Answer:
Option C. ⁰₊₁e
Explanation:
From the question given above, the following data were obtained:
¹⁵₈O —> ¹⁵₇N + __
Let the unknown be ʸₓM
Thus, the equation becomes
¹⁵₈O —> ¹⁵₇N + ʸₓM
Next, we shall determine x, y and M. This can be obtained as follow:
8 = 7 + x
Collect like terms
8 – 7 = x
1 = x
x = 1
15 = 15 + y
Collect like terms
15 – 15 = y
0 = y
y = 0
ʸₓM => ⁰₁M => ⁰₊₁e
Therefore,
¹⁵₈O —> ¹⁵₇N + ʸₓM
¹⁵₈O —> ¹⁵₇N + ⁰₊₁e
Answer: it is c
Explanation:
i took the t.e.s.t
A 4 kilogram mass is moving East a 5 meter per second what will be its speed after 10 seconds if a force of 100 Newtons act on it
Answer:
255 m/s
Explanation:
From the question,
F = ma.................................. Equation 1
Where F = Force, m = mass, a = acceleration.
Make a the subject of the equation
a = F/m............................. Equation 2
Given: F = 100 Newton, m = 4 kg.
Substitute these values into equation 2
a = 100/4
a = 25 m/s²
But,
a = (v-u)/t...................... Equation 3
Where, v = Final velocity, u = initial velocity, t = time
Given: u = 5 m/s, t = 10 s
Substitute into equation 3
25 = (v-5)/10
v-5 = 25×10
v-5 = 250
v = 250+5
v = 255 m/s
If the universe were to suddenly begin shrinking rather than continue expanding, how would it affect the cosmic microwave background radiation?
A. It would decrease in temperature.
B. It would blue-shift.
C. It would red-shift.
D. It would increase in temperature.
If the universe were to suddenly begin shrinking rather than continuing to expand, it would have a significant effect on the cosmic microwave background radiation (CMB).
The CMB is the afterglow of the Big Bang and is observed as a nearly uniform background radiation in all directions. It is thought to have been emitted when the universe was about 380,000 years old and had cooled enough for neutral atoms to form.
If the universe were to suddenly begin shrinking, the photons in the CMB would lose energy as they travel through the contracting space. This would cause the CMB radiation to shift to shorter wavelengths, which is known as blue-shifting.
Therefore, the correct answer is B. It would blue-shift.
2. If you are walking at a constant velocity of 5 km/h and a car passes you by at the speed of 20 km/h from behind, what is the car's velocity from your viewpoint?
Answer:
Explanation:
By the speed addition theorem:
V = 20 - 5 = 15 km/h
A group of physics students launched a rocket in a field at their school. They recorded the time it took for the rocket to launch into the air and come back to the ground. They calculated their average time for their rocket to land to be 12.74 seconds.
1. How long did the rocket take to reach max height?
2. What is the velocity of the rocket at max height?
3. What is the initial velocity of the rocket?
4. What was the maximum height of the rocket?
1) The time taken is 6.37 s
2) The velocity at maximum height is 0 m/s
3) The initial velocity is 62.4 m/s.
4) The maximum height is 198.66 m
What is the velocity?Let us recall that in this case, we have to use the equation of the motion that occurs under gravity In this case we have to take into account the the upwards motion is negative in the opposite direction as gravity and the down wards motion is positive and in the same direction as gravity.
1) Given that;
time is the same as the time taken to go up and come down thus the time taken to reach the maximum height is 12.74 seconds/2 = 6.37 s
2) The velocity of the rocket at the maximum height is zero because it momentarily comes to rest.
3) The initial velocity of the rocket is;
v = u - gt
At the maximum height v = 0 m/s
u = gt
u = 9.8 m/s^2 * 6.37 s
u = 62.4 m/s
4) The maximum height is obtained from;
v^2 = u^2 - 2gh
v = 0 m/s
u^2 = 2gh
h = u^2/2g
h = (62.4 m/s)^2/2 * 9.8 m/s^2
h = 198.66 m
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name the apparatus that can be used to measure the mass of the wooden block?
The apparatus used to measure the mass of a wooden block is called a weighing scale or a balance.
A weighing scale is a device that quantifies the force of gravity acting on an object, providing a measurement of its mass. There are various types of weighing scales available, ranging from simple mechanical balances to more sophisticated electronic scales.
