Please Help!!! I have no idea :(


1. During an experiment in which you are investigating the acceleration changes due to force changes, what value must stay constant during these trials?

a. Force
b. Velocity
c. Acceleration
d. Mass

2. An animal is walking forward. There is an applied force from the animal of 25 N to the right, a frictional force of 18 N to the left, a force of gravity of 65 N down and the animal is being pushed up by the ground with 65 N. What best describes the motion of the animal?

a. The animal will move to the left due to an unbalanced force on the left
b. The animal will move to the right due to an unbalanced force on the right
c. The animal will move down due to an unbalanced force down
d. The animal will move up due to an unbalanced force upwards

3. Two rockets are being tested. Both rockets have the same mass. One rocket accelerates at a higher rate than another rocket. What could be true about the difference between the rockets?

a. One rocket has more fuel than the other
b. One rocket is more streamlined than the other
c. One rocket engine produces more force than the other
d. One rocket is more badly designed than the other

4. According to Newton's Third Law, if a sledgehammer hits a wall with a force of 1000 N, how much force does the wall hit the sledgehammer?

a. 0 N
b. 500 N
c. 1000 N
d. - 1000 N

Answer:

t=8

Explanation:

u have solution I give solution also

don't mark plzz follow y

Answer:

25.5 pounds per square inch are equivalent to 1.735 atmospheres.

Explanation:

An atmosphere equals 14.695 pounds per square inch. We find the equivalent of given pressure in atmospheres by means of simple rule of three:

\(x = 25.5\,\frac{lb}{in^{2}} \times \frac{1\,atm}{14.695\,\frac{lb}{in^{2}} }\)

\(x = 1.735\,atm\)

25.5 pounds per square inch are equivalent to 1.735 atmospheres.

Answer:

\(p\times q=-23i+7j+6k\)

Explanation:

We are given that

p=2i+4j+3k

q=i+5j-2k

We have to find pxq

We know that

\(p\times q=\begin{vmatrix}  i&j  &k\\  2&4  & 3\\  1& 5 & -2\end{vmatrix}\)

\(p\times q=i(-8-15)-j(-4-3)+k(10-4)\)

\(p\times q=-23i+7j+6k\)

Hence,\(p\times q=-23i+7j+6k\)

On one cookie containing 50 calories, you could potentially go approximately 298 meters

Given that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:

50 food calories * 4184 J/calorie = 209,200 joules

Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).

Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)

Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)

Distance ≈ 298 meters

Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters

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Answer:

If you see images of a gas stove burner, pinto beans, fruits & vegetables, and grain, then the answer is A or 1.

Explanation:

Answer:

1. The work done on the cube during the time the cube is in contact with the spring is 0.8023705 J

2. The speed of the cube at the instant just before the sliding cube leaves the ramp is approximately 31.5 cm/s

Explanation:

The given parameters of the Rube Goldberg machine are;

The distance from the free end of the spring to the top of the ramp, d = 17.0 cm = 0.17 m

The mass of the small cube to be launched, m = 119.0 g = 0.119 kg

The spring constant of the spring, k = 461.0 N/m

The angle of elevation of the ramp to the horizontal, θ = 50.0°

The coefficient of static friction of the wood, \(\mu_s\) = 0.590

The coefficient of dynamic friction of the wood, \(\mu_k\) = 0.470

The velocity of the cube at the top of the ramp, v = 45.0 cm/s = 0.45 m/s

The amount by which the cube is compressed, x = 5.90 cm = 0.059 m

The work done on the cube during the time the cube is in contact with the spring = The energy of the spring, E = (1/2)·k·x²

∴ E = (1/2) × 461.0 N/m × (0.059 m)² = 0.8023705 J

The work done on the cube during the time the cube is in contact with the spring= E = 0.8023705 J

2. The frictional force, \(F_f\) = \(\mu_k\)·m·g·cos(θ)

∴ \(F_f\) = 0.470 × 0.119 × 9.8 × cos(50) ≈ 0.35232 N

The work loss to friction, W = \(F_f\) × d

∴ W = 0.35232 N × 0.17 m ≈ 0.05989 J

The work lost to friction, W ≈ 0.05989 J

The potential energy of the cube at the top of the ramp, P.E. = m·g·h

∴ P.E. = 0.119 kg × 9.8 m/s² × 0.17 m × sin(50°) ≈ 0.151871375 J

By conservation of energy principle, the Kinetic Energy of the cube at the top of the ramp, K.E. = E - W - P.E.

