Out of the following events, which one occurred first in the history of the universe?
(1 Point)
Answers
Cosmic inflation occurred first in the history of the universe. The correct option is D.
Cosmic inflation is believed to have occurred first in the history of the universe, shortly after the Big Bang. It is a hypothetical rapid expansion of spacetime that is thought to have taken place within the first fraction of a second after the Big Bang. During this inflationary period, the universe is believed to have undergone an exponential expansion, which helped to smooth out irregularities and set the stage for the subsequent formation of galaxies, clusters of galaxies, and other cosmic structures.
Now let's consider the other options and explain why they did not occur before cosmic inflation:
A. The formation of the Cosmic Microwave Background (CMB): The CMB is the afterglow of the Big Bang, and it originated about 380,000 years after the Big Bang. Cosmic inflation is thought to have occurred much earlier than the formation of the CMB, influencing the large-scale structure of the universe before it.
B. The formation of atoms: After the initial stages of the universe, protons, neutrons, and electrons were present. However, it took some time for these particles to combine and form stable atoms. The formation of atoms happened after the era of cosmic inflation and the formation of nuclei.
C. The formation of nuclei: Nucleosynthesis, the process of forming atomic nuclei, occurred during the early stages of the universe. It took place shortly after the Big Bang, when the universe was around a few minutes old. While the formation of nuclei happened before the formation of atoms, it still occurred after cosmic inflation.
Therefore, cosmic inflation is believed to have taken place first, followed by the formation of nuclei, the formation of atoms, and finally the formation of the Cosmic Microwave Background.
Provided question is incomplete , the questioon is,
Out of the following events, which one occured first in the history of the unvierse?
A. the formation of the Cosmic Microwave Background.
B. the formation of atoms
C. the formation of nuclei
D. cosmic inflation
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Related Questions
min has a shelf filled with books. the books have different thicknesses. this line plot shows the thickness of each book. he piles the four thickest books on top of each other. how thick is the pile? enter your answer as a mixed number in simplest form by filling in the boxes.
Answers
Given that Min has a shelf full of books, each of which is a different thickness, the pile is 3 cm thick.
The thickness of each book is displayed on the line graph. The four heaviest books are stacked on top of one another by Min. Given line plot: According to the given line plot, Thickness of the thickest book is 0.9 cm
Thickness of the second-thickest book is 0.8 cm
Thickness of the third-thickest book is 0.7 cm
Thickness of the fourth-thickest book is 0.6 cm
The thickness of the pile will be the sum of the thickness of all the four thickest books.
Thickness of the pile = 0.9 + 0.8 + 0.7 + 0.6
Thickness of the pile = 3 cm
Therefore, the thickness of the pile is 3 cm.
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Classify the following as a chemical change (C) or a physical change (P) : A bike rusting
Answers
Answer:
chemical change
Explanation:
When a substance rusts it reacts with air and moisture, iron oxide is formed as a product. Since there is a substance formed from the reaction this makes it a chemical change
Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continue walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other
Answers
Answer:
Δt=48 s
Explanation:
v: Barry's speed
v.: speed of the walkway
Δx=30 m
Δt1=30 s , Δt2=120 s
|Δx1|=|Δx2|
Δx=v*Δt
=> (v+v.)*30=(v-v.)*120
v=v.*5/3
30=(v+v.)*30
=> 30=(5v./3 +v.)*30
v.=3/8 m/s
v=5v./3 , v.=3/8
=> v=5/8 m/s
Δx=v*Δt
30=5/8 *Δt
Δt=48 s
What is force. in your own words
Answers
Answer:
force is a push or pull that exerted on a body
Answer:
force is that push or pull on a body that changes or tends to change the state of rest or of uniform motion in a straight line.
Explanation:
hope this helps
what is the sum of 231 + 5080 + 80 + 13 + 9
Answers
Answer:
5413
Explanation:
add them up
Part A An advertisement claims that a centrifuge takes up only 0.127 m of bench space but can produce a radial acceleration of 3100 g at 5000 rev/min For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Throwing a discus. Calculate the required radius of the centrifuge. Express your answer in meters. ALQ R 0 2 ? Submit Request Answer Part B Is the claim realistic? Yes No Submit Previous Answers ✓ Correct EVALUATE: The diameter is then 0.222 m, which is larger than 0.127 m, so the claim is not realistic.
