Please help!!!!!!!!!!!!!! ​

Adjust the parameters as needed, such as the step size (h) and the final x-value (xn), and run the code to obtain the solution for y(x).

The resulting plot will show the solution curve.

To solve the given set of differential equations using the Runge-Kutta method in MATLAB, we need to convert the second-order differential equations into a system of first-order differential equations.

Let's define new variables:

y = y(x)

z = dz/dx

Now, we have the following system of first-order differential equations:

dy/dx = z (1)

dz/dx = -k/(2y) (2)

To apply the Runge-Kutta method, we need to discretize the domain of x. Let's assume a step size h for the discretization. We'll start at x = 0 and proceed until x = infinite.

The general formula for the fourth-order Runge-Kutta method is as follows:

k₁ = h f(xn, yn, zn)

k₂ = h f(xn + h/2, yn + k₁/2, zn + l₁/2)

k₃ = h f(xn + h/2, yn + k₂/2, zn + l₂/2)

k₄ = h f(xn + h, yn + k₃, zn + l₃)

yn+1 = yn + (k₁ + 2k₂ + 2k₃ + k₄)/6

zn+1 = zn + (l₁ + 2l₂ + 2l₃ + l₄)/6

where f(x, y, z) represents the right-hand side of equations (1) and (2).

We can now write the MATLAB code to solve the differential equations using the Runge-Kutta method:

function [x, y, z] = rungeKuttaMethod()

   % Parameters

   k = 1;              % Constant k

   h = 0.01;           % Step size

   x0 = 0;             % Initial x

   xn = 10;            % Final x (adjust as needed)

   n = (xn - x0) / h;  % Number of steps

   % Initialize arrays

   x = zeros(1, n+1);

   y = zeros(1, n+1);

   z = zeros(1, n+1);

   % Initial conditions

   x(1) = x0;

   y(1) = 0;

   z(1) = 0;

   % Runge-Kutta method

   for i = 1:n

       k1 = h * f(x(i), y(i), z(i));

       l1 = h * g(x(i), y(i));

       k2 = h * f(x(i) + h/2, y(i) + k1/2, z(i) + l1/2);

       l2 = h * g(x(i) + h/2, y(i) + k1/2);

       k3 = h * f(x(i) + h/2, y(i) + k2/2, z(i) + l2/2);

       l3 = h * g(x(i) + h/2, y(i) + k2/2);

       k4 = h * f(x(i) + h, y(i) + k3, z(i) + l3);

       l4 = h * g(x(i) + h, y(i) + k3);

       y(i+1) = y(i) + (k1 + 2*k2 + 2*k3 + k4) / 6;

       z(i+1) = z(i) + (l1 + 2*l2 + 2*l3 + l4) / 6;

       x(i+1) = x(i) + h;

   end

   % Plotting

   plot(x, y);

   xlabel('x');

   ylabel('y');

   title('Solution y(x)');

end

function dydx = f(x, y, z)

   dydx = z;

end

function dzdx = g(x, y)

   dzdx = -k / (2*y);

end

% Call the function to solve the differential equations

[x, y, z] = rungeKuttaMethod();

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A congruent polygon refers to two or more polygons that have the same shape and size. There must be an equal number of sides between two polygons for them to be congruent.

Congruent polygons have parallel sides of equal length and parallel angles of similar magnitude. When two polygons are congruent, they can be superimposed on one another using translations, rotations, and reflections without affecting their appearance or dimensions. Concluding about the matching sides, shapes, angles, and other geometric properties of congruent polygons allows us to draw conclusions about them.

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Answer:

jsjshshshhsgdhshdhdhddhshggzggzgzhshsggggghzhgzgzgdgxgshdhdhgd

Step-by-step explanation:

h

Answer:

h

Step-by-step explanation:

Answer:

x=27

Step-by-step explanation:

m<AOB = 180

36+90+2x=180

x=27 degrees

The butterfly spread is constructed using the following three calls: - Buy 1 call with an exercise price of 120 at a price of $15.40.- Sell 2 calls with an exercise price of 125 at a price of $13.50 each.- Buy 1 call with an exercise price of 130 at a price of $11.35.


A butterfly spread involves buying one option with a lower exercise price, selling two options with a middle exercise price, and buying one option with a higher exercise price. In this case, we buy the call with an exercise price of 120, sell two calls with an exercise price of 125, and buy the call with an exercise price of 130.

