Part C


Now, it's time to analyze the author's diction and how it helps the author achieve his purpose. In 75 to 125 words, write


your analysis of diction in "Midas's Zinc Touch" by completing these steps:


1. Make a statement that identifies the author's choice of diction and how it relates to the author's purpose. (Review


these sentence frames to write your statement. )


2. Support your statement with evidence from the text.


3. Explain how the evidence supports your statement.

Therefore, at the given point (1, 1, 2, 4), ∂u/∂t = (ln(2) / 2) × ∂t/∂u, and ∂t/∂u cannot be determined from the given equation.

To calculate the partial derivatives ∂u/∂t and ∂t/∂u using implicit differentiation of the given equation, we'll differentiate both sides of the equation with respect to the variables involved, treating the other variables as constants.

Let's break it down step by step:

Given equation: (-2ln(-x) = ln(2)(tx - v) × 2ln(w - uv) = ln(2)

We'll differentiate both sides of the equation with respect to u and t, treating x, v, and w as constants.

Differentiating with respect to u:

Differentiate the left-hand side:

d/dt (-2ln(-x)) = d/dt (ln(2)(tx - v))

-2(1/(-x)) × (-1) × dx/du = ln(2)(t × du/dt - 0) [using chain rule]

Simplifying the left-hand side:

2(1/x) × dx/du = ln(2)t × du/dt

Differentiating with respect to t:

2ln(w - uv) × d/dt (w - uv) = 0 × d/dt (ln(2))

2ln(w - uv) × (dw/dt - u × dv/dt) = 0

Since the second term on the right-hand side is zero, we can simplify the equation further:

2ln(w - uv) × dw/dt = 0

Now, we substitute the given values (1, 1, 2, 4) into the equations to find the partial derivatives at that point.

At (1, 1, 2, 4):

-2(1/(-1)) × dx/du = ln(2)(1 × du/dt - 0)

2 × dx/du = ln(2) × du/dt

dx/du = (ln(2) / 2) × du/dt

2ln(w - uv) × dw/dt = 0

Since the derivative is zero, it doesn't provide any information about ∂t/∂u.

Therefore, at the given point (1, 1, 2, 4):

∂u/∂t = (ln(2) / 2) × ∂t/∂u

∂t/∂u cannot be determined from the given equation.

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Answer:

840

Step-by-step explanation:

7000×2×6 ÷ 100. since it is 2%

= 840

The angle which is complementary to angle BAC is ∠ACB which is option (a) .

From the figure we can see that ΔABC is right angled triangle at B .

∠BAC and ∠ACB on adding gives the right angle ∠CBA .

Hence , on adding ∠ACB  to ∠BAC  , we get the sum 90° so , ∠ACB is the complementary to angle BAC .

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The derivative of the function is

A) dw/dz=z^5 (7z-18)

B) dh/dx=192x^11+36x^5-6x^2+19

C) dy/dx=24x^2-38x-15

In mathematics, the derivative of a function measures the sensitivity to change of the function value with respect to a change in its argument. It is the rate of change of a function with respect to a variable.

A) w = z^7 – 3z^6 + 14

dw/dz=7z^6-18z^5

dw/dz=z^5 (7z-18)

B) h(x) = 16x^12 + 6x^6 – 2x^3 + 19x – 7

dh/dx=192x^11+36x^5-6x^2+19

C) y = (8x + 5)(x^2 – 3x)

dy/dx=  d/dx  [8x+5]*〖(x〗^2-3x)+(8x+5)*d/dx[x^2-3x]

dy/dx=(8*  d/dx  [x}+d/dx[5])*〖(x〗^2-3x)+(8x+5)*(d/dx[x^2]-3 d/dx[x])

dy/dx=(8*1+0)(x^2-3x)+(8x+5)(2x-3*1)

dy/dx=8(x^2-3x)+(2x-3)(8x+5)

dy/dx=24x^2-38x-15

Note: The question is incomplete. The complete question probably is: Find the derivative of the following function: A) w = z^7 – 3z^6 + 14 B) h(x) = 16x^12 + 6x^6 – 2x^3 + 19x – 7 C) y = (8x + 5)(x^2 – 3x).

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Answer:

X=17 degree

Step-by-step explanation:

Please mark as brainliest

Answer:

correct answer is 4 fish

Step-by-step explanation:

4 is the perfect number

Answer:

Yes

Step-by-step explanation:

Here is an ugly drawing of it......

