Observa el siguiente polígono y responde la pregunta.



¿Cuál es el perímetro del polígono?

A.
13mn3+4m2+3mn2+2mn
B.
53mn3+4m2+2mn2+2mn
C.
13mn3+3m2+4mn2+3mn
D.
53mn3+3m2+2mn2+3mn

The inequality that compares the score is written as -4 < x < - 1

The term inequality in math is defined as a relationship between two expressions or values that are not equal to each other

Here we have given that after playing 18 holes of golf, John's score was -4 and Terry's score was - 1.

While we looking into the given question, we have identified that

Total number of play = 18

John's score = - 4

Terry's Score = -1

Then here let us consider that 'x' represents the total score of Teri in the last six holes, then the pair of inequalities are

=> -4 < x < - 1

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Answer:

-2x - 2

Step-by-step explanation:

Step 1: Write expression

3 - (2x + 5)

Step 2: Distribute negative

3 - 2x - 5

Step 3: Combine like terms

-2x - 2

Answer:  put a dot at the place you  think 7 over 2 would be then put  one at -2 on the x axis then drawn a line

Step-by-step explanation:

The simplest form of the radical expression 4^(3√(3x)) + 5^(3√(10x)) cannot be determined without more information.

The given expression is 4^(3√(3x)) + 5^(3√(10x)). It appears to have a combination of exponentiation and radicals. However, it is unclear whether the exponent applies solely to the base numbers (4 and 5) or to the entire expression within the parentheses (3√(3x) and 3√(10x)). The expression can be interpreted in different ways, depending on the intended grouping of operations.

If the exponent only applies to the base numbers, the expression simplifies to 4^3√(3x) + 5^3√(10x). However, if the exponent applies to the entire expression within the parentheses, the expression would be written as (4^(3√(3x))) + (5^(3√(10x))). These two interpretations yield different results, and without further clarification or grouping, it is not possible to determine the simplest form of the expression.

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Answer:

take the length of each side, and multiply it by the number of sides I'm not sure why you have coordinates

Step-by-step explanation:

The ΔH (enthalpy change) for aluminum when it is heated from 0.0°C to 100.0°C is 2074.19 J.

The expression given for the temperature-dependent heat capacity of a substance is:

c_p = a + bT + cT^2

where c_p is the heat capacity in J/K, T is the temperature in °C, and a, b, and c are coefficients.

To calculate the ΔH (enthalpy change) for aluminum when it is heated from 0.0°C to 100.0°C, we need to integrate the heat capacity expression with respect to temperature over the given temperature range.

ΔH = ∫(c_p dT)

First, let's substitute the given coefficients into the expression:

c_p = 20.68 + (12.38×10^-3)T + 0

Next, we integrate the expression over the temperature range of 0.0°C to 100.0°C:

ΔH = ∫[20.68 + (12.38×10^-3)T] dT

Integrating with respect to T gives:

ΔH = 20.68T + (12.38×10^-3)(T^2/2)

To evaluate the integral, we substitute the upper and lower temperature limits:

ΔH = 20.68(100.0) + (12.38×10^-3)((100.0)^2/2) - [20.68(0.0) + (12.38×10^-3)((0.0)^2/2)]

Simplifying the equation gives:

ΔH = 2068 + 6.19

ΔH = 2074.19 J

Therefore, the enthalpy change (ΔH) for aluminum when it is heated from 0.0°C to 100.0°C is 2074.19 J.

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Answer:

77 feet

Step-by-step explanation:

Answer:

Step-by-step explanation:

which way do you have to reflect it? On the X or y axis?

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Define a slope of positive and negative line

A slant asymptote, just like a horizontal asymptote, guides the graph of a function only when x is close to but it is a slanted line, i.e. neither vertical nor horizontal. A rational function has a slant asymptote if the degree of a numerator polynomial is 1 more than the degree of the denominator polynomial.

A line that slants up from left to right has a positive slope. A line that slants down from left to right has a negative slope. Horizontal and vertical lines also have a slope.

STEP 2: Answer the question

Hence, the answer is "The line slants up"

OPTION D

As a result, the following equation can be used to determine t, or how many minutes it took to fill the tub with w liters of water: t = (w - 0.2) / 0.4

Slope is a unit used to describe how steep or slope a line is. The ratio of the vertical change (rise) to the horizontal change (run) between any two locations on the line is what is referred to as the slope. In other words, the slope of the line going through the two points (x1, y1) and (x2, y2), which are on a line, is given by: Slope is equal to y2 - y1 / x2 - x1. Positive, negative, zero, or undefinable slopes are all possible.

given

With the slope and y-intercept in hand, we can now write the line's equation:

y = 0.4x + 0.2

Given a value for y, we wish to find a solution to this equation for x. In this instance, we're looking for t, or how many minutes it took to fill the tub with w liters of water. We can solve for x by substituting w for y:

w = 0.4t + 0.2

0.4t = w - 0.2

t = (w - 0.2) / 0.4

As a result, the following equation can be used to determine t, or how many minutes it took to fill the tub with w liters of water: t = (w - 0.2) / 0.4.

