O
-200
Is the√8 a rational or irrational number?
irrational, because
its decimal
rational, because all
expansion does not radicals are rational
repeat
rational, because its
decimal expansion
eventually repeats
Sod
3980 207
irrational, because
all radicals are
irrational
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Dec 15

The answer is: for any value of c that is zero or negative, If c is positive, then limt[infinity]y(t) = infinity. If c is zero, then limt[infinity]y(t) = 0. And if c is negative, then limt[infinity]y(t) = 0.

To determine for what values of c the limit of y(t) as t approaches infinity is finite, we need to examine the behavior of the differential equation that defines y(t). Specifically, we need to look at the solution of the differential equation for different initial conditions and see whether the solution tends towards infinity or some finite value as t increases.
The differential equation that defines y (t) is typically written in the form:
dy/dt = f(y)
where f(y) is some function of y. We can think of this equation as describing the rate at which y is changing as a function of time. If f(y) is a positive function, then y will increase over time, and if f(y) is negative, then y will decrease over time. If f(y) is zero, then y will remain constant over time.
To see how the solution of the differential equation behaves for different initial conditions, we can use the method of separation of variables. Specifically, we can write the differential equation as:
dy/f(y) = dt
and integrate both sides with respect to their respective variables:
dy/f(y) = ∫ dt
This gives us:
ln|y| = t + C
where C is the constant of integration. Solving for y, we ge
y = Ce^t
where C = y(0) is the initial condition.
We can now see that the behavior of the solution depends on the value of C. If C is positive, then y will tend towards infinity as t increases since et grows exponentially. If C is zero, then y will remain constant over time. And if C is negative, then y will tend towards zero as t increases since et decreases exponentially.
So, The answer is: for any value of c that is zero or negative, If c is positive, then limt[infinity]y(t) = infinity. If c is zero, then limt[infinity]y(t) = 0. And if c is negative, then limt→[infinity]y(t) = 0.

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Answer:

metre squared (m²)

Step-by-step explanation:

metre×metre=metre squared (m²)

For the given triangle MNO, as per the given measurements the smallest angle among all the three angles is ∠M.

As given in the question,

In the given triangle MNO,

Measure of the sides of the triangle are as follow:

MN = 18 yd

NO = 17 yd

MO = 19 yd

Arrange them in ascending order we have,

17 < 18 < 19

NO < MN < MO

From the given measurement of the sides of the triangle , smallest side is NO.

Angle opposite to side MN = ∠O

Angle opposite to side NO = ∠M

Angle opposite to side MO = ∠N

Angle opposite to the smallest side is the smallest angle.

∠M is the smallest angle.

Therefore, for the given triangle MNO, as per the given measurements the smallest angle among all the three angles is ∠M.

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\( \frac{ab}{c} \)

\( \frac{4 \times - 5}{ - 2} \)

\( \frac{ - 20}{ - 2} \)

\( \frac{20}{2} \)

\( \frac{10}{1} \)

\(10\)

The covariance of their returns is approximately 0.0149601.

To calculate the covariance of the returns of two stocks, we need to multiply the difference between each pair of corresponding returns by the probability of each state, and then sum up these products. The formula for covariance is as follows:

Covariance = (Return_A1 - Mean_Return_A) * (Return_B1 - Mean_Return_B) * Probability_1

          + (Return_A2 - Mean_Return_A) * (Return_B2 - Mean_Return_B) * Probability_2

Where:

- Return_A1 and Return_A2 are the returns of stock A in state 1 and state 2, respectively.

- Return_B1 and Return_B2 are the returns of stock B in state 1 and state 2, respectively.

- Mean_Return_A and Mean_Return_B are the mean returns of stock A and stock B, respectively.

- Probability_1 and Probability_2 are the probabilities of state 1 and state 2, respectively.

