Please awnser asap I will brainlist

Answer:

1). Option (d)

2). Option (c)

3). Double the height

Step-by-step explanation:

1). If we triple the length of a box of milk dude,

    New length of the box will become 3 times the previous length.

    Option (d) is correct.

2). Surface area of box 'S' = 2(lb + bh + hl)

   Where l = length of the box

    b = Width of the box

    h = height of the box

   If all of these dimensions are tripled,

   Surface area of the box = 2[(3l)(3b) + (3b)(3h) + (3h)(3l)]

                                           = 2(9)[lb + bh + hl]

                                           = 9S

   Therefore, 9 times material will be required.

   Option (c) is correct

3). From the picture attached,

    Width of the box is less than the height of the box.

    Volume of a rectangular box = lbh

    If we double the length of the given box, volume of the box will be more than doubling the width of the box.

    In simpler words, more space to put the candies will be created if we double the length of the box.

The mass density in kg/m3 will be -  15 x \(10^{-2}\) Kg/m3.

We have a 100.0 m long polymer cable of uniform circular cross section and of diameter 0.4cm has a mass of 1885.0 gm.

We have to determine its mass density in kg/m3.

The amount of mass per unit volume present in the body is called its mass density.

According to question, we have -

Length of polymer cable = 100.0 m

diameter of polymer cable = 0.4 cm = 0.004 m

Therefore, its radius = 0.002 m

The mass density of the wire will be -

\(\rho =\frac{m}{\pi r^{2} l}\)

\(\rho\) = \(\frac{1885}{3.14 \times0.002 \times 0.002 \times 100 }\)

\(\rho = \frac{1885}{0.001256}\) = 1500796.1 g/m3

1 Kg = 1000g

1g = 1/1000kg

1500796.1g = 1500.7 Kg = 15 x \(10^{-2}\) Kg

Therefore, mass density = 15 x \(10^{-2}\) Kg/m3

Hence, the mass density in kg/m3 will be -  15 x \(10^{-2}\) Kg/m3.

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Answer:

130

Step-by-step explanation:

78/6=13

13*10=130

Answer:

C<-6

Step-by-step explanation:

C-C=0 it can not be less than 0

Answer:

7^2/(4+3)=7^2/7=7

(6+2^2)*10=(6+4)*10=10*10=100

Step-by-step explanation:

7²÷(4+3)

First you solve the bracket first;

7²÷(7)

And then you multiply 7 by 7 because of 7²

So it is going to be;

49÷7

=7

(6+2²)×10

Solve bracket first;

(6+2×2)

(6+4)×10

10×10

=100

Answer:

0.6 hours

Step-by-step explanation:

Let's say J is Jen's speed (cake pops per hour), and let's say M is Maryna's speed (cake pops per hour).

Let's say there are 12 cake pops total that need to be made.  Jen made half of the cake pops in 3 hours, so she made 6 cake pops in 3 hours.  So her speed is 2 cake pops per hour.

Then, Jen and Maryna made the other half of the cake pops in 1/2 hour.  Therefore, their combined speed is:

J + M = 6 cake pops / (1/2 hr)

J + M = 12

2 + M = 12

M = 10

So Maryna can make 10 cake pops per hour.

If Maryna was working alone, the amount of time it would take her to make 6 cake pops is:

6 cake pops / (10 cake pops per hour) = 0.6 hours

It would take 0.6 hours, or 36 minutes.

Use exp/log functions to rewrite y as

\(y = (1+x)^{\frac1x} \implies y = \exp\left(\ln\left(1+x)^{\frac1x}\right)\right)\)

One of the properties of logarithms lets us bring down the exponent, so

\(y = \exp\left(\dfrac{\ln(1+x)}x\right)\)

Now take the derivative of both sides with respect to x. By the chain and quotient rules,

\(\dfrac{dy}{dx} = \exp\left(\dfrac{\ln(1+x)}x\right) \times \dfrac{\frac x{1+x} - \ln(1+x)}{x^2}\)

Simplify:

\(\boxed{\dfrac{dy}{dx} = \frac{x - (1+x)\ln(1+x)}{x^2(1+x)} (1+x)^{\frac1x}}\)

Answer:

19

Step-by-step explanation:

6+39÷3

=6+13

=19

Answer:

19

6 + 30 = 36

36 / 3 =19

Based on the information given, the price of the zero coupon bond is $692.04.

To calculate the price of a zero coupon bond, we need to use the following formula:

\(\sf P =\dfrac{F}{1+r\div n}^{(nt)\)

Where:

Also, the annual interest rate is 7.50%, which is the market interest rate, and the compounding is semiannual, which means n = 2. Finally, the time to maturity is 5 years.