To analyze the strategy, we need to consider the stock price at expiration. The breakeven stock prices are calculated by adding and subtracting the net debit or credit from the middle exercise price. In this case, the net debit is $1.60 ($15.40 – 2*$13.50 + $11.35), so the breakeven prices are $121.40 ($125 - $1.60) and $128.60 ($125 + $1.60).

The maximum profit of $1.60 occurs when the stock price is exactly at the middle exercise price of 125 at expiration. In this case, the two sold calls expire worthless, and the two bought calls have intrinsic value of $5 each. The minimum profit of -$1.40 occurs when the stock price is below $121.40 or above $128.60 at expiration. In this situation, all the options expire worthless, resulting in a loss of the net debit.

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The statements that are true about rectangles are mentioned in options  

A,B,C,E.

Rectangles -A shape with four sides and internal angles is a rectangle. The lengths of the other two sides are offset by two. The rectangle's diagonal sides are of identical length.

The opposite sides of a rectangle are equal and parallel to one another.

The diagonals cut each other in half, but not exactly.

All diagonals are the same length.

The rectangle's diagonals line up.

The total internal angles add up to the same value

Every internal angle has the same value.

A rectangle has congruent angles on all sides.

A rectangle's opposing angles are congruent.

We may thus infer that the statements about rectangles in the options are accurate based on the aforementioned features.

Q. Select all the statements that are true about rectangles.

A Diagonals are congruent.

B Diagonals bisect angles.

C Opposite angles are congruent.

D Diagonals are perpendicular.

E Diagonals bisect each other.​

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Step-by-step explanation:

plug in variables for x

x= 1:

-(1)-2

y= -3

x=2

-(2)-2

y= -4

x=3

-(3)-2

y= -5

x=4

-(4)-2

y= -6

Step-by-step explanation:

hsusbdjdhssjzssisbzjshzbzbaizussbissbisbsisbsssj

Traveling at a speed of 1000 miles per hour for 7.5 * 10⁵ hours would result in traveling a distance of 7.5 * 10⁸ miles.

To calculate the distance traveled, we can multiply the speed by the time traveled.

Speed = 1000 miles per hour

Time = 7.5 * 10⁵ hours

Distance = Speed * Time

Distance = 1000 miles/hour * 7.5 * 10⁵ hours

To perform this calculation, we can multiply the numerical values and keep the scientific notation for the result:

Distance = 1000 * 7.5 * 10⁵ miles

Distance = 7.5 * 10⁸ miles

Therefore, traveling at a speed of 1000 miles per hour for 7.5 * 10⁵ hours would result in traveling a distance of 7.5 * 10⁸ miles.

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The accurate statement regarding these two distributions is that Distribution A has a higher variance, and both distributions are positively skewed.

To determine which distribution has a higher variance, we need to calculate the variance of each distribution. Recall that the variance is given by the formula:

Var(X) = E[(X - μ)²],

where E is the expected value operator and μ is the mean of the distribution.

For Distribution A, we have:

μ = 0(0.20) + 1(0.20) + 2(0.20) + 3(0.20) + 4(0.20) = 2

E[(X - μ)²] = (0 - 2)²(0.20) + (1 - 2)²(0.20) + (2 - 2)²(0.20) + (3 - 2)²(0.20) + (4 - 2)²(0.20) = 2

For Distribution B, we have:

μ = 0(0.01) + 1(0.02) + 2(0.94) + 3(0.02) + 4(0.01) = 2

E[(X - μ)²] = (0 - 2)²(0.01) + (1 - 2)²(0.02) + (2 - 2)²(0.94) + (3 - 2)²(0.02) + (4 - 2)²(0.01) = 1.24

Therefore, Distribution A has a higher variance than Distribution B.

Regarding the skewness, we can observe that Distribution A and Distribution B are not symmetric, but have a mode at 2, and the probabilities decrease as we move away from the mode. Therefore, both distributions are positively skewed.

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Check the picture below.

first off let's check what "h" is in the triangular face.

\(\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2 \qquad \begin{cases} c=\stackrel{hypotenuse}{10}\\ a=\stackrel{adjacent}{6}\\ b=\stackrel{opposite}{h}\\ \end{cases}\implies 10^2=6^2+h^2 \\\\\\ 10^2-6^2=h^2\implies \sqrt{10^2-6^2}=h\implies 8=h\)

so, the gazebo has 4 squarish faces, each 12x12, recall 48 ÷ 4 = 12, and it has 4 triangular faces, each with a height of 8 and a base of 12.

notice we're skipping the top and bottom of the cube and the bottom of the pyramid because they're not part of the "surface area".

\(\stackrel{\textit{\large Areas}}{\stackrel{\textit{4 triangular faces}}{4\left[\cfrac{1}{2}(12)(8) \right]}~~~~+~~~~\stackrel{\textit{4 squarish faces}}{4[12\cdot 12]}}\implies 192+576\implies 768\)

To determine the cheapest can that holds the required amount, we need to calculate the total cost of the can based on the costs of the different components (bottom, top, and side) and their respective surface areas.

The surface area of the bottom is given by the formula for the area of a circle, which is A_bottom = πr². The surface area of the top is also A_top = πr². The surface area of the side is given by the formula for the lateral surface area of a cylinder, which is A_side = 2πrh. To hold the required volume, we have the equation V = πr²h. We need to minimize the cost function C = 0.02A_bottom + 0.01A_top + 0.009A_side. Substituting the expressions for the surface areas and simplifying, we get C = 0.03πr² + 0.018πrh.

Using the equation for the required volume, we can express the height in terms of the radius as h = V / (πr²).

Substituting this expression for h into the cost function, we have C = 0.03πr² + 0.018πr(V / (πr²)) = 0.03πr² + 0.018V / r.

To find the minimum cost, we take the derivative of C with respect to r, set it equal to zero, and solve for r:

dC/dr = 0.06πr - 0.018V / r² = 0.

Simplifying the equation, we get 0.06πr³ - 0.018V = 0.

Solving for r, we find r³ = V / (0.06π).

Taking the cube root of both sides, we have r = (V / (0.06π))^(1/3).

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answer:

have any notes for reference?

Step-by-step explanation:

Answer:

40 mph per hour

Step-by-step explanation:

120/3=40

Answer:

D

Step-by-step explanation:

please brainliest me

The angle between the stick and the base of the box is 77. 9 degrees

To determine the angle between the stick and the base, we have to know the trigonometric identities.

These identities are;

From the information given, we have;

sin A = FB/AB

Given that;

GB = 14.5cm

AB = 18. 6cm

substitute for the length of the sides, we have;

sin A = 14.5/18. 6

Divide the values, we have;

sin A = 0. 7796

Find the inverse sine

A = 77. 9 degrees

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The lifespan of Amoeba A, in terms of amoeba C is 5 + 2n

So,

Amoeba B life span = 2(amoeba C life span)

= 2(n)

= 2n

Amoeba A life span = 5 + amoeba B

= 5 + 2n

Therefore, the lifespan of Amoeba A, in terms of amoeba C is 5 + 2n

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Answer:

Where is the question????????

Friend

What's your question, my friend?

Answer:

bc

Step-by-step explanation:

2:9 is equivalent to

18: 81 because is 2*9 : 9*9

12:54 because is 2*6 : 9* 6

Answer:

\(this \: can \: be \: done \: by \: appling \: the \to \\ rate \: of \: change \: law : \\ r.o.c \: (m) = \frac{y_{2} -y_{1} }{x_{2} -x_{1} } \)

The air speed of the plane to cover 360 miles against the wind and with the wind in the given time is equal to 200 miles per hour.

Let 'x' be the speed of the plane fly in still air.

And 'y' be the speed of the wind.

Speed against the wind = x - y

Speed with the wind = x + y

Total distance covered by plane = 360 miles

Time taken against the wind = 2 hours 15 minutes

                                               = 2 ( 1/4 ) hours

                                               = 9 / 4 hours

Time taken with the wind = 1 hour 30 minutes

                                          = 1 ( 1/2 ) hours

                                          = 3 /2 hours

Speed = distance / time

Against the wind :

x - y = 360 / (9 /4 )

⇒x - y = 160___(1)

With the wind:

x + y = 360 / (3 /2)

⇒x + y = 240 ___(2)

Add (1) and (2) we get,

2x = 400

⇒ x= 200miles per hour

⇒y = 40 miles per hour

Therefore, the air speed of the plane as per given condition is equal to 200miles per hour.

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Option D, 3x^3(3x - 4)(11x - 4), is not a correct factorization of the given expression.

