Answer:
\(\Large \boxed{\sf 956.56 \ mm^2}\)
Step-by-step explanation:
Surface area → area of 2 bases + area of 6 rectangles
Area of base is given
Area of rectangle → length × width
\(\left(2\cdot 166.28\right)+\left(8\cdot 13\cdot 6\right)=956.56\)
Answer:
956.56 only for the 50 my guy my friend justin he's already taken and he's cracked at fortnite my guy
Step-by-step explanation:
A cup of tea is placed on a table. At a time of t minutes after being placed on the table, its temperature in degrees Celsius is given by
T = 20 + Ae⁻ᵏᵗ
Where A and K are positive constants. The initial temperature of the tea was 70℃
a. Find the value of A
b. The tea takes 4 minutes to decrease in temperature from 70℃ to 50℃
show that k = 1/4 In (5/3)
please can someone explain how to get the time (t minutes) as well as a. and b. as i am baffled! i dont know what to do
Thankyouu!!
Step-by-step explanation:
To solve the problem, we'll use the information given to find the values of A and k in the equation T = 20 + Ae^(-kt), where T is the temperature in degrees Celsius at time t.
a. Finding the value of A:
We're given that the initial temperature of the tea was 70℃. Substituting this into the equation, we get:
70 = 20 + Ae^(0) (since e^0 = 1)
70 - 20 = A
A = 50
So the value of A is 50.
b. Finding the value of k:
We're told that it takes 4 minutes for the tea to decrease in temperature from 70℃ to 50℃. We can use this information to set up an equation and solve for k.
Substituting T = 70 and t = 4 into the equation, we have:
70 = 20 + 50e^(-4k)
Subtracting 20 from both sides:
50 = 50e^(-4k)
Dividing both sides by 50:
1 = e^(-4k)
Taking the natural logarithm (ln) of both sides:
ln(1) = ln(e^(-4k))
0 = -4k
Dividing both sides by -4:
0 = k
However, we need to check if this solution satisfies the condition for the tea to decrease in temperature from 70℃ to 50℃ in 4 minutes.
Substituting T = 50 and t = 4 into the equation, we have:
50 = 20 + 50e^(-4(0))
50 = 20 + 50e^0
50 = 20 + 50(1)
50 = 20 + 50
50 = 70
Since 50 is not equal to 70, the value of k = 0 does not satisfy the given condition.
Let's try another approach:
Substituting T = 50 and t = 4 into the equation, we have:
50 = 20 + 50e^(-4k)
Subtracting 20 from both sides:
30 = 50e^(-4k)
Dividing both sides by 50:
0.6 = e^(-4k)
Taking the natural logarithm (ln) of both sides:
ln(0.6) = ln(e^(-4k))
ln(0.6) = -4k ln(e)
ln(0.6) = -4k(1)
ln(0.6) = -4k
Simplifying further:
k = ln(0.6) / -4
Using a calculator or computer to evaluate ln(3/5) / -4, we get approximately:
k = ln(5/3) / 4
To recap:
a. The value of A is 50.
b. The value of k is approximately k = ln(5/3) / 4
.
Note: The calculations provided are based on the given information and assumptions. If there are any additional details or specific conditions provided, please let me know, and I'll be happy to assist you further.
Find the least common denominator (LCD) 8/9 and 4/5
Answer:
45
Step-by-step explanation:
First we write the first 10 multiples of 9 (the first denominator) :
9,18,27,36,45,54,63,72,81,90
Now we write the first 10 multiples of 5 (the second denominator) :
5,10,15,20,25,30,35,40,45,50
As we can see 45 is the lowest number that appears in both list.
Therefore 45 is the LCD of 8/9 and 4/5
Answer:
45
Step-by-step explanation:
So since we are finding the LCD, we only look at the denominators, 9 and 5.
We can count until we find the denominator:
\(9,18,27,36,45\\5,10,15,20,25,30,35,40,45\)
So the LCD would be 45.
SCALCET8 3.10.025. Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 126
Answer:
\(f(126) \approx 5.01333\)
Step-by-step explanation:
Given
\(\sqrt[3]{126}\)
Required
Solve using differentials
In differentiation:
\(f(x+\triangle x) \approx f(x) + \triangle x \cdot f'(x)\)
Express 126 as 125 + 1;
i.e.