A typical weighing scale consists of a platform or pan where the wooden block is placed. This platform is connected to a spring or a load cell that experiences a deflection proportional to the mass placed on it.
The deflection is then converted into an electrical signal, which is further processed and displayed as the measured mass on a digital or analog display.
When measuring the mass of a wooden block, it is important to place the block on the center of the platform to ensure accurate results. Additionally, any containers or materials used to hold the wooden block should be weighed separately and their mass subtracted from the total measurement to obtain the mass of the block alone.
Weighing scales are widely used in laboratories, industries, and everyday life for precise mass measurements of various objects, including wooden blocks, ensuring accuracy in research, manufacturing, and commerce.
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Can anyone prove to me that the Big Bang theory is real? That’s just the most crazy thing man kind can think of that, nothing, created everything, that’s scientifically imposible
I Think Its Real
A wide range of empirical evidence strongly favors the Big Bang event, which is now essentially universally accepted. Detailed measurements of the expansion rate of the universe place the Big Bang singularity at an estimated 13.787±0.020 billion years ago, which is considered the age of the universe.
Explanation:
eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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Choir members are traditionally grouped into four main vocal registers: bass,
tenor, alto, and soprano. Men with low-pitched voices tend to sing bass, while
those with slightly higher-pitched voices sing in the tenor range. Similarly,
women with low-pitched voices sing alto, while women with high-pitched
voices sing soprano. Which vocal register sings at the lowest frequency?
A. Bass
B. Alto
C. Soprano
D. Tenor
Answer:
The bass has the lowest frequency ,it only causes vibrations but at a lower frequency
A cylindrical specimen of aluminum having a diameter of 0.505 in. (12.8 mm) and a gauge length of 2.0 in. (50.8 mm) is pulled in tension. Use the load-elongation characteristics tabulated below to complete parts (a) through (f).
a. Plot the data as engineering stress versus engineering strain.
b. Compute the modulus of elasticity.
c. Determine the yield strength at a strain offset of 0.002.
d. Determine the tensile strength of this alloy.
e. What is the approximate ductility, in percent elongation?
f. Compute the strain energy density up to yielding (modulus of resilience).
( Load in N Load in lb Length in mm Length in in. 2.000 2.002 2.004 2.006 2.008 2.010 2.020 2.040 2.080 2.120 2.160 2.200 2.240 2.270 2.300 2.330 Fracture 50.800 7330 15,100 3400 23,100 5200 30,400 6850 34,400 7750 38,400 8650 41,3009300 44,800 10,100 46,200 10,400 53, 47,300 10,650 54.864 47,500 10,700 55.880 46,100 10,400 44,800 10,100 42,600 9600 3,400 8200 Fracture Fracture Fracture 50.851 50.902 50.952 51.003 51.054 1650 51.308 51.816 52.832 848 56.896 57.658 58.420 59.182
Answer:
A cylindrical specimen of aluminum having a diameter of 0.505 in. (12.8 mm) and a gauge length of 2.0 in. (50.8 mm) is pulled in tension. Use the load-elongation characteristics tabulated below to complete parts (a) through (f).
A 1.8 kg object is whirled on the end of a string that is 1.6 m long at a speed of 12.3 m/s. Calculate the angular momentum of the
object.
(Round your response to the nearest tenth, if necessary, and include the base unit abbreviation with your answer.)
Answer:
35.42kg m^2 s−1
Explanation:
Step one:
the expression for angular momentum is given as
\(L = mvr\)
m = mass = 1.8kg
v = velocity = 12.3m/s
r = radius= 1.6m,
Required
L = angular momentum
Step two:
substitute into the expression
L=1.8*12.3*1.6
L=35.42kg m^2 s−1
I don't quite understand. Can you help please?
Soccer can be traced back to the early Greeks and Romans.
O True
O False
Can Soccer be traced back to the early Greeks and Romans
Answer:
O False,
Explanation:
Although the game of soccer has been around for more than 2,000 years, soccer as we know it today is traced back to England. The game was once played in ancient China, Greece, Rome, and Japan but with different rules and variations.
what are ionic charges
Answer:
Ionic charges refer to the electrical charges of ions, which are atoms or molecules that have gained or lost electrons. These charges result from the loss or gain of electrons during chemical reactions.
When an atom loses one or more electrons, it becomes a positively charged ion known as a cation. The cation carries a positive charge equal to the number of electrons lost.