Let's calculate the covariance:

Return_A1 = 1%

Return_A2 = 80%

Return_B1 = 12%

Return_B2 = -10%

Probability_1 = 0.85

Probability_2 = 0.15

Mean_Return_A = (Return_A1 * Probability_1) + (Return_A2 * Probability_2)

             = (0.01 * 0.85) + (0.8 * 0.15)

             = 0.0085 + 0.12

             = 0.1285

Mean_Return_B = (Return_B1 * Probability_1) + (Return_B2 * Probability_2)

             = (0.12 * 0.85) + (-0.1 * 0.15)

             = 0.102 - 0.015

             = 0.087

Covariance = (Return_A1 - Mean_Return_A) * (Return_B1 - Mean_Return_B) * Probability_1

          + (Return_A2 - Mean_Return_A) * (Return_B2 - Mean_Return_B) * Probability_2

          = (0.01 - 0.1285) * (0.12 - 0.087) * 0.85

          + (0.8 - 0.1285) * (-0.1 - 0.087) * 0.15

          = (-0.1185) * (0.033) * 0.85

          + (0.6715) * (-0.187) * 0.15

          = -0.00489825 + 0.01985835

          = 0.0149601

To calculate the correlation of their returns, we divide the covariance by the product of the standard deviations of the returns of each stock. The formula for correlation is as follows:

Correlation = Covariance / (Standard_Deviation_A * Standard_Deviation_B)

Let's assume the standard deviations of the returns for stock A and stock B are known. If we use σ_A for the standard deviation of stock A and σ_B for the standard deviation of stock B, we can substitute these values into the formula to calculate the correlation. However, if you provide the standard deviations, I can provide a more accurate calculation.

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Answer:

C

Step-by-step explanation:

1 word 5 seconds

so, it is totally clear what that means : 1 word in 5 seconds. she needs 5 seconds to type 1 word.

Answer: 9.31*10^-3

Step-by-step explanation:

The decimal number 0.00931 written in standard form is 9.31•10^-3

Estimated is 9•10^-3

Heart it if it helps!

The measures of triangle exists 45 45 90 then the length of the hypotenuse is 6√2 units.

Due to the fact that the triangle's legs are always the same length, d = 8. Always on the other side of the right angle is the hypotenuse. The hypotenuse of this triangle, represented by the letter e, is at its base. You must multiply the leg of a 45-45-90 triangle by the square root of two to determine the hypotenuse.

The hypotenuse of a 45°, 45°, and 90° triangle measures about two times the length of a leg.

In the right triangle ABC, AB is equal to AC

AB = AC = 6 units

BC is the hypotenuse

Applying the Pythagorean Theorem

BC² = AB² + AC²

substitute the values in the above equation, we get

BC² = 6² + 6²

Simplifying the above equation, we get

BC² = 72

BC = √72

BC = 6 √2 units

Therefore, the length of the hypotenuse is 6√2 units.

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Answer:

2a+110=180(co interior angle)

2a=180-110

a=70/2=35

2a=2×35=70

a=x=35 alternate angle

x+2a=y exterior angle of triangle is equal to the sum of two interior angle

35+70=y

y=105

Answer:

x=a

(being alternate angles)

x+2a=110°

(Being sum of interior angles opposite to exterior angles)

or, a +2a =110°

or, 3a=110°

or, a=110°/3

therefore, a=36.67

Now;

2a = 2×36.67

= 73.34

the answer I solved is wrong please don't write it

Answer:

1. The Venn diagrams are attached

2. When the statistics students number = 10·x + 3, we have;

The number of students that study

a. Algebra = 128/11

b. Statistic = 213/11

When the statistics students number = 2·x + 3, we have;

The number of students that study

a. Algebra = 16

b. Statistic = 15

Step-by-step explanation:

The parameters given are;

Total number of students = 30

Number of students that study algebra n(A) = x + 10

Number of students that study statistics n(B) = 10·x + 3

Number of student that study both algebra and statistics n(A∩B) = 4

Number of student that study only algebra n(A\B) = 2·x

Number of students that study neither algebra or statistics n(A∪B)' = 3

Therefore;

The number of students that study either algebra or statistics = n(A∪B)

From set theory we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 10·x + 3 - 4 = 27

