Answer:
Given expression:
\(\dfrac{14a^4b^6c^{-10}}{8a^{-2}b^3c^{-5}}\)
Separate the variables:
\(\implies \dfrac{14}{8} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}\)
Reduce the first fraction:
\(\implies \dfrac{7}{4} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}\)
\(\textsf{Apply Division Property of Exponents rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:\)
\(\implies \dfrac{7}{4} \cdot a^{4-(-2)} \cdot b^{6-3} \cdot c^{-10-(-5)}\)
\(\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot c^{-5}\)
\(\textsf{Apply Negative Property of Exponents rule} \quad a^{-n}=\dfrac{1}{a^n}\)
\(\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot \dfrac{1}{c^5}\)
Therefore:
\(\implies \dfrac{7a^6b^3}{4c^5}\)
A jet aircraft was flying around the globe at a fixed distance of 3,966 miles from the Earth's center. If the jet keeps a constant speed of 2,000 miles per hour, how many hours will it take the jet to fly 1. 25 times around the world? Round your answer to the nearest tenth
It would take approximately 15.7 hours for the jet to fly 1.25 times around the Earth at a fixed distance of 3,966 miles from the Earth's center at a constant speed of 2,000 miles per hour.
To determine the number of hours it would take for the jet aircraft to fly 1.25 times around the Earth at a fixed distance of 3,966 miles from the Earth's center at a constant speed of 2,000 miles per hour,
we can use the formula for circumference as follows:
Circumference of the circle = 2πr
where r = 3,966 miles
Since the jet is flying around the Earth 1.25 times,
the distance it will cover would be 1.25 times the circumference of the Earth.
Distance covered by the jet = 1.25 × 2π × 3,966 miles
= 31,332.5 miles
Now, we can find the time it would take the jet to fly this distance by using the formula for speed as follows:
Speed = Distance / Time
we get:Time = Distance / Speed
Time = 31,332.5 miles / 2,000 miles per hour
= 15.67 hours (rounded to the nearest tenth)
Therefore, it would take approximately 15.7 hours.
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how would you express b⃗ b→b vec using unit vectors? express your answers in terms of the unit vectors x^x^x unit and y^y^y unit . use the button under the menu in the answer box to create unit vect
To express vector b→ using unit vectors, we can break down vector b→ into its components along the x-axis and y-axis.
Let's assume that vector b→ has a magnitude of b and an angle θ with respect to the positive x-axis.
The x-component of vector b→ can be found using the formula:
bₓ = b * cos(θ)
The y-component of vector b→ can be found using the formula:
by = b * sin(θ)
Now, we can express vector b→ using unit vectors:
b→ = bₓ * x^ + by * y^
where x^ and y^ are the unit vectors along the x-axis and y-axis, respectively.
For example, if the x-component of vector b→ is 3 units and the y-component is 4 units, the vector b→ can be expressed as:
b→ = 3 * x^ + 4 * y^
Remember that the unit vectors x^ and y^ have magnitudes of 1 and point in the positive x and y directions, respectively.
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The vector b can be expressed using unit vectors \(\widehat x\) and \(\widehat y\) by decomposing it into its x-axis and y-axis components, denoted as \(b_x\) and \(b_y\) respectively. This representation allows us to express b as the linear combination \(b_x \widehat x + b_y \widehat y\), providing a concise and clear representation of the vector.
To express the vector b using unit vectors, we can decompose b into its components along the x-axis and y-axis. Let's call the component along the x-axis as \(b_x\) and the component along the y-axis as \(b_y\).
The unit vector along the x-axis is denoted as \(\widehat x\), and the unit vector along the y-axis is denoted as \(\widehat y\).
Expressing b in terms of unit vectors, we have:
\(b = b_x \widehat x + b_y \widehat y\)
This equation represents the vector b as a linear combination of the unit vectors \(\widehat x\) and \(\widehat y\), with the coefficients \(b_x\) and \(b_y\) representing the magnitudes of b along the x-axis and y-axis, respectively.
Therefore, the vector b can be expressed using unit vectors \(\widehat x\) and \(\widehat y\) by decomposing it into its x-axis and y-axis components, denoted as \(b_x\) and \(b_y\) respectively. This representation allows us to express b as the linear combination \(b_x \widehat x + b_y \widehat y\), providing a concise and clear representation of the vector.
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Complete the two-column proof by providing the missing statements or reasons.
Given: ABCD is rhombus
Prove: angle 1 = angle 2
Statement Reason
1. 1. Given
2. 2.
3. ; 3. Diagonals of a parallelogram bisect each other.
4. 4.
5. 5.
The diagonals of a rhombus bisect each other perpendicularly, making the
angles formed by the intersecting diagonals to be 90°.
Correct Response:
∠1 and ∠2 are corresponding angles of congruent triangles ΔAOD and ΔAOB, therefore, ∠1 = ∠2Method used to prove that ∠1 = ∠2Given:
The quadrilateral represented by ABCD = A rhombus
Required:
To prove that ∠1 = ∠2
Solution:
From the diagram, we have;
The measure of ∠AOD = ∠1, the measure of ∠AOB = ∠2
The two column proof is presented as follows;
Statement \({}\) Reasons
1. ABCD is a rhombus \({}\) 1. Given
2. AB = BC = CD = DA \({}\) 2. Definition
3. AO = OC, BO = OD\({}\) 3. Diagonals of a rhombus bisect each other
4. ΔAOD ≅ ΔAOB \({}\) 4. SSS congruency postulate
5. ∠1 ≅ ∠2 \({}\) 5. CPCTC
6. ∠1 = ∠2 \({}\) 6. Definition of congruency
SSS (Side-Side-Side) congruency postulate states that if the three sides of
one triangle are congruent to the three sides of another triangle, the two
triangles are congruent.
CPCTC is an acronym for Corresponding Parts of Congruent Triangles are Congruent.
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Answer:
1. Given.
2. Definition.
3. Diagonals of a rhombus bisect each other.
4. SSS congruency postulate.
5. CPCTC.
6. Definition of congruency.
A ______ is a number formed by multiplying ten by a number.
Answer:
power of ten
Step-by-step explanation:
The perimeter of a
rectangular swimming pool is 84
meters. The width of the pool is
three fourths the length. What
are the length and width of the
pool?
Answer:
24
Step-by-step explanation:
let \(\ell=length\)
then \(width=\frac{3}{4}\ell\)
since the perimeter is 84, then
\(2(length+width)=84\\ 2(\ell+\frac{3}{4}\ell)=84\\ 2(\frac{4}{4}\ell+\frac{3}{4}\ell)=84\\2(\frac{7}{4}\ell)=84\\ \frac{7}{2}\ell=84\\ \ell=\frac{84\times 2}{7}\\ \ell=24\)
Write down the equation for the following
i,Grade 7 students received a total of 88 books from world vision.they received 63 books on Monday and g books on Tuesday
ii,Solve the equation above
I’m so confused please help
Answer:
umm im not smart sorry
Step-by-step explanation:
add 4312base5 3444base5 qunary number please add qunary
9514 1404 393
Answer:
13311₅
Step-by-step explanation:
Each column gets the sum mod 5, with a carry to the next column of the quotient of the sum and 5. For example, in the units column, 2+4 = 11₅, so 1 is written in the units column as the sum, and 1 is carried to the 5s column (next one to the left).
Continuing in this fashion gives the sum 13311₅.
__
If you recognize that 3444₅ = 4000₅ -1, you can subtract 1 from 4312₅ and add 4 in the 5³ place (4th column from the right). That gives you ...
4311₅ +4000₅ = 13311₅
_____
The base-5 addition table is attached.
What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0?
(–12, –2)
(–6, –1)
(6, 1)
(12, 2)
Answer:
(6,1)
Step-by-step explanation:
Just look for the terms with x and y in them. Divide their coefficients by two, and multiply by -1. And then put them in an ordered pair.
