The correct answer is transient airflows under the combined motion of a door and the force of buoyancy.
However, the combined airflow characteristics generated by door motion, ventilation airflow, and thermal impacts have not yet been thoroughly defined. Door motion has been acknowledged as playing a part in the confined conveyance between indoor and outdoor regions. This study employed dynamic CFD simulation to look at the transient airflow characteristics and amount of air exchange generated by door motions in a thermally stratified environment with displacement ventilation. The results show that at a door angle of 30°, there is a 40% air exchange even though only 15% of the overall door motion process is used during the initial phase. Two important contributing factors are the temperature difference between the air inside and outside, as well as the rotational speed of the door.
The thermal convective flow may have a considerable impact on the airflow pattern through the doorway when the door motion is slow enough and the temperature difference is greater than 3 °C. The amount of air exchange rises linearly with door motion speed when there is no difference in temperature between the internal and exterior spaces. When buoyant force and door motion are coupled, a modest door speed yields minimal air exchange. Only the air temperatures close to the door are impacted by door movement. In the displacement ventilated room, a single door open and close cycle does not considerably reduce the overall temperature stratification. The research findings may help to improve knowledge of the consequences of dynamic disturbances in thermally stratified environments as well as offer recommendations for decreasing door motion-induced pollutant movement.
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The water was used to power a generator, creating _______________ energy
Answer:
electric
please give brainliest
A person walks 100m in 5
minutes, then 200m in 7
minutes and finally 50m in
4 minutes. Find their
average speed.
The average speed of person is 21.87 m/s.
Given data:
The first 100 m distance is covered in 5 minutes.
Next, 200 m distance is covered in 7 minutes.
And finally, the distance of 50 m is covered in 4 minutes.
The average speed of any object is defined as the total distance covered by object in an entire journey divided by the total time taken to cover the journey. The mathematical expression for the average speed of person is,
\(v_{av.}=\dfrac{D_{total}}{t_{total}}\\\\\\v_{av.}=\dfrac{100 +200+50}{5+7+4}\\\\\\v_{av.}=21.87 \;\rm m/min\)
Thus, we can conclude that the average speed of person is 21.87 m/min.
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Each point of a light-emitting object (a) sends one ray. (b) sends two rays. (c) sends an infinite number of rays.
The answer to your question is (c): each point of a light-emitting object sends an infinite number of rays. This is because light is a form of electromagnetic radiation that is emitted in all directions from a source.
Each point on an object emits light in all directions, meaning that an infinite number of rays are sent out from each point. This is why we can see objects from different angles and perspectives - because light is being emitted in all directions from each point on the object.
However, it's important to note that not all of these rays will necessarily reach our eyes, as they can be blocked or scattered by other objects in the environment.
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The law of conservation of energy states that energy cannot be:.
Answer:
chenged when not anet force
(a) In the deep space between galaxies, the density of atoms is as low as 10^6 atoms/m^3 , and the temperature is a frigid 2.7 K. What is the pressure? (b) What volume (in m^3) is occupied by 1 mol of gas? (c) If this volume is a cube, what is the length of its sides in kilometers?
The length of its sides in kilometers is \(0.000290 km\)
What is celestial mechanics?
Celestial mechanics is a scientific discipline that studies the motion and behavior of celestial bodies, including planets, moons, asteroids, comets, and stars, using principles and laws of physics. It focuses on understanding the gravitational interactions between celestial objects and how they influence their orbits, positions, and movements in space.
\(\textbf{(a) Pressure Calculation:}\)
To find the pressure, we can use the ideal gas law equation, which states:
\(\[ PV = nRT, \]\)
where \($P$\) is the pressure, \($V$\) is the volume, \($n$\) is the number of moles of gas, \($R$\) is the gas constant and \($T$\) is the temperature.
In this case, the number of moles (\($n$\)) is given as 1 mol, the gas constant (\($R$\)) is a known value, and the temperature (\($T$\)) is given as \(2.7 K\). However, we need to determine the volume (\($V$\)) in order to calculate the pressure.
