On Earth the gravitational field strength is 10N/kg. What would be the weight of someone on Earth who had a mass of 75kg?


750N/kg

750N

75N

7500kg​

Answers

Answer 1

The weight of someone on Earth with a mass of 75kg is 750N.

option B.

What would be the weight of someone on Earth?

The weight of someone on Earth is calculated using Newton's second law of motion.

W = mg

where;

m is the massg is acceleration due to gravity

For the mass is 75kg and the gravitational field strength on Earth is 10N/kg.

W = 75 kg x 10 N/kg

W = 750 N

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Related Questions

The Earth's history is shaped by different geological processes over a wide range of space and time.

For example, in the late 1900s, a crater was discovered near the town of Wetumpka, Alabama. Scientists found shocked quartz in the core samples collected from the crater. Shocked quartz occurs as a result of intense metamorphism (change in the structure of rocks).

Which of the following geological processes is most likely responsible for the formation of the crater?
A. erosion by water
B. tectonic plate movement
C. volcanic eruption
D. meteor impact

Answers

The answer is D because I already took this in class before and I remember the answer

meteor impact this ecological processes is most likely responsible for the formation of the crater. Hence option D is correct.

What is meteor impact ?

A collision between celestial objects that has quantifiable effects is called an impact event. The most frequent impact events involve asteroids, comets, or meteoroids and have little impact. However, impact events have been shown to occur often in planetary systems and have physical repercussions. However, many surface impacts are reduced by atmospheres through atmospheric entry when massive objects strike terrestrial planets like the Earth. Nonetheless, there may be major physical and biospheric effects. The majority of the solid objects in the Solar System are covered with impact craters and structures, which provide the best empirical evidence for their frequency and size. Since the birth of the Solar System, impact events appear to have had a substantial impact on how the Solar System has changed. Significant impact events have impacted Earth's history and have been linked

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Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next

Answers

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

A bird flew to catch a prey and went from 12 m/s to 22 m/s in 2 seconds. What was the magnitude of the bird's acceleration?

Answers

Answer: Peregrine falcons are famed for their high-speed, high-altitude stoops. Hunting prey at perhaps the highest speed of any animal places a stooping falcon under extraordinary physical, physiological, and cognitive demands, yet it remains unknown how this behavioural strategy promotes catch success. Because the behavioral aspects of stooping are intimately related to its biomechanical constraints, we address this question through an embodied cognition approach. We model the falcon’s cognition using guidance laws inspired by theory and experiment, and embody this in a physics-based simulation of predator and prey flight. Stooping maximizes catch success against agile prey by minimizing roll inertia and maximizing the aerodynamic forces available for maneuvering but requires a tightly tuned guidance law, and exquisitely precise vision and control.

Explanation:

Why is it harder to build a supersonic ship than a supersonic airplane ​

Answers

Answer:

sound velocity is greater in water,and it is harder to move through.

thank you.

An object is casting a shadow on the ground If an object is 85 feet shorter than the length of the shadow on the ground and the tip of the

Shadow is 125 feet from

the top of the object, how tall is that object?

The object is

tall

Answers

The height of the given object is 35 feet tall.

From the given parameters:

Let the length of the shadow = xThe height of the object = x - 85

The two legs of the right triangle = x and (x - 85)

The hypotenuse side, = 125

The length of the shadow is calculated by applying Pythagoras theorem as follows;

\(x ^2 + (x - 85)^2 = 125^2\\\\x^2 + x^2 -170x + 7225= 15625\\\\2x^2 - 170x -8,400 = 0\\\\2(x^2 -85x - 4,200) = 0\\\\x^2 -85x - 4,200 = 0\\\\\)

Factorize the equation as follows;

\(x^2 + (35x - 120x) - 4200= 0\\\\x^2 + 35x \ - 120 x - 4200 = 0\\\\x(x + 35) - 120(x + 35) = 0\\\\(x + 35) (x -120) = 0\\\\x = - 35 \ \ or \ 120\\\\\)

The length is always positive, thus, x = 120 ft

The height of the object is calculated as follows;

h = x - 85

h = 120 - 85

h = 35 ft

Thus, the height of the given object is 35 feet tall.