So in this case, -12x --> 6 and -2y --> 1
Obviously the more orthodox way would be to actually complete the square, but I'm lazy, this way is faster, and since this seems to be multiple choice, as long as you have the correct answer, it shouldn't matter.
The required centre will be at (6,1)
Equation of a circleThe standard equation of circle is expressed as:
x^2+y^2+2gx+2fy+c = 0
where (-g, -f) is the centre of the circle
Given the equation x^2 + y^2 – 12x – 2y + 12 = 0
Compare with the general to have;
2gx = -12x
g = -6
2fy = -2y
y = -1
Since centre is at (-g, -f), hence the required centre will be at (6,1)
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0.796 divided by 9.95
Answer:
0.08
Step-by-step explanation:
Which expressions are equilvalent to 3^x
If Miguel types 40 words per minute and he types for 30 minutes how many words will he have typed total? *
Answer:
1200 words
Step-by-step explanation:
If he types 40 words a minute, you have to multiply that by thirty because he typed 40 words 30 timers. 40 x 30=1200
Answer:
120 words
Step-by-step explanation:
40 words/m × 30 minutes = 120 words
Tell whether the linear equation is in slope-intercept form, point-slope form, or standard form.
2x+4y=12
Answer:
Standard form
Step-by-step explanation:
In this question, we have to figure out what form the equation is.
Our options are: point-slope form, slope-intercept form, and standard form.
Our forms are structed as followed below:
Point-slope form: y - y1 = m(x - x1)
Slope-intercept form: y= mx + b
Standard form: Ax + By = C
Now, we just need to find out which form the equation resembles.
You would notice that the linear equation "2x + 4y = 12" follows the structure of the standard form.
Side-by-side comparison:
2x + 4y = 12
Ax + By = C
Therefore, your answer would be standard form.
what digit is in the
we have the number
5,937,852
this number can be written as
5*(1,000,000)+9*(100,000)+3*(10,000)+7*(1,000)+8*(100)+5*(10)+2*(1)
therefore
the digit 7 means ------> 7*1,000=7,000
7 thousandsIn many parades, flowers are used to decorate the floats. The table below shows the number of flowers used in each row of a parade float.
1
54
2
58
3
62
4
66
Which equation best describes these data?
Answer: C. n = 4r + 50
Step-by-step explanation:
The equation is in the form: y =mx + c
y is the number of flowers used.
x is the row number.
Solving for m. Pick any two points. (1, 54) and (2, 58)
m = (Y₂ - Y₁) / (X₂ - X₁)
= (58 - 54) / (2 - 1)
= 4
Solving for c. Use a point to fill up the formula and find c; (1, 54)
y = mx + c
54 = 4 * 1 + c
c = 54 - 4
c = 50
Formula will therefore be;
y = 4x + 50
or;
n = 4r + 50
The gold trophy has 27 racers, she will 12 racers on the racetrack that runs.
How many racers did she have runs?
She will have run a total of 2.25 racers in 27 racers
How to determine the number of racers?From the question, we have the following parameters that can be used in our solution:
Total number of racers = 27 racers
Number of racers in a run = 12 racers
From the above parameter, we can calculate the total number of racers using the following equation
The total number of racers is calculated as
Total number of racers in the run = Total number of racers/Number of racers in a run
Substitute the known values in the above equation
So, we have the following equation
Total number of racers in the run = 27/12
Evaluate the quotient
Total number of racers in the run = 2.25
Hence, the total number of racers in the run is 2.25 racers
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Please help me! thank you
Suppose an object is thrown upward with initial velocity of 48 feet per second from a high of 120 feet. The height of the object t seconds after it is thrown is given by h(t)=-16t^2+48t+120. Find the average velocity from t=2 to t=4.
Type your answer as a number with no units.
The average velocity from t = 2s to t = 4s would be - 48 ft/s.
What are algebraic expressions?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.
Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.
Given is that an object is thrown upward with initial velocity of 48 feet per second from a high of 120 feet. The height of the object t seconds after it is thrown is given by h(t) = - 16t² + 48t + 120.
