Of the five buying decisions that customers make, which is the final question that they
ask themselves?
1.Why should I buy from you?
2.What is appealing or unique about your product or service?
3.Is the product or service I'm about to purchase worth the investment?
4.When should I make this decision?

Answer:  2: an equation in the form y = mx + b

1. An x/y table may have two entries with the same x; not a function in that case.

2.  That's a line with a slope; for each x there's a single y, definitely a function

3.  Ordered pairs -- like the table, the same x with different ys is possible, which wouldn't be a function.

4. List of numbers  -- a list isn't a function, at least not without more context

Answer:

Step-by-step explanation:

\(2.5 {}^{2} - 2.89 \div 17 \\ 6.25 - 2.89 \div 17 \\ 3.36 \div 17 \\ 6.08..is \: the \: answer.\)

Answer:

125

Step-by-step explanation:

using the rule of exponents

\((\frac{a}{b}) ^{-n}\) = \((\frac{b}{a}) ^{n}\)

then

\((\frac{1}{5}) ^{-3}\)

= \((\frac{5}{1}) ^{3}\)

= 5³

= 125

The number of miles in 4 weeks is 20 mules

From the question, we have the following parameters that can be used in our computation:

Stone runs 1 mile five times a week

This means that the rate is

Rate = 1 mile * 5 per week

So, we have

Rate = 5 miles per week

For 4 weeks, we have

Distance = 5 * 4

Evaluate

Distance = 20 miles

Hence, the distance is 20 miles

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Answer:

$39

Step-by-step explanation:

The correct option is (a) two factors and three levels. The design has two factors (time of day) and three levels (7 a.m., noon, and 5 p.m.).

In this research design, the factor is the time of day and it has three levels: 7 a.m., noon, and 5 p.m. The researcher is conducting an ANOVA test to measure the influence of the time of day on reaction time.

The factor is the time of day, and it has three levels: 7 a.m., noon, and 5 p.m. The ANOVA test will help determine if there are any significant differences in reaction times between these three periods throughout the day.

Therefore, the design has two factors (time of day) and three levels (7 a.m., noon, and 5 p.m.). The ANOVA test will be used to analyze the influence of the time of day on reaction time.

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Step-by-step explanation:

a+b+c=78

b=10+a

c=2b

then, we back the first

a+10+a+2b=78

2a+2b=78- 10

2a+2(10+a)=68

2a+2a=48

4a=48

a=12

b=22

c=44

The tip of her shadow moving when she is 35 feet from the base of the pole is 8.77 feet.

Let H = the height of the pole.

h = the height of the woman.

x = the length of the woman's shadow.

s = the distance from the pole to the woman.

By similar triangles,  H/h = (s + x)/x  or  Hx = h(s + x).

Differentiating, H dx/dt = h(ds/dt + dx/dt)

⇒ 17 dx/dt = 6(6 + dx/dt)

                  = 36 + 6 dx/dt

                  = 13 dx/dt

                  = 36

⇒ dx/dt = 36/13 ft/sec = 2.77 ft/sec for how fast her shadow is lengthening.

The speed of the tip of her shadow would be this speed added to her traveling speed: 2.77 + 6 = 8.77 ft/sec.

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Answer:

"certain"

Step-by-step explanation:

by definition, any event with a probably of 1 is defined as certain (i.e certain to happen)

by contract any even with a probably of 0 is defined as impossible (i.e impossible to happen)

Answer:

18

Step-by-step explanation:

divide them

Based on the information in the graph, we can infer that the missing numbers are: 9, 4, 19, 30, 84, 16, 8, 22, and 40.

To complete the table correctly we must identify the columns or rows with more data. These will be the easiest to complete. First of all, we must fill in those that already have a number in the total box because we can add the available numbers and later subtract them from the total to identify the missing number.

We can also find the numbers in the total cells by adding all the numbers in a column or row to find this result. Finally, the boxes that are being completed serve as clues to complete the others.

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Error control, flow control, segmentation and reassembly, multiplexing, and connection setup are five tasks that a layer can perform.

Flow control: It is the efficient management of data flow between two or more devices like computers or nodes of a network.

Error control: The identification and correction of errors that occur during the transmission of data is called error control.

Segmentation and reassembly: Data to be transmitted is divided into small parts or chunks for convenience. This process is called segmentation. The combining of these chunks to reform the original data is called reassembling.

Multiplexing: The process of combination of digital data streams in one signal over a shared medium is known as multiplexing.

Connection setup: Establishing a connection between two devices that are connected to the same network is called connection setup.

All these tasks can be duplicated at different layers.

