Step-by-step explanation:
tn=3n+8
t1=3*1+8
=3+8
=11
t7=3*7+8
=21+8
=29
t14=3*14+8
=42+8
=50
How many times greater is the intensity of sound from a concert speaker at a distance of 1 meter than the intensity at a distance of meters?
The intensity of sound from a concert speaker decreases with distance according to the inverse square law. This law states that the intensity is inversely proportional to the square of the distance.
So, if the intensity at a distance of 1 meter is I1, and the intensity at a distance of d meters is I2, the ratio of the intensities can be calculated using the formula:
(I1/I2) = (d2/d1)^2
Since we want to find the ratio of the intensities, we can substitute the given values:
(I1/I2) = (1/d)^2
Simplifying the equation, we get:
(I1/I2) = 1/d^2
Therefore, the intensity of sound from a concert speaker at a distance of 1 meter is (1/d^2) times greater than the intensity at a distance of d meters.
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The intensity of sound from a concert speaker at a distance of 1 meter is $\left(\frac{1}{x}\right)^2$ times greater than the intensity at a distance of $x$ meters.
The intensity of sound from a concert speaker decreases as the distance from the speaker increases. The relationship between intensity and distance is inversely proportional.
To determine how many times greater the intensity of sound is at a distance of 1 meter compared to the intensity at a distance of $x$ meters, we need to use the inverse square law formula:
$\frac{\text{Intensity1}}{\text{Intensity2}} = \left(\frac{\text{Distance2}}{\text{Distance1}}\right)^2$
Let's assume the intensity at a distance of $x$ meters is $I2$. Plugging in the values into the formula, we get:
$\frac{\text{Intensity1}}{I2} = \left(\frac{1 \text{ meter}}{x \text{ meters}}\right)^2$
Simplifying the equation, we have:
$\text{Intensity1} = I2 \times \left(\frac{1}{x}\right)^2$
This means that the intensity of sound at a distance of 1 meter is $\left(\frac{1}{x}\right)^2$ times greater than the intensity at a distance of $x$ meters.
For example, if $x$ is 3 meters, then the intensity of sound at a distance of 1 meter would be $\left(\frac{1}{3}\right)^2 = \frac{1}{9}$ times greater than the intensity at 3 meters.
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Can someone pls help me
Ill give Brainly
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how do you simplify -10 divided by(-5) (8)
answer fast please!!
Answer:276
Step-by-step explanation:
*EXTRA POINTS -- 8TH GRADE MATH*
pls answer each one :)
What do the two variables in this system represent?
the two variables represent the number of hot dogs or soft drinks you will get.
Write a system of equations to represent the model.
let s = soft drinks and let h = hot dogs
3s+2h=7.70
2s+h=4.55
What is the cost of 1 soft drink? $1.4
What is the cost of 1 hot dog? $1.75
Solving for the above two questions
solve the second eqaution for h:
2s+h=4.55
subtract 2s
h=4.55-2s
substitute this into the first equation:
3s+2(4.55-2s)=7.70
distribute the 2
3s+9.1-4s=7.70
add like terms
-s+9.1=7.70
subtract 9.1
-s=-1.4
divide by -1
s=1.4
substitute into the equation for h:
h=4.55-2s
h=4.55-2(1.4)
h=4.55-2.8
h=1.75
When playing roulette at a casino, a gambler is trying to decide whether to bet $15 on the number 10 or to bet $15 that the outcome is any one of the three possibilities 00,0 , or 1 . The gambler knows that the expected value of the $15 bet for a single number is −79 e. For the $15 bet that the outcome is 00,0 , or 1 , there is a probability of
38
3
of making a net profit of $60 and a
38
35
probability of losing $15. a. Find the expected value for the $15 bet that the outcome is 00,0 , or 1 . b. Which bet is better: a $15 bet on the number 10 or a $15 bet that the outcome is any one of the numbers 00,0 , or 1 ? Why? a. The expected value is $ (Round to the nearest cent as needed.)
The expected value for the $15 bet that the outcome is 00, 0, or 1 can be calculated to determine its value.
To find the expected value for the $15 bet on the outcome of 00, 0, or 1, we need to consider the probabilities and outcomes associated with the bet.
Given the information provided, there is a probability of 38/3 of making a net profit of $60 and a probability of 38/35 of losing $15.
