Physics help me please I am struggling

Physics Help Me Please I Am Struggling

Answers

Answer 1

The solutions to the following questions on wave, frequency, wavelength is as follows:

4Hz50cm/s2Hz6cm6.6m/s4m

How to calculate speed, frequency and wavelength?

Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.

Wavelength is often designated in physics as λ, and corresponds to the velocity of the wave divided by its frequency.

QUESTION 1:

Period = 1/frequency

Frequency = 1/0.25 = 4Hz

QUESTION 2:

v = λf

v = 5 × 10 = 50cm/s

QUESTION 3:

λ = v/f

10 = 20/f

f = 2Hz

QUESTION 4:

λ = v/f

λ = 30/5 = 6cm

QUESTION 5:

f = 1/T

f = 1/3 = 0.33Hz

λ = v/f

20 = v/0.33

v = 6.6m/s

QUESTION 6:

λ = v/f

λ = 300/75

λ = 4m

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Related Questions

If a typical house requires 235 W of electric power on average, how much deuterium fuel would have to be used in a year to supply these electrical needs

Answers

For a typical house requires 235 W of electric power on average,  deuterium fuel used is mathematically given as

E=79206.75

How much deuterium fuel would have to be used in a year to supply these electrical needs?

Generally, the mass and time statement  of deuterium is mathematically given as

Mass deuterium=2.014g

time =3.15*107s= 1year

In conclusion, energy

E=235*3.15*107s

E=79206.75

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why energy crisis may create big problem in the near future.​

Answers

Answer:

Most energy crises have been caused by localized shortages, wars and market manipulation. Some have argued that government actions like tax hikes, nationalisation of energy companies, and regulation of the energy sector, shift supply and demand of energy away from its economic equilibrium.

A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?

Answers

Answer:

1350N

Explanation:

Given data

mass= 75kg

velocity= 6m/s

distance= 2m

The expression for the applied force is given as

F= mv^2/d

Substitute

F= 75*(6)^2/ 2

F= 75*36/2

F= 2700/2

F= 1350N

Hence the force is 1350N

7. Two carts are sitting on a frictionless track with a compressed spring between them. The sum of the masses of carts A and B is 1.5 kg. After the spring releases, Cart B has twice the speed of Cart A. What is the mass of each cart?

Answers

Answer:

Explanation:

Let mass of cart be m₁ and m₂

m₁ + m₂ = 1.5 kg

At the time of release , their momentum will be conserved

m₁ v ₁ = m₂ v₂

m₁ v ₁ = (1.5 - m₁ ) x 2 v₁

m₁ = 3 - 2m₁

3m₁ = 3

m₁ = 1 kg

m₂ = .5 kg

If a 1 kg book has 46 Joules of gravitational potential energy how high is the shelf it is on?
g = 9.8 m/s^2 KE = ½ mv^2 PE = mgh​

Answers

Answer:

4.7m

Explanation:

Given parameters:

Mass of the book  = 1kg

Gravitational potential energy  = 46J

Unknown:

Height of the shelf  = ?

Solution:

The potential energy is due to the position of a body above the ground.

        Gravitational potential energy  = mgh

m is the mass,

g is the acceleration due gravity  = 9.8m/s²

h is the height which is unknown

                       46  = 1 x 9.8 x h

                       h  = 4.7m

a wire 35.0 cm long, carrying a current of 3.50 a is placed at an angle of 40 degrees in a uniform magnetic field of 0.002 t. find the force on teh wire

Answers

A current-carrying wire in a magnetic field is subjected to a magnetic force. The direction of this force is perpendicular to both the direction of the current and the direction of the magnetic field. The force on the wire is 0.000728 N. This force is in a direction perpendicular to both the wire and the magnetic field.

In this problem, the wire is at an angle of 40 degrees to the magnetic field, but the force is still perpendicular to both the wire and the field. The force on the wire can be calculated using the following formula: F = BILsinθwhere F is the force on the wire, B is the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field. In this case: F = (0.002 T)(3.50 A)(0.35 m)sin(40°) = 0.000728 N

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Question 10
6.25 pts
A cannon is fired horizontally at 337 m/s off of a 80 meter tall, sheer vertical cliff. How many
seconds
will have elapsed before the cannonball strikes the ground?