\(x = 125; \triangle x = 1\)
So, we have:
\(f(125+1) \approx f(125) + 1 \cdot f'(125)\)
\(f(126) \approx f(125) + 1 \cdot f'(125)\)
To calculate f(125), we have:
\(f(x) = \sqrt[3]{x}\)
\(f(125) = \sqrt[3]{125}\)
\(f(125) = 5\)
So:
\(f(126) \approx f(125) + 1 \cdot f'(125)\)
\(f(126) \approx 5 + 1 \cdot f'(125)\)
\(f(126) \approx 5 + f'(125)\)
Also:
\(f(x) = \sqrt[3]{x}\)
Rewrite as:
\(f(x) = x^\frac{1}{3}\)
Differentiate
\(f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}\\\)
Using law of indices, we have:
\(f'(x) = \frac{x^\frac{1}{3}}{3x}\)
So:
\(f'(125) = \frac{125^\frac{1}{3}}{3*125}\)
\(f'(125) = \frac{5}{375}\)
\(f'(125) = \frac{1}{75}\)
So, we have:
\(f(126) \approx 5 + f'(125)\)
\(f(126) \approx 5 + \frac{1}{75}\)
\(f(126) \approx 5 + 0.01333\)
\(f(126) \approx 5.01333\)
What is 6/20 of a dollar
BRAINLIEST IS RIGHT
Answer: 30 cents
Step-by-step explanation:
1/20 of a dollar is 5 cents
Then we multiply by the numerator (6) to get our answer....
5x6= 30
Hoped this helps! :)
what is the estimated sum of 6/7 plus 4/7
Answer:
10/7
Step-by-step explanation:
6/7+4/7= 6+4/7= 10/7
Is this your question?
Answer:
1, hope this helps!
Step-by-step explanation:
I took the test
Which relations are functions?
A
x
y
-2
-4
-2 -6
0
-8
2
-10
B
x
y
0
4
10 5
20
6
10
7
C
x
y
2
-10
1 -20
0
-10
-1
-20
D
x
y
2.5
0
3.5 4
4.5
8
6.5
12
E
x
y
-10
4
-20 5
0
6
-10
7
Answer:
A. Relation
B. Relation
C. Function
D. Function
E. Relation
Use the given proof to answer the question below:
Given ABCD is a parallelogram.
Prove: ADCB
D
A
1
2
3
4
S
6
Statements
ABCD is a parallelogram
ABI CD and AD IBC
and
AC = AC
ADCA ABAC
AD CB
Which of the options below complete the proof?
A. Statement 3: LBACZCAD and ZBCA LDCA
Reason 5: A.A.S. Postulate
B. Statement 3: LBACCAD and ZBCA = LDCA
Reason 5: A.S.A Postulate
C. Statement 3: LBAC LDCA and LBCA LDAC
Reason 5: A.A.S. Postulate
D. Statement 3: ZBAC LDCA and LBCA LDAC
Reason 5: A.S.A Postulate
Reasons
Given
Definition of parallelogram
Alternate interior angles theorem
Reflexive property
C.P.C.T.C.
The correct option is D.
Given that ABCD is a parallelogram, we need to prove AD ≅ CB.
So,
Properties of a parallelogram =
Opposite sides are parallel.
Opposite sides are congruent.
Opposite angles are congruent.
Statement Reason
1. ABCD is a parallelogram Given
2. AB║CD and AD║BC Definition of parallelogram
3. ∠BAC ≅ ∠DCA and ∠BCA ≅ ∠DAC Alternate interior angles theorem
4. AC ≅ AC Reflexive property
5. ΔBAC ≅ ΔDCA A.S.A Postulate
6. AD ≅ CB CPCTC
Hence the correct option is D.
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What is an equation of the line that passes through the points (−3,8) and (-7, 8)
Answer:
y = 8
Step-by-step explanation:
Since the y- coordinates of the points are equal, both 8 , then
This indicates the line is horizontal and parallel to the x- axis with equation
y = c
where c is the value of the y- coordinates the line passes through
The line passes through (- 3, 8 ) and (- 7, 8 ) with y- coordinates 8 , then
y = 8 ← equation of line
12x^3-9x^2 factorised
How would you answer this?..
