Part 1 of "Birth of the Earth" (video clips 1 and 2)
1. Rusty Schweickart said that astronauts on the international space station (ISS) orbit the Earth every
hours.
2. Finding the conditions that led to Earth's formation around other stars could mean that
could be forming elsewhere in the universe.
3. How far do we have to rewind the clock to the beginning of our solar system?
years.
4. Our Earth started out as a
of
5. The same process that started our solar system formation is happening 7,000 light-years away in the
6. To compress the gas and dust into dense stars and planets, takes a supremely powerful event. What kind of
event?
miles per hour following a supernova.
7. Super-heated plasma blasts into space at
8. A host of different factors have to line up to get a planet just like the Earth. What 3 things does Professor
Krauss say you have to have?
The right
the right
and the right kind of
9.
is a powerful
systems. But specks of dust are far too small to pull on each other to form planets.
force. It shapes galaxies and solar
10. Launching a half ton canister at over 100 miles an hour gives the dust particles just
gravity.
11. The Germans think that the force that binds the dust particles together is
force.
seconds of zero
12. Turning dust balls into rocks takes a whole new process. A cosmic
13. Eventually the
(baby planets) get to the size of asteroids, kilometers across.
14. Baby Earth is now the size of a few city blocks. Big enough for a new force to take charge. That force is
15. So this formation process which was taking a long time to get to size where gravity kicks in, suddenly gets
kicked into overdrive and the
grows very rapidly.

When a substance lose an electron, it becomes positively charged. The dust particle will acquire positive charge when it losses electrons when it passes through the positively charged grid.

An atom contains equal number of electrons and protons. Hence, it possess no net charge and being neutral. When the atom lose or gain electrons it becomes ions.

When the atom lose one electron its number of protons dominates over that of electrons and it acquires a positive charge. When the atom gain an electron the reverse happen and it acquires a negative charge.

Here, the dust particle loses its electron to the positive grid thus it will gain a positive charge.  

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The gravitational potential energy (G.P.E) of the ceiling fan is 712.95 Joules.

Given the following data:

Scientific data:

To calculate the gravitational potential energy (G.P.E) of the ceiling fan:

Gravitational potential energy (G.P.E) can be defined as the energy that is possessed by an object or body due to its position (height) above planet Earth.

Mathematically, gravitational potential energy (G.P.E) is given by this formula;

\(GPE = mgh\)

Where:

Substituting the given parameters into the formula, we have;

\(GPE = 7.5 \times 9.8 \times 9.7\)

GPE = 712.95 Joules.

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it costs approximately 9.6 cents to operate the coffeepot for 1 hour when  if electrical energy costs 20 cents per kilowatt-hour .

To calculate the cost of operating the coffee pot for 1 hour, we need to first find the power consumed by the coffee pot.

The power consumed by the coffee pot can be calculated using the formula:

Power (P) = Voltage (V) x Current (I)

Substituting the given values, we get:

P = 120 V x 4.0 A = 480 W

Now, to calculate the energy consumed by the coffee pot in 1 hour, we need to convert the power from watts to kilowatts (kW) and multiply it by the time in hours:

Energy (E) = Power (P) x Time (t) / 1000

Substituting the given values, we get:

E = 480 W x 1 hour / 1000 = 0.48 kWh

Finally, to calculate the cost of operating the coffee pot for 1 hour, we need to multiply the energy consumed by the cost per kilowatt-hour:

Cost = Energy x Cost per kWh

Substituting the given cost per kilowatt-hour of 20 cents, we get:

Cost = 0.48 kWh x $0.20/kWh = $0.096

Therefore, it costs approximately 9.6 cents to operate the coffeepot for 1 hour.

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The minimum force (Fmin) required to move the block up the ramp is 12.7 N.

Mass of the block (m) = 3.3 kg

Angle of the ramp (θ) = 37°

Coefficient of friction between the block and the ramp (μg) = 0.44

Coefficient of kinetic friction between the block and the ramp (uk) = 0.30

Step 1: Resolve the forces acting on the block.

The weight of the block (mg) can be resolved into two components:

- The force acting parallel to the incline (mg*sinθ)

- The force acting perpendicular to the incline (mg*cosθ)

Step 2: Calculate the force of friction.

The force of friction can be calculated using the equation:

Force of friction (Ff) = μg * (mg*cosθ)

Step 3: Determine the minimum force required.

To move the block up the ramp, the applied force (Fapplied) must overcome the force of friction.

Thus, the minimum force required (Fmin) is given by:

Fmin = Ff + Fapplied

Step 4: Substitute the given values and calculate.

Ff = μg * (mg*cosθ)

Fmin = Ff + Fapplied

Now, let's calculate the values:

Ff = 0.44 * (3.3 kg * 9.8 m/s² * cos(37°))

Ff ≈ 12.717 N

Fmin = 12.717 N + Fapplied

Therefore, the minimum force (Fmin) required to move the block up the ramp is approximately 12.7 N.

