One isotope of Carbon(C) has exactly the same mass number and atomic mass since it was used as the definition of the atomic mass unit. Which isotope is it and what is it’s atomic mass?

The covalent bond is present in the compound C₃H₈. The reactant C is 3, product C is 6, reactant H is 8, product H is 10, Reactant O is 2, product O is 9.

What is covalent bond ?

Atoms share electron pair between them in covalent bonds. H-H or C-H are examples of nonpolar covalent bonds between atoms with similar or identical electronegativity, whereas polar covalent bonds are formed when unequal electronegativity is shared between atoms (e.g., H–O).

What is reactant ?

Raw materials known as reactants combine to create products. When the right factors, such as temperature, time, or pressure, come into play, the chemical bonds between the reactants are broken, allowing the atoms to form new bonds that lead to various combinations.

Therefore, covalent bond is present in the compound C₃H₈. The reactant C is 3, product C is 6, reactant H is 8, product H is 10, Reactant O is 2, product O is 9.

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From the list below, gamma ray radiation has the highest energy while visible light has the longest wavelength. The photon is the fundamental unit of all electromagnetic radiation, including visible light.

Only a percentage of visible radiation really causes light to be perceived by the human eye when it interacts with the body. The amount of viewable light that is produced by visible radiation rises with the power (luminous intensity) of the radiation. A periodic wave's wavelength, or the distance over which the wave's shape repeats, is its spatial period. The distance between two adjacent crests, troughs, or zero crossings on a wave are examples of consecutive corresponding points in the same phase. Gamma radiation ionizes in three different ways as it travels through matter: the impact of the photoelectric.

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The two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

A chemical compound is a substance made of numerous similar molecules (or molecular entities) joined by chemical bonds and comprising atoms from various chemical elements. Therefore, a molecule made up of only one type of atom is not a compound. Chemical reactions, which may entail interactions with other molecules, can change a compound into a distinct substance. Atomic bonds may be broken or new ones created during this process.

sample 1 = mass of lead / mass of oxygen = 12.92g/2g = 6.46 .

sample 2 = mass of lead/ mass of oxygen = 34.27 - 14.39/14.39 = 1.38 .

so, the ratios are not the same.

Hence, the two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

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Answer:

mass

Explanation:

Answer:

\(\boxed {\boxed {\sf 38.11 \ L}}\)

Explanation:

To find the volume, we need to convert grams to moles, then moles to liters.

We convert grams to moles using the molar mass. This is the mass of 1 mole of a substance. It is the same as the atomic mass found on the Periodic Table, but the units are grams per mole (not atomic mass units).

We have the compound carbon dioxide or CO₂. Look up the molar masses of the individual elements.

Notice that oxygen has a subscript of 2, so there are 2 atoms in each molecule. We have to multiply oxygen's molar mass by 2 before adding carbon's.

Use this value as a ratio.

\(\frac {44.009 \ g\ CO_2}{1 \ mol \ CO_2}\)

Multiply by the given number of grams: 74.87

\(74.87 \ g\ CO_2*\frac {44.009 \ g\ CO_2}{1 \ mol \ CO_2}\)

Flip the ratio so the units of grams cancel.

\(74.87 \ g\ CO_2*\frac {1 \ mol \ CO_2}{44.009 \ g\ CO_2}\)

\(74.87 *\frac {1 \ mol \ CO_2}{44.009 }\)

\({74.87 \ mol \ CO_2}{44.009 } = 1.701242928 \ mol \ CO_2\)

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole.

\(\frac {22.4 \ L}{1 \ mol \ CO_2}\)

Multiply by the number of moles we calculated.

\(1.701242928 \ mol \ CO_2*\frac {22.4 \ L}{1 \ mol \ CO_2}\)

The units of moles cancel.

\(1.701242928 *\frac {22.4 \ L}{1 }\)

\(1.701242928 *{22.4 \ L}= 38.10784158 \ L\)

The original measurement has 4 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

The 7 tells us to round the 0 10 a 1.

