Answers
Answer:
362.7 g of NH3
Explanation:
The balanced equation of the given reaction is represented as;
N2 (g) + 3H2 (g) -> 2NH3 (g)
From observation, we can see that the mole ratio between the elements in the reaction which are: N2, H2 and NH3 have a mole ratio 1 : 3 : 2
As we can see that N2 : H2 = 1:3
It means that the reaction will consume three times more moles of hydrogen than the moles of nitrogen consumed. Thus, the H2(hydrogen gas) will limit the amount of N2 (Nitrogen gas) that will take part in the reaction.
Thus,
No. of moles of N2 that will take part in the reaction is;
1 mole of H2 × 1 mole of N2/3 moles of H2
The moles of H2 will cancel out to give;
1/3 moles of N2
We are told we have 11.0 mol of N2.
Thus, remaining N2 will be; 11 - ⅓ = 32/3 moles of N2
The mole ration between N2 and NH3 as a earlier seen is 1:2.
Thus,
We have;
32/3 moles of N2 × 2 moles of NH3/1 mole of N2
The mole of N2 will cancel out to give;
64/3 moles of NH3
Now, atomic mass of NH3 = 17 g/mol
Thus, max amount of NH3 that could be produced is;
64/3 × 17 = 362.7 g
Related Questions
A 2.550×10−2 M glycerol solution (C3H8O3) in water is at 20.0 ∘C . The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.9 mL. The density of water at 20.0 ∘C is 0.9982 g/mL
a.) Calculate the molality of the glycerol solution
b.) Calculate the mole fraction of glycerol in this solution
c.) Calculate the concentration of the glycerol solution in percent by mass
d.) Calculate the concentration of the glycerol solution in parts per million by mass
Answers
The molality of the solution is 0.0256 m.
The mole fraction of glycerol is 0.00046
The percent by mass concentration of glycerol is 0.23%
The ppm concentration is 2300 ppm
What is the molality?Molality is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per kilogram of solvent.
The formula for molality is:
molality = moles of solute / mass of solvent in kilograms
1) Density of water = mass/volume
Mass of water = Density * volume of water
Mass =\(0.9982 g/mL * 998.9 mL\)
Mass =0.997 Kg of water
Number of moles of the glycerol = \(2.550* 10^-2 M * 1 L\)
= \(2.550*10^-2\) moles
Molality of the solution = \(2.550*10^-2\) moles/0.997 Kg
= 0.0256 m
Number of moles of water = 998.9/18 g/mol
= 55.5 mole
Mole fraction of glycerol = \(2.550*10^-2\) /\(2.550*10^-2\) + 55.5
= 0.00046
By percent by mass;
2.3/1001.2 * 100/1
= 0.23%
Mass of glycerol = 2.3 g
Volume of solution = 1 L
Thus we have concentration in ppm as;
\(2.3 * 10^3\) mg/ 1 L =2300 ppm
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Matter is never created or destroyed.
Lesson 5.04
Question 7 options:
True
False
Answers
Determine if the following two structures are identical, isomers, or unrelated? (image)
A. identical
B. isomers
C. unrelated
Answers
Answer:
Option (A) identical ,
because long change and branch chain are same and at same position
The following two structures are identical.
What are isomers?Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers.
The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830.
Structural isomerism is commonly referred to as constitutional isomerism. The functional groups and the atoms in the molecules of these isomers are linked in different ways. Different structural isomers are assigned different IUPAC names since they may or may not contain the same functional group. In the picture, we can see that IUPAC nomenclature also of the two structures are same hence they are identical.
Therefore, The following two structures are identical.
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8.0g of certain gas occupies 5.6 L at STP.
A) How many moles of gas are present?
B) What is the molar mass of the gas?
C) What is the common atmospheric gas was collected?
Answers
Answer:
A) Using the ideal gas law, we can calculate the number of moles of gas present:
```
PV = nRT
```
where:
* P = pressure (atm) = 1 atm
* V = volume (L) = 5.6 L
* n = number of moles of gas
* R = ideal gas constant = 0.08206 L atm / mol K
* T = temperature (K) = 273.15 K
Solving for n, we get:
```
n = (P * V) / RT
```
```
n = (1 atm * 5.6 L) / (0.08206 L atm / mol K * 273.15 K)
```
```
n = 0.25 mol
```
Therefore, there are 0.25 moles of gas present.
B) The molar mass of the gas can be calculated by dividing the mass of the gas (8.0 g) by the number of moles of gas (0.25 mol):
```
Molar mass = Mass / n
```
```
Molar mass = 8.0 g / 0.25 mol
```
```
Molar mass = 32 g/mol
```
The molar mass of the gas is 32 g/mol.