\(\textbf{(b) Volume Calculation:}\)
The volume occupied by 1 mol of gas can be calculated using Avogadro's Law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of particles. One mole of any gas at standard temperature and pressure (STP) occupies a volume of 22.4 liters
\((22.4 L) \\or\\ 0.0224 cubic meters (0.0224 m$^3$).\)
\(\textbf{(c) Length Calculation:}\)
If the volume is a cube, and we know the volume is \(0.0224 m$^3$\), we can calculate the length of its sides by taking the cube root of the volume. Therefore, the length of each side is:
\(\[ \text{Length} = \sqrt[3]{\text{Volume}} = \sqrt[3]{0.0224} \approx 0.290 \, \text{m}.\]\)
To convert this length to kilometers, we divide by 1000:
\(\[ \text{Length in kilometers} = \frac{0.290 \, \text{m}}{1000} = 0.000290 \, \text{km}.\]\)
Therefore, the length of its sides in kilometers is \(0.000290 km\)
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Determine both the mass and the charge of a block of material consisting of 3 x 10^27 protons, 3 x 10^37 neutrons, and 3.1 x 10^27 electrons.
Answer:
The mass of the block of material is 3 x 10³⁷ g/mol
The charge of the material is 4.8 x 10⁸ C
Explanation:
Given;
number of protons of the material, P = 3 x 10²⁷
number of neutrons in the material, N = 3 x 10³⁷
number of electrons in the material, E = 3 x 10²⁷
The mass of the block of material is calculated as follows;
M = P + N
M = 3 x 10²⁷ + 3 x 10³⁷
M = 3 x 10³⁷ g/mol
The charge of the material is calculated as follows;
charge of 1 electron = 1.6 x 10⁻¹⁹ C
charge of 3 x 10²⁷ electrons = 3 x 10²⁷ electrons x 1.6 x 10⁻¹⁹ C
= 4.8 x 10⁸ C
how long did it take the flag to rotate once in a full circle
Answer:
360 degrees is one full rotation starting at zero
it take 2 s to the flag to rotate once in a full circle with 3 rad/s of angular velocity.
What is Angular velocity and acceleration ?Angular velocity is "rate of change of angular displacement with respect to time". i.e. ω= dθ/dt. it is also defined as angular displacement over time. i.e. ω = angular displacement/Time.
Angular velocity shows how much angle can be covered in unit time. It's SI unit rad/s.
Angular acceleration is rate of change of Angular velocity with respect to time.
i.e. α = dω/dt if an object changes its angular velocity in short time, we can say that it has greater angular acceleration. It is expressed in rad/s².
In this problem we have to calculate time, but the angular velocity id not given.
Consider the angular velocity is 3 rad/s.
Given,
Angular displacement θ = 2π
angular velocity ω = 3 rad/s
Time t = ?
Time = θ/ω
Time = 2π/3 rad/s = 2 s
Hence the answer is 2s.
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1) how can you show that atmospheric exerts pressure?
2) how do you measure the volume of an irregular solid ? explain an experiment with diagram.
Answer:
1. While boiling replace the cap and allow it to cool. Vapours inside condense and form water creating vacuum above them. Observation - The can crumbles due to air pressure from outside. This proves that air exerts pressure.
2. Measure the volume of the liquid displaced when the object is submerged. Measure the initial volume of water in graduated cylinder. Submerge the irregular object. Measure the final volume of the water.
— The difference between the initial volume and the final volume is the volume of the object.
hope can help ^_^
A snow monster drags his injured prey across the snow. Assume
friction is zero. If the prey has a mass of 85 kg. If the monster applies
a constant force of 261 N at an angle of 60 degrees to drag the prey
32 m. How much work did the monster do?
The amount work done by the monster is 4176 J.
What is work done?Work is said to be done when a force moves an object through a distance.
To calculate the work done by the monster, we use the formula below
Formula:
W = Fdcos∅........................ Equation 1Where:
W = Work done by the monsterF = Force applied by the monsterd = Distance∅ = Angle to the horizontalFrom the question,
Given:
F = 261 Nd = 32 m∅ = 60°Susbtitute these values into equation 1
W = 261×32×cos60°W = 4176 JHence, the work done is 4176 J.
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The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object B?
