Other than translation, what transformation is used to create this frieze pattern?


glide reflection

180° rotation

horizontal reflection

vertical reflection

The empirical probability of drawing the cards will be 6 / 55.

The ratio of the number of outcomes in which a defined event occurs to the total number of trials, not in a theoretical sample space but in a real experiment, is the empirical probability, relative frequency, or experimental probability of an event.

Given that a card is drawn one at a time from a well-shuffled deck of 52 cards. In 13 repetitions of this experiment, 1 king is drawn.

The number of kings in a well-shuffled deck consists of 52 cards which is 4.

The number of ways of drawing consists of 4 kings in 13 repetitions which is ¹³C₄.

In 13 repetitions, 2 kings are drawn by ¹³C₂ ways,

The empirical probability will be calculated as,

P(E) = ¹³C₂ / ¹³C₄

P(E) = [ (13!) / (13-2)! ] ÷ [ (13!) / ( 13-4)!(4!) ]

P(E) = ( 4 x 3 ) / ( 11 x 10)

P(E) = 6 / 55

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Answer:

Step-by-step explanation:

Madison,   count from dot to dot, starting with the dot on the left.

count up.   then over,    slope is rise over run

I count up 3 , then over 4

or

slope = 3/4

Answer:3/4

Step-by-step explanation:

Answer:

Step-by-step explanation:

To answer this question we need to first understand and compare it with the equation of straight line.

i.e \(y= mx+c\)  which is the equation of line

where m= slope

           y= dependent variable

           x= independent variable

          c= intercept

Given

\(y= 25+5h\)

comparing both expression we can see that

25 corresponds to c which is the intercept

The flat pays $25 represent the intercept.

Given that,

Based on the above information, the calculation is as follows:

y = mx + c

where m= slope

y= dependent variable

x= independent variable

c= intercept

And,

y = 25 + 5h

So it is an intercept

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Answer:

D

Step-by-step explanation:

no explination

Answer:

Exponential growth

Step-by-step explanation:

This is not a negative so it is growing.

Hope this helps!

Answer:

infinite

Step-by-step explanation:

Both sides are equal

Answer:

No solution

Step-by-step explanation:

5x−4≥12 AND 12x+5≤−4

solve it separately

5x - 4>=12

add 4 on both sides

5x >= 16

Divide both sides by 5

x > = 16/5

12x+5≤−4

subtract 5 from both sides

12x <= -9

divide both sides by 12

x<= -9/12

x<=-9/12   and x>= 16/5

There is no intersection between the inequalities

so there is no solution

Answer:

2

Step-by-step explanation:

1) substitute a=6 into 36/3a:

36/3×6

2) calculate: 36/3×6 ->2

Answer:

Yes it does!

Step-by-step explanation:

Given, the growth of the bamboo changes over time. Therefore, the growth is directly proportional as it grows more with increase in time.

Answer:

V = 56.5 mi^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

V = pi ( 3)^2 (2)

V = 18 pi

Letting p = 3.14

V = 56.52 mi^3

Rounding to the nearest tenth

V = 56.5 mi^3

The given linear programming problem aims to maximize the objective function \(Z = 3x1 + 2x2\), subject to four constraints: x1 ≤ 4, x2 ≤ 6, 3x1 + 2x2 ≤ 18, and x1 ≥ 0, x2 ≥ 0.

The objective of linear programming is to optimize (maximize or minimize) a linear objective function while satisfying a set of linear constraints. In this case, the objective is to maximize \(Z = 3x1 + 2x2\).

The constraints in the problem define the feasible region, which is the set of all points that satisfy the constraints. The constraints state that x1 must be less than or equal to 4, x2 must be less than or equal to 6, and the linear combination \(3x1 + 2x2\) must be less than or equal to 18. Additionally, both x1 and x2 must be greater than or equal to zero.

To solve this linear programming problem, graphical methods or optimization algorithms such as the simplex method can be employed. The feasible region is determined by graphing the constraints and finding the overlapping region. The optimal solution is the point within the feasible region that maximizes the objective function.

The explanation of the solution, including the optimal values of x1 and x2, the maximum value of Z, and the graphical representation of the problem, can be provided based on the chosen method of solving the linear programming problem.

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Answer: x=1

Step-by-step explanation:

x-5=2x-6

x-5+6=2x-6+6

x+1=2x

x-x+1=2x-x

2x-x=1

x=1

Answer: x = 1

Step-by-step explanation:

fewer or less than means minus -

difference of x and 5 = x - 5

6 fewer = - 6

twice the number of x = 2x

x - 5 = 2x - 6

x = 2x - 6 + 5

x -2x = - 6 + 5

- x = - 1

x = 1

checking

1 - 5 = 2(1) - 6

4 = 2 - 6

4 = 4

The probability of obtaining the face showing a six between 15 and 20 times out of 100 rolls of the die ≈ 0.3106 and the probability of the sum of the face values of the 100 trials being less than 300 ≈ 0.1635.

To cumulate the probability of the face showing a six turns up between 15 and 20 times when rolling a six-sided die 100 times, we can use the normal approximation to the binomial distribution.

