oxide using the mass of calcium carbonate formed and the molar mass ratio of calcium carbonate to calcium oxide.
The balanced chemical equations for the reactions are:
CaC2O4 -> CaCO3 + CO2
CaCO3 -> CaO + CO2
The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CaO is 56.08 g/mol.
From the given information, we have:
0.0433 g = (x + y)(100.09 g/mol + 80.15 g/mol) / (128.10 g/mol + 80.15 g/mol)
0.0285 g = x(56.08 g/mol) + y(40.31 g/mol)
Solving these equations simultaneously, we get:
x = 0.0140 g
y = 0.0053 g
Therefore, the mass of calcium in the original sample (which is equal to the mass of calcium oxide formed after ignition) is:
0.0140 g
So the mass of calcium in the original sample is 0.0140 g.
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how many atoms of argon occupy 30.0L
Predict the chemical shifts for the signals in the proton NMR spectrum of each of the following compounds.
The proximity of unsaturated groups (C=C, C=O, aromatic) and electronegative atoms (O, N, halogen) has an impact on the proton NMR chemical shift. Electronegative groups shift to the left (down field; ppm rise).
What does NMR spectroscopy's chemical shift entail?The chemical shift in nuclear magnetic resonance (NMR) spectroscopy refers to the atomic nucleus' resonant frequency in relation to a standard in a magnetic field. The location and quantity of chemical changes frequently serve as diagnostic indicators of molecular structure.
You take into account the chemically non-equivalent proton(s) one at a time while making chemical shift predictions. Find the origin of each proton or proton pair that is not chemically comparable. Whether the proton(s) is/are linked to a methyl, methene, or methine determines the beginning point.
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Use the following key to classify each of the elements below in its elemental form:
A. Discrete atoms ...
B. Molecules ...
C. Metallic lattice
D. Extended, three-dimensional network
1. Argon
2. Bromine
3. Nitrogen
4. Fluorine
Answer:
Discrete atoms
Argon
Molecules
Bromine
Nitrogen
Fluorine
Explanation:
The existence of substances in the elemental form depends on the nature of the substance.
Argon is a noble gas hence it seldom participates in chemical combination therefore it exists as discrete molecules in elemental form.
Bromine, fluorine and nitrogen all exist as diatomic gases because they combine readily with each other to form elemental molecules. An elemental molecule is a molecule composed of the atoms of the same element.
20) If you have 4.450 x 1025 individual formaldehyde (CH2O = 30.03 g/mol) molecules, and their density is 0.8150 g/mL., then how many mL of space do they occupy? ________ mL
Answer
2722.81 mL
Explanation
Given:
Density = 0.8150 g/mL
Molecular mass CH2O = 30.03 g/mol
Number of formaldehyde, CH2O molecules = 4.450 x 10²⁵ moelcules
You need to first convert the number of molecules of formaldehyde to moles.
To do this, divide the the number of molecules by Avogardro's number
\(4.450\times10^{25}\text{ molecules }=\frac{4.450\times10^{25}}{6.022\times10^{23}}moles=73.89571571\text{ moles}\)Since molecular mass of 1 mole of CH2O = 30.03 g
Then, the mass of 73.89571571 moles will be
\(30.03\times73.89571571=2219.088343\text{ g}\)Now we can calculate the mL of space (volume) occupied by the molecules using the formula below
\(\text{Volume }=\frac{Mass}{Density}\)\(\text{Volume }=\frac{2219.088343\text{ g}}{0.8150\text{ g/mL}}=2722.81\text{ mL}\)2722.81 mL mL of space were occuppied by the formaldehyde.
a student has a 1 L solution of 2 M HCL and wants to increase the HCL concentration to 3 M
The student needs to add approximately 83.3 mL of 12 M HCl solution to the existing 1 L of 2 M HCl solution to increase the concentration to 3 M. It is important to handle concentrated acids with caution and follow proper safety procedures.
To increase the concentration of a 1 L solution of 2 M HCl to 3 M, the student needs to calculate the volume of concentrated HCl needed and add it to the existing solution. Here's how the calculation can be done:
Given:
Initial concentration of HCl solution = 2 M
Final concentration desired = 3 M
Initial volume of HCl solution = 1 L
Step 1: Calculate the moles of HCl in the initial solution.
Moles of HCl = Initial concentration × Initial volume = 2 M × 1 L = 2 moles
Step 2: Calculate the moles of HCl needed for the desired concentration.
Moles of HCl needed = Final concentration × Final volume = 3 M × 1 L = 3 moles
Step 3: Calculate the moles of HCl to be added.
Moles of HCl to be added = Moles needed - Moles present = 3 moles - 2 moles = 1 mole
Step 4: Convert the moles of HCl to the required volume of concentrated HCl.
