Please help me
I need help and it asked me to type 20 words soooooooo yea

Answer:

\((2x - 1)(x + 3) = \)

\(2 {x}^{2} + 5x - 3\)

A = 2, B = 5, C = -3

The number of bacteria that represents y at the end of x days will be \(y=(500)(2)^{x}\)

As per the given data on the day 0, there are 500 bacteria in a dish.

The number of bacteria that doubles every day after that.

Here we have to determine that how many bacteria which represent y are there after x number of days.

Therefore, the number of bacteria after every day will form a geometric progression (G.P) with the first term as a = 500 and the common ratio as r = 2

Therefore \(\mathrm{a}_3=\mathrm{ar}^2=(500)(2)^2=2000\)

Therefore, the number of bacteria at the end of 2nd day will be 480

\($a_5=a^4=(500)(2)^4=8000\)

And \($\mathrm{a}_{\mathrm{n}+1}=\mathrm{ar}^{\mathrm{n}}\)

\($\mathrm{a}_{\mathrm{n}+1}\) represents y and n represents x

\(y=(500)(2)^{\mathrm{x}}\)

Thus the number of bacteria at the end of x days will be \((500)(2)^{x}$=y\)

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Answer:

Step-by-step explanation:

Since M is the point of intersection of the diagonals of the square, it is also the midpoint of both diagonals. This means that AM is equal to half the length of a side of the square and also bisects the angle formed by the two sides that it connects.

Let's call the length of a side of the square s. Then, the distance AM can be found using the Pythagorean theorem:

AM = sqrt((5 - 2)^2 + (1 - 1)^2) = sqrt(3^2 + 0^2) = sqrt(9) = 3

So, the length of a side of the square is 2 * AM = 2 * 3 = 6.

Next, we can use the length of a side and the coordinates of A to find the coordinates of B. Since AB is a side of the square and is 6 units long, we can find B by moving 6 units to the right of A:

B = (2 + 6, 1) = (8, 1)

We can also find the coordinates of C by moving 6 units up and 6 units to the left of A:

C = (2 - 6, 1 + 6) = (-4, 7)

Finally, we can find the coordinates of D by moving 6 units down and 6 units to the right of A:

D = (2 + 6, 1 - 6) = (8, -5)

So, the coordinates of the other vertices of the square are B = (8, 1), C = (-4, 7), and D = (8, -5).

Answer:

Boys: 2/17

Girls: 4/17

Step-by-step explanation:

2 + 15 = 17 (to get the total number of boys in Sapphire's class)

4 + 13 = 17 (to get the total number of girls in the class)

The proportion is how many who are left handed over the total number of girls/boys. ^^

So, left-handed for boys = 2, which makes the proportion 2/17

And there are 4 left-handed girls, so the proportion is 4/17

The troop leader can use the two variables of preference (hiking or swimming) as the row and column headings of the table.

In mathematics, independent and dependent variables are values that vary in relation to one another. The dependent variable is dependent on the independent variable, which means that if the value of the independent variable changes, so will the dependent variable.

The troop leader can utilize the two variable categories (hiking or swimming) as the table's row and column headings.

The number of members who prefer each activity can be recorded in the cells of the table to show the distribution of preferences within each troop and the comparison between the two troops.

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Answer:

2) -7 i think

Step-by-step explanation:

Out of 20 booths at a trade show, you can visit approximately 11,287 different combinations of 15 booths.



To calculate the number of combinations of booths you can visit out of the 20 available booths, we can use the concept of combinations. The formula for combinations is given by:

C(n, r) = n! / (r! * (n - r)!)

where n is the total number of items (booths) and r is the number of items (booths) you want to select.

In this case, n = 20 (total booths) and r = 15 (booths you hope to visit). Plugging these values into the formula, we have:

C(20, 15) = 20! / (15! * (20 - 15)!)

Simplifying this expression, we get:

C(20, 15) = (20 * 19 * 18 * 17 * 16) / (15 * 14 * 13 * 12 * 11)

Calculating the numerator and denominator separately, we find:

C(20, 15) = 38,760 / 3,432

Finally, dividing these two numbers, we get:

C(20, 15) ≈ 11,287

Therefore, you can visit approximately 11,287 different combinations of booths out of the 20 available booths at the trade show.

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(a)  (1203)4 is equal to 99 in decimal and 12 in hexadecimal.

(b)  (5243)8 is equal to 2211 in decimal and 1523 in hexadecimal.