Answer:
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(12 • (x3)) - 32x2
STEP
2
:
Equation at the end of step
2
:
(22•3x3) - 32x2
STEP
3
:
STEP
4
:
Pulling out like terms
4.1 Pull out like factors :
12x3 - 9x2 = 3x2 • (4x - 3)
Final result :
3x2 • (4x - 3)
Given circle E with diameter CD and radius EA. AB is tangent to E at A. If AB=34 and EB=38, solve for EA. Round to the nearest tenth if necessary
The value of side EA is,
EA = 16.9
We have to given that;
Circle E with diameter CD and radius EA.
And, AB is tangent to E at A.
Here, AB = 34 and EB = 38
Hence, By using Pythagoras theorem we get;
AB² + AE² = EB²
34² + AE² = 38²
1156 + AE² = 1444
AE² = 1444 - 1156
AE² = 288
AE = √288
AE = 16.9
Thus, The value of side EA is,
EA = 16.9
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4. Jack ran mile and Roy ran mile. a. What benchmark fractions can be used to estimate how much farther Roy ran than Jack? b. Using the benchmark fractions, what is a reasonable estimate for the difference between the two distances? c. What is the actual difference?
1. The benchmark fractions that can be used to estimate how much farther Roy ran than Jack is 1/4 and 2/3.
2. By using the benchmark fractions, what is a reasonable estimate for the difference between the two distances is 5/12 mile.
3. The actual difference is 5/12 mile.
How to determine the benchmark fractions?In order to determine the benchmark fractions that can be used to estimate how much farther (the amount of distance) Roy ran than Jack, we would first of all, simplify the fraction representing the amount of distance covered by Jack as follows;
Jack's distance = 2/8 mile
Dividing by 2, we have this simplified fraction;
Jack's distance = 1/4 mile
Benchmark fractions = 2/3 and 1/4.
Part b
Additionally, by subtracting the amount of distance covered by Jack from the amount of distance covered by Jack as follows;
Difference = 2/3 - 1/4
Difference = (8 - 3)/12
Difference = 5/12 mile.
Part c
Actual Difference = 2/3 - 2/8
Actual Difference = (16 - 6)/24
Actual Difference = 10/24 mile.
Actual Difference = 5/12 mile.
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Complete Question:
Jack ran 2/8 mile and Roy ran 2/3 mile.
a. What benchmark fractions can be used to estimate how much farther Roy ran than Jack?
b. Using the benchmark fractions, what is a reasonable estimate for the difference between the two distances?
c. What is the actual difference?
I NEED HELP 30 POINT!!
Answer:
35
Step-by-step explanation:
You can easily graph this in desmos for a visual understanding.
The slope of a line is received by (y2-y1)/(x2-x1). Assuming that Days is X and the cost is Y, we get (160-90)/(4-2), and it makes 70/2, which equates out to 35. Because the prices become more and more expensive, the slope is positive 35.
If the customers order came to $13.58 and he gave you a $20.00 bill, what is his change?
Answer:
$6.42
Step-by-step explanation:
It's very simple, all you have to do is subtract 13.58 by the 20.00$, so you will get that.
7. The plot of land modeled below is composed of a right triangle and a rectangle. If Patrick wants to install a fence around the perimeter of the plot of land, how many feet of fencing will be needed
The number of feet of fencing that will be needed is illustrated below
How many feet of fencing will be needed The feet of fencing that will be needed is the perimeter of the fence
To find the perimeter of a composite figure, we need to add up the lengths of all the sides of the figure.
In this case, we add the side lengths of the rectangle to the side lengths of the right triangle and subtracting the common lengths between both shapes
Take for instance, we have
Right triangle: 3 units, 4 units and 5 unitsRectangle: 4 by 5 unitsCommon segment: 4 unitsSo, we have
Fencing = 2 * (4 + 5) + 3 + 4 + 5 - 2 * 4
Fencing = 22 units
So, the amount of fencing for the assumed dimensions is 22 units
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ANYONE GOOD IN MATH PLEASE HELP!
Answer: 15
Step-by-step explanation:
The range is the set of all Y values, in this question -8 is the minimum and +7 is the maximum, therefore the range is (-8-7) = -15, but range is not negative so we get 15
Match each linear system with one of the phase plane direction fields.
(The blue lines are the arrow shafts, and the black dots are the arrow tips.)
I need help. I don't know how to use the eigenvalues and take that information and put it on a graph. Please explain thoroughly! Thanks.
The correct match for each linear system with one of the phase plane direction fields will be:
1:B
2:C
3:D
4:A
What is plane?
In geometry, a plane is a surface made up of all the straight lines connecting any two locations on it. It is, in other words, a level or flat surface. A plane is uniquely defined in a Euclidean space of any number of dimensions by one of the following: three non-collinear points are used. Other names for it include a two-dimensional surface. A plane has an unlimited width, an endless length, zero thickness, and no curvature. The flat surfaces of a cube or cuboid, as well as the flat surface of paper, are all true instances of geometric planes, despite the fact that it is difficult to envision a plane in real life.
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m/2 =-6
plz help
will give brainliest
Answer:
m= -12
Step-by-step explanation:
m/2= -6
-multiply both sides by 2 to get rid of ( /2)
m= -12
PQRS is a quadilateral in which <PQR=74°;
<PSR 48°, <SRQ=116°. If <QPS is bisected to
meet QR at M, calculate the size of <PMQ
] Scientists trying to calculate the half-life (the time it takes for half of a sample to decay) of Phosphorus-32, took measurements of the sample once every day for five days. On what day should about a fourth of the original amount of P-32 remain? (Round answer to the nearest day.) Day Mass (g) 0 100 1 95 2 90.5 3 85 82 78 25 st 4 LO 5 ?
The time it will take for about a fourth of the original amount of P-32 remain is given as follows:
27 days.
How to define the exponential function?An exponential function is defined as follows:
y = ab^x.
In which:
a is the initial value.b is the rate of change.Considering that the initial amount is of 100, while after one day the amount was of 95, the parameters are given as follows:
a = 100, b = 95/100 = 0.95.
Hence the function for the amount remaining after x days is given as follows:
y = 100(0.95)^x.
One fourth of the amount will be remaining when y = 25, hence:
25 = 100(0.95)^x.
(0.95)^x = 0.25
xlog(0.95) = log(0.25)
x = log(0.25)/log(0.95)
x = 27 days.
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A nurse supervisor found that staff nurses complete a certain task in 10 minutes, on average. If the times required to complete the task are approximately normally distributed with a standard deviation of 3 minutes, find:
a) The percentage of nurses completing the task in less than 5 minutes.
% (e.g. 15.55%)
b) The percentage of nurses requiring more than 10 minutes to complete the task.
% (e.g. 15.55%)
c) The probability that a nurse who has just been assigned the task will take between 8 and 12 minutes to complete it.
(e.g. 0.7512)
d) The slowest 20% are given additional training. What task times qualify staff nurses for such training?
min (e.g. 45.5 min]
A) The percentage of nurses completing the task in less than 5 minutes is approximately 4.75%. b) The percentage of nurses requiring more than 10 minutes to complete the task is approximately 50%
To solve this problem, we will use the properties of the normal distribution and z-scores. Given that the average completion time for the task is 10 minutes and the standard deviation is 3 minutes, we can proceed with the following calculations:
a) To find the percentage of nurses completing the task in less than 5 minutes, we need to calculate the z-score corresponding to a time of 5 minutes and then determine the area under the normal distribution curve to the left of that z-score.
The z-score formula is given by: z = (x - μ) / σ
where x is the time in question (5 minutes), μ is the mean (10 minutes), and σ is the standard deviation (3 minutes).
z = (5 - 10) / 3 = -5/3 ≈ -1.67
Using a standard normal distribution table or a calculator, we can find that the area to the left of -1.67 is approximately 0.0475 or 4.75%. Therefore, approximately 4.75% of nurses complete the task in less than 5 minutes.
b) To find the percentage of nurses requiring more than 10 minutes to complete the task, we calculate the z-score for a time of 10 minutes and find the area to the right of that z-score.
z = (10 - 10) / 3 = 0
The area to the right of z = 0 is 0.5 or 50%. Therefore, approximately 50% of nurses require more than 10 minutes to complete the task.
c) To find the probability that a nurse will take between 8 and 12 minutes to complete the task, we need to find the area under the curve between the z-scores for 8 and 12 minutes.
z1 = (8 - 10) / 3 = -2/3 ≈ -0.67
z2 = (12 - 10) / 3 = 2/3 ≈ 0.67
Using a standard normal distribution table or a calculator, we find the area to the left of z = -0.67 as approximately 0.2514, and the area to the left of z = 0.67 as approximately 0.7514. Therefore, the probability that a nurse will take between 8 and 12 minutes to complete the task is approximately 0.7514 - 0.2514 = 0.5 or 50%.
d) To find the task times that qualify staff nurses for additional training, we need to determine the z-score corresponding to the slowest 20% of completion times and then convert it back to the original time scale.