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a body of mass 10kg on a smooth inclined plane is connected over a smooth pulley to a mass of 15kg . the acceleration of the system is? please help ASAP will give branliest​

Answers

The acceleration of the system is (m₁g sinθ  +  m₂g) / (m₁ + m₂) / (m₁ + m₂)

What is the acceleration of the system?

The acceleration of the system can be calculated using the equation of motion and considering the forces acting on each mass.

The equation of motion for the 10 kg mass is:

W₁ - T = m₁a

The equation of motion for the 15 kg mass is:

W₂ + T = m₂ a

Where;

m₁ and m₂ are the masses of the 10 kg and 15 kg masses respectivelya is the acceleration of the system.

Solving for the tension T and substituting the values for W₁ and W₂, we get:

T = (m₁g sinθ  +  m₂g) / (m₁ + m₂)

And substituting T back into either equation, we get:

a = (m₁g sinθ  +  m₂g) / (m₁ + m₂) / (m₁ + m₂)

where;

g is the acceleration due to gravityθ is the angle of inclination of the plane.

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A string with a length of 7.25 m is fixed at both ends. If the string is plucked so that there are five nodes along the string in addition to those at either end, what is the wavelength of the interfering waves for this mode?

Answers

Answer:

the  wavelength of the interfering waves for this mode is 2.4168

Explanation:

The computation of the wavelength of the interfering waves for this mode is shown below:

Given that

The length is 7.25m

And, the number of nodes is 6

So, the wavelength should be

= 2 × 7.25m ÷ 6

= 2.4168 m

Hence, the  wavelength of the interfering waves for this mode is 2.4168

The same would be considered

A steel ball of mass 0.500 kg is fastened to a cord that is 70.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal (Fig 9-65). At the bottom of its path, the ball strikes a 2.50 kg steel block initially at rest on a frictionless surface The collision is elastic. Find
(a)the speed of the ball and (b) the speed of the block, both just after the collision.

Answers

(a) ball velocity = - 2.47 m/s  

(b) block velocity = 1.236 m/s

What is collision?

Two items collide when they briefly come into touch with one another. To put it another way, a collision is a brief reciprocal encounter between two masses in which the momentum and energy of the masses change.

For ball as it is at initially at height of 70.0 cm = 0.7 m

so by energy conservation,

K.E.(i) P.E.(i) + K.E.(f)+P.E.(f)

0 + mg×(0.7)  = 1/2 mv² + 0

v = 3.71 m/s

now, collision b/w ball and block

as the block is in rest initially and there is no external force b/w them

so by momentum conservation,

m₁u₁+ m₂u₂ = m₁v₁+ m₂v₂

or, (0.5 x 3.71) + 0 = (0.5x v₁) + (2.5 x v₂)

3.71 = v₁ + 5v₂  .........(1)

as elastic collision so energy conservation

or, 1/2 m₁ u₁² + 1/2 m₂ u₂² = 1/2 m₁ v₁² + 1/2 m₂ v₂²

or, (1/2 x 0.5 x 3.712) + 0 = (1/2 x 0.5 x v₁²) + (1/2 x 2.5 x v₂²)

or, 3.433 = 0.25xv₁² + 1.25 v₂²      ...............(2)

from eq. 1 and eq. 2

or, 3.433 = 0.25 x (3.71 - 5 v₂)² + 1.25v₂²  

or, v² = 1.236 m/s

and v₁ = 3.71 - 5v₂

or, v₁ = - 2.47 m/s

so after collision

ball velocity = - 2.47 m/s       [(-)ve x direction]

block velocity = 1.236 m/s     [(+)ve x direction]

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Calculate the wave speed (in m/s) for the following waves:


a) A sound wave in steel with a frequency of 500 Hz and a wavelength of 3.0 meters. (2pts)







b) a ripple on a pond with a frequency of 2 Hz and a wavelength of 0.4 meters. (2pts)









Calculate the wavelength (in meters) for the following waves:



A wave on a slinky spring with a frequency of 2 Hz travelling at 3 m/s. (2pts)







An ultrasound wave with a frequency 40,000 Hz travelling at 1450 m/s in fatty tissue. (2pts)









Calculate the frequency (in Hz) for the following waves:



A wave on the sea with a speed of 8 m/s and a wavelength of 20 meters. (2pts)







A microwave of wavelength 0.15 meters travelling through space at 300,000,000 m/s. (2pts)

Answers

Answer: A : 250 is the answer

B; The frequency of a wave is the number of complete oscillations (cycles) made by the wave in one second.