Answer:

\(\textsf{Point-slope form}: \quad y-1=\dfrac{1}{5}(x-3)\)

Step-by-step explanation:

Define the given points:

Substitute the defined points into the slope formula to find the slope of the line:

\(\implies \textsf{Slope $(m)$}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-1-1}{-7-3}-\dfrac{-2}{-10}=\dfrac{1}{5}\)

Substitute the found slope and one of the points into the point-slope formula:

\(\implies y-y_1=m(x-x_1)\)

\(\implies y-1=\dfrac{1}{5}(x-3)\)

Simplify to slope-intercept form, if necessary:

\(\implies y-1=\dfrac{1}{5}x-\dfrac{3}{5}\)

\(\implies y=\dfrac{1}{5}x+\dfrac{2}{5}\)

Using linear function concepts, it is found that the volume of each marble is of 0.05 liters.

A linear function is modeled by:

y = mx + b

In which:

The linear function that gives the volume of water, when n marbles are inserted into the tank, is given by:

w = 32 - 0.05n

The slope of -0.05 means that for each marble inserted, there are 0.05 liters less for water, hence the volume of each marble is of 0.05 liters.

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Answer:

.05 liters

Step-by-step explanation:

Answer: The length of the edge of the crate is 3 feet.

Step-by-step explanation:

The formula of the volume of a cube is the cube of edge length.

The volume of the cube (V) = (edge)³ ...................................(1)

In the given question volume is 27 cubic feet.

So, V = 27 cubic feet

Now we replace the Volume with the edge using equation (1)

i.e. (edge)³ = 27

or we can say that the cube root of the edge is equal to 27

i.e. edge = ∛27

which is equal to 3

hence, edge = 3 feet

To calculate the cube root write prime factors of 27 and group them in groups of three

i.e. ∛27 = ∛(3×3×3) = ∛ (3)³ = 3

Step-by-step explanation:

The ratio is 2 to 5 or 2:5 or 2/5. All these describe the ratio in different forms of fractions. The ratio can consequently be expressed as fractions or as a decimal. 2:5 in decimals is 0.4.

Answer: C)5,5,10

Step-by-step explanation:

Answer:

Step-by-step explanation:

you just add 9000 to 250 which is equals to 9250 the clue was at the very bottom. "How many meters are there between the plane AND the submarine" 'and' is automatically addition.

Answer:

-21

Step-by-step explanation:

The correct statement is B. The center of the circle is the midpoint of the given endpoints of the diameter.

In a circle, the center is located at the midpoint of any diameter. A diameter is a line segment that passes through the center of the circle and has its endpoints on the circle. Therefore, if we are given the endpoints of a diameter, we can determine the center of the circle by finding the midpoint of these endpoints. This means that the x-coordinate of the center will be the average of the x-coordinates of the endpoints, and the y-coordinate of the center will be the average of the y-coordinates of the endpoints.

Option A is not necessarily true because the x-coordinate of the center may or may not be the same as the x-coordinates of the given endpoints.

Option C is incorrect because the center of the circle can be found by determining the midpoint of the diameter.

Option D is not necessarily true because the y-coordinate of the center may or may not be the same as the y-coordinates of the given endpoints.

Therefore, the correct statement is B. The center of the circle is the midpoint of the given endpoints of the diameter.

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Answer:

The degree of the polynomial is the greatest of its various terms' exponents (powers). This is a seconds degree polynomial.

Step-by-step explanation:

2x^2 - 3x^5 + 5x^6.

We observe that the above polynomial has three terms. Here the first term is 2x^2, the second term is -3x^5 and the third term is 5x^6.

Now we will determine the exponent of each term.

(i) the exponent of the first term 2x^2 = 2

(ii) the exponent of the second term 3x^5 = 5

(iii) the exponent of the third term 5x^6 = 6

Since the greatest exponent is 6, the degree of 2x^2 - 3x^5 + 5x^6 is also 6.

Therefore, the degree of the polynomial 2x^2 - 3x^5 + 5x^6 = 6.

Easy peasy, hope you understand now.

The statement that is true for the equation 5x - y/3 = 13 and the ordered pairs (2, -9) and (3, -6) is that neither of these ordered pairs satisfies the equation.

In the given equation, we have 5x - y/3 = 13.

To check if the ordered pairs satisfy the equation, we substitute the x and y values from each pair into the equation and see if the equation holds true.