The probability of rolling a six on a fair six-sided die is 1/6, and the probability of not rolling a six is 5/6.

Let's define a random variable X as the number of times a six appears when rolling the die 100 times.

X follows a binomial distribution with parameters n = 100 (number of trials) and p = 1/6 (probability of success).

To use the normal approximation, we need to calculate the mean (μ) and standard deviation (σ) of the binomial distribution:

μ = n * p = 100 * 1/6 = 16.67

σ = √(n*p*(1 - p)) = √(100 * 1/6 * 5/6) = 4.08

Now, we can standardize the values 15 and 20 using the normal distribution:

z1 = (15 - μ) / σ = (15 - 16.67) / 4.08 ≈ -0.41

z2 = (20 - μ) / σ = (20 - 16.67) / 4.08 ≈ 0.81

Using a standard normal distribution table or a calculator, we can find the cumulative probabilities for these z-values:

P(15 ≤ X ≤ 20) ≈ P(-0.41 ≤ Z ≤ 0.81)

From the table or calculator, we find that P(-0.41 ≤ Z ≤ 0.81) is approximately 0.3106.

Therefore, the probability that the face showing a six turns up between 15 and 20 times when rolling the die 100 times is approximately 0.3106.

To cumulate the probability that the sum of the face values of the 100 trials is less than 300, we need to consider the distribution of the sum of independent rolls of a six-sided die.

The sum of the face values of the 100 trials will follow an approximately normal distribution due to the Central Limit Theorem.

The mean (μ) of the sum is 100 * (1+2+3+4+5+6)/6 = 350.

The standard deviation (σ) of the sum is:

√(100 * (1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2)/6) ≈ 50.99.

Now, we can standardize the value 300 using the normal distribution:

z = (300 - μ) / σ = (300 - 350) / 50.99 ≈ -0.98.

Using a standard normal distribution table or calculator, we can find the cumulative probability for this z-value:

P(X < 300) ≈ P(Z < -0.98) ≈ 0.1635.

Hence, the probability that the sum of the face values of the 100 trials is less than 300 ≈ 0.1635.

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The probability of selecting exactly three clubs from a standard deck is 0.088. Where n = 5; p = 0.25; q = 0.75; and x = 3 . It is calculated by using binomial probability.

The binomial probability formula is

P(X = x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾ = \(\frac{n!}{(n-x)!x!} p^xq^{(n-x)}\)

Where n is the number of trials, p i is the probability of success, and q is the probability of failure.

And q = 1 - p

It is given that, a card is selected from a standard deck and replaced.

This experiment has repeated a total of five times. i.e., trials n = 5

So, the probability of success is p = 1/4 = 0.25

(Since one card is to be selected from the five trials where each time the card is replaced)

Then, the probability of failure is q = 1 - 0.25 = 0.75

And it is given that we need to find the probability of selecting exactly three clubs. So, the required random variable is x = 3.

Then, using the binomial probability formula, we get

P(X = x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾

⇒ P(X = 3) = ⁵C₃ p³q⁽⁵⁻³⁾ = ⁵C₃(0.25)³(0.75)² = 0.0878

On rounding off, we get the required probability as 0.088.

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Answer:

  no

Step-by-step explanation:

The only question here seems to be ...

  Have you ever been on or seen a ride like this at a fair or amusement park?

__

I have not seen such a ride.

I have not seen such a ride.

A large outdoor area with fairground rides, shows, refreshments, games of chance or skill, and other entertainments.

The only question here seems to be ...

 Have you ever been on or seen a ride like this at a fair or amusement park?

I have not seen such a ride.

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Answer:

see below

Step-by-step explanation:

123,116,109,102,95.

First find the common difference

d = 116 - 123 = -7

We are subtracting 7 each time

Using the formula

a1 = 123

d=-7

an = 123+ (n-1)(-7)

We need to find the 100th term

Let n = 100

a100 = 123 +(100-1) (-7)

         = 123+(99)(-7)

        = 123-693

        = -570

Answer:

1) arithmetic

2) geometric

3) geometic

4) geometric

I may be wrong tho

The first five terms of each sequence can be written from the nth term of the sequence and the type of sequence are, arithmetic, geometric, geometric, geometric, and geometric respectively.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

It is given that:

The sequences are:

1. a(1) = 7, a(n) = a(n - 1) - 3 for n > 2.

Plug n = 2 in the a(n)

a(2) = a(2 - 1) - 3

a(2) = a(1) - 3

a(2) = 7 - 3

a(2) = 4

lug n = 3

a(3) = 1

The first five terms are:

7, 4, 1, -2, -5 (arithmetic sequence)

2. b(1) = 2, b(n) = 2[b(n - 1) - 1] for n > 2.

Similarly,

The first five terms are:

2, 2, 2, 2, 2 (geometric sequence)

3. c(1) = 3. c(n) = 10 • c(n - 1) for n > 2.

