please help i need to know how to do it, plz tell me how you get it



(4-i)(6-6i)

The bill's price is $9,968.10. The correct answer is option 5

To calculate the price of the Treasury bill, we can use the formula for bank discount yield:

BDY = (Discount / Face Value) * (360 / Days) * 100

Given:

Bank discount yield (BDY) = 1.32%

Days until maturity (Days) = 87

Face Value = $10,000

Let's rearrange the formula to solve for the discount:

Discount = (BDY / 100) * (Face Value) * (Days / 360)

Discount = (1.32 / 100) * $10,000 * (87 / 360)

Discount ≈ $31.9

The price of the Treasury bill can be calculated by subtracting the discount from the face value:

Price = Face Value - Discount

Price = $10,000 - $31.9

Price ≈ $9,968.10

Therefore, the bill's price is approximately $9,968.18.

Among the given answer choices, the correct option price is 5) $9,968.10.

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Answer:

It can go 250 m deep

Step-by-step explanation:

The conversion of a fraction number with denominator 5 and numerator 2 , 2/5 in decimals is equals to the 0.4 value.

A decimal number can be defined as a number whose whole number part and fractional part are separated by a decimal point. Writing 2/5 as a decimal number by converting the denominator to powers of 10. We multiply the numerator and denominator by a number so that the denominator is a power of 10.

2/5 = (2 × 2) / (5 × 2) = 4/10

Now move the decimal point to the left as many places as there are zeros in the denominator, which is a power of 10.

The decimal moved one place to the left because the denominator was 10. Therefore, 4/10 = 0.4. Hence, required value is 0.4.

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Answer:

ok what is thepromblem

Step-by-step explanation:

Answer:

whats up? whats tha questionn :)

Step-by-step explanation:

Answer: Roots are real and distinct

Step-by-step explanation:

a = +ve  b = -ve  c = -ve

determinant = +ve

if determinant is positive then roots are real and distinct

Answer:

J

Step-by-step explanation:

You would need to use distance formula.

Distance formula is

\(Distance = \sqrt{(x_{2}-x_{1} )^2 +(y_{2}-y_{1})^2}\)

You would take the points of X which is (5,6) and insert 5 as \(x_{2}\) and 6 as \(y_{2}\).

And then take the points of Y which is (-5,0) and insert -5 as \(x_{1}\) and 0 as \(y_{1}\).

And then solve for the distance.

Answer:

there is no pic

Step-by-step explanation:

Answer:?

Step-by-step explanation:

?

The values of x are  in between -8 ≤ x ≤ 28.

To describe all x values at a distance of 18 or less from the number 10, we can use the inequality |x - 10| ≤ 18, where || denotes absolute value.                                                                                                                                                          

This inequality tells us that the distance between x and 10 is less than or equal to 18.The solution to this inequality is given by the interval [10 - 18, 10 + 18] or [-8, 28]. Therefore, all x values in the interval [-8, 28] are at a distance of 18 or less from 10.                                                                                                                                                                          Another way to express this interval is as the set of all x values such that 10 - 18 ≤ x ≤ 10 + 18, which can be simplified to  -8 ≤ x ≤ 28.

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All x values at a distance of 18 or less from the number 10 are between -8 and 28.

To describe all x values at a distance of 18 or less from the number 10, we can use absolute value inequality notation.

Let x be the number we are considering. Then we can write the absolute value inequality as:|x - 10| ≤ 18

To solve for x, we can split this inequality into two cases:

1. x - 10 is positive| x - 10 | = x - 10, so the inequality becomes:x - 10 ≤ 18 ⇒ x ≤ 28

So the solution set for this case is: 10 ≤ x ≤ 28.

2. x - 10 is negative| x - 10 | = -(x - 10), so the inequality becomes:- (x - 10) ≤ 18 ⇒ x ≥ -8

So the solution set for this case is: -8 ≤ x ≤ 10.

Combining the solution sets for both cases, we get:-8 ≤ x ≤ 28

Therefore, all x values at a distance of 18 or less from the number 10 are between -8 and 28 inclusive.

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The diameter of cylinder is 2.28 cm and area of wrapper is 60.56π cm².