Average velocity
Average rate of change of velocity with time is called average velocity. Mathematically -
v{avg.} = Δx/Δt .... Eq { 1 }
Δx = x(4) - x(2)
Δx = - 16(4)² + 48(4) + 120 - {- 16(2)² + 48(2) + 120}
Δx = - 96
Δt = 4 - 2 = 2
So -
v{avg.} = Δx/Δt = -96/2 = - 48 ft/s
Therefore, the average velocity from t = 2s to t = 4s would be - 48 ft/s.
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What are the first 3 consecutive odd numbers?
The first 3 consecutive odd numbers are 1,3,5. x and x + 2 are consecutive odd numbers if x is an odd number.
Consecutive numbers are those that always appear in the same order, from smallest to largest.
For instance:
The numbers 1, 2, 3, 4, 5, 6, and so on are consecutive.
consecutive odd numbers:
Let's call the odd number "x." The subsequent term becomes "x + 4" and the next consecutive odd number becomes "x + 2."
Numbers that begin with 1, 3, 5, 7, or 9 are considered odd. 1, 3, 5, 7, 9, 11, 13, 15, and so on are examples of consecutive odd numbers.
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How would you write 1/256^-4 using a positive exponent?
a
256^4
b
-256^4
c
1/2256^8
d
256^2
The simplified value of the expression (1/256⁻⁴) is 256⁴.
What are some rules of exponents?Some common rules of exponents are
xᵃ×xᵇ = xᵃ⁺ᵇ.
xᵃ/xᵇ = xᵃ⁻ᵇ.
Addition and subtraction of exponents is only possible for same base value and when the base is different and both have the same exponent we just multiply the bases and write the exponent.
We are given an expression (1/256⁻⁴) in exponent form.
Now, we know that an exponent changes its sign when it's moved from the numerator to the denominator or from the denominator to the numerator and it should always be a positive value.
Therefore, (1/256⁻⁴) can be written as, 256⁴.
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Which expression can be used to convert 22 Australian dollars to US dollars?
Assume 1.2 Australian dollars equals 1 US dollar.
$22 AUD × StartFraction 1.2 U S D Over 1 A U D EndFraction
$22 AUD × StartFraction 1 U S D Over 1.2 A U D EndFraction
$1.20 AUD × StartFraction 1 U S D Over 1.2 A U D EndFraction
$1.20 AUD × StartFraction 1.2 A U D Over 1 A U D EndFraction
Answer:
B. 22 AUD * ($1)/(1.2 AUD)
Step-by-step explanation:
Start with the equation of the conversion.
1.2 AUD = $1
Now divide both sides by 1.2 AUD.
(1.2 AUD)/(1.2 AUD) = ($1)/(1.2 AUD)
The left side equals 1 since you have a fraction in which the numerator and denominator are equal.
1 = ($1)/(1.2 AUD)
Notice that the line above shows that the fraction on the right equals 1. Since multiplying a number by 1 does not change the number, you can multiply a number of Australian dollars by ($1)/(1.2 AUD) without changing the amount.
Now start with 22 AUD.
We multiply it by the fraction ($1)/(1.2 AUD). This will nmot change the amount of ,money since this fraction equals 1.
22 AUD * ($1)/(1.2 AUD)
The expression above will give you a number in U.S. dollars since AUD cancels out.
Answer: B. 22 AUD * ($1)/(1.2 AUD)
Answer:
B
Step-by-step explanation:
Did the quiz
given that the time consecutive customers arriving is greater than 15 seconds, find the chance that the time is greater than 24 seconds?
The probability that the time is greater than 24 seconds is e^(-24λ).
Since it is a waiting time distribution, it definitely will be an exponential distribution. Here we might either be given the value of mean or λ.
If the mean is given we can find λ by using the formula
mean = 1/λ.
