PLEASE HELP!!! i think it’s HL But idk

Answer: its A

Step-by-step explanation:

Answer:

the answer is

13 / 40 = 32.5%

Answer:

18.0625 ft

Step-by-step explanation:

Greatest height is when:

t = -b/2a

t = -30/2(-16)

t = 15/16

Greatest height is:

-16t(15/16)² + 30(15/16) + 4 = 289/16

= 18.0625m

Answer:

no

Step-by-step explanation:

8.2x3=24.6

24.6 < 26.2, so no

The limit does not exist (denoted as DNE). The given limit is lim\((2^(12²-1))^(1/√r-1)\) as r approaches 1.

To evaluate this limit, we can simplify the expression.

In the exponent, 12² - 1 equals 143, and the base is 2. Therefore, we have \((2^143).\)

In the denominator, √r - 1 is a square root expression, and as r approaches 1, the denominator becomes √1 - 1 = 0.

Since we have the form 0^0, which is an indeterminate form, we need to further analyze the expression.

We can rewrite the original expression as \(e^(ln(2^143) / √r-1).\)

Using the properties of logarithms, we can simplify ln\((2^143)\) to 143 * ln(2).

Now, the expression becomes \(e^(143 * ln(2) / √r-1).\)

As r approaches 1, the denominator approaches 0, and the expression becomes \(e^(143 * ln(2) / 0).\)

Since the denominator is approaching 0, we have an indeterminate form of the type ∞/0.

To evaluate this limit, we need additional information or techniques. Without further clarification or specific instructions, we cannot determine the exact value of this limit.

Therefore, the limit does not exist (denoted as DNE).

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Answer:

ディクビッチを吸う?

Step-by-step explanation:

The answer is:

\(\large\textbf{They aren't equivalent.}}\)

In-depth explanation:

To determine the answer to this problem, we will use one of the exponent properties:

\(\sf{x^{-m}=\dfrac{1}{x^m}}\)

And

\(\sf{\dfrac{1}{x^{-m}}=x^m}\)

Now we apply this to the problem.

What is 4⁻³ equal to? Well according to the property, it's equal to:

\(\sf{4^{-3}=\dfrac{1}{4^3}}\)

And this question asks us if 4⁻³ is the same as 1/4⁻3.

Well according to the calculations performed above, they're not equivalent.

The required amount that Ethan have to pay is $32.

A sales discount is a marked down cost presented by a business on an item or administration. Figure out how to remember limits for solicitations. A deals rebate, likewise usually known as only a 'markdown' furnishes clients of a business with a diminished rate on at least one of the items or administrations being advertised.

We have,

Selling price = $39.99

Discount = 20%

20% of $39.99 = 20×$39.99/100

⇒ $7.99

So the payable amount for video game = $39.99 - $7.99

⇒ $32

Thus, required price is $32.

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Answer:

-4ctv² + 10xyz - 9

Step-by-step explanation:

(2 + 5xyz - 6tv²c) - (11 - 5yxz - 2ctv²)

2 + 5xyz - 6tv²c - 11 + 5yxz + 2ctv²

-4ctv² + 10xyz - 9

I hope this helps!

program in 'C' language to solve the boundary value problem

#include <stdio.h>

#include <math.h>

#define F(X,Y,Z) (X*Z+2*Y) // Function

#define H 0.25 // Step size

void main() {

 float x, y, z, k1, k2, k3, k4;

 int i;

 x = 0;

 y = 1;

 z = 0.45; // Assume value of y'(0)

 do {

   printf("x=%f, y=%f, z=%f\n", x, y, z);

   k1 = z;

   k2 = z + H * k1 / 2.0;

   k3 = z + H * k2 / 2.0;

   k4 = z + H * k3;

   z += (k1 + 2 * k2 + 2 * k3 + k4) / 6.0;

   k1 = F(x, y, z);

   k2 = F(x + H / 2.0, y + H * k1 / 2.0, z + H * k1 / 2.0);

   k3 = F(x + H / 2.0, y + H * k2 / 2.0, z + H * k2 / 2.0);

   k4 = F(x + H, y + H * k3, z + H * k3);

   y += (k1 + 2 * k2 + 2 * k3 + k4) / 6.0;

   x += H;

 } while (x <= 1.0);

 printf("x=%f, y=%f\n", x, y);

 if (fabs(y - 1.271) <= 150)

   printf("Error is within the given limit.");

 else

   printf("Error is not within the given limit.");

}

You can compile and run the above program using any C compiler of your choice.

