Nigel and Mia are searching for a treasure chest under water. The straight line distance between them is 100 meters.

A triangle has points Nigel, Mia, and Treasure Chest. The distance from Nigel to Mia is 100 meters. The angle between Treasure Chest, Nigel, and Mia is 65 degrees. The angle between Nigel, Mia, and Treasure Chest is 80 degrees.

Given the angles in the diagram, who is closer to the treasure chest and why?

Nigel is closer because his distance to the chest is opposite the larger angle.
Mia is closer because her distance to the chest is opposite the smaller angle.
Nigel is closer because his distance from the chest is 100 meters.
Mia is closer because her distance from the chest is 100 meters.

Answer:

try 2+2 that should work

The required number of markers does Gerald has 56 markers.

Let's represent the number of markers that Gerald has with the variable "m", and the number of pens he has with the variable "p". We can set up two equations based on the information given:

m + p = 78 (equation 1)

(m + 11) + (p + 11) = 78 (equation 2)

In equation 2, we add 11 to both the number of markers and the number of pens, since Gerald has 11 more of each. We can simplify equation 2 by combining like terms:

m + p + 22 = 78

m + p = 56 (equation 3)

Now we have two equations with two variables. We can use either substitution or elimination to solve for one of the variables. Let's use substitution and solve for "m" in terms of "p" using equation 1:

m + p = 78

m = 78 - p

Now we can substitute this expression for "m" into equation 3:

m + p = 56

(78 - p) + p = 56

Simplifying the equation, we get:

78 - p + p = 56

78 = 56 + p

p = 22

Therefore, Gerald has 22 pens. To find the number of markers he has, we can substitute this value of "p" into equation 1:

m + 22 = 78

m = 56

So, Gerald has 56 markers.

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a.  An expression to represent the total amount of juice left in the jar is (0.75 + 0.60 + 0.25) - 0.20 liters.

b. Simplification of the expression is 1.15 liters and Addition and subtraction property is used.

Part a: To represent the total amount of juice left in the jar, we can subtract the amount of guava juice poured and the amount Patrick drank from the initial amount of juice in the jar.

Total amount of juice left = (0.75 + 0.60 + 0.25) - 0.20 liters

Part b: To simplify the expression, we can add the amounts of blackberry juice, blueberry juice, and guava juice together, and then subtract the amount Patrick drank.

Total amount of juice left = 1.35 - 0.20 liters

Simplifying the expression and identifying the properties used in each step:
1.35 - 0.20 = 1.15 liters

Properties used:
- Addition property: Adding the amounts of blackberry juice, blueberry juice, and guava juice together.
- Subtraction property: Subtracting the amount Patrick drank from the total amount of juice.

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Answer:

B or D

Step-by-step explanation:

I believe the answer is B or D if it is not im am very sorry i forgot

The value of the numerical expression (7 x 3481) will be 24,367.

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The numbers are given below.

7 and 3481

Then the product of the numbers 7 and 3481 will be given by putting a cross sign between them. Then we have

⇒ 7 x 3481

⇒ 24,367

The value of the numerical expression (7 x 3481) will be 24,367.

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Answer:

1/5x(41-19h)

41/5-19/5h

Step-by-step explanation:

Answer:

1,298 yd²

Step-by-step explanation:

Formula for surface area of a rectangular prism:

A = 2(wl + hl + hw)

Plug your units in.

A = 2[(11 x 11) + (24 x 11) + (24 x 11)] = 1,298

Answer:

$470

Step-by-step explanation:

%30 of 470 = $141

Answer: $470

I hope it help

Answer:

StartFraction x over 7.5 EndFraction = StartFraction 12 over 1 EndFraction

Step-by-step explanation:

Here, in this question, given that Rosa earns $12 in an hour, she earns x dollars in 7.5 hours. So we are interested in finding the value of x.

Let’s write this in terms of proportion;

$12 = 1 hour

$x = 7.5 hours

$12 * 7.5 hours = $x * 1 hour

So this can be rewritten as;

$x/7.5 = $12/1 hour

Answer: Start Fraction x over 7.5 End Fraction Start Fraction 12 over 1

explanation:

To solve the initial value problem y′ 5y=t3e−5t, y(2)=0, we can use the method of integrating factors.

First, we need to identify the integrating factor, which is given by e^(∫5dt) = e^(5t).

Multiplying both sides of the differential equation by the integrating factor, we get:

e^(5t) y′ - 5e^(5t) y = t^3 e^(-t)

Using the product rule, we can rewrite the left-hand side as:

(d/dt)(e^(5t) y) = t^3 e^(-t)

Integrating both sides with respect to t, we get:

e^(5t) y = -t^3 e^(-t) - 3t^2 e^(-t) - 6t e^(-t) - 6 e^(-t) + C

where C is the constant of integration.

Using the initial condition y(2) = 0, we can solve for C:

e^(10) * 0 = -8e^(-10) + C

C = 8e^(-10)

Therefore, the solution to the initial value problem is:

y = (-t^3 - 3t^2 - 6t - 6)e^(-5t) + 8e^(-10)

and it satisfies the initial condition y(2) = 0.