A cylinder is a three-dimensional solid figure which has two identical circular bases joined by a curved surface at a particular distance from the center which is the height of the cylinder.

Here, Given area of cylinder = 25π cm²

          Height of cylinder = 11 cm.

Now, Area of Cylinder = 2πrh

                  25π = 2πr X 11

                   25 = 22r

                    r = 25 / 22

                  r = 1.14 cm

Then, diameter = 2r = 2 X 1.14 = 2.28 cm

Now area of wrapper = total surface area = 2πr(r + h)

                                    = 2π X 2.28 (2.28 + 11)

                                   = 4.56π X 13.28

                                   = 60.56π cm²

Thus, the diameter of cylinder is 2.28 cm and area of wrapper is 60.56π cm².

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"From a table of integrals, we know that for \(\(a \neq 0\)\) and \(\(b \neq 0\):\)

\(\[\int \cos(at) \, dt = \frac{1}{a} \cdot \cos(at) + \frac{1}{b} \cdot \sin(bt) + C\]\)

and

\(\[\int e^a t \cos(bt) \, dt = \frac{e^{at}}{a} \cdot \cos(bt) + \frac{b}{a^2 + b^2} \cdot \sin(bt) + C\]\)

Use this antiderivative to compute the following improper integral:

\(\[\int_{-\infty}^{0} \cos(3t) \, dt = \lim_{{T \to \infty}} \int_{0}^{T} e^t \cos(3t) \, e^{-st} \, dt = \lim_{{T \to \infty}} \text{ if } s \neq 1, \, \text{ or } \lim_{{T \to \infty}} \text{ if } s = 1.\]\)

For which values of \(\(s\)\) do the limits above exist? In other words, what is the domain of the Laplace transform of \(\(\frac{1}{\cos(3)} \cdot e^t \cos(3t)\)\)?

Evaluate the existing limit to compute the Laplace transform of  on the domain you determined in the previous part:

\(\[L\{e^t \cos(3t)\\).

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Answer:

The resulting function is \(g(x) = \log_{2} (x+5)-4\).

Step-by-step explanation:

Let \(f(x)\) a real function, we define the following function operations:

Horizontal translation

\(g(x) = f(x + a)\) (1)

If \(a > 0\), then horizontal translation is to the left, otherwise it is to the right.

Vertical translation

\(g(x) = f(x) + a\) (2)

If \(a> 0\), then vertical translation is upwards, otherwise it is downwards.

Knowing that \(f(x) = \log_{2}x\) and \(g(x)\) is the result of translating \(f(x)\) four units downwards and five units to the left. Then, we find that:

\(g(x) = \log_{2} (x+5)-4\)

The resulting function is \(g(x) = \log_{2} (x+5)-4\).

The exact value of the area between the graphs y = cos x and y = eˣ is 0.877.

Integration is the process reverse to differentiation. It is a method of adding the parts to get the whole.

The exponential graph goes above the cosine graph. Therefore, the area we are looking for is the difference of the area formed by the exponential graph and the area formed by the cosine graph.

Let A be the required area.

Let A₁ be the area of the graph formed by the cosine function. Then this area is the integral of the cosine function from the limit 0 to 1.

A₁ = \(\int\limits^1_0 {cos x} \, dx\)

    = [sin x]¹₀

Giving the values of the limits, we get

A₁ = sin 1 - sin 0

Now, the value of sin 0 equals  0.

A₁ = sin 1

Let A₂ be the area formed by the graph of exponential function.

A₂ = \(\int\limits^1_0 {e^x} \, dx\)

    = [eˣ]¹₀

    = e¹ - e⁰

    = e - 1 ( Since any value raise to 0 equals 1, e⁰ = 1.

Now, A = A₂ -  A₁

            = e - 1 - sin 1

Value of e equals 2.718 and value of sin 1 equals 0.841

A = 2.718 - 1 - 0.841 = 0.877

Hence the exact value of the area between the graphs y = cos x and y = eˣ is 0.877.