\(38.11 \ L\)

The chemical formulas for the ions and compounds you listed:

Copper (II) ion: Cu²⁺

Bromide ion: Br⁻

Magnesium ion: Mg²⁺

Phosphide ion: P³⁻

Copper (I) Bromide: CuBr

Sulfur Dichloride: SCl₂

Barium Fluoride: BaF₂

Magnesium Phosphate: Mg₃(PO₄)₂

Lithium Permanganate: LiMnO₄

Strontium Sulfite: SrSO₃

Nitrogen Monoxide: NO

Diselenium Tetraoxide: Se₂O₄

Aluminum Sulfide: Al₂S₃

Tin (IV) Iodide: SnI₄

Beryllium Oxide: BeO

Potassium Hydroxide: KOH

Copper (II) ion: Cu²⁺

Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.

Bromide ion: Br⁻

The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.

Magnesium ion: Mg²⁺

The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.

Phosphide ion: P³⁻

The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.

Copper (I) Bromide: CuBr

Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.

Sulfur Dichloride: SCl₂

Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.

Barium Fluoride: BaF₂

Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.

Magnesium Phosphate: Mg₃(PO₄)₂

Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.

Lithium Permanganate: LiMnO₄

Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.

Strontium Sulfite: SrSO₃

Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Nitrogen Monoxide: NO

Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.

Diselenium Tetraoxide: Se₂O₄

Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.

Aluminum Sulfide: Al₂S₃

Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "

2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.

Tin (IV) Iodide: SnI₄

Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.

Beryllium Oxide: BeO

Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Potassium Hydroxide: KOH

Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.

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Isotonic solutions restore fluid volume because they fill the tissues and maintain fluid volume more effectively than hypertonic or hypotonic solutions.

Cells are the basic unit of life.

If a cell is placed in an isotonic solution, there will be no net flow of water into or out of the cell, and the cell's volume will remain stable.

If the solute concentration outside the cell is the same as inside the cell, and the solutes cannot cross the membrane, then that solution is isotonic to the cell.

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Answer: 179 grams

Explanation:

In a chemical reaction, the law of conservation of mass applies, meaning that the total mass of the reactants is equal to the total mass of the products. In this case, the reactants are 162 grams of copper and 17 grams of oxygen, and the product is copper (II) oxide. Using the balanced chemical equation 2Cu + O2 -> CuO, we know that 1 copper atom reacts with 1 oxygen molecule to form 1 copper oxide. Therefore, the mass of copper oxide produced is equal to mass of copper plus mass of oxygen, which is 162g + 17g = 179g.

Answer:

106.7 degrees f

Explanation:

Answer:

Kb = 1.77x10⁻⁵

Explanation:

When NH₃, a weak base, is in equilibrium with waterm the reaction that occurs is:

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

And the dissociation constant, Kb, for this equilibrium is:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

To find Kb you need to find the concentration of each species. The equilibrium concentrations are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

Where X is reaction coordinate.

You can know [OH⁻] and, therefore, X, with pH of the solution, thus:

pH = -log [H⁺] = 11.612

[H⁺] = 2.4434x10⁻¹²

As 1x10⁻¹⁴ = [H⁺] [OH⁻]

1x10⁻¹⁴ / 2.4434x10⁻¹² = [OH⁻]

4.0926x10⁻³ = [OH⁻] = X

Replacing, concentrations of the species are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

[NH₃] = 0.9459M

[NH₄⁺] = 4.0926x10⁻³M

[OH⁻] = 4.0926x10⁻³M

Replacing in Kb expression:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

Kb = [4.0926x10⁻³M] [4.0926x10⁻³M] / [0.9459M]

The branch of science which deals with the chemical bond is called Chemistry.

The correct answer to the question is  \(Kb = 1.77*10^{-5\)

Explanation:

When NH₃, is acts as a  weak base it forms an equilibrium with water the reaction occurs is:

\(NH_3(aq) + H_2O(l) ---><NH_4^+(aq) + OH^-(aq)\)

The formula we gonna use is as follows:-

\(Kb = \frac{[NH_4^+] [OH^-]}{[NH_3]}\)

The data is given in the question is as follows:-

Where X stands for reaction coordinate.

