Please help me :3 please explain

Answer: x=4

Step-by-step explanation:

Subtract 6x from both sides.

5x+3−6x=6x−1−6x

−x+3=−1

Step 2: Subtract 3 from both sides.

−x+3−3=−1−3

−x=−4

Step 3: Divide both sides by -1.

−x/−1 = −4/−1

x=4

Answer:

the volume of the basketball when the radius is r

Step-by-step explanation:

Answer: $450

Step-by-step explanation:

Cost of 3kg flour=$90

cost of 1kg flour=$90/3 =$30

cost of 15 kg flour=$30*15=$450

Answer:

.........................................

Answer:

Answer is 69.08 m

Step-by-step explanation:

use formula 2 pie r

radius=diameter/2

=22/2

=11

therefore radius is 11

put the value of radius in the formula 2 pie r

pie=3.14

The value of q is -27.

Recall Vieta's Formulas, which state that for a quadratic equation \(ax^2\) + bx + c = 0 with zeroes alpha and beta, the sum of the zeroes is equal to -b/a, and the product of the zeroes is equal to c/a.

In our equation \(x^2\) - 3x + q, the sum of the zeroes alpha and beta is -(-3)/1 = 3.

We are given that 2 alpha + 3 beta = 15. Substitute alpha = (15 - 3 beta)/2 into the equation.

Replace the value of alpha in the sum of zeroes equation: (15 - 3 beta)/2 + beta = 3.

Simplify the equation by multiplying both sides by 2: 15 - 3 beta + 2 beta = 6.

Combine like terms: 15 - beta = 6.

Subtract 15 from both sides: -beta = -9.

Multiply both sides by -1 to solve for beta: beta = 9.

Substitute the value of beta into the sum of zeroes equation: alpha = (15 - 3 * 9)/2 = -3.

Since we have the values of alpha and beta, we can find q using the product of the zeroes formula: q = alpha * beta = -3 * 9 = -27.

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Answer:

2x + 1

Step-by-step explanation:

To find f(g(x)), we need to substitute g(x) for x in the function f(x) = 2x + 7.

so f(g(x)) = 2(x - 3) + 7 = 2x - 6 + 7 = 2x + 1

So the composition of function f(g(x)) is f(g(x)) = 2x + 1.

the indentation diagonal length is approximately 0.0686 units.

What is Intention Diagonal Length?

The indentation diagonal d is determined by the mean value of the two diagonals d 1 and d 2 at right angles to each other: To avoid the risk of bulging of the material on the opposite side of the sample, the thickness should not fall below a certain minimum value. value. The minimum thickness depends on the expected hardness of the material and the test load.

To calculate the indentation diagonal length using the Vickers hardness value, you need to know the applied load and the hardness number. The Vickers hardness test measures the resistance of a material to indentation using a diamond indenter.

In this case, you have the following information:

Load: 0.700 kg

Vickers HV: 650

The Vickers hardness number (HV) is defined as the applied load divided by the surface area of the indentation.

The formula to calculate the indentation diagonal length (d) is:

d = 1.854 * sqrt(L / HV)

Where:

d = indentation diagonal length

L = applied load in kg

HV = Vickers hardness number

Plugging in the values:

d = 1.854 * sqrt(0.700 / 650)

Calculating the square root and performing the division:

d ≈ 1.854 * 0.0370262

d ≈ 0.0686

Therefore, the indentation diagonal length is approximately 0.0686 units. Please note that the specific unit (e.g., millimeters) was not provided in the question, so the answer is given in relative units.

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Answer:

150 ft

Explanation:

The number of feet of fencing needed should cover the entire perimeter of the rectangular garden.

Now the perimeter of the rectangle is

Hence, the 150 ft of fencing is required to enclose the rectangular garden,

Answer:

The answer to 1 + 1 is 2.

Very complicated problem, please mark brainliest!

