PLEASE ANSWERING THIS QUESTION!!!


Riley drove home from college traveling an average speed of 65.1 mph and drove back to the college the following week at an average speed of 69.6 mph. If the total round trip took 12 hours, how much time did it take Riley to drive from home back to college? Express the time in hours and minutes. Round to the nearest minute.



(Blank) hours (Blank) minutes



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Answer:

KL = 23

KM = 29

Step-by-step explanation:

By applying cosine rule in the given triangle KLM,

cos(∠M) = \(\frac{\text{Adjacent side}}{\text{Hypotenuse}}\)

cos(52°) = \(\frac{LM}{KM}\)

cos(52°) = \(\frac{18}{KM}\)

KM = \(\frac{18}{\text{cos}52}\)

KM = 29.24

KM ≈ 29

By applying sine rule,

sin(52°) = \(\frac{\text{Opposite side}}{\text{Hypotenuse}}\)

sin(52°) = \(\frac{KL}{29.24}\)

KL = 29.24[sin(52°)]

    = 23.03

    ≈ 23

KL = 23

Answer:

35 years old.

Step-by-step explanation:

To find the age of Gwen, multiply Robin's age, which is 11, by 3, which gives you 33. Then add two to 33 to get Gwen's age, which is 35 years.

Answer:

Gwen is 35 years old

Step-by-step explanation:

In order to understand the word problem better, I turned it into and equation.

Since Gwen is 2 years older than 3 times Robins age, the equation would be:

Gwens age = (3 • Robins age) + 2

G = (3 • 11) + 2

G = (33) + 2

G = 35

So Gwen is 35 years old.

It is important to note that sharing or requesting specific keys or answers to educational materials, including guided notes, would be considered unethical and potentially a violation of academic integrity.

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By analyzing the graph and evaluating the objective function at each vertex of the feasible region, we can find the optimal solution, which is the vertex that maximizes the objective function z = 3x + y.

To find the optimal solution of the given problem using the graphical method, we need to plot the feasible region determined by the given constraints and then identify the point within that region that maximizes the objective function.

Let's start by graphing the constraints:

1. Plot the line 2x - y = 5. To do this, find two points on the line by setting x = 0 and solving for y, and setting y = 0 and solving for x. Connect the two points to draw the line.

2. Plot the line -x + 3y = 6 using a similar process.

3. The x-axis and y-axis represent the constraints x ≥ 0 and y ≥ 0, respectively.

Next, identify the feasible region, which is the region where all the constraints are satisfied. This region will be the intersection of the shaded regions determined by each constraint.

Finally, we need to identify the point within the feasible region that maximizes the objective function z = 3x + y. The optimal solution will be the vertex of the feasible region that gives the highest value for the objective function. This can be determined by evaluating the objective function at each vertex and comparing the values.

Note: Without a specific graph or additional information, it is not possible to provide the precise coordinates of the optimal solution in this case.

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Answer:

12

Step-by-step explanation:

12>6

12 is factor of 36    36/12=3

12 is factor of 48    48/12=4

Answer:

x is 6

Step-by-step explanation:

3/4 * x/8

3*8=24 then,

divide by 4 which gives you 6.

Also if you simplify 6/8, it will give you 3/4.

Answer:

6 =x

Step-by-step explanation:

Answer:

I might be able to help what do you need to know

The Total Probability of getting exactly two 3s in two throws is 1/36

What is Probability?

A probability is a number that represents the possibility or chance that a specific event will occur. Probabilities can be stated as proportions ranging from 0 to 1, as well as percentages ranging from 0% to 100%.

Solution:

Probability of Obtaining 3 in the first throw = 1/6

Since, the number of possible outcome is 11 and total outcomes are 6

Similarly the probability of getting 3 in the second throw is 1/6

Therefore, total probability = 1/6 * 1/6 = 1/36

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Answer:

Sampling bias can occur when the procedure leads to a favoring of one population over another.