To calculate the expected value, we multiply each outcome by its corresponding probability and sum them up:
Expected Value = (Probability of Net Profit) * (Net Profit) + (Probability of Loss) * (Loss)
Expected Value = (38/3) * $60 + (38/35) * (-$15)
Calculating the above expression will give us the expected value for the $15 bet on the outcome of 00, 0, or 1.
Expected value is a concept used in probability theory to quantify the average outcome of a random variable. It represents the average value we can expect to win or lose over a large number of repetitions of an experiment.
In this case, we are comparing two different bets: a $15 bet on the number 10 and a $15 bet on the outcome of 00, 0, or 1.
To determine which bet is better, we compare their expected values. The bet with the higher expected value is generally considered more favorable.
To make this comparison, we need to find the expected value for the $15 bet on the number 10. However, the expected value for this bet is not provided in the question.
Once we have the expected values for both bets, we can compare them. If the expected value for the $15 bet on the outcome of 00, 0, or 1 is higher than the expected value for the $15 bet on the number 10, then the former bet is considered better.
In summary, without the specific expected value for the $15 bet on the number 10, we cannot determine which bet is better. It depends on the calculated expected values for both bets, with the higher value indicating the more favorable option.
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R(x)=-3tan(1/2x)
What kind of reflection is this?
What is the vertical stretch factor?
What is the horizontal stretch factor?
What is the period?
A shopper at a clearance sale is pleased to discover some flutes on sale for $693 each. The original price tags read $770. What is the discount, as a percentage?
Answer:
10%
Step-by-step explanation:
Original price of flutes = $770
Discounted price = $693
To find:
Discount percentage = ?
Solution:
To find the discount percentage, we need to first find out the discount value.
Discount = Original price of flutes - Discounted price of flutes
Discount = $770 - $693 = $77
Discount percentage will be calculated on the original price.
\(Discount \%=\dfrac{Discount}{Original\ Price}\times 100\\\Rightarrow Discount \%=\dfrac{77}{770}\times 100\\\Rightarrow Discount \%=\bold{10\%}\)
So, the discount as a percentage is 10%.
x) = 3 x+2 and g( x) = 2 x+5. Find fo g(5).
Answer:
Put it in math-way and please write the expression so I can solve it
Step-by-step explanation:
In arguing against the death penalty, Amnesty International has pointed out supposed inequities, such as the many times a black person has been given the death penalty by an all-white jury. If jurors are selected randomly from an adult population, find the probability that all 12 jurors are white when the population is (a) 90% white and (b) 50% white.
Answer:
(a) 0.2824
(b) 0.0002441
Step-by-step explanation:
Assuming that the population is large enough to behave as a binomial distribution (between whites and non-whites), the probability of 12 out of 12 juros being white is:
\(P(w=12) = p(w)^{12}\)
Where p(w) is the proportion of the population that is white:
(a) for p = 0.90
\(P(w=12) = 0.90^{12}\\P(w=12) =0.2824\)
The probability is 0.2824.
(b) for p = 0.50
\(P(w=12) = 0.50^{12}\\P(w=12) =0.0002441\)
The probability is 0.0002441.
what is the height of the water prism
Answer:
32 because I Don't know please vote my answer please
Answer:
12 (10) cm 937 637 = hafe 2929888389292822
Use the row of numbers shown below to generate 12 random numbers between 01 and 99.
82077 84091 87154 65432 52179 58505 72538 08164
Starting at the beginning of the row, what are the first 12 numbers between 01 and 99 in the sample?
The first 12 random numbers between 01 and 99 in the sample are:24, 11, 53, 25, 45, 91, 38, 89, 77, 8, 30, 26
To generate 12 random numbers between 01 and 99 using the given row of numbers, we can use the method of linear congruential generator.
