Physical activities teaches an individual sense of responsibility and initiative.
True Or False

Answers

Answer 1

Answer:

true

Explanation:

Physical fitness is a personal responsibility so I would say true

Answer 2
the correct answer is true :)

Related Questions

7. A student draws a model of the paths of two light rays after they interactwith Substance X and Substance Y. The student's model is shown below.Substance XSubstance YKEYLight ray 1Light ray 2Which of the following best describes the interactions of the light rayswith the two substances?A. The light rays are refracted by both Substance X and Substance Y.B. The light rays are transmitted by Substance X and refractedby Substance Y.C. The light rays are reflected from the surfaces of both Substance Xand Substance Y.D. The light rays are absorbed by Substance X and reflected from thesurface of Substance Y.

7. A student draws a model of the paths of two light rays after they interactwith Substance X and Substance

Answers

When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light.

So, here in both the pictures reflection is taking place

Result , Option C is correct

an object is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground. taking g

Answers

The correct answer i.e., the final speed for the object that is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground is 13.14 m/s.

The object is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground. We can use the equation of motion to find the final speed of the object when it hits the ground. The equation of motion is:
v^2 = u^2 + 2as

Where v is the final speed, u is the initial speed, a is the acceleration, and s is the displacement.

Given:
u = 4 m/s
a = g = 9.8 m/s^2
s = 8 m

Plugging in the given values into the equation, we get:
v^2 = 4^2 + 2(9.8)(8)
v^2 = 16 + 156.8
v^2 = 172.8

Taking the square root of both sides, we get:
v = 13.14 m/s
Therefore, the final speed of the object when it hits the ground is 13.14 m/s.

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The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-N applied force. The uniform horizontal rod has a mass of 15 kg and is welded to the block at B. Friction in the guide is negligible.

Required:
Compute the bending moment M exerted by the weld on the rod at B. The bending moment is positive if counterclockwise, negative if clockwise.

Answers

Answer:

The bending moment is 459.16 N.m

Explanation:

From the given information;

Let's assume that the angle is 66°

Then, the free body diagram is draw and attached in the file below.

Now, the calculation of the acceleration from the first part of the free body diagram is:

\(\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a \\ \\ a = \dfrac{347.906}{50} \\ \\ a = 6.96 \ m/s^2\)

Bending moment M:

From the second part of the diagram:

\(\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435 \\ \\ M = 238.435 + 220.725 \\ \\ \mathbf{M = 459.16 \ N.m}\)

The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?

Answers

Answer: τy = 2τx

Given: graph of L vs t
Ly = 20 at t = 5
Lx = 10 at t = 5
All L = 0 at t = 0
So change in angular momentum of y is 20 and x is 10

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy


Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X

why is interpretation an important part of meteorology

Answers

Strong interpretation is an important thing in meteorology. Because, analyzing the climate level in each area and the factors affecting it with their visual representation is very important in weather forecast.

What is meteorology ?

Meteorology is a branch of science dealing with the weather in different regions. On interpreting data, forecasters are tasked with synthesizing available observations from multiple platforms (including surface observations, weather balloons, radar, and satellite), numerical guidance from computer model forecasts, scientific theory, and experience-based intuition to arrive at a forecast.  

The forecast process is often collaborative, with teams of meteorologists routinely integrating new information into the forecast as the event approaches.

Increasingly, forecasters are also responsible for effectively communicating the forecast and its anticipated impacts upon life and property to various stakeholders, including the public.

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An object is projected from a height of 100m above the ground at an angle of 300to the
horizontal with a velocity of 100m/s.
Calculate
(4)
(4)
The maximum height reached above the ground
Time of flight
The velocity and the direction of the object 1 sec before it hit the ground
(4)​

Answers

Answer:

a) y = 127.6 m, b) 11.9s,  c)  v = 103.6  m / s, θ’= 326.7º

Explanation:

This is a missile throwing exercise

let's start by breaking down the initial velocity

         sin 30 = \(\frac{v_{oy} }{v_o}\)

         cos 30 = v₀ₓ / v₀

         v_{oy} = v₀ go sin 30

         v₀ₓ = v₀ cos 30

         v_{oy} = 100 sin 30 = 50 m / s

         v₀ₓ = 100 cos 30 = 86.6 m / s

a) the maximum height is requested.

At this point the vertical velocity is zero (v_y = 0)

         v_y² = \(v_{oy}^2\) - 2 g y

         0 = v_{oy}^2 - 2g y

         y = \(\frac{v_{oy}^2 }{2g}\)

         y = 50² / (2  9.8)

         y = 127.6 m

b) Flight time

this is the time it takes to reach the ground, the reference system for this movement is taken on the ground this is a height of y = 0 m and the body is at an initial height of i = 100m

         y = y₀ + v₀ t - ½ g t²

         

       0 = 100 + 50 t - ½ 9.8 t²

we solve the quadratic equation

        4.9 t² - 50 t - 100 = 0

         t = \(\frac{50 \pm \sqrt{50^2 + 4 \ 4.9 \ 100} }{2 \ 4.9}\)

         t = \(\frac{50 \ \pm \ 66.8}{9.8}\)

         t₁ = 11.9 s

         t₂ = -8.4 s

flight time is 11.9s

c) The time 1 s before hitting the ground is

        t1 = 11.9 -1

        t1 = 10.9 s

let's find the vertical speed

       v_y =\(v_{oy}\) - g t

       v_y = 50 - 9.8 10.9

       v_y = -56.8 m / s

the negative sign indicates that the direction of the velocity is downward.

On the x-axis there is no acceleration therefore the speed is constant.

Let's use the Pythagorean theorem

        v = \(\sqrt{v_x^2+v_y^2}\)

        v = \(\sqrt { 86.6^2 + 56.8^2}\)

        v = 103.6  m / s

let's use trigonometry

        tan θ = \(\frac{v_y}{v_x}\)

        θ = tan⁻¹  \frac{v_y}{v_x}

        θ = tan⁻¹  (-56.8 / 86.60)

        θ = -33.3º

the negative sign indicates that it is measured clockwise from the x-axis

for a counterclockwise measurement

          θ’= 360 - θ

          θ' = 360 - 33.3

          θ’= 326.7º

A spring of force constant 400 N/m is hung vertically from a ceiling. When a 32 kg mass hangs from the lower end of the spring, how far does the spring stretch?[Use g = 10 m/s2]

Answers

Answer:

The spring stretches by 0.8m

Explanation:

The force constant, k = 400 N/m

The mass of the object that hangs from the lower end of the spring, m = 32kg

The acceleration due to gravity, g = 10 m/s²

The weight of the object, W = mg

W = 32 x 10

W = 320 N

The force applied to the spring, F = kx

where x is the extension of the spring

F = 400x

The weight of the object = The force applied to the spring

W = F

320 = 400x

Divide both sides by 400

x = 320/400

x = 0.8 m

The spring stretches by 0.8m

A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m? ii. How long it takes to stop?​

Answers

Answer:

Refer to the attachment for solution (1).

Calculating time taken by it to stop (t) :

By using the second equation of motion,

→ v = u + at

v denotes final velocityu denotes initial velocityt denotes timea denotes acceleration

→ 0 = 5 + (-5/6)t

→ 0 = 5 - (5/6)t

→ 0 + (5/6)t = 5

→ (5/6)t = 5

→ t = 5 ÷ (5/6)

→ t = 5 × (6/5)

→ t = 6 seconds

→ Time taken to stop = 6 seconds

A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m?

Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Which statement describes a primary difference between an electromagnetic wave and a mechanical wave

Answers

The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

Difference between an Electromagnet and Mechanical Wave

A primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.

Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.

On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.

Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.

In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

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50 POINTS HELP ME
How are the circulatory, respiratory, skeletal, muscular, and nervous systems put into use when a rabbit runs from danger?
Carbon dioxide is considered a waste product in animals. How do plants use carbon dioxide?
How do living things reproduce?
Why is it a good idea for carriers of disease genes to get tested before having children?
How do organisms interact?
What would happen if an organism at the bottom of a food chain died?
How are ecosystems different?
Why does burning fossil fuels create carbon dioxide?
How does Earth’s surface change?
How can people prevent damage from earthquakes?
What are Earth’s resources?
Why do you think most households and businesses get water from water companies?

Answers

Explanation:

Q1. Circulatory/respiratory systems: get blood with oxygen and food to leg muscles

Skeletal/muscular systems: make legs move

Nervous system: sense danger, coordinate leg movements

Hormones to change body activity's are sent out by the ___________

Endocrinesystem

Q2. Excess carbon dioxide and oxygen are excreted from the plant through the stomata in the leaves.

Q3. Reproduction is the process by which new living things are created. People, animals, plants, and even bacteria, reproduce. There are two methods by which living things reproduce--asexual or sexual. Asexual reproduction allows for a living thing to reproduce without another member of its species, while sexual reproduction requires genetic material from two different members of the species, usually but not always, a male and a female. There are a few rare species that have the ability to reproduce both sexually and asexually.

Sexual Reproduction

In sexual reproduction, species can be either anisogamous or isogamous. In anisogamous reproduction, there are two parents, generally male and female. In order to reproduce, both contribute a gamete, or reproductive cell containing a haploid, or single set of chromosomes, that will make up the offspring. Each gamete provides half of the offspring’s genetic material. Many animals, including humans, reproduce in this way. Males produce sperm, which fertilize a female’s ova, or egg, within her body during the process of sexual intercourse. The point at which the egg is fertilized is called conception. The union of the two gametes results in a new cell, called a zygote. This cell continuously divides, implanting itself into the female uterus, and developing into what becomes known first as an embryo, and later, as a fetus. It is nourished and grows in the uterus throughout what is referred to as a period of gestation. This length of time varies for different animals. When development is complete, the birth process allows the female parent to deliver the baby that has grown within her, so that it can begin to thrive and grow on its own. Humans can also fertilize eggs externally, through a process called in vitro fertilization. Some animals, particularly those that live in the water, fertilize eggs externally, by releasing sperm and egg into the water, where they join together and become fertilized. Birds and reptiles have their eggs fertilized internally, and then lay eggs, in which the new creature develops, and then is hatched. Flowering plants even reproduce sexually, through a process called pollination. However, depending on the plant, it may self-pollinate, or cross-pollinate.

Asexual Reproduction

In asexual reproduction, a living thing can reproduce without receiving any cells from another living thing. All chromosomes come from one parent causing the offspring to be similar or identical in genetic structure. Organisms that produce asexually include but are not limited to bacteria, molds, yeast and some plants. Methods of asexual reproduction include budding, in which a new organism is formed directly from a part of an organism, such as with plants. Fragmentation means a living thing is split into fragments, which grow to be clones of the original living thing. Molds and starfish are examples of organisms that reproduce through fragmentation. Binary fission occurs when a cell divides into two parts. These organisms may not be genetically identical. Bacteria reproduce in this way. Spore formation is another form of asexual reproduction. According tothe New World Encyclopedia, a spore is a reproductive structure that is adapted for dispersion and survival for extended periods of time in unfavorable conditions. Once conditions are favorable, the spore can develop into a new haploid organism using mitotic division

Q4. We cannot prevent natural earthquakes from occurring but we can significantly mitigate their effects by identifying hazards, building safer structures, and providing education on earthquake safety. By preparing for natural earthquakes we can also reduce the risk from human induced earthquakes.

hope it is helpful

Answer:

.

I did not mean to do this!

can I delete it?

Explanation:


What is the resistance at 20°C of a 2.0-meter length of tungsten wire with a cross-sectional area of 7.9 10^-7
meter^2

Answers

Answer:

1.4 * 10 ^-1 Ω

Explanation:

Hi,

For this question, we gotta use the formula

R = pL/A

p = The resistivity of your material at 20°C

L = length of the wire

A = cross-sectional area

The resistivity of tungsten is 5.60 * 10^-8 at 20°C

By plugging the values, we get:

R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω

difference between boiling point and freezing point​

Answers

Laurie the vapor pressure of a substance has an advice effect and boiling point the boiling point goes up of pressure as the temperature at which the short salad in it with the liquid at the freezing point the rate at which the solid months is equal to the rate at which the liquid freezers

why was bowling one of the first racially integrated sports

Answers

Answer:

bowling was one of the first racially integrated sports because bowling alleys were primarily located in urban areas. Racial integration was inevitable since it was promoted by US Armed Forces during 1940s and its image as sport for the common man made it a choice of activity for Americans!!

Explanation:

A hopper jumps straight up to a height of 0.45 m. With what velocity will it return to the table?

Answers

Answer:

3 m/s

Explanation:

We can solve with kinematics or with energy.

Using kinematics, and taking down to be positive, we're given:

Δy = 0.45 m

v₀ = 0 m/s

a = 10 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (10 m/s²) (0.45 m)

v = 3 m/s

Or, we can use energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 10 m/s² × 0.45 m)

v = 3 m/s

Which statement is true of a catalyst in a reaction?

A. It acts as a reactant, in place of the original reactant.

B. It gets used up in the reaction.

C. It changes the activation energy required for the reaction.

D. It makes a reaction faster by adding energy.

Answers

Answer:

Hello There!!

Explanation:

The answer is=>C. It changes the activation energy required for the reaction.

hope this helps,have a great day!!

~Pinky~

The true statement for a catalyst used in a reaction is that it makes a reaction faster by adding energy. The correct option is D.

What is a catalyst?

A catalyst is a substance that increases the chemical reaction rate without undergoing any permanent chemical change in itself. It makes the reaction faster.

