Answers
Explanation:
The answer is (C) \(^{111}_{\:40}\text{Zr}\)
Related Questions
A particle changed q= 3,10x10^-6 C stays still on point P, a second particle with the same value q and a mass of 1,80x10^-2 kg is initially in repose at a distance of r1 = 9,00 cm from point P. This is second particle is released and repelled by the first. Determine the velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P.
note 1: from what i know i have to use the potential energy formula (U= mV^2/2), and possible calculate the electric force ? but from there i get lost
note 2: sorry if this isn't grammatically correct, i translated it from spanish
Answers
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is 17.22 m/s.
What is the electric force between the two particles?The electric force between the two particles is calculated from Coulomb's law of electrostatic force.
F = kq₁q₂/r²
where;
k is Coulomb's constantq₁ is magnitude of first chargeq₂ is magnitude of second charger is the distance between the two chargesF = (9 x 10⁹ x 3.10 x 10⁻⁶ x 3.10 x 10⁻⁶) / (0.09 m)²
F = 10.68 N
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is calculated by applying the principle of conservation of energy.
W = ΔK.E
where;
W is work doneΔK.E is kinetic energy of the particleFr = ¹/₂mv²
2Fr = mv²
v² = 2Fr/m
v = √(2Fr/m)
v = √(2 x 10.68 x 0.25 / 1.8 x 10⁻²)
v = 17.22 m/s
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Nate the Skate was an avid physics student whose main non-physics interest in life was high-speed skateboarding. In particular,
Nate would often don a protective suit of Bounce-Tex, which he invented, and after working up a high speed on his skateboard,
would collide with some object. In this way, he got a gut feel for the physical properties of collisions and succeeded in
combining his two passions.* On one occasion, the Skate, with a mass of 117 kg, including his armor, hurled himself against a
879 kg stationary statue of Isaac Newton in a perfectly elastic linear collision. As a result, Isaac started moving at 1.63 m/s and
Nate bounced backward.
What were Nate's speeds immediately before and after the collision? (Enter positive numbers). Ignore friction with the ground.
Answers
Answer:
Explanation:
The statue, being initially at rest, will move off at twice the velocity of the center of mass of the Skate-Statue system
The CM velocity is 1.63/2 = 0.815 m/s
so the Skates initial velocity can be found
(117 + 879)(0.815) = 879(0) + 117u
u = 6.93794...
|u| = 6.94 m/s
for elastic collisions, the relative velocity of approach will equal the relative velocity of departure.
Approach velocity 6.94 m/s
Skate's departure velocity 1.63 - 6.94 = - 5.31 m/s
|v| = 5.31 m/s
Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.
Answers
The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.
How to find displacement ratio?To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:
d = vt + 1/2at²
where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.
Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.
Assume that the time at which they meet is t, then:
d₁ = 1/2 * 2.4t²
And the equation for the displacement of the second body:
d₂ = 1/2 * 4.8t²
If d₁ = d₂
then, 1/2 * 2.4t² = 1/2 * 4.8t²
Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2
So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.
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When potential energy is converted into Kinetic energy, some of that kinetic energy is always in the form of
chemical energy
nuclear energy
thermal theat) energy
electromagnetic light) energy
Answers
Answer: thermal energy
Explanation: Thermal energy is the conversion of kinetic energy
When potential energy is converted into Kinetic energy, some of that kinetic energy is always in the form of thermal heat energy.therefore the correct option is C.
What is mechanical energy?The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.
The expression for total mechanical energy can be given as follows
ME= PE + KE
Because all the kinetic and potential energy that is present in the system is added together to form total mechanical energy. Any object or body that moves at any speed has kinetic energy inherent to it; nevertheless, some of this kinetic energy is constantly transformed into thermal energy due to friction.
Hence, we can say that when potential energy is converted into kinetic energy some amount of kinetic energy is always converted into thermal heat energy,therefore the correct option is C.