LCG is an algorithm that yields a sequence of pseudorandom numbers. The generator is defined by the recurrence relation:
\($$X_{n+1}=(aX_n+c)\mod m$$\)
Here, m, a, c, and X0 are seed value or starting value. We can use these values to generate the random numbers as follows:
Seed value (X0): 82077
Multiplier (a): 101427
Increment (c): 32147Modulus (m):
\(2^_16\) = 65536
Using these values, we can generate the 12 random numbers as follows:
$$X_1= (101427 × 82077 + 32147) mod 65536
= \(24935X_2\)
= (101427 × 24935 + 32147) mod 65536
= \(11712$$X_3\)
= (101427 × 11712 + 32147) mod 65536
= \(25931$$X_4\)
= (101427 × 25931 + 32147) mod 65536
= \(23255$$X_5\)
= (101427 × 23255 + 32147) mod 65536
= \(61145$$X_6\)
= (101427 × 61145 + 32147) mod 65536
= \(64913$$X_7\)
= (101427 × 64913 + 32147) mod 65536
= \(38138$$X_8\)
= (101427 × 38138 + 32147) mod 65536
= \(29088$$X_9\)
= (101427 × 29088 + 32147) mod 65536
=\(2779$$X_{10}\)
= (101427 × 2779 + 32147) mod 65536
=\(42108$$X_{11}\)
= (101427 × 42108 + 32147) mod 65536
= \(1730$$X_{12}\)
= (101427 × 1730 + 32147) mod 65536
= \(47826$$\)
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3t – 2(t – 1) ≥ 5t – 4(2 + t) please help ill give the crown thingy to the first person who gives me an answer
Answer:
Infinite many solutions
Meaning there is more than one solution
Hope this helps!
Let me know if this is right.
Step-by-step explanation:
Remove the parentheses
3t-2t+2 > 5t-8+4t
t+2 > t-8
Cancel equal terms
2 > -8
The statement is true
PLEASE NOTE:That sign you are putting under this > I didn't put it so just remember to put it.
WHAT DOES AN ANIMAL BREEDER DO?????????
I LITERALLY NEED HELP ON THIS ONE!!
Some school commercial thingy.
Answer:
Breeders cross animals of the same species with desirable traits to create desirable offspring.
Step-by-step explanation:
Find the volume of the solid bounded by the coordinate planes and the plane 4x+9y+z=6. Find the volume of the solid under the plane 9x+5y−z=0 and above the region bounded by y=x and y=x4. Evaluate the double integral. ∬D(4x−7y)dA,D is bounded by the circle with center the origin and radius 2
The volume of the solid bounded by the coordinate planes and the plane 4x + 9y + z= 6 is 9, the volume of the solid under the plane 9x+5y-z=0 and above the region bounded by y=x and y=x⁴ is 37/18 and the double integral ∬D(4x−7y)dA where D is bounded by the circle with center the origin and radius 2 is 0.
1) To find the volume of the solid bounded by the coordinate planes and the plane 4x + 9y + z = 6, follow these steps:
We need to find the limits of integration for the three variables x, y, and z. For z, the limit is from z=0 to z =6-4x-9y. For y, the limits are y=0 to y= (6 - 4x)/9. For x, the limits are x=0 to x=3/2.Integrating from z=0 to z= 6-4x-9y, \(V= \int\limits^{3/2}_0 \int\limits^{(6 - 4x)/9}_0 \int\limits^{6-4x-9y}_0 dz dy dx \\ = \int\limits^{3/2}_0 \int\limits^{(6 - 4x)/9}_0 [z]^{6-4x-9y} _0= \int\limits^{3/2}_0 \int\limits^{(6 - 4x)/9}_0(6-4x-9y)dy dx\)Integrating from y=0 to y=(6-4x)/9, \(V= \int\limits^{3/2}_0 \int\limits^{(6 - 4x)/9}_0(6-4x-9y)dy dx \\ = \int\limits^{3/2}_0 [(6-4x)y- \frac{9y^2}{2}]^{(6 - 4x)/9} _0\\ = \int\limits^{3/2}_0 \frac{9\cdot (6-4x)^2}{18} \\ = \int\limits^{3/2}_0 \frac{36 + 16x^2 -48x}{2} \\ = \int\limits^{3/2}_0 18+ 8x^2- 24x\)Integrating from x=0 to x= 3/2, \(\int\limits^{3/2}_0 18+ 8x^2- 24x= [18x + \frac{8}{3} x^3 -12x^2]^{3/2} _0\\ = 18\cdot\frac{3}{2} + \frac{8}{3}\cdot \frac{27}{8} -12\cdot \frac{9}{4} =27 +9 -27= 9\)Hence, the volume is 9.2) To find the volume of the solid under the plane 9x + 5y − z = 0 and above the region bounded by y = x and y = x⁴, follow these steps:
We need to find the limits of integration for the three variables x, y, and z.The equation of the plane is 9x + 5y − z = 0. At the point of intersection of y=x and y= x⁴, x⁴=x ⇒x(x³-1)=0. Hence, the limits for x is from x=0 to x=1. The limits for y is from y= x⁴ to y=x and for z, the limits are from z=0 to z = 9x + 5y.Integrating from z=0 to z= 9x+5y, \(V= \int\limits^{1}_0 \int\limits^{x}_{x^4} \int\limits^{9x+5y}_0 dz dy dx \\ = \int\limits^{1}_0 \int\limits^{x}_{x^4} [z]^{9x+5y} _0 \\ = \int\limits^{1}_0 \int\limits^{x}_{x^4} 9x+5y\)Integrating from y=x⁴ to y=x, \(V= \int\limits^{1}_0 \int\limits^{x}_{x^4} 9x+5y = \int\limits^{1}_0[9xy + \frac{5}{2}y^2]^x _{x^4} \\ = \int\limits^{1}_09x^2 + \frac{5}{2}x^2 - 9x^5- \frac{5}{2}x^8 = \int\limits^{1}_0 \frac{23}{2}x^2 - 9x^5- \frac{5}{2}x^8\)Integrating from x=0 to x=1, \(V= \int\limits^{1}_0 \frac{23}{2}x^2 - 9x^5- \frac{5}{2}x^8= [\frac{23}{6}x^3 - \frac{9}{6}x^6 - \frac{5}{18}x^9]^1 _0 \\ = \frac{14}{6}- \frac{5}{18} = \frac{37}{18}\)Hence, the volume is 37/183) To find the double integral ∬D(4x−7y)dA where D is bounded by the circle with center, the origin and radius 2, follow these steps:
The circle with center at the origin and radius 2 has the equation x² + y² = 4or, y² = 4 − x². Therefore, the limits of y are −√(4 − x²) and √(4 − x²). Also, since the region is bounded by the circle, the limits of x are −2 and 2.Integrating from y=−√(4 − x²) to y=√(4 − x²) , ∬D (4x − 7y) dA=\(\int \limits_{-2} ^{2}\int \limits _{-\sqrt{4 - x^2}} ^{\sqrt{4 - x^2}} (4x - 7y) dy dx= \int \limits_{-2} ^{2} [4xy - \frac{7}{2} y^2] _{-\sqrt{4 - x^2}} ^{\sqrt{4 - x^2}} \\ = \int \limits_{-2} ^{2}[ 4x\sqrt{4 - x^2} - \frac{7}{2} (4-x^2) + 4x\sqrt{4 - x^2} + \frac{7}{2} (4-x^2)]\\ = \int \limits_{-2} ^{2} 8x\sqrt{4 - x^2}\)Integrating from x=-2 to x=2, ∬D(4x−7y)dA= \(\int \limits_{-2} ^{2} 8x\sqrt{4 - x^2}\). This can be solved by using integration by substitution. Suppose 4 - x²= t² ⇒-2x dx = 2t dt ⇒ -xdx= tdt. So, ∬D(4x−7y)dA= \(\int \limits_{-2} ^{2} -8t dt= -4[t^2]^2_{-2}= -4[4-x^2]^2_{-2}= -4[4-4-4+4]= 0\)Hence, ∬D(4x−7y)dA=0Learn more about double integral:
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(a) Derive the class equation of a finite group G.
(b) Prove that a Sylow p-subgroup of a finite group G is normal if and only if it is unique.
a) The center of G and determining the distinct conjugacy classes, we can calculate the class equation of the finite group G.
b) We have shown both implications: if a Sylow p-subgroup is normal, then it is unique, and if it is unique, then it is normal.
(a) Deriving the class equation of a finite group G involves partitioning the group into conjugacy classes. Conjugacy classes are sets of elements in the group that are related by conjugation, where two elements a and b are conjugate if there exists an element g in G such that b = gag^(-1).
To derive the class equation, we start by considering the group G and its conjugacy classes. Let [a] denote the conjugacy class containing the element a. The class equation is given by:
|G| = |Z(G)| + ∑ |[a]|
where |G| is the order of the group G, |Z(G)| is the order of the center of G (the set of elements that commute with all other elements in G), and the summation is taken over all distinct conjugacy classes [a].
The center of a group, Z(G), is the set of elements that commute with all other elements in G. It can be written as:
Z(G) = {z in G | gz = zg for all g in G}
The order of Z(G), denoted |Z(G)|, is the number of elements in the center of G.
The conjugacy classes [a] can be determined by finding representatives from each class. A representative of a conjugacy class is an element that cannot be written as a conjugate of any other element in the class. The number of distinct conjugacy classes is equal to the number of distinct representatives.
By finding the center of G and determining the distinct conjugacy classes, we can calculate the class equation of the finite group G.
(b) To prove that a Sylow p-subgroup of a finite group G is normal if and only if it is unique, we need to show two implications: if it is normal, then it is unique, and if it is unique, then it is normal.
If a Sylow p-subgroup is normal, then it is unique:
Assume that P is a normal Sylow p-subgroup of G. Let Q be another Sylow p-subgroup of G. Since P is normal, P is a subgroup of the normalizer of P in G, denoted N_G(P). Since Q is also a Sylow p-subgroup, Q is a subgroup of the normalizer of Q in G, denoted N_G(Q). Since the normalizer is a subgroup of G, we have P ⊆ N_G(P) ⊆ G and Q ⊆ N_G(Q) ⊆ G. Since P and Q are both Sylow p-subgroups, they have the same order, which implies |P| = |Q|. However, since P and Q are subgroups of G with the same order and P is normal, P = N_G(P) = Q. Hence, if a Sylow p-subgroup is normal, it is unique.
If a Sylow p-subgroup is unique, then it is normal:
Assume that P is a unique Sylow p-subgroup of G. Let Q be any Sylow p-subgroup of G. Since P is unique, P = Q. Therefore, P is equal to any Sylow p-subgroup of G, including Q. Hence, P is normal.
Therefore, we have shown both implications: if a Sylow p-subgroup is normal, then it is unique, and if it is unique, then it is normal.
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an elevator began at an elevation of 85.5 feet and ascended at a rate of 2.75 feet per second. what was the elevation of the elevator after 8 seconds?
Answer:
107.5
Step-by-step explanation:
8 × 2.75ft = 22ft
22ft + 85.5ft = 107.5ft
Answer:
107.1
Step-by-step explanation:
the elevator is at 85.5 feet.
if the ascending (going up) rate is 2.75 and you want to know how far in 8 seconds, it's an easy process.
1. find the direction your going (up or down)
2. how far? (what rate for this one)
3. multiply said problem (2.75 x 8)
4. get your answer (21.6 ft per 8 seconds)
5. add or subtract to the height you are at now (85.5 ft)
6. you now have your answer! (107.1 ft in the air)
solve for y
a. 7 cm
b. 20 cm
c. 14 cm
d. 10 cm
Answer:
20 cm
Step-by-step explanation:
We can use ratios to solve
We know x = 7 since they are of equal length
x x+7
----- = -------
10 y
7 7+7
----- = -------
10 y
Using cross products
7y = 14*10
7y = 140
Divide by 7
7y/7 = 140/7
y = 20
can you tell me the steps on how to get the circled answer? i figured it out last night before i went to bed and now i can’t remember and i’ve been at this for hours.
In order to get the circled answer, you need to follow these steps:
1. Start by identifying the problem you are trying to solve and the information you have available.
2. Look for any relevant formulas or equations that could be used to solve the problem.
3. Plug in the values you have into the appropriate places in the formula or equation.
4. Simplify the equation by combining like terms and performing any necessary calculations.
5. Solve for the unknown variable, which should be the circled answer you are looking for.
If you are still having trouble, double-check your work to make sure you didn't make any mistakes along the way. It can also be helpful to review any notes or resources you have on the topic or to ask a teacher or tutor for assistance.
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The conversion of stored potential energy into kinetic energy can also be harnessed to power homes, factories and entire cities. Which example from the text supports this conclusion?
A the softball pitcher
B the slingshotting comet
C the archer
D the Hoover Dam
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how do I graph the function: d(x)=|x| -4 ?
Answer:
attached below
Step-by-step explanation:
d(x)=|x| -4
x≥0 d(x) = x -4
x<0 d(x) = -x -4
can you help me please
Answer:
189
Step-by-step explanation:
7 x 9 x 3 = 189
Use the coordinates to find the length of each side of the rectangle. Then find the perimeter. M(1,1) N(1,9) P(7. 9) Q(7,1)
The length of each side of the rectangle can be found by calculating the distance between the given coordinates.
The side lengths are 8 units and 6 units, respectively. The perimeter of the rectangle is the sum of all four side lengths, which is 28 units.
To find the length of each side of the rectangle, we calculate the distance between the given coordinates. Let's consider the coordinates M(1,1), N(1,9), P(7,9), and Q(7,1).
The side MN has coordinates (1,1) and (1,9). The vertical distance between these two points is 9 - 1 = 8 units.
The side NP has coordinates (1,9) and (7,9). The horizontal distance between these two points is 7 - 1 = 6 units.
