Please help me?! All you have to do is find the missing side

Answer:

This hurt my head

Step-by-step explanation:

\(2 - \sqrt{1} \\ = 2 - 1 \\ = 1\)

The relation displayed in the table is

The relation in the table is compared by identifying how a coordinate point are expressed as ordered pair and how they are expressed as a table

For instance, say (b, c) is represented in a table as

x    y

a    b

Using this instance and writing out the values in the table we have

(3, 3), (-1, 1), (2, -2), and (-3, 2)

This is similar to option B making option B the appropriate option

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Answer:

Doman is the x intercpet range

Step-by-step explanation:

all real numbers is the domain since the function goes on and on forever and will at one point get to 1 billion or trillion or just on and on forever.

The Answer Is:

All Real Numbers

Answer:

9m squared

Step-by-step explanation:

Area of a kite is xy/2

= 8 X 10 divided by 2

Answer:

One of the options is most likely "Point C's coordinates do not change". I can't help much other than that.

Step-by-step explanation:

I apologize but I'd need to see the graph and the options to provide a completely accurate answer.

To differentiate the given equation implicitly, we find the first partial derivatives of z with respect to x and y. The derivative of z with respect to x is obtained by applying the product rule and the chain rule, while the derivative of z with respect to y is determined using the quotient rule and the chain rule.

To find the first partial derivatives of z, we differentiate the given equation implicitly. Starting with the equation:

x ln(y) y^2z + z^2 = 5

We differentiate both sides of the equation with respect to x. Applying the product rule and the chain rule, we obtain:

ln(y) y^2z + x * (1/y) * y^2z * dy/dx + 2z * dz/dx = 0

Simplifying the expression, we have:

ln(y) y^2z + x * yz * dy/dx + 2z * dz/dx = 0

Next, we differentiate both sides of the equation with respect to y. Using the quotient rule and the chain rule, we get:

x * (1/y) * y^2z + ln(y) * 2yz * dy/dx + x * y * dz/dy + 2z * dz/dy = 0

Simplifying the expression further, we have:

x * yz/y + 2ln(y)yz * dy/dx + x * y * dz/dy + 2z * dz/dy = 0

Thus, the first partial derivatives of z are given by:

dz/dx = -(ln(y) y^2z)/(x * yz) - (2z * dz/dx)/(x * yz)

dz/dy = -(x * yz/y)/(2ln(y)yz) - (x * y * dz/dy)/(2ln(y)yz) - (2z * dz/dy)/(2ln(y)yz)

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The rate of change of volume with respect to R is 4πR².

The rate of change function is defined as the rate at which one quantity is changing with respect to another quantity. In simple terms, in the rate of change, the amount of change in one item is divided by the corresponding amount of change in another. The rate of change formula gives the relationship describing how one quantity changes in relation to the change in another quantity. The rate of change from the coordinates of y to the coordinates of x can be found out as Δy/ Δx = (y2 - y1 )/ (x2 - x1 ). For a linear function, the rate of change m is represented in the slope-intercept form for a line: y=mx+b whereas the rate of change of functions is otherwise defined as, (f(b)-f(a))/ b-a.

The volume of the sphere is:

V = (4π/3)(R³)

Differentiating volume with respect to radius gives:

dV/dR  = (4π/3)× (3R²) = 4πR²

Thus, the rate of change of volume with respect to R is 4πR².

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Given that,

∠C = (6x-21)° and ∠A = (4x+11)°

To find,

Choose the correct option.

Solution,

For a parallelogram, the opposite angles are equal. ATQ,

(6x-21)° = (4x+11)°

Taking like terms together,

6x-4x = 21 + 11

2x = 32

x = 16

∠C = (6x-21)° = 6(16) -21 = 75°

So, ∠A = 75°

So, ∠A = ∠C = 75°. Hence, the correct option is (B).

The approximate solutions for f(x) = 0 are -1.8, 0.6, and 1.2. Using  Newton's method, we can approximate the roots to be -1.8, 0.6, and 1.2. These are the three options to select as the approximate solutions for x when f(x) = 0.

To graph the function f(x) = x3 – 4x – 1, we can plot several points and connect them with a curve. Alternatively, we can use calculus to find the critical points, where the derivative is zero, and analyze the behavior of the function near those points.

Using calculus, we can find that the derivative of f(x) is f'(x) = 3x2 - 4. Setting f'(x) = 0 and solving for x, we get x = ±sqrt(4/3). We can then use the second derivative test to see that f''(sqrt(4/3)) > 0, so it is a local minimum, and f''(-sqrt(4/3)) < 0, so it is a local maximum.