Then to find the probability that the waiting time is greater than 24 seconds we will use the cumulative density function formulae
F(x) = 1 - e^(-λx)
here we will find
F(24) = 1 - e^(-24λ)
Then to find P(X>24) we will subtract 1 from F(24) to get
P(X>24) = e^(-24λ)
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In the adjoining equilateral triangle PQR , X , Y and Z are the middle points of the sides PQ , QR and RP respectively. Prove that XYZ is also an equilateral triangle.
~Thanks in advance !
Answer:
See Below
Step-by-step explanation:
Statements: Reasons:
\(1)\text{ } \Delta PQR\text{ is equilateral}\) Given
\(2)\text{ }PQ=QR=RP\) Definition of Equilateral
\(3)\text{ } X, Y, Z\text{ are the midpoints of } PQ, QR, RP\) Given
\(4)\text{ } PX=XQ\) Definition of Midpoint
\(5)PQ=PX+XQ\) Segment Addition
\(6)\text{ } PQ=2XQ\) Substitution
\(7)\text{ } QY=YR\) Definition of Midpoint
\(8)\text{ }QR=QY+YR\) Segment Addition
\(9)\text{ } QR=2QY\) Substitution
\(10)\text{ } 2XQ=2QY\) Substitution
\(11)\text{ } XQ=QY\) Division Property of Equality
\(12)\text{ } XQ=PX=QY=YR\) Transitive Property
\(13)\text{ } RZ=ZP\) Definition of Midpoint
\(14)\text{ } RP=RZ+ZP\) Segment Addition
\(15)\text{ } RP=2RZ\) Substitution
\(16)\text{ } 2XQ=2RZ\) Substitution
\(17)\text{ } XQ=RZ\) Substitution
\(18)\text{ } XQ=PX=QY=YR=RZ=ZP\) Transitive Property
\(19)\text{ } \angle Q\cong \angle R\cong \angle P\) Definition of Equilateral
\(20)\text{ } \Delta XQY\cong \Delta YRQ \cong \Delta ZPX\) SAS Congruence
\(21)\text{ } XY\cong YZ\cong ZX\) CPCTC
\(22)\text{ } \Delta XYZ\text{ is equilateral}\) Equilateral Triangle Theorem
Answer:
this is your answer. thanks, for great point
In this triangle, what is sin 30°? What is sin 60°? What is the product of sin 30° and sin 60°?
Answer:
1800
Step-by-step explanation:
60.30= 1800
can you guys help with at least one of these two? Thanks!
Answer:
1) B. -2 hours per person
2) C. 3.60 per pound
Step-by-step explanation:
1)
We can make a slope triangle connecting the points (4, 12) and (10,0)
We get -12/6, or -2 as our slope & final answer
2)
You can do x/y to find the unit rate for this one, or in this case 18/5 = 3.6
(a) Find the Fourier transform X (jw) of the signals x(t) given below: i. (t – 2) – 38(t – 3) ii. e-2t u(t) iii. e-3t+12 uſt – 4) (use the result of ii.) iv. e-2|t| cos(t) (b) Find the inverse Fourier transform r(t) of the following functions X(jw): i. e-j3w + e-jów ii. 27 8W - 2) + 210(w + 2) iii. cos(w + 4 7T )
i. The Fourier transform of (t - 2) - 38(t - 3) is [(jw)^2 + 38jw]e^(-2jw). ii. The Fourier transform of e^(-2t)u(t) is 1/(jw + 2). iii. The Fourier transform of e^(-3t+12)u(t-4) can be obtained using the result of ii. as e^(-2t)u(t-4)e^(12jw). iv. The Fourier transform of e^(-2|t|)cos(t) is [(2jw)/(w^2+4)].
i. To find the Fourier transform of (t - 2) - 38(t - 3), we can use the linearity property of the Fourier transform. The Fourier transform of (t - 2) can be found using the time-shifting property, and the Fourier transform of -38(t - 3) can be found by scaling and using the frequency-shifting property. Adding the two transforms together gives [(jw)^2 + 38jw]e^(-2jw).
ii. The function e^(-2t)u(t) is the product of the exponential function e^(-2t) and the unit step function u(t). The Fourier transform of e^(-2t) can be found using the time-shifting property as 1/(jw + 2). The Fourier transform of u(t) is 1/(jw), resulting in the Fourier transform of e^(-2t)u(t) as 1/(jw + 2).