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Answer:

It is the inability of the body to change by itself its state of rest or uniform motion or direction. Types of Inertia- It is of three types-(1)Inertia of rest (2) Inertia of motion(3) Inertia of direction. (1) Inertia of rest - It is the inability of the body to change by itself its state if rest.

Remember to input the appropriate values for the variables in the equations and perform the necessary calculations to obtain the absolute pressure in the pipe required to choke the nozzle and maintain isentropic subsonic flow.

To determine the absolute pressure required to choke the nozzle and maintain isentropic subsonic flow through the pipe, we can use the choked flow condition and the isentropic flow equation.

1. Choked Flow Condition:
When the fluid velocity at the throat of the nozzle reaches sonic velocity, the flow is said to be choked. At this point, any decrease in downstream pressure will not result in an increase in flow rate. The choked flow condition can be expressed using the following equation:

\( \frac{{A_t}}{{A}} = \left( \frac{{\gamma + 1}}{{2}} \right)^{\frac{{\gamma + 1}}{{2(\gamma - 1)}}} \)

where:
- \(A_t\) is the throat area of the nozzle,
- \(A\) is the flow area of the pipe, and
- \(\gamma\) is the specific heat ratio of the fluid (usually around 1.4 for air).

2. Isentropic Flow Equation:
The isentropic flow equation relates the pressure and density of a fluid at two different points in an isentropic process. In this case, we want to maintain isentropic subsonic flow through the pipe. The isentropic flow equation is given by:

\( \frac{{P_2}}{{P_1}} = \left( \frac{{\rho_2}}{{\rho_1}} \right)^{\gamma} \)

where:
- \(P_1\) and \(P_2\) are the pressures at points 1 and 2, respectively,
- \(\rho_1\) and \(\rho_2\) are the densities at points 1 and 2, respectively, and
- \(\gamma\) is the specific heat ratio of the fluid.

To solve for the absolute pressure in the pipe required to choke the nozzle and maintain isentropic subsonic flow, we can follow these steps:

Step 1: Determine the throat area of the nozzle, \(A_t\).
Step 2: Determine the flow area of the pipe, \(A\).
Step 3: Calculate the specific heat ratio of the fluid, \(\gamma\).
Step 4: Use the choked flow condition equation to find the value of \(\frac{{A_t}}{{A}}\).
Step 5: Given the specific heat ratio, \(\gamma\), calculate the value of \(\left( \frac{{\gamma + 1}}{{2}} \right)^{\frac{{\gamma + 1}}{{2(\gamma - 1)}}}\).
Step 6: Substitute the value of \(\left( \frac{{\gamma + 1}}{{2}} \right)^{\frac{{\gamma + 1}}{{2(\gamma - 1)}}}\) into the choked flow condition equation to solve for \(\frac{{A_t}}{{A}}\).
Step 7: Determine the density ratio, \(\left( \frac{{\rho_2}}{{\rho_1}} \right)\), based on the desired isentropic subsonic flow.
Step 8: Substitute the density ratio into the isentropic flow equation and solve for the pressure ratio, \(\frac{{P_2}}{{P_1}}\).
Step 9: Given the pressure ratio, \(\frac{{P_2}}{{P_1}}\), calculate the absolute pressure in the pipe required to choke the nozzle using the known pressure, \(P_1\).

Remember to input the appropriate values for the variables in the equations and perform the necessary calculations to obtain the absolute pressure in the pipe required to choke the nozzle and maintain isentropic subsonic flow.

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Answer:

0/10

Explanation:

_--------------------

Answer:

No. -infinity/10

Explanation:

Ew. Just why, like no.

To find the magnitude of vector F3 using the tail-to-head method of vector addition, we can visualize the vectors F1 and F2 and then add them geometrically.

Let's assume that F1 is represented by an arrow with a certain magnitude and direction. Similarly, F2 is represented by another arrow with its own magnitude and direction. To find F3, we place the tail of F2 at the head of F1, maintaining the direction and magnitude. The resulting arrow drawn from the tail of F1 to the head of F2 represents the vector sum of F1 and F2.Now, we can extend the arrow representing F3, starting from the tail of F1 and ending at the head of F2. The length of this extended arrow represents the magnitude of F3. By measuring this length accurately, we can determine the magnitude of vector F3.It's important to note that this method assumes that F1 and F2 are represented accurately in terms of their magnitudes and directions. Proper scaling and alignment of the arrows are crucial for an accurate representation of the magnitude of vector F3.