When the researcher wants to know on average how a certain plant will grow; given that they have been germinated for a week's time. By oy using a certain plant, assuming t

Answer:

Yes, he sampled plants from only one​ tray, so the sample is not random.

Answer: \(150^{\circ}\)

Step-by-step explanation:

By the exterior angle theorem,

\(m\angle BQR=50^{\circ}+100^{\circ}=\boxed{150^{\circ}}\)

Answer:

The score of class b were better than the scores of class a.

the median for class a was 77.5

the median for class b was 90

therefore class b overall scored better on the quiz than class a

Step-by-step explanation:

hope this helps :)

Answer:

70 feet

Step-by-step explanation:

Given

\(Sides: 23ft, 15ft, 32ft\)

Required

The tape needed

This implies that we calculate the perimeter (P)

This is calculated as:

\(P = \sum sides\)

So:

\(P = 23ft +15ft + 32ft\)

\(P = 70ft\)

Answer:

dude why does it say your in college?!?

Step-by-step explanation:

Also I DON'T KNOW just kidding um before some fork tard deletes my answer Hi how are you????

The common ratio of the geometric sequence 7⁽ⁿ⁺²⁾ / 2 is 7 and the a₁ = 7² / 2, a₂ = 7³ / 2, a₃ = 7⁴ / 2, and a₄ = 7⁵ / 2.

A specific number is multiplied by each number in the geometric sequence to produce the pattern. The following number in the series is decided by this. The common ratio refers to the multiplied number, which must be the same for each phrase in the sequence.

Given:

The geometric sequence = 7⁽ⁿ⁺²⁾ / 2,

For the first term, put n = 0 in the above sequence,

a₁ = 7² / 2

For the second term, put n = 1

a₂ = 7³ / 2

For the third term, put n = 2

a₃ = 7⁴ / 2

For the fourth term, put n = 3

a₄ = 7⁵ / 2

Now, for the common ratio

CR = a₂ / a₁ = 7³ / 2 ÷ 7² / 2

CR = 7

Therefore, the common ratio of the geometric sequence 7⁽ⁿ⁺²⁾ / 2 is 7 and the a₁ = 7² / 2, a₂ = 7³ / 2, a₃ = 7⁴ / 2, and a₄ = 7⁵ / 2.

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Answer:

QS=51

Step-by-step explanation:

It was given that RS = 19 and QR =32

QS=x

Q-R was measured and found to be 32

R-S was measured and found to be 19

Q-S will be the sum of Q-R and R-S which is 32+19= 51

QS=51

Answer:

51

Step-by-step explanation:

I took the test and it was correct :)

So, we know the bus can hold 20 people in 15 minutes, so the rate per hour is:

20/15m

60m/15m
4

20/15 x 4/4m
80/60m (80 per hour)

4/1 = 4

80/60m x 4/4
320/240m
320/4h

320 people could ride the bus in 4 hours.

The sample space for the acceptance outcomes of the three friends is S={G, B, R, G', B', R'}. Therefore, option A is the correct answer.

A sample space is a set of potential results from a random experiment. The letter "S" is used to denote the sample space. Events are the subset of possible experiment results. Depending on the experiment, a sample area could contain a variety of results.

Given that, Ghanem, Bilal and Rashed, applied for admission at ZU. Define G for "Ghanem is accepted" and G' for "Ghanem is not accepted". Similarly, you can define B & B' for Bilal and R & R' for Rashed.

Sample space of accepted ={G, B, R, G', B', R'}

Therefore, option A is the correct answer.

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The equilibium price is 163.39 and the supply quantity is 150

He estimated the market demand and supply function as follows demand :P=q²+13/2q+64 and supply: P= 10q²-45/2q-164​

We need to find the equilibium price

The equilibrium price (EP) is the price where the demand for a product or service balances its supply. .