Answers
Part A: The required radius of the centrifuge is 0.111 m.
Part B: The claim is not realistic.
Part A: To calculate the required radius of the centrifuge, we need to use the formula for radial acceleration:
a = R * (ω²),
where a is the radial acceleration, R is the radius, and ω is the angular velocity. The given radial acceleration is 3100 g (g = 9.81 m/s²), so we need to convert it to m/s²:
a = 3100 * 9.81 m/s² = 30411 m/s².
Next, we need to convert the given 5000 rev/min to radians per second:
ω = (5000 rev/min) * (2π rad/rev) * (1 min/60 s) = 523.6 rad/s.
Now, we can solve for the radius R:
R = a / (ω²) = 30411 m/s² / (523.6 rad/s)² = 0.111 m.
Part B: Since the required radius is 0.111 m, the diameter of the centrifuge would be 2 * 0.111 m = 0.222 m. This is larger than the advertised 0.127 m of bench space. Therefore, the claim is not realistic.
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An observer standing near a window 5 m high observe that an object falling downwards is passing across the window in 0.5 s. Find at what height above the window the object was dropped. (g = 10 m/s2).
Answers
Answer:
Explanation:
An object in free fall, NOT experiencing parabolic motion, has an equation of
\(h(t)=\frac{1}{2} gt^2+h_0\) which says:
The height of an object with respect to time in seconds is equal to the pull of gravity times time-squared plus the height from which it was dropped. Normally we use -9.8 for gravity but you said to use 10, so be it.
For us, h(t) is 5 because we are looking for the height of the window when the object is 5 m off the ground at .5 seconds;
g = 10 m/s/s, and
t = .5sec
\(5=\frac{1}{2}(-10)(.5)^2\)+h and
5 = -5(.5)² + h and
5 = -5(.25) + h and
5 = -1.25 + h so
h = 6.25
That's how high the window is above the ground.
Height above the window object was dropped is 6.25 m
Given:
Height of window = 5 m
Time taken to drop object = 0.5 sec
Gravitational acceleration = 10 m/s²
Find:
Height above the window object was dropped
Computation:
We know that;
\(H(T) = \frac{1}{2}(g)(t^2) + H(S)\\\\5 = \frac{1}{2}(10)(0.5^2) +H(S)\\\\5 = (5)(0.5^2)+H(S)\\\\H(S) = 6.25\)
So,
Height above the window object was dropped = 6.25 m
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Explain how the loudspeaker converts current in an electrical circuit to a sound wave. (6)
Answers
Alternating current supplied to the loudspeaker creates sound waves in the following way:
A current in the coil creates a magnetic field around it. The magnetic field interacts with the permanent magnet generating a force, which pushes the cone outwards. The current changes direction.
A change in the magnetic field through a coil can induce a potential difference across it which drives a current. The voltage and current changes in a transformer can be calculated, as power transfer is constant.
The motor effect is used inside headphones, which contain small loudspeakers. In these devices, variations in an electric current cause variations in the magnetic field produced by an electromagnet. This causes a cone to move, which creates pressure variations in the air and forms sound waves.
The end of the speaker cone is surrounded by a permanent magnet. A coil of wire which carries electrical signals is wrapped around the end of the cone. The movement generated causes the cone to vibrate.
The alternating current supplied to the loudspeaker creates sound waves in the following way:
A current in the coil creates a magnetic field around it. The magnetic field interacts with the permanent magnet generating a force, which pushes the cone outwards. The current changes direction. The direction of the magnetic field around the coil reverses. The force on the cone now pulls it back in.6. Repeatedly alternating the current direction makes the converts vibrate in and out.
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A motorcycle cop, parked at the side of a highway reading a magazine, is passed by a woman in a red Ferrari 308 GTS doing 120.0 km/h. After a few attempts to get his cycle started, the officer roars off 2.00 s later. At what average rate must he accelerate if 159 km/h is his top speed and he is to catch her just at the state line 3.04 km away?