Answer:
\(m_B > m_A\)
the mass of body B must be greater than the mass of body A
Explanation:
Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration
F = m a
a = F / m
Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships
a_A > a_B
\(\frac{F}{m_A} > \frac{F}{m_B}\)
\(m_B > m_A\)
Therefore, for this to happen, the mass of body B must be greater than the mass of body A
To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from the pulley, to the velocity the stone would have if falling the same distance while unconnected to the pulley. What is the velocity of an untethered stone after falling 0.337 m from rest
Answer:
The velocity of the stone is 2.57 m/s.
Explanation:
Given that
Height = 0.337 m
We need to calculate the velocity of the stone
Using equation of motion
\(v^2-u^2=2gh\)
Where, v = velocity of stone
u = initial velocity
g = acceleration due to gravity
h = height
Put the value into the formula
\(v^2-0=2\times9.8\times 0.337\)
\(v=\sqrt{2\times9.8\times0.337}\)
\(v=2.57\ m/s\)
Hence, The velocity of the stone is 2.57 m/s.
Calculate the kinetic energy of a car which has a mass of 1000 kg and is moving at the rate of 20 m/s.
Given,
The mass of the car, m=1000 kg
The velocity of the car, v=20 m/s
The kinetic energy of an object is the energy of the body possessed due to its motion. The kinetic energy of a body is directly proportional to the square of the velocity of the object.
The kinetic energy of the car is given by,
\(E=\frac{1}{2}mv^2\)On substituting the known values,
\(\begin{gathered} E=\frac{1}{2}\times1000\times20^2 \\ =200000\text{ J} \\ =200\text{ kJ} \end{gathered}\)Thus the kinetic energy of the given car is 200 kJ.
a 30 kg cart is travelling in a zero friction environment at a constant velocity of 5m/s. It's about to go up a very steep hill. How high will the cart be when the velocity changes to zero? PLEASE HELP
Answer:
1.27551m
Explanation:
This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.
Thus, we get:
\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)
We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)
One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.
\(KE_{initial} = PE_{final}\)
Plugging in:
\(\frac{1}{2}*30*5^2 = 30*9.8*h\)
Solving for h, we get 1.27551m
Sentence A: At the same time, teachers will benefit from teaching fewer students per semester and gaining more one-on-one time with students Sentence B: For all of these reasons, a change from the traditional seven-period class schedule to more compact, four-class block schedule will be beneficial for both students and teachers. Sentence C: Students will enjoy less homework each night, better focus due to fewer subjects, and more variety, with new classes each semester. Sentence D: When it comes to exchanging the seven- period day to a four-period day, less is definitely more. Which arrangement of these sentences would be best for a conclusion paragraph?
A. B, C, A, D
B. B, D, A, C
C. D, A, C, B
D. C, A, B, D
plz help me
I think its c
d a c b
I hope this is helpful
Answer:
Its A. B, C, A, D
Explanation:
Which of the following is a source of thermal energy that is absorbed by Earth's atmosphere?
Answer:
100% of the energy entering earth's atmosphere comes from the sun. ~50% of the incoming energy is absorbed by the earth's surface i.e. the land and oceans.
Which trait is solely dependent on its environment?
Answer:
The tendency of a dog to bark defines entirely on the type of environment and the situation the dog looks at. Hence the correct answer is option.
a pencil partially submerged in a glass of water appears broken or offset because of
When a pencil is partially submerged in a glass of water, it appears broken or offset due to the refraction of light. Refraction occurs when light passes through a medium with a different density than the one it was previously in, such as air and water. This causes the light to bend and change direction, resulting in the pencil appearing differently than it actually is.
The light that enters the water from the submerged portion of the pencil is refracted towards the normal (the imaginary line perpendicular to the surface of the water), while the light that enters the air from the exposed portion of the pencil is refracted away from the normal. This causes the image of the pencil to appear broken or offset at the water-air interface.
The degree of the bend depends on the angle of incidence and the refractive index of the medium. Hence, the amount of refraction varies with the thickness of the water column, making the pencil look even more broken or offset when viewed from different angles.
In conclusion, the illusion of a broken or offset pencil in water is caused by the refraction of light at the interface between water and air.