To convert numbers from different bases to decimal using the direct method, we multiply each digit of the number by the corresponding power of the base and sum the results. To convert to hexadecimal using the intermediary binary conversion method, we first convert the number to binary and then group the binary digits into groups of 4, starting from the rightmost digit, and convert each group to its hexadecimal equivalent.

(a) Converting (1203)4 to decimal:

(1203)4 = 1 * 4³ + 2 * 4² + 0 * 4¹ + 3 * 4⁰

= 64 + 32 + 0 + 3

= 99

Converting (1203)4 to hexadecimal:

First, convert (1203)4 to binary:

(1203)4 = (10010)2

Next, group the binary digits into groups of 4:

(10010)2 = (0001 0010)2

Finally, convert each group to its hexadecimal equivalent:

(0001 0010)2 = (12)16

Therefore, (1203)4 is equal to 99 in decimal and 12 in hexadecimal.

(b) Converting (5243)8 to decimal:

(5243)8 = 5 * 8³ + 2 * 8² + 4 * 8¹ + 3 * 8⁰

= 2048 + 128 + 32 + 3

= 2211

Converting (5243)8 to hexadecimal:

First, convert (5243)8 to binary:

(5243)8 = (101 010 100 011)2

Next, group the binary digits into groups of 4:

(101 010 100 011)2 = (0001 0101 0010 0011)2

Finally, convert each group to its hexadecimal equivalent:

(0001 0101 0010 0011)2 = (1523)16

Therefore, (5243)8 is equal to 2211 in decimal and 1523 in hexadecimal.

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Step-by-step explanation:

y = 200  - 3 *x  has slope = -3   this is downward sloping from L to R

Answer:downward sloping

Step-by-step explanation:

negative slope

If Hilda has $210 worth of $10 and $12 stock shares and the number of $10 shares is 5 more than twice the number of $12 shares, then the number of $10 shares and $12 shares she has is equal to 15 and 5 respectively.

The number of $10 shares and $12 shares can be calculated by forming linear equations.

Consider the number of $10 shares to be x and the number of $12 shares to be y.

x = 2y + 5

10x + 12y = 210

Putting the value x = 2y + 5 in the second equation,

10x + 12y = 210

10 (2y + 5) + 12y = 210

20y + 50 + 12y = 210

32y + 50 = 210

32y = 210 - 50

32y = 160

y = 160 ÷ 32

y = 5

Putting y = 5 in the first equation,

x = 2y + 5

x = 2(5) + 5

x = 10 + 5

x = 15

Hence the number of $10 and $12 shares she has is calculated to be 15 and 5 respectively.

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The common ratio of the sequence is 0.5.

The common ratio of a geometric sequence can be found by dividing any term by its previous term. Let's call the first term "a" and the common ratio "r". Then we have:

third term = a * r^2 = 100

eighth term = a * r^7 = 3.125

We can divide the equation for the eighth term by the equation for the third term to eliminate "a":

\((a * r^7) / (a * r^2) = 3.125 / 100\)

\(r^5 = 0.03125\)

r = 0.5

Therefore, the common ratio of the sequence is 0.5.

We are given two terms of a geometric sequence and are asked to find the common ratio. We can use the formula for the nth term of a geometric sequence to write two equations involving the first term "a" and the common ratio "r". By dividing the two equations, we can eliminate "a" and solve for "r". In this case, we get a fifth degree equation for "r", which we can solve using a calculator or by recognizing that 0.03125 is equal to 1/32, and therefore r is equal to the fifth root of 1/32, which simplifies to 0.5.

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Answer:

A line graph would be nice

Step-by-step explanation:

It would show how the prices increase over time

***im probs too late

Answer:

8

Step-by-step explanation:

8-15=-7

-7/7=-1

Answer:

I'm pretty sure it is 0.75

Step-by-step explanation:

It is a3 so that means it is the 3rd answer in the sequence.

Answer:

The sequence is adding 0.25

The correct formula for the general term of the arithmetic sequence representing the cost of the venue hire and catering for n guests is 1950 + 100n.

To find the formula for the general term of the arithmetic sequence representing the cost of the venue hire and catering for n guests, we can analyze the given information.

We are given two data points: the cost for 50 guests, which is $6,950, and the cost for 100 guests, which is $11,950. We can observe that the difference between these two costs is $11,950 - $6,950 = $5,000.