Instead, the wavelength is the distance between two consecutive crests (highest position) or 2 troughs (lowest position) of the wave.

In this problem, we are told that the leaf does two full up and down bobs: this means that it completes 2 full cycles in one second. Therefore, its frequency is

where  is called Hertz (Hz). So, the correct answer is

Explanation:

#Wavespeed

#1

\(\\ \rm\Rrightarrow v=\nu\lambda=500(3)=1500m/s\)

#2

\(\\ \rm\Rrightarrow v=2(0.4)=0.8m/s\)

#Wavelength

#1

\(\\ \rm\Rrightarrow \lambda=\dfrac{v}{\nu}=\dfrac{3}{2}=1.5m\)

#2

\(\\ \rm\Rrightarrow \lambda= \dfrac{1450}{40000}=0.03625m\)

#Frequency

\(\\ \rm\Rrightarrow \nu=\dfrac{v}{\lambda}=\dfrac{8}{20}=0.4Hz\)

#2

\(\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8}{15\times 10^{-2}}=0.2\timee 10^{10}=2\times 10^9Hz\)

A teacher is examining laboratory supplies with a diverging lens. The lens has a focal length of magnitude 19.4 cm. The lens is always held between the teacher's eye and the object under study. However, the distance between the lens and the object is different for each object that the teacher observes.
Determine the image location and magnification for each of the following three objects. In addition, determine whether the image is real or virtual, whether it is upright or inverted, and whether it makes the object appear larger or smaller than actual size.
A) The object lies 38.8 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (a).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
B) A) The object lies 19.4 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (b).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken
C) A) The object lies 9.70 cm behind the lens. Determine the image location. (Enter the magnitude in cm.)
|q| =
Determine the magnification.
M =
Select all of the following that apply to the image formed in part (c).
- real
- virtual
- upright
- inverted
- enlarged
- shrunken

Answers

The answers are (a) |q| = 58.2 cm, M = -1.50, virtual, upright, shrunk; (b) |q| =, M = -, actual, substantially magnified; and (c) |q| = 6.5 cm, M = -1.68, virtual, upright, enlarged.

We can use the magnification formula and the thin lens equation to solve:

Where f is the lens's focal length, d_i is the image distance, and d_o is the object distance, the equation is: 1/f = 1/d_i + 1/d_o.

The formula for magnification is M = -d_i/d_o, where M stands for magnification.

For part (a), the object distance is d_o = -38.8 cm and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-38.8

|d_i| = 58.2 cm

The image is virtual and smaller than the object (since the magnification is less than 1)

For part (b), the object distance is d_o = -19.4 cm, and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-19.4

|d_i| = ∞

The image is at infinity, which means it is a real image and highly magnified (since the object distance is close to the focal length).

For part (c), the object distance is d_o = -9.70 cm, and the focal length is f = -19.4 cm.

1/-19.4 = 1/d_i + 1/-9.70

|d_i| = 6.5 cm

The image is virtual and larger than the object (since the magnification is greater than 1).
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The net force on a 13 kg cart is 4.6 N backward.
Ignoring friction, what is the acceleration of the
cart?
a. 0.27 m/s2 backward
b. 3.8 m/s2 backward
c. 35 m/s2 backward
d. 38 m/s2 backward

Answers

Divide the net force by the mass:

a = (4.6 N) / (13 kg) ≈ 0.35 m/s²

also pointing backward, which looks like option B, but hard to say for sure since it's missing a decimal point.

Refer to the picture!

Refer to the picture!

Answers

(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

What is the work done by the donkey on the cart?

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

F is the applied force by the donkeyd is the displacementθ is the angle of inclination

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

Fg is the force of gravityd is the displacementθ is the angle between the force of gravity and displacement

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff is the force of friction;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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Whoever can answer this is smart
What is an electrostatic force in a simple definition
What is a magnetic force in simple definition

Answers

An electrostatic force = forces that can push or pull an object without touching it.