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Will oil or vinegar flow faster?
Answer:
Vinegar
...................
1)
How much time does it take to lift a box using 18.0 J of work and 20.89 Watt of power?
Answer:.
Explanation:
Z
The temperature at which a liquid becomes a gas is the _____ point.
freezing
boiling
condensation
melting
Boiling!
Explanation:
this is when it evaporates
What is the velocity of a freely falling object 10 seconds after it is released from rest?
Answer:
around 98 meters per second.
Explanation:
Instantaneous velocity can be found with a equation.
Vf=Vi+At
Since it fell and had no initial velocity the equation becomes
Vf=At
The Acceleration is 9.8 m/s^2
So the velocity of it fell for ten seconds is
Vf=9.8m/s^2 * 10
Vf= 98 m/s
The motor draws in the cable at a rate of V(0.06s3/2) m/s where s is in meters. The crate has a mass of 20 kg, and the coefficient of kinetic friction between the crate and the ground is 0.3. (Figure 1) Part A Determine the tension developed in the cable whens 15 m Express your answer to three significant figures and include the appropriate u T-1 Value Units
The tension developed in the cable when s = 15m is 87.6 N (to three significant figures).
To determine the tension developed in the cable when s = 15m, we need to use the equation for the force of friction:
f_friction = μ * f_norm
where μ is the coefficient of kinetic friction, and f_norm is the normal force acting on the crate. The normal force can be calculated as:
f_norm = m * g
where m is the mass of the crate and g is the acceleration due to gravity (9.81 m/s^2).
So, f_norm = 20 kg * 9.81 m/s^2 = 196.2 N
The force of friction can be calculated as:
f_friction = μ * f_norm = 0.3 * 196.2 N = 58.86 N
Now, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:
F_net = m * a
where F_net is the net force, m is the mass of the crate, and a is the acceleration of the crate.
The net force in this case is the tension in the cable minus the force of friction:
F_net = T - f_friction
The acceleration of the crate can be calculated as the derivative of the velocity with respect to time:
a = dV/dt = d/dt(V(0.06s^(3/2))) = (0.09s^(1/2)) m/s^2
Now we can plug in the values and solve for the tension:
T - f_friction = m * a
T - 58.86 N = 20 kg * (0.09s^(1/2)) m/s^2
T = 58.86 N + 1.8s^(1/2) N
When s = 15m, the tension in the cable is:
T = 58.86 N + 1.8(15)^(1/2) N = 87.58 N
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Organizing data into a graph is an
example of
a. collecting data.
b. forming a hypothesis.
c. asking a question.
d. analyzing data.
a certain heat engine operating on a carnot cycle absorbs 450 j of heat per cycle at its hot reservoir at 145 ∘c and has a thermal efficiency of 26.0 % . part a how much work does this engine do per cycle?
The heat engine operating on a Carnot cycle absorbs 450 J of heat per cycle and does 117 J of work per cycle.
The work done by a heat engine can be determined using the formula:
Work = Efficiency x Heat Absorbed
In this case, the efficiency is given as 26.0% or 0.26. The heat absorbed per cycle is given as 450 J.
To find the work done per cycle, we can substitute these values into the formula:
Work = 0.26 x 450 J
Work = 117 J
Therefore, the heat engine does 117 J of work per cycle.
In conclusion, the heat engine operating on a Carnot cycle absorbs 450 J of heat per cycle and does 117 J of work per cycle.
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If a 60 W light bulb and a 75 W light bulb operate from 150 V source, which bulb has a greater current in it?
60 W
75 W
Answer:
Since it us the resistance that causes the power output, it might be intuitive to think that more resistance produces more power but as P=I^2 * R one actually needs high current and low resistqnce. That means 75 W has lower resistance and higher current.
Now you may think that making the resistance very low, one gets the most power. Not so, as the circuit has wires, power source etc. All the have their resistance. In theory one gets the maximum power over a resistor when the resistor is half of the total resistance of the circuit. This in practice would be inefficient as one would lose half of the total power elsewhere. In practice circuits have fuses that limit the current and one gets the maximum power at the current the fuse is rated to. So if there is 20 A fuse, the maximum power is 2400 W and the corresponding resistance 6 ohm.