Since the cost forms an arithmetic sequence, the difference between consecutive terms will remain constant. In this case, the difference is $5,000.

Now, we need to find the initial term of the sequence. By examining the cost for 50 guests, we notice that the difference between the cost for 50 guests and the initial term is $6,950 - $5,000 = $1,950.

Putting it all together, we have the formula for the general term of the arithmetic sequence: initial term + (difference × (n - 1)).

Plugging in the values, the formula becomes: 1,950 + (5,000 × (n - 1)) = 1,950 + 5,000n - 5,000 = 5,000n - 3,050. Simplifying further, we get the final formula: 5,000n - 3,050.

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The surface area of a square pyramid net can be found by adding the areas of the base and the four triangular faces.

First, find the area of the base by multiplying the length and width of the square base.

Area of base = length × width

Next, find the area of one of the triangular faces by using the formula:

Area of triangle = 0.5 × base × height

Since there are four triangular faces in a square pyramid, multiply the area of one triangle by four to find the total area of the triangular faces.

Area of triangular faces = 4 × (0.5 × base × height)

Finally, add the area of the base and the area of the triangular faces to find the total surface area of the square pyramid net.

Surface area = Area of base + Area of triangular faces

= (length × width) + (4 × (0.5 × base × height))

= (length × width) + (2 × base × height)

So, the surface area of a square pyramid net is the sum of the area of the base and the area of the four triangular faces.

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The optimal consumption vector and the minimum expenditures necessary to reach a utility of U =50 is $25.

The consumer can reach a maximum utility of 12.5 with an income of $20.

I. Expenditure minimization problem:

To find the optimal consumption vector and minimum expenditure, we use the Lagrangian function:

L = x y + λ(I – Px x – Py y)

Where λ is the Lagrange multiplier and I is the income of the consumer.

Taking the partial derivative of L with respect to x and y and equating them to zero, we get:

y/2λ = Px

x/2λ = Py

Solving for x and y, we get:

x = 2λPy and y = 2λPx

Substituting these values in the budget constraint, we get:

I = Px(2λPy) + Py(2λPx)

I = 4λPxPy

λ = I/(4PxPy) = 20/(412) = 2.5

Thus, the optimal consumption vector is (x,y) = (5,10) and the minimum expenditure necessary to reach a utility of U=50 is:

Expenditure = Px x + Py y = 1(5) + 2(10) = $25

II. Utility maximization problem:

To find the optimal consumption vector and maximum utility, we use the Lagrangian function:

L = x y + λ(I – Px x – Py y)

Taking the partial derivative of L with respect to x and y and equating them to zero, we get:

y/2λ = Px

x/2λ = Py

Substituting the values of Px, Py, I, and λ, we get:

x = 2λPy = 2.5(2) = 5

y = 2λPx = 2.5(1) = 2.5

Thus, the optimal consumption vector is (x,y) = (5,2.5) and the maximum utility the consumer can reach is:

U = xy = 5(2.5) = 12.5

Therefore, the consumer can reach a maximum utility of 12.5 with an income of $20.

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The optimal consumption bundle is (10, 2.5). The minimum expenditures necessary to reach a utility of U = 50 are 15.

I. To solve the expenditure minimization problem, we need to find the optimal consumption bundle that will allow the consumer to achieve a utility level of U = 50 while minimizing their total expenditures. The consumer's budget constraint is given by Pxx + Pyy = I, where Px and Py are the prices of x and y, respectively, and I is the consumer's income.

Using the utility function U = xy, we can rewrite the budget constraint as y = (I/Px) - (Px/Py)x. Substituting this equation into the utility function, we get U = x((I/Px) - (Px/Py)*x). Taking the derivative of U with respect to x and setting it equal to zero, we can find the optimal value of x:

dU/dx = (I/Px) - (2/Py)x = 0

x = (PyI)/(2*Px)

Substituting this value of x into the budget constraint, we can find the optimal value of y:

y = (I/Px) - (Px/Py)x

y = (I/Py) - (Px/Py)((PyI)/(2Px))

y = I/(2*Py)

So, the optimal consumption bundle is (x*, y*) = ((PyI)/(2Px), I/(2Py)) = (10, 2.5). The minimum expenditures necessary to reach a utility of U = 50 are Pxx* + Pyy = 110 + 22.5 = 15.

II. To solve the utility maximization problem, we need to find the optimal consumption bundle that will allow the consumer to maximize their utility level given their budget constraint. Using the same budget constraint as before, we can rewrite it as y = (I/Px) - (Px/Py)*x.

