PLEASE HELP I WILL MARK BRAINLIEST

Answer:

3000

Step-by-step explanation:

Answer:

80 kg

Step-by-step explanation:

To find the mass of the skater, you can use the formula for centripetal force:

F_centripetal = m * v^2 / r

Where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.

Plugging in the values you know, you get:

720 N = m * (15 m/s)^2 / 25 m

Solving for m, you find that the mass of the skater is:

m = 720 N * 25 m / (15 m/s)^2

= 720 N * 25 m / 225 m^2/s^2

= 80 kg

So the mass of the skater is approximately 80 kilograms.

Answer

32

Step-by-step explanation:

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Answer:

2 ?

Step-by-step explanation:

Step-by-step explanation:

Simply graph the two equations....the intersection of the two graphs is the solution

Answer:8758125

Step-by-step explanation:

In both the triangles,

three sides are congruent,

so,

the two triangles are related by side -side -side , so the triangles can be proven congruent .

Step-by-step explanation:

8x + 3y = 7 --------(1)

2x + y = 2 ----------(2)

y = 2 – 2x ---------(3)

just substitute for y in equation (1)

8x + 3(2–2x) = 7

8x + 6 – 6x = 7

8x – 6x + 6 = 7

2x = 7 – 6

2x = 1

x = ½

since x = ½ just substitute for x in equation(3)

y = 2 – 2x

y = 2 – 2(½)

y = 2 – 1

y = 1

so x = ½,y = 1

i hope this helped

Answer:

b=sqrt7

Step-by-step explanation:

16=9+b^2

Answer:

aszdxcfgvhbjnk

Step-by-step explanation:

Answer: 1. 64 | 2. 32

Step-by-step explanation:

Formula for a rectangle is Area = Length*Width

Therefore: 8*8 = 64

Formula for a triangle is Area = 1/2*Base*Height, which is also 1/2*length*width

Therefore: 1/2*8*8 = 32

Hope this helps :)

\(\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(49)=y\implies \log_{10}(49)=y\implies 1.690196\approx y \\\\\\ \log_{10}(49)\approx 1.690196\implies \stackrel{\textit{then we can say}}{10^{1.690196}\approx 49}\)

The probability that the trade balance is greater than 0 is 1 - 0.1056 = 0.8944, or 89.44%.

Here is the breakdown-

The probability that the trade balance is greater than 0 can be determined using the given information.

To solve this, we need to find the probability that exports minus imports is greater than 0.

Let's denote X as exports and Y as imports. The trade balance is defined as X - Y.

To find the probability that the trade balance is greater than 0, we need to find the probability that X - Y > 0.

We know that the correlation between exports and imports is +0.70.

Using this information, we can calculate the covariance of X and Y as:

Cov(X, Y) = correlation * standard deviation of X * standard deviation of Y

\(Cov(X, Y) = 0.70 * sqrt(900) * sqrt(625)\)

= 0.70 * 30 * 25

= 525

Now, we can calculate the standard deviation of the trade balance as:

Standard deviation of trade balance = sqrt(variance of X + variance of Y - 2 * Cov(X, Y))

Standard deviation of trade balance = sqrt(900 + 625 - 2 * 525)

= sqrt(400)

= 20

Now, we can standardize the trade balance by subtracting the mean of the trade balance and dividing by the standard deviation:

Z = (trade balance - mean of trade balance) / standard deviation of trade balance

Z = (0 - (100 - 125)) / 20

= -25 / 20

= -1.25

Finally, we can find the probability that the trade balance is greater than 0 by finding the area under the standard normal distribution curve to the right of Z = -1.25:

Probability = 1 - cumulative distribution function (CDF) of Z at -1.25

Using a standard normal distribution table or calculator, we find that the CDF at -1.25 is approximately 0.1056.

Therefore, the probability that the trade balance is greater than 0 is 1 - 0.1056 = 0.8944, or 89.44%.

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except for letter a. LIZM

There is a 20% chance that you made a Type II error in your study with an alpha value of 0.05 and a power of 80%. This means that there is a 20% chance that you failed to detect a true effect or relationship in the population.