A magnetic force = can attract or repel of a force that is exerted between poles (like north and south). It is between electrically charged particles.

Answer:

Hope it helps you

Explanation:

An electrostatic force is an attractive as well as replusive force caused by the electric charge particles.

Magnetic force is a consequence of electromagnetic force and is caused due to the motion of charges.

PLS RATE AS BRAINLIEST ANSWER


Which describes the magnetic field that forms when a wire carries an electric current?

Answers

The magnetic field that forms when a wire carries an electric current is a circular field that is strongest at the ends of the wire and weakest in the middle.

What does a current-carrying wire's magnetic field look like?

A current-carrying wire's magnetic field looks like a series of concentric circles that extend outward from the wire in both directions.

The magnitude of the magnetic field is greatest at the center of the wire and decreases as you move away from it.

The direction of the magnetic field is determined by the direction of the current flow: if the current is flowing clockwise around the wire, then the magnetic field will be pointing outward from the wire.

The magnetic field also has a north and south pole, so the direction of the field also depends on which direction around the wire the current is flowing.

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I need help with question 8Find the distance and displacement

I need help with question 8Find the distance and displacement

Answers

Draw a diagram to visualize the situation:

The displacement of an object is the change in its position between the starting point and the endpoint of the trajectory. On the other hand, the distance is the length of the trajectory of the object.

In this case, the total displacement can be calculated adding 5km+4km noting that both displacements were performed to the East. Then, the displacement is:

\(9\operatorname{km}\text{ to the East}\)

The total distance traveled is the same as the modulus of the displacement whenever the movement is constrained to a straight line with no changes in the direction. Then, the distance traveled is:

\(9\operatorname{km}\)

I need help with question 8Find the distance and displacement

Hector stretches a spring with a spring constant of 3 N/m until it is extended by 50 cm. What is the elastic potential energy stored by the spring?

Answers

The elastic potential energy stored in the spring is 0.375 J.

The formula for elastic potential energy is:

E = 1/2 * k * x^2

where:

* E is the elastic potential energy in Joules

* k is the spring constant in N/m

* x is the distance the spring is stretched or compressed from its equilibrium position in meters

In this problem, we have:

* k = 3 N/m

* x = 0.5 m (50 cm)

Substituting these values into the formula, we get:

E = 1/2 * 3 * 0.5^2 = 0.375 J

Therefore, the elastic potential energy stored in the spring is 0.375 J.

The following are four electrical components.
A. A component which obeys ohm's law
B. Another component which obeys ohm's law
but which has higher resistance than A
A filament lamp
C.
D. A component, other than a filament lamp,
which does not obey ohm's law.
a. For each of these components, sketch current-
voltage characteristics, plotting current on the
vertical axis, and showing both positive and
negative values. Use one set of axes for A and
B, and separate sets of axes for C and for D.
label your graphs clearly.
b.
Explain the shape of the characteristic for C
c. Name the component you have chosen for D.

Answers

For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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in pushes a 500 N crate with an applied force of 1450 N to the left. He encounters a fridtional force of 200 N and his evil co-worker Jim adds a
500 N opposing force to the right. What is the magnitude and direction of the net force


A.1750 N. Right
B.2650 N Left
C. 750 N. left

Answers

Answer:

C. 750 N. left

Explanation:

let the force to the right be positive, and the left be negative

Step one:

given

mass of crate m= 500N

1450N force left

Frictional force of 200 N -----this opposes the motion

500 N opposing force to the right

The net force is equal to the summation of all the forces in Newton

Net force= -1450+200+500

Net force=-750N

The direction is right

PLEASE HELP QUICKLY THANKS

PLEASE HELP QUICKLY THANKS

Answers

Answer: the answer is d

Explanation:

The position-time equation for a certain train is
2.9m + (8.8m/s)t + (2.4m/s2)+2

What is it’s acceleration?

Answers

Answer:

\(a=4.8m/s^2\)

Explanation:

Hello,

In this case, since the acceleration in terms of position is defined as its second derivative:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d^2}{dt^2}(2.9+8.8t+2.4t^2)\)

The purpose here is derive x(t) twice as follows:

\(a=\frac{d^2x(t)}{dt^2}=\frac{d}{dt}(8.8+2*2.4*t)\\ \\a=4.8m/s^2\)

Thus, the acceleration turns out 4.8 meters per squared seconds.