11·x+13 = 27 + 4 = 31

11·x = 18

x = 18/11

The number of students that study

a. Algebra

n(A) = 18/11 + 10 = 128/11

b. Statistic

n(B) = 213/11

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11

However, assuming n(B) = (2·x + 3), we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 2·x + 3 - 4 = 27

2·x+3 + x + 10= 27 + 4 = 31

3·x = 18

x = 6

Therefore, the number of students that study

a. Algebra

n(A) = 16

b. Statistics

n(B) = 15

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11

The Venn diagrams can be presented as follows;

Following are the calculation for the given question:

Given:

Overall students is \(=30 \\\\\)

study algebra\(= (x+10) \\\\\)

study statistics\(= (10x+3) \\\\\)

study both algebra and statistics\(= 4\\\\\)

study only algebra\(= 2x \\\\\)

study neither algebra nor statistics\(= 3 \\\\\)

Calculating the  A.T.Q:  

\(\to 2x+4+10x-1+3=30\\\\\to 12x+6=30\\\\\to 12x=24\\\\\to x=\frac{24}{12}\\\\\to x=2\\\\\)

For question 2:

For point a:  

Calculating number of students in its study:

\(\to algebra= 4+4=8\)

For point b:  

Calculating number of students study only:

\(\to statistics= 19\)

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There are 18 different triples of natural numbers with a sum of 10, considering (1,8,1) and (8,1) as the same triple as (1,1,8).

To find the number of different triples of natural numbers with a sum of 10, we can consider different cases based on the value of the first number in the triple.

Case 1: The first number is 1.

In this case, we need to find the number of ways to represent 10 as a sum of the remaining two numbers. Since we have already considered (1,8,1) and (8,1) as the same triple as (1,1,8), we only need to find the ways to represent 10 using two numbers, excluding 1. The possible pairs are:

(2,8), (3,7), (4,6), (5,5)

Case 2: The first number is 2.

In this case, we need to find the number of ways to represent 8 as a sum of the remaining two numbers. The possible pairs are:

(1,7), (3,5), (4,4)

Case 3: The first number is 3.

In this case, we need to find the number of ways to represent 7 as a sum of the remaining two numbers. The possible pairs are:

(1,6), (2,5), (4,3)

Case 4: The first number is 4.

In this case, we need to find the number of ways to represent 6 as a sum of the remaining two numbers. The possible pairs are:

(1,5), (2,4), (3,3)

Case 5: The first number is 5.

In this case, we need to find the number of ways to represent 5 as a sum of the remaining two numbers. The possible pair is:

(1,4)

Case 6: The first number is 6.

In this case, we need to find the number of ways to represent 4 as a sum of the remaining two numbers. The possible pairs are:

(1,3), (2,2)

Case 7: The first number is 7.

In this case, we need to find the number of ways to represent 3 as a sum of the remaining two numbers. The possible pair is:

(1,2)

Case 8: The first number is 8.

In this case, we need to find the number of ways to represent 2 as a sum of the remaining two numbers. The only possible pair is:

(1,1)

Adding up the counts from each case, we get:

4 + 3 + 3 + 3 + 1 + 2 + 1 + 1 = 18

Therefore, there are 18 different triples of natural numbers with a sum of 10, considering (1,8,1) and (8,1) as the same triple as (1,1,8).

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hello,

we already know that for 2 hours of babysitting, Mara earned $25.

to find how much she'd make for 5 hours of babysitting:

divide 25 by 2 which gets us 12.50.

if mara were to babysit for 5 hours, she'd make $62.50.

I hope this was helpful =]

Answer:

+ x = 116/9

- x = 40

* x = -2/3 and x = 59/3

/ x =  -2/3

Step-by-step explanation:

Since it's unclear what operations here are all of them, plus, minus, multiply and divide. If you need Steps, let me know.

Answer:

False.

Step-by-step explanation:

Answer:

60

Step-by-step explanation:

60 times 2 is 120 plus 24 is 144

Since none of the 13 classmates had been given math homework between the original survey and Kelly's second survey, the sum of the values in the second data set is the same as the sum of the values in the original data set. Therefore, the change in the means can be determined without calculating the mean of either data set by considering the number of data points in each set.