For the ordered pair (2, -9), substituting x = 2 and y = -9 into the equation gives us 5(2) - (-9)/3 = 13, which simplifies to 10 + 9/3 = 13, and further simplifies to 10 + 3 = 13.

However, 13 does not equal 13, so the equation is not satisfied.

Similarly, for the ordered pair (3, -6), substituting x = 3 and y = -6 into the equation gives us 5(3) - (-6)/3 = 13, which simplifies to 15 + 6/3 = 13, and further simplifies to 15 + 2 = 13.

Again, 17 does not equal 13, so the equation is not satisfied.

In summary, for the equation 5x - y/3 = 13, neither the ordered pair (2, -9) nor the ordered pair (3, -6) satisfies the equation when their x and y values are substituted into it.

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\((\stackrel{x_1}{6}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{6}}}\implies \cfrac{-1}{1}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{-1}(x-\stackrel{x_1}{6}) \\\\\\ y-2=-x+6\implies y=-x+8\)

To address these bad aspects, it is important to regularly assess and improve bunding arrangements. This can include increasing the capacity of the bund, conducting regular maintenance and inspections, ensuring proper drainage, providing secondary containment for pipes and valves, using compatible materials, and providing training and awareness for personnel.

The bunding arrangements of chemical tanks have several potential drawbacks or bad aspects. Here are some of them:

1. Inadequate capacity: One common issue is when the bund (secondary containment system) does not have enough capacity to hold all the contents of the tank in case of a spill or leak. This can lead to the overflow of hazardous materials, posing risks to the environment and human health.

2. Poor maintenance: If the bund is not properly maintained, it may deteriorate over time, compromising its effectiveness. Cracks, holes, or corrosion can develop, allowing chemicals to escape into the surroundings. Regular inspections and repairs are crucial to ensure the bund remains intact.

3. Inefficient drainage: The bund should have a proper drainage system to remove any spilled or leaked substances. However, if the drainage is blocked or inadequate, the containment area may become flooded, making it difficult to control the situation and causing further environmental damage.

4. Lack of secondary containment for pipes and valves: While the bund may provide containment for the tank itself, it is important to also consider the pipes and valves connected to the tank. If these components are not adequately contained within a secondary system, leaks or spills can occur during maintenance or operation.

5. Incompatible materials: Another issue arises when the bund materials are incompatible with the chemicals being stored. Certain chemicals can corrode or degrade certain materials, rendering the bund ineffective. It is important to consider the compatibility of materials to ensure the bund's reliability.

6. Insufficient training and awareness: If personnel working with the tanks are not properly trained on spill response protocols and unaware of the potential risks, they may not be able to respond effectively to an incident. Adequate training and regular drills are essential to mitigate risks and minimize the impact of any spills.

To address these bad aspects, it is important to regularly assess and improve bunding arrangements. This can include increasing the capacity of the bund, conducting regular maintenance and inspections, ensuring proper drainage, providing secondary containment for pipes and valves, using compatible materials, and providing training and awareness for personnel.

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(a) (f o g)(-2) = 6 (b) (g o f)(-2) = 2  is the evaluated expression.

To evaluate the expressions (fog)(-2) and (gof)(-2), we need to plug in -2 as the input to the composition functions f o g and g o f.

First, let's find the functions f o g and g o f:

(f o g)(x) = f(g(x)) = f(2) = 3(2) - 5(0) = 6

(g o f)(x) = g(f(x)) = g(3x - 5y) = 2

(a) To find (f o g)(-2), we substitute -2 into the function f o g:

(f o g)(-2) = 6

Therefore, (f o g)(-2) = 6.

(b) To find (g o f)(-2), we substitute -2 into the function g o f:

(g o f)(-2) = g(f(-2)) = g(3(-2) - 5y) = g(-6 - 5y) = 2

Therefore, (g o f)(-2) = 2.

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Answer:

B. (6,-2)

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2

The center of the circle is (h,k)

So, in this problem, h is 6 and k is -2, so the center of this circle is (6,-2).

Answer:

C. 1

Step-by-step explanation:

Start at (0,3)

Slope is -3/1

X intercept would be 1

Answer:

i think the answer is A. -9

Step-by-step explanation:

i really hoped this helped

Answer:

y=-2   x=7

Step-by-step explanation:

Answer:

Decisions help know what you believe in and in what you trust. It also expirements many new things. Some decisions end up being good one and correct ones.