Answers
Answer:
XZXDHF
Explanation:ZDHF
Please help!!!! Will mark brainliest.
Spiderman, on a strand of web, accelerates upward at 1.3 m/s2. If spiderman has a mass of 76 kg,
what is the force in the strand of webbing?
Answers
Answer:
Approximately \(8.4 \times 10^{2}\; \rm N\), assuming that \(g = 9.8\; \rm m \cdot s^{-2}\).
Explanation:
Let \(m\) and \(a\) denote the mass and acceleration of Spiderman, respectively.
There are two forces on Spiderman:
Downward gravitational attraction from the earth: \(W = m \cdot g\).Upward tension force from the strand of web \(F(\text{tension})\).The directions of these two forces are exactly opposite of one another. Besides, because Spiderman is accelerating upwards, the magnitude of \(F(\text{tension})\) (which points upwards) should be greater than that of \(W\) (which points downwards towards the ground.)
Subtract the smaller force from the larger one to find the net force on Spiderman:
\((\text{Net Force}) = F(\text{tension}) - W\).
On the other hand, apply Newton's Second Law of motion to find the value of the net force on Spiderman:
\((\text{Net Force}) = m \cdot a\).
Combine these two equations to get:
\(m \cdot a = (\text{Net Force}) = F(\text{tension}) - W\).
Therefore:
\(\begin{aligned}& F(\text{tension})\\ &= m \cdot a + W \\ &= m \cdot (a + g)\\ &= 76\; \rm kg \times \left(1.3\; \rm m \cdot s^{-2} + 9.8\; \rm m \cdot s^{-2}\right)\\ &\approx 8.4\times 10^{2}\; \rm N\end{aligned}\).
By Newton's Third Law of motion, Spiderman would exert a force of the same size on the strand of web. Hence, the size of the force in the strand of the web should be approximately \(8.4\times 10^{2}\; \rm N\) (downwards.)
A 650 nm laser shines through a diffraction grating. The first bright band is 0.59 m from the center. Another laser is only deflected to 0.41 m from the center. What is the wavelength of this light
Answers
The wavelength of the second laser is 650 nm.When A 650 nm laser shines through a diffraction grating. The first bright band is 0.59 m from the center.
We can use the formula for the position of the bright fringes in a diffraction grating:
d sinθ = mλ,
where d is the spacing of the grating, θ is the angle between the incoming beam and the direction of the bright fringe, m is the order of the fringe, and λ is the wavelength of the light.
Let's assume that the first bright band corresponds to the m=1 order, and that the distance between the bright bands is the same for both lasers. Then we have:
d sinθ₁ = λ,
d sinθ₂ = λ + Δλ,
where Δλ is the difference in wavelength between the two lasers.
We can eliminate λ from these equations to obtain:
d sinθ₁ - d sinθ₂ = Δλ,
Substituting the given values, we get:
Δλ = 650 nm.
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A car traveling along the highway needs a certain amount of force exerted on it to stop it in a certain distance. More stopping force is required when the car has:.
Answers
More stopping force is required when the car has to stop in a shorter distance.
What is the relationship between force and acceleration?Force is directly proportional to acceleration according to Newton's second law of motion.
This means that acceleration increases when force increases.
Stopping of a moving car is negative acceleration.
Therefore, more stopping force is required when the car has to stop in a shorter distance.
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The net electric flux through a cubic box with sides that are 22.0 cm long is 4950 N⋅m2/C . What charge is enclosed by the box?
Answers
Answer:
43.83 nC
Explanation:
We know Q = ε₀Ψ where Q = charge enclosed by the cubic box, ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C
So, substituting the values of the variables into the equation, we have
Q = ε₀Ψ
= 8.854 × 10⁻¹² F/m × 4950 Nm²/C
= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C
= 43.8273 × 10⁻⁹ C
= 43.8273 nC
≅ 43.83 nC
Find the magnetic field a distance r from the center of a long wire that has radius a and carries a uniform current per unit area j in the positive z direction.