Plugging in the values into the formula, we get:

\(\sf P = \dfrac{1000}{(1+0.075\div2)^{(2\times5)}}\)

\(\sf P = \dfrac{1000}{(1.0375)^{10}}\)

\(\sf P = \dfrac{1000}{1.4450}\)

\(\sf P = \$692.04 \ \ (rounded \ to \ the \ nearest \ cent)\)

Therefore, the price of the zero coupon bond is $692.04.

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Answer:

Problematic is that - only one factor should be analysed at a time. However she has considered both.

Step-by-step explanation:

Groups for any experimental study should be selected on the basis of one variable, other factor(s) remaining constant.

In this case, here are two variables - lights on or off, music playing or not playing - effecting relax level during exams.

She selects 10 students for exam with lights off , 10 for exam without music. This is problematic, as at once only lights or only music factor should be considered.

If one group is with light on , other should be with light off. If one group is with music, other should be without music. This mix up of one light off aspect & one music without music is inapt.

Answer:

1/748 or about 0.0013

Step-by-step explanation:

Since there is an exactly equal probability of drawing any of the chips, the probability of drawing the one numbered 513 is:

\(\dfrac{1}{748}\approx 0.0013\)

Hope this helps!

Answer:

87

Step-by-step explanation:

3 times 29

If the rectangle is 29 centimeters longer than it is wide, the area of the rectangle is 96 square centimeters.

To find the area of the rectangle, we first need to determine its length. The problem states that the rectangle is 29 centimeters longer than it is wide, and the width is 3 centimeters.

Let's denote the length of the rectangle as 'L.'

According to the given information, the length is:

L = Width + 29

L = 3 + 29

L = 32 centimeters

Now that we have both the width (3 centimeters) and the length (32 centimeters), we can calculate the area of the rectangle using the formula:

Area = Length × Width

Area = 32 cm × 3 cm

Area = 96 square centimeters

The area of a rectangle is the product of its length and width, and it represents the region enclosed by the rectangle. In this case, knowing that the width is 3 centimeters and the length is 32 centimeters allows us to calculate the area as 96 square centimeters.

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Answer:

you can either factorise or use tge formula method

Step-by-step explanation:

3x2−7x−20=03x2-7x-20=0

Use the quadratic formula to find the solutions.

−b±√b2−4(ac)2a-b±b2-4(ac)2a

Substitute the values a=3a=3, b=−7b=-7, and c=−20c=-20 into the quadratic formula and solve for xx.

7±√(−7)2−4⋅(3⋅−20)2⋅37±(-7)2-4⋅(3⋅-20)2⋅3

Simplify.

Tap for more steps...

x=7±176x=7±176

The final answer is the combination of both solutions.

x=4,−53

Answer:

12.5, 11, 9.5, 8, 6.5, 5, ... 4. an = 14 − 1.5n

Step-by-step explanation:

Step-by-step explanation:

Hey there!

After looking at the figure we can state that;

X + 53° = 105°. { the exterior angle is equal to the sum of adjacent interior angle}

X = 105° - 53°

Therefore, X = 52°

Hope it helps...

Ok, so

We know that about 102 out of every 320 people are left handed.

And, we notice that there's 13.300 students who attend Ben Davis High School.

The number of students left handed in this High School, will be:

(102 * 13.300) / 320

which is about 4239 students.

Answer:

(a) O(x²)

(b) O(x²)

(c) O(x²)

(d) Not O(x²)

Step-by-step explanation:

If a function is O(x²), then the highest power of x in the function ia greater or equal to 2.

(a) 100x + 1000

This is O(x), not O(x²)

(b) 100x² + 1000

This is O(x²)

(c) x³.100 − 1000x²

This is O(x²)

(d) x log x²

This is not O(x²)

The probability that the student got an 'A' given they are male is approximately 0.12 or 12%.

To find the probability that a student got an 'A' given they are male, we need to use Bayes' theorem:

P(A | Male) = P(Male | A) × P(A) / P(Male)

We can find the values of the terms in the formula using the information given in the table:

P(Male) = (25/54) = 0.46 (the proportion of all students who are male)

P(A) = (17/54) = 0.31 (the proportion of all students who got an 'A')

P(Male | A) = (3/17) = 0.18 (the proportion of all students who are male and got an 'A')

Therefore, plugging these values into the formula:

P(A | Male) = 0.18 × 0.31 / 0.46

P(A | Male) ≈ 0.12

So the probability that the student got an 'A' given they are male is approximately 0.12 or 12%.

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Answer:

The  average temperature  is \(T_{a} = 81.95^oC\)

Step-by-step explanation:

From the question we are told that

    The temperature of the coffee after time t is   \(T(t) = 25 + 72 e^{[-\frac{t}{45} ]}\)

Now the average temperature during the first 22 minutes i.e fro \(0 \to 22\)minutes is mathematically evaluated as

              \(T_{a} = \frac{1}{22-0} \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx\)

               \(T_{a} = \frac{1}{22} [25 t + 72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.\)

             \(T_{a} = \frac{1}{22} [25 t - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.\)

              \(T_{a} = \frac{1}{22} [25 (22) - 3240e^{[-\frac{22}{45} ]} - (- 3240e^{0} )]\)

            \(T_{a} = \frac{1}{22} [550 - 1987.12 + 3240]\)

          \(T_{a} = 81.95^oC\)

Hello !