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A projectile is launched over level ground with an initial velocity of 65 m/s at 30° above the horizontal. What is
the projectile's time of flight? (SHOW WORK)
A. 3.6 s
B. 6.6 s
C. 11 s
D. 13 s
Answers
The projectile's time of flight is approximately 6.6 seconds, which is closest to option B.
Projectile Motion: What Is It?An object that is shot into the air and subsequently proceeds along a curved route while being pulled by gravity is said to be in projectile motion. There is no additional propulsion or lift involved. A ball that is tossed, a bullet that is shot from a pistol, or a rocket that is launched into space are examples of things in projectile motion.
We can use the kinematic equations of motion to calculate the projectile's time of flight. The initial velocity can first be divided into its horizontal and vertical components as follows:
\(Vx = V \times cos(\theta)\\= 65 m/s \times cos(30)\\= 56.18 m/s\\Vy = V \times sin(theta)\\= 65 m/s \times sin(30)\\= 32.5 m/s\\\)
where V is the magnitude of the initial velocity, and theta is the launch angle (30 degrees).
The horizontal velocity of the projectile remains constant throughout its flight, while the vertical velocity changes due to the effect of gravity. At the highest point of the trajectory, the vertical velocity becomes zero, and the time it takes to reach this point is equal to half of the time of flight.
The time it takes for the projectile to reach the highest point can be found using the following kinematic equation:
\(V_y = V_oy + a \times t\)
where Voy is the vertical component of the initial velocity (in this case, 32.5 m/s), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes to reach the highest point.
\(0 = 32.5 m/s + (-9.81 m/s^2) \times t\\t = 3.32 s\)
The total time of flight can be found by doubling the time it takes to reach the highest point:
time of flight = 2 × 3.32 s
= 6.64 s
Therefore, the projectile's time of flight is approximately 6.6 seconds, which is closest to option B.
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How fast must the space shuttle go to cover 20,000 meters in 4.0 seconds?
Answers
Answer:
5000 m/s
Explanation:
URGENT
__ mass is the measurement of fat on the body. Fat or lean
Answers
\( \huge\fbox\red{Lean}\ \)
Lean body mass represents the weight of your muscles, bones, ligaments, tendons, and internal organs.\( \small\mid{ \underline{ \overline{ \tt \: －ɪƭ'ꜱ \: ʙᴙᴜᴛᴀʟ \: σʋʇ \: ɦэŗǝ}} \mid} \)
Answer:
\(lean \: is \: the \: measure \: of \: fat \\ you \: can \: remembar \: by \: using \\ \: the \: term \: lean \: meat \: usually \: used \: to \: \\ eat \\ thank \: you\)
A ball is projected at an angle of 53°. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was launched?
A.) 31 meters/second
B.) 38 meters/second
C.) 44 meters/second
D.) 55 meters/second
Answers
Answer:
The vertical component of the velocity can be found using the formula:
V₀y = V₀ * sin(θ)
where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.
Substituting the given values, we have:
V₀y = 48 * sin(53°)
Using a calculator, we can evaluate sin(53°) to be approximately 0.799:
V₀y = 48 * 0.799
V₀y ≈ 38.352
Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.
Answer:
B.) 38 meters/second
Explanation:
A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.
When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e
Answers
Answer:
e
Explanation:
A container holds a gas consisting of 5.75 moles of oxygen molecules. One in a million of these molecules has lost a single electron. NA=6.022×1023mol−1 , e=1.60×10−19C.
What is the net charge of the gas?
Express your answer to three significant figures and include the appropriate units.
Answers
Answer:The oxygen molecules have lost a total of 0.94 coulombs in charge of their electrons.
Explanation:No
how to prepare for neet
Answers
Be Familiar With The Syllabus.
High-Quality Study Material.
Create a Realistic Timetable.
Prepare Notes While Learning.
Revise Regularly.
Maintain a Healthy Diet.
Regular Study Breaks are a Must.