The Lagrangian function for this problem is L = xy + λ(I - Pxx - Pyy), where λ is the Lagrange multiplier. Taking the partial derivatives of L with respect to x, y, and λ and setting them equal to zero, we can find the optimal consumption bundle:

∂L/∂x = y - λPx = 0

∂L/∂y = x - λPy = 0

∂L/∂λ = I - Pxx - Pyy = 0

Solving these equations simultaneously, we get:

x = (PyI)/(2Px)

y = (I/Px) - (Px/Py)x

y = (I/Px) - (Px/Py)((PyI)/(2Px))

y = I/(2*Px)

So, the optimal consumption bundle is (x*, y*) = ((PyI)/(2Px), I/(2Px)) = (10, 5). The maximum utility the consumer can reach is U = xy = 10*5 = 50.

In summary, the consumer should consume 10 units of good x and 2.5 units of good y to achieve a utility level of U = 50 with minimum expenditures of 15. If the consumer has an income of I = 20, they should consume 10 units of good x and 5 units of good y to maximize their utility level of U = 50.

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Answer: 70 degrees 35 times 2

The set {h| 0 ≤ h ≤ 60} describe the domain of p(h).

According to the statement

We have given that the brenton gets paid $20 per hour for the first 40 hours he works in a week. For any hours above that, he is paid overtime at $30 per hour.

and we have to find that the those set which describes the domain of p(h).

So,for this purpose

In this case, the domain represents the set of hours he is permitted to work

From the question, we understand that he cannot work more than 60 hours

This means that, the least number of hours to work is 0, and the highest is 60

So, the domain is 0 to 60

When represented properly, the domain of P(h) is (b)  {h| 0 ≤ h ≤ 60}.

So, The set {h| 0 ≤ h ≤ 60} describe the domain of p(h).

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

Brenton’s weekly pay, P(h) , in dollars, is a function of the number of hours he works, h. He gets paid $20 per hour for the first 40 hours he works in a week. For any hours above that, he is paid overtime at $30 per hour. He is not permitted to work more than 60 hours in a week. Which set describes the domain of P(h)? {h| 0 ≤ h ≤ 40} {h| 0 ≤ h ≤ 60} {P(h)| 0 ≤ P(h) ≤ 1,400} {P(h)| 0 ≤ P(h) ≤ 1,800

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Answer:

B.{h|0<h<60}

Step-by-step explanation:

The earliest finish time for the activity 10-11(far right-hand side) is 23 if the earliest start time of activity 8-10 and activity -10 is 12 and 13 respectively.

The depicted graph represents the critical path method(CPM)

Given,

Earliest start time of 8-10 = 12

Earliest start time of 9-10 = 13

From the network, it is observed that at 10, two networks are connecting, we need to take the largest earliest finish time from both the activities as earliest start time for 10-11.

Earliest finish time = earliest start time + activity duration

Earliest finish time for 8-10 = 12+4=16

Earliest finish time for 9-10 = 13+2=15

From above two times, 8-10's earliest finish time is the greatest. So, consider 16 as earliest start time for 10-11.

Now,

Earliest finish time for 10-11= earliest start time + activity duration=16+7=23

Thus, the earliest finish time for 10-11 is 23.

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The expression that can be factored by grouping is pr + ps + qr + qs. We can group the terms into two groups, factor out the common factors from each group, and simplify the expression to get (p+q)(r+s). So, the correct answer is D).

The expression that could be factored by grouping is

pr + ps + qr + qs

To factor this expression by grouping, we can first group the first two terms and the last two terms

(pr + ps) + (qr + qs)

We can then factor out the common factors from each group

pr + ps = p(r+s)

qr + qs = q(r+s)

We can see that both groups have a common factor of (r+s), so we can further simplify the expression

(p+q)(r+s)

Therefore, the final factored form of the expression pr + ps + qr + qs is (p+q)(r+s).

None of the other expressions given can be factored by grouping.

For pq + ps - pr + pt, we cannot group any two terms that have a common factor. For pq + rs - pq + rs, we can simplify it as 2rs, but it cannot be factored by grouping. For pr + ps - qr - qs, we cannot group any two terms that have a common factor. So, the correct option is D).