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Answer:

you have it crrect

Step-by-step explanation:

it is 37

The standard form of the given numbers is 207360 × 10¹⁷.

The number system is a way to represent or express numbers.

A decimal number is a very common number that we use frequently.

Since the decimal number system employs ten digits from 0 to 9, it has a base of 10.

Any of the multiple sets of symbols and the guidelines for utilizing them to represent numbers are included in the Number System.

Given the numbers is  (5 x 1,000,000) (6 x 100,000) (4 x 10,000) (8 x 1,000) (3 x 100) (2 x 10) (4 x 0.1) (9 x 0.001)

Now standard form means we need to write the exponents form.

So,

5 x 6 x 4 x 8 x 3 x 2 x 4 x 9 = 207360

And

1,000,000 x  100000 x 10000 x 1000 x 100 x 10 x 0.1 x 0.001 = 10¹⁷

So, combine 207360 x  10¹⁷

Hence "The standard form of the given numbers is 207360 × 10¹⁷".

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Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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Answer:

5y+45

Step-by-step explanation:

The y-intercept of both the functions a(x) and b(x) are the same. Then the correct option is D.

A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.

Consider the function a(x) = - x³ + 8 and function b modeled by this graph.

Then the graph of a(x) and b(x) is shown below.

Then the y-intercept of both the functions a(x) and b(x) are the same.

And the x-intercept of the function a(x) is 2 and b(x) is negative 2.

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Answer:

the y-intercept of b is equal to the y-intercept of a ​

Step-by-step explanation:

All the correct answers of the equations using order of operations are;

B. 8⋅7 ÷ 2 − 12 = 22 − 2⋅3

C. 48 ÷ 8 + 2³ = 5 + 3²

The rule used for order of operations is PEMDAS and it states that the order of operation starts with the calculation enclosed in brackets or the parentheses first. Exponents (degrees or square roots) are then operated on, followed by multiplication and division operations, and then addition and subtraction.

Using the PEMDAS rule, the solutions would be as follows:

A. 9² − 7² = 20 ÷ (7 − 2)

81 - 49 = 20 ÷ 5

32 = 4

Thus, this is not true.

B. 8⋅7 ÷ 2 − 12 = 22 − 2⋅3

56 ÷ 2 − 12 = 22 - 6

28 - 12 = 16

16 = 16

Thus, this is true.

C. 48 ÷ 8 + 2³ = 5 + 3²

6 + 2³ = 5 + 9

6 + 8 = 14

14 = 14

Thus, this is true.

D. 150 ÷ 5² = 30 − 4² − 12

150 ÷ 25 = 30 − 16 − 12

6 = 30 - 28

6 = 2

Thus, this is not true.

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Complete question is;

Which equations are true equations? Select all correct answers.

A. 9² − 7² = 20 ÷ (7 − 2)

B. 8⋅7 ÷ 2 − 12 = 22 − 2⋅3

C. 48 ÷ 8 + 2³ = 5 + 3²

D. 150 ÷ 5² = 30 − 4² − 12

To calculate the number of hands that contain exactly two 8s and two 9s, we first need to determine the number of ways we can choose 2 8s and 2 9s from the deck.

The number of ways to choose 2 8s from the deck is (4 choose 2) = 6, since there are 4 8s in the deck and we need to choose 2 of them. Similarly, the number of ways to choose 2 9s from the deck is also (4 choose 2) = 6. To find the total number of hands that contain exactly two 8s and two 9s, we need to multiply the number of ways to choose 2 8s and 2 9s together:
6 * 6 = 36
Therefore, there are 36 hands that contain exactly two 8s and two 9s, out of the total number of possible 7-card hands that can be chosen from a standard deck of playing cards.

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Fixed costs are expenses that remain constant regardless of the level of production. The calculation of average fixed costs (AFC) is obtained by dividing the total fixed cost by the number of units produced.

AFC provides the amount per unit that the company will spend on fixed costs to produce a given quantity of output. Therefore, to calculate the average fixed cost at the Shanghai factory if the 2020 output level (= 35,000 cars annually) were maintained for ten years, we will first calculate the total fixed costs.

The formula for calculating average fixed cost (AFC) is:

Average Fixed Cost (AFC) = Total Fixed Cost / Quantity ProducedTotal Fixed Cost is obtained by multiplying the fixed cost per unit with the total number of units produced.

Total Fixed Cost (TFC) = Fixed Cost per Unit × Number of Units ProducedThe problem does not provide any information about the fixed cost per unit, which is why it cannot be calculated.

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To calculate the average fixed cost at the Shanghai factory, divide the total fixed costs by the output level. For a given output level of 35,000 cars annually maintained for 10 years, the average fixed cost would be $285.71 per car.

To calculate the average fixed cost at the Shanghai factory, we need to divide the total fixed costs by the output level. Since the question specifies that the output level is 35,000 cars annually and we want to maintain this level for 10 years, we can calculate the average fixed cost as follows:

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Answer:

14 feet

Step-by-step explanation:

We solve the above question by using the Greatest Common Factor method

We find the factors of 56 and 98

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

The factors of 98 are: 1, 2, 7, 14, 49, 98

Then the greatest common factor is 14.

Therefore, the greatest possible length you can cut the rope so all pieces will be the same is 14 feet

Answer:

You draw the line of the graph and every point on the line is a solution

Step-by-step explanation:

y = mx + b  You graph the b which is the y intercept.  This is where the graph crosses the x axis.  In this case it is -12.  From that point (0,-12)  You follow a pattern which is the slope.  In this case the slope is -3.  That mans that you move three units down and then 1 unit right.

I highlighted a few points on the line.  Every point on the line is a solution.

Answer:

x = 19

Step-by-step explanation:

Step-by-step explanation:

6x + 5x - 6 = 32 + 9x

11x - 6 = 32 + 9x

Bringing like terms on one side

11x - 9x = 32 + 6

2x = 38

x = 38/2 = 19

There are 40 such bit strings.

To count the number of bit strings of length seven that either begin with two 0s or end with three 1s, we need to use the principle of inclusion-exclusion.

Let A be the set of bit strings that begin with two 0s, and let B be the set of bit strings that end with three 1s.

Then, we want to find the size of the set A ∪ B, which consists of bit strings that satisfy either condition.

The size of A can be calculated as follows:

since the first two digits must be 0, the remaining five digits can be any combination of 0s and 1s,

so there are \(2^5 = 32\) possible strings that begin with two 0s.

Similarly, the size of B can be calculated as follows:

since the last three digits must be 1, the first four digits can be any combination of 0s and 1s,

so there are\(2^4 = 16\) possible strings that end with three 1s.

However, we have counted the strings that both begin with two 0s and end with three 1s twice.

To correct for this, we need to subtract the number of strings that belong to both A and B from the total count.

The strings that belong to both A and B must begin with two 0s and end with three 1s, so they have the form 00111xxx,

where the x's can be any combination of 0s and 1s.

There are \(2^3 = 8\) such strings.

Therefore, the total number of bit strings of length seven that either begin with two 0s or end with three 1s is:

|A ∪ B| = |A| + |B| - |A ∩ B| = 32 + 16 - 8 = 40.

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Probabilities are used to determine the chances of events

There are 4 C2 cards in the first deck out of a total of 12 cards, and there are 3 C6 cards in the second deck out of a total of 14 cards.

So, the probability that the player will choose a C2 card from the first deck or a C6 card from the second deck is:

\(P = \frac{4}{12} + \frac{3}{14}\)

Simplify

\(P = \frac{1}{3} + \frac{3}{14}\)

Take the LCM

\(P = \frac{14 + 3}{42}\)

\(P = \frac{17}{42}\)

Also;

There are 3 C3 cards in the first deck out of a total of 12 cards, and there are 4 C5 cards in the second deck out of a total of 14 cards.

So, the probability that the player will choose a C3 card from the first deck or a C5 card from the second deck is:

\(P = \frac{3}{12} + \frac{4}{14}\)

Simplify

\(P = \frac{1}{4} + \frac{2}{7}\)

Take the LCM

\(P = \frac{4 + 14}{28}\)

\(P = \frac{18}{28}\)

\(P = \frac{9}{14}\)

Hence, the probability that the player will choose a C3 card from the first deck or a C5 card from the second deck is 9/14

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Answer:

-6

Step-by-step explanation:

Answer:

3 is a whole number but 2x is 2 multiplied by a variable

1. The cosine function that models the situation is:

y = 7cos(0.4πx) + 31.

2. The times of the day that he should try to fish are between 12:15 pm and 1:45 pm.

The cosine function is defined by the rule as follows:

g(x) = acos(bx+c)+d.

The coefficients have the roles listed as follows:

The amplitude is given by half the difference of the highest and of the lowest value, hence:

a = 0.5 x (38 - 24) = 7.

The vertical shift is of d = 31, as a standard cosine function with amplitude 7 varies between -7 and 7, not between 24 and 38.

The difference in the inputs between the maximum and the minimum value is of half the period, hence the period in hours is obtained as follows:

Period = 2.5 hours/0.5 = 5 hours.

Thus the coefficient B of the function is:

2π/B = 5

B = 2π/5

B = 0.4π.

There is no phase shift, as we suppose 8 a.m. as the time zero.

Hence the equation is:

y = 7cos(0.4πx) + 31.

He should try to fish when the depth is above 35 inches, hence, from the graph, these are the times in which the function is above the horizontal line y = 35, hence:

Between 12:15 pm and 13:45 pm.

As:

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Answer:

Step-by-step explanation:

m= 3/1

Answer: 3

Step-by-step explanation: This equation is written in y = mx + b form.

In this form, the m is the slope and the b is the y-intercept.

Take a look below.

So the slope of this line is 3.