Organic chemists often purify organic compounds by a method known as fractional crystallization. An experimenter wanted to prepare and purify 4.85 g of aniline. Ten 4.85-gram specimens of aniline were prepared and purified to produce acetanilide. The following dry yields were obtained: 3.85, 3.88, 3.90, 3.62, 3.72, 3.80, 3.85, 3.36, 4.01, 3.82. Construct a 95 percent confidence interval for the mean number of grams of acetanilide that can be recovered from 4.85 grams of aniline.

Answer:

a temperature of -10 °C

Explanation:

The thermometer would indicate a temperature of -10 °C even if the wind speed decreased to 0 mph. The wind speed affects the perceived temperature, but it does not actually change the air temperature. So, if the air temperature is -10 °C, it would remain the same regardless of the wind speed.

ALLEN

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

Answer:

% yield of the student's experiment is

\(\frac{0.34}{0.60}\) ˣ 100 = 56.67%

Explanation:

given

volume of acetone= 43.8 mL

molar weight of acetone = 58.08 g/mol

density of acetone = 0.791 g/mL

A student mixes 43.8 mL of acetone (58.08 g/mol, 0.791 g/mL)

43.8 mL = 43.8mL × 0.791g/mL

= 34.6458g ≈34.65g

1 mole of acetone = 58.08g

∴34.65g = 34.65g/58.08g

= 0.60mol

molecular weight of the product 1,5-diphenylpenta-1,4-dien-3-one = 234.29 g/mol

mole = mass/ molar weight

mole = 79.4g/ 234.29g/mol

mole(n) = 0.3389mol ≈ 0.34mol

1 mole of acetone will produce 1 mole of the product

∴0.60mol of acetone will produce 0.60mol of the product

but we get 0.34mol of the product

∴ % yield of the student's experiment is

\(\frac{0.34}{0.60}\) ˣ 100 = 56.67%

Answer:

4P+ 3(O2)= 2(P2O3)

Explanation:

Need to add 4 infront of P on left hand side to balance number of atoms on both sides

Answer:

The actual yield is 2.675 grams and the theoretical yield is 4.0543 grams.

Explanation:

Based on the given question the reaction will be,  

SiO₂ (s) + 4HF ⇒ SiF₄ + 2H₂O (l)

Let w be the concentration of silicon tetrafluoride generated by reacting silicon dioxide with hydrogen fluoride. The mass of silicon dioxide given in the question is 2.339 grams. The molar mass of silicon dioxide is 60 grams per mole and the molar mass of silicon tetrafluoride is 104 grams per mole.  

Therefore, it can be said that 60 grams of silicon dioxide is giving rise to 104 grams of silicon tetrafluoride. So, 2.339 grams of silicon dioxide will generate,  

As w is the weight of silicon tetrafluoride produced, so with the help of cross-multiplication we get,  

60 × w = 2.339 × 104

w = 2.339 × 104 / 60 = 4.054 grams is the theoretical yield. However, the actual yield is 2.675 grams. So, the percent yield will be,  

Percent yield = actual yield / theoretical yield × 100  

Percent yield = 2.675 grams / 4.054 grams × 100

Percent yield = 65.98 %

The theoretical yield would be 4.052 g while the actual yield is 2.675 g

The reaction between SIO2 with HF can be represented by the following equation:

\(SiO_2 + 4HF ---> 2H_2O + SiF_4\)

The ratio of SiO2 reacted to SiF4 produced is 1:1.

Theoretically:

mole of 2.339 SiO2 = mass/molar mass

                               = 2.339/60.08

                                   = 0.00389 moles

Thus, equivalent mole of SiF4 = 0.00389 moles

Mass of 0.00389 moles of SiF4 = mole x molar mass

                                                   = 0.00389 x 104.0791

                                                    = 4.052 g

Hence, the theoretical yield is 4.052 g while the actual yield is 2.675 g

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The completed sentence is given as follows:

As more solvent is added, more dissolves. As some of the solute particles collide with the solid surface, it rejoins the solid crystal.

When maximum solubility is reached, particles are returning to the solid form at the same rate at which they are going into the solution.

Saltwater: Salt: Solvent
Water: Solute

Saltwater- Mixture - Uniform - but, no definite shape. Salt dissolves in water. Salt is best described as a solute.
Soluble: Dissolving

Aqueous Solutions: solutions in which water is the solvent. Water: the universal solvent.

Water is known as the "universal solvent" because it dissolves more compounds than any other liquid. This is critical for all living things on the planet.

It implies that water transports vital chemicals, minerals, and nutrients everywhere it travels, whether through the air, the earth, or our bodies.

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Answer:

0.4941, 0.5059

Explanation:

\(P_N\) = Partial pressure of nitrogen = 417 mm Hg

\(P_{Xe}\) = Partial pressure of xenon = 427 mm Hg

Total pressure in the system is given by

\(P=P_N+P_{Xe}\\\Rightarrow P=417+427=844\ \text{mm Hg}\)

Mole fraction is given by

\(X_N=\dfrac{P_N}{P}\\\Rightarrow X_N=\dfrac{417}{844}\\\Rightarrow X_{N}=0.4941\)

For xenon

\(X_{Xe}=1-0.4941=0.5059\)

or

\(X_{Xe}=\dfrac{P_{Xe}}{P}\\\Rightarrow X_{Xe}=\dfrac{427}{844}\\\Rightarrow X_{Xe}=0.5059\)

So, mole fraction of nitrogen is 0.4941 and xenon is 0.5059.

Answer:

Explanation:

From the information given :

we can understand the solute is glucose and the solvent is water,

So, the weight of glucose = 20.23 g

the molecular weight of glucose = 180.2 g/mol

weight of water = 95. 75 g

the molecular weight of water = 18.02 g/mol

pure vapor pressure of water \(P_A = 26.7 \ mmHg\) at 27°C

moles of glucose = weight of glucose/ molecular weight of glucose

= 20.23/180.2

= 0.11 mole

moles of water =  weight of water / molecular weight of water

= 95.75/18.02

= 5.31 mole

mole fraction of glucose \(X_{glucose} =\) (moles of glucose)/(moles of glucose+ moles of water)

\(X_{glucose} =\) 0.11/(0.11 + 5.31)

\(X_{glucose} =\)  0.0203

mole fraction of glucose \(X_{water} =\) (moles of water)/(moles of water+ moles of glucose)

\(X_{water} =\) 5.31/ (5.31 + 0.11)

\(X_{water} =\)  0.9797

Using Raoult's Law:

\(P_S = P^0_A \times X_A \ \ \ OR \ \ \ P_A = P^0_A \times X_A\)

where:

\(P_S\) = vapor pressure of the solution

\(P_A\) = total vapor pressure of the solution

\(P^0_A\)= vapor pressure of the solvent in the pure state

\(X_A\) = mole fraction of solvent i.e. water

\(P_A =\) 95.75 ×  0.9797

\(P_A =\)  93.81 mmHg

the total vapor pressure of the solution = 93.81 mmHg

\(\boxed{\sf Density=\dfrac{Mass}{Volume}}\)

\(\\ \sf\longmapsto Density=\dfrac{9.2}{12.3}\)

\(\\ \sf\longmapsto Density=0.74g/cm^3\)

It will float in water

Answer:

it is released and absorbed:)

Answer:

concentration is the abundance of a constituent divided by the total volume of a mixture.

Explanation:

hope this helps <33

have a good afternoon:)

and also can i have brainliest plz? :D

Answer:

52.2. The large chicken egg minus the human head is 52.2 g. The egg is not a good model because it does not resemble a human head. Also, the egg is made of parts such as food and things that are not similar to a human head. Furthermore, they are not the same shape.

Explanation:

Answer:

8.34

Explanation:

1) how much moles of NH₃ are in the reaction;

2) how much moles of H₂ are in the reaction;

3)  the required mass of the H₂.

all the details are in the attachment; the answer is marked with red colour.

Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.

Note2: the suggested solution is not the shortest one.

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume of gas = 500 mL

density = 0.88 g/mL

We have

mass = 0.88 × 500

We have the final answer as

Hope this helps you

Nadia will take 8 seconds to reach her friend's house.

Speed is the measure of the distance traveled by an object per unit of time. It is a scalar quantity and is typically expressed in units such as meters per second (m/s), miles per hour (mph), or kilometers per hour (km/h).

To calculate the time Nadia will take to reach her friend's house, we can use the formula;

time = distance / speed

where distance is the amount of space traveled by an object, and time is the duration of travel.

Put the values given in the problem, we have:

time = 24 meters / 3 m/s

time = 8 seconds

Therefore, Nadia will take 8 seconds.

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As per the standard data, the heat evolved during one mole of calcium carbonate decomposes is 177.8 KJ. Thus 15 g or 0.15 moles of calcium carbonate when decomposed will produce 26.67 KJ of heat.

Reaction enthalpy of a substance is the heat evolved or absorbed during a reaction. Reaction enthalpy is negative for an exothermic reaction and positive for an endothermic reaction.

Molar mass of calcium carbonate = 100 g.

no.of moles in 15 g = 15 /100 = 0.15 moles.

One mole or 100 g of calcium carbonate decompose to evolve 177.8 KJ according to the scientific record.

Thus, heat evolved by the decomposition of 0.15 moles is 0.15 × 177.8 KJ = 26.67 KJ.

Hence, the heat evolved during the decomposition of 15 g of calcium carbonate is 26.67 KJ.

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Answer:

The number of molecules of water us 1.50× 10²⁵ molecules

Explanation:

From N=nL

where L =avogadro number ( 6.02× 10^²³ entities)

The number of the molecules of water =1

n (amount of substance)=25 moles

hence (N) = 25×1×6.02×10^²³

=1.50×10²⁵ molecules of H2O

Answer

172 g/mol

Explanation

The chemical formula of copper I carbonate is Cu₂CO₃

Using the given molar masses of:

Cu = 56 g/mol

C = 12 g/mol

O = 16 g/mol

The molar mass of Cu₂CO₃ = (2 x 56 g/mol) + 12 g/mol + (3 x 16 g/mol)

Cu₂CO₃ = 112 g/mol + 12 g/mol + 48 g/mol

Cu₂CO₃ = 172 g/mol

Answer:

cool and dry

Answer:

A cool and dry

Explanation:

on edge

Answer:
52 grams (B)

Explanation:

Given: 4.16 grams of W
           1.92 grams of O2

The reaction:
2W + 1.5 O2 ----> W2O3

We are gonna calculate the molar mass of W with ratios
So, to calculate that, we will multiply the moles by molar masses (O2: 1.5 * 32 & W: 2x) and divide the over the given masses and equating both fractions:

\(\frac{2x}{4.16} = \frac{1.5*32}{1.92}\)

\(x = \frac{1.5*32*4.16}{2*1.92} = 52 grams\)

According to molar concentration, 0.055 ×10\(^-3\) mg of sodium sulfide are needed to completely react with 4.80 mL of a 0.0900 M aqueous solution of cadmium nitrate, to form a precipitate of CdS.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

mass of sodium sulfide is calculated as, 0.09×236.42×0.0048=0.102 g.Now, according to stoichiometry where 78.04 g Na₂S gives 144.46 g CdS ,for 0.102 g  sodium sulfide 78.04×0.102/144.46=0.055 g or 0.055×10\(^-3\) mg.

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Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

Carbon (C) = 40.92%

Hydrogen (H) = 4.58%

Oxygen (O) = 54.50%

The empirical formula for the compound can be obtained as follow:

C = 40.92%

H = 4.58%

O = 54.50%

Divide by their molar mass

C = 40.92/12 = 3.41

H = 4.58/1 = 4.58

O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

H = 1.3 x 3 = 4

O = 1 x 3 = 3

The empirical formula for the compound is C3H4O3

Hey dear,

Benzene is a 6-C cyclic structure with alternate double bonds.

● Reactions -

1) Benzene to cyclohexane -

Benzene can be reduced to cyclohexane with

the help of Ni/H2. C6H6 + 3H2 --> C6H12

All 3 double bonds in ring are reduced here.

2) Benzene to benzoquinone - Benzene can be oxidized to benzoquinone with

the help of acidic K2Cr207. C6H6 +3[O] --> C6H4O2 + H2O

Only 1 double bond is lost in this reaction.

Hope this helps you.

The options that affect the amount that the freezing point is lowered by the addition of the solute include :

The increasing of a solvent's boiling point as a result of the addition of a solute is known as boiling point elevation. Similar to freezing point depression, adding a solute lowers the freezing point of a solvent. In actuality, a solvent's freezing point drops as its boiling point rises.

Any solvent's freezing point will be lowered by the presence of a solute; this action is known as freezing-point depression. The fact that the solute is present in the liquid solution but not in the pure solid solvent is crucial to understanding this phenomenon.

This includes the compound being ionic or the solubility of the solvent.

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Answer:

sedimentary rocks

Explanation:

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