The correct option is D.

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2
Ca
+
O
2

2
CaO
What is the product of the reaction

Answers

\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

The product in a chemical reaction is written on the Right side of the arrow, so

the product formed here in given reaction is :

CaO (Calcium Oxide)

2. 0,25 moles of sodium chloride is dissolved in water to form 100 cm solution. Calculate the concentration of the solution. 3. 20 g of sodium hydroxide is dissolved in 200 cm³ of water. Calculate the concentration of the solution. 4 Calculate the mass of magnesium chloride needed to prepare 100 ml of a standard solution of​

Answers

The  concentration of the solution will be 0.25M and the concentration of the  

sodium Hydroxide is 2.5 M .

What is Stoichiometry ?

A branch of chemistry deals with the application of  the laws of definite proportions and of the conservation of mass and energy to chemical activity. The quantitative relationship between constituent in a chemical substance.  

We have given here,

Moles of sodium chloride  =  0.25moles

Let us assume the the volume of  the solution is 1 L.

Molarity = 0.25/

Molarity will be 0.25 M

The mass of sodium Hydroxide is 20g and the molar mass is 40g ,

and the Volume will be 0.2L

Molarity = 20/ 40×0.2

Molarity = 2.5 mol / L

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Help with (iii) and (iv) please:
A train consists of an engine and three trucks with masses and resistances to motion as shown in
Fig. 1. There is also a driving force of 37 000 N. All the couplings are light, rigid and horizontal.
(i) Show that the acceleration of the train is 0.3 ms2.
(i) Draw a diagram showing all the forces acting on truck Z in the line of its motion.
Calculate the force in the coupling between trucks Y and Z.
[3]
[4]
With the driving force removed, brakes are applied, so adding a further resistance of 11 000 N to
the total of the resistances shown in Fig. 1.
(iii) Calculate the new acceleration of the train.
(iv) Calculate the new force in the coupling between trucks Y and Z if the brakes are applied
(A) to the engine,
(B) to truck Z
In cach case state whether the force is a tension or a thrust.
[2]
[6]

Answers

(i) The total force acting on the train is the driving force minus the total resistance to motion. The total resistance to motion is the sum of the resistances of the three trucks. Therefore, the total force acting on the train is:

F = 37,000 N - (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s² = 37,000 N - 25,740 N = 11,260 N

The acceleration of the train is given by the formula:

a = F / (m1 + m2 + m3) = 11,260 N / (1,200 kg + 900 kg + 600 kg) = 0.3 m/s²

Therefore, the acceleration of the train is 0.3 m/s².

(ii) The forces acting on truck Z are the driving force, the force in the coupling between trucks Y and Z, and the resistance to motion of truck Z. The diagram showing all the forces acting on truck Z in the line of its motion is:

Driving force ≥ Truck Z ≤ Force in coupling Y and Z ≤ Resistance to motion of truck Z

(iii) With the driving force removed and brakes applied, the total resistance to motion is the sum of the resistances of the three trucks and the additional resistance due to the brakes. Therefore, the total resistance to motion is:

R = (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s²+ 11,000 N = 25,740 N + 11,000 N = 36,740 N

The total force acting on the train is the total resistance to motion. Therefore, the acceleration of the train is:

a = F / (m1 + m2 + m3) = 0 / (1,200 kg + 900 kg + 600 kg) = 0 m/s²

Therefore, the new acceleration of the train is 0 m/s².

(iv) When the brakes are applied to the engine, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z. Therefore, the force in the coupling between trucks Y and Z is:

F = 600 kg ² 9.8 m/s² + 11,000 N = 5,880 N + 11,000 N = 16,880 N

The force in the coupling between trucks Y and Z is a tension.

When the brakes are applied to truck Z, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z plus the resistance to motion of the engine and the trucks in front of truck Y. Therefore, the force in the coupling between trucks Y and Z is:

F = (600 kg + 900 kg + 1,200 kg) ₓ9.8 m/s² + 11,000 N = 17,640 N + 11,000 N = 28,640 N

The force in the coupling between trucks Y and Z is a thrust.

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A parallel plate air capacitor of value C, is charged to a potential V, between
the plates and +9, is charge on one plate. Separation between plates is d. A
dielectric of dielectric constant K = 3 fills the space between the plates. Which
of these quantities will change and why. (i) capacitance (ii) charge (iii) po-
tential difference and (iv) field density?

Answers

Answer:

(i) C=3Co

(ii) V=Vo/3

(iii) Decrease

Explanation:

(i) capacitance increase K times.

(ii) As charge remain constant so by using Q=CV

you will get potential decrease by K time.