∴ K.E. = 0.8023705 J - 0.05989 J - 0.151871375 J ≈ 0.590609125 J

K.E. = (1/2)·m·v²

Where;

v = The speed of the cube at the instant just before the sliding cube leaves the ramp

∴ K.E. = (1/2) × 0.119 kg × v² ≈ 0.590609125 J

v² ≈ 0.590609125 J/((1/2) × 0.119 kg) ≈ 9.92620378 m²/s²

v = √(9.92620378 m²/s²) ≈ 3.15058785 m/s ≈ 31.5 cm/s

The speed of the cube at the instant just before the sliding cube leaves the ramp, v ≈ 31.5 cm/s.

The density of gold can also be used in various scientific and industrial applications, such as in the manufacturing of electronic components and medical implants.

The density of a material is defined as its mass per unit volume. In this case, we have a block of gold with a mass of 170g and a volume of 9 cm^3. To find the density, we can simply divide the mass by the volume:

Density = Mass / Volume

Density = 170g / 9 cm^3

Density = 18.89 g/cm^3

Therefore, the density of the gold block is 18.89 g/cm^3. This means that for every cubic centimeter of the block, there is a mass of 18.89 grams. Gold is a dense material, and its high density is one of the reasons why it is valued in jewelry and other decorative items.

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Answer:

50kgm/2

Explanation:

If the given speed of any atom in a monatomic state of an ideal gas were doubled, then by using four factor we would multiplied the Kelvin present temperature of the gas. Option (a) is correct.

We recollect a monatomic best fueloline having debris of mass m that don't engage and whose middle of mass stays at rest. For a monatomic best fueloline (which include helium, neon, or argon), the most effective contribution to the strength comes from translational kinetic strength. The common translational kinetic strength of a unmarried atom relies upon most effective at the fueloline temperature and is given through the equation: Kavg = 3/2 kt.

These are helium, neon, argon, krypton, xenon, and radon. Noble gases have a complete outer valence shell making them as an alternative non-reactive species. Many gases which include nitrogen, oxygen, hydrogen, noble gases, a few heavier gases like carbon dioxide and combinations which include air, may be dealt with as best gases inside affordable tolerances over a significant parameter variety round widespread temperature and pressure.

We know that,

K.E = (1/2) m*\(V^{2}\)

If we doubled the speed then 2*2=4 times its affect the temperature.

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The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

Given the following data:

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

\(Total \;mass=2 + 97\)

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

\(Force = mass \times acceleration\)

Substituting the given parameters into the formula, we have;

\(Force = 99 \times 2\)

Net force = 198 Newton

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The work done by the force on the block is approximately 311.2 Joules.

To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.

The horizontal component of the force can be calculated using trigonometry:

F_horizontal = F * cos(angle)

            = 45 N * cos(30 degrees)

            = 45 N * (√3 / 2)

            ≈ 38.9 N

Now, we can calculate the work done by the force using the equation:

Work = Force * Distance * cos(theta)

where theta is the angle between the force and the displacement.

Work = F_horizontal * Distance * cos(0)

     = 38.9 N * 8 m * cos(0)

     = 38.9 N * 8 m

     = 311.2 Joules

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Answer: THEY ATTRACT CERTIN METALS

THEY REQUIRE ELECTRIC CURRENTS

THEY EXERT FORCE

Explanation:

The true statements about magnetic fields are

The magnetic field is the area around a magnet in which the effect of magnetism is felt. The magnetic field is used to describe how the magnetic force is distributed in the space around and within something magnetic in nature.