Determine la resistencia equivalente de la "escalera" de
resistores iguales de 125 æ que se muestra en la figura 26-40.
En otras palabras, ¿qué resistencia registraría un óhmetro si se
conecta entre los puntos A y B? b) ¿Cuál es la corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B?
Las respuestas a cada inciso son:
a) La resistencia equivalente de la "escalera" de resistores iguales de 125 Ω que se muestra en la figura adjunta es:
\(R_{t} = 341.7 \: \Omega\)
b) La corriente a través de cada uno de los tres resistores de la izquierda si se conecta una batería de 50.0 V entre los puntos A y B es:
Correspondiente a R8 y R9 es 0.23 ACorrespondiente a R7 es 0.17 A.a) En la imagen adjuntada correspondiente a la Figura 26-40, podemos observar que las resistencias 1, 2 y 3 están en serie, por lo tanto la ressitencia equivalente entre estas 3 es:
\( R' = R_{1} + R_{2} + R_{3} \)
De aquí en adelante tendremos presente que las todas las resistencias son iguales entre sí y por ende igual a 125 Ω. Las notaciones del 1 al 9 son para poder mostrar la resolución del problema.
Entonces:
\( R' = 3R \)
Ahora, esta resistencia está en paralelo con la resistencia R₄, por lo tanto la resistencia equivalente entre estas dos es:
\( \frac{1}{R''} = \frac{1}{R'} + \frac{1}{R_{4}} = \frac{1}{3R} + \frac{1}{R} = \frac{4R}{3R^{2}} \)
\( R'' = \frac{3}{4}R \)
Luego, esta resistencia está en serie con las resistencias R₅ y R₆, por lo tanto:
\( R''' = R'' + R_{5} + R_{6} = \frac{3}{4}R + 2R = \frac{11}{4}R \)
Esta resistencia está ahora en paralelo con R₇, entonces:
\( \frac{1}{R''''} = \frac{1}{R'''} + \frac{1}{R_{7}} = \frac{4}{11R} + \frac{1}{R} = \frac{15R}{11R^{2}} \)
\( R'''' = \frac{11}{15}R \)
Finalmente, esta resistencis está en serie con las resistencias R₈ y R₉, por lo tanto la resistencia total es:
\(R_{t} = R'''' + R_{8} + R_{9} = \frac{11}{15}R + 2R = \frac{41}{15}R = \frac{41}{15}*125 \: \Omega = 341.7 \: \Omega\)
b) Para este inciso debemos usar la Ley de Kirchhoff, pues tenemos tres mallas. Supondremos que las corriente de cada malla fluiran en sentido horario, por lo tanto las ecuaciones de para cada malla serán:
Malla 1
Segun la ley de Ohm tenemos:
\(V-i_{1}R-i_{3}R=0\) (1)
Malla 2
\(-i_{2}R-i_{5}R-i_{2}R+i_{3}R=0\) (2)
Malla 3
\(-i_{4}R-i_{4}R-i_{4}R+i_{5}R=0\) (3)
Recordemos tambien que:
\(i_{1}=i_{2}+i_{3}\) (4)
\(i_{2}=i_{4}+i_{5}\) (5)
Lo que debemos hacer ahora es resolver el sistema de ecuaciones y encontrar los valore de las corrientes. Por lo tanto, los valores de las corrientes serán:
\(i_{1}=3/13\: A\)
\(i_{2}=4/65\: A\)
\(i_{3}=11/65\: A\)
\(i_{4}=1/65\: A\)
\(i_{5}=3/65\: A\)
Finalmente:
La corriente correspondiente a R8 y R9 es 0.23 ALa corriente correspondiente a R7 es 0.17 A.Pudes aprender mas de mallas aquí:
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If the current in the circuit is 10.5 A,
what is the potential difference across the
source?