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Answer:

51°

Explanation:

dark fringe equation = dsinθ = (m + 1/2)λ

sinθ = [(m + 1/2)λ]d

sinθ1 = [(m + 1/2)λ]d

sinθ1/sinθ =  [(m + 1/2)(λ/d)] / [[(m + 1/2)(λ/d)] = [(m + 1/2)] / [(m + 1/2)]

sinθ1 = [(m + 1/2)] / [(m + 1/2)] (sinθ)

sinθ1 = [1+1/2]/[0+1/2] (sin15)

sinθ1 = 3sin15

sinθ1 = 0.77645

θ1 = sin^-1( 0.77645)

θ1 = 50.94° = 51°

The dark fringe for m = 0 in a young's double-slit experiment is located at an angle. The angle that locates the dark fringe for m = 1 is  51°.

When light passes through a slit , it produces a spectrum which can be seen on the screen kept a distance in form of fringes of different intensity. The fringe with intensity zero is called the dark fringe.

Given is the angle θ = 15°

The equation for the dark fringe is

d sinθ = (m + 1/2)λ

For m= 0 and m=1, the ratio of the sines  is

sinθ₁/sinθ₀ = [(m + 1/2)] / [(m + 1/2)]

Rearranging for sinθ₁, we have

sinθ₁ = [(m + 1/2)] / [(m + 1/2)] (sinθ₀)

Substituting the values into the equation and solving for θ₁

sinθ₁ = [1+1/2]/[0+1/2] (sin15)

θ₁ = 51°

Thus, the angle that locates the dark fringe fro m = 1 is 51°.

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In relation to line locators, conductive refers to a direct connection between the pipe and transmitter. Conductive locating involves connecting a transmitter to a metallic pipe or cable and then using a receiver to detect the signal transmitted through the pipe or cable.

The transmitter sends an electrical signal through the conductive material, which is then picked up by the receiver. This technique is particularly useful when locating pipes or cables that are buried underground or hidden behind walls. By using conductive locating, line locators can accurately determine the location, depth, and direction of the pipe or cable. In contrast, an indirect connection with radio waves, as in option B, is referred to as inductive locating, which involves detecting the electromagnetic field around the pipe or cable. While inductive locating can be useful in some situations, such as locating non-conductive pipes or cables, it is less accurate than conductive locating. Overall, conductive locating is a key technique used by line locators to accurately and efficiently locate buried or hidden pipes and cables.

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Answer:

36 J

Explanation:

Let's start off with the Kinetic Energy formula: 1/2m\(v^{2}\)

So to find the change in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.

*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the mass, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.

If 6 kg is the MASS:

Beginning: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2 = \(\frac{1}{2}\)(6)(2 squared)= \(\frac{1}{2}\)(6)(4)= 12 J

End: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2=\(\frac{1}{2}\)(6)(4 squared)=\(\frac{1}{2}\)(6)(16)= 48 J

Answer:

36 J

If 6 kg is the WEIGHT:

We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:

Weight = mass x acceleration due to gravity

6 = mass x 9.8

6 = 9.8m

*Divide both sides*

mass = 0.6 kg

Now, we can use the mass to find the kinetic energy.

Beginning: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2 = \(\frac{1}{2}\)(0.6)(2 squared)= \(\frac{1}{2}\)(0.6)(4)= 1.2 J

End: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2=\(\frac{1}{2}\)(0.6)(4 squared)=\(\frac{1}{2}\)(0.6)(16)= 4.8 J

Answer:

3.6 J

(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)

Answer:

What I like the most about engaging to different recreational activities is that these contribute to my entertainment and relax after working.

That is, recreational activities allow individuals to abstract from their daily responsibilities, encouraging distraction and concentration of the individual on issues of less importance, allowing them to relax.

Therefore, in my case I love that different recreational activities, such as sports or social gatherings, allow me to abstract from my responsibilities and allow me to enjoy moments of fun.

Answer:

1. D

2. A

‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎v

Answer: Insulators if i'm correct.

Explanation:

The major difference between ultraviolet and visible light is that UV has a wavelength of 10-400 nm, while visible light has a wavelength of 400–700 nm and infrared has a wavelength of 700 nm–1 mm.

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Answer: D

Explanation: The weather is making the Bits of rock and the glaciers are moving it so that is weathering.

Answer:

the force pulls each other cause its just physics

The configuration with the resistors connected in series results in a higher total resistance.

A series circuit configuration is one in which the electrical components are connected end-to-end, so that the current must flow through each component before reaching the next one. This means that the current is the same through all components, and the total resistance of the circuit is equal to the sum of the individual resistances. In contrast, a parallel circuit configuration is one in which the electrical components are connected side-by-side, so that the current can flow through multiple components at the same time. This means that the voltage across all components is the same, and the total resistance of the circuit is lower than the smallest individual resistance.