At equilibium price

Demand function = supply function

q²+13/2q+64 = 10q²-45/2q-164​

(10 - 1)q² - (45/2 + 13/2)q - (164 + 64) = 0

9q² - 29q - 228

q = 6.895 = 6.9

The equilibium price = 6.9² + (13/2)6.9 + 64

= 163.36

similarly putting the value of q in supply function we get supply quantity   ie 149.95 = 150

Therefore, the equilibium price is 163.39 and the supply quantity is 149.95 = 150

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The answer is:

g(x + 1) = 6x + 1

g(4x) = 24x -5

Work/explanation:

To evaluate, I plug in x + 1 into the function:

\(\sf{g(x)=6x-5}\)

\(\sf{g(x+1)=6(x+1)-5}\)

Simplify

\(\sf{g(x+1)=6x+6-5}\)

\(\sf{g(x+1)=6x+1}\)

------------------

Do the same thing with g(4x)

\(\sf{g(4x)=6(4x)-5}\)

\(\sf{g(4x)=24x-5}\)

Hence, these are the answers.

Step-by-step explanation:

it seems you solved the tricky part yourself already.

just to be sure, let's do the first derivative here again.

the easiest way would be for me to simply multiply the functional expression out and then do a simple derivative action ...

f(t) = (t² + 6t + 7)(3t² + 3) = 3t⁴ + 3t² + 18t³ + 18t + 21t² + 21 =

= 3t⁴ + 18t³ + 24t² + 18t + 21

f'(t) = 12t³ + 54t² + 48t + 18

and now comes the simple part (what was your problem here, don't you know how functions work ? then you are in a completely wrong class doing derivatives; for that you need to understand what functions are, and how they work). we calculate the function result of f'(2).

we simply put the input number (2) at every place of the input variable (t).

so,

f'(2) = 12×2³ + 54×2² + 48×2 + 18 = 96 + 216 + 96 + 18 =

= 426

The length KL is 8 units

The value of x is undefined

The length KL is 12 units

From the question, we have the following parameters that can be used in our computation:

The rhombus

Also, we have

DK = 8

A rhombus is a quadrilateral with all sides equal.

So, we have

KL = 8

Here, we have

SKAL = 2x - 8

There is no point S on the rhombus

This means that

x = undefined

Here, we have

DM = 5y + 2 and DK = 3y + 6

A rhombus is a quadrilateral with all sides equal.

So, we have

5y + 2 = 3y + 6

Evaluate

2y = 4

Divide

y = 2

So, we have

KL = 5 * 2 + 2

KL = 12

Hence, the length KL is 12 units

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Answer:

166.07

Step-by-step explanation:

Answer:

AC = 17.8

Explanation:

to figure out the length of AC, you want to put the values into the tangent function:

tan 64° = AC/8.7

Now to solve:

first swap them so you have AC/8.7 = tan 64°

Multiply both sides by 8.7 to get AC = 8.7 tan 64°

then calculate it

AC = 8.7 x 2.0503...

AC = 17.8376

AC = 17.8 (3 Significant Figures)

Answer:

The growth model that represents the population of this city is not linear--it is exponential:

\(f(t) = 10000( {1.025}^{t} )\)

\(t = 0 \: represents \: 2010\)

If 4/10 of Lake Okeechobee is covered in a harmful algal bloom in the first month, then 6/10 of the lake is not covered in the bloom.

In the second month, if 90% of the lake is covered in the bloom, then 10% of the lake is not covered in the bloom.

Since the amount of the lake that is covered by the bloom increased from 4/10 to 9/10, this is an increase of:

(9/10) / (4/10) = (9/10) x (10/4) = 2.25 times

Therefore, the algal bloom increased by 2.25 times.

It would take approximately 17.12 years for the amount to reach Birr 56,398.43 with a deposit of Birr 500 at the end of each six-month period, compounded semi-annually at an interest rate of 6%.

To solve this problem, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = Final amount

P = Principal amount (initial deposit)

r = Annual interest rate (in decimal form)

n = Number of compounding periods per year

t = Number of years

In this case, the principal amount is Birr 500, the annual interest rate is 6% (or 0.06), and the interest is compounded semi-annually, so there are 2 compounding periods per year.