Answer:

1+1 = 2

Or, 1=2-1

1=1

we know value of one is one

so,

1+1=11

distance between 2 points = root (x1-x2)²+(y1-y2)²

so root (-2-2)²+(5--3)² = 8.994 ≈ 9 units

SOLUTION

The given equation is:

The graph of the function is shown:

The vertical asymptotes is x=2

The horizontal asymptote is y=3

A manufacturer of compact fluorescent light bulbs advertises have a standard deviation of 1,000 hours so the values are:

A normal distribution with,

μ = 9000

σ = 1000

a) The standardized score is the value x decreased by the mean and then divided by the standard deviation.

x = 105000 - 9000 / 1000 ≈ 1.50

Determine the corresponding probability using the normal probability table in appendix,

P(X>10500) = P(Z>1.50) = 1 - P(Z<1.50)

= 1 - 0.9332 = 0.0668.

b) n = 15

The sampling distribution of the mean weight is approximately normal, because the population distribution is approximately normal.

The sampling distribution of the sample mean has mean μ and standard deviation σ/√n

μ = 1000/√15 = 258.19

c) The sampling distribution of the sample mean has mean μ and standard deviation σ/√n

The z-value is the sample mean decreased by the population mean, divided by the standard deviation:

z = x-u/σ/√n = 10500-9000/1000√15 = 5.81

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Tool dividing beats into two, three or four parts is called a simple meter.

A simple meter is a tool in music which divides beats into a number of two, three or four parts. A simple meter is of three types :

1. Duple - a meter which helps to divide a beat into 2 (i.e. into two parts).
2. Triple - a meter which helps to divide beats into 3(i.e. into three parts)

3. Quadruple - a meter which helps to divide beats into 4(i.e. into four parts).
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Duple - a meter which helps to divide a beat into 2 (i.e. into two parts).

Triple - a meter which helps to divide beats into 3(i.e. into three parts)

Quadruple - a meter which helps to divide beats into 4(i.e. into four parts).

The list of courses where the percentage of students with D or F grades is greater than the average includes Course A and Course B.

To find a list of courses where the percentage of students with a grade of D or F is greater than the average, follow these steps:

1. Calculate the average percentage of students with D or F grades across all courses.
2. Determine the percentage of students with D or F grades for each course.
3. Compare the percentage of students with D or F grades for each course to the average percentage calculated in step 1.
4. Identify the courses where the percentage of students with D or F grades is greater than the average.

Let's assume we have the following data for three courses:

Course A:
- Total number of students: 50
- Number of students with D or F grades: 10
- Percentage of students with D or F grades: (10/50) * 100 = 20%

Course B:
- Total number of students: 60
- Number of students with D or F grades: 15
- Percentage of students with D or F grades: (15/60) * 100 = 25%

Course C:
- Total number of students: 40
- Number of students with D or F grades: 5
- Percentage of students with D or F grades: (5/40) * 100 = 12.5%

Now, let's calculate the average percentage of students with D or F grades:

Total percentage of students with D or F grades = (20% + 25% + 12.5%) / 3 = 57.5% / 3 = 19.17%

Finally, compare the percentage of students with D or F grades for each course to the average percentage:

- Course A's percentage (20%) is higher than the average (19.17%)
- Course B's percentage (25%) is higher than the average (19.17%)
- Course C's percentage (12.5%) is lower than the average (19.17%)

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Answer:

\(\dfrac{1}{729}\)

Step-by-step explanation:

\(\left(\dfrac{}{}(-3)^2\dfrac{}{}\right)^{-3}\)

First, we should evaluate inside the large parentheses:

\((-3)^2 = (-3)\cdot (-3) = 9\)

We know that a number to a positive exponent is equal to the base number multiplied by itself as many times as the exponent. For example,

\(4^3 = 4 \, \cdot\, 4\, \cdot \,4\)

       ↑1 ↑2 ↑3 times because the exponent is 3

Next, we can put the value 9 into where \((-3)^2\) was originally:

\((9)^{-3}\)

We know that a number to a negative power is equal to 1 divided by that number to the absolute value of that negative power. For example,

\(3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{3\cdot 3} = \dfrac{1}{9}\)

Finally, we can apply this principle to the \(9^{-3}\):

\(9^{-3} = \dfrac{1}{9^3} = \boxed{\dfrac{1}{729}}\)

Answer:

D. There is sufficient evidence to warrant rejection of the claim that the mean pulse rate (in beats per minute) of the group of adult males is 69bpm.

Step-by-step explanation:

Hypothesis testing is used in statistics to confirm the validity of a statement or observation. Null hypothesis is the original observation for which the test is being conducted. Alternative hypothesis is set against the null hypothesis to reach a conclusion whether to accept or reject the null hypothesis. In the given scenario there is sufficient evidence to reject the null hypothesis.

Answer:

m = -4

Step-by-step explanation:

move -9 to the other side so it will be positive. -13 + 9 = -4

m= -4

Add 9 to both sides of the equation,

m=-13+9

Add -13 and 9.

m= -4

It's the Second one and the third one

Step-by-step explanation:

Pie is irrational so you can easily cross it off and it leads to to the second one and the third one

Answer:

The worth of boat in 2013 will be $9202.6

Step-by-step explanation:

Rate of depreciation = 9% = 0.09

Cost of Boat in 2006 =$ 17,800

Cost of Boat in 2013 = ?

Years = 2013-2006= 7 years

The formula used is: \(\mathbf{A=P(1+r)^{t}}\)

Since the value of boat is depreciating the value of r will be r=-0.09

Here P = 17,800 , r=-0.09 and t = 7 years Finding A

\(A=P(1+r)^{t}\\A=17,800(1+(-0.09))^7\\A=17,800(0.91)^7\\A=17,800(0.517)\\A=9202.6\)

So, the worth of boat in 2013 will be $9202.6

devide 15 by 5 it will be 3

The surface described by the equation ρ^2(sin^2φ*sin^2σ +cos^2φ) = 9 is a sphere. The given equation represents a sphere in spherical coordinates.

In the equation, ρ represents the radial distance from the origin, φ represents the azimuthal angle (measured from the positive z-axis), and σ represents the polar angle (measured from the positive x-axis in the xy-plane).

The equation can be simplified to ρ^2(sin^2φ*sin^2σ +cos^2φ) = 9. This equation indicates that the sum of the squares of the trigonometric functions involving φ and σ, along with the square of the cosine of φ, is a constant value of 9.

This equation describes a sphere centered at the origin, where the radius of the sphere is determined by the square root of the constant value 9. The concept of a sphere is fundamental in geometry and has various applications in mathematics, physics, and engineering.

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Answer:

K^2 - 100 = (K + 10)(K - 10)

16p^2 - 36 = 4(4p^2 - 9) = 4(2p + 3)(2p - 3)

9d^2 - 32 = (3d - 4)(3d + 4)

24a^2 - 54b^2 = 6(4a^2 - 9b^2) = 6(2a + 3b)(2a - 3b)

100b^3 - 36b = 4b(25b^2 - 9) = 4b(5b - 3)(5b + 3)

Answer:

If 4 units equal 16 ounces, we can find the value of 1 unit by dividing both sides by 4:

4 units = 16 ounces

4 units ÷ 4 = 16 ounces ÷ 4

1 unit = 4 ounces

So, 1/4 x 16 ounces = 4 ounces.

4/1 is the answer in fraction :)

By simple reasoning, The chance of Carol being selected is 1/800.

A collection of random variables, typically indexed by time, makes up a random process. Here, the process S(t) is an illustration of a continuous-time random process. In general, a random process X(t) is a continuous-time random process if t can take real values in an interval on the real line.

A straightforward random sample is being taken from a population that includes both Larry and Carol.

So both of them have an equal chance of being chosen.

Now, Larry's likelihood of being chosen is 1 in 800.

The likelihood of Carol being chosen is then 1 in 800.

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Answer:x − x^{2} − 1.

Step-by-step explanation:

.

Answer:

D. The pH indicates how acidic or basic a solution is.

Step-by-step explanation:

The range goes from 0 to 14, with 7 being neutral.