Answers

Answer: 4 seconds are elapsed before the cannonball strikes the ground.

Explanation:

Height of tower (h) = 80m

Initital velocity in x-dir (\(u_{x}\)) = 337m/s

Initial velocity in y-dir (\(u_{y}\)) = 0m/s

Time of flight (T)

Gravitational acceleration (g) = 10 m/s

Using second equation of motion,

h = \(u_{y}\) + \(\frac{1}{2}\)g\(t^{2}\)

80 = \(\frac{1}{2}\)×10×\(T^{2}\)

\(T^{2}\) = 16

T = 4s

Question 106.25 ptsA cannon is fired horizontally at 337 m/s off of a 80 meter tall, sheer vertical cliff.

Hey you know these safety barriers you see on the freeway all the time? Explain the physics behind how the safety barriers help save lives during car accidents.​

Answers

In the event of an accident or a car crash, road safety barriers and fences prevent automobiles from running off the road.

Which laws explain the physics behind the safety barriers and their use ?

Newton's Three Laws of Physics can help explain what these safety barriers are and how they help to save lives during car accidents :

I.  Unless acted upon by an imbalanced force, an object at rest will remain at rest, and an object at constant velocity will remain at constant velocity.

II.  If an imbalanced force occurs, a mass will experience acceleration proportional to its magnitude.

III.  When you apply a force to an object, you will feel a force that is equal    in magnitude but opposite in direction.

What are the reasons for installing road safety barriers ?To protect and prevent out-of-control automobiles from entering other vehicles' lanes. As a result, the safety road barriers are installed in the middle of the road.To keep the automobiles from sliding down an incline. If there is a drop of 5 meters or more along the road, the road safety barriers should be put at one end of the road.To keep an out-of-control car from collapsing and colliding with a roadside obstacle. If there are numerous items along the road, such as large traffic signs, bridge piers, poles, and so on, safety road barriers should be built on one end of the road.

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what payment rules apply when the patient sees an out-of-network physician

Answers

When a patient sees an out-of-network physician, the payment rules depend on the type of insurance plan the patient has.

In general, out-of-network care is not covered or is only partially covered by insurance plans, and the patient may be responsible for paying the difference between the amount charged by the out-of-network physician and the amount that the insurance plan covers.

For example, in a preferred provider organization (PPO) plan, patients may have some coverage for out-of-network care, but they will generally have to pay higher copays, coinsurance, and deductibles.

In a health maintenance organization (HMO) plan, out-of-network care may not be covered at all, except in emergency situations.

In some cases, out-of-network physicians may be willing to accept the insurance plan's payment as payment in full, but this is not guaranteed, and patients should check with their insurance plan and the physician's office to understand their financial responsibility.

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An object attached to an ideal spring executes simple harmonic motion. If you want to double its total energy, you could An object attached to an ideal spring executes simple harmonic motion. If you want to double its total energy, you could double the mass. double the force constant (spring constant) of the spring. double both the mass and amplitude of vibration. double the amplitude of vibration. double both the amplitude and force constant (spring con

Answers

Answer:

double the force constant

Explanation:

For this exercise we see that the unit mass to the spring executes a simple harmonic motion, the maximum mechanical energy is

             Em = ½ k A²

where A is the range of motion

To double the energy we must increase the amplitude or the spring constant

Therefore, to double the total energy we must increase the amplitude by an amount √2

or we can increase the spring constant to double

The correct answer is to double the force constant

Which option is an example of a conceptual model?A. mental image of gas molecules as tiny ballsB. A weather map created by Doppler radarC. A clay ball with a slice cut out, showing the layers of EarthD. A diagram of a flagpole and its shadow with measurements provided to calculate the length of the shadow

Answers

From the given options let's select the example which shows a conceptual model.

A conceptual model can be said to be a model which shows an abstract representation of any concept which can be visualized or imagined than other models.