We are given the expression:

3x(3x - 4)^2 + x^8(3x - 4)(3)

We can first factor out the common factor of (3x - 4) from both terms, giving us:

(3x - 4)[3x(3x - 4) + x^8(3)]

Simplifying the expression inside the square brackets, we get:

(3x - 4)[9x^2 - 12x + 3x^8]

Now, we can factor out 3x^2 from the expression inside the square brackets, giving us:

(3x - 4)[3x^2(3x^6 - 4) + 3]

We can simplify further by factoring out 3 from the expression inside the square brackets, giving us:

(3x - 4)[3(x^2)(3x^6 - 4) + 1]

Therefore, the fully factored expression is:

3x(3x - 4)^2 + x^8(3x - 4)(3) = (3x - 4)[3(x^2)(3x^6 - 4) + 1]

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P(X = 7), λ = 6: The Poisson probability of X = 7, with a parameter (λ) value of 6, is 0.1446. P(X = 11), λ = 12: The Poisson probability of X = 11, with a parameter (λ) value of 12, is 0.0946. P(X = 6), λ = 8: The Poisson probability of X = 6, with a parameter (λ) value of 8, is 0.1206.

The Poisson probability is used to calculate the probability of a certain number of events occurring in a fixed interval of time or space, given the average rate of occurrence (parameter λ). The formula for Poisson probability is P(X = k) = (e^-λ * λ^k) / k!, where X is the random variable representing the number of events and k is the desired number of events.

To calculate the Poisson probabilities in this case, we substitute the given values of λ and k into the formula. For example, for the first case (a), we have λ = 6 and k = 7: P(X = 7) = (e^-6 * 6^7) / 7!

Using a calculator, we can evaluate this expression to find that the probability is approximately 0.1446. Similarly, for case (b) with λ = 12 and k = 11, and for case (c) with λ = 8 and k = 6, we can apply the same formula to find the respective Poisson probabilities.

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Differentiating each function, we have for all x, unless otherwise indicated,

\(h(x) = 2^x - 1 \implies h'(x) = \ln(2) \, 2^x > 0\)

\(g(x) = -4 (2^x) \implies g'(x) = -4 \ln(2) \, 2^x < 0\)

\(f(x) = -3x+7 \implies f'(x) = -3 < 0\)

\(j(x) = x^2 + 8x + 1 \implies j'(x) = 2x + 8 > 0 \text{ only when } x > -4\)

and only h(x) has a strictly positive derivative. (A)

Answer:

How many standard deviations above the mean is 14,500 hours? 1.25 1.5 2.5 Using the standard normal table, the probability that Seth's light bulb will last no more than 14,500 (P(z ≤ 1.25)) hours is about ✔ 89% .

Answer:

89%

Step-by-step explanation:

brainliest please

Answer:

y = -4x-34

Step-by-step explanation:

From the line to which the line is parallel, we can get the slope

The general form of a linear model is;

y = mx + b

where m

is the slope and b is the y-intercept

From the question, using the given line,

we have the slope of that line as -4

Now, we want to write the equation of a line that passes through (-7,-6) and has a slope of -4

we can use the point-slope form

for this

That would be;

y-y1 = m(x-x1)

y + 6 = -4(x+ 7)

y + 6 = -4x -28

y = -4x -28-6

y = -4x - 34

Answer:

I'm thinking it's A...

==================================================

Explanation:

I'm assuming you meant to say 2 & 1/2 instead of 2,1/2

If so, then we cut that last term 2 & 1/2 in half

The whole part 2 cuts in half to 1

The fractional part 1/2 cuts in half to 1/4

2 & 1/2 cuts in half to 1 & 1/4 which leads to choice C

The reason why we cut in half is because the jump from 20 to 10 is "divide by 2", and the same applies from 10 to 5, and from 5 to 2 & 1/2.

Answer:

1/6

Step-by-step explanation:

hope this helps :)

1/6

divide both by 2 and you get 1/6

Answer:

The initial value of the boat was $20,000

The percent decrease per year of the value of the boat is 10%.

The interval on which the value of the boat is decreasing while Harry has it is (0,10)

Step-by-step explanation:

It is given that the boat costs $20,000 in 2010 when x = 0. So, the initial value of the boat was $20,000.

Next, find the percent decrease per year of the value of the boat. Consider the general form of an exponential equation, y = a(b)x, where a is the initial value of the boat, b is the base of the exponent, x is the number of years after 2010, and y is the value of the boat, in dollars.

Consider the point (1 , 18,000) which lies on the graph of this situation. Substitute x = 1, y = 18,000, and a = 20,000 into the exponential equation and isolate b.

Recall that for exponential decay, b = 1 - r where r represents the decay rate. Substitute b = 0.9 into this equation and solve for r.

So, the decay rate is 0.1, and the percent decrease per year of the value of the boat is 10%.

Harry bought the boat in 2010, and plans on selling it after 10 years in 2020. Therefore, the interval on which the value of the boat is decreasing while Harry has it is [0, 10].