1. A quadratic equation results in the form: ax² + bx + c

2. Calculate the discriminant: Δ = b² - 4ac

3. Calculate x with the dicriminant: (-b ± √Δ) / 2a

Example:

3x² + 7x - 2 = 0 is a quadratic equation.

x = (-b ± √(b² - 4ac)) / 2a

= (-7 ± √(7² - 4*3*(-2))) / (2*3)

= (-7 ± √73)/6

Answer:

212 degrees Fahrenheit (100 degrees Celsius)

Step-by-step explanation:

not really sure how to do this stuff

The ladder will reach a Height of approximately 43.46 meters on the building.

To find out how high on the building the ladder will reach, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the ladder forms a right triangle with the ground and the building. The base of the ladder is 7 meters, the height of the building is what we need to find, and the length of the ladder is given as 44 meters.

Using the Pythagorean theorem, we can set up the equation:

(Height of the building)^2 + 7^2 = 44^2

Simplifying the equation, we have:

(Height of the building)^2 + 49 = 1936

Subtracting 49 from both sides, we get:

(Height of the building)^2 = 1887

To find the height of the building, we take the square root of both sides:

Height of the building = √1887

Calculating the square root of 1887, we find that the height of the building is approximately 43.46 meters.

Therefore, the ladder will reach a height of approximately 43.46 meters on the building.

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The value of the expression is \(\frac{1}{216}\)

An expressions are mathematical statement which have more than two terms that contains variables and constants along with mathematical symbols.

Given the expression, \(p^{-3}\) for p=6

⇒\(p^{-3} =\frac{1}{p^{-3} }\)

⇒if p=3, then \(\frac{1}{p^{-3} } = \frac{1}{216}\)

Hence, the value of expression is \(\frac{1}{216}\).

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Using the given zero . The three zeros of the polynomial function are 1 + i, 1 - i, 1/2, and 2.

If 1 + i is a zero of the polynomial function P(x), then its conjugate, 1 - i, must also be a zero of the polynomial, since complex zeros of polynomial functions with real coefficients always come in conjugate pairs.

To find the remaining zero, we can use polynomial division or synthetic division to divide P(x) by (x - 1 - i)(x - 1 + i), which is the quadratic factor corresponding to the two known zeros:

      2x^2 - 3x + 2

P(x) = --------------

       (x - 1 - i)(x - 1 + i)

Now we need to solve for the roots of the quadratic factor 2x^2 - 3x + 2. We can use the quadratic formula:

x = [3 ± sqrt(9 - 4*2*2)] / (2*2)

 = [3 ± sqrt(1)] / 4

 = 1/2 or 2

Therefore, the remaining zeros of P(x) are 1/2 and 2. The three zeros of the polynomial function are 1 + i, 1 - i, 1/2, and 2.

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The number of horse is 1, goat is 2 and sheep is 3 a man has.

The problem we are dealing with is related to the linear equation which is referred to as the algebraic condition where each term has an exponent of 1 and when this condition is graphed, it continuously comes about in a straight line.

Now w consider x to be the number of sheep, y to be the  number of  goats, and z to be the number of horses the man owns.

the actual equation for the total number of animals he owns  is :

x+ y+ z

according to the first condition:

that all sheep bar three, means

y+ z=3

similarly, for the other condition, it will be

x+ z=4   and x+ y=5

Now we adding the three  equations:

y + z +x +z +x +y=5+4 +3

2(x+y+z)=12

x+y+z=6........equation(1)

As x + y = 5

Put this in equation in (1), we get

x+y+z = 6

5 + z = 6

z = 1

x + z = 4

x + y + z = 6

y + 4 = 6

y = 2

Now we know

x + y + z = 6

x + 1 + 1 = 6

x = 4

So simplifying the other equation  we get, that the number of horse is 1, goat is 2, and sheep is 4.

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Answer:

Step-by-step explanation:

Answer:

If a function is increasing, the average rate of change between any 2 points must be positive.

If we have an increasing function, the average rate of change between any two points must always be positive.

For an increasing function f(x), we have that if:

b > a

Then:

f(b) > f(a).

Now, we define the average rate of change on an interval (a, b) as:

\(R = \frac{f(b) - f(a)}{b - a}\)

In this case, because:

b > a

f(b) > f(a)

Then:

b - a > 0

f(b) - f(a) > 0.

So both numerator and denominator are positive, which implies that the quotient must be positive.

Then, if we have an increasing function, the average rate of change between any two points must always be positive.

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