Answers
The magnetic field a distance r from the center of a long wire that has radius a and carries a uniform current per unit area j in the positive z direction will be B = mu0 * j * \(a^{2}\) / (2r) .
The magnetic field is a region around a magnetic material or a moving electric charge within which the force of magnetism acts. A magnetic field is a force field that is created by moving electric charges and magnetic dipoles and exerts a force on other nearby moving charges and magnetic dipoles.
\(\int\limits {Bdl} \,\) = mu0 * I net
B (2πr) = mu0 ( j A )
B (2πr) = mu0 * j (π \(a^{2}\))
B = mu0 * j * \(a^{2}\) / (2r)
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A car goes around a curve at a constant speed. what is the direction of the net force on the car?
Answers
Answer:
The direction of the net force is at a tangent to the circle.
a particle moves along a straight line such that in 4s it moves from an initial position sa=-8m to a position sb= 3m. Then in another 5 s it moves from Sb to Sc = -6 m. Determine the particle's average velocity and average speed during the 9-s time interval.
Answers
The particle's average velocity during the 9-s time interval is 0.22 m/s and its average speed is 2.22 m/s.
To determine the particle's average velocity and average speed during the 9-s time interval, we need to use the given information and the formulas for average velocity and average speed.
First, let's find the particle's velocity from Sa to Sb. We can use the formula:
velocity = (final position - initial position) / time
velocity = (3m - (-8m)) / 4s
velocity = 11m / 4s
So, the particle's velocity from Sa to Sb is 11m/4s.
Next, let's find the particle's velocity from Sb to Sc. We can use the same formula:
velocity = (final position - initial position) / time
velocity = (-6m - 3m) / 5s
velocity = -9m / 5s
So, the particle's velocity from Sb to Sc is -9m/5s.
Now, to find the particle's average velocity for the 9-s time interval, we can use the formula:
average velocity = total displacement / total time
total displacement = final position - initial position = (-6m) - (-8m) = 2m
total time = 4s + 5s = 9s
average velocity = 2m / 9s
average velocity = 0.22 m/s (rounded to two decimal places)
Finally, to find the particle's average speed for the 9-s time interval, we can use the formula:
average speed = total distance / total time
total distance = distance from Sa to Sb + distance from Sb to Sc = 11m + 9m = 20m
total time = 4s + 5s = 9s
average speed = 20m / 9s
average speed = 2.22 m/s (rounded to two decimal places)
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A baseball is thrown at a 22.5° angle and an initial velocity of 65 m/s. What will be its horizontal
and vertical velocity?
Guys pls someone answer my question I have an exam and this question has 5 marks
Answers
Answer:
Horizontal component = 60.05 m/s
vertical component = 22.96 m/s
Explanation:
cosine(angle) = adjacent / hypotenuse or horizontal / angled velocity
angled velocity * cosine (angle) = horizontal velocity
65 m/s * cosine(22.5) = 60.05 m/s
sine(angle) = adjacent/ hypotenuse or vertical/ angled velocity
angled velocity * sine (angle) = vertical velocity
65m/s sine(22.5) = 22.96 m/s
When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal velocity. This means thatSelect one:a. the force of air resistance is equal to zero. b. the effect of gravity has died down.c. the effect of gravity increases as he becomes closer to the ground.d the acceleration is equal to g.e. the force of air resistance is equal to the weight of the parachutist.
Answers
When an object moves at constant speed, the net force acting on that object is equal to 0:
\(\Sigma\vec{F}=0\)Two forces act over a parachutist while falling: the force of gravity (weight) and the air resistance. Those two forces have opposite directions, we can consider that the air resistance is positive because it points upwards, and the weight is negative because it points downwards:
\(\begin{gathered} \Sigma F=F_{\text{air}}-F_{\text{gravity}}=0 \\ \Rightarrow F_{air}=F_{gravity} \end{gathered}\)Then, when the parachutist reaches the terminal velocity, the force of air resistance is equal to the weight of the parachutist.
Therefore, the answer is option e:
\(\begin{gathered} e) \\ \text{The force of air resistance is equal} \\ \text{to the weight of the parachutist.} \end{gathered}\)How much time is it required for a athlete to lift a 1200 Kg weights up 14m from the ground if he can only produce 9 Kw of power.