(AI 0.750 V
(B) 9.19 V
(C) 12.0 V
(D) 49.0 V
(E) 147 V
Answer:
E) 147 V
Explanation:
Ra+Rb+Rc = 14.0
V = IR
V = (10.5)(14.0)
V = 147 V
The potential difference across the source will be c)12V
What is Ohm's law ?Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points .
since , R(A) , R(B) AND R(C) are in parallel combination , hence equivalent
resistance of the circuit will be
1/R = 1/R(A) + 1/ R(B) + 1/ R(C)
1/R= 1/2 + 1/4 +1/8
1/R = 7/8
R = 8/7 ohm
from ohm's law
Voltage = current * resistance
V( source ) = current (in circuit ) * R (equivalent resistance)
V = 10.5 * (8/7)
V = 12 V
The potential difference across the source will be c) 12V
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The Flash can travel 400 m in just 5.2 minutes. What is his average velocity in m/s?
Answer:
76.9231
Explanation:
Divide 400m by 5.2 to get the answer.
Speed = (distance) / (time to cover the distance)
Speed = (400 m) / (5.2 minutes)
Speed = (400 m) / (312 seconds)
Speed = 1.28 m/s
There's not enough given information to find his velocity.
(I'll be honest with ya, Flash: 1.28 m/s is no big deal. It's only about 2.87 miles per hour. My dog can walk faster than that, and so can most healthy people. If that's the best you can do, then you probably shouldn't be running around chasing bad guys.)
how many grams of matter would have to be totally destroyed to run a 50 −w lightbulb for 2.5 y ?
To run a 50 W lightbulb for 2.5 years, approximately 1.384 × 10⁸ grams of matter would have to be totally destroyed.
To calculate the amount of matter that would need to be destroyed, we can use Einstein's mass-energy equivalence principle, which states that mass and energy are interchangeable and related by the equation E = mc².
Power of the lightbulb: P = 50 W
Time: t = 2.5 years = 2.5 * 365 * 24 * 60 * 60 seconds
Total energy consumed: E = P * t = 50 W * 2.5 * 365 * 24 * 60 * 60 seconds
Using the mass-energy equivalence principle, E = mc², we can solve for the mass (m):
m = E / c²
Speed of light: c ≈ 3 * 10⁸ m/s
Substituting the values:
m = (50 W * 2.5 * 365 * 24 * 60 * 60 seconds) / (3 * 10⁸ m/s)²
Calculating the result:
m ≈ 1.384 * 10⁸ grams
Approximately 1.384 × 10⁸ grams of matter would need.
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To run a 50-watt lightbulb for 2.5 years, approximately 0.0438 grams of matter would have to be completely annihilated. This is based on the conversion of energy and mass according to Einstein's equation E = mc^2.
Explanation:Firstly, we need to convert the given time, 2.5 years, into seconds, which is the basic unit used in physics for time. So, 2.5 years equals approximately 2.5 * 365 * 24 * 60 * 60 = 7.89 * 10^7 (78900000) seconds.
Next, knowing that energy consumption of a device, such as a lightbulb, can be formulated as power times time, (E = Pt), the total energy needed for a 50-watt lightbulb to operate for 2.5 years would be: E = 50 Watts * 7.89 * 10^7 seconds = 3.94 * 10^9 (3940000000) Joules.
Now, using Einstein’s equation E = mc^2 (Energy equals mass times the speed of light squared), we can solve for the mass (m) with m= E/c^2. Given that the speed of light (c) is approximately 3 × 10^8 meters per second, the mass (m) destroyed to generate this amount of energy is roughly m = 3.94 * 10^9 Joules / (3*10^8)^2 = 4.38 * 10^-5 kg, or 0.0438 grams.
So, about 0.0438 grams of matter would need to be totally destroyed to run a 50-watt lightbulb for 2.5 years.
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A) 750gm
11. Ifa rectangular solid box of aluminum is heated, which of the following is not true?
A) Its mass remains constant
Cits density increase
B) Its volume increase
Do none of the above
Given :
A rectangular solid box of aluminum is heated.
To Find :
Which of the following is not true.
A) Its mass remains constant
C) its density increase
B) Its volume increase
D) none of the above
Solution :
We know, when an object is heated it expands.
Objects expands means that the volume increases but mass remains same by conservation of mass.
Since mass remains constant and volume increases.
So, density will decrease.
Hence, this is the required solution.