Given:

\(\log_{a}(3) = 0.477,\log_{a}(5) = 0.699\)

To find:

The value of \(\log_{a}(0.6)\).

Solution:

We need to find the value of:

\(\log_{a}(0.6)\)

It can be written as

\(\log_{a}(0.6)=\log_a\left(\dfrac{6}{10}\right)\)

\(\log_{a}(0.6)=\log_a\left(\dfrac{3}{5}\right)\)

By using the property of logarithm, we get

\(\log_{a}(0.6)=\log_a(3)-\log_a(5)\)        \([\because \log \dfrac{a}{b}=\log a-\log b]\)

\(\log_{a}(0.6)=\log_a(3)-\log_a(5)\)

On substituting the given values, we get

\(\log_{a}(0.6)=0.477-0.699\)

\(\log_{a}(0.6)=-0.222\)

Therefore, the values of \(\log_a(0.6)\) is -0.222.

The given function satisfies the differential equation.Therefore, the given functions ex cos(5x) and ex sin(5x) form a fundamental set of solutions of the differential equation y'' - 2y' + 6y = 0 on the interval (−∞, ∞).

Given Differential Equation: y'' - 2y' + 6y

= 0Let's substitute the given function ex cos(5x) to the differential equation:y'' - 2y' + 6y

= 0 Differentiating y'' with respect to x:dy''/dx

= -25ex cos(5x) + 10ex sin(5x) dy''/dx

= (5.25) ex cos(5x) + 25ex sin(5x)Substituting these values, we get the following:y'' - 2y' + 6y

= (-25) ex cos(5x) + 10ex sin(5x) - 2(5ex sin(5x)) + 6ex cos(5x)

= (5.25ex cos(5x) + 25ex sin(5x)) - (10ex sin(5x) + 10ex sin(5x)) + 6ex cos(5x)

= ex cos(5x)(5.25 - 2 + 6) + ex sin(5x)(25 - 10 - 10)

= 9.25 ex cos(5x) + 5 ex sin(5x)The given function satisfies the differential equation.Now, let's substitute ex sin(5x) into the differential equation:y'' - 2y' + 6y

= 0 Differentiating y'' with respect to x:dy''/dx

= 25ex sin(5x) + 10ex cos(5x) dy''/dx

= (5.25) ex sin(5x) - 25ex cos(5x)Substituting these values, we get the following:y'' - 2y' + 6y

= (25) ex sin(5x) + 10ex cos(5x) - 2(25ex cos(5x)) + 6ex sin(5x)

= (5.25ex sin(5x) - 25ex cos(5x)) - (20ex cos(5x) - 10ex cos(5x)) + 6ex sin(5x)

= ex sin(5x)(5.25 + 6) + ex cos(5x)(10 - 20)

= 11.25 ex sin(5x) - 10 ex cos(5x).The given function satisfies the differential equation.Therefore, the given functions ex cos(5x) and ex sin(5x) form a fundamental set of solutions of the differential equation y'' - 2y' + 6y

= 0 on the interval (−∞, ∞).

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If a cube is rolled 24 times and lands on 2 four times and on 6 three times , then the experimental probability of not landing on a "6" is 0.171   .

on a cube there are total 6 outcomes ,

the probability of getting "2" on a single cube is = P(2) = 1/6  ;

the probability of getting "6" on a single cube is = P(6) = 1/6  ;

the probability of the cube not landing on 6 is = P'(6) = 5/6  ;

Since the cube is rolled 24 times , the experimental probability of not landing on "6" is

⇒ P(not 6) = ²⁴C₅×(1/6)⁵×(5/6)¹⁹ ;

On simplifying ,

we get ;

⇒ P(not 6) = 0.171  .

Therefore , the experimental probability of not landing on a 6 is 0.171  .

The given question is incomplete , the complete question is

A number cube is rolled 24 times and lands on 2 four times and on 6 three time. Find the experimental probability of not landing on a 6 .

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