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Answer: 3750

Step-by-step explanation:

Answer:

8218.406
Go through the process yourself to make sure my answer is correct

Step-by-step explanation:

The best way to solve these problems is by breaking them up into the difference shapes you see

A. Semi-sphere

The volume of a sphere is \(\frac{4}{3} \pi r^3\). Since we have a semi-sphere, we divide this by 2 and get:

\(V=\frac{4}{6} \pi r^3\\\\V= \frac{4}{6} \pi (12)^3\\\\V=3619.115\)

B. Cone

The volume of a cone is \(\pi r^2\frac{h}{3}\)

\(V = \pi (12)^2\frac{30.5}{3}\\V = 4599.292\)

C. Add

Add these two values:

3619.115 + 4599.292 = 8218.406

A Type I error is the incorrect rejection of a true null hypothesis. A Type II error is the failure to reject a false null hypothesis. The level of significance (alpha) determines the trade-off between these two types of errors.

The p-value is used to help determine whether or not the null hypothesis is statistically significant, which is used to make decisions based on sample data. If the p-value is less than or equal to the alpha level, it is considered significant, and the null hypothesis is rejected.

If the p-value is greater than the alpha level, it is not significant, and the null hypothesis is not rejected. Large p-values indicate that there is insufficient evidence to reject the null hypothesis. An alpha level is the probability of making a Type I error, which is the likelihood of rejecting the null hypothesis when it is true. The level of alpha is determined by the researcher and is usually set at 0.05 or 0.01.

For a result to be statistically significant, it means that it is unlikely that the result occurred due to chance. The significance level (alpha level) must be lower than the p-value to consider the result significant.

A 95% confidence interval corresponds to a two-sided hypothesis test at an alpha level of 0.05. A 90% confidence interval corresponds to a one-sided hypothesis test at an alpha level of 0.1.A Type I error is the incorrect rejection of a true null hypothesis. A Type II error is the failure to reject a false null hypothesis. The level of significance (alpha) determines the trade-off between these two types of errors.

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The elimination method is a technique used to solve a system of linear equations by eliminating one variable at a time.

If the coefficients of the variables are already the same, no multiplication is necessary and you can simply add or subtract the equations to eliminate the variable.

y = 9x - 23

y = x + 1

9x - y = 23

x - y = -1

8x = 24

x = 3

3 - y = -1

y = 4

x + y = 3

x - y = 7

2x = 10

x = 5

5 + y = 3

y = 3 - 5

y = -2

7x - 4y = -11

7x - 10y = 25

6y = -36

y = -6

7x - 4(-6) = -11

7x = -11 + 24

x = 13/7

4x - 2y= - 30 ---- x1

-x - 2y = 5 ----- x4

4x - 2y = -30

-4x - 8y = 20

-10y = -10

y = 1

4x - 2(1) = -30

x = -7

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Step-by-step explanation:

To find the vector parametric equation for the parabola from the origin to a point P, we need to express the position vector of P as a function of a parameter. Let's assume the coordinates of P are (x, y).

(a) Vector Parametric Equation for the Parabola: We can represent the position vector of P as a linear combination of two vectors. The first vector will point from the origin to P, and the second vector will be perpendicular to it.

Let's consider the vector from the origin to P as OP. Since P lies on the parabola, the magnitude of OP is given by the equation y = x^2. Therefore, the magnitude of OP is √(x^2 + (x^2)^2) = √(x^2 + x^4).

The unit vector in the direction of OP can be found by dividing OP by its magnitude: u = OP / √(x^2 + x^4).

To find a perpendicular vector, we can take the cross product of u with the vector (0, 0, 1) (which is perpendicular to the xy-plane). This will give us a vector perpendicular to the plane containing the parabola.

Let's call the perpendicular vector v. The cross product of u and (0, 0, 1) is given by: v = u × (0, 0, 1).

Finally, the vector parametric equation for the parabola from the origin to P is given by: r(t) = tu + tv, where t is the parameter ranging from 0 to 1.

(b) Line Integral along the Parabola: To find the line integral of a vector field F along the parabola from the origin to P, we need to evaluate the line integral: ∫(F · dr) from 0 to 1, where F is the vector field, dr is the differential vector along the parabola, and the integral is taken with respect to t.

The line integral can be calculated as follows: ∫(F · dr) = ∫(F · (du/dt) dt), where du/dt is the derivative of the unit vector u with respect to t.

Substituting r(t) = tu + tv into the above expression, we can find the line integral.

Please provide the vector field F so that I can assist you further in evaluating the line integral.

The tread life of tires on light-duty trucks follows a normal distribution with a mean of 60,000 miles and a standard deviation of 4,000 miles. We need to determine the likelihood that the mean tire life of a set of four tires falls between 57,000 and 63,000 miles.