The side PQ has coordinates (7,9) and (7,1). The vertical distance between these two points is 9 - 1 = 8 units.
The side QM has coordinates (7,1) and (1,1). The horizontal distance between these two points is 7 - 1 = 6 units.
Therefore, the length of each side of the rectangle is 8 units and 6 units.
The perimeter of a rectangle is the sum of all four side lengths. In this case, the perimeter is 8 + 6 + 8 + 6 = 28 units.
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A scientist counts 35 bacteria present in a culture and finds that the number of bacteria triples each hour. The function y = 35 ∙ 3x models the number of bacteria after x hours. Estimate when there will be about 550 bacteria in the culture.
Answer:
After 5 hoursStep-by-step explanation:
If a scientist counts 35 bacteria present in a culture and finds that the number of bacteria triples each hour and the function y = 35 ∙ 3x models the number of bacteria after x hours, in order to estimate when there will be about 550 bacteria in the culture we will substitute y = 550 into the modeled equation and calculate the value of x as shown;
If y = 35*3x
when y = 550
550 = 35*3x
Dividing both sides by 35;
550/35 = 35*3x/35
3x = 550/35
x = 550/3*35
x = 550/105
x = 5.24
This means that there will be 550 bacteria in the culture after approximately 5 hours
I am trash.No but seriously can someone help meh?
Answer:
Apples: 2.1
Blueberries: 1.1
Lemons: ?.1
Oranges: 3.5
Peaches:2.6
Pears : 3.6/2.6
Step-by-step explanation:
20 points, please help. Geometry help needed.
C is 56.55
D is 25.38
Answer:
c cause it willl be more likely trust
Step-by-step explanation:
The terminal side of O is in quadrant II and cos 0What is sin ?1313O A. - 12O B.O c. 5O D. 1 / 1
Solution
Using the trigonometric ratio, SOHCAHTOA
\(\begin{gathered} \text{SOH, CAH and TOA respectively represents} \\ \sin e\text{ }\theta=\frac{opposite}{\text{hypothenus}} \\ \cos \theta=\frac{adjacent}{\text{hypothenuse}} \\ \text{Tan}\theta\text{ = }\frac{opposite}{\text{adjacent}} \end{gathered}\)
From the question
\(\begin{gathered} \cos \theta=-\frac{5}{13} \\ \text{Therefore } \\ \text{adjacent = 5} \\ hypothenuse\text{ = 13} \end{gathered}\)Using pythagoras theorem, we can find the opposite
so that
\(\begin{gathered} \text{Hypothenuse}^2=opposite^2+adjacent^2 \\ 13^2=opposite^2+5^2 \\ opposite\text{ }^2=169-25 \\ \text{opposite =}\sqrt[]{144} \\ \text{opposite = 12} \end{gathered}\)Hence,
\(\begin{gathered} \sin e\theta=\frac{opposite}{\text{hypothenuse}} \\ \sin e\theta=\frac{12}{13} \\ \sin ce\text{ the terminal side is in the quadrant II and sine positive in the quadrant II, } \\ Sine\text{ }\theta=\frac{12}{13} \end{gathered}\)Therefore the right answer is option B
Gemma wrote the equation for a linear relationship below. y = 3x + 5 If x equals 9, what is the value of y? y = _____
Answer:
y = 32
Step-by-step explanation:
y = 3x + 5
y = 3(9) + 5
y = 27 + 5
y = 32
Answer:
Step-by-step explanation:
You replace all the x's in the problem with 9.
3(9)+5
3(9)=27
27+5=32
- 2x + 3y = 14
x + 2y = 7
Answer:
x = -1 , y = 4Step-by-step explanation:
x + 2y = 7 ⇒ x = 7 - 2y
- 2x + 3y = 14
- 2(7 - 2y) + 3y = 14
-14 + 4y + 3y = 14
-14 +7y +14 = 14 +14
7y = 28
y = 4
x = 7 - 2y = 7-2(4) = 7 - 8 = -1
Solve for y
3x + 2y = 9
Answer:
y = -\(\frac{3}{2}\)x + 4\(\frac{1}{2}\)
Step-by-step explanation:
Given: 3x + 2y = 9
Get y alone: 2y = -3x + 9
Get y alone part 2: y = -\(\frac{3}{2}\)x + 4\(\frac{1}{2}\)
Unless we have an x value this is as far as we can solve. Have a nice day! :D
(side note: it is now also in slope-intercept form!)