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Answer: 24 millimeters

the length of the other leg is x (x > 0)(millimeters)

using Pythagoras theorem with the right triangle, we have:

x² + 10² = 26²

⇔ x² = 26² - 10² = 576

=> x = 24 (mm)

Step-by-step explanation:

Step-by-step explanation:

(26)^2 = (10)^2 + BC^2

676 = 100 + BC^2

576 =BC^2

BC = 24 mm

Answer:

(0,0)

Step-by-step explanation:

x value of vertex = -b/2a

ax^2+bx+c

-2x^2+0x+0 sinc you have no value of b & c in your quadratic function

-b = 0

2a = (2)(-2)

-b/2a = (0/-4) = 0

x value of the vertex = 0

plug 0 in for all values of x in the function to find y coordinate value

-2(0)^2 = 0

(x,y) = (0,0)

Answer:

m=2

Step-by-step explanation:

(−2,−3);(3,7)

(x1,y1)=(−2,−3)

(x2,y2)=(3,7)

Use the slope formula:

m=y2−y1/x2−x1

=7 − −3/3 − −2

=10/5

=2

Graph:

(-2,-3) is blue

(3,7) is red

Answer:

m=2

Step-by-step explanation:

m=y2-y1/x2-x1

m= 7-(-3)/3-(-2)

m=7+3/3-(-2)

m=10/3-(-2)

m=10/3+2

m=10/5

m=2

Step-by-step explanation:

3. a & d

4. b

5. d

-----------

a. At values of x=1 and x =3 the local maximum and minimum values of g occur

b. The absolute maximum value of g(x) is approximately 0.76 and occurs at x = 4.

c. On the intervals [0, 1) and (3, 4] g concave downward

Since g(x) is defined as the definite integral of f(t) from 0 to x, we can use the First Fundamental Theorem of Calculus to find g'(x) in terms of f(x):

g'(x) = f(x)

Similarly, we can use the Second Fundamental Theorem of Calculus to find g''(x) in terms of f'(x):

g''(x) = f'(x)

(a) The local maximum and minimum values of g occur at critical points of g(x), which are values of x where g'(x) = f(x) = 0 or is undefined. From the graph of f(x), we see that f(x) = 0 at x = 1 and x = 3, so these are possible candidates for critical points of g(x). We also see that f(x) is undefined at x = 2, so this is another possible critical point. Evaluating g'(x) and g''(x) at each of these values, we have:

g'(1) = f(1) = 0, g''(1) = f'(1) < 0, so g(x) has a local maximum at x = 1.

g'(2) is undefined, so x = 2 is not a critical point of g(x).

g'(3) = f(3) = 0, g''(3) = f'(3) > 0, so g(x) has a local minimum at x = 3.

Therefore, the local maximum of g(x) occurs at x = 1, and the local minimum of g(x) occurs at x = 3.

(b) To find the absolute maximum value of g(x), we need to examine the values of g(x) at the endpoints of the interval [0, 4]. We have:

g(0) = 0

g(4) = R 4 0 f(t)dt = the area under the curve of f(x) from x=0 to x=4.

From the graph, we can see that the absolute maximum value of g(x) occurs when x is in the interval [1, 3], so we can evaluate g(x) at the critical points found in part (a) and the endpoints of the interval to find the absolute maximum value of g(x):

g(1) = R 1 0 f(t)dt ≈ 0.72

g(3) = R 3 0 f(t)dt ≈ 0.65

g(4) = R 4 0 f(t)dt ≈ 0.76

Therefore, the absolute maximum value of g(x) is approximately 0.76 and occurs at x = 4.

(c) The function g(x) is concave downward on an interval if its second derivative, g''(x), is negative on that interval. From part (a), we know that g''(x) = f'(x), so we need to find where f'(x) is negative. From the graph of f(x), we can see that f'(x) is negative on the intervals [0, 1) and (3, 4]. Therefore, g(x) is concave downward on the intervals [0, 1) and (3, 4].

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Answer:

5000

ghsjdjdjdjdjdjdjdkdkdkdkdkdkdkdk

The given function is

First, we make x = 0.

Second, we make g(x) = 0.

Third, we graph the points (0, 4) and (-16, 0).

At last, we draw the line through the points to get the line.

Answer:

-20

Step-by-step explanation:

-20

g(4) = 1 * g(4), which means that q(4) is equal to g(4). y(-4) = f(-4) * h(-4) = 1 * (-4) = -4. Therefore, the values of q(4), y(-4), and y(4) are determined as follows: q(4) = g(4), y(-4) = -4, and y(4) = 0.