Best regards.

Calculate the momentum of a 6 kg ball thrown at 20 m/s by a 3 newton
force. *

Answers

Answer:

momentum = mass × velocity = 6× 20 =120 kg.ms-1

Explanation:

not sure if this is right

When cold milk
is added to hot
coffee, the milk
warms up and the
coffee cools down.
What can be said
about the energy
of the milk and
the energy of
the coffee when
this happens?

Answers

Answer:

See explanation below.

Explanation:

The internal energy (kinetic energy) of the milk particles increases thus warming the milk up, while the internal energy of the coffee particles reduce their initial average speed as they are imparting energy to the slow milk particles.

The blue wave and the green have are traveling through the same medium at the same time. They will cause an interference pattern in the medium. What will be the amplitude at point D?




The blue wave and the green have are traveling through the same medium at the same time. They will cause an interference pattern in the medium. What will be the amplitude at point D?


1.25 Squares

4.25 Squares

1.00 Squares

2.50 Squares

The blue wave and the green have are traveling through the same medium at the same time. They will cause

Answers

When two sound waves have the same amplitude, wavelength, and direction of travel, and a phase difference of 6π, they exhibit constructive interference. The perfectly aligned crests and troughs result in the superposition of the waves, leading to an increased amplitude in the combined wave.

When two sound waves are traveling through the same medium with the same amplitude, wavelength, and direction of travel, and their phase difference is 6π, they exhibit constructive interference.

Constructive interference occurs when two waves are perfectly in phase, meaning their crests and troughs align. This alignment leads to the superposition of the waves, resulting in a combined wave with an increased amplitude.

To understand why this is the case, let's consider the mathematical relationship between the phase difference and interference. The phase difference (Δφ) between two waves is given by the equation Δφ = 2π(Δx / λ), where Δx is the path difference and λ is the wavelength. In constructive interference, the phase difference is a multiple of 2π, meaning Δφ = 2πn, where n is an integer.

In this case, the phase difference is 6π, which can be written as 2π(3). Since 3 is an integer, the condition for constructive interference is satisfied. This means that the two waves are perfectly aligned and their crests and troughs coincide at every point along their paths.

As a result, the amplitudes of the waves add up, leading to an overall increase in the amplitude of the combined wave. This constructive interference produces a stronger and louder sound at the points where the waves overlap.

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The question probable may be:

Two sound waves are traveling through the same medium. They have the same amplitude, wavelength, and direction of travel. If the phase difference between them is 6π, what type of interference do they exhibit? Why is that the case?

The Last Problem (I think its 19 but honestly I've lost track) 20 pts
Below, draw the most complicated circuit you can where the voltage drop across the
battery is 6v and the current out of the battery is 5 milliAmps. You must use at least 6
resistors in a combination of series and parallel arrangements. The resistors must be of a
realistic value (no decimal points). Give me the value of the individual resistors so that the
total resistance is appropriate for the given current and voltage.

Answers

The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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In the Roman soldier model for refraction, what happens to the first soldier who hits the muddy stream?
A. They slow down and keep going straight
B. They slow down and turn slightly
C. They speed up and keep going straight
D. They speed up and turn slightly

Answers

In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.

The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.

When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.

The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.

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HELP! An electron is accelerated from 0 m/s to 8 x 10^7 m/s by a uniform electric field. What is the potential difference (voltage) between the plates that make the field?

Answers

The potential difference (voltage) between the plates is approximately 1.45 kV.

The kinetic energy of an electron can be related to the potential difference between the plates of an electric field using the equation:

KE = qV,

where KE is the kinetic energy of the electron, q is its charge, and V is the potential difference between the plates.

We know that the electron is accelerated from rest to a final velocity of 8 x 10^7 m/s, so its change in kinetic energy is given by:

ΔKE = 1/2 mv^2 - 1/2 m(0)^2 = 1/2 mv^2

where m is the mass of the electron.