Since we are dealing with the mean tire life of a set of four tires, we need to consider the sampling distribution of the sample mean. According to the Central Limit Theorem, when the sample size is large, the sampling distribution of the sample mean will approach a normal distribution, regardless of the shape of the population distribution.

In this case, since the sample size is four, we can assume that the sampling distribution of the sample mean will be approximately normally distributed. The mean of the sampling distribution of the sample mean will be equal to the population mean, which is 60,000 miles.

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1. P(X) = 7/15

2. P(Y|X) = 2/3

3. P(Y|X') = 1 - P(Y|X) = 1 - 2/3 = 1/3

1. P(X) is the probability of event X occurring and is given as 7/15.

2. P(Y|X) is the conditional probability of event Y given that event X has occurred. It is given as 2/3, which means that if event X has occurred, the probability of event Y occurring is 2/3.

3. P(Y|X') is the conditional probability of event Y given that event X has not occurred. It is equal to 1 minus the conditional probability of Y given X, which is 1 - 2/3 = 1/3. This means that if event X has not occurred, the probability of event Y occurring is 1/3.

Based on the given probabilities, we can conclude that events X and Y are dependent because the probability of Y occurring depends on whether X has occurred or not. If X occurs, the probability of Y occurring is 2/3, and if X does not occur, the probability of Y occurring is 1/3. If the events were mutually exclusive, the conditional probability of Y given X or X' would be 0.

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Answer:

y = 4 - 2x

Step-by-step explanation:

That is the formula, in y = a + mx but it you want it in y = mx+c, it is y = -2x + 4

A symmetrical distribution of exam scores in a college course indicates that the student's scores are evenly distributed across the entire range of scores. This suggests that about an equal number of students had relatively high and relatively low scores.

Correct answer will be b) About an equal number of students had relatively high and relatively low scores.

And that there is no single group that overwhelmingly outperformed or underperformed the others. Furthermore, it indicates that there were a substantial number of students who achieved high scores, as well as a substantial number who achieved low scores.

This type of even distribution of scores is often seen when students are equally prepared, and when the exam is designed to be neither too difficult nor too simple.

In conclusion, a symmetrical distribution of exam scores suggests that the students were similarly prepared and that the exam was appropriately challenging.

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A box plot shows the minimum, maximum, median, and any outliers of a data set. It does not show individual values in the data set. Therefore, options A, C, D, and E are the correct answers.

A box plot is a graphical representation of a data set that displays the median, individual values, outliers, minimum, and maximum of the data set.

The box plot is created by drawing a box from the lower quartile, or the 25th percentile, to the upper quartile, or the 75th percentile, with a line in the middle of the box representing the median of the data set.

The individual values in the data set are represented by dots, marks, or lines outside of the box. Outliers, or values that are significantly different from the rest of the set, are also represented outside of the box. T

he minimum and maximum of the data set are typically represented by either a line or a dot outside of the box.

Therefore, options A, C, D, and E are the correct answers.

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Therefore, 3/10 of students don't like having class outside on days when it's humid outside.

An expression for a portion of a whole is a percentage. It is made up of two components, the numerator and the denominator, which are separated by a fraction bar. The denominator is the total number of components that make up the whole, whereas the numerator is the number of parts that are being taken into account. For instance, the fraction 3/5 denotes three of a whole's five equal portions. "Three-fifths" can be interpreted as the word. The fraction 2/7, for example, indicates two parts out of seven equally sized parts of a whole.

given

If seven out of ten students opt to attend class outside on warm days, then the remaining three do not.

This can be expressed as a fraction:

3/10

Therefore, 3/10 of students don't like having class outside on days when it's humid outside.

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Answer:

5.905

Step-by-step explanation:

Formula

For an approximate result, multiply the length value by 3.281

1.8 × 3.281 = 5.905

-TheUnknownScientist

The value of the investment at the end of 6 years is $105

How to calculate the value of investment ?

Sanjay invests $700 in an open account

The account pays a simple interest rate of 2.5%

Therefore the value of the investment after 6 years can be calculated as follows

Principal × rate × time/100

= 700 × 2.5 × 6/100

= 10,500/100

= 105

Hence the value of the investment after 6 years is $105

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Answer:

8. -1

6-9=-3

-3/3=-1

Answer:

total amount of students in the class = 24

the amount of boy students in the class = 8

the amount of girl students in the class = ?

a) we know how many boys are in so B=8/24

b) know you calculate the amount of girl students in the class

totally they are 24 students are found we know the boys then the last are girls to know how many girls are in there

24 - 8 = 16 girls.

G=16/24

Answer:

The median is 82

Step-by-step explanation:

Order least to greatest

66, 66, 66, 78, 82, 82, 85, 97, 98

Eliminate one from each side until you get the one in the center of all of the numbers

In this case, it is 82

Hope this helps!