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Answer:

Lysosme

Explanation:

All plant cells have cell walls due to their ability to not protect themseleves unlike us humans or aniamls. Ribosomes and vacuoles also are in all plant cells as provide it with nutrients. Lysosme are not always commonly found in all plant cells because they have cell walls to proctect them. Hope this helps :)

Answer:

Acceleration 0.238 m/s²

Explanation:

Given:

V₀ = 13.2 m/s

V = 15.1 m/s

t = 8.00 s

__________

a - ?

Is the acceleration of the object:

a = (V - V₀) / t

a = (15.1 - 13.2) / 8.00 ≈ 0.238 m/s²

Acceleration of the object is 0.238 m/s²

Acceleration of an object is rate of change of velocity with respect to time. Due to having both direction and magnitude, it is a vector quantity of SI unit meter/second².

Given parameters:

Initial velocity; V₀ = 13.2 m/s

Final velocity; V = 15.1 m/s

time; t = 8.00 s

acceleration of the object; a = ?

We know, for accelerated object;

acceleration; a = (V - V₀) / t

⇒a = (15.1 - 13.2) / 8.00 ≈ 0.238 m/s²

Hence, acceleration of the object is 0.238 m/s².

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Fast moving rivers of air, known as jet streams, can reach speeds of 75 to 150 miles per hour (mph).

Jet streams are narrow bands of strong winds that flow in the upper levels of the atmosphere, typically between 25,000 and 35,000 feet above the Earth's surface.

These high-speed air currents are driven by the temperature and pressure gradients in the atmosphere, particularly between warm and cold air masses.

The jet streams flow in a wavy pattern from west to east, influenced by the rotation of the Earth and atmospheric conditions. They can extend thousands of miles in length and a few hundred miles in width.

Jet streams play a crucial role in weather patterns, affecting the movement of storms and the distribution of temperature and precipitation.

Aviation and weather forecasting heavily rely on understanding and monitoring the jet streams. Their high speeds can benefit air travel by reducing flight times for planes flying with the jet stream and increase fuel efficiency.

However, flying against the jet stream can result in longer flight durations and higher fuel consumption.

In summary, jet streams are fast-moving rivers of air with speeds ranging from 75 to 150 mph. They are important atmospheric phenomena that impact weather patterns and have implications for aviation and weather forecasting.

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Answer:

The difference between inherent and instrumental value is that inherent value is valued for its own sake, whereas instrumental value is valued for the end results gained from it.

Answer:

28.6 m/s

Explanation:

Using the equation for the range of a projectile,

R = U²sin2θ/g where U = initial speed of flaming pitch balls, θ = launch angle = 53° and g = acceleration due to gravity = 9.8 m/s²

Making U subject of the formula, we have

U = √(gR/sin2θ)

substituting the values of the variables into the equation given that R = 81.1 m, we have

U = √(9.8 m/s² × 81.1 m/sin2(53°))

U = √(794.78 m²/s²/sin106°)

U = √(794.78 m²/s²/0.9613)

U = √(826.78 m²/s²)

U = 28.75 m/s

U ≅ 28.6 m/s

Answer:

Elastic goods and services generally have plenty of substitutes. As an elastic service/good's price increases, the quantity demanded of that good can drop fast. Example of elastic goods and services include furniture, motor vehicles, instrument engineering products, professional services, and transportation services.

Explanation:

elasticity of supply measures the responsiveness to the supply of a good or service after a change in its market price. According to basic economic theory, the supply of a good will increase when its price rises. Conversely, the supply of a good will decrease when its price decreases.

The two earth satellites are in parallel orbits of differing radii, so they will not always be 1 km apart. Therefore, the time it takes for them to be 1 km apart again will depend on their rate of revolution, which is determined by the time it takes for them to complete one orbit.

To answer Part A, we must calculate the orbital period of each satellite, which is calculated by dividing the circumference of the orbit by the speed of the satellite. Once we calculate the orbital period for each satellite, we can use this information to determine how long it will take for the two satellites to be 1 km apart again.

For Part B, we must calculate the thermal efficiency of the heat engine. This is done by dividing the amount of heat extracted from the hot reservoir (60 kJ) by the amount of heat exhausted (35 kJ). The thermal efficiency is the ratio of these two numbers, and can be expressed as a percentage.

Finally, we must calculate the work done per cycle, which is the difference between the heat extracted and the heat exhausted (60 kJ-35 kJ = 25 kJ). This amount can also be expressed to two significant figures, with the appropriate units.

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Answer: left side

Explanation:

Given

Block of wood is pushed to the right

As friction always resist the motion, it must be acting towards the left side to stop the block

Answer:

When the acceleration of the elevator is going upward, the rider experiences a sensation of being heavier than his normal weight due to the upward normal force being more than the rider's weight.

When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.

A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.

Two forces are acting on the person, the force of gravity and the upward normal force from the elevator.

When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight.

N = mg + ma

When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight.

N = mg - ma

However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight.

N = mg

When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness.

N = (mg - mg) = 0

When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.

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