For the first part of the problem, we are given f(t) = u(t), g(t) = 2tu(t), and g(t) = f(t - 1) * g(t). To determine q(4), we need to substitute t = 4 into the equation g(t) = f(t - 1) * g(t). This gives us g(4) = f(3) * g(4). Since f(t) = u(t), we know that f(3) = u(3) = 1 because u(t) is a unit step function that equals 1 for t ≥ 0. Therefore, we have g(4) = 1 * g(4), which means that q(4) is equal to g(4).

For the second part of the problem, we are given f(t) = u(-t), h(t) = tu(-t), and y(t) = f(t) * h(t). To determine y(-4) and y(4), we substitute t = -4 and t = 4 into the equation y(t) = f(t) * h(t). For y(-4), we have y(-4) = f(-4) * h(-4). Since f(t) = u(-t), we have f(-4) = u(4) = 1 because u(t) is a unit step function that equals 1 for t ≥ 0. Similarly, h(-4) = -4u(4) = -4. Therefore, y(-4) = f(-4) * h(-4) = 1 * (-4) = -4.

Similarly, for y(4), we have y(4) = f(4) * h(4). Since f(t) = u(-t), we have f(4) = u(-4) = 0 because u(t) is a unit step function that equals 0 for t < 0. Thus, y(4) = f(4) * h(4) = 0 * h(4) = 0.

Therefore, the values of q(4), y(-4), and y(4) are determined as follows: q(4) = g(4), y(-4) = -4, and y(4) = 0.

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Answer:

Option C

Step-by-step explanation:

\(y = x(x -6)(x +1)(x+3)\)

There are four expressions in the above equation, which are multiplying with each other:

1. \(x\)

2. \((x -6)\)

3. \((x + 1)\)

4. \((x + 3)\)

The values of x (for which zero y values are obtained) are determined when setting each of the above mentioned expressions equal to 0:

1. \(x = 0\)

∴x = 0

2. \((x - 6) = 0\)

 ∴x = 6

3. \((x + 1) = 0\)

∴x = \(-1\)

4. \((x + 3) = 0\)

∴ x = \(-3\)

∴The function have zeros at -3, -1, 0 and 6

Function in option C represent the above mentioned characteristics.

a. The initial height of the baseball is 6 feet.

b. It takes 15/16 seconds for the ball to reach its maximum height.

c. The maximum height of the ball is approximately 20.25 feet.

a. The initial height of the baseball can be found by evaluating the height function h(t) when t=0.

Plugging in t=0 into the equation h = -16t² + 30t + 6, we get h = -16(0)² + 30(0) + 6, which simplifies to h = 6 feet.

b. To find the time it takes for the ball to reach its maximum height, we need to find the vertex of the parabolic function.

The time at which the maximum height occurs can be found using the formula t = -b/(2a) where a = -16 and b = 30.

So, t = -(30)/(2*(-16)) = 30/32 = 15/16 seconds.

c. To find the maximum height, plug the value of t from the previous step into the height function h(t): h = -16(15/16)² + 30(15/16) + 6.

This results in h ≈ 20.25 feet.

So, the ball's maximum height is approximately 20.25 feet.

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Answer:

15,999,999,995

Step-by-step explanation:

16 billion - 5 = 15,999,999,995

Answer:

2 733.25 + 7270 = 10 003.25

Step-by-step explanation:

192 * 36 = 6 912 +358 = 7 270

45425 - 36000 ( allowed miles for 3 years )

9 425 * 0.29 = 2 733.25

Answer: 1) 4 1/12

2) 3 11/15

Step-by-step explanation:

Answer:

31.4 in

Step-by-step explanation:

the formula for circumference is 2*\(\pi\)*radius. Since the diameter (which is the radius multiplied by 2) is labeled we can divide 10 by 2 to get the radius. 10/2 is 5. Since pi is an infinite number, we round it to 3.14. Then, plug in the numbers. The expression will be 2*3.14*5. 2* = 10 and 10 * 3.14 you can just move the decimal so the answer is 31.4.