On Earth, a person can jump vertically and rise to a height h Part A What is the radius of the largest spherical asteroid from which this person could escape by jumping straight upward? Assume that each cubic meter of the asteroid has a mass of 3200 kg O 3300 km h O 3300 ma h O 3300 km2. O 3300 1/m-

Answer:

A. 0.5m/s².

B. –0.5m/s².

C. –0.5m/s².

D. 100m.

Explanation:

A. Determination of the acceleration in the first 20s.

Initial velocity (u) = 0

Final Velocity (v) = 10m/s

Time (t) = 20secs.

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (10 – 0)/20 = 10/20

a = 0.5m/s²

Therefore, the acceleration of the cyclist in the first 20secs is 0.5m/s²

B. Determination of the acceleration between 20 and 30s. This can be obtained as follow:

Initial velocity (u) = 10m/s

Final Velocity (v) = 5m/s

Time (t) = 30 – 20 = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (5 – 10)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the 20 and 30secs is

–0.5m/s².

C. Determination of the acceleration in the last 10s.

Initial velocity (u) = 5m/s

Final Velocity (v) = 0

Time (t) = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (0 – 5)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the last 10secs is

–0.5m/s².

D. Determination of the distance travelled by the cyclist when he was moving at a constant speed.

Velocity (v) = 5m/s

Time (t) = 50 – 30 = 20secs

Displacement (d) =?

Velocity = Displacement /Time

v = d/t

5 = d/20

Cross multiply

d = 5 x 20

d = 100m

Therefore, the distance travelled by the cyclist at constant speed is 100m

Answer:

10 N

Explanation:

\(f = ma\)

= 10m/s^2 * 1 kg

=10N

The average force exerted by the club on the ball is 838,400 N. Force can be characterized by its magnitude, direction, and point of application.

It can be a push or pull, and it can cause an object to start moving, stop moving, or change its direction of motion.

Force is indeed a physical factor that alters or has the potential to alter an object's state at rest or motion as well as its shape. Newton is the SI unit of force.

Finally, the average force exerted by the club on the ball is:

F = I / t = (1676.8 N·s) / (0.0020 s) = 838,400 N

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The absolute pressure of the seawater on the outside of the submarine is approximately 20.725 MPa.

To calculate the absolute pressure, we can use the hydrostatic pressure formula, which states that the pressure at a certain depth in a fluid is equal to the product of the density of the fluid, the acceleration due to gravity, and the depth. The formula is given by \(P = ρ * g * h\), where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.

Given that the submarine is located 2,000 km (or 2,000,000 meters) below the surface, and the density of seawater is \(1,025 kg/m^3\), we can substitute these values into the formula. The acceleration due to gravity, g, is approximately 9.8 m/s^2.

\(P = (1,025 kg/m^3) * (9.8 m/s^2) * (2,000,000 m) = 20,725,000,000\)

\(N/m^2, or 20.725 MPa (megapascals).\)

Therefore, the absolute pressure of the seawater on the outside of the submarine is approximately 20.725 MPa.

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Answer:

F+20Hz

Explanation:

At 0.0804 km altitude the 1% of the mass of the atmosphere lies above and 99% of the mass lies below. Assumptions made are the global mean surface pressure of 1000 hPa is a representative value and the scale height is assumed to be constant throughout the entire atmosphere.

First, we need to calculate the pressure at the desired percentiles (1% and 99%) relative to the surface pressure.

For 1% of the mass lying above, we consider the pressure to be 1% of the surface pressure:

1% of 1000 hPa = 0.01 × 1000 hPa

= 10 hPa.

For 99% of the mass lying below, we consider the pressure to be 99% of the surface pressure:

99% of 1000 hPa = 0.99 × 1000 hPa

= 990 hPa.

Next, we use the exponential relationship between pressure and altitude:

P = P0 × exp(-z/H),

where P is the pressure at a given altitude, P0 is the surface pressure, z is the altitude, and H is the scale height.

To find the altitude z at which the pressure is equal to 10 hPa (1% of the surface pressure), we rearrange the equation:

10 hPa = 1000 hPa × exp(-z/H).

Taking the natural logarithm (ln) of both sides, we have:

ln(10 hPa / 1000 hPa) = -z / H.

ln(0.01) = -z / 8 km.

z = -8 km × ln(0.01).

Evaluating the expression:

z = -8 km × (-4.605)

= 36.84 km.

Therefore, 1% of the mass of the atmosphere lies above an altitude of approximately 36.84 km.

Similarly, to find the altitude z at which the pressure is equal to 990 hPa (99% of the surface pressure), we follow the same procedure:

990 hPa = 1000 hPa × exp(-z/H).

ln(990 hPa / 1000 hPa) = -z / H.

ln(0.99) = -z / 8 km.

z = -8 km × ln(0.99).

Evaluating the expression:

z = -8 km × (-0.01005)

= 0.0804 km.

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An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The  pressure at the point on the wing is  \(P = 6.96 * 10^4 N/m^2\).

To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.

The equation is as follows:

P + 1/2 * ρ * \(V^2\) = constant

where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.

Given:

\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)

ρ = \(0.909 kg/m^3\) (density of the fluid)

\(V_1 = 42 m/s\) (velocity of the airplane)

\(V_2 = 88 m/s\) (velocity at the point on the wing)

To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:

\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\)  * ρ * \(V_2^2\)

Substituting the given values:

\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)

Simplifying the equation:

\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)

7.01 × 10^4 + 804.906 = P + 3526.242

\(P + 4329.148 = 7.01 *10^4\)

\(P = 7.01 * 10^4 - 4329.148\)

\(P = 6.96 * 10^4 N/m^2\)

Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)

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Answer:

1. The three main acidic gases responsible for lowering the pH of rainwater are non-metal oxides produced by the burning of fossil fuels like coal, oil and natural gas. Sulfur dioxide is produced when fossil fuels containing sulfur impurities are burned.

2. A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power. Renewable energy sources help reduce acid rain because they produce much less pollution.

3. The pH scale is logarithmic, meaning that an increase or decrease of an integer value changes the concentration by a tenfold. For example, a pH of 3 is ten times more acidic than a pH of 4.

The angular momentum of the moon around the earth is 2.92 * \(10^{34}\) kg \(m^{2}\)/s

Angular momentum a vector quantity that is a measure of the rotational momentum of a rotating body or system, that is equal in classical physics to the product of the angular velocity of the body or system and its moment of inertia with respect to the rotation axis, and that is directed along the rotation axis.

m (mass of moon ) = 7.4 * \(10^{22}\) kg

orbit = 3.8 * \(10^{8}\) m

L = I ω

  = m \(r^{2}\)ω

  = 7.4 * \(10^{22}\)  * \((3.8 *10^{8} )^{2}\) * (2π / 27 * 24 * 3600)

  = 2.92 * \(10^{34}\) kg \(m^{2}\)/s

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The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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A fish under water appears to be at a different depth than it actually is due to the refraction of light as it passes through the water.

When light travels through a medium with a different index of refraction, such as air to water, it bends, or refracts. This causes objects to appear displaced, or closer or farther away than they actually are. Because water has a higher refractive index than air, light bends more when it enters the water, causing objects, like fish, to appear closer to the surface than they actually are.

The result is that the fish will appear to be deeper in the water than it actually is.

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Although a magnet can change the direction of travel of an electron beam, it cannot change its charge. The charge of an electron is a fundamental property and is not affected by magnetic fields.

A magnet is an object or material that produces a magnetic field, which can exert attractive or repulsive forces on other magnets or magnetic materials. It has a north pole and a south pole with opposite magnetic polarities. Magnets can be natural or artificial, and they are used in numerous applications like electric motors, generators, speakers, magnetic storage devices, and medical imaging machines. They play a crucial role in various industries and scientific fields where the manipulation of magnetic fields is necessary.

They are also commonly used in magnetic compasses for navigation and in various industrial and scientific applications where the manipulation of magnetic fields is required.

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Answer:

The answer is B - the bending of rock layers happens due to stress, and this process is called folding. Faults are when it looks broken/displaced

Answer:

See explanation

Explanation:

The question is incomplete, as the required parameters are missing. The general solution to this is as follows;

First, get the mass (m) and the acceleration (a) of the sled

So, the force (f) to stop the sled is:

\(f = ma\) ---- Newton 2nd law

However, the force to stop the sled will be in the opposite direction of the sled.

So:

\(f =-ma\)

Assume that:

\(m \to 5kg\)

\(a \to 6m/s^2\)

The required force is:

\(f =-ma\)

\(f =-5kg * 6m/s^2\)

\(f = -30N\)

Answer:

the third law (for every action there is an equal and opposite reaction).