Do Proper Exercise.
with an armature resistance of 0.03 2 and a field resistance of
41.67 2. The motor has compensating windings, so armature
reaction can be ignored. Mechanical and core losses may be
assumed to be negligible for the purposes of this problem. The
motor is assumed to be driving a load with a line current of 126 A
and an initial speed of 1103 r/min. To simplify the problem,
assume that the amount of armature current drawn by the motor
remains constant.
A. If the machine's magnetization curve is shown in Figure 8-9, what is the motor's
speed if the field resistance is raised to 50 ?
B. Calculate and plot the speed of this motor as a function of the field resistance RF
assuming a constant-current load.
R₁ = 0.03 2
EA
IA
IF
IL
RF + Radj
LF
+
250 V
Answers
A. The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min
A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:
EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.
Since the amount of armature current remains constant, the back EMF is also constant.
Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:
IF = (250 V - EA)/(RF + R₁)
At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.
If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.
Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:
kϕN/IF1 = kϕN/IF2
N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min
Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:
N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min
where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.
Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.
A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.
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A woman carries a 12 kg box holding it in both armsa. How much force must be exerted on each of her arms to support the box?b. How will this force change if she holds the box with only one arm?
Answers
a)58.8 N
b)117.6 N
Explanation
Weight is a quantity representing the force exerted on a particle or object by an acceleration field , on earth we have weigth due to acceleratioi of gravity ,its value is
\(g=\text{ 9.8}\frac{m}{s^2}\)caused by the presence of a massive second object,the earth
so, the weight is given as
\(\begin{gathered} weigth=mg \\ where\text{ m is the mass} \end{gathered}\)Step 1
given
\(mass=\text{ 12 kg}\)a) if she holds the box holding in both arms
the sum of force must equal zero, hence
\(\begin{gathered} arm1+arm2-weigth=0 \\ arm1+amr2=weigth \end{gathered}\)so, the sum of the forces on both arms must equal tehh weigth of the box,
let's find the weigth of the box
\(\begin{gathered} weigth=\text{ mg} \\ w=12\text{ kg*9.8}\frac{m}{s^2} \\ w=117.6\text{ Newtons} \end{gathered}\)so
\(\begin{gathered} arm1+amr2=117.6\text{ N} \\ arm1=\text{ arm2, so} \\ 2(arm1)=117.6 \\ arm1=\frac{117.6N}{2} \\ arm=58.8\text{ N} \end{gathered}\)therefore, she must exerts a force of 58.8 Newtons on each arm
a)58.8 N
Step 2
now, if she holds the box with only one arm:
in this case, the weight of the box must be supported by only one arm, so
the force must be equal to the weigth of the box
\(\begin{gathered} arm\text{ force= weigth} \\ arm\text{ force=mg} \\ armforce=12\text{ kg*9.8 }\frac{m}{s^2} \\ arm\text{ force= 117.6 N} \end{gathered}\)so
b)117.6 N
I hope this helps you
A 200kg car is driving at 20m/s down the road when he sees a red light. He slows to a stop.
The car's initial momentum is ___kg m/s
The car's final momentum is ___kg m/s
The car's impulse is
___kg m/s
Answers
Answer:
Initial Momentum - 4000 kg*m/s
Final Momentum - 0 kg*m/s
Impulse: -4000 kg*m/s
Explanation:
The equation for momentum is P = mv
Initial Momentum
200kg * 20m/s = 4000 kg*m/s
Final Momentum
200kg * 0m/s = 0kg*m/s
Impulse = ΔP
Pfinal - Pintial = Impulse
0-4000 = -4000 kg*m/s
A ball of clay is moving at a speed of 12 m/s collides and sticks to a stationary ball of clay. If each ball has a mass of 13 kg, what's the combined velocity of the two balls of clay after the collision
Answers
Answer:
p_{f} = 6 m / s
Explanation:
We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved
Initial instant. Before the crash
p₀ = m v +0
Final moment. Right after the crash
\(p_{f}\) = (m + m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 2 m v_{f}
v_{f} = v / 2
we calculate
v_{f} = 12/2
p_{f} = 6 m / s
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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3.