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Answer:

C - 6 < = 5.3

Step-by-step explanation:

Writing the above as an equality, we would have ;

Since C is less than 6, then;

C - 6

Therefore, C minus 6 is less than or equal to 5.3 is

C - 6 < = 5.3

An inequality is when an unequal relationship exist between two expressions, which uses signs such as not equal to , less than < , greater than > etc.

Answer:

31

Step-by-step explanation:

Increases by 7 each time

its 31 bc 24 plus 7 is 31............

A rank 6 approximation of matrix A would only require us to store 1692 values.

To find the number of values needed to store a rank 6 approximation of the matrix A, we need to consider the formula for the rank-k approximation of a matrix:

A_k = U_k * Sigma_k * V_k^T

where U_k is a matrix of size m x k, Sigma_k is a diagonal matrix of size k x k, and V_k is a matrix of size n x k.

For a rank 6 approximation, we only need to keep the first 6 columns of U and V, and the first 6 diagonal entries of Sigma.

The number of values needed to store U_k and V_k is:

43 x 6 + 85 x 6 = 828

The number of values needed to store Sigma_k is:

6 x 6 = 36

Therefore, the total number of values needed to store a rank 6 approximation of matrix A is:

828 + 36 + 828 = 1692

So, a rank 6 approximation of matrix A would only require us to store 1692 values, which is much less than the 3655 values needed to store the full matrix.

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Answer:

The answer assumes that the density of glass is 3 g/cm^3, not 3 g/cm^2.

The mass of the paperweight is 270 grams.

Step-by-step explanation:

Lets calculate the volume of a sphere having a radius of 3.5cm, and then divide that by 2 to get the volume of the hemisphere (half a sphere).  The sphere has a diameter of 7cm (therefore, a radius of 3.5cm).

Vol (sphere) = (4/3)πr^3

Vol = (4/3)(3.14)(3.5cm)^3

Vol = 180 cm^3

Half of this (the hemisphere) will be 90 cm^3

We know the volume, and we know the density of glass (3 g/cm^3), so multiply the two to obtain the mass of the paperweight.

 (90 cm^3)*(3g/cm^3) = 270 grams

Answer:

50

Step-by-step explanation:

The sum of the measures of the interior angles of a triangle is 180°.

x - 10 + 2x + 5 + 35 = 180

3x + 30 = 180

3x = 150

x = 50

we calculate the interest for 8 years

here principal is P = 800 $

time T= 8 yr

Rate R = 11 %

interest will be

so the interest is 704$

now he will pay

principal + interest = 800 + 704 =1504 $

so the answer is 1504 $.

Answer:

60.89 lbs.

Step-by-step explanation:

(362) x (4/9)

= 1448/9

= 160 8/9 = 60.89 lbs of canned goods

Answer:

58to20meters a pear of a day

Step-by-step explanation:

1hu2ji

The unit cost of pears is $1.50 per pound.

Ratio basically compares quantities, that means it show value of one quantity with respect to other quantity.

If a and b are two values, their ratio will be a:b,

Given that,

Cost for 1/3 lb of pears = $0.50

Since, 1 lb = 1 pound

Implies that,

Cost of 1/3 pounds of pears = $0.50

To find the cost of one pound of pears,

Use ratio property,

1/3 pound costs = 0.50

1 pound costs = 0.50 x 3 = $1.50

The cost of one pound of pear is $1,.50.

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Answer:

B; the angles of the triangle and the hypothnuse can be multiplied.

Answer: 4(5+3) = 4(5) + 4(3) = 20 + 12 = 32

Step-by-step explanation:

Answer:

32=32 ?

Step-by-step explanation:

The length of BD is 53 units.

We are given here that BD is (8x - 27) units and EC is (2x + 33) units. BD and EC are the diagonals of a trapezoid. As we know that diagonals of a trapezoid are equal. Therefore, we will equate the given diagonals of a trapezoid.

BD  =  EC

Substituting the given values of BD and EC

8x - 27  =  2x + 33

combining the like terms

8x - 2x  =  33 + 27

6x  =  60

x = 60/6

x = 10

Now, as we have to find BD, we will substitute the value of x in the given equation for BD.

BD = 8x - 27

BD = 8(10) - 27

BD = 80 - 27

BD = 53

Therefore, BD is 53 units.