Conversely, when an atom gains one or more electrons, it becomes a negatively charged ion known as an anion. The anion carries a negative charge equal to the number of electrons gained.
The magnitude of the ionic charge depends on the number of electrons gained or lost, which is determined by the element's position in the periodic table and its electron configuration. For example, sodium (Na) loses one electron to become a +1 charged cation (Na+), while chlorine (Cl) gains one electron to become a -1 charged anion (Cl-).
when measuring the distance for a vehicle , which part of the vehicle do you use to measure the distance? ( at the beginning AND the end ?)
Answer:
odometer
Explanation:
this tracks your total mileage it can also track trip mileage
If you can run 10.43 m in 14.22 s. How fast are you running?
Answer:
I am 15th in my state for 55m hurdles with a time of 10.4 seconds
Explanation:
BAM
Answer: 44 m per minute
Explanation:
Given the following information, what is the magnitude of the sum of the three
vectors?
Vector A: [13, 8, 0]
Vector B: [13, 0, 8]
Vector C: [0, 1, 8]
Express your answer to two decimals
Answer:
31.84
Explanation:
To find the magnitude of the sum of the three vectors, first, we need to add the vectors component-wise. Then, we can find the magnitude of the resulting vector.
Add the vectors component-wise:
Vector A + Vector B + Vector C = [13+13+0, 8+0+1, 0+8+8] = [26, 9, 16]
Find the magnitude of the resulting vector:
The magnitude of a vector [x, y, z] is given by the formula:
magnitude = sqrt(x^2 + y^2 + z^2)
Plugging in the values from the resulting vector:
magnitude = sqrt(26^2 + 9^2 + 16^2)
magnitude = sqrt(676 + 81 + 256)
magnitude = sqrt(1013)
magnitude ≈ 31.84
The magnitude of the sum of the three vectors is approximately 31.84.
Hope this helps!
Calculate the potential difference to be maintain between two horizontal conducting plates separated by a distance of 10mm so that a small charged oil drop of mass 1.31x10-14 kg will remain in equilibrium. [charge on the oil drop = 6·4×10-¹⁹c] C
Answer:
Explanation:
The potential difference required to maintain the equilibrium of a charged oil drop in a uniform electric field can be calculated using the following equation:
V = (mg)/(qE)
where V is the potential difference, m is the mass of the oil drop, g is the acceleration due to gravity, q is the charge on the oil drop, and E is the electric field strength.
We are given the mass of the oil drop (m = 1.31x10^-14 kg), the charge on the oil drop (q = 6.4x10^-19 C), and the separation between the plates (d = 10 mm = 0.01 m).
The electric field strength between two parallel plates separated by a distance d and with a potential difference V applied between them is given by:
E = V/d
Substituting this expression for E into the equation for V, we get:
V = (mg)/(qE) = (mgd)/(qV)
Rearranging this equation, we obtain:
V^2 = (mgd)/q
Substituting the given values, we get:
V^2 = [(1.31x10^-14 kg)(9.81 m/s^2)(0.01 m)]/(6.4x10^-19 C)
V^2 = 2.02x10^-5 V^2
Taking the square root of both sides, we obtain:
V = 0.0045 V
Therefore, the potential difference required to maintain the equilibrium of the charged oil drop is approximately 0.0045 volts.
The average mass for a spacesuit plus astronaut is 191 kg. The average speed for air molecules inside the space suit is 549 m/s and has a density of 1.05 kg/m^3. If the air escapes Whatney's suit at 0.020 m^3/s moving directly away from him, how fast will he be going after 8.1 seconds (in m/s) if he started from rest?
Answer:
The value is \(v_a = 0.489 \ m/s\)
Explanation:
From the question we are told that
The mass of the spacesuit plus astronaut is \(m = 191 \ kg\)
The average speed of air molecules is \(v = 549 \ m/s\)
The density of air molecule is \(\rho = 1.05 \ kg / m^3\)
The acceleration of the air from Whatney's suit is \(a = 0.020 \ m/s^2\)
The time considered is \(t = 8.1 \ s\)
Generally the mass of air that have left Whatney's suit after the time considered is mathematically represented as
\(M = a * \rho * t\)
=> \(M = 0020 * 1.05 * 8.1\)
=> \(M = 0.1701 \ kg\)
Generally the momentum of the escaped air is
\(p = M * v\)
=> \(p = 0.1710 * 549\)
=> \(p = 93.38 \ kg \cdot m/s\)
Generally from the law of momentum conservation
\(p = p_a\)
Here \(p_a\) is the momentum of the astronaut at the considered time
\(93.38 = m * v_a\)
Here \(v_a\) is the velocity of the astronaut at the considered time
=> \(93.38 = 191 * v_a\)
=> \(v_a = 0.489 \ m/s\)
just add an answer and you get 50 points
Answer:
cswqwqqddqd
Explanation:
wdq
Answer:
tyyyyy ..