Therefore, we know that f(x) has one local maximum and one local minimum. By looking at the graph or using the intermediate value theorem, we can see that f(x) changes sign at x = -2, x = 0, and x = 1.5. This means that there is at least one root in each of the intervals (-∞, -2), (-2, 0), (0, 1.5), and (1.5, ∞).

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1478 cubic feet

First, calculate volume of the shed, then minus that by the volume of the cubes...

Volume(shed) = 12*12*12 = 1728

Volume(cube) = 2.5*2.5*2.5 = 15.625

1728 - 15.625(16) = 1478 cubic feet

Answer:

B

Step-by-step explanation:

4x=3y

x/y=3/4

Just like the photo I attached

If 4x=3y, then 3/4 is the ratio of x to y in the simplest form. Option B is correct.

The ratio of x to y can be determined by dividing both sides of the equation 4x = 3y by y:

4x/y = 3y/y

4x/y = 3

To express the ratio of x to y in simplest form, we divide both sides of the equation by 4:

x/y = 3 / 4

Therefore, the ratio of x to y in simplest form is 3/4. option B is correct.

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The derivative of f(x) = sech^(-1)(x^2) is f'(x) = 2x/sqrt(1 - x^4).

a) To find f'(x) for f(x) = x*sin(x), we can use the product rule and the derivative of the sine function.

Using the product rule, we have:

f'(x) = (xsin(x))' = xsin'(x) + sin(x)*x'

The derivative of sin(x) is cos(x), and the derivative of x with respect to x is 1. Therefore:

f'(x) = x*cos(x) + sin(x)

So, the derivative of f(x) = xsin(x) is f'(x) = xcos(x) + sin(x).

(b) To find f'(x) for f(x) = sech^(-1)(x^2), we can use the chain rule and the derivative of the inverse hyperbolic secant function.

Let u = x^2. Then, f(x) can be rewritten as f(u) = sech^(-1)(u).

Using the chain rule, we have:

f'(x) = f'(u) * u'

The derivative of sech^(-1)(u) can be found using the derivative of the inverse hyperbolic secant function:

(sech^(-1)(u))' = 1/sqrt(1 - u^2)

Since u = x^2, we have:

f'(x) = 1/sqrt(1 - (x^2)^2) * (x^2)'

Simplifying:

f'(x) = 1/sqrt(1 - x^4) * 2x

So, the derivative of f(x) = sech^(-1)(x^2) is f'(x) = 2x/sqrt(1 - x^4).

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Nevertheless, factοrizing  intο twο binοmials is nοt pοssible since  expressiοns is a quadratic equatiοn with nο factοrs οf the fοrm  where a, b, c, and d are cοnstants.

In mathematics, an expressiοn is a set οf numbers, variables, and mathematical οperatiοns (such as additiοn, subtractiοn, multiplicatiοn, divisiοn, expοnentiatiοn, and sο οn) that expresses a quantity οr value. Expressiοns might be simple, like "3 + 4", οr cοmplex, like "(3x² - 2) / (x + 1)". They may alsο include functiοns such as "sin(x)" οr "lοg(y)". Expressiοns can be evaluated by substituting values fοr the variables and carrying οut the mathematical οperatiοns in the given οrder. Fοr instance, if x = 2, the fοrmula "3x + 5" is 3(2) + 5 = 11. In mathematics, expressiοns are widely used tο explain real-wοrld situatiοns, build equatiοns, and simplify cοmplex mathematical issues.

cannοt be factοrized any further because it is already in its mοst basic fοrm.

Nevertheless, factοrizing  intο twο binοmials is nοt pοssible since  is a quadratic equatiοn with nο factοrs οf the fοrm  where a, b, c, and d are cοnstants.

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Complete Question;

Factorise 3x squared  intο twο binοmials.

To determine whether the given function is one-to-one or not, we need to examine if the function passes the horizontal line test or not.

That is, we need to ensure that each horizontal line intersects the graph of the function at most once. Here's how to determine if the function is one-to-one or not :To find the formula for the inverse, let us assume the inverse function to be f⁻¹(x). Then, switch the x and y terms of the given function. This means, f(x) = y will become x = f⁻¹(y)  . Now solve the obtained equation for y to get the formula for f⁻¹(x). If we get two or more different values of y, then the function does not have an inverse since it fails the vertical line test. In other words, the function is one-to-one if it passes the horizontal line test and only has one output value for each input value. If it is not one-to-one, then it does not have an inverse function.