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The complete question is " If BD = 8x - 27 and EC-2x + 33, find BD​ with respect to the image shown."

average rate of change from 4 to 9 minutes is 2.25 min . division of the y-value change by the x-value change.

It represents the average change in the function's per-unit value during that time period. On the function's graph, it is generated from the slope of the line connecting the interval's ends.

the difference between the y- and x-values is divided. Calculating the average rate of change is very helpful for tracking changes in measurable parameters like average speed or average velocity.

Given that

the change in y value occurred in 9 minutes and the change in x value occurred in 4 minutes, the average rate of change was 9 minutes by 4 minutes, or2.25 minutes.

9 min / 4 min

= 2.25 min

average rate of change from 4 to 9 minutes is 2.25 min . division of the y-value change by the x-value change.

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The answer is H0: At the 10% significance level, we conclude that the CFA designation is more lucrative than an MBA.

a. Set up the hypotheses to test if a CFA designation is more lucrative than an MBA at the 10% significance level.

The null hypothesis is: H0: μ1 ≤ μ2

The alternative hypothesis is: H1: μ1 > μ2So, the answer is (c) H0: μ1 − μ2 ≤ 0; HA: μ1 − μ2 > 0. b-1. Calculate the value of the test statistic.

The formula to find the test statistic is given by,

\[{\rm{T}} = \frac{{\left( {{\overline X _1} - {\overline X _2}} \right) - \left( {{\mu _1} - {\mu _2}} \right)}}{{\sqrt {\frac{{{\rm{s_1}^2}}}{n} + \frac{{{\rm{s_2}^2}}}{n}} }}\]Substituting the given values,\[{\rm{T}} = \frac{{\left( {146 - 133} \right) - \left( 0 \right)}}{{\sqrt {\frac{{{{\left( {53} \right)}^2}}}{41} + \frac{{{{\left( {26} \right)}^2}}}{52}} }} = 2.417\]

So, the value of the test statistic is 2.417.b-2. Find the p-value.

We need to find the p-value for a one-tailed test at a 10% significance level.

Since the alternative hypothesis is μ1 > μ2, the p-value is the area to the right of the test statistic.

Using a t-distribution table with 91 degrees of freedom (rounded to the nearest integer), we get the p-value as 0.010.

Since the p-value is less than the significance level, we reject the null hypothesis and conclude that the CFA designation is more lucrative than an MBA.

Therefore, the answer is H0: At the 10% significance level, we conclude that the CFA designation is more lucrative than an MBA.

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An equivalent  is the amount of a substance that reacts with  an arbitrary amount of another substance in a given chemical reaction.

Arbitrary

It is a relative unit of measurement to show the ratio of amount of substance, intensity, or other quantities, to a predetermined reference measurement.

chemical reaction

chemical reaction is a process in which one or more substances, the reactants, are converted to one or more different substances, the products. Substances are either chemical elements or compounds.

Examples of chemical changes include baking soda and vinegar creating carbon dioxide, iron rusting, and wood burning.

There are five types of general chemical reactions: Combination or synthesis, decomposition, single displacement, double displacement, and combustion.

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The first four terms and the 10th term of each sequence is given as follows:

a) n + 4:

b) 3n - 1:

To find the numeric value of a function or of an expression, we replace each instance of the variable in the function or in the expression by the value at which we want to find the numeric value.

The sequences are defined as follows:

Hence the first term of a(n) is given as follows:

a(1) = 1 + 4 = 5.

The tenth term of b(n) is given as follows:

b(10) = 3(10) - 1 = 30 - 1 = 29.

The same procedure is applied to find the remaining terms.

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The correct answer is option B. Rewrite sin °x as (1 - cos 2x) sinx, then use the substitution u = cos x.

What is sine?

Sine is a trigonometric function that relates the ratio of the length of the side opposite an angle in a right triangle to the length of the hypotenuse. In a right triangle, the sine of an angle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse.

Mathematically, the sine function is denoted as sin(x), where x is the angle. The sine function takes an angle in radians as its input and returns the corresponding sine value.

By using the identity \(sin^2(x) + cos^2(x) = 1\), we can rewrite sin °x as (1 - cos 2x) sinx.

Then, we can make the substitution u = cos x, which allows us to express the integral in terms of u. This substitution simplifies the integral and makes it easier to evaluate.

Therefore, the correct method to integrate sin °x is to rewrite it as (1 - cos 2x) sinx and then use the substitution u = cos x.

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