We need to find the number of years (t) it takes for the amount to reach Birr 56,398.43.

Let's substitute the given values into the formula and solve for t:

56,398.43 = 500(1 + 0.06/2)^(2t)

Divide both sides by 500:

112.79686 = (1 + 0.03)^(2t)

Take the natural logarithm of both sides to eliminate the exponent:

ln(112.79686) = ln(1.03)^(2t)

Using the property of logarithms, we can bring down the exponent:

ln(112.79686) = 2t * ln(1.03)

Now, divide both sides by 2 * ln(1.03):

t = ln(112.79686) / (2 * ln(1.03))

Using a calculator, we find t ≈ 17.12.

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Answer:

86.53

Step-by-step explanation:

Area of Triangle Formula: A = 1/2bh

Pythagorean Theorem: a² + b² = c²

Step 1: Draw altitude and label numbers

If we draw a line down the middle, we can see that we get a perpendicular bisector and that we get 2 right triangles with a hypotenuse of 29 and a leg of 3. We need to find h using Pythagorean Theorem in order to use area formula:

3² + b² = 29²

b² = 29² - 3²

b = √832 = h

Step 2: Plug in known variables into area formula:

A = 1/2(√832)(6)

A = 3√832

A = 86.5332

Answer:

The answer to this question can be described as follows:

Step-by-step explanation:

A)

The goal is to increase the area and therefore  

Target formula: A = xy  

The limited amount of money, which we have for the fence, and it only has $400  

The equation of constraints: 400=(fence costs parallel to roads) +( 3 other side cost)    

\(\to 400 = 15x+ 5(5y+x)\\\\ \to400 =15x+25y+5x\\\\ \to 400=20x+25y\\\)

B)

To solve y we use the limiting equation:  

\(\to 400=20x+25y\\\\ \to 25y= 400-20x\\\\\to y=\frac{(400-20x))}{25}\\\\\to y=16-\frac{4}{5}x\\\\\)

Now, put the value in the y and maximise as much as possible into our goal equation:  

A function for:  

\(\to A(x)= x(16-(\frac{4}{5}x)\\\\\to A(x) =16x-\frac{4x^2}{5}\)

C)

Select the critical value the A(x):  

\(\to \frac{dA}{dx} 16-\frac{8x}{5}=0 \\\\\to 16=\frac{8x}{5}\\\\\to 16 \times 5 =8x\\\\\to 80=8x \\\\\to x=\frac{80}{8}\\\\\to x=10\\\\\)

We now need, with the second derivative, to ensure that this value is maximum:  

\(\to \frac{d^2A}{dx^2} = \frac{-8}{5}\\\\ \to \frac{d^2A}{dx^2}(10) < O\)

not only is there a relative maximum at x = 10, but we can conclude that the

maximum occurs as\(x = 10 \ since \ \frac{d^2A}{dx^2}< O\) for all x. We also need y:

\(\to y= 16-\frac{4}{5}x\\\\\to y=16-\frac{4}{5}*10\\\\\to y= 16-8\\\\\to y=8\\\\\)

Answer:

Step-by-step explanation:

yes you can depending on your grades in that class though you might have to redo the semester in your free time if your grade is not high enough

Answer:

The measure of the reference angle = 30°

Step-by-step explanation:

Convert 11\(\pi\)/6 (radians) to degrees by multiplying by 180 and dividing by \(\pi\):

11\(\pi\)/6 (radians) = 330\(\pi\)/\(\pi\) = 330°

Therefore, reference angle = 360 - 330 = 30°

First convert to degree from radian .

\(\\ \tt\hookrightarrow \dfrac{11\pi}{6}\times \dfrac{180}{\pi}\)

\(\\ \tt\hookrightarrow \dfrac{1980}{6}=330°\)

Find reference angle=360-330=30°

Last option is correct