The potential difference between the plates can be found by rearranging the equation to solve for V:

V = ΔKE / q

Substituting the values we have:

V = (1/2) mv^2 / q

The mass of an electron is approximately 9.11 x 10^-31 kg, and its charge is -1.6 x 10^-19 C. Substituting these values and the final velocity of 8 x 10^7 m/s, we get:

V = (1/2) (9.11 x 10^-31 kg) (8 x 10^7 m/s)^2 / (-1.6 x 10^-19 C)

V = -1.45 kV

Therefore, the potential difference (voltage) between the plates is approximately 1.45 kV.

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NEED A PHYSICS EXPERT TO HELP ME PLS

I've been stuck on this for two hours:

Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe.



Assuming that Bernoulli's equation applies, compute the volume of water ΔV that flows across the exit of the pipe in 1.00 s . In other words, find the discharge rate ΔV/Δt.
Express your answer numerically in cubic meters per second.

NEED A PHYSICS EXPERT TO HELP ME PLSI've been stuck on this for two hours:Water flows steadily from an

Answers

The discharge rate of water (Q) that flows across the exit of the pipe in 1.00 seconds is 0.200 \(m^3/s\).

Given the following data:

Elevation of point 1 = 10.0 mElevation of point 2 = 2.00 mElevation of point 3 = 2.00 mCross-sectional area at point 2 = \(4.80\times 10^{-2} \;m^2\)Cross-sectional area at point 3 = \(1.60\times 10^{-2} \;m^2\)

To find the discharge rate of water (Q) that flows across the exit of the pipe in 1.00 seconds assuming that Bernoulli's equation applies:

In this exercise, we would apply Torricelli's Law, which states that the speed of the efflux in an apparatus, under the force of gravity is directly proportional to the square root of the height of the fluid above it.

Mathematically, Torricelli's Law is given by the formula:

\(V =\sqrt{2gh}\)

Where:

g is the acceleration due to gravity.h is the height of the apparatus.V is the speed of liquid.

Substituting the given parameters into the formula, we have;

\(V =\sqrt{2 \times 9.8 (10-2)}\\\\V =\sqrt{19.6 (8)}\)

Speed, V = 12.52 m/s

Now, we can find the discharge rate of the pipe:

\(Q = V \times A\\\\Q = 12.52 \times 1.60\times 10^{-2}\)

Discharge rate, Q = 0.200 \(m^3/s\)

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find the magnetic filed strength at acenter of a soleneind with 500 turns and acurrent of 5A the permability of free space 4× 10-7n/m​

Answers

Answer:

The magnetic field strength at the center of a solenoid can be found using the formula:

B = u_0 * N * I / L

where B is the magnetic field strength, u_0 is the permeability of free space (4π × 10^-7 T·m/A), N is the number of turns in the solenoid, I is the current flowing through the solenoid, and L is the length of the solenoid.

Given:

N = 500 turns

I = 5 A

u_0 = 4π × 10^-7 T·m/A

Since we don't know the length of the solenoid, we can't calculate the magnetic field strength.

The amount of energy needed to a power a 0.20kw bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of

Answers

The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:

Potential energy (PE) = mass (m) × gravity (g) × height (h)

Where:

m = 2.5 kg (mass of the object)

g = 9.8 m/s² (acceleration due to gravity on Earth)

h = ? (height)

First, let's find the height (h) by rearranging the formula:

h = PE / (m × g)

Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):

Energy (E) = power (P) × time (t)

E = 0.20 kW × 1 min × 3,600 J/kW

Now, we can substitute the values into the equation to find the height:

h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)

Calculating the expression on the right side:

h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)

Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

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Calculate the speed of an ancient ship that registers a distance of 3482m in 1 h​

Answers

Hello..! :)

The speed of the ancient ship is 3482 meters per hour or 96.72 centimeters per second.

Explanation:

Data:

D = 3482mT = 1hV = ?

Formula:

V = D/T

Developing:

V = 3482m/1hV = 3482 m/h

Now, we convert to see what its speed is in cm/s.

Conversion:

3482m/h (1m/100cm) (1h/3600s)

V = 96.72 cm/s

¿Doubts? On the comments. Greetings :D

Answer:

Thanks For the points

It is or 96.72 cm/s

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