After solving the ph of the compound the value is as follows:-

Putting the value in the formula.

\(Kb = \frac{[4.0926*10^{-3}M] [4.0926*10^{-3}M]}{[0.9459M]}\)

After solving the equation the value of Kb is \(1.77*10^{-5\)

Hence, the correct answer is \(1.77*10^{-5\)

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Answer: Booting up the computer: When you turn on the computer, it requires a burst of energy to start up the various components and initialize the operating system.

Explanation:

The grams of iburofen does such a tablet contain 800 mg =   0.8g Ibuprofen

1 g = 10^-3g = .001g

Ibuprofen has  800 mg doses in over-the-counter analgesic

800g = 800 × .001

        = 0.8g

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To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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Millikan's oil drop experiment measured the size of the electric charge on the electron.

This is referred to as a type of procedure which is carried out in other to accept or refute a hypothesis. Electron on the other hand, is the negatively charged subatomic particle which is present in an atom and are involved in the formation of new substances during a chemical reaction.

Millikan's oil drop experiment measured the size of the electric charge on the electron and used tiny drops of oil which helped in the calculation of the charge and the mass of an electron.

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According to the problem the specific heat of the metal is 0.0329 cal/g°C.

Specific heat is the amount of heat energy required to raise the temperature of a unit mass of a substance by one degree. It is usually expressed in units of joules per kilogram-kelvin (J/kg-K). It is an important physical property of a substance that affects the rate of heat transfer.

The specific heat of a metal can be calculated using the equation, q = mcΔT,
where q is the amount of heat energy,
m is the mass of the metal sample,
c is the specific heat, and
ΔT is the change in temperature. In this problem, q = 10.57 g × c × (24.15ºC - 22.50ºC) = 2.85 g × c.
The amount of heat energy required to raise the temperature of the water bath can be calculated using the equation q = mcΔT,
where q is the amount of heat energy, m is the mass of the water bath,
c is the specific heat of water (4.184 J/g°C), and
ΔT is the change in temperature. In this problem, q = 104.0 g × 4.184 J/g°C × (24.15ºC - 22.50ºC) = 86.67 J.
The specific heat of the metal can be calculated by dividing the amount of heat energy required to raise the temperature of the metal sample by the amount of heat energy required to raise the temperature of the water bath. This gives us c = 2.85 g × c / 86.67 J = 0.0329 cal/g°C.
Therefore, the specific heat of the metal is 0.0329 cal/g°C.

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4) The volume of the HCl used is 9.500 mL while the volume of the NaOH used is 3.800 mL.

5) Molarity of sodium hydroxide is obtained from; Molarity of HCl * 1/2

By reacting an unknown component with a known quantity of a different chemical known as a titrant, titration is a laboratory procedure used to measure the concentration of an unknown substance, often a solute dissolved in a liquid.

The endpoint of a titration can be detected in a number of ways, depending on the specific titration being performed.

4)

Volume of the Acid used = Initial reading - Final reading = 25.00 - 15.50 = 9.500 mL

Volume of the base used = 8.80 - 5.00 = 3.800 mL

5)

We know that the mole ratio is 1:2 and the implication of this is that the set up to obtain the molarity of the sodium hydroxide solution is Molarity of HCl * 1/2

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In the balanced equation \(2C_{2} H_{6}\) + \(7 O_{2}\) --> \(4 CO_{2}\) + \(6H_{2}O\) if 21 g of \(C_{2} H_{6}\) reacts with 32 g O₂, C₂H6 is the limiting reactant.

To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometric ratio in the balanced equation.

Let's calculate the number of moles for each reactant using their molar masses:

For \(C_{2} H_{6}\) (ethane):

Molar mass of \(C_{2} H_{6}\) = 2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol

Number of moles of C₂H6 = 21 g / 30.07 g/mol ≈ 0.698 mol

For O₂ (oxygen):

Molar mass of O₂ = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O₂ = 32 g / 32.00 g/mol = 1.00 mol

Next, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation:

2 moles of \(C_{2} H_{6}\) react with 7 moles of O₂ to produce 4 moles of CO₂ and 6 moles of H₂O.

From the given amounts, we have:

0.698 mol \(C_{2} H_{6}\) and 1.00 mol O₂.

Using the stoichiometric ratio, we can calculate the expected amount of CO₂ and H₂O produced for each reactant:

For C₂H6:

Expected moles of CO₂ = 0.698 mol C₂H6 * (4 mol CO₂ / 2 mol C₂H6) = 1.396 mol CO₂

For O₂:

Expected moles of CO₂ = 1.00 mol O₂ * (4 mol CO₂ / 7 mol O₂) ≈ 0.571 mol CO₂

Comparing the expected moles, we see that the calculated amount of CO₂ is greater when used \(C_{2} H_{6}\) as the limiting reactant. Therefore, the limiting reactant in this reaction is \(C_{2} H_{6}\).

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Answer:

1. acid produced by plants growing on rocks

plz give me BRAINLIEST answer

Answer:

A number of organisms in a specific area/place

Explanation:

Answer:

D is the answer

Explanation:

Reverse the sign of the second equation, change the sign of the enthalpy and add. Option B

The enthalpy could be obtained by the use of the Hess law of constant heat summation. As such, we have a number steps and it is possible for use to obtain the enthalpy of the final reaction as shown by a series of manipulations.

By inspection, we can see that, if we desire to obtain the enthalpy of the final reaction as shown, then we have to reverse the sign of the second equation, change the sign of the enthalpy and add. Option B

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Water molecules did not have a slight negative charge on one end and a slight positive charge on another, the loss of polarity would have profound effects on various biological, chemical, and physical processes. The unique properties of water that are vital for life as we know it would be significantly altered, potentially rendering many biological systems nonfunctional and disrupting the stability of ecosystems.

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Answer:

Ground state

the state with the smallest amount of energy.

The electronic configuration of the divalent calcium ion is;\(1s^2, 2s^2, 2p^6\). Option A

Calcium is an element found in group 12 of the periodic table. The group has elements that have a valence of 2. This means that they can lose electrons to form an ion.

Remember that an ion forms when there is a loss or gain of electrons in the atom. Now calcium forms an ion by loss of electrons, hence the positive sign.

The electronic configuration of the divalent calcium ion is \(1s^2, 2s^2, 2p^6\) . Option A

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Equivalence point is dependent on stoichiometry of balanced reaction of acid and base. Stoichiometry only considers number of mols involved, not strength of reactants involved.

To ascertain how much of a specific drug is present in a sample, an experiment called a b is done. A diprotic acid is one that has a two-proton (H+) capacity per molecule. Two equivalence points—points at which the number of moles of acid and base are equal—are present when a diprotic acid is titrated with NaOH. When all of the acids have been neutralised, the first equivalence point is reached; meanwhile, the second equivalence point is reached when the surplus base has been neutralised. The amount of NaOH solution required to go from the first equivalence point to the second equivalence point is twice the amount required to travel from the first equivalence point to the first equivalence point.

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Answer:

optical engineer

Explanation:

Answer:optical engineer

Explanation: HOPE IT HELPS YOU .PLEASE GIVE BRAINLIEST THANKS . .

Answer:

1.12x10⁷ mi / min

Explanation:

Speed is a magnitude defined as the distance an object travels per unit of time.

Speed light is 3.00x10⁸ m/s. To convert this to miles per minute we need to convert the meters to miles and the seconds to minutes:

3.00x10⁸ m/s * (1mi / 1609.344m) = 186411.4 mi/s

186411.4 mi/s * (60s / 1min) =

Answer:

Voltage is the measure of electric potential energy per unit charge, current is the flow of electric charge through a circuit, and resistance is the property of a material that opposes the flow of electric current.

Ohm's Law relates these three concepts by stating that current is directly proportional to voltage and inversely proportional to resistance.

Hope this helps!