Explanation:
Imagine that the electrostatic forces on the cart and track were suddenly removed.When the cart hits the track, what evidence would there be that energy was transferred?
The change in motion, visible effects of the collision, and temperature increase would all serve as evidence that energy was transferred during the collision between the cart and the track after the removal of electrostatic forces.
If the electrostatic forces on the cart and track were suddenly removed and the cart hits the track, there would be several pieces of evidence indicating that energy was transferred during the collision.Firstly, there would be a noticeable change in the motion of the cart. The cart would decelerate as it collides with the track, and its velocity would decrease due to the loss of energy. This change in motion demonstrates that energy has been transferred from the cart to the track.
Secondly, there may be visible effects of the collision, such as deformation or damage to the cart or the track. This deformation or damage occurs because the energy transferred during the collision is transformed into other forms, such as heat or sound energy. These visible effects provide evidence of energy transfer.Additionally, there could be an increase in the temperature of the cart and/or the track due to the conversion of kinetic energy into thermal energy upon impact. This temperature change would be another indication that energy has been transferred.
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A 1000 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 16 s, then the motor stops. The rocket altitude 20 s after launch is 6600 m. You can ignore any effects of air resistance.
Required:
a. What was the rocket's acceleration during the first 16s?
b. What is the rocket's speed as it passes through acloud 5100 m above the ground?
Answer:
a) a = 34.375 m / s², b) v_f = 550 m / s
Explanation:
This problem is the launch of projectiles, they tell us to ignore the effect of the friction force.
a) Let's start with the final part of the movement, which is carried out from t= 16 s with constant speed
v_f = \(\frac{x-x_1}{t}\)
we substitute the values
v_f = \(\frac{ 6600 -x_1}{4}\)
The initial part of the movement is carried out with acceleration
v_f = v₀ + a t
x₁ = x₀ + v₀ t + ½ a t²
the rocket starts from rest v₀ = 0 with an initial height x₀ = 0
x₁ = ½ a t²
v_f = a t
we substitute the values
x₁ = 1/2 a 16²
x₁ = 128 a
v_f = 16 a
let's write our system of equations
v_f = \(\frac{6600 - x_1}{4}\)
x₁ = 128 a
v_f = 16 a
we substitute in the first equation
16 a = \(\frac{6600 -128 a}{4}\)
16 4 a = 6600 - 128 a
a (64 + 128) = 6600
a = 6600/192
a = 34.375 m / s²
b) let's find the time to reach this height
x = ½ to t²
t² = 2y / a
t² = 2 5100 / 34.375
t² = 296.72
t = 17.2 s
We can see that for this time the acceleration is zero, so the rocket is in the constant velocity part
v_f = 16 a
v_f = 16 34.375
v_f = 550 m / s
Light travels about 180 million kilometers in 10 minutes. How far does it travel in 1 minute? How far does it travel in 1 second? Show your reasoning
I need help
Explanation:
180 million km = 10 min
? = 1 min
180 million x 10 = 1,800,000,000 km
180 million km = 600s
? = l s
108,000,000,000km
4. What is the velocity of an object that doesn't move?
It depends on the object b. it depends on the speed c. it depends on the height
O mis
help
Answer:
Acceleration /Speed
Explanation:
An objects Velocity can be determined by acceleration,
Please pay attention in your middle school class, speed and velocity quiz.
A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later. Determine the distance the ball was thrown.
The distance the ball was thrown is 52.22m by A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later.
How to calculate distance?Every motion under constant acceleration is projectile motion
Angle above horizontal Ф = 35°, initial speed v1 = 25m/s , time 2.55s
Substituting value in the below equation
x=x₁ + (v₁*cosθ)(t)+1/2 *a*t²
a= 0 as acceleration in horizontal direction is zero
x= 25*cos(35)*2.55
x=52.22 m
Projectile motion is a form of motion in which object influenced when it is launched into the gravitational force from the surface of Earth along a curved path.