iii. The function e^(-3t+12)u(t-4) can be rewritten as e^(-2t)u(t-4)e^(12jw) using the time-shifting property. From the result of ii., we know the Fourier transform of e^(-2t)u(t-4) is 1/(jw + 2). Multiplying this by e^(12jw) gives the Fourier transform of e^(-3t+12)u(t-4) as e^(-2t)u(t-4)e^(12jw).
iv. To find the Fourier transform of e^(-2|t|)cos(t), we can use the definition of the Fourier transform and apply the properties of the Fourier transform. By splitting the function into even and odd parts, we find that the Fourier transform is [(2jw)/(w^2+4)].
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for the given literal equation z=a/b + c/d .solve for D
An equation is formed of two equal expressions. The given literal equation z=(a/b)+(c/d) is d=cb/(zb-a).
What is an equation?An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The given literal equation z=(a/b)+(c/d) can be solved for D as,
z-(a/b) = (c/d)
(zb-a)/b = c/d
d = cb/(zb-a)
Hence, The given literal equation z=(a/b)+(c/d) is d=cb/(zb-a).
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Can someone please help me ASAP?? It’s due today!! I will give brainliest If It’s correct!!
please do part a, b, and c
The five-number summary of each distribution is shown below.
The difference of the median value of the two data sets is 1.
The difference and multiple of variation for the range are 4 and 1.444.
How to determine the five-number summary of each distribution?Based on the information provided about the first data set (Girls), the five-number summary for the given data set include the following:
Minimum (Min) = 25.
First quartile (Q₁) = 26.
Median (Med) = 30.
Third quartile (Q₃) = 31.
Maximum (Max) = 34.
For the Boys, the five-number summary include the following:
Minimum (Min) = 23.
First quartile (Q₁) = 24.
Median (Med) = 29.
Third quartile (Q₃) = 32.
Maximum (Max) = 36.
Difference in median = 30 - 29
Difference in median = 1.
Range of girls = 34 - 25 = 9
Range of boys = 36 - 23 = 13
Difference in range = 13 - 9
Difference in range = 4.
Multiple of variation for range = 13/9 = 1.444.
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(7000).03 + (x).05=830
Answer:
Sure! Let’s solve this equation step by step.
(7000).03 + (x).05=830
First, we can simplify the left side of the equation:
210 + 0.05x = 830
Next, we can subtract 210 from both sides:
0.05x = 620
Finally, we can divide both sides by 0.05 to solve for x:
x = 12400
So the solution to the equation (7000).03 + (x).05=830 is x = 12400.
A linear function has an x-intercept of 8 and a y-intercept of 4 . which of these is an equation of the linear function?
The equation of the linear function having an x-intercept of -8 and a y-intercept of 4 is y = (1/2)x + 4.
What are lines and their slopes?
We know lines have various types of equations, the general type is
Ax + By + c = 0, and the equation of a line in slope-intercept form is
y = mx + b.
Where slope = m and b = y-intercept.
the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.
Given, A linear function has an x-intercept of -8 and a y-intercept of 4.
So, The two points on the line are (- 8, 0) and (0, 4).
Now, slope(m) = (4 - 0)/(0 + 8).
slope(m) = 4/8.
slope(m) = 1/2.
As it has a y-intercept of 4 it is the value of b, In y = mx + b.
Therefore, The linear function is y = (1/2)x + 4.
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Please help me !! would appreciate
The answers that describe the quadrilateral DEFG area rectangle and parallelogram.
The correct answer choice is option A and B.
What is a quadrilateral?A quadrilateral is a parallelogram, which has opposite sides that are congruent and parallel.
Quadrilateral DEFG
if line DE || FG,
line EF // GD,
DF = EG and
diagonals DF and EG are perpendicular,
then, the quadrilateral is a parallelogram
Hence, the quadrilateral DEFG is a rectangle and parallelogram.
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