Explanation:

The skateboarder pushes backwards on the road (that is he applies a force on the road in a direction opposite the direction of intended motion). By Newton's third law, this action of the skateboarder causes an equal reaction of the road on the skateboarder in the opposite direction. Newton's third law states that action and reaction are equal but opposite in direction. So, the road in response to this backward force pushes the skateboarder in the forward direction causing the skateboarder and the skateboard to move in the forward direction.

The magnitude of the electric field inside the solid at a distance of 9.20 cm from the centre of the cavity is 394.6857x10⁻⁶ N/C.

Potential energy is the energy that is stored in any object or system as a result of its position or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles within a system or an object.

Given that,

Charge inside the cavity = -3μC = -3x10⁻⁶ C

The charge density of the sphere, ρ = 7.35x 10⁻⁴ C/m³

Radius of he cavity = 6.90 cm = 0.0690 m

We have to find the electric field at a radius of 9.20 cm, therefore, the effective radius,

Effective radius = 0.092-0.069 = 0.023 m

Effective Volume = (4/3)πr³ = 0.5093 x10⁻⁴ m³

The charge, Q = volume x charge density = 374.33 x 10⁻⁶ C

The net charge enclosed,

Q = (374.33 - 3 ) x 10⁻⁶ C

Q = 371.33 x 10⁻⁶ C

We know according to the Gauss law,

\(\bar E = \dfrac{Q_in}{\epsilon_0}\)

E = 394.68 x 10⁻⁶ C

Hence, the magnitude of the electric field inside the solid at a distance of 9.20 cm from the centre of the cavity is 394.6857x10⁻⁶ N/C.

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Answer:

a. 100N +60N =160N

b. . the box will move in the direction the force is applied.

Answer:

Option C. vi = 0

Explanation:

An object held at a particular height above the ground is considered to be at rest. If the object is release from that height, the initial velocity (vi) is considered to be zero since the object is at rest or at a stand still position.

Thus,

Initial velocity (vi) = 0

Answer:

F = I L B     describes the perpendicular force on a wire of length L in a uniform field B

B = F / (I L) = 1.2 / (9 * 2.5) = .053 Tesla

Answer:

A. I and V

Explanation:

According to Le Chatelier's Principle, increasing the product side will cause the equilibrium to shift back towards the reactant side, so I is true.  By the same principle, II is false.

For gases, decreasing the pressure will cause the equilibrium to shift towards the side with higher number of moles.  So V is true.

The reaction is endothermic, so increasing the temperature will shift the equilibrium to the products, so IV is false.  And adding a catalyst has no effect on the equilibrium, so III is false.

The changes would result in more reactants being produced will increase NO₂ and decrease the pressure. Then the correct option is A.

The chemical reaction is the reaction between two reactants that led to the formation of products.

The products are substances that form after the reaction. The reactants are the substances that are original materials.

Given the reaction: N₂(g) +2O₂(g) ⇌ 2NO₂(g)

The forward reaction is endothermic. Increasing the product side will cause the equilibrium to shift back towards the reactant side, so I is true.  

By the same principle, II is false.

For gases, the decrease in pressure will shift the equilibrium toward the high number of moles side.  

So V is true.

The reaction is endothermic, so increasing the temperature will shift the equilibrium to the products, so IV is false.  Adding a catalyst has no effect on the equilibrium, so III is false.

The changes would result in more reactants being produced will increase NO₂ and decrease the pressure.

Then the correct option is A.

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Answer:

1.00000 x10^5     (or  1. x 10^5 )

Explanation:

Count the number of  0's ...this is the power of 10

The magnetic field at the center of the arc due to the current carrying wire is \(1.14 \times 10^{-7} T\).

To determine the magnetic field at the center of the arc, we can use the Biot-Savart Law, which relates the magnetic field at a point to the current element and its distance from the point.

\(B = \mu _0I/(2\pi r)\)

where μ₀ is the magnetic constant, I is the current flowing through the wire, and r is the distance of the point of interest from the wire.

Since the arc has a radius of 14 cm, we need to find the magnetic field at a distance of 14 cm from the wire due to one-fourth of the circumference of the circle.

The current through the wire is 32 A.

Thus, the magnetic field at the center of the arc is given by:

\(B = \mu _0I/(8\pi d)\)

Putting the given values, we get:

\(B = (4\pi \times 10^{-7} Tm/A) \times (32 A)/(8\pi  \times 14 \ cm)= 1.14 \times 10^{-7} T\)

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If a mountain goat starts a rock slide and the rocks crash down the slope 100 m. If the rocks reach the bottom in 5 s, then the acceleration of the rock would be 8 meters/second².