To calculate the chance of making a Type II error, we need to understand what Type II error is and how it relates to the alpha value and power of a study.

Type II error, also known as a false negative, occurs when we fail to reject the null hypothesis when it is actually false. In other words, it means we incorrectly conclude that there is no effect or relationship in the population, even though there is one.

The power of a study represents the probability of correctly rejecting the null hypothesis when it is indeed false. It is directly related to the probability of making a Type II error. Therefore, the chance of making a Type II error is equal to 1 minus the power of the study.

Given that the power of the study is 80% (or 0.80), the chance of making a Type II error can be calculated as follows:

Chance of making a Type II error = 1 - Power of the study
                                = 1 - 0.80
                                = 0.20 or 20%

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Answer:

25 cm

Step-by-step explanation:

19*2 = 38

88-38=50

50/2=25

Answer:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x. x= i, −i, 3,−2

Step-by-step explanation:

Answer:

\((x-3)({x}^{2}+1)(x+2)\)

Step-by-step explanation:

1) Factor \(x^4 - x^3 - 5x^2 - x - 6\) using Polynomial Division.

1 - Factor the following.

\(x^4 - x^3 - 5x^2 - x - 6\)

2 - First, find all factors of the constant term 6.

\(1, 2, 3, 6\)

3 - Try each factor above using the Remainder Theorem.

Substitute 1 into x. Since the result is not 0, x-1 is not a factor..

\(1^4 - 1^3 - 5 * 1^2 - 1 - 6 = - 12\)

Substitute -1 into x. Since the result is not 0, x+1 is not a factor..

\(( - 1 ) ^ 4 - ( - 1 ) ^ 3 - 5 ( - 1 ) ^ 2 + 1 - 6 = - 8\)

Substitute 2 into x. Since the result is not 0, x-2 is not a factor..

\({2}^{4}-{2}^{3}-5\times {2}^{2}-2-6 = -20\)

Substitute -2 into x. Since the result is 0, x+2 is a factor..

\({(-2)}^{4}-{(-2)}^{3}-5{(-2)}^{2}+2-6 = 0\)

⇒ \(x+2\)

4 - Polynomial Division: Divide \({x}^{4}-{x}^{3}-5{x}^{2}-x-6\) by \(x+2\)

                                        \(x^3\)                \(-3x^2\)              \(x\)           \(-3\)

                                            --------------------------------------------------------------

\(x+2\)                                    |   \(x^4\)        \(-x^3\)               \(-5x^2\)     \(-x\)           \(-6\)

                                                  \(x^4\)         \(2x^3\)

                                                 ------------------------------------------------------------

                                               \(-3x^3\)         \(-5x^2\)          \(-x\)              \(-6\)

                                                 \(-3x^3\)       \(-6x^2\)

                                                   ---------------------------------------

                                                    \(-3x\)         \(-6\)

                                                       \(-3x\)      \(-6\)

                                                       ---------------

5 - Rewrite the expression using the above.

\({x}^{3}-3{x}^{2}+x-3\)

2) Factor out common terms in the first two terms, then in the last two terms.

\(({x}^{2}(x-3)+(x-3))(x+2)\)

3) Factor out the common term \(x-3\).

\((x-3)({x}^{2}+1)(x+2)\)

Answer:

1.25

Step-by-step explanation:

adding a positive to a negative it would go down to 1.25

Answer:

I'm pretty sure its 80°

Step-by-step explanation:

One possible half-angle identity that can be used to solve this problem is: tan (θ/2) = sin θ / (1 + cos θ)