A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

The properties of magnetic field are

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Answer:

a)speed of light.

a)speed of light×time=distance.

Explanation:

light has a constant speed of 299,792,458m/s

This distance is analyzed quantitatively by LIDAR (Light Detection And Ranging) stations, which bounce laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

Lidar is a method of determining ranges that involves using a laser to target an object or a surface and measuring the time it takes for the reflected light to return to the receiver.

LiDAR is a type of remote sensing technology. LiDAR technology collects measurements by using a laser pulse. These are employed in the production of 3D models and maps of objects and environments.

Lidar, which stands for light detection and ranging, has been around for quite some time. It employs lasers to ping off objects and return to the laser source, measuring distance by timing the travel, or flight, of a light pulse.

LIDAR (Light Detection And Ranging) stations analyze this distance quantitatively by bouncing laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

Thus, this way, the distance can be calculated.

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We can find the time for which the glider is in contact with the spring by using the impulse-momentum theorem:

Impulse = Change in momentum

The impulse of the force exerted by the spring is given by the area under the force-time graph, which is a triangle:

Impulse = (1/2) * (1 N) * (0.02 s) = 0.01 Ns

The initial momentum of the glider is:

p1 = m * v1 = (0.5 kg) * (0.3 m/s) = 0.15 kg m/s

The final momentum of the glider is zero, since it comes to rest:

p2 = 0 kg m/s

Therefore, the change in momentum is:

Δp = p2 - p1 = -0.15 kg m/s

Setting the impulse equal to the change in momentum and solving for the time gives:

Impulse = Change in momentum

0.01 Ns = Δp = p2 - p1

0.01 Ns = 0 - 0.15 kg m/s

0.01 Ns = -0.15 kg m/s

t = Δp / Impulse = (-0.15 kg m/s) / (0.01 Ns) ≈ -15 s

The negative value for time doesn't make sense physically, so we need to check our work. Looking at the force-time graph, we see that the force is actually zero for most of the time, and only becomes non-zero when the glider is in contact with the spring. Therefore, we need to find the time for which the force is non-zero.

The force is non-zero for a duration of 0.01 s, so this is the contact time:

t = 0.01 s

Therefore, the glider is in contact with the spring for 0.01 seconds.

here's the answer. I'm not too sure about it, but good luck

The time for which the glider is in contact with the spring is approximately 0.17 s.

Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and velocity. Mathematically, momentum can be expressed as:

p = mv

where p is momentum, m is the mass of the object, and v is the velocity of the object.

Impulse is the change in momentum of an object that results from the application of a force over a certain period of time. Impulse is equal to the product of force and the time interval over which the force acts. Mathematically, impulse can be expressed as:

J = FΔt

where J is the impulse, F is the force applied to the object, and Δt is the time interval over which the force acts.

The relationship between impulse and momentum is given by the impulse-momentum theorem, which states that the impulse applied to an object is equal to the change in momentum of the object. Mathematically, the impulse-momentum theorem can be expressed as:

J = Δp

where J is the impulse, and Δp is the change in momentum of the object. This theorem is useful in analyzing collisions and other situations where forces act on objects for a finite period of time.

Here in the Question,

To find the time for which the glider is in contact with the spring, we need to use the impulse-momentum theorem, which relates the impulse (change in momentum) of an object to the force applied to it and the time over which the force is applied:

impulse = force x time = change in momentum

The momentum of the glider before it collides with the spring is:

p1 = m1v1 = (0.500 kg)(0.750 m/s) = 0.375 kg·m/s

The momentum of the glider after it rebounds from the spring is:

p2 = m2v2

We can find v2 from the velocity-time graph in Figure 1. At the moment of maximum compression, the velocity of the glider is zero, so we need to find the time at which this occurs. From the graph, we can see that this occurs at about t = 0.02 s. Therefore, the velocity of the glider after rebounding from the spring is:

v2 = -0.750 m/s

(Note that the negative sign indicates that the glider is moving in the opposite direction after rebounding.)