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem a mountain goat starts a rock slide and the rocks crash down the slope 100 m. If the rocks reach the bottom in 5 s,

initial velocity of rock = 0 m/s

displacement = 100 meters

time = 5 seconds

s = ut + 0.5at²

100 = 0 + 12.5a

a = 100/12.5

  = 8 meters/second²

Thus, the acceleration of the rock would be 8 meters/second².

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Answer:they are a renewable source

Explanation: because they come from the ocean and the ocean is 75% of the world so there will always be waves.

Newton's law of universal Gravity:

F = G * (M1 * M2)/ r^2

Where:

G = gravitational constant = 6.674 x10^-11 Nm^2kg^2

M1 = mass 1 = 45.9 kg

M2 = mass 2 = 5.98 x 10 ^24 kg

r = Distance between the 2 objects = 6.38 x 10 ^6 m

Replacing;

F = 450.048 N

F = 0(I1I2L)/(2d) represents the force between two parallel wires, where 0 is the permeability of free space, L represents the wires' length, and d represents the spacing between the wires. We obtain r = 5.02 by solving for r in the formula F = I2 r and substituting the supplied values.

F = 0(I1I2L)/(2d), where 0 is the permeability of empty space, I1 and I2 are the currents flowing through the wires, L is the length of the wires, and d is the distance between the wires, calculates the force between two parallel wires. The formula F = I2 r, where F is the force between the wires and I2 is the current running through one of the wires, may be used to determine the resistance value that will produce a force of 1.26x10-4 N. We get r = 5.02 by entering the specified data into these calculations. This indicates that a resistor with a value of 5.02 ohms would produce a force between the two of 1.26x10-4 N.

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The distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

The following question has two parts

For part 1 we need to calculate the distance covered by the truck in 12 seconds

We know that

 s = ut + \(\frac{1}{2}a .t^{2}\) . . . . . . .  . . . . .(1)

where s = distance travelled

           u = initial velocity

           a = acceleration

           t  =  time in seconds

Now , As per the question

u = 6 m/s

a = 2 m/\(s^{2}\)

t  = 12 seconds

Putting the values in the equation (1)

                          s = 6 X 12 + \(\frac{1}{2}\) X 2 X 144

                          s = 72 + 144

                          s = 216 m

Therefore the distance travelled is 216 m

For part 2 we need to calculate the final velocity that Paco was driving

We know that

v = u + at . . . . . . . . . . .  .(2)

where v = final velocity

          u = initial velocity

          a = acceleration

           t = time in seconds

As per the question,

u = 4m/s

a = 0.5 m/\(s^{2}\)

t = 30 seconds

Putting in equation (2)

                                      v = 4 + 0.5 X 30

                                      v  =  4 + 15

                                      v = 19 m/s

Therefore the final velocity is 19 m/s

Therefore , the distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

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The final velocity of the scooter is 19 m/s.

Given:

Initial velocity of truck, u = 6 m/s

Acceleration of truck, a = 2 m/s²

Time taken by the truck, t = 12 s

Formula used:

s = ut + 1/2 at²

Where,

s = Distance travelled

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

s = ut + 1/2 at²

 = 6(12) + 1/2 × 2 × (12)²

 = 72 + 1/2 × 2 × 144

 = 72 + 144

 = 216 m

Therefore, the truck travels 216 m in the given time.

Given:

Initial velocity of scooter, u = 4 m/s

Acceleration of scooter, a = 0.5 m/s²

Time taken by the scooter, t = 30 s

Formula used:

v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

v = u + at

 = 4 + 0.5 × 30

 = 4 + 15

 = 19 m/s

Therefore, the final velocity of the scooter is 19 m/s.

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This statement is True. Neptune has a highly tilted rotation axis, much like Uranus, and very unlike Saturn's. This means that Neptune's poles experience extreme seasons, with three long summers and three long winters in each Neptune year.

Additionally, the planet's magnetic field is also highly tilted, with the magnetic axis offset from the planet's center by about three-quarters of the planet's radius. Overall, these unique characteristics make Neptune an intriguing and complex planet to study. Neptune has a moderately tilted rotation axis, similar to Uranus, but not as extreme. Its axial tilt is around 28 degrees, whereas Uranus has a significant tilt of approximately 98 degrees. This is in contrast to Saturn, which has a relatively smaller tilt of about 27 degrees. Consequently, Neptune's tilt results in pronounced seasonal changes and weather patterns, as observed on Uranus, but to a lesser extent.

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