The expressions that have 3 as the greatest common factor are b + 3 + 6c, 27n + 66p, and 36 - 9j + 6k.

Thus,

b + 3 + 6c         - Yes

-30 - 24z           - No

27n + 66p         - Yes

36 - 9j + 6k       - Yes

From the question, we are to determine if 3 is the greatest common factor of the given expressions

b + 3 + 6c

3(b + 1 + 2c)

The greatest common factor is 3

-30 - 24z

6(-5 -4z)

The greatest common factor is not 3. The greatest common factor is 6

27n + 66p

3(9n + 22p)

The greatest common factor is 3

36 - 9j + 6k

3(12 - 3j + 2k)

Thus, The greatest common factor is 3

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Answer:

36\(\sqrt{3}\) + 72

Step-by-step explanation:

The length of the rectangle = diameter of 2 circles = 4 × 3 = 12 mm

The width of the rectangle = 2 radii + distance d between radii ( lower to upper )

Using the right triangle formed by joining the 3 centres with legs 3 and d and hypotenuse 6

Using Pythagoras' identity, then

d² + 3² = 6²

d² + 9 = 36 ( subtract 9 from both sides )

d² = 27 ( take the square root of both sides )

d = \(\sqrt{27}\) = 3\(\sqrt{3}\)

Thus width of rectangle = 3 + 3\(\sqrt{3}\) + 3 = 6 + 3\(\sqrt{3}\)

Hence

area = length × width

        = 12 × (6 + 3\(\sqrt{3}\) ) = 36\(\sqrt{3}\) + 72 mm ²

36 \(\sqrt{3}\)+ 72

The length of the rectangle = diameter of 2 circles = 4 × 3 = 12 mm

The width of the rectangle = 2 radii + distance d between radii ( lower to upper )

Using the right triangle formed by joining the 3 centres with legs 3 and d and hypotenuse 6

Using Pythagoras' identity, then

d² + 3² = 6²

d² + 9 = 36 ( subtract 9 from both sides )

d² = 27 ( take the square root of both sides )

d =  = 3

Thus width of rectangle = 3 + 3 + 3 = 6 + 3

Hence

area = length × width

       = 12 × (6 + 3 ) = 36 + 72 mm ²

Answer:

c = 80:)

Step-by-step explanation:

1. m • m (factors)  =>  m² (exponents)

2. a^a * b³ • a² (factors) =>  a^(a+2) * b³ (exponents)

3. rs³ • 6r²s (factors) =>  6r³s⁴ (exponents)

1. Expression: m • m

  Factors: The expression consists of two factors, both of which are 'm'.

  Exponents: To rewrite it with exponents, we count the number of 'm' factors, which is 2. Therefore, we can write it as m².

2. Expression: aªb³ • a²

  Factors: The expression consists of two factors. The first factor is 'a' raised to the power of 'a', and the second factor is 'b' raised to the power of 3.

  Exponents: To rewrite it with exponents, we simplify the first factor 'aªb³' as a³b³. Then, we multiply it by the second factor 'a²'. The resulting expression is a³b³ • a².

3. Expression: rs³ • 6r2s

  Factors: The expression consists of two factors. The first factor is 'rs' raised to the power of 3, and the second factor is 6r²s.

  Exponents: To rewrite it with exponents, we simplify the first factor 'rs³' as r³s³. Then, we multiply it by the second factor '6r²s'. The resulting expression is r³s³ • 6r²s.

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The area of the triangle is 31.54 square units

From the question, we have the following parameters that can be used in our computation:

We have the following values

a = 7 units

c = 11 units

B = 55 degrees

The area of the triangle is calculated using the following area formula

Area = 1/2absin(C)

Substitute the known values in the above equation, so, we have the following representation

Area = 1/2 * 7 * 11 * sin(55 degrees)

Evaluate

Area = 31.54

Hence, the area is 31.54 square units

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Answer:

8/3 or 2 and 2/3

Step-by-step explanation:

Answer:

2.666

If the number you're dividing by has a decimal, move the decimal point all the way to the right counting the number of places you've moved it to. Then move the decimal point in the number you're dividing the same number of places to the right.

Insert a decimal point in the quotient (answer) space, exactly above the decimal point in the number under the division bar.

Divide until the remainder is zero, or until you have enough decimal places in your answer. You can also stop if the remainder repeats because this indicates that your answer is a repeating decimal.