The first five terms are:

3, 30, 300, 3000, 30000 (geometric sequence)

4. d(1) = 1, d(n) = n • d(n - 1) for n > 2.​

1, 2, 6, 24, 48 (geometric sequence)

Thus, the first five terms of each sequence can be written from the nth term of the sequence and the type of sequence are, arithmetic, geometric, geometric, geometric, and geometric respectively.

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Answer:

Slope = -2/3

Step-by-step explanation:

Slope = \(\frac{y_{2} -y_{1}}{x_{2}-x_{1}}\)

Slope = \(\frac{-1 -(-5)}{-4-2} = \frac{4}{-6} =-\frac{2}{3}\)

a. The graph of the budget line would have hamburgers on the x-axis and bags of figs on the y-axis. b. the budget line equation represents Rachel's affordability based on her income and the prices of hamburgers and figs. Changes in prices, income, or additional resources can affect the slope, position, or rotation of the budget line on a graph.

a) Rachel's budget line equation can be written as follows:

Budget = (Price of Hamburger * Quantity of Hamburgers) + (Price of Figs * Quantity of Figs)

Since the price per hamburger is $3 and the price per bag of figs is $2, the equation becomes:

Budget = 3x + 2y

Where x represents the quantity of hamburgers and y represents the quantity of bags of figs. The graph of the budget line would have hamburgers on the x-axis and bags of figs on the y-axis.

b) If the price of figs increases to $3, the new budget line equation becomes:

Budget = 3x + 3y

The graph of the new budget line would show a steeper slope compared to the original budget line. This indicates that the relative price of figs has increased, making them relatively more expensive compared to hamburgers.

c) In this scenario, Rachel has an income of $50, the price per hamburger is $3, the price per bag of figs is $3, and she receives an additional $10 in cash from a friend. The new budget line equation can be written as:

Budget = (3x + 3y) + 10

The graph of the new budget line would shift upward parallel to the original budget line. The additional cash from Rachel's friend increases her purchasing power, allowing her to afford more hamburgers and/or bags of figs.

d) Now, Rachel's friend gives her a gift basket containing 3 free bags of figs. In this case, the budget line equation remains the same as in part c:

Budget = (3x + 3y) + 10

However, since Rachel receives 3 free bags of figs, she can allocate more of her budget towards purchasing hamburgers. This would cause the budget line to rotate outward from the y-intercept, resulting in a flatter slope. The new budget line would reflect Rachel's ability to purchase more hamburgers with the same income and price of figs.

In summary, the budget line equation represents Rachel's affordability based on her income and the prices of hamburgers and figs. Changes in prices, income, or additional resources can affect the slope, position, or rotation of the budget line on a graph.

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Answer:

C 4 loaves

Step-by-step explanation:

The items matched in the left column to the items in the right column are

Ratio is the number representing a comparison between two named things or quantities.

1. total to fish

= 8 : 3

2. starfish to fish

= 5 : 3

3. starfish to total

= 5 : 8

4. fish to starfish

3 : 5

In conclusion, the ratio of the total to fish to starfish is 8 : 3 : 5

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Answer:

y=12x/5

x=5y/12

Step-by-step explanation:

y:3x-y=4

y=4(3x-y)

because if there is divide sign if it will go to another side it will be multiply

y=12x-4y

y+4y=12x

5y=12x

y=12x/5

or, x=5y/12

Hope it is helpful for you

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It took Vic (1/2) hour to get from his school to the soccer field.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

We know, Distance = Speed×Time or d = rt.

Given, Let, The distance between the soccer field from his school be 'd'.

Therefore, From the given information,

10t = 30(t - 1/3).

10t = 30t - 10.

- 20t = - 10.

t = 1/2.

So, The distance is 10×(1/2) miles = 5 miles or 30[(1/2) - (1/3) miles = 30×(1/6) = 5 miles.

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Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that \(x \le 0\) but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when \(x \ge 0\)

So we could have this piecewise function

\(f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}\)

Or we could easily swap the "or equal to" portion to move to the first part instead like this

\(f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}\)

Either way, we're involving the equations mentioned in choice A

Answer:

occurred during the same period of time

Step-by-step explanation:

Answer:

Occurred in the same period of time

Step-by-step explanation:

"Studying" and "making" are both past tense, and the word "while" implies it was the same time period.

Hope this helps :)

Answer:

Well I got \(\frac{1}{4} plus or minus \sqrt{33}\)

Step-by-step explanation:

1/4±\(\sqrt{33}\)

Answer:

The person above is correct this is just confirmation

Step-by-step explanation:

Answer:

36.33

Step-by-step explanation:

The given figure is pentagon

The sum of angles of polygon is (2n-4)*90 where n is number of sides of polygon

for pentagon number of sides is 5

thus, n = 5

\

sum of angles of pentagon = (2*5-4)*90 = 6*90 = 540

Given angles of pentagon

t, 149 , t+144, 3t -11 , t+40

Thus, sum of all these angles should be equal to 540

t + 149 + t+144 + 3t -11 + t+40 = 540

=> 6t + 322 = 540

=> 6t = 540 - 322 = 218

=> t = 218/6 = 36.33

Thus, t = 36.33