It is a model which the designers want users to understand.

From the list, the best option which is an example of a conceptual model is a mental image of gas molecules as tiny balls.

Let's say, for example, you imagine or have a mental picture of gas molecules using your imagination, it helps to understand how a vacuum system works and you can easily solve the problem if something goes wrong.

Therefore, the example of a conceptual model is:

A mental image of gas molecules as tiny balls.

• ANSWER:

A. mental image of gas molecules as tiny balls

why should we change worn out tyres​

Answers

Answer:

Your vehicle's tires work hard every time you go on the road. As they age, they become more and more worn down, especially if you use the same set of tires year round. As a result, your tires will need to be replaced. ... If you are driving on a dirt road, or one that is worn, chances are you will feel vibrations.

Which formula can be used to find the tangential speed of an orbiting object?
Ova 21
Ov=v2.70
Ov=G
m central
Ov=r
plmcentral)

Which formula can be used to find the tangential speed of an orbiting object?Ova 21Ov=v2.70Ov=Gm centralOv=rplmcentral)

Answers

Answer: A.) v = 2πr/T

Explanation:

The tangential speed of an orbiting object can be obtained by the product of the radius of the orbit and the angular speed of the object in a circular motion.

This the tangential seed can be represented mathematically as :

Tangential speed (v) = angular speed(ω) × radius(r)

v = r × ω --------(1)

Recall:

ω = 2π/T

Substituting ω = 2π/T in equation (1)

v = r × 2π/T

v = 2πr/T

Which formula can be used to find the tangential speed of an orbiting object?Ova 21Ov=v2.70Ov=Gm centralOv=rplmcentral)

Answer:

Answer: A.) v = 2πr/T

Explanation:

edg 2022 got 100%

Which one of these responses is true with regard to a 0.1 m solution of a weak acid ha?

Answers

A 0.1 M solution of weak acid HA has a concentration of 0.1 M, independent of its strength as an acid. The strength of the acid is not specified by the given information.

In a 0.1 M solution of a weak acid, the concentration of the weak acid, denoted as [HA], is 0.1 M.

The term "m" in this context refers to molarity, which represents the number of moles of solute (in this case, the weak acid HA) per liter of solution. Therefore, a 0.1 M solution means there are 0.1 moles of HA dissolved in every liter of the solution.

It's important to note that the concentration of HA in the solution is independent of its strength as an acid. The strength of an acid is determined by its ability to donate protons (H+) to a solution.

In summary, the true response with regard to a 0.1 M solution of a weak acid HA is that the concentration of HA in the solution is 0.1 M. The strength of the acid is not specified by the given information.

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All of the following are ways that an electromagnetic can be made stronger EXCEPT-

A) increasing the size of the iron core

B) adding more loops of wire

C) increasing the current moving through the wire

D) changing the direction of the current moving through the wire

Answers

Answer:

D is right option

...............

a bag contains 2 red balls and 18 green balls. a ball is chosen at random from the bag. what is the best answer for the probability of drawing a green ball? responses a certain

Answers

The best answer for the probability of drawing a green ball is 90%.When there are two outcomes (success or failure), it is referred to as a binomial probability problem.

There are 18 green balls and 2 red balls in a bag. A ball is chosen at random from the bag. The probability of drawing a green ball is: \[\frac{18}{18+2}=\frac{18}{20}=0.9=90\%\]Thus, the best answer for the probability of drawing a green ball is 90%.When there are two outcomes (success or failure), it is referred to as a binomial probability problem. A binomial probability formula is used to solve these types of problems.

The probability formula for a single event with two possible outcomes is as follows: \[P(x)=\left(\begin{array}{c}n\\ x\end{array}\right){p}^{x}{q}^{n-x}\]Where:P(x) = probability of x occurrencesn = number of trialsp = probability of a successq = 1 - p, probability of a failure.

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Imagine you have a circular loop of wire placed in the x-y plane. The current I = 5 A is flowing along clockwise through the loop if we look from above the xy plane. Calculate the magnetic dipole moment. Assume that the radius of the loop is R = 15 cm.
Give your answer up to at least three significant digits.

Answers

The magnetic dipole moment of the circular loop of wire with a current of 5 A and radius of 15 cm is approximately 0.354 Tm², up to three significant digits.

The magnetic dipole moment of the circular loop of wire in the x-y plane. Given the current I = 5 A flowing clockwise and the radius R = 15 cm, you can use the following formula:

Magnetic dipole moment (μ) = current (I) × area of the loop (A)

First, convert the radius from centimeters to meters:
R = 15 cm × (1 m / 100 cm) = 0.15 m

Next, calculate the area of the loop:
A = π × R² = π × (0.15 m)² ≈ 0.0707 m²

Now, find the magnetic dipole moment:
μ = I × A = 5 A × 0.0707 m² ≈ 0.354 Tm²

So, the magnetic dipole moment of the circular loop of wire with a current of 5 A and radius of 15 cm is approximately 0.354 Tm², up to three significant digits.

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In what way are liquids different from
solids?
A Liquid molecules are lighter than solid molecules.
B Liquids are made of atoms; solids are made of molecules.
C Liquids don't have a fixed shape; solids do.
D Liquids are always denser than solids.

Answers

Answer: The answer is C

The liquids are different from solids because Liquids don't have a fixed shape; solids do have a fixed shape.

Therefore the correct answer is option C.

What is the matter?

Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

Solids     ⇒    fixed shape and fixed volume

liquids    ⇒    fixed volume but the shape is not fixed

gases     ⇒     neither have fixed volume nor fixed shape

Because liquids lack a definite shape, they vary from solids, which do have a defined shape.

Thus, option C is the appropriate answer.

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The fastest pitch ever thrown was 105 mph, or 47 m/s. Wow! The moon's gravity is 16. 7% that of earth. If this pitcher threw the ball straight up on earth, it would reach a height of 112. 59 meters. How high would it go on the moon? This is a conversation of energy program. Kinetic energy = Potential energy. Truncate

Answers

The ball would reach a height of approximately 68.88 meters on the moon.

How to find height?

To find the height the ball would reach on the moon, equate the kinetic energy of the ball on Earth to the potential energy it reaches at its maximum height.

On Earth:

Kinetic energy (KE) = Potential energy (PE)

The kinetic energy of the ball can be calculated using the formula:

KE = (1/2) × mv²

Let's assume the mass of the ball is m, and the velocity is v.

On Earth, the kinetic energy of the ball is:

KE_earth = (1/2) × m × (47 m/s)²

The potential energy of the ball at its maximum height on Earth is given by:

PE_earth = m × g × h_earth

where g = acceleration due to gravity on Earth (9.8 m/s²) and h_earth = height reached on Earth (112.59 meters).

Therefore, the equation:

KE_earth = PE_earth

(1/2) × m × (47 m/s)² = m × 9.8 m/s² × 112.59 meters

Now, calculate the height the ball would reach on the moon using the given information that the moon's gravity is 16.7% that of Earth's.

On the Moon:

The acceleration due to gravity on the Moon (g_moon) is 16.7% of Earth's gravity:

g_moon = 0.167 × 9.8 m/s²

The potential energy of the ball at its maximum height on the Moon is given by:

PE_moon = m × g_moon × h_moon

where h_moon = height we need to calculate.

Since the kinetic energy of the ball is conserved (KE_earth = KE_moon), we can set up the equation:

(1/2) × m × (47 m/s)² = m × g_moon × h_moon

Now solve for h_moon:

(1/2) × (47 m/s)² = g_moon × h_moon

h_moon = [(1/2) × (47 m/s)²] / g_moon

Substituting the values:

h_moon = [(1/2) × (47 m/s)²] / (0.167 × 9.8 m/s²)

h_moon = 68.88 meters

Therefore, the ball would reach a height of approximately 68.88 meters on the moon.

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a fugitive tries to hop on a freight train traveling at a constant speed of 5.0 m/s. just as an empty box car passes him, the fugitive starts from rest and accelerates at 1.4 m/s^2 to his maximum speed of 6.2 m/s. how long does it take him to catch up to the empty box car?

Answers

The fugitive takes approximately 11.31 seconds to catch up to the empty box car.

To determine the time it takes for the fugitive to catch up to the empty box car, we need to find the time it takes for the fugitive to reach a speed of 6.2 m/s. The fugitive starts from rest and accelerates at a rate of 1.4 m/s^2 until reaching the maximum speed.

Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can rearrange the equation to solve for time: t = (v - u) / a.

Given that the fugitive starts from rest (u = 0), reaches a maximum speed of 6.2 m/s (v = 6.2 m/s), and accelerates at 1.4 m/s^2 (a = 1.4 m/s^2), we can substitute these values into the equation and calculate the time: t = (6.2 - 0) / 1.4 = 4.43 seconds.

Therefore, it takes approximately 4.43 seconds for the fugitive to reach his maximum speed. However, we need to determine the time it takes for the fugitive to catch up to the empty box car. Since the box car is already moving at a constant speed of 5.0 m/s, the fugitive needs to cover the initial distance between them before he starts accelerating.

The distance traveled by the fugitive during this initial time can be calculated using the equation d = ut + (1/2)at^2, where d is the distance, u is the initial velocity, a is the acceleration, and t is the time. Given that the fugitive starts from rest (u = 0), the equation simplifies to d = (1/2)at^2.

Substituting the values of acceleration (1.4 m/s^2) and time (4.43 seconds) into the equation, we can find the distance traveled during the initial time: d = (1/2)(1.4)(4.43)^2 = 13.57 meters.

Therefore, the fugitive covers a distance of 13.57 meters during the initial time. To determine the total time it takes for the fugitive to catch up to the empty box car, we divide this distance by the relative velocity between them: t = d / (5.0 - 6.2) = 13.57 / (-1.2) = -11.31 seconds.

However, we need to consider that time cannot be negative in this context. Thus, we take the absolute value of the time to obtain the positive value: t = |-11.31| = 11.31 seconds.

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A 60 kg woman stands on the very end of a uniform board of length l, which is supported one quarter of the way from one end and is balanced. 
What is the mass of the board?
A.15 kg.
B. 20 kg.
C.30 kg.
D. 60 kg.
E. 120 kg.

Answers

The mass of the board is 80 kg which matches none of the options.

What is mass and it's SI unit?

Mass is a fundamental property of matter that quantifies the amount of material an object contains. It is a scalar quantity and is independent of gravity. The SI unit of mass is the kilogram (kg).

Let's denote the length of the board as l and the distance from the pivot point to the woman as d. The distance from the pivot point to the center of mass of the board is then (3/4)l (given that the board is supported one quarter of the way from one end).

Since the woman's weight is mg (where m is her mass and g is the acceleration due to gravity), the torque equation becomes:

mgd = (m_board)(g)(3/4)l.

Canceling out the acceleration due to gravity and rearranging the equation:

d = (3/4)l(m_board / m).

We know that the woman's mass is 60 kg and she stands at the very end of the board, so d = l. Substituting these values into the equation:

l = (3/4)l(m_board / 60 kg).

Simplifying:

1 = (3/4)(m_board / 60 kg).

Solving for m_board:

m_board = (1 kg)(60 kg) / (3/4).

m_board = 80 kg.

Therefore, the mass of the board is 80 kg. None of the given options (A, B, C, D, E) matches this result.

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Ima Rilla Saari rushes to her car in order to hurry home and get dressed for work. Failing to realize the dangers of driving under slick and icy conditions, she collides her 964.0-kg Mazda Miata into the rear of a 3280.0-kg pick-up truck which was at rest at the light on Lake Avenue. Ima's pre-collision speed was 12.1 m/s. Determine the 3280.0-collision speed of the two entangled cars as they slide across the ice.

Answers

Answer:

The collision speed of the two cars is 8.8 m/s.

what mass of aluminum metal would absord 250 kj when it melted at its melting point? the heat of fusion for aluminum is 396.6 j/g

Answers

In this problem, we are given that the heat of fusion for aluminum is 396.6 J/g, which means that it takes 396.6 joules of heat to melt one gram of aluminum at its melting point.

We are also given that 250 kJ of heat is absorbed when the aluminum melts.

To find the mass of aluminum that would absorb this amount of heat, we can use the equation Q = m * ΔH_fus, where Q is the heat absorbed, m is the mass of aluminum, and ΔH_fus is the heat of fusion for aluminum.

Substituting the values given, we get:

250,000 J = m * 396.6 J/g

Solving for m, we get:

m = 630.1 g

Therefore, the mass of aluminum required to absorb 250 kJ of heat when it melts at its melting point is approximately 630.1 grams.

It's important to note that the heat of fusion is a characteristic property of a substance, which means that it is constant for a given substance at a given pressure and temperature.

This property can be used to calculate the amount of heat required to melt a given amount of a substance or the amount of substance that will melt with a given amount of heat.

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The students tested each solution. They started each test with a bowl with one cup of water and 30 grams of oil on top. They recorded the mass of each bowl with water and oil before and after each test. They also described the results of each test. Solution Mass of Bowl Before Mass of Bowl After Description Scooping the oil with a spoon 212 g 196 g The spoon easily picked up a lot of the oil at first. As the amount of oil decreased, it got too hard to pick up the oil. Trying to remove more oil spread it around the bowl. Absorbing the oil with a paper towel 214 g 160 g The paper towel absorbed the oil really well at first. As the amount of oil decreased, the paper towel started to pick up a lot of water. The paper towel couldn't get all of the oil. Using soap to break up the oil 210 g 216 g Adding the soap rapidly cleared the oil from the top of the water. It went to the sides of the bowl. With mixing, the oil all broke up as the water got sudsy. Question After reading the results of each test, identify an advantage and a disadvantage of each solution. Drag each result to the correct location on the table. Each result can be used more than once, but not all results will be used. removes clean water with oildisperses oil on surfaceremoves all oil from the waterspreads oil around surfaceleaves all oil in the waterremoves some oil from water

Answers

Each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.

The three solutions tested to remove oil from water are scooping the oil with a spoon, absorbing the oil with a paper towel, and using soap to break up the oil. Each solution has its advantages and disadvantages. Scooping the oil with a spoon is an effective solution to remove a significant amount of oil quickly. However, it is not a practical solution for removing a large amount of oil. The disadvantage is that it spreads the oil around the surface of the water and leaves some oil in the water. Absorbing the oil with a paper towel can effectively remove a lot of oil. The advantage is that it removes some oil from the water, leaving it relatively clean. However, it also picks up a lot of water and can't get all of the oil. Using soap to break up the oil is a good solution that removes all of the oil from the water. The advantage is that it removes all of the oil from the water, leaving it clean. However, the disadvantage is that it disperses the oil on the surface of the water, making it harder to remove from the sides of the bowl. In conclusion, each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.

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A student pours a small amount of ethanol into a beaker. She places the beaker on an electronic
balance to find its mass, and adds a thermometer to measure the temperature of the liquid.
Two hours later, she returns to her experiment. She notices that the mass of the bezker and its
contents has decreased. She can also see that the temperature of the ethanol has decreased.
She guesses that some of the ethanol has evaporated from the beaker.
Describe how evaporation can explain the decrease in mass.
b Describe how evaporation can explain the decrease in temperature.
a

Answers

Answer:

Evaporation is the vaporization of a liquid to the gaseous phase which occurs at the liquid's surface when the gas above the surface is unsaturated or contains less amount of the evaporating substance and the molecules at the surface absorbs enough energy during the transfer of energy from internal collision to withstand the vapor pressure of the surrounding and exist as a gas

a) Evaporation can explain the decrease in mass as follows;

Given that evaporation is the conversion of a liquid to a gas, the loss in mass of the ethanol can be explained by the conversion of some of the ethanol liquid to gas by evaporation such that the volume of ethanol remaining, and therefore, the mass of ethanol is reduced

b) The evaporation of the energized ethanol molecules from the surface of the ethanol results in a loss of energy of the remaining ethanol in the beaker, which can be observed as a reduction in temperature of the ethanol

Explanation:

With an air speed of 100km/h a pilot flies a course bearing 120°. If steady wind of 50km/h is blowing from a bearing of 080°. Determine the ground speed and the track.​

Answers

The ground speed is approximately 67.32 km/h and the track is approximately 158.24°.