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Answer:

(-x,-y)

Step-by-step explanation:

I checked inside the module where I learned it. So, I’m pretty sure this is the right answer.

Answer:

e3iuehe3ieeiuhiuwh3ewiuhd god igood great

Step-by-step explanation:

The calculated summation value with the message "Summation: " preceding it. The program assumes that the user will provide valid numerical inputs (integers) when prompted.

Here's a Python program that calculates the sum using a loop based on the user's input values for `i` and `k`. The program handles cases where `i` is larger than `k` and continuously asks for proper values until valid inputs are provided.

```python

while True:

   i = int(input("Enter value for i: "))

   k = int(input("Enter value for k: "))

   if i <= k:

       break

   else:

       print("Error: i cannot be greater than k.")

summation = 0

for x in range(i, k+1):

   summation += 2 * x

print("Summation:", summation)

```

In this program, we use a `while` loop to repeatedly prompt the user for values of `i` and `k`. We convert the inputs to integers using `int()` for numerical comparison. If the condition `i <= k` is satisfied, we break out of the loop; otherwise, an error message is displayed, and the loop continues.

Once we have valid values for `i` and `k`, we initialize the `summation` variable to 0 and use a `for` loop with `range(i, k+1)` to iterate through the values of `x` from `i` to `k` (inclusive). We accumulate the sum by adding `2 * x` to `summation` in each iteration.

Finally, we print the calculated summation value with the message "Summation: " preceding it.

Note: The program assumes that the user will provide valid numerical inputs (integers) when prompted.

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Answer:

there is no simplfying so this is the answer but what lesson is it?

Step-by-step explanation:

Answer: A. 33

Step-by-step explanation:

The company has an initial valuation of 1200

From the question, we have the following parameters that can be used in our computation:

Falls = 40%

Increase = 25%

Final valuation = $900

The final valuation of the company can be calculated using

Final valuation = Initial valuation * (1 - Falls) * (1 + Increase)

Substitute the known values in the above equation, so, we have the following representation

900 = Initial valuation * (1 - 40%) * (1 + 25%)

This gives

900 = Initial valuation * 0.75

Divide both sides by 0.75

Initial valuation = 1200

Hence, the initial valuation is $1200

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You can buy car A, because the acceptable rate is 14% and here car A has a rate of 20%

Given,

There are three different cars that you could buy. They differ in initial cost, annual operating costs, and life. Your minimum acceptable rate of return is 14%. Use the ROR method to select the best alternative.

Alternative            A             B                 C

Initial Cost          10,000     8,000       5,000

Annual Cost       1,000       1,500        1,500

Life                     8 years    8 years     5 years

Here,

Rate of Return of car A = (10,000 - 1000 x 8) / 100 = 2000/100 = 20%

Rate of Return of car B = (8,000 - 1500 x 8) / 100 = -4000/100 = -40%

Rate of Return of car B = (5,000 - 1500 x 5) / 100 = -2500/100 = -25%

That is,

You can buy car A, because the acceptable rate is 14% and here car A has a rate of 20%

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On factorizing 2v² + 4v = 6 the obtained solutions of the quadratic equation are v = 1 and v = -3.

What is factorization by splitting middle term?

The method of Splitting the Middle Term by factorization is where you divide the middle term into two factors. We know that composite numbers can be expressed as the product of prime numbers.

Rule to factorize trinomial expression where coefficients are real numbers, is to split b (the coefficient of x) into two real numbers such that the algebraic sum of these two numbers is b and their product is c, then factorize by grouping method.

According to the given question:

Factorizing 2v² + 4v = 6 by Splitting the Middle Term method

2v² + 4v = 6

2v² + 4v - 6 = 0

2v² + 6v - 2v - 6 = 0

2v(v+3) - 2(v+3) = 0

(2v-2)(v+3) = 0

Therefore the solutions are

2v - 2 = 0                                      v +3 = 0

v = 1                                                   v = -3

Hence on factorizing 2v² + 4v = 6 the obtained solutions of the quadratic equation are v = 1 and v = -3

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Answer:

150°

Step-by-step explanation:

The sum of the angles in a quadrilateral = 360°

Divide by the sum of the parts of the ratios to find the value of one part of the ratio.

sum of parts , 3 + 2 + 2 + 5 = 12 parts

360° ÷ 12 = 30° ← value of 1 part of the ratio , then

3 parts = 3 × 30° = 90°

2 parts = 2 × 30° = 60°

5 parts = 5 × 30° = 150°

The largest angle in the quadrilateral is 150°

Answer:

Step-by-step explanation:

Rectangles have 2 pairs of equal sides that means:

2(4x) and 2(3x+2)

8x and 6x+4

8x+ (6x + 4) = 14x + 4

The answer is that Point D is Circumcentre and other lengths DE,DF,DG are perpendicular bisectors of sides of triangle ABC

What is Circumcentre?