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For the following graph indicate the title with units for the X-and Y-axis: a) Annual cray fish caught in Lambert Bay for the last 20 years.
For the graph of Annual cray fish caught in Lambert Bay for the last 20 years, the axes are as follows:
Y-axis: amount of fish caught
X-axis: year
What is a graph?A graph is a pictorial illustration of data.
There are different types of graphs such as
Bar graphsLine graphScatter plotsPie chart.Pictograph.Column chart.Bubble chart, etcA graph has the vertical axis, known as the Y-axis, and the horizontal axis known as the X-axis.
For the graph of Annual cray fish caught in Lambert Bay for the last 20 years, the axis can be labelled as follows:
Y-axis: amount of fish caught
X-axis : year
In conclusion, in a graph, the vertical axis is known as the Y-axis while the horizontal axis is known as the X-axis.
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What are electromagnetic waves?
A:Waves that have different colors and can travel through
the emptiness of space.
B:Waves that can travel through the emptiness of space
very slowly
C:Waves that can travel through the emptiness of space
and stops when it gets close to the earth's
atmosphere.
D:Waves that can travel through the emptiness of space,
at the speed of light.
D: Sóng có thể truyền qua khoảng không của không gian,
với tốc độ ánh sáng.
Jamison turns around 5 times
Answer:
UMMMMMMMMMMMMMMM ]
Explanation:
WHAT
Answer:
dang, he should go see a doctor
find the average speed of a car that travels 45km in 2hours 15minutes
Answer:
20 km/h
Explanation:
45 km ÷ 2.25 hours (15 mins is 0.25 hours)
= 20
20 km/h
An athlete on the training ground starts at point and runs 120 m South to point B, then runs 200 m East to point C and the runs 270 m North to point D. The points on the training ground are shown in the diagram below: 2.2. 2.3 B Use the tail to head method, draw a neat, fully labelled displacement vector diagram and include the resultant displacement of the athlete. D Is the vector diagram in question 2.2, closed or not closed vector diagram? Explain the answer. 2.4 Calculate the 2.4.1 magnitude of the resultant displacement of the athlete 2.4.2 direction of the resultant displacement (4) (2) (4) 6 [15]
To draw the displacement vector diagram, we start at point A and draw a vector from A to B, representing the athlete's displacement of 120 m South. We then draw a vector from the end of the first vector (B) to the end of the second vector (C), representing the athlete's displacement of 200 m East. Finally, we draw a vector from the end of the second vector (C) to point D, representing the athlete's displacement of 270 m North. The diagram should form a closed triangle.
To find the resultant displacement of the athlete, we can use the Pythagorean theorem and trigonometry. Let's call the displacement from A to B "vector AB," the displacement from B to C "vector BC," and the displacement from C to D "vector CD." The magnitude of the resultant displacement (R) is given by:
R = √(AB² + BC² + CD²)
R = √(120² + 200² + 270²) = 334.4 m (rounded to one decimal place)
To find the direction of the resultant displacement, we can use trigonometry. We can find the angle between the resultant displacement and the North direction using the following formula:
θ = tan⁻¹[(ΣN)/(ΣE)]
Where ΣN is the sum of the Northward components of the displacement vectors (in this case, CD), and ΣE is the sum of the Eastward components of the displacement vectors (in this case, BC).
θ = tan⁻¹[(270 m)/(200 m)] = 53.1° (rounded to one decimal place)
Therefore, the magnitude of the resultant displacement is 334.4 m and the direction of the resultant displacement is 53.1° North of East.
while keeping your gaze forward, a rabbit runs in front of you from left to right. which of the following structures is involved in the visual pathway to see the rabbit when it's to your right, just before it disappears out of sight?
From the retina to the brain, structures in the visual pathway relay visual information.
What is meant by visual pathway?Structures in the visual pathway transmit visual data from the retina to the brain. Many abnormalities of the visual field are brought on by lesions in that pathway.
Beginning with the retina, whose ganglion cell axons comprise the optic nerve, the basic visual pathway is made up of a relay system. The nasal fibers of the contralateral nerve join the temporal fibers of the opposite nerve as the optic nerve fibers from each eye hemidecussate in the optic chiasm (OC).
A visual feeling is conveyed from the retina to the brain along the visual pathway. This consists of a cornea, a lens, nerve fibers that transmit visual perceptions from the retina to the optic nerve, and a lens and cornea that focus images on the retina.
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