To determine the ground speed and track, we need to consider the effect of the wind on the aircraft's motion.

The air speed of the aircraft is 100 km/h, which means that it moves through the air at this speed relative to the surrounding air mass. The course of the aircraft is the direction in which it is intended to fly, given as a bearing of 120°.

The wind is blowing from a bearing of 080° with a speed of 50 km/h. To find the effect of the wind on the aircraft, we need to decompose the wind vector into its components relative to the course of the aircraft.

Using basic trigonometry, we can find that the component of the wind perpendicular to the course is 50 km/h * sin(120° - 80°) = 50 km/h * sin(40°) ≈ 32.68 km/h. This component affects the aircraft's ground speed.

The component of the wind parallel to the course is 50 km/h * cos(120° - 80°) = 50 km/h * cos(40°) ≈ 38.24 km/h. This component affects the aircraft's track.

To calculate the ground speed, we subtract the perpendicular component of the wind from the air speed: 100 km/h - 32.68 km/h ≈ 67.32 km/h.

To calculate the track, we add the parallel component of the wind to the course: 120° + 38.24 km/h ≈ 158.24°.

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What is the potential energy of a 3.00 kg object at the bottom of a well 10.0 m deep as measured from ground level ? Explain the sign of the answer. (b) How much qirk is required to lift a 3.00 kg object from the bottom of the well 10.0 m deep

Answers

The potencial energy is given by the following formula:

\(E_P=\text{mgh}\)

Where "m" is the mass, "g" is the acceleration of gravity, and "h" is the height. Since the height is below the reference point it has a negative sign. Replacing we get:

\(E_P=(3kg)(9.8\frac{m}{s^2})(-10m)\)

Solving the operation:

\(E_P=-294J\)

The negative sign indicates that the object is below the zero point.

b. Since the work is equivalent to:

\(W=Fd\)

The force that acts on the object is equivalent to its weight and the distance the height, therefore:

\(W=\text{mgh}\)

Replacing:

\(\begin{gathered} W=(3\operatorname{kg})(9.8\frac{m}{s^2})(10m) \\ W=294J \end{gathered}\)

a. 8.25749 x 1017 protons and 5.26 x 1014 electrons; the charge on this object is ____ coulombs.

Answers

8.25749 x 10¹⁷ protons and 5.26 x 10¹⁴ electrons; the charge on this object is 0.4791  coulombs

To determine the charge on an object given the number of protons and electrons, we need to consider the elementary charge of a single proton and electron and their respective quantities.

The elementary charge, denoted as "e," is the fundamental unit of electric charge and is approximately equal to 1.602 x 10⁻¹⁹ coulombs.

Given that the number of protons is 8.25749 x 10¹⁷ and the number of electrons is 5.26 x 10¹⁴, we can calculate the total charge on the object.

Charge on protons = (Number of protons) * (Charge of a proton)

= (8.25749 x 10¹⁷) * (1.602 x 10⁻¹⁹ C)

Charge on electrons = (Number of electrons) * (Charge of an electron)

= (5.26 x 10¹⁴) * (-1.602 x 10⁻¹⁹ C) (Note: electrons have a negative charge)

Total charge = Charge on protons + Charge on electrons

Performing the calculations, we have:

Charge on protons = (8.25749 x 10¹⁷) * (1.602 x 10⁻¹⁹ C) ≈ 1.3227 C

Charge on electrons = (5.26 x 10¹⁴) * (-1.602 x 10⁻¹⁹ C) ≈ -0.8436 C

Total charge = 1.3227 C + (-0.8436 C) ≈ 0.4791 C

Therefore, the charge on this object is approximately 0.4791 coulombs.