Answers
Given,
The mass is m=1200kg
Height is h=14 m
Power is P=9kW
We know
Energy per unit time is power.
Thus,
P=mgh/t
where t is the time.
Thus,
\(\begin{gathered} 9\times10^3=\frac{1200\times9.81\times14}{t} \\ \Rightarrow t=18.312 \end{gathered}\)The time is 18.312 sec.
If a 5 n force is pushing upward on an object what force would need to be applied to create a net force of zero?
Answers
Answer:
the foce aplied to make the net force be 0 is 5n force pushing downward on the object becasue it will cancel it out
Explanation:
An ohm is best described as a unit of measure for...
A. electrical resistance
B. electrical current
C. electrical potential difference
D. magnetic field strength
Answers
+ 9. What force (in units of Newtons) is needed to give a 3.5 m/s" acceleration to a 1200 kg car?
Answers
Answer:
4200 Newtons
Explanation:
Force = mass x acceleration
1200 x 3.5 = 4200
Which wave has the lowest amplitude?
Answers
Wave D has the lowest amplitude. The highest point of a wave is called amplitude.
What is amplitude?The distance between from the crest of a wave to the next crest is known as the amplitude. It is denoted by a.
The standard equation for the SHM is found as;
\(\rm y = asin \omega t\)
Where, a represent the amplitude of the wave.
In the wave D it is observed that the distance from center axis to the highest point of the wave is smallest. Hence, wave D has the lowest amplitude.
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Answer:
To summarize what the expert answer said, it's the last box.
Explanation:
HELP ME ASAP PLZZZ NOW!!!
Answers
Answer:
B. It's nucleus releases energy
Explanation:
13. Which one of the colors has the longest wavelength A, Red B. Yellow C. Blue 14. The sky appears blue due to A. Diffraction of light C. Refraction of light B. Reflection of light D. Scattering of light
Answers
13.The color with the longest wavelength is option A. Red.
14.The sky appears blue due to option D. Scattering of light.
Red light has a longer wavelength compared to yellow and blue light.The color that has the longest wavelength is red. The color of the sky appears blue due to scattering of light. The distance between one peak and the next in a series of waves, particularly electromagnetic waves traveling through space or along a wire is referred to as wavelength.
The wavelength of light, for example, determines its color. Red light has the longest wavelength, followed by orange, yellow, green, blue, and purple, with violet light having the shortest wavelength. When light is reflected off a surface or passes through a medium, it can be deflected in various directions, a phenomenon known as scattering of light.
The Earth's atmosphere scatters sunlight in all directions, but the shorter blue wavelengths are scattered more than the longer wavelengths. As a result, we perceive the sky as blue during the day. The light becomes scattered when it interacts with particles in the atmosphere, causing the sky to appear blue during the day and red during sunset or sunrise. The scattering of light is the process that causes the sky to appear blue.
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explain why atoms only emit certain wavelengths of light when they are excited.
Answers
When atoms are excited, they only emit specific wavelengths of light because of the quantized energy levels of their electrons.
The electrons in an atom are arranged in discrete energy levels or shells. When the electrons are in their lowest energy state or ground state, they occupy the lowest energy level. When an external source of energy, such as heat or electricity, is supplied to the atom, it can cause the electrons to become excited and move to a higher energy level. This process is called excitation.
When the excited electrons return to their ground state, they release the extra energy that they have acquired in the form of electromagnetic radiation. The energy of the radiation depends on the difference in energy between the two energy levels that the electron moves between. This difference in energy between energy levels corresponds to a specific wavelength of light.This means that only certain wavelengths of light will be emitted by the atom, as these correspond to specific energy level differences. The wavelengths of light that an atom emits are known as its emission spectrum.
By studying the emission spectrum of an element, scientists can determine its atomic structure and identify the element.
Atoms only emit certain wavelengths of light when they are excited because of the quantized energy levels of their electrons. When an electron moves between two energy levels, it emits radiation with a specific wavelength corresponding to the energy difference between those levels. This gives rise to the emission spectrum of an element, which can be used to identify it.