The z-score corresponding to the slowest 20% is found by locating the z-score that has an area of 0.2 to its left. Using a standard normal distribution table or a calculator, we find this z-score to be approximately -0.84.
Now, we can convert the z-score back to the original time scale:
z = (x - μ) / σ
-0.84 = (x - 10) / 3
Solving for x, we have:
-0.84 * 3 = x - 10
-2.52 = x - 10
x = 10 - 2.52
x ≈ 7.48
Therefore, the task times that qualify staff nurses for additional training are approximately greater than 7.48 minutes.
In summary:
a) The percentage of nurses completing the task in less than 5 minutes is approximately 4.75%.
b) The percentage of nurses requiring more than 10 minutes to complete the task is approximately 50%
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Write an equation that represents the perimeter of the rectangle. The width of a rectangle is 9 less than one-third it's width, when the perimeter is 45.
Answer:
The equation that represents the perimeter of the rectangle is:
\(\text{Perimeter} = \frac{2}{3} \times [4l-27]\)
Step-by-step explanation:
The perimeter of a rectangle is given by the formula:
Perimeter = 2 × [l + w]
It is provided that the width of a rectangle is 9 less than one-third it's length.
That is:
\(w = \frac{1}{3}l-9\)
The perimeter is given as 45.
The equation that represents the perimeter of the rectangle is:
\(\text{Perimeter} = 2 \times [l + \frac{1}{3}l-9]\\\\\text{Perimeter} = 2 \times [\frac{3l+l-27}{3}]\\\\\text{Perimeter} = 2 \times [\frac{4l-27}{3}]\\\\\text{Perimeter} = \frac{2}{3} \times [4l-27]\)
Thus, the equation that represents the perimeter of the rectangle is:
\(\text{Perimeter} = \frac{2}{3} \times [4l-27]\)
Miss Lianto mowed 2 7 of her lawn. Her son mowed 1 3 of it. Who mowed most of the lawn? How much of the lawn still needs to be mowed?
HURRY!!!!!!!!!!!!!!!!!!!!!!!!!
8/21 of the lawn still needs to be mowed.
To compare fractions, we need a common denominator. The least common multiple of 7 and 3 is 21.
Miss Lianto's fraction: (2/7) x (3/3) = 6/21
Son's fraction: (1/3) x (7/7) = 7/21
To calculate how much of the lawn still needs to be mowed, we can subtract the combined fractions mowed from the total:
Combined fractions mowed: 6/21 + 7/21 = 13/21
So, Remaining fraction: 1 - 13/21 = 8/21
Therefore, 8/21 of the lawn still needs to be mowed.
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James wants to buy a gaming computer priced at $3,774, but he is not able to pay the amount in full.
The shop, though, offers purchase plans to help customers afford their products.
The annual interest rates on offer are below. Simple interest will be calculated on each loan.
Payment Period Interest Rate
12 months 14.8%
24 months 11.6%
James chooses to go with the 12-month plan.
How much will the shop earn in interest? (Answers to whole dollars)
$
What is the total amount that James will pay for the computer?
$
If the repayments are split evenly over the year, how much will James pay per month?
$
I need help with this please if you can :)
What item shown below?? Imao I'll edit my answer if you put it below in the comments
f÷−32=−31
whats the answer?
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "/-32" was replaced by "/(-32)".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
f/(-32)-(-31)=0
Step by step solution :
STEP
1
:
f
Simplify ———
-32
Equation at the end of step
1
:
f
——— - -31 = 0
-32
STEP
2
:
Rewriting the whole as an Equivalent Fraction
2.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using -32 as the denominator :
-31 -31 • -32
-31 = ——— = —————————
1 -32
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
f • -1 - (-31 • 32) 992 - f
——————————————————— = ———————
32 32
Equation at the end of step
2
:
992 - f
——————— = 0
32
STEP
3
:
When a fraction equals zero
3.1 When a fraction equals zero
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
992-f
————— • 32 = 0 • 32
32
Now, on the left hand side, the 32 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
992-f = 0
Solving a Single Variable Equation:
3.2 Solve : -f+992 = 0
Subtract 992 from both sides of the equation :
-f = -992
Multiply both sides of the equation by (-1) :
f = 992
the answer is f = 992
Ninety-two percent of the people who have a particular disease will have a positive result on a given
diagnostic test. Ninety-six percent of the people who do not have the disease will have a negative result on
this test. Suppose 5 percent of the population has the disease.