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a. There are 24,840 ways to select 6 students from a class of 25 to serve on a committee. b. There are 156,250 ways to select 6 students from a class of 25 to hold six different executive positions on a committee.

a. To answer this question we can use the combination formula. This formula is written as C(n,r), where n is the total number of objects and r is the number of objects that you are selecting. In this case, n=25 and r=6. Therefore, the formula becomes C(25,6). By substituting these values into the formula you get C(25,6) = 25!/(6!*(25-6)!) = 25!/6!*19! = 24,840. This means that there are 24,840 ways to select 6 students from a class of 25 to serve on a committee.

b. To answer this question we can use the permutation formula. This formula is written as P(n,r), where n is the total number of objects and r is the number of objects that you are selecting. In this case, n=25 and r=6. Therefore, the formula becomes P(25,6). By substituting these values into the formula you get P(25,6) = 25!/(25-6)! = 25!/19! = 156,250. This means that there are 156,250 ways to select 6 students from a class of 25

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Answer:

-4

any more help just ask :)

Answer:

x = -27

Step-by-step explanation:

he number of ways the friends can choose seats without sitting next to each other is 7! - 4! = 5040

If there are 5 seats open in a row and no restrictions on the seating arrangement, each friend can choose one seat independently. Therefore, the total number of ways the friends can choose seats is 5 factorial (5!) which is equal to 5 × 4 × 3 × 2 × 1 = 120.

(b) If there are 7 seats open in a row and no restrictions on the seating arrangement, each friend can choose one seat independently. Therefore, the total number of ways the friends can choose seats is 7 factorial (7!) which is equal to 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040.

(c) If two friends are required to sit next to each other, we can treat them as a single entity. This reduces the problem to arranging four entities (three individual friends and one pair of friends) and three empty seats. The total number of ways the friends can choose seats is then 4 factorial (4!) which is equal to 4 × 3 × 2 × 1 = 24.

(d) If two friends are required to not sit next to each other, we can count the complement of the situation in part (c). There are 7 factorial (7!) total seating arrangements without any restrictions. From part (c), we found that there are 4 factorial (4!) seating arrangements where the two friends sit next to each other. - 24 = 5016.

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Answer:

x = 2, y = -1/3

Step-by-step explanation:

I'm pretty sure the question is asking for the values of x and y. By finding these values you will need to use elimination.

Equations given:

5x + 3y = 9

2x - 3y = 5

To find x:

5x + 3y + 2x - 3y = 9 + 5  (add to eliminate y to solve for x)

7x = 14

x = 2

To find y:

5(2) + 3y = 9

10 + 3y = 9

3y = -1

y = -1/3

Therefore, x = 2 and y = -1/3

Velocity of jet in still air is 647 miles per hour and velocity of wind is 70 miles per hour.

Given,

Jet's velocity against wind 1731 / 3 = 577  mile per hour

flying with wind it   2151 / 3 = 717 miles per hour.

Let the velocity of jet in still air be x miles per hour and velocity of wind be y miles per hour.

As such its velocity against wind is x−y and with wind is x+y and therefore

x−y=577;

x+y=717

Adding the two

2x = 1294

x = 647

y= 717 − 647

y = 70

Hence velocity of jet in still air is 647 miles per hour and velocity of wind is 70 miles per hour.

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Answer:

yes look at the eslotp uudh

Both betas and correlation coefficients can tell you something about the direction of a relationship. The corect option is D.

The coefficient of variation is a ratio which is used to show the level dispersion of values or treatments around the mean of a set of values.

The coefficient of variation is the ratio of the standard deviation to the mean of a set of numbers or treatments. The higher the coefficient of variation the higher the dispersion from the mean.

The coefficient of variation is the best measure of risk for an isolated single asset. Beta is the a measure of how volatile a particular stock is compared to the market.

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If you received a gift of $10,000 3 years ago and you want to spend it in 3 years with interest rate is 4%, it will be worth $12,653.19. Option b is correct.

To calculate the future value of a present sum after a specified period, we can use the formula for compound interest:

Future Value = Present Value * (1 + Interest Rate)ᴺ

In this case, the present value is $10,000, the interest rate is 4% or 0.04, and the number of periods is 6 years because you received the gift 3 years ago and want to spend it in 3 years.

Using the formula:

Future Value = \(\$10,000 * (1 + 0.04)^6\)

Future Value = \(\$10,000 * (1.04)^6\)

Future Value = $10,000 * 1.1265319

Future Value ≈ $12,653.19

Therefore, the amount will be approximately $12,653.19. Option b is correct.

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