(iii) Decrease due to induced electric field inside

dielectric material..

E=Eo-Eind

Explanation:

heyaaa hope it helps ☺️✌️

WHAT IS THE MASS OF A PURE PLATINUM DISK

Answers

The mass of a pure platinum disc can be gotten by multiplying the density with the volume.

Therefore the mass is 2418.2 grams or 2.4182 kilograms.

What is mass?

A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.

The kilogram is the primary mass unit in the SI.

The resistance of the body to acceleration in the presence of a net force can be measured as mass.

Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. This is due to the fact that mass, coupled with gravity, determines the strength of weight, which is a force.

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What is the mass of a pure platinum disk with a volume of 113 cm3? The density of platinum is 21.4 g/cm3.

Give your answer in grams and kilograms.

5 points
15. *
15. Which one of the following
quantities is NOT a vector?
A velocity
B acceleration
C distance
D displacement
A
B
С

Answers

Answer:

distance is not a vector. it is scalar

Which term is most applicable to a discussion of angular momentum in the context of black holes?
A. photon
B. curvature
C. spin
D. time

Answers

Answer:

Curvature

Explanation:

A geologist notices that a river is eroding its valley at a constant rate. Knowing the height of the valley walls, how could the geologist figure out when the river started carving the valley?
A.
Count growth rings of trees growing on the valley floor.
B.
Divide the height of the valley walls by the rate of erosion.
C.
Fill up the river valley with rocks, and time how long it takes the rocks to wash out.
D.
Sit and observe the river for a few hours until the valley walls double in height.

Answers

Answer:

B.

Divide the height of the valley walls by the rate of erosion.

Explanation:

There is a relationship between the rate of erosion and the hieght at which it is eroded according to Newton's law of motion. In the case of the scenario above, the best way to determine the time the river started carving the valley would be the division of the height of the valley walls by the rate of erosion.

A man is passing barrels of water to another person from a height of 7 meters. The barrel is attached to a roof that is 10 meters above the ground. The rope holding the barrel is 8 meters long and will break if the tension exceeds 638 N. How many liters of water can the man put in the barrel without the rope breaking (assuming that the barrel is massless)? (The density of water = 1000 kg/m3 and 1 m3 = 1000 L. Density = mass/volume.)

Answers

B it is because when you break hold

Create a diagram. cell, switch, two lamps, all connected in series

Answers

Recall the symbols for a cell, a switch, and a lamp:

To create a diagram of a cell, a switch and two lamps connected in series, draw the symbols one after another in a circuit:

Create a diagram. cell, switch, two lamps, all connected in series
Create a diagram. cell, switch, two lamps, all connected in series

Which of the following is NOT true about the mass of an object?

A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.

Answers

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

the government can encourage the production of goods that create positive externalities by creating?

Answers

The government can encourage the production of goods that create positive externalities by implementing policies and mechanisms such as subsidies, tax incentives, and regulations.

Positive externalities occur when the production or consumption of a good or service benefits society beyond the direct parties involved. These benefits can include improved public health, environmental sustainability, or increased social welfare. To encourage the production of goods with positive externalities, the government can take the following steps:

Subsidies: The government can provide financial support to producers of goods with positive externalities. Subsidies can offset production costs, making it more attractive for producers to supply these goods. By reducing the costs of production, subsidies can encourage higher output and more widespread availability of goods that benefit society.

Tax incentives: The government can offer tax incentives or tax breaks to businesses that produce goods with positive externalities. By reducing the tax burden on producers, it becomes economically advantageous for businesses to engage in activities that generate positive externalities. Tax incentives can stimulate investment, innovation, and production in areas that have positive spillover effects.

Regulations: The government can implement regulations and standards that require or promote the production of goods with positive externalities. For example, environmental regulations can encourage industries to adopt cleaner technologies and reduce pollution. By setting standards and enforcing regulations, the government can steer production towards goods that have positive impacts on society.

Public-Private Partnerships: The government can collaborate with private entities to promote the production of goods with positive externalities. Through partnerships, the government can provide resources, expertise, and incentives to businesses that are willing to produce goods that generate social benefits. This collaboration can help overcome barriers and create a conducive environment for the production of socially beneficial goods.

By employing these measures, the government can provide the necessary incentives and support for the production of goods that create positive externalities. These actions align the private interests of producers with the broader goals of societal welfare, fostering a more sustainable and socially responsible economy.

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How to find the angle in a projectile motion when displacement and heigh are the same​

Answers

projectile's vertical speed v yv y v, start , y,  drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward

.

At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.

In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.

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Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.​

Answers

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

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