The point of intersection of Perpendicular bisectors in a triangle is called called Circumcentre.

Solution;

The circumcentre is equidistant from all sides of an triangle when we draw the perpendicular from this point to sides of triangles, the length of all perpendiculars will be same and this is its another property

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Answer:

5/3

Step-by-step explanation:

to find the slope, we have to use the formula y2-y1 over x2-x1. Now, plug in our values; 8-28 over 6-18. Our answer becomes -20 over -12 this simplifies to 5 over 3, and there's your answer.

Answer:

4(2x+1)=-28

2x+1=-7

2x=-7-1

2x=-8

x=-4

The general solution of the differential equation y"-8y+15y=0 is \(y(t) = C_{1}sinh(\sqrt{3}t) + C_{2}sinh(\sqrt{5}t)\), where \(C_{1}\) and \(C_{2}\) are constants of integration

The characteristic equation for this differential equation is r^2 - 8r + 15 = 0, which factors as (r-3)(r-5) = 0. Therefore, the roots are r=3 and r=5.

The general solution of the differential equation is \(y(t)= C_{1}e^{3t}+C_{2}e^{5t}\), where \(C_{1}\)  and \(C_{2}\) are constants of integration.

we can write this as: \(y(t)= C_{1}sinh(at)+  C_{2} sinh(bt)\), where a and b are the square roots of the roots of the characteristic equation, i.e. \(a=\sqrt{3}\) and \(b=\sqrt{5}\).

Therefore, the general solution of the differential equation y"-8y+15y=0 is \(y(t) = C_{1}sinh(\sqrt{3}t) + C_{2}sinh(\sqrt{5}t)\), where \(C_{1}\) and \(C_{2\) are constants of integration.

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Using the arithmetic operations -

a) For the expression \((2.3\times10^4) \times (1.5\times10^{-2})\) the value is 345.

b) For the expression \((3.6\times10^{-5}) \div (1.8\times10^2)\) the value is \(2 \times 10^{-56}\).

What is arithmetic operation?

A subject of mathematics known as arithmetic operations deals with the study and use of numbers in all other branches of mathematics. Basic operations including addition, subtraction, multiplication, and division are included.

a) The scientific notation expression is given as -

\((2.3\times10^4) \times (1.5\times10^{-2})\)

Using the rule \(a \times 10^m \times b \times 10^n = ab \times 10^{(m+n)}\) -

\((2.3 \times 1.5) \times (10^4 \times 10^{-2})\)

Apply the arithmetic operation of multiplication -

= 3.45 x 10²

= 345 (in standard form)

Therefore, the value is obtained as 345.

b) The scientific notation expression is given as -

\((3.6\times10^{-5}) \div (1.8\times10^2)\)

Using the rule \(\frac{a \times 10^m}{b \times 10^n} = \frac{a}{b} \times 10^{(m-n)}\) -

\(\frac{3.16}{1.8} \times \frac{10^{-54}}{10^2}\)

Apply the arithmetic operation of division -

\(2 \times 10^{-56}\)

\(2 \times 10^{-56}\)(in standard form)

Therefore, the value is obtained as \(2 \times 10^{-56}\).

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Below is the Python code to simulate the probability of pulling a gold marble.

Python

import random

def simulate_pulling_gold_marble(num_trials):

 num_gold_marbles = 0

 for _ in range(num_trials):

   marble = random.choice(["gold", "red", "blue", "green"])

   if marble == "gold":

     num_gold_marbles += 1

 return num_gold_marbles / num_trials

def main():

 num_trials = 10000

 probability = simulate_pulling_gold_marble(num_trials)

 print("The probability of pulling a gold marble is", probability)

if __name__ == "__main__":

 main()

This code simulates pulling a gold marble 10,000 times. Each time a marble is pulled, it is put back in the bag so that the probability of pulling a gold marble remains the same each time. The code then calculates the proportion of times a gold marble was pulled and prints the probability.

To run the simulation, you can save the code as a Python file and then run it from the command line.

python simulation.py

The output of the simulation should be something like this:

The probability of pulling a gold marble is 0.2433

This means that the probability of pulling a gold marble is about 24%

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Answer:

The constant of proportionality is the ratio between two directly proportional quantities.

Step-by-step explanation:

Step-by-step explanation:

There is always the same relationship

In other words: If we divide any quantity of one of the magnitudes by the one that corresponds to it in the other, the value it gives us is always the same. This value is known as the PROPORTIONALITY CONSTANT

Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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Using Naïve Bayes multinomial with alpha=1, we classify the given messages based on their content. Message 4, "Tokyo Japan Chinese," is classified as spam.

To classify the messages using Naïve Bayes multinomial, we consider the content of the messages and their corresponding classifications. We calculate the probabilities of each message belonging to the "Normal" or "Spam" classes.

3 messages are classified as "Normal."

1 message is classified as "Spam."

We calculate the probabilities as follows:

P(Class = Normal) = 3/4 = 0.75

P(Class = Spam) = 1/4 = 0.25

Next, we analyze the occurrence of words in each class:

For the "Normal" class:

The word "Chinese" appears 5 times.

The word "Beijing" appears 1 time.

The word "Shanghai" appears 1 time.

The word "Macao" appears 1 time.

For the "Spam" class:

The word "Tokyo" appears 1 time.

The word "Japan" appears 1 time.

The word "Chinese" appears 1 time.

Now, we calculate the probabilities of each word given the class using Laplace smoothing (alpha=1):

P(Chinese|Normal) = (5 + 1)/(5 + 4) = 6/9

P(Beijing|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Shanghai|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Macao|Normal) = (1 + 1)/(5 + 4) = 2/9

P(Tokyo|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Japan|Spam) = (1 + 1)/(3 + 4) = 2/7

P(Chinese|Spam) = (1 + 1)/(3 + 4) = 2/7

To classify Message 4, "Tokyo Japan Chinese," we compute the probabilities for each class:

P(Normal|Message 4) = P(Chinese|Normal) * P(Tokyo|Normal) * P(Japan|Normal) * P(Class = Normal)

≈ (6/9) * (0/9) * (0/9) * 0.75

= 0

P(Spam|Message 4) = P(Chinese|Spam) * P(Tokyo|Spam) * P(Japan|Spam) * P(Class = Spam)

≈ (2/7) * (2/7) * (2/7) * 0.25

≈ 0.017

Since P(Spam|Message 4) > P(Normal|Message 4), we classify Message 4 as spam.

In summary, using Naïve Bayes multinomial with alpha=1, we classify Message 4, "Tokyo Japan Chinese," as spam based on its content.

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The maximum profit is 6 and it is obtained when we mix 0.6 kg of type A, 0 kg of type B, and 0.4 kg of type C.

The optimal mix for the maximum profit can be found as follows:

The company mixes three types of toffees, A, B, and C. Let the weights of type A, B, and C be a, b, and c kg, respectively. Let us assume that we are making 1kg of toffee pack. Therefore, the weight of type C should be 1 - (a + b) kg. Also, the mixture must contain at least 300 gms of type A i.e a >= 0.3 kg

Also, the weight of the first two types (A and B) must be at least equal to the weight of type C, i.e a + b >= c. This condition can also be written as a + b - c >= 0

Let us now calculate the total cost of making 1kg of toffee pack.

Cost = 20a + 10b + 5c

If the pack is sold at Rs. 17, then the profit per 1kg of toffee pack is by

Profit = Selling Price - Cost = 17 - (20a + 10b + 5c)

Now we have the following linear programming problem:

Maximize P = 17 - (20a + 10b + 5c)

Subject to constraints: a + b + c = 1 (since we are making 1kg of toffee pack)

a >= 0.3a + b - c >= 0a, b, c >= 0

We can use the simplex method to solve this linear programming problem. However, to save time, we can solve it graphically. The feasible region is as follows:

We can see that the corner points of the feasible region are: (0.3, 0, 0.7), (0.6, 0, 0.4), (0, 0.5, 0.5), and (0, 1, 0).

Let us calculate the profit at each of these corner points. For example, at the point (0.3, 0, 0.7), we have a = 0.3, b = 0, and c = 0.7. Therefore, the profit is

P = 17 - (20(0.3) + 10(0) + 5(0.7)) = 3.5

Similarly, we can calculate the profit at the other corner points as well. The corner point (0.3, 0, 0.7) gives a profit of 3.5

Corner point (0.6, 0, 0.4) result in a profit of 6

Corner point (0, 0.5, 0.5) results in a profit of 5

Corner point (0, 1, 0) gives a profit of 3

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Answer:

A) f(x) = x^2 +8(x+2)

Step-by-step explanation:

We will start by putting y=0

0 = x^2+8(x+2) -Apply distributive property

0 = x^2+8x+16

0=(x+4)(x+4)

0=x+4, 0=x+4

x=-4

There is only one zero, and that is x=-4

Brainiest would be appreciated.

First one

Because

If we solve for x

Option A