We can apply this identity by letting θ = 5π/6, since 5π/12 is half of that angle. Therefore:
tan (5π/12) = tan [(1/2) * (5π/6)]
Using the half-angle identity, we have:
tan (5π/12) = sin (5π/6) / [1 + cos (5π/6)]
Now we need to find the values of sin (5π/6) and cos (5π/6). To do that, we can use the fact that sin (π - x) = sin x and cos (π - x) = -cos x. Therefore:
sin (5π/6) = sin [π - (π/6)] = sin (π/6) = 1/2
cos (5π/6) = -cos (π/6) = -(√3/2)
Substituting these values back into the half-angle identity, we get:
tan (5π/12) = (1/2) / [1 - (√3/2)]
To simplify this expression, we can use the difference of squares formula:
a² - b² = (a + b)(a - b)
By letting a = 1 and b = (√3/2), we get:
1 - (√3/2)² = 1 - 3/4 = 1/4
Therefore:
tan (5π/12) = (1/2) / [1 - (√3/2)] = (1/2) * (1 / [1 - (√3/2)]) * [(1 + (√3/2)) / (1 + (√3/2))] = (1 + √3) / (2 - √3)
This is the exact value of tan (5π/12) in simplified form.

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Answer:

1:3

Step-by-step explanation:

3:12 is the amount of shaded circles to all circles, 8:2 is basically the same thing as 3:12 and 9:3 is the amount of shaded circles to the amount of non-shaded circles.  1:3 wouldn't work because it is not the right ratio.

Answer:

\(68 = 2 \times 2 \times 17\)

To calculate the annualized rate of return, we can use the formula for compound interest. The correct answer is 11.66%.

The formula for compound interest is given by: A = P(1 + r)^t, where A is the final amount, P is the principal amount, r is the annual interest rate, and t is the time in years.

In this case, the initial investment (P) is BD 14,000, the final amount (A) is BD 52,600, and the time (t) is 12 years. We need to solve for the annual interest rate (r).

\(BD 52,600 = BD 14,000(1 + r)^{12}\)

By rearranging the equation and solving for r, we find:

\((1 + r)^{12} = 52,600/14,000\)

Taking the twelfth root of both sides:

\(1 + r = (52,600/14,000)^{(1/12)}\\r = 0.1166 / 11.66 \%\)

Therefore, Areej has earned an annualized rate of approximately 11.66% on this investment.

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These are the solutions to the quadratic equation p^2 + 2p^2 - 5 * 2p + 5 = 0.

To solve the quadratic equation p^2 + 2p^2 - 5 * 2p + 5 = 0, we need to simplify and rearrange the equation to its standard form and then solve for p.

Combining like terms, the equation becomes:

3p^2 - 10p + 5 = 0

Now, we can use the quadratic formula to solve for p. The quadratic formula states:

p = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 3, b = -10, and c = 5. Substituting these values into the quadratic formula, we have:

p = (-(-10) ± √((-10)^2 - 4 * 3 * 5)) / (2 * 3)

Simplifying further:

p = (10 ± √(100 - 60)) / 6

p = (10 ± √40) / 6

p = (10 ± 2√10) / 6

Now, we can simplify and find the two possible values of p:

p₁ = (10 + 2√10) / 6

p₂ = (10 - 2√10) / 6

These are the solutions to the quadratic equation p^2 + 2p^2 - 5 * 2p + 5 = 0.

In simplified form, the solutions are:

p₁ = (5 + √10) / 3

p₂ = (5 - √10) / 3

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There is no absolute value function when graphed, will be wider than the graph of the parent function f(x) = |x|

An absolute value function is a function such that,

\(|x|=-1 when x\geq 0 and |x|=1 when x\leq 0\)

For the given example,

We have been given a parent function f(x) = |x|

We need to find the absolute value function, when graphed, will be wider than the graph of the parent function.

Consider the graph of all absolute value functions.

The graph of f(x) = |x| + 3 is represented blue color.

The graph of f(x) = |x − 6| is represented green color.

The graph of f(x) = |x| is represented red color.

The graph of f(x) = 9|x| is represented violet color.

From this graph, we can observe that,

f(x) = |x| + 3 is as wise as the parent absolute value function f(x) = |x| translated up by 3 units.

Similarly, the function f(x) = |x - 6| is as wise as the parent absolute value function f(x) = |x| translated right by 6 units.