How much force does the atmosphere exert on one side of a vertical wall 4.00-m high and
10.0-m long? The atmospheric pressure is standard atmospheric pressure.
4.05 x 105 N
E)
C)
4.05 x 106N
A)
2.53 x 103 N
D)
zero N
101 x 105N
Answers
Answer:
4.05×10⁶ N.
Explanation:
The following data were obtained from the question:
Breadth (B) = 4 m
Length (L) = 10 m
Standard pressure (P) = 101325 Nm¯²
Force (F) =..?
Next, we shall determine the area of the wall. This can be obtained as follow:
Area (A) = length (L) × breadth (B)
A = 10 × 4
A = 40 m²
Finally, we shall determine the force exerted on one side of the wall as follow:
Standard pressure (P) = 101325 Nm¯²
Area (A) = 40 m²
Force (F) =.?
Pressure (P) = Force (F) /Area (A)
101325 = F/40
Cross multiply
F = 101325 × 40
F = 4.05×10⁶ N.
Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.
To move the Center of Gravity (CG) forward, you could do which of the following?
Add clay to the nose.
Increase the density of the nose material.
Decrease the volume of the horizontal and vertical stabilizer material.
All of the above.
its not Increase the density of the nose material bc i tried that so help pleasee
Answers
Answer:
I think it's no. 3
Decrease the volume of the horizontal and vertical stabilizer material.
Explanation:
Lemme know if it's correct
Answer:
all of the above
Explanation:
What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.
Answers
We are given:
Mass of the Paint bucket (with paint) = 7000 grams
Mass of the paint bucket (without paint) = 500 grams
Volume of Paint in the Bucket = 5000 cm³
Mass of Paint in the Bucket:
To get the mass of the paint in the bucket, we will subtract the mass of the bucket from the mass of the paint bucket (with paint)
Mass of Paint = Mass of Paint bucket (with paint) - Mass of the paint Bucket (without paint)
Mass of Paint = 7000 - 500
Mass of Paint = 6500 grams
Density of the Paint:
We know that density = Mass / Volume
Density of Paint = Mass of Paint / Volume occupied by Paint
Density of Paint = 6500/5000
Density of Paint = 1.3 grams / cm³
The weight of a box is found to be 30 N. What is the approximate mass of the box?
3 kg
300 kg
120 kg
30 kg
Answers
Answer:
3kg
Explanation:
3kg is the appropriate mass
Answer:
3kg
Explanation:
just took the test
Pls help ASAP
Imagine that Maritans launch a rocket toward the Earth at a great speed. While the
rocket is traveling toward us, it will appear
than it actually is.
O more blue
darker
larger
more red
Answers
Answer:
The rocket will appear larger than it actually is
What normal force does a horizontal table exert on a 3.5 kg book that sits at rest?
Answers
Answer:
34.3N
Explanation:
The normal force, denoted by F(N), is the force exerted on an object by a surface. The normal force in this case is acting in an opposite manner but equal magnitude to the force of gravity.
F(N) = Fg
Where;
F(N) = Normal force
Fg = gravitational force
Fg = mg
Where;
m = mass (kg)
g = acceleration due to gravity
F(N) = mg
F(N) = 3.5kg × 9.8m/s²
F(N) = 34.3N
Hence, the normal force acting on the object is 34.3N.
An object of mass 1 kg is dropped from a table of height 1 m. If you represent the motion by drawing velocity and acceleration vectors of the object at 10 cm intervals below the table, which of the following statements are true?
The velocity vector at 50 cm is shorter than the one at 80 cm away from the table.
The acceleration vector is the same, both at 50 cm and 80 cm away from the table.