Since both data sets have the same number of data points, the change in the means will be zero. This is because the mean is calculated by dividing the sum of the values by the number of data points, and since the sum of the values is the same in both data sets, the means will also be the same.

In other words, the change in the mean is calculated as follows:

Change in mean = Mean of second data set - Mean of first data set

Since none of the values in the second data set have changed, the mean of the second data set is the same as the mean of the first data set. Therefore, the change in the mean is:

Change in mean = Mean of second data set - Mean of first data set

= Mean of first data set - Mean of first data set

= 0

Thus, the change in the means between Kelly's original survey and her second survey is zero.

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Answer:

its 13

Step-by-step explanation:

are u try to find out what x and y equal

Answer:

20 18. on the answer is 18 and 20 give me the brainlyest

Answer:

Step-by-step explanation:

We observe the terms increase twice, therefore r = 2.

The missing terms are:

To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

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Answer:

3 x 3 = 9

Step-by-step explanation:

Answer: -12

Step-by-step explanation:

Answer:

∠F = 19.5

Step-by-step explanation:

180 - 127 - 33.5 = 19.5

Answer:

The cost for camping is 266 pounds

The cost for camping per night is 14 pounds

The cost for camping at the second campsite would be 114 pounds more than the first one.

Per night that is 6 pounds more if you needed that.

The derivative of the function at s=0 is approximately 258.

The derivative of the function\(r=[5(e4s-e-45)]/e45\)is:

\(r' = 5[(4e4s + 45e-45)e45 - e45(4e4s - e-45)(e45)]/e902\)

Plugging in s=0, we get:

\(r' = 5[(4 + 45)e45 - (4 - 1)(e45)]/e902\)

\(r' = 5[49e45 - 3e45]/e902\)

\(r' = 5(46e45)/e902\)

r' ≈ 258

Therefore, the derivative of the function at s=0 is approximately 258.

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The constant of proportionality of y and x in the graph is given as follows:

k = 3/4.

In a proportional relationship, the ratio between the output variable y and the input variable x is constant, and is called constant of proportionality, given as follows:

k = y/x.

A proportional relationship is a special case of a linear function, which has an intercept of zero, as is the case for the graph in this problem.

The marked point on the graph has the coordinates given as follows:

(4,3).

Meaning that the constant of proportionality of y and x in the graph is calculated as follows:

k = y/x = 3/4.

(division of the value of the y-coordinate by the value of the x-coordinate).

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Answer:

this is the answer I came up with hope this helps

Answer:

E. The absolute value and square root function share an x-intercept.

Step-by-step explanation:

Pre-Calc on Edge 2022

The area of the triangle for the given parameter is 12.4 squared cm.

How to calculate the area of the triangle?

In mathematics, the area of the triangle is classified into three forms isosceles, scalene and equilateral. Depending upon the sides of the triangle, it is classified. That means, when the two sides are equal then the triangle is isosceles triangle.

According to the question, the given parameters for the calculation of the area of the triangle is as written below:

Side of the triangle(a) = 5.2 cm. Angle of a triangle(B) = 67°.

Using standard formula for the area of the triangle, we get:

Area of the triangle = (1/2)(5.2)(5.2)sin(67°) = 12.4384 = 12.4 squared cm.

Hence, the area of the triangle for the given parameter is 12.4 squared cm.

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On solving the following question, the function that has domain of all real numbers is - \(y = -2(3X)^{\frac{1}{6} }\)

All numbers that we can recall are real numbers except complex numbers. The union of the set of rational numbers and the set of irrational numbers is the set of real numbers denoted by the symbol R.

A rational number is any number that can be expressed as the ratio p/q. The fraction's denominator is denoted by "q," while the numerator is represented by "p." "q" is not zero.

Both 5 and 1/2 are actual figures. X also defines a number, but since it's negative, it's an integer because it's rational.

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Answer:

I hope it's helpful.........