This means, there is no absolute value function when graphed, which will be wider than the graph of the parent function f(x) = |x|

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Answer:

I believe the answer is C. F(x)= 1/3|x|

Step-by-step explanation:

i hope this helps.

The missing quantities are 0.04 units of wood, 0.4 units of paper, and 0.6 units of paper.

To fill in the missing quantities, we can use the technology matrix A and the formula A = [a11 a12; a21 a22], where a11 is the amount of sector 1 used in the production of one unit of sector 1, a12 is the amount of sector 2 used in the production of one unit of sector 1, a21 is the amount of sector 1 used in the production of one unit of sector 2, and a22 is the amount of sector 2 used in the production of one unit of sector 2.

Using this formula, we can fill in the missing quantities as follows:

(a) The amount of wood (sector 2) needed to produce one unit of paper (sector 1) is a12, which is 0.04 units of wood.

(b) The amount of paper (sector 1) used in the production of one unit of paper (sector 1) is a11, which is 0.4 units of paper.

(c) The production of each unit of wood (sector 2) requires the use of a21 units of paper (sector 1), which is 0.6 units of paper.

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Sam had 3 times as much money as James. After spending  $38 on a pair of shoes, now Sam has $256.

To translate a math word problem into equations, assign the unknowns to variables.

Let:

s = the amount of Sam's money

j = the amount of James' money

"Sam and James saved $392 altogether"  can be translated into:

s + j = 392  (Equation 1)

Sam had 3 times as much money as James, means:

s = 3j  (Equation 2)

Substitute equation 2 into equation 1

s + j = 392

3j + j = 392

4j =  392

j =  392 /4 = 98

Hence,

Sam's money before he bought shoes"

s = 3j = 3 x 98 = $294

After Sam bought a pair of shoes, his remaining money:

= $294  - $38 = $256

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i. To find the component form of the vector AB, we subtract the coordinates of A from the coordinates of B:
AB = <52 - 12, 33 - 41> = <40, -8>
To find the magnitude of the vector AB, we use the formula:
|AB| = sqrt((40)^2 + (-8)^2) = sqrt(1600 + 64) = sqrt(1664) ≈ 40.79

ii. Similarly, we find the component form of AB:
AB = <12 - 8, 3 - 14> = <4, -11>
And the magnitude of AB:
|AB| = sqrt((4)^2 + (-11)^2) = sqrt(157) ≈ 12.53

iii. To find the component form of AB in 3D space, we subtract the coordinates of A from the coordinates of B:
AB = <8 - 9, 5 - (-2), 11 - 5> = <-1, 7, 6>
To find the magnitude of AB, we use the formula:
|AB| = sqrt((-1)^2 + (7)^2 + (6)^2) = sqrt(86) ≈ 9.27

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The critical points of the function y = 49y - y³ are y = 7/√3 (local maximum) and y = -7/√3 (local minimum).

To find the critical points of the function y = f(x) = 49y - y³, we need to find the values of y where the derivative dy/dx is equal to zero or undefined.

To find where the derivative is undefined, we need to look for any values of y where the denominator of the derivative, dx/dy, is equal to zero. However, in this case, the derivative is given as dy/dx, so we first need to find the derivative with respect to y:

f(y) = 49y - y³

f'(y) = 49 - 3y²

Now, we can set f'(y) equal to zero and solve for y to find where the derivative is equal to zero:

49 - 3y² = 0

3y² = 49

y² = 49/3

y = ±(7/√3)

So the critical points of the function occur at y = 7/√3 and y = -7/√3.

To determine whether these critical points correspond to local maximum or minimum points, we need to use the second derivative test. Taking the second derivative of f(y), we get:

f''(y) = -6y

Plugging in y = 7/√3, we get:

f''(7/√3) = -6(7/√3) < 0

Therefore, y = 7/√3 corresponds to a local maximum.

Plugging in y = -7/√3, we get:

f''(-7/√3) = -6(-7/√3) > 0

Therefore, y = -7/√3 corresponds to a local minimum.

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