Answers
A 1 m-high table drops an object with a mass of 1 kg. This acceleration vector is identical at 50 cm and 80 cm distant the table if you depict the motion by sketching the object's velocities and accelerations vectors.
What are vectors of acceleration and velocity?A vector quantity with direction is velocity. The velocity vector's direction is always parallel to the object's motion. Acceleration direction: The vector quantity of acceleration has a direction.
What are vectors of acceleration?This acceleration vector, which represents the instantaneous acceleration, may be found by taking the velocity function's derivative with respect to time, as we saw in the previous chapter. The fact that they are essentially vector quantities is the only variation in either two or three dimensions.
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The graph shows the force and displacement of an object that is being pushed. How much work is done to push the object 0.12m?
Answers
Answer:
Work done, W = 0.72 J
Explanation:
From the given graph, it is clear that the force applied is 6 N if the extension is 0.12 m.
Work done is given by :
W = Fx
\(W=6\ N\times 0.12\ m\\\\W=0.72\ J\)
So, 0.72 J of work is done to push the object 0.12 m
100=50a
find acceleration
Fnet =ma
Answers
The answer is\(2ms^{-2}\).
we know that
Force can be calculated by: F=ma
F=>total force
m=>mass of the object
a=> acceleration
by observing the given data we can say
F=100
m=50
a=?
so we can find the value by using
a=F/m
=100/50
=2
So the answer is \(2ms^{-2}\).
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100=50a
Divide both sides by 50:
100/50=a
a=2units/sec²
F=ma
1. Your car has a mass of 2000 kg. If your car produces a force of 7000 N, how fast will it accelerate?
Formula
Substitution
(plug and chug)
Answer
(number and unit)
Submit Assig
Answers
Answer:
\(\huge\boxed{\sf a = 3.5\ m/s\²}\)
Explanation:
Given data:Mass = m = 2000 kf
Force = F = 7000 N
Required:Acceleration = a = ?
Formula:F = ma (derived from Newton's Second Law of Motion)
Solution:Taking formula.
F = ma
Solve it for a.
a = F / m
a = 7000 / 2000
a = 3.5 m/s²\(\rule[225]{225}{2}\)
A small bar magnet is placed in the magnetic field of a larger bar magnet, at
the position marked Yin the diagram below. Assuming the small bar magnet
is free to rotate, how would it be positioned?
X
Answers
The orientation of the magnet that is free to rotate is the wil be oriented as shown as the magnet in the option D.
The correct option is therefore, option D.
What is a bar magnet?A magnet produces magnetic field and it also attracts magnetic materials.
The directions of the lines of flux from a magnetic field is from the north to the south, such that the lines of flux emerges from the north of the magnet and enters into the magnet from the south pole of the magnet.
The point Y on the diagram shows the lines of flux entering the magnet, which indicates that the point Y is located in the south pole of the magnet, and therefore, will attract the north pole of another magnet, aligning it with the north and south pole of the large magnet in the figure.
The magnet free to rotate will therefore, be oriented with the north pole on the right (closer due to the attraction to the point Y) and the south pole on the left, which corresponds to the magnet D.
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Voltage
Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above
Answers
Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.
According to the Ohm's Law, the current through a conductor between two points is directly proportional to the voltage across the two points.
Mathematically,
V ∝ I
V = IR
where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.
Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.
Hence All of the above option in the given question are true.
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Squid use jet propulsion for rapid escapes. A squid pulls water into its body and then rapidly ejects the water backward to propel itself forward. A 1.5 kg squid (not including water mass) can accelerate at 20 m/s2 by ejecting 0.15 kg of water. Part A What is the magnitude of the thrust force on the squid
Answers
Answer: see attachment
Explanation:
Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.
Answers
1,401.88 N is the required weight of the man using the given conversion factor.
Determining the weight of an objectTo calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:
314 pounds ÷ 2.2 pounds/kg = 142.73 kg
Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):
Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N
The required weight in Newton of the man is 1,401.88 N
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