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a 0.11-kg tin can is resting on top of a 1.7-m high fence post. a 0.0020-kg bullet is fired horizontally at the can. it strikes the can with a speed of 900.0 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fencepost? disregard friction while the can is in contact with the post.
Answers
It is 1.93 metres away from the post.
for vertical motion
\(S= u t + \frac{1}{2} g t^{2}\)
S = 0 + \(\frac{1}{2} g t^{2}\)
1.7 = \(\frac{1}{2} 9.8 t^{2}\)
t = 0.589 sec
using law of conservation of momentum, on the horizontal motion
\(m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}\)
\(0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}\)
\(v_{tin}\) = 3.273 m/s
S = \(v_{tin} \ t\)
= 3.273 m/s * 0.589 s
= 1.93 m
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a parabolic mirror on a telescope 30 cm in diameter has a focal length of 15 cm. for the coordinate system shown, write an equation of the parabolic cross section of the mirror.
Answers
To write the equation of the parabolic cross-section of the mirror, we can use the standard form of a parabolic equation, y^2 = 4px, where (x, y) represents the coordinates on the mirror and p is the focal length.
In a parabolic mirror, the focal length (f) is equal to half the radius (r) of the mirror. Given that the telescope has a diameter of 30 cm, the radius is half of that, which is 15 cm. Therefore, the focal length is also 15 cm.
In the standard form of a parabolic equation, y^2 = 4px, the parameter p represents the distance between the vertex of the parabola and the focus. Since the focal length is equal to p, we can substitute p = 15 cm into the equation.
Hence, the equation of the parabolic cross-section of the mirror is y^2 = 4 * 15 * x, which simplifies to y^2 = 60x. This equation represents the shape of the parabolic mirror in the given coordinate system, where (x, y) are the coordinates on the mirror and y represents the height of the mirror surface at a given x-coordinate.
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Exercise 2. Consider the discrete-time signal x[n]=−2δ[n]−δ[n−1]+δ[n−3]+2δ[n−4] where δ[n] is the unit impulse function. A) Derive the energy and the time-averaged power of signal x[n] over −[infinity]
Answers
Given, discrete-time signal is as follows; x[n] = -2δ[n] - δ[n-1] + δ[n-3] + 2δ[n-4] The time-averaged power of a signal x(t) is defined as the average of the square of the absolute value of the signal over time T.
It is given by; \(Pav = lim (T → ∞) {1/T ∫[x(t)]^2 dt}\) joules For a discrete-time signal x(n), the power can be defined by replacing the integral with summation as;\(P[n] = 1/N ∑_{n=0}^{N-1} |x(n)|^2\)joules where N is the total number of samples in the signal. Let's find the energy of the given signal;
E[n] = ∑_{n= -∞}^{∞} |x(n)|^2Let's calculate E[n] for \(n=0;x[0] = -2δ[0] - δ[-1] + δ[-3] + 2δ[-4]δ[-1] = 0, δ[-3] = 0\), δ[-4] = \(0x[0] = -2δ[0]x[0]^2 = 4δ[0]^2 = 4E[0] = 4\) joules Let's calculate E[n] for n=1; \(x[1] = -2δ[1] - δ[0] + δ[-2] + 2δ[-3]δ[-2] = 0\), \(δ[-3] = 0x[1] = -δ[0] - 2δ[1]x[1]^2 = δ[0]^2 + 4δ[1]^2 + 4δ[0]δ[1] = 4δ[1]^2E[1] = 4\) joules.
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the lava cools to 700.0° c before solidifying. what is the change in entropy δs1 of the lava in joules per kelvin during this process?
Answers
The change in entropy δs1 of the lava is not given in the question.
What is the entropy change of the lava as it cools to 700.0°C before solidifying?Entropy is a measure of the amount of energy in a system that is unavailable to do work. The change in entropy of a system is related to the amount of heat added or removed from the system and the temperature at which the heat transfer occurs.
In the case of the lava cooling to 700.0°C before solidifying, we would need to know the amount of heat lost by the lava and the temperature at which this heat transfer occurred in order to calculate the change in entropy. Without this information, we cannot determine the value of δs1.
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