The change in momentum of the glider is:

Δp = p2 - p1 = m2v2 - m1v1 = (0.500 kg)(-0.750 m/s) - (0.500 kg)(0.750 m/s) = -0.750 kg·m/s

The impulse applied to the glider by the spring is equal in magnitude to the change in momentum:

impulse = Δp = -0.750 kg·m/s

We can find the time for which the force is applied by rearranging the impulse-momentum theorem:

time = impulse/force

We can find the force from the force-time graph in Figure 2. The force at the maximum compression is approximately 4.5 N. Therefore, the time for which the glider is in contact with the spring is:

time = impulse / force = (-0.750 kg·m/s) / (4.5 N) ≈ 0.167 s ≈0.17 s

Therefore, Rounding to two significant figures and including the appropriate units, the time for which the glider is in contact with the spring is approximately 0.17 s.

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Answer:

D. 12.5 min

Explanation:

Speed = distance ÷ time.

time = distance ÷ speed.

18km × 1000m = 18000m (as speed is in m/s).

time = 18000m ÷ 24.0m/s

t = 750s.

750s ÷ 60

= 12.5mins is your answer.

hope this helps. :)

Answer:

The Object will immediately begin moving toward the left

Explanation:

Because the force of thirteen is greater than ten and applied to the opposite side

The products have different arrangement of atoms to the reactants.

Products are substances which are produced from the chemical changes that occur in the substances.

Reactants are the substances which form products as a result of  chemical changes that occur in them.

The reactants and products in a chemical reaction contain the same atoms, but the arrangement of their atoms differs.

Therefore, the products have different arrangement of atoms to the reactants.

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Positive changes in the ball's total energy show that additional energy from outside the system was used to raise the ball and propel it into the basket.

If energy is conserved, the sum of an object's kinetic, gravitational potential, and heat energy—among others—might change forms as it moves about over time.

The ball's kinetic energy and potential energy combine to make its total energy:

E_total = U + K

Its initial potential energy is given by:

U_i = mgh = 2kg x 9.8m/s² x 0m = 0J

The amount of work done is equal to the ball's change in potential energy:

W = U_f - U_i

where U f is the ball's ultimate potential energy.

The ball's final potential energy is determined by:

U_f = mgh = 2kg x 9.8m/s² x 2.5m = 49J

As a result, the ball's work is as follows:

W = U_f - U_i = 49J - 0J = 49J

The ball's final kinetic energy is determined by:

K_f = 0.5mv^2

where v represents the ball's final speed.

Inputting the values provided yields:

K_f = 0.5 x 2kg x (3m/s)² = 9J

As a result, the ball's final total energy is as follows:

E_f = U_f + K_f = 49J + 9J = 58J

The change in total energy of the ball is:

ΔE = E_f - E_i = 58J - 0J = 58J

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Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

The man’s resultant velocity is 4m/s in the north-westerly direction.

According to mathematics, the relative velocity is the vector difference between the velocities of two objects. The difference between the velocities of body A and body B determines the relative velocities between them.

The total of an object's component vector velocities is the resulting vector velocity. The sum of the vector forces acting on an object is equal to the scalar product of its mass and acceleration vector.

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Answer:

Kinetic energy

Explanation:

The swing will have potential energy at all points before the lowest, where it will all be converted to kinetic.

Since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

A negative velocity occurs when an object moves in the negative direction.

Example of negative velocity;

If a car is moving away from you (reference point) then the velocity is positive.

If a car is coming towards you (reference point) then the same vector reverses direction and hence the velocity is negative.

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion. Thus, the acceleration of the object will be negative.

Thus, since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

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Answer:

a)  w = 2.52 10⁷ rad / s, b)  K / K₀ = 1.19 10⁴

Explanation:

a) We can solve this exercise using the conservation of angular momentum.