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Answer:

5sqrt3

Step-by-step explanation:

You can use trigonometry to figure out the answer

TOA is tan(any angle) = opposite/adjacent

Tan(30) = 5/x

tan(30) = sqrt3/3

x = tan inverse (30) multiplied by 5

x = 5sqrt3

In linear equation, 24.9  tall is the tree .

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.

                          Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.

We can set up a proportion comparing the height of each object to the length of the shadow.

     h/15 = 21.1/12.7

     h = 1.66 * 15  

   h   = 24.9

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(a) To rank each lottery pair by statewise dominance, we compare the prizes of each lottery for each possible outcome of the die roll. Here are the six rankings:
Lottery 1 >SW Lottery 2
Lottery 1 >SW Lottery 3
Lottery 1 >SW Lottery 4
Lottery 2 ∼SW Lottery 3
Lottery 2 ∼SW Lottery 4
Lottery 3 ∼SW Lottery 4

(b) To rank each lottery pair by first-order stochastic dominance, we compare the cumulative distribution functions (CDFs) of each lottery. The CDF of a lottery gives the probability that the prize is less than or equal to a certain value. Here are the rankings:
Lottery 1 >F OSD Lottery 2 >F OSD Lottery 3 >F OSD Lottery 4
To show why Lottery 1 is first-order stochastically dominant over Lottery 2, consider the following CDFs:
Lottery 1:
Prize ≤ $1: 1/6
Prize ≤ $2: 2/6
Prize ≤ $3: 3/6
Prize ≤ $4: 4/6
Prize ≤ $5: 5/6
Prize ≤ $6: 6/6
Lottery 2:
Prize ≤ $1: 0/6
Prize ≤ $2: 1/6
Prize ≤ $3: 2/6
Prize ≤ $4: 3/6
Prize ≤ $5: 4/6
Prize ≤ $6: 6/6
We can see that for any prize value, the CDF of Lottery 1 is always greater than or equal to the CDF of Lottery 2. This means that the probability of winning a certain prize or less is always greater for Lottery 1 than for Lottery 2, which is the definition of first-order stochastic dominance.
We can similarly compare the CDFs of the other lotteries to arrive at the ranking above.

(c) To rank each lottery pair by second-order stochastic dominance, we compare the CDFs of the lotteries' expected values. The expected value of a lottery is the sum of the prizes multiplied by their probabilities, and the CDF of the expected value gives the probability that the expected value is less than or equal to a certain value. Here are the rankings:
Lottery 1 >SOSD Lottery 2 >SOSD Lottery 4 >SOSD Lottery 3
To show why Lottery 1 is second-order stochastically dominant over Lottery 2, consider the following CDFs of the expected values:
Lottery 1:
Expected value ≤ $1: 1/6
Expected value ≤ $2: 3/6
Expected value ≤ $3: 4/6
Expected value ≤ $4: 5/6
Expected value ≤ $5: 6/6
Expected value ≤ $6: 6/6
Lottery 2:
Expected value ≤ $1: 0/6
Expected value ≤ $2: 1/6
Expected value ≤ $3: 2/6
Expected value ≤ $4: 3/6
Expected value ≤ $5: 4/6
Expected value ≤ $6: 5/6
We can see that for any expected value, the CDF of Lottery 1 is always greater than or equal to the CDF of Lottery 2. This means that the probability of getting an expected value or less is always greater for Lottery 1 than for Lottery 2, which is the definition of second-order stochastic dominance.
We can similarly compare the CDFs of the other lotteries to arrive at the ranking above.

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Answer:b

Step-by-step explanation:

b

Answer:

182

Step-by-step explanation:

152

+31

---------

182

The prefix associated with the multiplier 0.001 is "milli-."

The International System of Units (SI) uses prefixes to denote decimal multiples and submultiples of units. The prefix "milli-" corresponds to a multiplier of 0.001. Here's a stepwise explanation of how this prefix is determined:

1. Identify the multiplier: The given multiplier is 0.001.

2. Understand the prefix: The prefix "milli-" represents a factor of 1/1000 or 0.001.

3. Determine the prefix symbol: The symbol for "milli-" is "m." It is written in lowercase.

4. Attach the prefix: To express a unit with the multiplier 0.001, you attach the prefix "milli-" to the base unit. For example, if the base unit is meter (m), the millimeter (mm) represents 0.001 meters.

5. Other examples: The milligram (mg) represents 0.001 grams, the millisecond (ms) represents 0.001 seconds, and the milliliter (mL) represents 0.001 liters.

By using the "milli-" prefix, we can conveniently express values that are a thousandth of the base unit, allowing for easier comprehension and communication in various scientific and everyday contexts.