C) The common atmospheric gas with a molar mass of 32 g/mol is oxygen (O2). Therefore, the gas that was collected is oxygen.
Explanation:
What do you expect to happen to the volume of a gas if it’s pressure is doubled and it’s temperature is reduced to half?
Answers
the volume of the gas is quadrupled.
Explanation:
In which food or drink are the particles most likely moving the fastest? Answers they gave to us: popsicle, cheese, a drink, Coffee. Please help me please i will give you a 5 star.
Answers
Answer:
Coffee
Explanation: When a liquid is warm the particles move faster
What things contribute to the amount of greenhouse gasses on Earth?
Answers
Human activities are responsible for almost all of the increase in greenhouse gases in the atmosphere over the last 150 years. The largest source of greenhouse gas emissions from human activities in the United States is from burning fossil fuels for electricity, heat, and transportation.
Why would you not want to use a salt bridge saturated with potassium chloride solution in an electro-chemical cell made from a Ag/Ag+ cathode and a Cu/Cu²+ anode?
Answers
We can not use a salt bridge saturated with potassium chloride solution in an electro-chemical cell made from a Ag/Ag+ cathode and a Cu/Cu²+ anode because it will precipitate.
An electrochemical cell that uses a weak electrolyte and a salt bridge to connect oxidation as well as reduction half cells. A junction that joins the anodic with cathodic compartments of a cell and electrolytic solution is referred to as a salt bridge.
Because both chloride and potassium ions have very similar diffusion coefficients and minimise junction potential, the inactive minerals potassium chloride (KCl) frequently used. We can not use a salt bridge saturated with potassium chloride solution in an electro-chemical cell made from a Ag/Ag+ cathode and a Cu/Cu²+ anode because it will precipitate.
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Calculate the [H3O+] value of each aqueous solution.milk of magnesia with [OH−]=1.4×10−5M .Express your answer using two significant figures.
Answers
Answer:
[H3O (+)] = 7.1 x 10⁻¹⁰ M.
Explanation:
To solve this problem, we have to use the following equation:
\(\lbrack H_3O^+]\lbrack OH^-]=1\cdot10^{-14}.\)As we have the value of [OH (-)], we just have to solve for [H3O (+)] and replace the data that we have, like this:
\(\begin{gathered} \lbrack H_3O^+]=\frac{1\cdot10^{-14}}{\lbrack OH^-]}=\frac{1\cdot10^{-14}}{1.4\cdot10^{-5}}, \\ \lbrack H_3O^+]=7.1\cdot10^{-10}\text{ M.} \end{gathered}\)The answer would be that the concentration of [H3O (+)] = 7.1 x 10⁻¹⁰ M.
A 2.75 kg sample of a substance occupies a volume of 250.0 cm3.
Find its density in g/cm3.
Answers
Answer:
11g/cm³
Explanation:
Use the formula
density = mass ÷ volume
mass = 2.75kg →2750gvolume = 250cm³Sub in the values:
density = 2750 ÷ 250
density = 11g/cm³
Hope this helps!
Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 12 moles of Al react with 12 moles of HBr, what is the limiting reactant?
Answers
Answer:
the limiting reactant is HBr
Explanation:
if you tried to make the products using 12 mol Al and 12 mol HBr, the HBr will run out first
What systems keep something inside them the same temperature (either hot or cold) without using electricity?
Answers
Answer:
Solar Gain. Solar gain is our bread and butter, defined as an object's increase in temperature from solar radiation. ...
Thermal Mass. If an object has great thermal mass, it is capable of retaining heat for long periods of time. ...
Insulation. ...
Orientation. ...
Convection. ...
Cooling Tubes. ...
Deflection. ...
Explanation:
Arrange the following aqueous solutions in order from smallest to greatest freezing point depression: 0.400 m CaCl2, 0.400 m glucose or 0.400 m NaCl, Then determine the freezing point depression for each. For water, Kf = 1.86°C/m.
Answers
Answer:
glucose<NaCl<CaCl2
Explanation:
Hello there!
In this case, since the general equation for the calculation of the freezing point depression is:
\(\Delta T=-i*m*Kf\)
Whereas m and Kf are the same for the given salts, then we conclude that the greatest freezing point is exhibited by the salt with the greatest Van't Hoff's factor and the smallest freezing point with the smallest Van't Hoff's factor. In such a way, since this factor is equal to the number of ionized species, we infer that CaCl2 has i=3, glucose i=1 (nonionizing) and NaCl i=2; therefore, the order from smallest to greatest is:
glucose<NaCl<CaCl2
Regards!
How many moles are equal to 3.67 x 1023 formula units of potassium permanganate?
Answers
Answer:
3.67 x 10^23 formula units of potassium permanganate is equal to 0.6108 moles.
Explanation:
The formula unit of a compound is the lowest whole number ratio of atoms in the compound. In the case of potassium permanganate, the chemical formula is KMnO4, which means that one formula unit of potassium permanganate contains one atom of potassium (K), one atom of manganese (Mn), and four atoms of oxygen (4O).
To find the number of moles in 3.67 x 10^23 formula units, we can use Avogadro's number, which is the number of atoms, ions, or molecules in one mole of a substance and is equal to 6.022 x 10^23/mol.
We can use the following formula:
moles = formula units x (1 mol/ Avogadro's number)
moles = 3.67 x 10^23 formula units x (1 mol/6.022 x 10^23/mol)
moles = 0.6108
So, 3.67 x 10^23 formula units of potassium permanganate are equal to 0.6108 moles.
(Please give brainlist)
A liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 90.0 mL. The liquid solvent has a mass of 47.3 g and a density of 0.865 g/mL. Determine the mass of the solid given its density is 3.25 g/mL.
Answers
The mass of the solid will be 114.7 g.
Density problemThe density of a substance is given as the ratio of its mass and its volume.
Also, a solid will always displace its own volume in a liquid.
Mass of liquid solvent = 47.3 g
Density of liquid solvent = 0.865 g/mL
Recall that: density = mass/volume
Volume of liquid solvent = mass/density
= 47.3/0.865
= 54.7 mL
Volume of solid + liquid solvent = 90.0 mL
Volume of solid = 90.0 - volume of liquid solvent
= 90.0 - 54.7
= 35.3 mL
Density of solid = 3.25 g/mL
Mass of solid = density x volume
= 3.25 x 35.3
= 114.7 g
The mass of the solid is 114.7 g.
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A balloon filled with air has a volume of 4.24 liters at 23.00°C. If the balloon is cooled at a constant pressure to 5.00°C, what is the new volume?
Answers
Why is there something blocking the answer?
Answers
Answer: the answer you are looking for does not exist
Explanation:
which has a higher melting point CH3CH2CH2CH2CH2CH3 or CH3CH2CH2CH2CH2CH2CH2CH3
Answers
Answer:
the second one
Explanation:because its higher
Answer:
CH3CH2CH2Ch2Ch2Ch3
Explanation:
That's the answer
Which statements are part of the safety protocol for this lab experiment? Check all that apply.
Always wear nitrile gloves while handling chemicals such as water.
Do not throw around any of the athletic equipment used in this exercise.
Be careful not to spill when transferring water from the water displacement procedure; this could cause people to slip and fall.
Check containers, such as beakers, graduated cylinders, and buckets, for cracks or chips prior to use.
Avoid submerging sports equipment under water.
Answers
Answer: the answer is B, C, and D
Explanation:
Answer:
-Do not throw around any of the athletic equipment used in this exercise.
-Be careful not to spill when transferring water from the water displacement procedure; this could cause people to slip and fall.
-Check containers, such as beakers, graduated cylinders, and buckets, for cracks or chips prior to use.
Explanation:
hope it helps! correct on edge :)
Calculating the mass of a reactant The reaction between H2 and O2 and produces 26.2 g water. How many grams of O2 reacted?
Answers
Answer:
23.3 grams
Explanation:
First we'll need the balanced equation for this equation.
2H₂ + O₂ → 2H₂O
This shows us that we need one mole of O₂ to produce two moles of water.
Now we need to convert grams to moles.
There is 18.01528 g for every mole of water
26.2/18.01528 = 1.454321
There 1.454321 moles of water produced
Remember that two moles of water are produced from a gram of O₂
1.454321/2 = 0.72716
0.72716 moles of O₂ were used
Now convert moles back to grams. There are 31.998 g for every mole of O₂
31.998 x 0.72716 = 23.2677
23.2677 grams of oxygen were used
1 point
To help you with estimating, the individual answers to A, B, C should all
have zero in the one's place. Add those answers up to get the numerical
code. Input that code to move on.*
A) 56 g NH3 can be dissolved in 100 g of water at °C
B) At 50°C, 166 g of KNO, can be dissolved in g of water to make a saturated
solution
C) At 76°C, KCI and HCI have the same solubility. What mass of each could be dissolved in
80 g of water?
Your answer
This is a required question
Back
Next
Answers
Answer:ee
Explanation:
Help anyone? :) please
Answers
Answer:
6. protons, mass number from the atomic number
7. Li= ,
H3PO4 + Ca(OH)2 ----> H2O + Ca3(PO4)2 If 10.3g of Ca(OH)2 reacts , How much water is made
Answers
Taking into account the reaction stoichiometry, if 10.3 g of Ca(OH)₂ reacts, 5.01 grams of H₂O are formed.
Reaction stoichiometryThe balanced reaction is:
2 H₃PO₄ + 3 Ca(OH)₂ → 6 H₂O + Ca₃(PO₄)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
H₃PO₄: 2 molesCa(OH)₂: 3 molesH₂O: 6 molesCa₃(PO₄)₂: 1 moleThe molar mass of the compounds is:
H₃PO₄: 98 g/moleCa(OH)₂: 74 g/moleH₂O: 18 g/moleCa₃(PO₄)₂: 310 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
H₃PO₄: 2 moles ×98 g/mole= 196 gramsCa(OH)₂: 3 moles ×74 g/mole= 222 gramsH₂O: 6 moles ×18 g/mole= 108 gramsCa₃(PO₄)₂: 1 mole ×310 g/mole= 310 gramsMass of water formedThe following rule of three can be applied: if by reaction stoichiometry 222 grams of Ca(OH)₂ form 108 grams of H₂O, 10.3 grams of Ca(OH)₂ form how much mass of H₂O?
mass of H₂O= (10.3 grams of Ca(OH)₂ ×108 grams of H₂O)÷ 222 grams of Ca(OH)₂
mass of H₂O= 5.01 grams
Finally, 5.01 grams of H₂O are formed.
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How many mg does an 830 kg sample contain?
Answers
Answer:
A sample of 830 kg would contain 830000000 mg
Explanation:
The following two organic compounds are structural isomers to each other. Carefully identify and justify the structural isomers type (skeletal, functional, or positional) with their common molecular formula
Answers
Structural isomers are molecules with the same molecular formula but with different structural formulae. This means that they have the same number and types of atoms, but they are arranged differently. The following two organic compounds are structural isomers of each other.
Carefully identify and justify the structural isomers type (skeletal, functional, or positional) with their common molecular formula.Common molecular formula: C6H14Structural isomers:(i) Hexane: Hexane is a straight-chain alkane with six carbon atoms and no double bonds or rings. The carbon atoms are linked together in a linear or straight-chain configuration in the skeletal isomer. The skeletal isomer differs in terms of the arrangement of atoms in its molecule. This indicates that it is a skeletal isomer.(ii) 2-methylpentane: It is a branched-chain alkane with six carbon atoms and no double bonds or rings. It differs from the first molecule in terms of the location of a methyl group on the second carbon of the five-carbon chain, rather than a straight six-carbon chain. This difference is due to a change in the positioning of the carbon atoms in the molecule. As a result, it is a positional isomer, as it differs by the position of the functional group or substituent. Therefore, the skeletal and positional isomerism types are present between these two compounds.For such more question on molecular
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Determine the mass in grams of 3.27 × 10²¹ atoms of arsenic. (The mass of one mole of arsenic is 74.92 g.)
Answers
Explanation:
74.92 g.
(The mass of one mole of arsenic is 74.92 g.
1. Before starting, make a prediction: If substances B and C are both in the gas phase and are at the same energy level, which of the two substances will need to have more energy transferred out in order to change to the liquid phase? Substance B or substance C? Explain your answer.
Answers
Answer:
Substance C
Explanation:
Substance C would be the answer because Substance C has a lower attraction level. Because of this, it takes more energy to take out of in order to become a liquid.
6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
Answers
How many moles of H2O are found in a sample containing 7.1 * 10 (19) molecules
Answers
The sample containing 7.1 × 10^19 molecules of H2O corresponds to approximately 1.18 × 10^(-4) moles of H2O.
To determine the number of moles of H2O in a sample containing 7.1 × 10^19 molecules, we need to use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 molecules.
Given that there are 7.1 × 10^19 molecules of H2O in the sample, we can calculate the number of moles using the following formula:
Moles = Number of molecules / Avogadro's number
Moles = 7.1 × 10^19 / 6.022 × 10^23
Moles ≈ 1.18 × 10^(-4) moles
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At 298 K and 1atm, Br2 is a liquid with a high vapor pressure, and CI2 is a gas. Those observations provide evidence that under the given conditions, the forces among Br2 molecules are stronger than those among CI2 molecules forces among CI2 molecules are stronger than the Cl-Cl bond Br-Br bond Is stronger than the Cl-Cl bond Cl-Cl bond Is stronger than the Br-Br bond
Answers
The statement that at 298K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas provides evidence that forces among Br2 molecules are greater than those among Cl2 molecules.
The three states in which matter can exist are solids, gases and liquids. These states of matter are made up of molecules held together by forces of attraction. The force of attraction that holds the molecules of the three states of matter varies as it decreases in the following order: solids > liquids > gases. Liquids possess a greater intermolecular force of attraction than gases, hence, they cannot move around freely like gases. Account to this question, at 298 K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas. This statement reveals that forces among Br2 molecules are greater than those among Cl2 molecules.
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