7. Draw a tree diagram to illustrate these probabilities.
8. What percent of the population would test positive for the disease?
9. If someone from the population tests positive, what is the probability that (s)he has the disease?
99.4% chance that you are healthy if you receive a negative test. 67.9% chance that you are sick if you receive a positive test.
How to calculate probability?14% of population would test positive for the disease
Step 1. Give algebraic names to various events described:
Let the event A represent the event that the diagnostic test gives a positive resultthe event E1 represent the event that a person has the particular disease, and, the event E2= not E1 represent the event that a person does not have the particular disease.Step-2: Model the given situation mathematically.
It is given that ninety percent of the people who have the disease will have a positive result on a given diagnostic test.In other words, the conditional probability of the event that the diagnostic test gives a positive result (A) given that the tested person has the disease (E1) is given to be 90% Thus, P(A/E1)=90%It is also given that ninety percent of the people who do not have the disease will have a negative result on a given diagnostic test.In other words, the conditional probability of the event that the diagnostic test gives a negative result (not A), given that the tested person does not have the disease (E2 = not E1) is given to be 90%
Thus P(not A/E2)=90%
Further, it is given that five percent of the population has the disease. In other words, the event that a person has the disease (E1) has the probability of 5% Thus P(E1)=5%
It is needed to find what percent of that population would test positive for the disease.
Thus, the probability that a person will have a positive result when tested, P(A) is to be determined.
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431.67 In a different number, the 4 represents a value which is one-tenth of the value of the 4 in the number above. What value is represented by the 4 in the other number?
So the different number has a 4 with a value of 40.
What is Algebraic expression ?
Algebraic expression can be defined as combination of variables and constants.
To solve this problem, we need to first identify the place value of the digit 4 in the given number.
The digit 4 is in the hundreds place in the number 431.67, so its value is 4 x 100 = 400.
According to the problem statement, the 4 in the different number represents a value which is one-tenth of the value of the 4 in 431.67. Therefore, the value of the 4 in the different number is:
400/10 = 40
To determine the value of the different number, we need to look at the other digits in the number. Since we don't have any information about the other digits, we cannot determine the value of the different number. The answer is that the value of the different number cannot be determined with the information given.
Therefore, So the different number has a 4 with a value of 40.
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Which ordered pair is a reflection of (3, 7) across the y-axis?
(7, -3)
(-3, 7)
(-3, -7)
(3, -7)
Answer:
(-3, 7)
Step-by-step explanation:
It is like putting a mirror on the y-axis. It is asking what point is the photo negative of the point, like a mirror. You see yourself in the mirror but everything is opposite. Your right hand is your left. So which point is the photo negative of (3, 7)? (-3, 7) Because it is only across the y-axis, the y value stays the same.
Duane begins paying a $5,000
student loan with an annual interest rate of 6.5%
compounded monthly. He schedules monthly payments of $118.57
for 4
years.
The following table shows the first payment in the amortization schedule.
Payment
Number Loan
Amount Payment Interest Principal Remaining
Balance
1
$5,000.00
$118.57
?
What amount of Duane's first payment goes to interest?
Responses
The amount of Duane's first payment that goes to interest is approximately $26.47.
To determine the amount of Duane's first payment that goes to interest, we need to use the amortization formula for a loan.
The formula to calculate the interest portion of a loan payment is:
Interest = Remaining Balance * Monthly Interest Rate.
Let's calculate the interest for the first payment using the given information:
Loan Amount = $5,000.00
Monthly Payment = $118.57
First, we need to calculate the monthly interest rate:
Monthly Interest Rate = Annual Interest Rate / 12
= 6.5% / 12
= 0.00542
Next, we need to calculate the remaining balance after the first payment:
Remaining Balance = Loan Amount - Principal Paid
= $5,000.00 - $118.57
= $4,881.43
Finally, we can calculate the interest portion of the first payment:
Interest = Remaining Balance * Monthly Interest Rate
= $4,881.43 * 0.00542
= $26.47
For more such questions on interest
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WILL GIVE BRAINLEST 658 minus what equals 98?
Answer:
-560 is the answer
Step-by-step explanation:
658 - (-560 )= 98
Answer:
Hello!!! erz here ^^
Step-by-step explanation:
658 - 560 = 98
Hope this helps!! :D