Initial instant. Before collapse

         L₀ = I₀ w₀

Final moment. After the collapse

         L_f = I w

angular momentum is conserved

        L₀ = L_f

         I₀ w₀ = I w                 (1)

The moment of inertia of a sphere is

        I = 2/5 m r²

we take from the table the mass and diameter of the star

        m = 1,991 10³⁰ kg

        r₀ = 6.96 10⁸ m

        r = 6.37 10⁶ m

to find the angular velocity let's use

       w = L / T

where the length of a circle is

      L = 2π r

      T = 24 days (24 h / 1 day) (3600 s / 1h) = 2.0710⁶ s

we substitute

      w = 2π r / T

      wo = 2π 6.96 10⁸ / 2.07 10⁶

      wo = 2.1126 10³ rad / s

we substitute in equation 1

      w = \(\frac{I_o}{I}\)

      w = 2/5 mr₀² / 2/5 m r² w₀

      w = (\(\frac{r_o}{r}\)) ² wo

      w = (6.96 10⁸ / 6.37 10⁶) ² 2.1126 10³

      w = 2.52 10⁷ rad / s

b) the kinetic energy ratio

      K = ½ m w²

       K₀ = ½ m w₀²

       K = ½ m w²

       K / K₀ = (w / wo) ²

       K / K₀ = 2.52 10⁷ / 2.1126 10³

       K / K₀ = 1.19 10⁴

Answer:

The example of the center of the gravity is the middle of a seesaw

Explanation:

I hope this will help you and plz mark me brainlist

Answer:

1 436 000 000 hrs     163 814 .7 years

Explanation:

40208000000000 km  / 28000 km/hr  =

The Space shuttle's speed is 28,000 km/hr, and the time it will take to get you there is 1436000000 hours or 163814.7 years.

Although Proxima Centauri cannot be seen normally with eyes, it is one of the most famous stars in the sky. This is because it is a member of the Alpha Centauri star system, which is the nearest stellar system to our sun and is home to three known stars.

Proxima, with a distance of 4.22 light-years from our sun, is thought to be the star in Alpha Centauri that is nearest to our sun of the three. For Proxima, astronomers have so far found two planets. It also produces large solar flares, and a strange radio signal may come from it.

According to the question :

The given distance is 4.3 light-years or,

Distance = 40,208,000,000,000 km

Given speed is 28,000 km/hr.

So the time it will take to get you up there is:  Distance/speed

Time = 40,208,000,000,000 km/28,000 km/hr

Time = 1436000000 hours or,

Time = 163814.7 years

Hence, the time taken to get you there will be 163814.7 years.

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If the applied force is 20 N and the displacement is from X=0m to X=5.0m, the work done is 100 Joules.

To determine the work done by a force, you need to know the displacement and the component of the force parallel to the displacement.

In this case, if the force applied is 20 N and the displacement is from X=0m to X=5.0m, you need to determine if the force is parallel to the displacement.

If the force is parallel to the displacement, then the work done is simply the product of the force and the displacement, which is:

Work = Force x Displacement

Work = 20 N x (5.0 m - 0 m)

Work = 100 Joules

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The complete question is below:

What is the work done from X =0m to 5.0m? if the applied force is 20 N

Answer:

slope

Explanation:

The slope is how how steep the line is.

Please delete my answer. I made a mistake

This question involves the concepts of focal length and mirror formula.

The image distance will be "1 cm".

The mirror formula relates the focal length, image distance, and object distance through the following formula:

\(\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\)

where,

Therefore.

\(\frac{1}{1.5\ cm}=\frac{1}{3\ cm}+\frac{1}{q}\\\\\frac{1}{1.5\ cm}-\frac{1}{3\ cm}=\frac{1}{q}\\\\0.667 + 0.333 = \frac{1}{q}\\\\\)

q = 1 cm

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Answer:

The image distance is 3.0 cm

Explanation:

Object distance: 3.0 cm          Focal length: 1.5 cm       Image distance: ? cm

1/f=(1/ do）+（1/di​​​​​​​)

1/1.5=(1/3.0)+(1/x)

(2/3)-(1/3)=1/x

1/3=1/x

x=3.0 cm

The image distance is 3.0 cm.