To calculate the volume, we need to know the concentration of the concentrated HCl solution. Assuming it is 12 M, we can use the following formula:
Volume of concentrated HCl = Moles of HCl to be added / Concentration of concentrated HCl
Volume of concentrated HCl = 1 mole / 12 M = 0.0833 L or 83.3 mL
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What does water vapor do to the density of the air
Answer:
The amount of water vapor in air influence density. Water vapor is relatively light compared to diatomic Oxygen and diatomic Nitrogen - the dominant components in air. When vapor content increases in moist air the amount of Oxygen and Nitrogen are decreased per unit volume and the density of the mix decreases since the mass is decreasing.
Explanation:
6.(01.05 LC) Which states of matter change shape when moved?(2 points) Gases and solids Liquids and gases Liquids, solids, and gases Solids and liquids
Answer:Gases and solids , Solids and liquids
Explanation:
A solid has a definite shape while liquids and gases take the shape of the container in which they are found .
Hence when a substance changes it's state from gas to solid or solid to liquid, it's shape automatically changes as explained above.
Modeling Nuclear changes
Answer:
can someone please do this and put the answers below !!!!
Explanation:
Why KHPo4 ignore effective as a buffer but kh2po4 is not
KH2PO4 is a more suitable choice as a buffer because it has a greater buffering capacity due to the presence of the weak acid and its conjugate base.
KHPo4 is not considered an effective buffer compared to KH2PO4 due to its limited buffering capacity. The effectiveness of a buffer is determined by the concentration and dissociation properties of its conjugate acid-base pair.
KH2PO4 is a salt composed of the weak acid H2PO4- and its conjugate base HPO4^2-. In an aqueous solution, KH2PO4 can dissociate to release H+ ions from the H2PO4- component, which acts as a weak acid, and the HPO4^2- component can accept H+ ions, acting as a weak base. This allows KH2PO4 to effectively resist changes in pH when small amounts of acid or base are added to the solution.
On the other hand, KHPo4 consists of the strong acid H3PO4 and the weak base HPO4^2-. H3PO4 fully dissociates in water, providing a large concentration of H+ ions, making it difficult for the HPO4^2- to effectively act as a base and maintain pH stability.
Therefore, KH2PO4 is a more suitable choice as a buffer because it has a greater buffering capacity due to the presence of the weak acid and its conjugate base.
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How much would 400. jelly beans weigh in grams?
Answer:
453 or 453.592
Explanation:
400 jellybeans are about a pound and a pound is 453.592 grams
What is the concentration of potassium ions in a solution obtained by mixing 480. mL of 0.410 M potassium hydroxide(aq) with 440. mL of 0.290 M potassium sulfate(aq). Enter your answer in decimal notation rounded to the appropriate number of significant figures.
The concentration of potassium ions, K⁺ in the solution obtained by mixing 480 mL of 0.410 M KOH with 440 mL of 0.290 M K₂SO₄ is 0.491 M
We'll begin by calculating the number of mole of potassium ion, K⁺ in each solution.
For KOH:Volume = 480 mL = 480 / 1000 = 0.48 L
Molarity = 0.410 M
Mole of KOH =?Mole = Molarity x Volume
Mole of KOH = 0.410 × 0.48
Mole of KOH = 0.1968 moleKOH(aq) —> K⁺(aq) + OH¯(aq)
From the balanced equation above,
1 mole of KOH contains 1 mole of K⁺
Therefore,
0.1968 mole of KOH will also contain 0.1968 mole of K⁺
Thus, 0.1968 mole of K⁺ is present in 480 mL of 0.410 M KOH
For K₂SO₄:Volume = 440 mL = 440 / 1000 = 0.44 L
Molarity = 0.290 M
Mole of K₂SO₄ =?Mole = Molarity x Volume
Mole of K₂SO₄ = 0.290 × 0.44
Mole of K₂SO₄ = 0.1276 moleK₂SO₄(aq) —> 2K⁺(aq) + SO₄²¯(aq)
From the balanced equation above,
1 mole of K₂SO₄ contains 2 moles of K⁺
Therefore,
0.1276 mole of K₂SO₄ will contain = 0.1276 × 2 = 0.2552 mole of K⁺
Thus, 0.2552 mole of K⁺ is present in 440 mL of 0.290 M K₂SO₄
Next, we shall determine the total mole of K⁺ in the resulting solution.Mole of K⁺ in KOH = 0.1968 mole
Mole of K⁺ in K₂SO₄ = 0.2552 mole
Total mole = 0.1968 + 0.2552
Total mole = 0.452 moleNext, we shall determine the total volume of the resulting solutionVolume of KOH = 0.48 L
Volume of K₂SO₄ = 0.44 L
Total volume = 0.48 + 0.44
Total volume = 0.92 LFinally, we shall determine the molarity of K⁺ in the resulting solutionTotal mole = 0.452 mole
Total volume = 0.92 L
Molarity of K⁺ =?Molarity = mole / Volume
Molarity of K⁺ = 0.452 / 0.92
Molarity of K⁺ = 0.491 MTherefore, the molarity of potassium ion, K⁺ in the resulting solution is 0.491 M
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