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The figure shows a thin rod with charge Q that has been bent into a semicircle of radius R. (Figure 1) Part A Find an expression for the electric potential at the center. Give your answer in terms of Q, R and appropriate constants

Answers

The expression for the electric potential at the center of the semicircle, in terms of Q, R, and appropriate constants, is V = (kQ / 2R).

To find the electric potential at the center of the semicircle, we can consider the contribution of each small segment of the bent rod. We'll assume the rod has a uniform charge distribution.

Let's denote an infinitesimally small element of the rod as dq. The electric potential at the center due to this element can be calculated using the equation for the electric potential from a point charge:

dV = k * dq / r

Where dV is the potential contribution from the small segment, k is the electrostatic constant, dq is the charge of the element, and r is the distance from the element to the center of the semicircle.

Since the charge is distributed uniformly, the charge per unit length of the rod is Q / (πR), where Q is the total charge and R is the radius of the semicircle.

Now, we integrate the contributions of all the infinitesimal segments along the semicircle to obtain the total electric potential at the center:

V = ∫(k * dq / r) from -π/2 to π/2

Since the charge per unit length is Q / (πR), dq = (Q / πR) * ds, where ds is an element of arc length along the semicircle.

Substituting these values into the integral:

V = ∫(k * (Q / πR) * ds / r) from -π/2 to π/2

The integral of ds / r along the semicircle simplifies to the arc length, which is R * π / 2:

V = k * (Q / πR) * ∫(ds / r) from -π/2 to π/2

V = k * (Q / πR) * R * π / 2

Simplifying further:

V = (kQ / 2R)

Therefore, the expression for the electric potential at the center of the semicircle, in terms of Q, R, and appropriate constants, is V = (kQ / 2R).

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The figure shows a thin rod with charge Q that has been bent into a semicircle of radius R. (Figure 1)

Consider the sinusoidal wave Y(x, t) = sin[2r(0.2t - 4x)]. What are its period, frequency, angular frequency, wave number, wavelength and speed?

Answers

The period of the wave is 0.1 seconds, the frequency is 10 Hz, the angular frequency is 20π rad/s, the wave number is 4π rad/m, the wavelength is 0.5 m, and the speed of the wave is 2 m/s.

The general form of a sinusoidal wave is given by Y(x, t) = A * sin(kx - omega t + phi ), where A is the amplitude, k is the wave number, omega is the angular frequency, t is the time, x is the position, and phi is the phase constant.

Comparing this to the given wave Y(x, t) = sin[2π(0.2t - 4x)], we can extract the following values:

Period: The period T of a wave is the time it takes for one complete cycle. In this case, the coefficient of t in the argument of the sine function is 0.2, so the period is T = 1/0.2 = 0.1 seconds.

Frequency: The frequency f of a wave is the number of cycles per unit time. It is the reciprocal of the period, so f = 1/T = 1/0.1 = 10 Hz.

Angular Frequency: The angular frequency ω is the rate at which the phase of the wave changes with time. It is related to the frequency by omega= 2πf, so omega = 2π(10) = 20π rad/s.

Wave Number: The wave number k is the spatial frequency of the wave, which represents the number of cycles per unit distance. In this case, the coefficient of x in the argument of the sine function is -4, so the wave number is k = -4π rad/m.

Wavelength: The wavelength λ is the distance between two consecutive points in the wave that are in phase. It is related to the wave number by λ = 2π/k = 2π/(-4π) = 0.5 m.

Speed: The speed of a wave is the rate at which a point on the wave moves through space. It is given by the equation v = λf, where λ is the wavelength and f is the frequency. Substituting the values, we get v = (0.5)(10) = 5 m/s.

Therefore, the given sinusoidal wave has a period of 0.1 seconds, a frequency of 10 Hz, an angular frequency of 20π rad/s, a wave number of -4π rad/m, a wavelength of 0.5 m, and a speed of 5 m/s.

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