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True. depending on the circumstances, the dequeue method of our linkedqueue class sometimes throws the queueunderflowexception

The dequeue method of a LinkedQueue class throws a QueueUnderflowException when the queue is empty, and the user attempts to remove an element from it. This is because removing elements from an empty queue is not allowed and violates the basic properties of a queue data structure. Therefore, depending on the circumstances, the dequeue method may throw a QueueUnderflowException to indicate that the operation is invalid.

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On solving the provided question, we can say that a set's elements can be arranged in any sequence.

A mathematical representation of a variety of different things is called a set. Any type of mathematical object may be one of the elements or terms that make up a set. Symbols, numbers, lines, other geometric shapes, points in space, variables, and even other quantities. A proposition in mathematics is a structured group of items that can be expressed as a list or a proposition builder. Curly brackets are commonly used to identify sets. For instance, A = 1, 2, 3, 4 is a set. A set is essentially a group of items that are seen together. The items that make up a set are referred to as its members or elements. The components of a set may consist of any item, but for our purposes, they usually consist of mathematical objects like numbers, functions,

Set Representation

A capital letter indicates a set. For instance, consider sets A, B, N, etc.

Small letters are used to identify the components of a set. Each element is written using curly brackets and a comma in between.

Elements are not repeated in set notation.

A set's elements can be arranged in any sequence.

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The best type of graph to display the results of this survey would be a histogram. A histogram is a graph that uses bars to represent the frequency distribution of a set of data. In this case, the shoe sizes would be grouped into intervals (e.g., 1-3, 4-6, 7-9, etc.) and the height of each bar would represent the number of students who have shoe sizes within that interval. A histogram is an effective way to show the overall pattern of the distribution of shoe sizes in the class.

A circle graph, also known as a pie chart, is useful for showing parts of a whole. It may not be the best choice for this survey since it does not show the distribution of shoe sizes as effectively as a histogram would.

A line plot, also known as a dot plot, is useful for showing the frequency of individual values in a small data set. It may not be the best choice for this survey since it may not be practical to list every individual shoe size.

A box plot, also known as a box-and-whisker plot, is useful for showing the distribution of a large data set. It may not be the best choice for this survey since the data set is likely to be small, and a histogram would be more appropriate for displaying the results.

Answer:

Option A.

Step-by-step explanation:

We are asked to add these 2 expressions.

First, we should know how to combine like terms.

Combining like terms is adding 2 or more numbers, or variables that are alike.

\(-\frac{4}{5} t+\frac{5}{3} s \ + -3 - \frac{7}{5} s+2t=?\)

Let's first begin by combining s and t. We can combine like terms for these two variables.

\(-\frac{4}{5} t + 2t = \frac{6}{5} t \ \checkmark\)

\(\frac{5}{3} s \ + \frac{7}{5} s \\Which \ can \ also \ be \ represented \ as...\\\frac{25}{15} s \ - \frac{21}{15} s = \frac{4}{15} s \ \checkmark\)

-3 doesn't have any like terms, meaning it'll stay as -3.

\(\frac{6}{5} t + \frac{4}{15} s - 3\)

Therefore, our answers matches with Option A.

Answer:

Ratio is 2:1

Step-by-step explanation:

The bigger triangle is ×2 bigger so ratios can be

2:1 , 4:2, 8:4 , 16:8 and so on

well, profit equations are usually a parabolic path like a camel's hump, profit goes up up and reaches a maximum then back down, the issue is to settle at the maximum point, thus the maximum profit.

So for this equation, like any quadratic with a negative leading coefficient, the maximum will occur at its vertex, with x-price at y-profit.

\(\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-5}x^2\stackrel{\stackrel{b}{\downarrow }}{+209}x\stackrel{\stackrel{c}{\downarrow }}{-1090} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 209}{2(-5)}~~~~ ,~~~~ -1090-\cfrac{ (209)^2}{4(-5)}\right) \implies\left( - \cfrac{ 209 }{ -10 }~~,~~-1090 - \cfrac{ 43681 }{ -20 } \right)\)

\(\left( \cfrac{ 209 }{ 10 }~~,~~-1090 + \cfrac{ 43681 }{ 20 } \right)\implies \left( \cfrac{ 209 }{ 10 }~~,~~-1090 + 2184.05 \right) \\\\\\ ~\hfill~\stackrel{ \$price\qquad profit }{(~20.90~~,~~ 1094.05~)}~\hfill~\)

Step-by-step explanation:

x = devaughn age

y = sydney age

x = y - 9

x + y = 61

y-9 + y = 61

2y= 61+9

2y = 70

y = 35

x = 35 - 9 = 26

check

35 + 26 = 61

35- 26 = 9

Hope this helps!

Given: